The amount of work the two tugboats completed on the supertanker W = 3.12 × 10^9 joules .
Work is a physics term used to describe the energy transfer that takes place when an object is moved over a distance by an external force, at least some . The component of the force acting along the path multiplied by the length of the path can be used to calculate work if the force is constant. Mathematically, this idea is expressed as W = fd, where W is the work and f is the force multiplied by d, the distance. Work is completed when the force is applied at an angle of with respect to the displacement. Performing work on a body involves moving it in its entirety from one location to another as well as other methods. However, the work is thought to be negative if the applied force is in opposition to the item's motion, indicating that energy is being pulled away from the object
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NEED HELP URGENTLY FOR 10 POINTS
Answer:
Option 2
Explanation:
This is the definition of the plum-pudding model.
A charge of 15C has flowed past a point in the circuit with a current of 2A. How long has this charge been flowing through this circuit?
Round the answer to 2 decimal places.
The charge of 15 Chas been flowing through a circuit with current of 2 A for a time period of 7.5 s
Q = I t
Q = Electric charge
I = Electric Current
t = Time
Q = 15 C
I = 2 A
t = Q / I
t = 15 / 2
t = 7.5 s
Electric current is the rate of flow of charge. In a circuit the current always flows from the negative terminal to the positive terminal. Its unit is Ampere ( A ) which is C / s.
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4. given long wire connecting c and d c d 220 v where the motor is drawing 8 amps and the lamp 2 amps, find a. the voltage drop across the wire - modeled by the 2 ohm resistor. b. the voltage across the motor and lamp
A body weighs (i) 900N on the surface of earth how much will it weigh on the surface of
Mars whose mass is one ninth and radius is one half that of the earth take g on the surface
of earth to be 10 m/s2
The weight of the body on the surface of mars would be 333.9 Newtons.
What is Weight ?Weight is the force exerted by the earth on an object at the surface of the earth and this force is directed towards the center of the earth. Mathematically -
W = mg
where -
[m] is the mass of object
[g] is acceleration due to gravity
Given is a body that weighs 900N on the surface of earth. Mars is a planet whose mass is one ninth and radius is one half that of the earth. The same body is now placed on mars.
Since the weight of the body is 900 N on earth, we can write -
W = mg
900 = m x 10
m = 900/10
m = 90 Kg
Now, we know for a body of mass [m] on a planet of mass [M], the gravitational force exerted by planet on the body will be -
F = GMm/r²
but
F = W = mg
So, we can write -
mg = GMm/r²
g = GM/r²
For the planet of mars, we can write -
g = GM[mars]/r[mars]²
g = (6.6743 × 10⁻¹¹ x 0.65 x 10²⁴)/(3185.5 x 10³)
g = 3.71 m/s²
So, the weight of the body on mars will be -
W = mg = 90 x 3.71
W = 333.9 N
Therefore, the weight of the body on the surface of mars would be 333.9 Newtons.
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when the spectrum of light from a star is redshifted, the star must be when the spectrum of light from a star is redshifted, the star must be moving away from you moving toward you cooling off ready to explode
The distance traveled will therefore simply be equal to the original velocity multiplied by the time period. The result of adding these two numbers together is about 2.41, or 4 times 10 to the ninth meters.
Some star material, with an initial velocity of roughly 40,232,600 m/s, is accelerated outward in specific shock waves that are created by a star dying. Let's record that as beginning velocity, which is 40 million 233,600 meters per second. And we inquired as to how far it travels in a minute. Since we are in space, there are essentially no accelerations to take into account. Therefore, we don't need to think about any form of slowing down or speeding up of this velocity.
The distance traveled will simply be equal to the original velocity multiplied by the time interval because this is how long it has been moving. And when we combine those two figures, we get a result of around 2.41, or 4 times 10 to the ninth meters.
