18 cm is correct .
Step-by-step explanation:
The sum of two smaller sides is greater that the largest side.
It is given that the two sides of a triangle measure 8 cm and 15 cm.
Case 1: Let 8 cm and 15 cm. are smaller side. So,
Third side < 8 + 15
Third side < 23
It means 3rd side must be less than 23
Case 2: Let 15 cm is the largest side.
15 < Third side + 8
15 - 8 < Third side
7 < Third side
It means 3rd side must be greater than 7.
Since only 18 is less than 23 and greater than 7, therefore the possible length of third sides is 18 cm and option 2 is correct.
Find the probability using the normal distribution: P(0 P(0
The probabilities are:
P(0 < z < 1.96) = 0.4750
P(-1.23 < z < 0) = 0.3907
P(z > 0.82) = 0.2061
P(z < -1.77) = 0.0384
P(-0.20 < z < 1.56) = 0.5199
P(1.12 < z < 1.43) =0.0550
P(z > -1.43) = 0.9236
To locate the chances of the usage of the same old ordinary distribution, we will use a well-known normal desk or a calculator. Here are the calculations for the given possibilities:
P(0 < z < 1.96):
Using the standard everyday desk, the place to the left of one.Ninety-six is 0.9750, and the vicinity to the left of zero is 0.5000. Therefore, the chance between zero and 1.96 is:
P(0 < z < 1.96) = 0.9750 - 0.5000 = 0.4750
P(-1.23 < z < 0):
Using the usual ordinary table, the vicinity to the left of -1.23 is 0.1093, and the area to the left of zero is zero.5000. Therefore, the possibility between -1.23 and 0 is:
P(-1.23 < z < 0) = 0.5000 - 0.1093 = 0.3907
P(z > 0.82):
Using the standard everyday table, the region to the left of zero.82 is zero.7939. Therefore, the possibility of z being extra than 0.82 is:
P(z > 0.82) = 1 - 0.7939 = 0.2061
P(z < -1.77):
Using the same old regular desk, the vicinity to the left of -1.Seventy-seven is zero.0384. Therefore, the chance of z being much less than -1.77 is:
P(z < -1.77) = 0.0384
P(-zero.20 < z < 1.56):
Using the standard ordinary desk, the area to the left of -0.20 is 0.4207, and the area to the left of 1.56 is 0.9406. Therefore, the opportunity between -0.20 and 1. Fifty-six is:
P(-0.20 < z < 1.56) = 0.9406 - 0.4207 = 0.5199
P(1.12 < z < 1.43):
Using the standard regular desk, the place to the left of 1.12 is 0.8686, and the location to the left of one. Forty-three is zero.9236. Therefore, the opportunity between 1.12 and 1. Forty-three is:
P(1.12 < z < 1.43) = 0.9236 - 0.8686 = 0.0550
P(z > -1.43):
Using the same old normal desk, the location to the left of -1.43 is zero.0764. Therefore, the possibility of z being greater than -1. Forty-three is:
P(z > -1.43) = 1 - 0.0764 = 0.9236
Please word that the chances are rounded to 4 decimal locations for clarity.
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The correct question is:
"Find the probability using the standard normal distribution. P(0 < z <1.96), P(-1.23 < z < 0), P(z > 0.82), P(z < -1.77), P(-0.20 < z < 1.56), P(1.12 < z < 1.43), P(z > -1.43)"
HELP PWEASEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE
Answer:
rap music
Step-by-step explanation:
^
Answer:
i’m not sure if these are right or not but
Step-by-step explanation:
the first one is no
i think the second one is no
i think the third one is yes
i think the fourth one is yes
i am not sure and i’m REALLY sorry if its wrong
Let p(x)=x+3x²-4x-12 a) Find the x-intercepts of the graph of p(x) c) Sketch a graph of p(x) b) Find the y-intercept of the graph of p(x)
a) The x-intercepts of p(x) are x = 3 and x = -4/3. b) The y-intercept of p(x) is y = -12.
