Una caja con medicina es lanzada desde un avión localizado a una distancia vertical de 340 m por encima de un río. Si el avión lleva una velocidad horizontal de 70 m/s¿Qué distancia horizontal recorrerá la caja con medicina antes de caer al río?

Answers

Answer 1

Answer:

La distancia horizontal que recorrerá la caja con medicina antes de caer al río es 583.1 metros.

Explanation:

Una caja con medicina es lanzada desde un avión localizado a una distancia vertical de 340 m por encima de un río.  Este movimiento posee una composición en dos dimensiones: uno horizontal sin aceleración, y el otro vertical con aceleración constante debido a la gravedad.  Por lo que se trata de un movimiento rectilíneo uniforme (MRU) en su trayectoria horizontal o eje horizontal (es decir, su velocidad es constante) y un movimiento uniformemente variado (MRUV) en su trayectoria vertical o en el eje vertical (es decir, su aceleración es constante).

En este caso, son conocidos los datos, considerando el sistema de referencia de la imagen:

Vy = 0 m/s (trayectoria vertical) Vx = 70m/s (velocidad horizontal)  hi = 340 m (altura inicial) g = -9,8 m/s² hf = 0 m (altura final. Cuando la caja de medicina cae al río, su altura será 0 m)

En el caso del MRUV, la posición puede calcularse mediante la expresión:

Posición final= Posición inicial + Velocidad inicial*t + [tex]\frac{1}{2}[/tex]*a*t²

donde a es la aceleración y t el tiempo transcurrido.

En este caso, reemplazando los datos conocidos, teniendo en cuenta que el MRUV sucede en la trayectoria vertical y que la aceleración es el valor de la gravedad:

0 m= 340 m + 0 m/s*t + [tex]\frac{1}{2}[/tex]* (-9.8 m/s²)* t²

Resolviendo:

-340 m= [tex]\frac{1}{2}[/tex]* (-9.8 m/s²)* t²

[tex]\frac{-340 m}{\frac{1}{2} *(9.8\frac{m}{s^{2} } )} =t^{2}[/tex]

69.39 s²= t²

t= √69.39 s²

t= 8.33 s

La posición en MRU se obtiene mediante:

Posición final= Posición inicial + velocidad* tiempo

Con los datos conocidos y el tiempo calculado previamente, es posible calcular la distancia horizontal que recorrerá la caja con medicina antes de caer al río, siendo la posición inicial en x igual a cero:

Posición final= 0 m + 70m/s* 8.33 s

Posición final= 583.1 m

La distancia horizontal que recorrerá la caja con medicina antes de caer al río es 583.1 metros.

Una Caja Con Medicina Es Lanzada Desde Un Avin Localizado A Una Distancia Vertical De 340 M Por Encima
Answer 2

Veremos que la distancia horizontal que recorre la caja es 583.1 metros.

¿Como encontrar la distanca horizontal recorrida?

Recordar que la velocidad vertical y horizontal son independientes.

Aqui, lo primero que debemos hacer es encontrar el tiempo que la caja tarda en llegar al suelo.

Para ello usamos la ecuación de movimiento vertical:

p(t) = (-4.9 m/s^2)*t^2 + v*t + h

Donde el primer termino representa la gravedad, el segundo la velocidad inicial (que es cero en este caso) y el tercero la altura inicial, que es 340m.

p(t) = (-4.9 m/s^2)*t^2 + 340m

La caja llegara al suelo cuando la función de arriba sea igual a cero:

(-4.9 m/s^2)*t^2 + 340m = 0

t = √(340m/(4.9 m/s^2)) = 8.33 s

Es decir, la caja tarda 8.33 segundos en llegar al suelo.

Esto significa que la caja se va a mover horizontalmente durante 8.33 segundos con una velocidad de 70m/s (la que tenía el avion). Es decir, la distancia horizontal que se mueve la caja es :

D = 8.33s*(70m/s) = 583.1 m

Sí quieres aprender más sobre ecuaciones de movimiento, puedes leer:

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Related Questions

Geothermal energy is an alternative energy source, although it is not resourceful enough to replace more than a minor amount of the Earth’s energy needs. Why is this?

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The circumference of a circle is the distance around it (linear) while a period is the completion of a cycle or the length from one peak to the next of a periodic function

Explanation:

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Answer:

Stir/agitate and heat the tea

Answer:

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Explanation:

Heating and stirring both increase the energy of the tea molecules, which increases interactions with the sugar. Grinding sugar allows more sugar molecules to be exposed to the solvent particles that dissolve them.

A plumber is going to put two pipes in a wall, one in front and one in back. The pipes will be touching once they are installed. Both pipes are the same size and have the same number of molecules. The diagram above shows the pipes now, before they have touched. Use the information in the diagram to answer the question.

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Answer:

They become the same exact tempature

Explanation:

Since they got connected it should be the same.

the temperature of the front pipe compare with the temperature of the back pipe before the pipes touch by using same temperature.

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the time required for half of something to undergo a process: such as. a : the time required for half of the atoms of a radioactive substance to become disintegrated.

Answer:

the time taken for the radioactivity of a specific isotope to fall to half its original value.

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A 25 N force stretches a spring 0.280 m. What was the spring constant?

Answers

Answer:

the  spring constant is -89.2857 n/m

Explanation:

The computation of the spring constant is shown below:

As we know that

Force in newtons = Spring constant × amount of extension

F = -k × x

where

F = 25 N

And, x = 0.280m

So, the spring constant would 2  

= 25N ÷ 0.280 m

= -89.2857 n/m

Hence the  spring constant is -89.2857 n/m

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Answer:

“The Tyger” represents the evil and beauty too, “the forest of the night” represents unknown challenges, “the blacksmith” represents the creator and “the fearful symmetry” symbolizes the existence of both good and evil. Imagery: Imagery is used to make the readers perceive things with their five senses.

