Two pieces of steel wire with identical cross sections have lengths of L and 2L. The wires are each fixed at both ends and stretched so that the tension in the longer wire is four times greater than in the shorter wire. If the fundamental frequency in the shorter wire is 60 Hz, what is the frequency of the second harmonic in the longer wire?

Answers

Answer 1

Answer:

Explanation:

Expression for fundamental  frequency of tone produced in a wire under tension of T and length L is given as follows

[tex]f=\frac{1}{2L} \times \sqrt{\frac{T}{ m} }[/tex]

m is mass per unit length .

We shall apply this formula for given wires .

For shorter wire

[tex]60 =\frac{1}{2L} \times \sqrt{\frac{T}{ m} }[/tex]

For longer wire for second harmonic

length of wire is 2L , tension is 4T ,

[tex]f =\frac{2}{4L} \times \sqrt{\frac{4T}{ m} }[/tex]

[tex]f =\frac{2\times 2}{4L} \times \sqrt{\frac{T}{ m} }[/tex]

f = 2 x 60 = 120 Hz .


Related Questions

which changes will increase the rate of reaction during combustion

Answers

Answer:

reducing temperature of the surrounding

Explanation:

combustion reactions are exothermic so they give off heat. reducing the temperature of the surrounding will enable more efficient energy transfer

The main idea of this paragraph is:
a. Boots is my dog.
b. Boots can sit.
c. Boots is very smart.
d. Most dogs can't dance.

Answers

You didn’t upload the paragraph

The force of gravity acting on an object is directed through this
center of gravity and toward the center of the

Answers

Answer:

Earth.

Explanation:

Center of gravity can be defined as the specific point where all of the weight of an object is concentrated.

Generally, all the objects found around the world all have a center of gravity.

When an object is balanced so that a displacement lowers its center of gravity, the object is said to be in stable equilibrium.

Hence, the force of gravity acting on an object is directed through this center of gravity and toward the center of the earth.

Weight can be defined as the force acting on a body or an object as a result of gravity.

Mathematically, weight is given by the formula;

[tex] Weight, W = mg [/tex]

Where;

m is the mass of an object.

g is acceleration due to gravity.

An object of mass 5kg travels in the positive direction with a speed of 1ms1ms. The object collides with a second object that exerts an average net force over an interval of time such that the 5kg object comes to rest. Which of the following best predicts the change in momentum for the 5kg object?

a. The change in momentum is in the negative direction.
b. The change in momentum is in the positive direction.
c. The change in momentum is zero.
d. The direction of the change in momentum cannot be determined without knowing the value of the average force and time in which the force is exerted.

Answers

Answer:

Explanation:

The change in momentum is in the negative direction.

10) A soccer player kicks a soccer ball (m = 0.42 kg) accelerating from rest to 32.5m/s in 0.21s. Determine the force that sends soccer ball towards the goal.
G
U
E
S
S
Formula

11) Small rockets are fired to make small adjustments in the speed of a satellite. A certain small rocket can change the velocity of a 72,000kg satellite from 0m/s to 0.63m/s in 1296s. What force is exerted by the rocket on the satellite?

G
U
E
S
S
Formula

please I need help I don't understand it and I had to deliver it yesterday helpp:(

Answers

Explanation:

(10) Mass of a soccer player, m = 0.42 kg

Initial speed, u = 0

Final speed, v = 32.5 m/s

Time, t = 0.21 s

We need to find the force that sends soccer ball towards the goal.

Force, F = ma

[tex]F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{0.42 \times (32.5-0)}{0.21}\\\\F=65\ N[/tex]

So, 65 N of force soccer ball sends towards the goal.

(11) Mass of the satellite, m = 72,000 kg

Initial speed, u = 0 m/s

Final speed, v = 0.63 m/s

Time, t = 1296 s

We need to find the force is exerted by the rocket on the satellite.

Force, F = ma

[tex]F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{72,000\times (0.63-0)}{1296}\\\\F=35\ N[/tex]

So, 35 N of the force is exerted by the rocket on the satellite.