a) To find the x-intercepts, we set p(x) = 0 and solve for x:
x + 3x² - 4x - 12 = 0
Simplifying the equation, we get:
3x² - 3x - 12 = 0
Factoring, we have:
(x - 3)(3x + 4) = 0
Setting each factor equal to zero, we find the x-intercepts:
x = 3 and x = -4/3
b) The y-intercept is the value of p(0), so we substitute x = 0 into the equation:
p(0) = 0 + 3(0)² - 4(0) - 12 = -12
Therefore, the y-intercept is -12.
c) To sketch the graph, we plot the x-intercepts (x = 3 and x = -4/3) and the y-intercept (y = -12) on a coordinate plane.
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Wiseman Video plans to make four annual deposits of $2,000 each to a special building fund. The fund’s assets will be invested in mortgage instruments expected to pay interest at 12% on the fund’s balance. (FV of $1, PV of $1, FVA of $1, PVA of $1, FVAD of $1 and PVAD of $1) (Use appropriate factor(s) from the tables provided.)
Using the appropriate annuity table, determine how much will be accumulated in the fund on December 31, 2019, under each of the following situations.
1. The first deposit is made on December 31, 2016, and interest is compounded annually.
Table or calculator function: FVA of $1
Payment: $2,000
n = 4
i = 12%
Fund balance 12/31/2019: $9,559
2. The first deposit is made on December 31, 2015, and interest is compounded annually.
Table or calculator function: FVAD of $1
Payment: $2,000
n = 4
i = 12%
Fund balance 12/31/2019: $10,706
3. The first deposit is made on December 31, 2015, and interest is compounded quarterly.
Using the FV of $1 chart, calculate the fund balance:
Deposit Date i = n = Deposit Fund Balance 12/31/2019
12/31/2015 3% 16 $2,000 $3,209
12/31/2016 3% 12 2,000 2,852
12/31/2017 3% 8 2,000 2,534
12/31/2018 3% 4 2,000 2,251
$10,846
4. The first deposit is made on December 31, 2015, interest is compounded annually, and interest earned is withdrawn at the end of each year.
Deposit Amount No. of Payments Interest left in Fund Fund Balance 12/31/2019
$2,000 $8,000
The fund balance at the end of 2019 will be $8,000.
The given problem has four different parts, where we are supposed to calculate the accumulation of funds at the end of 2019 in different scenarios.
Scenario 1In the first scenario, the first deposit is made on December 31, 2016, and interest is compounded annually.
Using the FVA of $1 table; Payment: $2,000n = 4i = 12%
Fund balance 12/31/2019: $9,559
Hence, the fund balance at the end of 2019 will be $9,559.Scenario 2In the second scenario, the first deposit is made on December 31, 2015, and interest is compounded annually.
Using the FVAD of $1 table;Payment: $2,000n = 4i = 12%
Fund balance 12/31/2019: $10,706 Therefore, the fund balance at the end of 2019 will be $10,706.Scenario 3In the third scenario, the first deposit is made on December 31, 2015, and interest is compounded quarterly. Using the FV of the $1 chart, we get the following calculation:
Deposit Date i = n = Deposit Fund Balance 12/31/2015 3% 16 $2,000 $3,20912/31/2016 3% 12 $2,000 $2,85212/31/2017 3% 8 $2,000 $2,53412/31/2018 3% 4 $2,000 $2,251
The interest rate is 3%, and the payment is $2,000. Hence, the fund balance at the end of 2019 will be $10,846.Scenario 4In the fourth scenario, the first deposit is made on December 31, 2015, interest is compounded annually, and interest earned is withdrawn at the end of each year.
Deposit Amount No. of Payments Interest left in Fund Fund Balance 12/31/2019$2,000 $8,000 Hence, the fund balance at the end of 2019 will be $8,000.
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Use Strong Induction to prove that: If p + 1/p E N, then Pn+1/Pn EN for all nEN.
