Two pipes of identical diameter and material are connected in parallel. The length of pipe A is three times the length of pipe B. Assuming the flow is fully turbulent in both pipes and thus the friction factor is independent of the Reynolds number and disregarding minor losses, determine the ratio of the flow rates in the two pipes.

Thus, the statement 'the buoyant force on the block exerted by the water is equal to the weight of the volume of water displaced by the block' is correct.

In the figure, (FB)block is buoyant force on block, (FB)steel is buoyant force on steel object, Wsteel is weight of the steel object, Wblock is weight of the steel block, and 7 is tension in the string. is

Weight of an object acts always in downwards.

Buoyant force on an object which is placed in a fluid is always upward direction. When the buoyant force is equal to the weight of the object, then the object floats in the fluid.

From the Archimedes principle, the buoyant force exerted by a fluid on an object which is placed in it is equal to the weight of the fluid displaced by the object.

Thus, the statement 'the buoyant force on the block exerted by the water is equal to the weight of the volume of water displaced by the block' is correct.

When the block is floating, the buoyance force supported by the water is equal to the total weight of the block and steel object. Thus, the statement the buoyant force on the block is equal to its weight is not correct.

As the steel object is at rest in the water, then the net force acting on it is zero.

(F ret )steel  =0

T+(F B ) steel -W steel =0 W steel =T+(F B ) steel

Therefore,

T<W steel

Thus, the statement tension in the string is less than weight of the steel object is correct.

If the weight of the steel object is equal to the buoyant force, then the tension in the string should be zero. But the steel object is hanging with the string, so tension never is zero.

Thus, the statement 'the buoyant force on the steel object is equal to its weight' is not correct.

If the tension in the string is equal to the weight of the steel object, then the buoyant force on the steel object should be zero. But any object in a fluid should experiences the buoyant force.

Thus, the statement 'the tension in the string is equal to the weight of the steel object' is not correct.

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The period of oscillation of the Taipei 101 building is 13 seconds .

In the question ,

it is given that ,

the length of the cables(L) is = 42 m

the mass of the mass damper is = 660000 Kg ,

the amplitude is = 75 cm = 0.75 m

we know that the acceleration due to gravity(g) is = 9.8 .

the formula for the Time Period (T) is

T = 2π√(L/g)

Substituting the values ,

we get ,

T = 2π√(42/9.8)

Simplifying further ,

we get ,

T = 13.00079 seconds

T ≈ 13 seconds .

Therefore , the period of oscillation is = 13 seconds .

The given question is incomplete , the complete question is

Taipei 101 (a 101-story building in Taiwan) is sited in an area that is prone to earthquakes and typhoons, both of which can lead to dangerous oscillations of the building. to reduce the maximum amplitude, the building has a tuned mass damper, a 660,000 kg mass suspended from 42-m-long cables that oscillates at the same natural frequency as the building . when the building sways, the pendulum swings, reaching an amplitude of 75 cm in strong winds or tremors. damping the motion of the mass reduces the maximum amplitude of oscillation of the building .

What is the period of oscillation of the building?

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The specific heat of a metal is 54.89J/kg.K

What does "specific heat" mean?

Specific heat is the amount of energy needed to raise a substance's temperature by one degree Celsius per gram. Typically, the units of specific heat are calories or joules per gram per degree Celsius.

Given: The bottle weighs 3.6 kg and holds 13.5 kg of water.

The weight of the metal is 1.8 kg, and its initial temperature is 175 C.

From 16 to 18 degrees Celsius, the temperature rises.

The container and water both received the same amount of heat from the metal object.

Qp = Qw +Qc

​(mp)cΔT= (mw)(cw)ΔT + (mc)cΔT

where, respectively, p, w, and c stand for a metal object, a liquid, and a container.

c = [(mw)(cw)ΔT] / [(mp)cΔT -  (mc)cΔT]

  =[ 13.5*4187*(18-16) ] / [1.8*(175-16) - 3.6* (18-16)]

  =  54.89J/kg.K

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At touchdown, the flaps' lift coefficient reaches its maximum of 1.8. Upon touchdown, there is a 279-meter zero lift drag.