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Answer:

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Answers

Answer:

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hoped so u got the answer mark me as brainellist :)

Answer:

0.5/1.6×10^-19

Explanation:

formula for current is v

I R

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0.5/1.6×10^-19

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Answers

F= 100 N , d= 5 m
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100*5/10
= 500/10
= 50 watt

The power used when a 100 N force is applied to move an object through a distance of 5 m at constant speed in 10 seconds is 50 W

We'll begin by calculating the energy. This can be obtained as follow:

Force (F) = 100 N

Distance (s) = 5 m

Energy (E) =?

E = F × s

E = 100 × 5

E = 500 J

Finally, we shall determine the power. This can be obtained as follow:

Energy (E) = 500 J

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A force of 120 N is applied to the front of a sledge at an angle of 28.00 above the horizontal so as to pull the sledge a distance of 165 meters. How much work was done by the applied force?

Answers

Answer:

Workdone = 17482.36 Joules

Explanation:

Given the following data;

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To find the work done, we would use the following formula;

Workdone = FxCosd

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Workdone = 120*165*Cos(28)

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An effect analogous to two-slit interference can occur with sound waves, instead of light. In an open field, two speakers placed 1.19 m apart are powered by the same function generator producing sine waves at 1,163 Hz frequency. Assume that the speed of sound is 340 m/s. A student walks along a line 12.5 m away and parallel to the line from one speaker to the other speakers. She hears an alternating pattern of loud and quiet, due to constructive and destructive interference. What is the distance between the central maximum and the first maximum (loud) position along this line in m

Answers

Answer:

3.04 m

Explanation:

The interference by diffraction of waves is noticeable only when the dimension of the opening through which the wave is passing through is comparable to the wavelength of the passing wave.

It is given that :

Distance between two speakers, d = 1.19 m

Speed of sound,  v = 340 m/s

The frequency is f = 1163 Hz

Distance the student walk along the line of the speaker, D = 12.5 m

We know the wavelength of the sound produced by the speakers is given by :

[tex]$\lambda=\frac{v}{f}$[/tex]

  [tex]$=\frac{340}{1163}$[/tex]

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Now the distance between the central maximum and the first maximum position is given by :

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True or false. In a parallel circuit the current remains the same everywhere.
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Answers

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Answer:

Its False

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Yes you are right

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Answers

Answer:

The solution of the given query is explained below in the explanation portion.

Explanation:

Given value is:

Work,

⇒  [tex]W=4.30\times 10^3 \ J[/tex]

(a)

The change in the internal energy will be:

⇒  [tex]\Delta V=\frac{3}{2}nR(\Delta T)[/tex]

Throughout the isothermal procedure, The temperature will be constant "ΔT = 0".

then,

⇒  [tex]\Delta V = \frac{3}{2}nR(0)[/tex]

⇒  [tex]\Delta V = 0 \ J[/tex]

(b)

As we know,

⇒  [tex]\Delta V = Q-W[/tex]

On substituting the value, we get

⇒      [tex]0=Q-W[/tex]

On adding W both sides, we get

⇒    [tex]W=Q-W+W[/tex]

⇒    [tex]W=Q[/tex]

On substituting the given value of "W", we get

⇒     [tex]Q=4.30\times 10^3 \ J[/tex]    

An incident ray that passes through the vertex of a convex lens:
F
F
c
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B. continues in a straight line without refracting.
C. refracts parallel to the axis of the lens,
D. refracts outward, at an angle equal to the angle of incidence.

Answers

the answer is refracts parallel to the axis of the lens

In regions of the cardiovascular system where there is steady laminar blood flow, the shear stress on cells lining the walls of the blood vessels is about 20 N / M2. If the shear strain is about 0.008, estimate the shear modulus for the affected cells.

Answers

Answer:

Shear Modulus = 2500 Pa = 2.5 KPa

Explanation:

The shear modulus is defined as the ratio between the shear stress and the shear strain. Hence, the shear modulus, in this case, can be calculated by the use of the following formula:

[tex]Shear\ Modulus = \frac{Shear\ Stress}{Shear\ Strain}\\[/tex]

we have,

shear stress = 20 N/m²

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Therefore,

[tex]Shear\ Modulus = \frac{20\ N/m^2}{0.008}\\\\[/tex]

Shear Modulus = 2500 Pa = 2.5 KPa

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Answer:

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Explanation:

Answer:

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A spring is stretched 0.15 m and the force was 1500 N. What is the spring constant?

Answers

Use the formula f=kx where f is force, k is spring constant, and x is extension.

1500=k* 0.15
K= 1500/0.15 = 10000

The spring constant for a spring is stretched 0.15 m and the force was 1500 N is 10000.

What is spring constant?

The spring constant, k, is a measure of the spring's stiffness. It varies depending on the spring and material. The greater the spring constant, the stiffer the spring and more difficult to stretch.

The letter k symbolizes the "spring constant," which is a number that tells us how "stiff" a spring is.

If k is large, it means that more force is required to stretch it a certain length than would be required to stretch a less stiff spring the same length.

We know that,

F = k(x)

Where k is the spring constant.

Here, it is given that:

F = 1500N

x = 0.15m

So,

1500 = k (0.15)

k (0.15) = 1500

k = 1500/0.15

k = 150000/15

k = 10000

Thus, the value of spring constant is 10000.

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