We prove with the help of Strong Induction.
Let P(n) be the statement that Pn+1/Pn E N.
In order to prove this statement, we will utilize strong induction.So we are given that p + 1/p E N. We will show that P(n) is true for all n >= 1.
Let's consider the base case
P(1):P2/P1 = (p + 1/p)^2 - 2 = (p^2 + 2 + 1/p^2) - 2p/p = (p^2 + 1/p^2) - (2p - 2/p)
Since p + 1/p E N, both p and 1/p must be integers.
Hence, p^2 and 1/p^2 are also integers. This implies that (p^2 + 1/p^2) is an integer.
It only remains to show that (2p - 2/p) is an integer. This is equivalent to showing that 2p^2 - 2 E 0 mod p. But this is clearly true, since 2p^2 - 2 = 2(p^2 - 1) and p^2 - 1 is divisible by p.
Let's assume that P(k) is true for all k such that 1 <= k <= n. We need to prove that P(n+1) is true as well.
Now we need to prove that P(n+1) is true. In other words, we need to show that P(n+2)/P(n+1) E N, assuming that P(n+1)/P(n) E N and P(n)/P(n-1) E N.
Using the definition of P(n), we have:P(n+1)/P(n) E N and P(n)/P(n-1) E N imply that P(n+1) = aP(n) and P(n) = bP(n-1) for some integers a and b. Then:P(n+2)/P(n+1) = (P(n+2)/P(n+1)) * (P(n)/P(n)) = (P(n+2)P(n))/(P(n+1)P(n)) = (aP(n+1)P(n))/(bP(n)P(n+1)) = a/bIf we can show that a/b E N, then P(n+2)/P(n+1) E N, and P(n+1) satisfies the inductive hypothesis.
But this follows from the fact that a and b are integers and the product of two integers is always an integer.
Hence, P(n+1) is true for all n >= 1, by strong induction.Therefore, by strong induction, we have proved that if p + 1/p E N, then Pn+1/Pn EN for all nEN.
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a man sold an article at a gain of 5 percent if it had sold for rs 16.30 less he would have suffered a loss of 5 percent find the cost price?
Answer:
Step-by-step explanation:
let CP of the article = x
at 5% gain, SP of article = x + (5/100)x = 1.05x
at 5% loss, SP of article = x - (5/100)x = 0.95x
given that 1.05x - 0.95x = 16.5
⇒ 0.1x = 16.5
⇒ x = 16.5/0.1
⇒ x = Rs. 165.
The cost price of the article is Rs. 165.
38 − 7x = −2(x − 29)
Answer:
x = -4Step-by-step explanation:
38 − 7x = −2(x − 29)
=> 38 - 7x = -2x + 58
=> 38 - 58 = 7x - 2x
=> -20 = 5x
[tex] = > x = \frac{ - 20}{5} [/tex]
=> x = -4 (Ans)
plz help fast!!!!!!!!!!!!!!!!!!!!!
Answer:
D) 156/100 = n/70
Step-by-step explanation:
n = 156% of 70
% indicates a fraction over 100.
"of" indicates multiplication.
n = 156/100 • 70
Let's divide both sides by 70 to have one fraction one each side.
n/70 = 156/100
This is equal to D) [tex](\frac{156}{100}) = (\frac{n}{70})[/tex]
please answer this i will mark brainliest
Answer:
The median is 2
Step-by-step explanation:
Arrange your numbers in numerical order.
0011112233445
Count how many numbers you have.
If you have an odd number, divide by 2 and round up to get the position of the median number.
If you have an even number, divide by 2. Go to the number in that position and average it with the number in the next higher position to get the median.
PLEASE MARK ME BRAINLIEST
Let be an equivalence relation on a set S, and let a, b e S. Show that two equivalence classes under ~ are either equal or disjoint, i.e. either [a] = [b] or [a] n [b] = 0.