Vt = 1.8 Vtotal = 1.8 [tex]\sqrt{2w/PSc}[/tex]

Pg = 1.225 kg/m³

1.8 [tex]\sqrt{2* 105000/1.225*50*3}[/tex] = 61.02

V = 0,7 Vt = 0.7 *61.02 = 42.714

After touch down L = 0,

Drag = 1/2 *1.225 *30 *30 *50*0.05 = 1448

Sl = 1.69 * 105000² / 9.81 * 61.02*50*3[1448 + 0.02*105000]

Sl = 279m

The zero-lift drag coefficient and the lift-induced drag coefficient factor, respectively, are denoted by CD0 and k. Under a particular aircraft aerodynamic configuration, the values of both parameters are taken to be constants. Flight can be accomplished without drag. However, without removing air, it is impossible to completely eliminate drag during flight. Although it is not entirely necessary for flight, an airplane that achieves lift will always experience some form of drag because air is required to produce lift. Increasing the zero-lift drag coefficient Cd0 has the effect of raising (TR)min while lowering the velocity at which it occurs. When the drag-due-to-lift factor K is raised, the result is an increase in (TR)min and an increase in the velocity at.

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The measurement is 15.21 meters. When the jumper is at its maximum elongation, the cord will be extended by 85.21 m.

In light of this,

h=100 m bridge height

30 meters in length

40 N/m spring constant

Weight = 80 kg Assume we need to determine the distance at which the cord reaches its maximum elongation.

We must compute the distance.

We must compute the gravitational potential energy.

Using the gravitational potential energy formula

We must compute the value of x.

When the jumper is at its maximum elongation, the cord will be extended by 85.21 m. We must compute the distance. The negative symbol indicates the depth of the water.

As a result, the distance is 15.21 m.

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V(x, Y, Z) = 16Vo/pi2 is the potential inside the pipe. (-pi(m/a)2 + (n/b)2)1/2) sin (m*piy/a)sin (n*pi*Z/b). Because only one end of a rectangular metal pipe with sides a and b is grounded at x = 0.

Simply said, potential difference is the difference in electrical potential between two places. Two positive charges will repel one another when presented close to one another. The standard addresses the sizing and dimensioning of steel pipes. These pipes come in seamless and welded varieties, and they can withstand high or low temperatures and pressures. The pipe is distinct from the tube (Pipe versus Tube) in this context because it is specifically used for pipeline systems and the transmission of fluids (oil and gas, water, slurry).

In the event that Vo(y, z) = Vo Vo(a)(1-(-1)m-1 * b/n*pi(1-(-1)n) = Cn,m(a/2, b/2) V(x, y, z) = 16Vo/pi2(-pi(m/a)2+(n/b)2)1/2) sin (m*piy/a)sin(n*p)

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The complete question  is -

An infinitely long rectangular metal pipe (sides a and b) is grounded, but one end, at x = 0, is maintained at a specified potential Vo(y, z), Find the potential inside the pipe. as indicated in Fig. y V=0 Vo(y, 2) b

The maximum acceleration which the truck can have without causing the normal reaction at a to be zero is  77.3 ft/sec²

Calculation :

Sum of vertical forces,

By - W = (W/g) ay

By - 180 = (180/32.2) x 0

Vertical reaction, By = 180 lb

Horizontal forces,

Bx = m ax

Bx = (W/g) ax = (180/32.2) x 7.3

Horizontal reaction, Bx = 432 lb

Now taking moment about B,

W x 10 x (12/13) = m ax x 10 x (5/13)

180 x 10 x 12/13 = (180 /32.2) ax x 10 x 5/13

Acceleration, the rate of change of velocity over time for both velocity and direction. A point or object moving in a straight line accelerates as it accelerates or decelerates. Circumferential motion is accelerated because it always changes direction even at constant velocity.

Acceleration, ax = 77.3 ft/sec^2

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According to the given hint, solar panels generate an average  about 200 Watt/m2.

1. The annual USA energy consumption is 103,108,904,000,000,000,000J.

2. The average power required for the USA over one year is 3.2 trillion watt.

3. The total area needed to provide this power is 32.6 billion [tex]m^{2}[/tex].

4. The surface area of the USA is 9.834*[tex]10^{12}[/tex] [tex]m^{2}[/tex].

Solar energy originates from the sun. Solar panels (also called "PV panels") are used to convert light from the sun, which consists of energetic particles called "photons", into electricity that can be used to power electrical loads increase.

Solar panels can be used in a variety of applications including remote power systems for cabins, telecommunications equipment, remote sensing and, of course, power generation for residential and commercial photovoltaic systems.

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When air enters the diffuser of a ramjet engine decelerates to negligible velocity then nozzel exit velocity is 1320.725 m/s.

A nozzle (from nose, meaning 'small spout') is a tube of varying cross-sectional area (usually axisymmetric) aiming at increasing the speed of an outflow, and controlling its direction and shape. Nozzle flow always generates forces associated to the change in flow momentum.