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you are 9.0 m from the door of your bus, behind the bus, when it pulls away with an acceleration of 1.0 m/s2. you instantly start running toward the still-open door at 5.7 m/s.
a) It takes you 1.893s to reach the opened door and jump in.
b) The maximum time that you can wait before starting to run and still catch the bus is 1.27s
The time which the passenger can delay and still catch the bus must be less than this.
From the question:
Distance between the passenger and the door of the bus d = 9
Acceleration of the bus a¹ = 1.0m/s²
Speed of the passenger v = 5.7m/s
Time taken for you to catch up with the bus must occur at the exact position with the bus,
Let the position = y
The time taken for you to reach the point:
t = total speed/distance
t = y + 9/5.7 ..................... eqn 1
The time taken for the bus to reach the same point;
y = vt + 1/2at²
Initial velocity of the bus is zero
y = 0.5*(1)t²
y = t²/2
t = √2y .......................eqn 2
We solve eqn (1) and (2) together:
9 + y = 5.7 * √2y
81 + y² + 18y = 64.98y
y² - 46.98y + 81 = 0
y = 45.187m or 1.792m
Now we take the smallest distance: x=1.792 m
Time taken for both to reach this point: (put x in eq. (1))
t = 1.792+9/5.7
t = 1.893s
For the maximum waiting time we find have:
Relative acceleration, ar = -1m/s⁻²since the bus is moving away from the intended
The final relative velocity for the passenger to catch it, vr = 0m/s⁻¹
Using equation of motion:
s = 9 + 1/2 * (-1)t²
also the initial relative velocity:
vr = ur + ar.t
ur = 5.7 - t
and
vr² = ur² + 2ar.s
0² = (5.7 - 1)² - 2 * 1 * (9 - 0.5t²)
t = 1.27s
Here's the complete question:
You are 9.0 m from the door of your bus, behind the bus, when it pulls away with an acceleration of 1.0 m/s2. You instantly start running toward the still-open door at 5.7 m/s.
How long does it take for you to reach the open door and jump in?
What is the maximum time you can wait before starting to run and still catch the bus?
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6. Substances soluble in water possess which molecular characteristic that substances insoluble in water lack?
Substances that are soluble in water are polar substances which is a molecular characteristics that is not possessed by insoluble substances.
What is molecular characteristics?The molecular characteristics of a substance is the features that are exhibited by the ions and molecules of that substance that makes it unique from others.
Soluble substances are those substances that are able to dissolve in water while insoluble substances are those substances that are not able to form solution with water.
Example of soluble substances are salt and sugar while examples of insoluble substances are metals and fat.
The soluble substances are polar substances are they possess a negative and a positive pole in their molecules that allows for dissolution in water.
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9. A driver, driving a Bugatti Veyron, accelerates at 26.7 m/s² for 2.4 seconds. What change in
velocity did the driver experience?
The change in velocity experience by a driver, driving a Bugatti Veyron, accelerating at 26.7 m/s² for 2.4 seconds is 64.08 m/s.
What is chnage in velocity?Change in velocity is the difference between the final and the initial velocity of a body.
To calculate the change in velocity experienced by the driver, we use the formula below.
Formula:
Δv = at........... Equation 1Where:
Δv = Change in velocitya = Accelerationt = Time.From the question,
Given:
a = 26.7 m/s²t = 2.4 secondsSubstitute these values above into equation 1
Δv = 26.7×2.4Δv = 64.08 m/s.Hence, the change in velocity experienced by the driver is 64.08 m/s.
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A BALL Is released from a hight of 20m calculate the time it taken to fall. The velocity with it hits the ground
A ball is released from a certain height of 20m then the time taken by the ball to fall is 2 sec and the velocity is 20m/s
Here: s (height) = h =20
a=g=±10m/s
a=10m/s (since it is dropped)
[tex]v^{2} -u^{2} =2as\\v^{2} =2*10*10\\v^{2}= 200[/tex]
(u=0; it is dropped not thrown)
v=20m/s
for calculating time we know,
v=u+at
20= 0+ 10xt
t=20/10
t=2seconds
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each of the following situations involves the flow of heat energy. for each scenario, specify the primary mode (conduction, convection, or radiation) by which the energy is transferred.