Given, an equivalence relation ~ on a set S. Let a and b be two elements in the set S. Assuming that [a] and [b] are two equivalence classes under the equivalence relation ~. Now we need to prove that either [a] = [b] or [a] ∩ [b] = ∅ (disjoint).
Proof:If [a] and [b] are not equal, then there must be some element c in the intersection of the equivalence classes [a] and [b]. i.e, c belongs to [a] and c belongs to [b].Thus, [a] ∩ [b] is not empty.
Let x be an element in [a], then x~a, and a~c (since c belongs to [a]) and hence x~c. So, x belongs to [c] which implies that [a] is a subset of [c].Now, let y be an element in [b], then y~b, and b~c (since c belongs to [b]) and hence y~c. So, y belongs to [c] which implies that [b] is a subset of [c].Thus, both [a] and [b] are subsets of [c].
Therefore, if [a] and [b] are not equal, then [a] and [b] are both subsets of [c] and hence the intersection of [a] and [b] is not empty. Thus, [a] and [b] are not disjoint. Hence, the proof by contradiction.
Conversely, if [a] and [b] are disjoint, then [a] ∩ [b] = ∅. And thus, [a] is not equal to [b].Therefore, two equivalence classes under the equivalence relation ~ are either equal or disjoint.
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The blood results for a particular sample unknown test from ten finalists of a medical study were recorded for further analysis. Find the following quantities below.
Blood test results: {580, 610, 530, 530, 440, 670, 480, 540, 590, 490 }
(Use only 2 decimal places. Ex. if answer is 34.568, just write 34.56. If the answer is 321 just leave as 321, do not add any decimals)
a) Mean _______
(b) Median______
(c) Mode________
(d) Range________
(e) Variance ________
(f) Standard deviation_______
(g) IQR ______
(h) Upper fence ________
Answer:
(a) Mean = 541.00
(b) Median = 535.00
(c) Mode: 530
(d) Range = 230
(e) Variance = 5340.40
(f) Standard deviation = 73.10
(g) IQR = 100
(h) Upper fence = 740.00
Step-by-step explanation:
Please help me, GodBless.
Answer:
Rate of change is 1
Step-by-step explanation:
Well rate of change in a function is basically slope
theres 1 rise and.1 run
1/1=1
So rate of change is 1
This trapezoid is made up of two right triangles and one rectangle.
Drag numbers to show the area of each triangle and the area of the rectangle. Then drag a number to show the total area of the trapezoid.
30 PIONT IF YOU ANSWER
9514 1404 393
Answer:
each triangle: 29.75 in²rectangle: 374 in²total area: 433.5 in²Step-by-step explanation:
The base of each triangle is half the difference between the bases of the trapezoid:
(29 in -22 in)/2 = 7 in/2 = 3.5 in
The area of the triangle is given by the formula ...
A = 1/2bh
A = 1/2(3.5 in)(17 in) = 29.75 in² . . . triangle area
__
The area of the central rectangle is the product of its base and height.
A = bh = (22 in)(17 in) = 374 in² . . . rectangle area
__
The total area of the trapezoid is the sum of the areas of the two triangles and the area of the rectangle.
total area = 2(29.75 in²) + 374 in² = 433.5 in² . . . total trapezoid area
You are a civil engineer designing a bridge. The walkway needs to be made of wooden planks. You are able to use either Sitka spruce planks (which weigh 3 pounds each), basswood planks (which weigh 4 pounds each), or a combination of both. The total weight of the planks must be between 600 and 900 pounds in order to meet safety code. If Sitka spruce planks cost $3.25 each and basswood planks cost $3.75 each, how many of each plank should you use to minimize cost while still meeting building code?
The optimal solution to minimize cost while meeting the building code is to use 0 Sitka spruce planks and 150 basswood planks.
How to Minimize Cost Using Function Equations?To minimize the cost while meeting the building code, let's assume we use x Sitka spruce planks and y basswood planks.