Hence, this is the required solution.

I NEED HELP ASAPPPP PLEASE

Answers

I think it’s c i’m not sure tho

What is the instantaneous velocity of a freely falling object 11 s after it is released from a position of rest

Answers

Answer:

v= -107.8 m/s

Explanation:

Since the object is in free fall, this means that is moving at an accceleration equal to the one due to gravity.Since it starts at rest, we can apply the definition of acceleration, rearranging terms as follows:

       [tex]v_{f} = v_{o} + a*t = a*t = -g*t = 9.8m/s2*11s = -107.8 m/s (1)[/tex]

(Assuming as positive the upward direction)

I NEED HELP ASAP PLEASE!
Study the scenario.

Boiling water is poured into a Styrofoam cup and a metal cup. You pick up and hold the metal cup and the Styrofoam cup. The metal cup burns your fingers, but you can hold the Styrofoam cup without experiencing any pain.

The difference in the rate at which these two materials transfer thermal energy throughout the cups is known as __________.

evaporation
electrical energy
thermal conductivity
condensation

Answers

Answer: thermal conductivity

The difference in the rate at which these two materials transfer thermal energy throughout the cups is known as thermal conductivity.

What is thermal conductivity?

It is the rate where the heat is to be transferred from conduction via the cross section area of the unit with respect to the material at the time when the temperature should be gradient and existed with the perpendicular to the area.

Also, in this, two material is to be transferred via the thermal energy with the help of cups.

Learn more about energy here: https://brainly.com/question/17447827

A 4 kg object moving to the left collides with and sticks to a 3 kg object moving to the right. Which of the following is true of the motion of the combined objects immediately after the collision?

a. They must be moving to the left.
b. They must be moving to the right.
c. They must be at rest.
d. The motion cannot be determined without knowing the speeds of the objects before the collision.

Answers

Answer:

D. The motion cannot be determined without knowing the speeds of the objects before the collision.

Explanation:

This question is tricky! We know the object moving to the left has a greater mass than the one moving to the right. We'd assume they would move to the left because the leftwards object has a greater mass, right?

Not. So. Fast.

We can solve for the objects' final velocity using the formula for momentum, m₁v₁ + m₂v₂ = (m₁ + m₂)v .

Now here's where the trap is sprung: we don't think about the equation. This shows that the final velocity of the objects and the direction depends on both the mass of the objects and their initial velocity.

Basically, what if the 3 kg object is moving at 1 m/s and the 4 kg object is moving at –0.5 m/s? The objects would move to the right after the collision!

Do we know the velocity of these objects? No, right?

That means we can't determine the direction of their motion unless we know their initial, pre-collision velocity. This question is tricky because we look at the 4 kg vs. 3 kg and automatically assume the 4 kg object would dictate the direction of motion. That's not true. It depends on velocity as well.

I hope this helps you! Have a great day!

If a car is traveling at an average speed of 20 m/s, how long will it take to travel 500 meters?
A. 0.04 seconds
B. 25 seconds
C. 520 seconds
D. 10,000 seconds

Answers

Answer:

B. 25 seconds

Explanation:

500÷20=25

500/20=25
B.25 seconds

A 10kg toy truck has a 5kg toy car at rest. If the toy truck was moving at 3 m/s before the collision and carries that car with it, what is the
Final velocity of the car and truck.
A. 15 m/ s
B. 30 m/ s
C 2 m/ s
D. 18 m/ sc free

Answers

Answer:

[tex]v_f=2\:\mathrm{m/s}[/tex]

Explanation:

From the Law of Conservation of Momentum, momentum is conserved. Therefore, we can set up the following equation:

[tex]m_1v_1+m_2v_1=m_fv_f[/tex]

Since the 5kg toy car was initially and rest, [tex]m_2v_2=0[/tex].

Therefore, plugging in our values, we have:

[tex]10\cdot 3=(10+5)v_f,\\v_f=\frac{30}{15},\\v_f=\fbox{$2\:\mathrm{m/s}$}[/tex].