For each of these scenarios, the primary method by which heat energy is transferred is:
A) Radiation B) Conduction
C) Convection D) Radiation
E) Conduction F) Convection
G) Radiation H) Convection
What are conduction, convection and radiation?
Conduction, convection and radiation are all methods of heat transfer. Conduction is the transfer of heat between two solid objects in contact. Convection is the transfer of heat by convection currents in fluids (liquids or gases). Liquids and gases on their own don't conduct heat, but when molecules of a fluid are heated up, they move within the medium and carry the heat energy with them. This phenomenon is called convection currents. Radiation is the transfer of heat in a vacuum. Unlike convection and conduction, radiation does not need a material medium for heat to be transferred, as heat is transferred through electromagnetic waves.
For each situation in the question, heat is transferred in one way or another. The methods are:
The hot coffee inside a Thermos bottle to the environment: the primary method of heat transfer here is radiation. From your bare feet to a cold ceramic bathroom floor in the middle of winter: This involves contact between two solid surfaces, your feet and the floor, so it's conductionFrom your body to your hands when you blow on them: The air is warmed up in your body and carried outside your body by convection currents, hence, it's convectionInto your sealed car parked in the sun: Radiation from the sun warms up the earth, including the car that was parked under the sun, thus, it's radiation.From your tongue to a metal railing if you happen to lick it on a cold winter day: This is a case of conduction as your tongue came in contact with the metal railing before heat was transferredFrom a hair dryer to your wet hair: Convection currents enable the warm air to reach your wet hair from the hand dryer, so it's convectionFrom your body on a cold day with no wind: This is radiation. The human body normally emits heat energy in the form of radiation, so in the absence of wind, heat will be transferred from your body to the environment by radiation.From your body on a very windy day: The primary method of heat transfer here is conduction.Learn more about conduction, convection and radiation here:
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Complete question:
Each of the following situations involves the flow of heat energy. For each scenario, specify the primary mode (conduction, convection, or radiation) by which the energy is transferred. a)What is the primary mode of energy transfer from hot coffee inside a Thermos bottle to the environment? b)What is the primary mode of energy transfer from your bare feet to a cold ceramic bathroom floor in the middle of winter? c)What is the primary mode of energy transfer from your body to your hands when you blow on them to warm them? d)What is the primary mode of energy transfer into your sealed car parked in the sun on a hot summer day? e)What is the primary mode of the flow of energy from your tongue to a metal railing if you happen to lick it on a cold winter day? f)what is the primary mode of energy transfer from a hair dryer to your wet hair? g)What is the primary mode of energy transfer from your body on a cold day with no wind? h)What is the primary mode of energy transfer away from your body on a very windy day?
2. Your household electricity system is labeled as 127V/30A. If each electricheater consumes 1600W. How many such heaters can be running at the sametime safely?
We can calculated the maximum power as follows:
[tex]\begin{gathered} P_{Max}=VI \\ so: \\ P_{Max}=(127)(30) \\ P_{Max}=3810W \end{gathered}[/tex]Since the heater consumes 1600W, we can write the following inequality:
[tex]n1600<3810[/tex]Where n is the number of heaters, so:
[tex]\begin{gathered} n<\frac{3810}{1600} \\ n<2.38 \\ so: \\ n\approx2 \end{gathered}[/tex]Answer:
2 heaters
a human expedition lands on an exoplanet. one of the explorers is able to jump a maximum distance of 18.0 m with an initial speed of 2.60 m/s. find the gravitational acceleration on the surface of the exoplanet. assume the planet has a negligible atmosphere. (enter the magnitude in m/s2.)
The gravitational acceleration on the surface of the exoplanet is 0.188 m/s².