We want to minimize the cost, so our objective function is the cost of the planks. The cost is given by:
Cost = 3.25x + 3.75y
We also have the constraint that the total weight of the planks must be between 600 and 900 pounds:
3x + 4y ≥ 600
3x + 4y ≤ 900
To solve this optimization problem, we can use linear programming. We'll use the Simplex method to find the optimal solution.
Let's rewrite the constraints in standard form:
-3x - 4y ≤ -600
3x + 4y ≤ 900
Now we have the following system of equations:
-3x - 4y ≤ -600
3x + 4y ≤ 900
The feasible region is a quadrilateral with vertices at (0, 150), (0, 225), (300, 150), and (225, 0).
To minimize the cost, we need to find the corner point of the feasible region that lies on the cost line, which is given by 3.25x + 3.75y.
Let's evaluate the cost at each corner point:
Cost at (0, 150) = 3.25(0) + 3.75(150) = 562.50
Cost at (0, 225) = 3.25(0) + 3.75(225) = 843.75
Cost at (300, 150) = 3.25(300) + 3.75(150) = 1500.00
Cost at (225, 0) = 3.25(225) + 3.75(0) = 731.25
From the evaluations, we can see that the minimum cost is achieved at (0, 150), which means we should use 0 Sitka spruce planks and 150 basswood planks.
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Make r the subject of x=e+r/d
Answer:
r = dx - de
Step-by-step explanation:
x = e + r/d
x - e = r/d
d (x - e) = r
dx- de = r
r = dx - de
What is the smallest solution to the equation 3x2 - 16 = 131?
Answer:
7,-7 are the solutions
Step-by-step explanation:
Not a perfect square so its
+-7
I would go with -7 since its the lowest amount
Answer:
-7
Step-by-step explanation:
Last year, a marketing research company estimated Amazon Prime members spent $1,825 on Amazon.com. The company believes that due to the pandemic. Amazon Prime members have spent more on average at Amazon.com compared to last year. They take a sample of 150 Amazon Prime members to test their belief. These sample members spent an average of $1,950. Assume the population standard deviation is $600.
Specify the hypotheses.
Null hypothesis (H0): µ ≤ 1825, the alternative hypothesis is µ > 1825.
The hypotheses are given below:
Null hypothesis (H0): µ ≤ 1825
Alternative hypothesis (Ha): µ > 1825 where µ represents the population mean amount spent by Amazon Prime members on Amazon.com.
As given in the question, the company believes that due to the pandemic, Amazon Prime members have spent more on average at Amazon.com compared to last year.
Therefore, the alternative hypothesis is µ > 1825.
The null hypothesis is that there is no significant difference or increases in the mean amount spent on Amazon.com by Amazon Prime members last year and this year or that the mean amount spent this year is less than or equal to that of last year, which is µ ≤ 1825.
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I NEEED HELP match the equation with the term it belongs to. 3.14 *r *r. 2* 3.14 *r
Answer:
3.14 * r * r = area of circle, 2 * 3.14 * r = circumference
Step-by-step explanation:
Remember these formulas, very important.
A standard test of intelligence is scaled so that the mean IQ is 100, and the standard deviation is 15. If there are 40,00 people in a certain town , what is the percentage of people who have an IQ between 70 and 130 ?
a. 47.5%
b. 95%
c. 68 %
d. 99.7
The correct option to the sentence "The percentage of people who have an IQ between 70 and 130 ?" is:
b. 95%.
To solve for the percentage of people who have an IQ between 70 and 130, we will have to use the standard deviation and the mean IQ.
It is given that: Mean = 100, Standard deviation = 15
Now we will use these values to find the percentage of people who have an IQ between 70 and 130.
The first step to this process is to standardize the IQ scores by converting them to Z-scores.
The formula for Z-score is:
Z = (X - µ) / σ, where X represents the IQ score, µ represents the mean IQ, and σ represents the standard deviation.