In the simplest case of a rocket nozzle, relative motion is created by ejecting mass from a chamber backwards through the nozzle, with the reaction forces acting mainly on the opposite chamber wall, with a small contribution from nozzle walls.

The flow in a nozzle is very rapid (and thus adiabatic to a first approximation), and with very little frictional loses (because the flow is nearly one-dimensional, with a favourable pressure gradient except if shock waves form, and nozzles are relatively short), so that the isentropic model all along the nozzle is good enough for preliminary design.

Applying steady flow energy equation,

h1+v1^2/2000 = h2+v2^2/2000

680.556^2/2000 = Cp(T2-T1)

230.42 = T2-T1

T2=460.425 K

and P2=227 Kpa

h2+q=h3

q=Cp(T3-T2)

T3=1734.05K

Now by sfee equation

V4=1320.725 m/s

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Option B;A coin and a ring roll down an incline starting at the same time. The coin will be the one to descend first.

Its rotational inertia will be higher. Because of this, it accelerates more slowly than a coin. First to the bottom, the coin makes it. Any item that can be turned possesses rotational inertia. It is a scalar value that indicates how challenging it is to modify the object's rotational velocity around a specific rotational axis and time. Similar to how mass functions in linear mechanics, rotational inertia plays a similar purpose. According to the equation rotational inertia = mass x radius2, rotational inertia is not a vector but a scalar that depends on the radius of rotation.

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The light that hits the slits has a wavelength of [tex]5.692 *10^{-4} m[/tex]

Fringe separation = 2.90 mm = 0.0029 m

Slit separation = 0.420 mm = 0.00042 m

Screen distance from slits =2.14 mm = 0.00214 mm

Wavelength is given by the following relation;

Wavelength = Fringe Separation * Slit Separation / Distance from the slit to Screen

Thus,

Putting all the given values in the above formula,

We evaluate the wavelength in the following way, we get

Wavelength = [tex]\frac{0.0029 *0.00042}{0.00241}[/tex] = [tex]5.692 *10^{-4}[/tex] m

The light's wavelength when it hits the slits is [tex]5.692 *10^{-4}[/tex] m

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if all volcanic activity were to stop tomorrow, there would be a reduction in carbon flux into the atmosphere. is 99%

A carbon flux is the volume of carbon that is transferred across carbon stocks during a certain period of time. 1. To put it simply, it is the transfer of carbon from the land to the seas, the atmosphere, and living things. For instance, the atmosphere receives inflows from decomposition (CO2 emitted by the breakdown of organic matter), forest fires, and the burning of fossil fuels, while the atmosphere also receives outflows from plant growth and ocean absorption. The ocean operates as a net sink of 1.7 GtCyr, which is where the highest natural flow occurs between the atmosphere and the ocean. A significantly smaller net sink exists in the terrestrial ecosystem.

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The tension of the left rope is 98N and tension of the right rope is 29.4N if two boxes are connected by a rope passing over a pulley .

We know very well when two masses are attached by a pulley,the only force acting on the blocks is the force due to gravity. Tension is measured in newtons. Also, since different masses are attached on both ends of pulley due to that tension generated in the rope are different.

We know force due to gravity is equal to =mg where m is defined as the mass and g is defined as the acceleration due to gravity.

Now, mass of left block is =10kg.Therefore,tension in left rope=mg

=>Tension in left rope=10×9.8

=>Tension in left rope=98N

Similarly, mass of right block is =3kg.Therefore,tension in right rope=mg

=>Tension in right rope=3×9.8

=>Tension in right rope=·29.4N

Hence, required tensions are 98N and 29.4N

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The amount of heat energy that must be transferred for conversion is 632730 J.

Mass of ice = m = 210 g

Temperature change = t = 100 - 0 = 100

Latent heat of fusion = L = 334 KJ/ Kg

Latent heat of vaporisation = L' = 2.26 X 10³ KJ/Kg

Specific heat of water = c = 4.19 KJ/Kg

Heat required to convert ice to water = mL

Heat required to raise the temperature of water to boiling point = m X c X t

Heat required to convert water to steam = mL'

Thus, total heat energy required = q =

= q = mL + mL' + (m X c X t)

= q = (210 X 334) + (210 X 2.26 X 10³) + (210 X 4.19 X 100)

= q = 70140 X 474600 + 87990

= q = 632730 J

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If a person's strength test standard score is 0.0, assuming a normal distribution, that person is stronger than 50% of the population.