Answer:

Let m1 = mass of big toy car=10kg

m2= mass of small toy car= 5kg

U1= initial velocity of big toy car= 3m/s

U2= initial velocity of small toy car=0

Since the big toy car moved the small one after the collision, their final velocity will be the same.

m1u1 + m2u2= (m1+m2)v

10(3)+(5)(0)=(10+5)v

30=15v

Divide both sides by 15

V=2

The final velocity is 2m/s

Explanation:

3. As the mass of an object increases, the force of gravity

Answers

Answer:

As the mass of an object increases, the force of gravity increases as well.

Explanation:

Objects with more mass have more gravity. They work together.

A truck pushes a mound of dirt 5 meters with a force of 75 newtons. How much
work has been done?

Answers

Answer:

[tex]375\:\mathrm{N}[/tex]

Explanation:

Work is given by the equation [tex]W=F\Delta x[/tex]. Plugging in given values, we get:

[tex]W=75\cdot 5=\fbox{$ 375\:\mathrm{N}$}[/tex].

To understand and apply the formula τ=Iα to rigid objects rotating about a fixed axis. To find the acceleration a of a particle of mass m, we use Newton's second law: F net=ma , where F net is the net force acting on the particle.To find the angular acceleration α of a rigid object rotating about a fixed axis, we can use a similar formula: τnet=Iα, where τnet=∑τ is the net torque acting on the object and I is its moment of inertia.
Part A:
Assume that the mass of the swing bar, is negligible. Find the magnitude of the angular acceleration α of the seesaw.
Express your answer in terms of some or all of the quantities m1, m2, l, as well as the acceleration due to gravity g.
Part B:
Now consider a similar situation, except that now the swing bar itself has mass mbar.Find the magnitude of the angular acceleration α of the seesaw.
Express your answer in terms of some or all of the quantities m1, m2, mbar, l, as well as the acceleration due to gravity g.

Answers

Answer:

Hello your question is incomplete attached below is the missing part of the question

In this problem, you will practice applying this formula to several situations involving angular acceleration. In all of these situations, two objects of masses m1 and m2 are attached to a seesaw. The seesaw is made of a bar that has length l and is pivoted so that it is free to rotate in the vertical plane without friction. Assume that the pivot is attached tot he center of the bar.

You are to find the angular acceleration of the seesaw when it is set in motion from the horizontal position. In all cases, assume that m1>m2.I

answer : part A = 2*[(M1 - M2)/(M1 + M2)]*g/L

              part A = attached below

Explanation:

Part A :

Assuming that mass of swing is negligible

α = T/I

where ; T = torque, I = inertia,

hence T =  L/2*9*(M1 - M2)

also;  I = [tex]M1*(L/2)^2 + M2*(L/2)^2[/tex]=  ( M1 + M2) * (L/2)^2

Finally the magnitude of the angular acceleration α

α = 2*[(M1 - M2)/(M1 + M2)]*g/L

Part B attached below

Waves in the ocean are tearing apart the shoreline. Which of the following two Earth Systems are interacting with each other.

Answers

Answer:

the Indian Ocean on 26 December 2004. This event claimed 227,898 dead and missing from 14 countries. The difference in mortality rates between these tsunamis reflects, in part, the benefits of understanding how tsunami waves are generated and move, and educating citizens to make scientifically

sound and potentially life-saving decisions.

A tsunami is a series of rapidly propagating, shallow-water ocean waves that develops when a submarine earthquake, landslide, or volcanic eruption displaces a large volume of water. Powerful earthquakes, with magnitudes of 9 or greater, caused both the 2004 and 2011 tsunamis. The earthquakes resulted from the movement of large tectonic plates. The 11 March 2011 earthquake occurred at 32 km (20

mi.) deep in Earth’s crust about 130 km (81 mi.) east of the city of Sendai. This location is on the boundary between two tectonic plates—the Pacific plate to the east and North American plate to the west. This

boundary fractured, releasing energy that was transmitted through the rocks and elevated portions of the

ocean floor. This drastic movement transmitted energy to the overlying ocean water, which generated

tsunami waves that radiated outward. The waves washed over the nearby coastlines and were felt around

the globe within hours (Figure 1.1).  