IQ score of 70:
Z = (70 - 100) / 15
Z = -2
IQ score of 130:
Z = (130 - 100) / 15
Z = 2
Now that we have the Z-scores for IQ scores of 70 and 130, we can find the percentage of people who have an IQ between these two scores. We will use the Z-table to do this. The Z-table provides the area under the standard normal distribution curve for a given Z-score.
From the Z-table, we can find that the area under the curve between Z = -2 and Z = 2 is approximately 0.9545. This means that approximately 95.45% of people have an IQ between 70 and 130.
Therefore, the correct option is: b. 95%.
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Compute r''(t) and r'''(t) for the following function. r(t) = (9t² +6,t + 5,6) Find r'(t). r(t) = 0.00
The derivatives of the vector function are r'(t) = (18 · t, 1, 0), r''(t) = (18, 0, 0) and r'''(t) = (0, 0, 0).
How to determine the first three derivatives in a vector functionIn this question we find the definition of a vector function in terms of time, whose first, second and third derivatives must be found. This can be done by using derivative rules several times. First, define the vector function:
r(t) = (9 · t² + 6, t + 5, 6)
Second, find the first derivative:
r'(t) = (18 · t, 1, 0)
Third, find the second derivative:
r''(t) = (18, 0, 0)
Fourth, find the third derivative:
r'''(t) = (0, 0, 0)
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HELPPP PLSSS Choose the most appropriate translation of the English sentence.
The radius of a balloon (which depends on the amount of air inside) is 3
inches.
Answer:
A radius(radius) = 3The radius of a balloon (which depends on the amount of air inside) is 3
inches
The G.M and H.M between two number are respectively 9 & 5.4. Find the numbers.
Answer:
The numbers are 3 and 27.
Step-by-step explanation:
The explanation is attached below.
If a researcher wants to determine if there is a linear relationship between the number of hours a person goes without sleep and the number of mistakes he makes on a simple test. The following data is recorded.
n = 4, Σx = 20, Σy = 25, Σxy = 144 & Σx² = 120.
Find the equation of the regression line:
y = a + bx. y = (a = ____) + (b = _____)x.
b = [n(Σxy) - (Σx)(Σy)] / [n(Σx²) - (Σx)²] = ____
a = [(Σy)(Σx²) - (Σx)(Σxy)] / [n(Σx²) - (Σx)²] = _____
The equation of the regression line is: y = 1.5 + 0.95x
How to find the equation of the regression lineTo find the equation of the regression line, we can use the formulas:
b = [n(Σxy) - (Σx)(Σy)] / [n(Σx²) - (Σx)²]
a = [(Σy)(Σx²) - (Σx)(Σxy)] / [n(Σx²) - (Σx)²]
Given the following data:
n = 4
Σx = 20
Σy = 25
Σxy = 144
Σx² = 120
Let's calculate the values step by step:
b = [4(144) - (20)(25)] / [4(120) - (20)²]
= (576 - 500) / (480 - 400)
= 76 / 80
= 0.95
a = [(25)(120) - (20)(144)] / [4(120) - (20)²]
= (3000 - 2880) / (480 - 400)
= 120 / 80
= 1.5
Therefore, the equation of the regression line is:
y = 1.5 + 0.95x
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What’s the website in this image called?
Find the measurements of DBC
Answer:
72 degrees
Step-by-step explanation:
To determine the value of DBC, we first have to determine the value of q
Angle on a straight line = 180 degrees
7q - 46 + 3q + 6 = 180
10q - 40 = 180
collect like terms
10q = 180 + 40
10q = 220
q = 22
Substitute for q in angle dbc
3(22) + 6 = 72 degrees
A 5 meter ladder is leaning against a house when its base starts to slide away. By the time the base is 3 meter from the house, the base is moving at the rate of 2 m/sec. (a) How fast is the top of the ladder sliding down the wall then? (b) At what rate is the angle between the ladder and the ground changing then?
(a) The top of the ladder is sliding down the wall at a rate of 3/2 m/sec.