The most prevalent continuous probability distribution is the Normal (or Gaussian) distribution. As the curve becomes closer to zero on either side of the mean, the function calculates the likelihood that a given event will fall between any two real number limits. A normal curve's undercut area is always equal to one.

Approximately 68 percent of the observations (or 68 percent of the area under the curve) will always fall within two standard deviations (one above and one below) of the mean, regardless of how a normal distribution appears or how large or small the standard deviation is.

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For coexisting states of matter, this measurement is utilized in its orthobaric form. Comparing these ratios is specific gravity. This idea is used by buoyancy to determine whether an object will float or sink.

1 gram per cubic centimeter is the unit of measurement for water. This number, which is equal to mass over volume, is known as density, and it is represented by the Greek letter rho. A hydrometer or aerometer measures a fluid's specific gravity, or relative density, which is the difference between the density of the fluid and the density of water. The typical components of a hydrometer are a cylindrical stem made of glass, a bulb weighed down with lead or mercury so that it can float, and a water-filled container.

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The difference between analog and digital electronics is the signals and the components used.

The electronics can be classified into categories: analog and digital electronics. Some differences between both of them are as follows :

Thus, two differences between analog and digital electronics are analog uses continuous signals while digital uses discrete signals. Then, the analog uses passive components whereas digital uses active components.

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Difference between analog and digital electronics:

Analog electronics are electronics that deal with continuous signals. They generally provide a better and more accurate representation of changes in physical phenomena, such as position, pressure, and light.

Digital electronics are electronics that deal with binary signals. The digital signals for this type of electronics are represented using binary language (0's and 1's). Their circuits are usually composed of large assemblies of logic gates.

The difference between the two are the components used and the type of signal they deal with.

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The wave frequency, speed, and wavelength of two strings with the same thickness but differing lengths will be the same in both strings.

A string will vibrate at a varied frequency depending on its length. Higher frequency and higher pitch are produced by shorter strings. The  frequency and wavelength are inversely proportional. Shorter frequency corresponds to a longer wavelength. The relationship between these two characteristics is explained by the fact that the speed of a wave is equal to the product of its frequency and wavelength. A wave's speed increases with increased string tension, which raises its frequency (for a given length). The wave frequency, speed, and wavelength of two strings with the same thickness but differing lengths will be the same in both strings.

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Option B;  Natural levees formed Suspended load is deposited when the river covers the floodplain.

Usually, earth is used to construct levees. Sediment is forced to the side by the natural flow of a body of water, forming a natural levee. Frequently, a river's banks rise up from the river bed just a little bit . Sediment, silt, and other materials pushed aside by the rushing water are accumulated along the banks to form levees. A natural levee may be the intersection of the flood plain and the channel (a broad, low ridge of built along the side of a channel by debris- laden floodwater). When floodwater that is clogged with debris overflows a channel and goes into a floodplain, a levee is formed.

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82 K is the change in temperature of the gas during this expansion.

Monatomic gases are those that are composed of molecules with just one atom in them. Monatomic gases include gases like helium or sodium vapor. They may be recognized from diatomic or polyatomic gases relatively simply.

A single atom makes up a monoatomic gas. Examples include the gases helium and neon. Since there is just one atom in monoatomic gas, N has the value and K has an independent interaction with the other particles (again because it is composed of only one atom).

Given that,

no. of moles (n) = 8.8 moles

work (W) = 9000 J

For adiabatic process, Q = 0

=> ΔU = - W

For ideal mono-atomic gas, ΔU = 3nRΔT/2

So, ΔT = -2W/3nR

or, ΔT = - (2 × 9000) / (3 × 8.8 × 8.314)

or, ΔT = - 82 K

So, 82 K is the change in temperature of the gas during this expansion.

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Over the last 600,000 years, the highest pre-industrial concentration of carbon dioxide in the atmosphere was approximately 300 ppm.