Gravitational acceleration has an important role in uniform motion. Uniform motion is an object's motion under acceleration. It should follow the rule
vt = vo + a . t
vt² = vo² + 2a . s
s = vo . t + 1/2 . a . t²
where vt is final velocity, vo is initial velocity, a is acceleration (gravitational acceleration), t is time and s is displacement.
From the question above, we know that
h = 18 m
vo = 2.6 m/s
In this case, the final velocity should be zero. Hence,
vt² = vo² + 2a . s
vt² = vo² - 2g . h
0² = 2.6² - 2.g . 18
36g = 6.76
g = 0.188 m/s²
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A pack of dogs are pulling a wooden sled and rider of combined mass
of 238 kg across dry snow. How much force do the dogs need to apply
to cause the sled to begin to move?
Answer:
FN=-Fg -> Fg=mg -> Fg = 238 kg*9.8 m/s^2 ->
Fg = -2432.4 so FN = 2432.4 -> FF = μs*FN ->
FF = 0.22*2332.4 N -> FF = 513.128 ->
Fapplied > 513.128 N
Explanation:
...
If a man pulls a box with a force of 90 N at an angle of 45
degrees, then what are the X and Y components of the force?
Answer:
See below
Explanation:
x component = 90 cos 45 = 63.6 N
y component = 90 sin 45 = 63.6 N
a 0.24 kg blob of clay is thrown at a wall with an initial velocity of if the clay comes to a stop in what is the average force experienced by the clay?
The - 60.6 N is the average force experienced by the clay.
Define average force.The force applied by a body moving at a constant velocity (rate of speed) over a fixed time period is known as the average force. The magnitude and direction of force are both vector quantities. The term 'average' denotes that this velocity was not precisely measured or was not 'instantaneous.' As a result, the average force over a given time period is equal to the body's mass multiplied by its average velocity. The magnitude and direction of the average force are both vector quantities.
Average acceleration = Δv/t
We know F = ma,
We have m = 0.24
Δv = Final velocity - Initial velocity
Δv = (0 - 23) m/s
Δv = -23 m/s
t = 91 ms or 0.91 s
As we know acceleration (a) = v/t
So, a = -23/0.91
a = - 25.27 m/s²
Put the above value in formula F = ma.
F = (0.24 kg) × (-25.27 m/s²)
F = - 60.6 N
Therefore, the average force experienced by the clay is - 60.6 N.
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The complete question is:
"A 0.24 kg blob of clay is thrown at a wall with an initial velocity of 23 m/s. the clay comes to a stop against the wall in 91 ms, what is the average force experienced by the clay"
at the instant a ball is thrown horizontally with 100m/s, an identical ball is dropped from the same height. which ball hits the ground first? (ignore air resistance) * 1 point a)the horizontally thrown ball b)the dropped ball c)neither - they both hit the ground at the same time d)the horizontally thrown ball never reaches the ground. it keeps circling earth.
option c When a ball is thrown horizontally at 100 m/s, a second ball is dropped from the same height at the exact same moment neither they both hit the ground at the same time .Here gravitational force plays role.
Gravitational force tells if Any two bodies' mutual attraction is directly proportional to the sum of their masses and inversely proportional to the square of their separation. As a "thought experiment," Newton proposed the Newton's cannonball, which supports the idea that gravity is a powerful force that affects planetary motion.
He assumed a cannon on top of a very tall mountain peak in this thinking experiment. If the cannon is loaded with gunpowder and fired, the following situations might occur.
If the cannon's speed is modest, it will fall to Earth in a projectile motion.
If the speed of the cannon is equal to the orbital speed at that altitude, the cannonballNo change in gravity affects the speed of light.
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Write a properly formatted hypothesis statement to answer this question: how does the amount of dissolved salt affect the boiling point of water? specify how you plan to change the independent variable by using terms such as increase or decrease. also, specify how the dependent variable will change in response by using terms such as increase, decrease, or stays the same.
The theory is that:
H0: The amount of salt added to ice has no bearing on how quickly it melts.
H1: The amount of salt added to ice will have an impact on how quickly it melts.