Explanation:

Answer:

I believe Geosphere (lithosphere) and Hydrosphere

Explanation:

I hope it's right if not please notify me.

_____________________health is how you feel and how you react to situations bases on how you feel.
Group of answer choices

Mental

Physical

Emotional

Social

Answers

Answer: Emotional

Explanation:

Answer:

Physical

Explanation:

I love going going for a jog or a run so does my dog

what do scientists call a substance that forms during a chemical reaction

Answers

Answer:

A chemical reaction is a process in which one or more substances, also called reactants, are converted to one or more different substances, known as products.

Answer:

the answer is reactants i guess

In March 1999 the Mars Global Surveyor (GS) entered its final orbit about Mars, sending data back to Earth. Assume a circular orbit with a period of 7.08 × 103 s and orbital speed of 3.40 × 103 m/s . The mass of the GS is 930 kg and the radius of Mars is 3.43 × 106 m. Calculate the mass of Mars.

Answers

Answer: [tex]5.944\times 10^{23}\ kg[/tex]

Explanation:

Given

Time period [tex]T=7.08\times 10^3\ s[/tex]

Orbital speed [tex]v=3.40\times 10^3\ m/s[/tex]

mass of GS [tex]m_{GS}=930\ kg[/tex]

Radius of Mars [tex]r=3.43\times 10^6\ m[/tex]

Consider the mass of mars is M

Here, Gravitational pull will provide the centripetal force

[tex]F_G=F_c[/tex]

[tex]\dfrac{GMm_{GS}}{r^2}=\dfrac{m_{GS}v^2}{r}\\M=\dfrac{v^2\cdot r}{G}\\M=\dfrac{(3.43\times 10^3)^2\cdot 3.43\times 10^6}{6.67\times 10^{-11}}[/tex]

[tex]M=5.944\times 10^{23}\ kg[/tex]

In March 1999 the Mars Global Surveyor (GS) entered its final orbit on Mars, sending data back to Earth. The mass of Mars is approximately 6.419 × 10²³ kg.

Kepler's Third Law states that the square of the orbital period (T) is proportional to the cube of the semi-major axis (a) of the orbit:

T² = (4π² / GM) × a³

In a circular orbit, the semi-major axis is equal to the radius of the orbit (r).

Given:

Orbital period (T) = 7.08 × 10³ s

Orbital speed (v) = 3.40 × 10³ m/s

Mass of GS (m) = 930 kg

Radius of Mars (r) = 3.43 × 10⁶ m

The orbital speed (v) is related to the radius (r) and the gravitational constant (G) by:

v = √(GM / r)

v² = GM / r

G = (v² × r) / M

T² = (4π² / [(v² × r) / M]) × r³

T² = (4π² × M × r²) / v²

M = (T² × v²) / (4π² × r²)

M = ( (7.08 × 10³)² × (3.40 × 10³)² ) / (4π² × (3.43 × 10⁶)²)

M = 6.419 × 10²³ kg

Therefore, the mass of Mars is approximately 6.419 × 10²³ kg.

To know more about the mass of Mars:

https://brainly.com/question/2168817

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PLEASSEE HELP MEEE WITHH THESEEE
Forty-five cm are equivalent to how many m? State your answer using Scientific Notation.

a
45 x 10^-2 m
b
4.5 x 10^-2 m
c
.45 x 10^-2 m
d
0.45 x10^-2 m
The radius of the earth is 6378 km. What is the diameter of the earth in meters? Use scientific notation to state your answer.



a
6378 x 10^3 m
b
.6378 x 10^3 m
c
6.378 x 10^6 m
d
6.378 x 10^3 m
In an experiment, you find the mass of a cart to be 250 grams. What is the mass of the cart in kilograms?

a
2.5 x 10^3 kg
b
2.50 x 10^3 kg
c
2.50 x 10^-3 kg
d
2.5 x10^-3 kg

Answers

Answer:

Q1: (a)

[tex]1cm \: = 10 {}^{ - 2}m[/tex]

so

[tex]45 \times {10}^{ - 2} m[/tex]

Q2:

[tex]1km = 10 {}^{3} m \\ 6378km \times {10}^{ 3} [/tex]

this is the radius in meter

diameter = 2r

in this i don't know which choice is the right answer

Q3:

[tex]1gram = \: {10}^{ - 3} kg[/tex]

so

[tex]250 \times {10}^{ - 3} = 2.5 \times {10}^{ - 1} kg[/tex]

again there is no correct answer

A car is traveling at speed of 18.6m/s and entering a 12m wide intersection when the light has 0.582seconds More Time remain yellow.

a) what does the acceleration of the car needed to be so that its infront is out of the intersection when the light turns red? ​

Answers

Answer:

6.94 m/s²

Explanation:

Given that:

Initial Velocity (u) = 18.6 m/s

Time, t = 0.582

S, distance = 12 m

S = ut + 0.5at²

12 = (18.6 * 0.582) + 0.5(a)(0.582²)

12 = 10.8252 + 0.169362a

12 - 10.8252 = 0.169362a

1.1748 = 0.169362a

a = 1.1748 / 0.169362

a = 6.9366209

a = 6.94 m/s²

Hence, acceliofbthe car should be 6.94 m/s²

An electric heater draws a steady 15.0A on a 120-V
line. How much power does it require and how
much does it cost per month (31days) if it operates
2.0 h per day and the electric company charges 15.5
cents per kWh?

Answers

Answer:

1. 1800 W

2. $ 17.3

Explanation:

From the question given above, the following data were obtained:

Current (I) = 15 A

Voltage (V) = 120 V

Time (t) = 20 h per day

Duration = 31 days

Cost = 15.5 cents per kWh

1. Determination of the power.

Current (I) = 15 A

Voltage (V) = 120 V

Power (P) =?

P = IV

P = 15 × 120

P = 1800 W

Thus, 1800 W of power is required.

2. Determination of the cost per month (31 days).

We'll begin by converting 1800 W to KW.

1000 W = 1 KW

Therefore,

1800 W = 1800 W × 1 KW / 1000 W

1800 W = 1.8 KW

Next, we shall determine the energy consumption for 31 days. This can be obtained as follow:

Power (P) = 1.8 KW

Time (t) = 2 h per day

Time (t) for 31 days = 2 × 31 = 62 h

Energy (E) =?

E = Pt

E = 1.8 × 62

E = 111.6 KWh

Finally, we shall determine the cost of consumption. This can be obtained as follow:

1 KWh = 15.5 cents

Therefore,

111.6 KWh = 111.6 KWh × 15.5 cents / 1 KWh

111.6 KWh = 1729.8 cents

Converting 1729.8 cents to dollar, we have:

100 cents = $ 1

Therefore,

1729.8 cents = 1729.8 cents × $ 1 / 100 cents

1729.8 cents = $ 17.3

Thus, it will cost $ 17.3 per month to run the electric heater.

The amount of power it requires is 180 Watt, and the cost per month to operate the electric heater for 2.0 h is 5.58 cent

To calculate the electric power required by the electric heater, we use the formula below.

⇒ Formula:

P = Vi................ Equation 1

⇒ Where:

P = PowerV = Voltagei = current

From the question,

⇒ Given:

V = 120 VI = 15.0 A

⇒ Substitute these values into equation 1

P = 120(1.5)P = 180 Watt.

For the cost of running the electric heater per month, if it operates 2.0 h per day. We use the relation below

C = Pt×C'/1000............... Equation 2

⇒ Where:

C = The cost per month to operate the electric heater for 2.0ht = timeC' = Cost per kWh charge by the electric company.

From the question,

⇒ Given:

C' = 15.5 cent per kWh t = 2.0 hP = 180 Watt

⇒ Substitute these values into equation 2

C = 180(15.5)(2)/1000C = 5.58 cent.