One carbon atom is covalently doubly linked to two oxygen atoms in every carbon dioxide molecule, giving it the chemical formula CO2. At room temperature, it exists. in. the gaseous. state. Carbon dioxide functions as a greenhouse gas in the atmosphere by being transparent to visible light while absorbing infrared radiation. As of May 2022, it was a trace gas in the Earth's atmosphere, rising from pre-industrial levels of 280 ppm to 421 ppm (or around 0.04%) by volume. [9] [10] These elevated carbon dioxide concentrations and climate change are mostly brought about by the burning of fossil fuels. [11] Groundwater, lakes, ice caps, and ocean all contain carbon dioxide because it is soluble in water. Upon dissolving in water, carbon dioxide

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Volume of water is  17.2N,

The rock displace volume of water whose weight is 37.6 - 20.4 = 17.2N

The mass of this water is 17.2/9.80 =1.755 kg and its volume equal to the rock volume is 1.755/1000 =  1.755 × [tex]10^{-3}[/tex]

The form of the container where the water is contained affects the amount of water inside. You must know the vessel's length, width, and depth in order to calculate the volume of a square or rectangular vessel. The volume equation is V=L W D, where L stands for length, W for width, and D for depth. The formula for the rectangular tank's filled volume is provided as V(fill) = l b f, where "l" denotes the tank's length, "b" denotes its width, "f" denotes its level of water fill, and "V(fill)" is the filled volume of the tank.

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Answer:

A: It becomes bigger.

Explanation:

When the ball is moved closer to the light source, the size of its shadow on the wall will increase. This is because the light from the bulb will be more concentrated on the ball, resulting in a larger area of the wall being blocked from the light and therefore appearing as part of the shadow. The darkness of the shadow will not change, as the amount of light being blocked by the ball remains the same. The sharpness of the shadow may also not change, as the distance between the ball and the wall will not affect the clarity of the shadow's edges. However, the length of the shadow may appear shorter, as the ball will be closer to the wall and therefore the shadow will appear to be cast over a shorter distance.

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The answer to the question is that the acceleration equals 4.9 m/s² and the cord tension is 58.8 N.

The force produced when ever a load is attached at one or both of the end of such a material in such a direction away from the material's cross-section is known as the tension force. It's frequently referred to a tension force as a "pushing" force.

(a) Let's use Newton's Second Law for Movement to our example:

[tex]$$\begin{gathered}T-m_1 g=m_1 a, \\T-m_2 g=-m_2 a .\end{gathered}$$[/tex]

Eliminating [tex]$T$[/tex], we get:

[tex]$$\begin{gathered}\left(m_2-m_1\right) g=\left(m_1+m_2\right) a, \\a=\frac{\left(m_2-m_1\right) g}{m_1+m_2}, \\a=\frac{(12 \mathrm{~kg}-4 \mathrm{~kg}) \cdot 9.8 \frac{\mathrm{m}}{\mathrm{s}^2}}{4 \mathrm{~kg}+12 \mathrm{~kg}}=4.9 \frac{\mathrm{m}}{\mathrm{s}^2} .\end{gathered}$$[/tex]

(b) By adding "a" to the first equation, we can get the cord's tension:

[tex]$$T=m_1(a+g)=4 \mathrm{~kg} \cdot\left(4.9 \frac{\mathrm{m}}{\mathrm{s}^2}+9.8 \frac{\mathrm{m}}{\mathrm{s}^2}\right)=58.8 \mathrm{~N}$$[/tex]

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a) The amplitude of oscillation is 0.780 m.

b) The force constant of the spring can be determined by using the equation F=kx, where F is the force applied to the mass, k is the force constant, and x is the displacement of the mass. Since the displacement of the mass is 0.780 m, we can solve for k to get k = F/x = 0.780 N/m.

c) The position of the mass after one half a period is given by x(t) = (0.780 m)cos[(18.0 rad/s)t] = (0.780 m)cos[(9.0 rad/s)t] = 0.780 m.

d) The position of the mass one-third of a period after it has been released is given by x(t) = (0.780 m)cos[(18.0 rad/s)t] = (0.780 m)cos[(6.0 rad/s)t] = -0.500 m.

e) To determine the time it takes the mass to get to the position x=-0.500 m after it has been released, we can use the equation x(t) = (0.780 m)cos[(18.0 rad/s)t]. Since we know that x=-0.500 m when t=t0, we can solve for t0 to get t0=6.00 s. Therefore, it takes the mass 6.00 s to get to the position x=-0.500 m after it has been released.

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Yes, for floating objects, the buoyant force equals the weight of the objects. since each object has the same weight, they must have the same buoyant force to counteract that weight and make them float.

The object can stay suspended at its current depth if the buoyant force is equal to its weight. Regardless of whether an item floating, descends, or is immersed in a liquid, the buoyant force is constantly at work. Any item in any fluid will experience an upward push called the buoyant force.

The total upward force acting on any item in any fluid is known as buoyant force. The object will ascend to the surface as well as float if the buoyant force is higher than its weight. The object will sink if the buoyant force is lower than its weight.