By altering the rate at which salt is introduced to the equation, the independent variable can be modified.
The ice, which is the dependent variable, will alter or melt in response because it will get smaller as the rate at which salt is injected rises.
The boiling point of water, or the temperature at which it may erupt, rises when salt is added to it. For every 58 grams of dissolved salt per kilogram of water, the temperature required to reach boiling rises by around 0.5 C. This is an illustration of an elevated boiling point, which is not just a property of water.
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HELP ILL GIVE BRAINLYIST Compare the interaction between light and two different materials: a reflective glass mirror and a transparent glass block. How did the light behave differently
Answer: See Below
Explanation:
A reflective glass mirror will reflect all the components of white light and not allow visible light to pass through.
A transparent glass block will allow light to pass through with some refraction.
you need to determine the density of a ceramic statue. if you suspended from a spring scale, the scale reads 28.4 n. if you than lower the statue into a tab of water, so that it is completely submerged, the scale reads 17.0 n. what is the statue density?
The density of the ceramic statue is "2495.5 kg/m³".
This question involves the concepts of density, weight, volume, and buoyant force.
First, we will find out the mass of the statue:
W=mg
m=W/g
where,
W = hanging weight of statue = 28.4 N
g = acceleration due to gravity = 9.81 m/s²
Therefore,
28.4/9.81
m= 2.9kg
Now, we will find out the volume of the statue.
The difference, in weight of the statue upon submerging, must be equal to the buoyant force applied by the water. This buoyant force is equal to the weight of the volume of water displaced, which is equal to the volume of the statue.
V = 1.16 x 10⁻³ m³
Density= 2.9/1.16 x 10^-3
=2495.5kg/m^3
Therefore, the stature density is 2495.5 kg/m^3.
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A baseball is thrown at a speed of Vo at an angle of elevation θ. Determine its range (R) in terms of Vo and θ.
The range of baseball thrown at a speed of Vo at an angle of elevation theta is Vo^2sin2theta/g.
What is range and how it comes out to be so ?See we have already studied about projectile in so many instances and in our earlier classes also.Projectile is simply a thing or an object thrown at a speed by the means of external force under the influence of gravity.Range is the maximum height that can be attained by the projectile , that is thrown up.We can also sometimes depict it as the horizontal displacement of the projectile.Whenever we throw a baseball up at sky , there is a launch point , the distance between the launch point and the end point is range.To know more about range visit:
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what's the answer to this question?
Answer:
Energy
Explanation:
Some of the suns energy is converted into wind and water waves
a conductor consists of an infinite number of adjacent wires, each infinitely long and carrying a current i (whose direction is out-ofthe-page), thus forming a conducting plane.
The important Physics chapter "Conductors and Dielectrics in an Electric Field" focuses on the electric field and its interactions with different kinds of materials, such as conductors and dielectrics.
The significance of its components in the electrical circuit is explained in Conductors and Dielectrics in an Electric Field. is a crucial resource component that all students require in order to succeed in the Class 12 Physics exams and admission exams. It is one of the greatest ways to prepare for physics exams and practice problems in order to get good marks. Here, the questions are primarily centered on electric field, current, speed, voltage, and other related concepts.
In-depth explanations are provided for the behavior of conductors and dielectrics. The issues help to strengthen the applicability of the theoretical ideas in daily life and activities.
For clear knowledge and a firm grasp of the syllabus and concept, students aiming for a good mark in a competitive examination must solve every issue provided.
Based on each and every formula, equation, and procedure, there are a variety of difficulties that can be accessed. Each problem's solution is broken down into logical steps and supported with relevant data, formulas, graphs, and equations. All questions based on conductors and dielectrics are readily available to students. This aids in conceptual clarity and full knowledge for kids.
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a dc 2-wire system is to be converted into ac 3-phase, 3-wire system by the addition of a third conductor of the same cross-section as the two existing conductors. calculate the percentage additional load which can now be supplied if the voltage between wires and the percentage loss in the line remain unchanged. assume a balanced load of unity power factor.
