unknown substance's mass: 75.0g, unknown substances molar mass = 150.0 g/mol, Hfus = 5.0x10^3 J/mol, Hvap = 1.00 x 10^4 J/mol, unknown substance's specific heat (liquid) = 2.2 J/g, unknown substance's specific heat (gas) = 4.8 J/g, unknown substances's specific heat (solid) = 5.0 J/g; Calculate the amount of heat (in J) for the unkown sample as it is heated at a constant rate from 10.0c to 25.0c as it passes through each of the following regions: region uv

2

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Answer: A- 1 day

Explanation: I really hope that helped. BYE!!

1 day is the half-life of a radioisotope if a 20 g sample becomes 5 g after 2 days

Answer: 0.040 mol/l

Explanation: Molarity c = n/V (Concentration)

c = 0.060 mol / 1,5 l = 0,040 mol/l

According to the law of conservation of mass, mass is neither created nor destroyed in a chemical reaction. If the reaction obeys the law of conservation of mass, the mass before and after the reaction will be the same.

Any element's mass at the start of a reaction will equal its mass at the end of the reaction. Accounting for all reactants and products in a chemical reaction results in the same total mass at any point in time in any closed system.

When coal, for example, is burned, the carbon atom transforms into carbon dioxide. The carbon atom undergoes transformation from solid to gas, but its mass remains constant.

According to the law of conservation of mass, the amount of mass that enters a chemical reaction in the form of reactants must equal the amount of mass that exits the reaction process in the form of products. This is only possible in a closed system. For example, if 2g of reactant A reacts with 32g of reactant B, the mass of the product AB formed is 34g.

To learn more about Law of conservation of mass, refer to:

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Answer:

10 is the atomic number

Ne is the chemical symbol

Neon is the element name

20 is the atomic mass

Answer:

the answer is b: it shows how temperature of a substance changes when heated

Answer:

Solution A

Explanation:

Solution A

1 mole of MgO = 24 + 16 = 40 g

? moles of MgO = 135.75g

[tex]\frac{135.75}{75}[/tex] = 1.81 moles

1.81 moles of MgO is in 2 liters of water

? moles of MgO is in 1 liter of water

[tex]\frac{1.584}{2}[/tex] = 0.905moles/liter or 0.905M

Solution B

1 mole of CaCl₂ = 40 + 35.5 = 75.5 g

? moles of CaCl₂ = 119.6g

[tex]\frac{119.6}{75.5}[/tex] = 1.584moles

1.584 moles of MgO is in 2 liters of water

? moles of MgO is in 1 liter of water

[tex]\frac{1.584}{2}[/tex]= 0.792moles/liter or 0.792M

Answer:

I knew that I learned something and passed that test. And that is all I want to do.

Explanation:

Answer:

vaiana and I have been working with our team since we been through

Answer: Radon is radioactive

Explanation: thats all i know

Answer:

It is a combustion reaction

Explanation:

Answer:

option A,B and C.

are the options I chose.

The electrical devices include those that are needed to power appliances and those that are used in daily life. In order to make things operational, they need power or energy.

Hence the option C is correct.

Learn more about the choices are uses of electrical energy.

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Explanation:

Fertilizers are chemically synthesized plant nutrients.

Nitrogen (N), Phosphorus (P) and Potassium (K) are macronutrients and are required in large amounts by plants. So, farmers use fertilizers in order to supply these nutrients. NPK 15:15:15 , NPK 20:20:20, NPK 15:30:15 are examples of fertilizers used to supply N, P, K to crops.

Explanation:

1.Potassium Nitrate(KNO3)

2.Potassium Sulphate(K2SO4)

They provide potassium to plants for making their roots and shoots healthy.

Answer:

A. Oil is to heavy to mix with water

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-Todo <3

Explanation:

Answer:

It should be C - Water can only mix with polar molecules.

Explanation:

Oil is non-polar and water is polar.

Answer:

M2 = 0.95M

Explanation:

M1V1 = M2V2

(1.9)(0.5) = M2(1)

M2 = 0.95M

Answer:

The answer is in the photo

Explanation:

I hope that is useful for you :)

Answer:

I think C...................

Answer:

[tex] \huge\blue{ \mid{ \underline{ \overline{ \tt ♡ AQUAMARINE ♡ }} \mid}}[/tex]

=> The colour of this stone is usually a pale greenish blue, owing to the presence of iron impurities. Stones that are treated with heat look more blue than green. On the Mohs scale of hardness, aquamarine ranges between 7.5 and 8 making it a relatively hard gemstone.

=> The best way to identify a real aquamarine stone is by looking at its colour. In its natural form, they have a pale blue colour, which is similar to seawater. They may have a slight green or yellow tint as well. Naturally occurring gems have excellent clarity and transparency.

=> The hardness of the stone is another feature you can use to identify the stone. Aquamarine stones are hard and they don’t get scratches easily. However, they can easily scratch glass and other such surfaces. So, if you find visible scratches on the stone, rethink your decision to buy it.

=> Most faceted aquamarine stones are clean to the eye and clear of any inclusions. However, translucent and opaque aquamarine is also available. These are usually fashioned into cabochons or beads. In some cases, inclusions may appear as parallel tubes. Such stones can be crafted to show a cat’s eye. Stones with cat’s eye and star effect are rare and highly priced.

Answer:

what are the following

Explanation:

what are the options?

Answer:

the ball will stop moving

Answer:

Explanation:

At STP 1 mole of an ideal gas = 22.4 L.

Assuming SO2 (sulfur dioxide) acts as an ideal as, we have 16 g SO2 x 1 mol/64 g = 0.25 moles SO2

0.25 moles x 22.4 L/mole = 5.6 liters

Answer: OCl2 is polar because the two O-Cl bond dipoles don't cancel each other.

Answer:

Average atomic mass = f1M1 + f2M2 +… + fnMn where f is the fraction representing the natural abundance of the isotope and M is the mass number (weight) of the isotope. The average atomic mass of an element can be found on the periodic table, typically under the elemental symbol.

Answer:

The dry bulb temperature is the ambient air temperature that is measured by regular thermometers, while the wet bulb temperature is measured by thermometers that are wrapped in  wicks. The greater the wet bulb depression, the greater the felt effect is on the discharge air temperature.

Explanation:

Answer:

yep.. I am wide awake here.

yep

ExPlAnAtIoN:

yezs and nozs

Answer:b

Explanation:

Answer:

Explanation:

¡Hola!

En este caso, dado que las reacciones de desplazamiento simple se llevan a cabo cuando un metal desplaza a otro metal de su sal u otro compuesto, es preciso tener en cuenta la serie de reactividad de los metales que se muestra en el archivo adjunto.

Así, es mandatorio que el metal con el que la sal original reacciona, sea más reactivo que el catión de la misma, de modo contrario, la reacción tendría lugar. Por ejemplo, si el sodio reacciona con cloruro de zinc, al este primero estar más arriba en la serie, quiere decir que es capaz de desplazar el zinc en el cloruro original y así se formaría zinc metálico y cloruro de sodio.

¡Saludos!