Two people compete in a five-mile go kart race. Person A travels 1/10 miles every 15 seconds while Person B travels 3/8 mile every 48 seconds. Who wins the race? What is the difference of the finish times of the competitors?

Answers

Answer 1

Answer:

a) Person B wins the race.

b) The difference in the finish times of the competitors is 110 s.

Step-by-step explanation:

a) We can find the time that takes Person A and B to finish the race:

Person A:

[tex] t_{F_{A}} = \frac{t_{A}}{d_{A}}*d_{T} [/tex]

Where:

[tex]t_{A}[/tex]: is the time of Person A = 15 s [/tex]

[tex]d_{A}[/tex]: is the distance of Person A = 1/10 miles [/tex]

[tex]d_{T}[/tex]: is the total distance = 5 miles [/tex]

[tex] t_{F_{A}} = \frac{15 s}{1/10 miles}*5 miles = 750 s [/tex]

Person B:

[tex] t_{F_{B}} = \frac{t_{B}}{d_{B}}*d_{T} = \frac{48 s}{3/8 miles}*5 miles = 640 s [/tex]

Hence, Person B wins the race.        

                                 

b) The difference in the finish times is:

[tex] t_{F_{A}} - t_{F_{B}} = 750 s - 640 s = 110 s [/tex]

Therefore, the difference in the finish times of the competitors is 110 s.

I hope it helps you!                                


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