The percentage of additional power transmitted is 73.2%.
A conductor is an object or form of fabric that permits the flow of fee in a single or extra instruction. Materials manufactured from steel are not unusual electrical conductors.
A conductor, or electrical conductor, is a substance or fabric that allows energy to drift through it. In a conductor, electric rate carriers, typically electrons or ions, pass without problems from an atom to an atom when voltage is carried out.
IN DC 2-WIRE SYSTEM
If R is the resistance oper conductor,then the power transmitted is
P=VI
And power loss is = I²R
IN AC 3-PHASE 3 WIRE SYSTEM
P=√3VIcos φ
=√3VI [as unity power factor,cos φ=1]
power loss= 3I²R
The percentage of additional power transmitted in a phase 3 wire ststem is
(√3VI-VI )/ VI *100 =73.2%
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A trebuchet is a compound machine. What individual simple machines is it composed of ?
It uses one main simple machine, the lever, to propel a projectile, making it both a compound machine (a device that employs a number of simple machines) and a simple machine.
How Do Trebuchets Work?A trebuchet is a form of catapult, a weapon that can launch things considerably farther than a person can. The usage of trebuchets is first recorded in second-century China, however catapults were in use far before the Roman Empire. Trebuchets are most known for their use in medieval castle raids because they could be placed so far away from the fortress that archers couldn't touch them and could launch practically anything.
They are the most basic techniques that are now understood for using leverage (or mechanical advantage) to increase force. The wheel and axle, inclined plane, lever, wedge, pulley, and screw are examples of rudimentary machines.
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your friends have heard that you took an astronomy class and they need your advice. they plan to get married at sunset, and they want the moon to be high in the sky. what phase should the moon be?
In astronomy class friends plan to get married at sunset, and they want the moon to be high in the sky. The moon should be First Quarter phase.
The study of the cosmos and everything in it that is not within the atmosphere of Earth is referred to as astronomy. Astronomers investigate the locations, movements, and characteristics of celestial objects. Astrology tries to understand how those placements, motions, and qualities impact people and events on Earth. The main distinction between astrology and astronomy is what determines the outcome. The Sun and Moon's effects during a particular zodiac sign are interpreted by the ancient tradition of astrology. 12 divisions of the sky, each measuring precisely 30 degrees, are said to exist in astrology. The scientific community has rejected astrology because it lacks the ability to explain how the cosmos works. The premises and claimed effects described in astrological traditions have not been proven by scientific research to be true.
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PLEASE HELP!!! WILL MARK BRAINLIEST
The environmental impact of the changes in the amount of energy resources is reduction in air pollution.
What are energy resources?Energy resources are the materials that can act as sources of energy which is grouped into two namely:
Renewable energy resources: These are energy resources that can easily be replaced by nature. A typical example is the solar energy.Non renewable energy resources: These are energy resources that cannot easily be replaced by nature. Examples include coal, nuclear and gas.From the given figures,
In 2014 renewable energy = 19%; while in 2015 it is = 25%
In 2014 non renewable energy when added = 79%; while in 2015 it is = 73%
This shows that there was reduction in the use of non renewable energy from 2014 to 2015 by 6%.
This would affect the environment positively as there would be reduction in air pollution caused by non renewable energy resources.
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a ball of mass m collides completely inelastically in one dimension with another ball of mass 3m that is initially at rest (the balls stick together after the collision). what fraction of the initial kinetic energy is lost in the collision
Fraction of the initial kinetic energy is lost in the collision f = 3/4.
