Type equation for the line shown in the graph

Answer:

y = [tex]\frac{1}{2}[/tex] x + 4

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (- 2, 3) and (x₂, y₂ ) = (2, 5) ← 2 points on the line

m = [tex]\frac{5-3}{2+2}[/tex] = [tex]\frac{2}{4}[/tex] = [tex]\frac{1}{2}[/tex] , then

y = [tex]\frac{1}{2}[/tex] x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (2, 5 ) , then

5 = 1 + c ⇒ c = 5 - 1 = 4

y = [tex]\frac{1}{2}[/tex] x + 4 ← equation of line

A quadratic function y = f(x) is plotted on a graph and the vertex of the resulting
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BRAINLIEST
a. 2 root of 5
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Which of the following statements is true?
AD
O
T
is a
O meRem20
RS - PQ
O
STOP
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B
40
24
С
A
b
Find the length of “b” using
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Enter

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