Hence, The amount of power it requires is 180 Watt, and the cost per month to operate the electric heater for 2.0h is 5.58 cent

Learn more about electric power here: https://brainly.com/question/16641884

. Which of the statement below about the magnetic
properties of iron and steel is correct?
A. Both iron and steel are equally magnetized and
demagnetized
B. Iron is more easilymagnetized and demagnetized
than steel.
C. Steel is more easily magnetized and demagnetized
than iron
D. Iron is more easily magnetized than steel but steel is
more easily demagnetized than iron.​

Answers

Answer:

D. Iron is more easily magnetized than steel but steel is more easily demagnetized than iron.

Two balls of unequal mass are hung from two springs that are not identical. The springs stretch the same distance as the two systems reach equilibrium. Then both springs are compressed and released. Which one oscillates faster?
a) The spring with the heavier ball,
b) Springs oscillate with the same frequency,
c) The spring with the light ball.

Answers

Answer:

b) Springs oscillate with the same frequency,

Explanation:

expression for frequency of vibration of mass hanging from a spring is given as follows

f = [tex]\frac{1}{2\pi} \times \sqrt{\frac{k}{m} }[/tex]

k is force constant of spring and m is mass vibrating .

In the present case, if mass stretches the spring by x and remains balanced

mg = k x

[tex]\frac{k}{m} =\frac{g}{x}[/tex]

g and x are same  for both cases

[tex]\frac{k}{m}[/tex] will also be same for both cases .

Hence frequency of vibration will also be same for both the balls .

Describe the effect of the amplitude on the velocity of the pulse!???

Answers

Answer:

Amplitude increases with decreasing velocity.

Explanation:

At the same time, an increase in attention takes place

Show that the speed of a moving particle over a time interval is constant if and only if its velocity and acceleration vectors are perpendicular over the time interval.

Answers

Answer:

[tex]|v|(t)=\sqrt{v_{x}^{2}(t)+v_{y}^{2}(t)+v_{z}^{2}(t)}=C[/tex]

[tex]2v(t)\cdot \frac{dv(t)}{dt}=0[/tex]

[tex]v(t)\cdot a(t)=0[/tex]

Explanation:

Let's start with the definition of a constant velocity.

If the velocity magnitude, in three dimensions,  is a constant value (C) we have a constant velocity, which means.

[tex]|v|(t)=\sqrt{v_{x}^{2}(t)+v_{y}^{2}(t)+v_{z}^{2}(t)}=C[/tex]

Now, we know that the dot product between v(t) and v(t) is the |v|².

[tex]v(t)\cdot v(t)=|v|^{2}(t)[/tex]

If we take the derivative whit respect to time in both sides of this equation we will have:

[tex]\frac{d}{dt}(v(t)\cdot v(t))=\frac{d}{dt}|v|^{2}(t)[/tex]

We apply the product rule on the left side and the right side will zero because the derivative of a constant is 0.

[tex]\frac{dv(t)}{dt}\cdot v(t)+v(t)\cdot \frac{dv(t)}{dt}=0[/tex]

[tex]2v(t)\cdot \frac{dv(t)}{dt}=0[/tex]

We know that dv(t)/dt = a(t) (using the acceleration definiton)

Therefore, we conclude:

[tex]v(t)\cdot \frac{dv(t)}{dt}=0[/tex]

[tex]v(t)\cdot a(t)=0[/tex]

If the dot product is 0, it means that v(t) and a(t) are orthogonal.

I hope it helps you!

A ball has a velocity of 11 m/s and a momentum of 47 kgm/s, what is its mass? Show
your given, required, and solutions.

Answers

Explanation:

p=m x v

to find the mass:

m= p/v

=47/11

=4.27 kg

Assuming no friction, how does the initial gravitational potential energy of
the marble on a downward slope compare to the final kinetic energy?

a) they are the same
b) the initial gravitational potential energy is greater than the final kinetic energy
c) the initial gravitational potential energy is less then the final kinetic energy

Answers

Answer:

a) They are the same.