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In order to find the actual distance of the shark from the wall, we need to use the lens equation. This equation is used to calculate the distance of an object from a lens, given the distance of the image from the lens, the focal length of the lens, and the refractive index of the material between the lens and the object. In this case, we can assume that the tunnel wall acts as a lens, and the water between the shark and the wall acts as the medium through which the light travels.

We can use the lens equation to find the actual distance of the shark from the wall by setting the distance of the image from the lens (3.0 m) equal to the focal length of the lens (R) divided by the refractive index of the medium (1.33), minus the actual distance of the shark from the wall (d):

3.0 m = (4.0 m)/1.33 - d

Solving for d, we find that the actual distance of the shark from the wall is 1.5 m. Therefore, the shark is actually 1.5 m away from the tunnel wall, not 3.0 m as it appears in the tunnel.

This calculation assumes that the shark is a flat object, which is not necessarily true. In reality, the shark may be closer to or further from the wall than the calculation indicates, depending on its shape and orientation. Additionally, the refractive index of water can vary depending on factors such as temperature, salinity, and pressure, so the value used in this calculation may not be entirely accurate.

The shark 's actual distance from the wall is 4 m.

The ratio of light's speed in a vacuum to that in a particular medium is known as the refractive index.

Refraction index and index of refraction are other names for the term "refractive index." The characteristics of the medium affect the speed of light in that medium. The optical density of the medium affects the speed of electromagnetic waves.

When the object is in denser medium and  observer is in rarer medium; refractive index of the medium can be written as:

μ = actual distance/apparent distance

actual distance = μ × apparent distance

= 1.33 × 3.0 m

= 3.99 m

= 4 m. (approx.)

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The tension in the cable is F = πEaV²r³/2d²

The work. done. by the cable. is W = πEaV²r²/4d

[tex]\mathbf{U_i-U_f=\frac{\varepsilon_0\pi r^2 V^2}{2d}-\frac{\varepsilon_0\pi r^2 V^2}{4d}}\mathbf{\Rightarrow U_i-U_f=\frac{\varepsilon_0\pi r^2 V^2}{4d}}[/tex]

The equation can be used to depict the electric field created between two circular plates of a capacitor if they are separated by a constant distance and supported by a cable.

E = V/d

E' = E/2

F = qv/2d

F = Eav2r2/2d2.

Assuming that dz has shifted the upper plate higher, we can express the tension's work as follows:

dw = T*dz

dz = F * dw

The cable's work is W = Eav2r2/4d, or W = Eav2r2/2z2*dz.

Before the top plate is raised, the electrical energy capacitor has the following amount of energy stored in it:

Ui = 1/2 Cv²

Ui = EaR2V2D

Yes, the work carried out by the cable is equivalent to the change in electrical energy that has been stored. The variation in energy previously stored

Ui = Eaπr²v²/4d

[tex]\mathbf{U_i-U_f=\frac{\varepsilon_0\pi r^2 V^2}{2d}-\frac{\varepsilon_0\pi r^2 V^2}{4d}}\mathbf{\Rightarrow U_i-U_f=\frac{\varepsilon_0\pi r^2 V^2}{4d}}[/tex]

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A 0.53kg mass is hung on a vertical spring which has spring constant k=70N/m, balanced then the spring stretch relative to its original length as a result of the mass hanging on it is 0.742m

Given that the mass of block (m) = 0.53kg

spring constant of the spring (k) = 70N/m

The force exerted by the spring balances the weight of the hanging mass is (F) = kl where l is length of the spring

We know that F = mg

mg = kl

then 0.53 x 9.8 = 70 x l

l = 0.0742m

Hence the length of the spring is 0.742m

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When  two lamps with one thick filament and one with a thin filament of the same material, are connected in parallel to a power supply. Then the  current is greater in the lamp with a thick filament.

Ohm's Law can be used to calculate the relationship between voltage, current, and resistance in an electrical circuit.

Ohm's law can be written as follows:,

V = I x R

When written out, the formula is as follows: voltage = current x resistance, or

Volt = Amp x Ω.

Because theory is connected in parallel and the potential difference across each filament is the same, we can conclude that a material's resistance is [tex]R = \rho*lA[/tex]

[tex]\rho[/tex] is the resistivity if the material for the two filaments is the same and the length 'l' is also the same

The area of cross section of a thick filament is greater than that of a thin filament. The resistance is less than the thin filament current. [tex]I = \frac{V}{R}[/tex]

since V is same

If R is smaller, current is greater, and thus current is greater in thick filament.

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