Two balls of masses M and 3M kinetic energy
Initially before collision:
Speed of ball of mass M = −V0 (Right direction is taken as negative)
Speed of ball of mass 3M = +V0
Finally after collision: Speed of ball of mass M = v
Speed of ball of mass 3M = V02
[tex]Finding the fraction(f) of initial kinetic energy lost in the collisionf=1−Final Kinetic EnergyInitial Kinetic Energyf=1−12×M×(v02)2+12×3M×(v02)212×M×(−v0)2+12×3M×(v0)2f=1−v024v02f=1−14=34[/tex]
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problem 4: a disk of mass m and radius r, a hoop of mass 2m and radius r, and a ball of mass m and radius 2r are rolling without slipping. the hoop can be treated as a thin ring and the ball should be modeled as a hollow sphere.
a. Angular speed, w = v/r where v is the linear speed, r is the radius
b. v = w*r
c. I(disk)=1/2mr^2,I(hoop)=mr^2, I(Ball)=8/3mr^2 disk is the smallest moment of inertia.
A body has an attribute called inertia that makes it resist attempts to move it or, if it is already moving, to alter the speed or direction of its motion. A body's inertia is a passive characteristic that prevents it from doing anything other than opposing active agents like forces and torques. A moving body continues to move not because of its inertia but rather because no force exists to stop it, alter its direction, or accelerate it.
A body's moment of inertia, which quantifies its resistance to the action of a force, and its mass, which determines how resistant it is to the action of a force, are two numerical measures of inertia.
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Newton's First Law
A lantern of mass m is suspended by a string that is tied to two other strings, as shown
in the figure below. The free-body diagram shows the forces exerted by the three
strings on the knot.
F₂
Fy
0₂
¥
F₁
1. In terms of F₁, F2, and F3, what is the net force acting on the knot?
(Hint: The lantern is in equilibrium.)
2. Find the magnitudes of the x and y components for each force acting on the knot.
(Assume the positive directions are to the right and up.)
String 1 (F₁)
x component
y component
String 2 (F₂)
x component
y component
String 3 (F3)
x component
y component
3. In terms of F1, F2, and F3, what is the magnitude of the net force acting on the
knot in the x direction? in the y direction?
Fx net=
Fynet
=
. Assume that 8₁ = 30°, ₂ = 60°, and the mass of the lantern is 2.1 kg. Find,
F1, F2 and F3.
F₁=
F₂=
F3 =
Answer:
1. If the knot is in equilibrium - no net force acts on the knot.
2. F1x = 0 F1y = -F1
F2x = -F2 cos θ1 F2y = F2 sin θ1
F3x = F3 cos θ2 F3 = sin θ2
3. Fx net = 0
Fy net = 0 for equilibrium to occur
4. F2 cos θ1 = F3 cos θ2
F1 = M g = 2.1 * 9.8 = 20.6 N
F2 sin 30 + F3 sin 60 = 20.6 balancing forces in y-direction
or .5 F2 + .866 F3 = 20.6 (use this equation below ) (I)
F2 cos 30 = F3 cos 60 as stated above
.866 F2 = .5 F3 or F3 = 1.732 F2 substituting for θ
.5 F2 + .866 (1.732 F2) = 20.6 using (I) above
2.0 F2 = 20.6 and
F2 = 10.3 N
F3 = 1.732 * 10.3 = 17.8 N
Check:
10.3 * .866 = .5 * 17.8 using values above
8.92 = 8.9 forces balance
Also .5 * 10.3 + .866 (1.732 * 10.3) = 20.6
suppose that the resistance between the walls of a biological cell is 1.00 109 ω. (a) what is the current when the potential difference between the walls is 45 mv?
The current when the potential difference between the walls is 45 mv is 4.500×10⁻¹¹ A.
To find the current when the potential difference between the walls is 45 mv, we will Use Ohm's law.
V = IR ........................ Eqn 1
Where
V = Potential difference between the walls
I = current
R = Resistance between the walls
Make I the subject of the equation
I = V/R...................... Eqn 2
From the question, we are given that:
V = 45 mV = 0.045 V
R = 1.0×10⁹ Ω.
Substitute into Eqn 2
I = 0.045/(1.0×10⁹)
I = 4.500×10⁻¹¹ A.
Learn more about Ohm's law from:
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