(b) The angle between the ladder and the ground is changing at a rate of 1/2 rad/sec.
To solve this problem, we can use related rates, considering the ladder as a right triangle formed by the ladder itself, the wall, and the ground.
Let's denote:
x: the distance from the base of the ladder to the house (in meters)
y: the height of the ladder on the wall (in meters)
θ: the angle between the ladder and the ground (in radians)
Given:
dx/dt = -2 m/sec (the rate at which the base of the ladder is moving away from the house)
Using the Pythagorean theorem, we have:
x^2 + y^2 = 5^2 (since the ladder has a length of 5 meters)
Taking the derivative of both sides with respect to time (t), we get:
2x(dx/dt) + 2y(dy/dt) = 0
(a) To find dy/dt:
We can solve the equation above for dy/dt:
2x(dx/dt) + 2y(dy/dt) = 0
2(3)(-2) + 2y(dy/dt) = 0 (substituting x = 3 and dx/dt = -2)
-12 + 2y(dy/dt) = 0
2y(dy/dt) = 12
dy/dt = 12/(2y)
dy/dt = 6/y
Now, we need to find y. Using the Pythagorean theorem again:
x^2 + y^2 = 5^2
3^2 + y^2 = 5^2
9 + y^2 = 25
y^2 = 25 - 9
y^2 = 16
y = 4 (taking the positive value as y represents a length)
Substituting y = 4 into dy/dt = 6/y:
dy/dt = 6/4
dy/dt = 3/2 m/sec
Therefore, the top of the ladder is sliding down the wall at a rate of 3/2 m/sec.
(b) To find dθ/dt:
We can use trigonometry to relate θ, x, and y:
tan(θ) = y/x
Differentiating both sides with respect to time (t), we get:
sec^2(θ)dθ/dt = (x(dy/dt) - y(dx/dt))/x^2
Substituting the given values:
sec^2(θ)dθ/dt = (3(3/2) - 4(-2))/3^2
sec^2(θ)dθ/dt = (9/2 + 8)/9
sec^2(θ)dθ/dt = (25/2)/9
sec^2(θ)dθ/dt = 25/18
Since sec^2(θ) is equal to 1 + tan^2(θ) and tan(θ) = y/x:
sec^2(θ) = 1 + (y/x)^2
sec^2(θ) = 1 + (4/3)^2
sec^2(θ) = 1 + 16/9
sec^2(θ) = (9 + 16)/9
sec^2(θ) = 25/9
Substituting sec^2(θ) = 25/9 into the equation:
(25/9)dθ/dt = 25/18
Simplifying and solving for dθ/dt:
dθ/dt = (25/18) * (9/25)
dθ/dt = 1/2 rad/sec
Therefore, (b) the angle between the ladder and the ground is changing at a rate of 1/2 rad/sec.
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Simplify.
+6 - 4 =
please help ..........
Answer:
2
Step-by-step explanation:
it's literally 6-4 = 2
Answer: 2
Step-by-step explanation: +6 is simply 6 and 6-4 is 2.
Solve each inequality.
2s+5> 49
_
Answer: S > 22
Step-by-step explanation:
Answer:
s = 23 and above
Step-by-step explanation:
2s + 5 > 49
-5 -5
2s > 44
44/2
= 22
However, the answer for s is not 22
Since it has this sign > not ≥ then that means s = 23 and above
Check:
2(23) + 5 > 49
46 + 5 > 49
51 > 49
There are 40 batteries in 10 packs.
Gavin wants to know how many batteries are in 1 pack.
Kylie wants to know how many batteries are in 5 packs.
Drag an expression to answer each question.
Help me Please I would appreciate your help!
:-):-):-):-):-)
Step-by-step explanation:
1) 40÷10
2) 40÷2
You invest $32,000 in an account that earns 5.75% interest compounded yearly. What is
the total amount of money you will have in the account after 20 years if you never
deposit any additional funds?
Answer:
$97,894.33.
Step-by-step explanation