Explanation:

Assuming no friction, there should be no energy transfer and thus the Law of Conservation of Energy says:

[tex]PE=KE,\\mgh=\frac{1}{2}mv^2[/tex]

These types of problems also disregard any air resistance the surface of the object may cause. Therefore, no energy is transferred and from the Law of Conservation of Energy, [tex]100\%[/tex] of energy is preserved.

In 1800, Herschel wondered if the different colors of the rainbow were equal in brightness and heat. He used a prism to separate sunlight into it's different colors and thermometers to measure how much "heat energy" was included with each color. He also measured how much "brightness" was associated with each color. He noticed a "brightness" peak at the middle of the spectrum. Red and violet had the least amount of brightness with a "peak" at green and yellow. But for "heat energy", violet had the least and the amount of heat climbed more and more and showed no sign of a "peak" .

His observations supported the idea that neither Brightness nor heat were evenly distributed between the different colors. Some colors had more brightness (green and yellow) and a different color had the most heat (red).

But this lead to a new question. Did the "heat" exist even where there was no visible light and did it peak at wavelengths less than red. He did another set of experiments and found this to be the case. He again used a prism to separate sunlight into the colors of the rainbow. These colors were cast on a sheet of paper and a thermometer could be moved from one color to the next to measure the amount of heat. But this time, he moved the thermometers beyond the red light and made measurements on the paper where there was no visible light. He found the maximum amount of heat at wavelengths longer visible red light.


When Herschel selected where to place his thermometer and then measure the temperature, which variable was the Independent variable.

Question options:

A. The time of day


B. The month of the year


C. the temperature rise


D. the placement of the thermometer

Answers

Answer:

D.

Explanation:

im guessing.

Why can ultraviolet waves be dangerous

Answers

Answer:

They can cause sunburn. Exposure to UV rays can cause premature aging of the skin and signs of sun damage such as wrinkles, leathery skin, liver spots, actinic keratosis, and solar elastosis. UV rays can also cause eye problems.

Explanation:

PLEASEEEEEE HELPPPPPPP

Define resistance and discuss how it affects current.

Answers

Answer:

Resistance is the opposing of the flow of current through a conductor.

Other Questions
Which of these best describes rt?A) The square root of the area of a circleB) The ratio of the radius of a circle to its diameterC) The radius of a circle times 3.14D) The ratio of the circumference of a circle to its diameter Look at each expression below. Indicate if each is equivalent to 64g 40h. Select Yes or No for each expression. a. 40(24g h) Yes No b. 8(8g 5h) Yes No c. 24gh Yes No d. 4(16g 10h) Yes No e. 2(32g 20h) Yes No Why were many adult immigrants not acculturated? which sentence shows best tbat the writer is aware of the appropriate tone for the audience?1. Perhaps Anna could consider her decisions more carefully.2. I know you would make better choice in that situation. 3. Anna-she's a girl who acts really silly.4. What was Anna thinking when she did something so dum?b Which statement summarizes Samantha's claim? Which scenario can be modeled using the graph below? Can you please help with both? :) hey, does anyone know the answer? -49r - 21r + 35rfactor out the gcf Identify the value of C for completing the square X^2 16x + cA) 16B) 64C) -64D) -16 does anybody know what these shoes are called? Which value of x is a solution of the inequality 25x - 100 < 250? Pls help extra points and mark brainlist easy reading The area of a right triangle with one leg measuring 10 feet and the hypotenuse measuring 26 feet issquare feetA 81B 100 C 120 Someone help me it was due a week ago please help me What is physical appearance of traits called? Dancing is becoming a popular hobby.Which statement correctly describes the verb function in this sentence?The word dancing is a verb that functions as a noun.The word dancing is a verb that functions as an adjective.The word becoming is a verb that functions as a noun.The word becoming is a verb that functions as an adjective. Help. How the slave trade impacted West Africa and the Americas. According to the US Constitution, states have legislative powers thatare delegated to the federal government.relate to currency, the economy, and trade.are not assigned to the federal government.relate to the declaration of war and the military. Do it in order. from smallest to largest hiiiii? i was wondering if you might enjoy life?