Two masses m1 13.6 kg and m2 22.9 kg are connected by a rope that hangs over the pulley. The pulley has form of solid cylinder of radius 0.6 m and mass 10.6 kg. Initially m1 is on the ground and m2 rests 8.0 m above the ground. At some moment system is released. Find velocity of m2 just before it hits the ground. Neglect friction in the pulley.
Answers
The conservation of energy allows finding the result of the velocity of the body 2 when it reaches the ground is:
v = 6.32 m / s
Given parameters
Body mass 1 m₁ = 13.6 kg body mass 2 m₂ = 22.9 kg height y = 8.0 mTo find
speed.
The conservation of energy is one of the most important principles of physics, it establishes that if there is no friction force, the mechanical energy is conserved at all points, where the mechanical energy is the sum of the kinetic energy plus the different potential energies.
Let's write the energy at two points before we drop the system.
Em₀ = U₁ + U₂
Where potential energy is
U = m g y
They indicate that body 1 is on the ground and body 2 is at a height .
y₂ = 8 m
Em₀ = m₂ g y₂
Let's write the energy of the system for when body 2 is reaching the ground
[tex]Em_f[/tex] = K₂ + K₁ + U₂ + U₁
At this moment body 2 is reaching the ground, its height is zero and the height of body 1 is y₁ = 8 m. Since the two bodies are joined by the rope, they must have the same speed..
[tex]Em_f[/tex] = ½ (m₁ + m₂) v² + m₁ g y₁
As there is no friction, the energy is conserved.
Em₀ = Em_f
m₂ g y₂ = ½ (m₁ + m₂) v² + m₁ g y₁
The rope is inextensible, the heights are equal.
y₁ = y₂ = y = 8.0 m
v² = [tex]\frac{m2-m1}{m2+m1} \ 2g y[/tex]
Let's calculate.
[tex]v^2 =\frac{22.9-13.6}{ 22.9+13.6} \ 2 \ 9.8 \ 8 \\ v = \sqrt{39.95}[/tex]
v = 6.32 m / s
In conclusion using the conservation of energy we can find the result of the velocity when the body 2 reaches the ground is:
v = 6.32 m / s
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Answer:
Explanation:
vo= 0
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t=?
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Here it is, hope it helps!
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Answer:
250N
Explanation:
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Answer:
250 N
Explanation:
Refer the attachment for explanation.
xác định quỹ của chất điểm chuyển động với phương trình chuyển động sau đây
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Answer:
pls English
Explanation:
plsss,ಠ﹏ಠಠ﹏ಠಠ﹏ಠಠ﹏ಠಠ﹏ಠಠ﹏ಠಠ﹏ಠ
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Answer: False
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a) the person’s hand
b) the tube
c) the hanging weight
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a) doubled
b) halved
c) tripled
d) quadrupled
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a) doubled
b) halved
c) tripled
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just doing your module wag asa brainly ok malaki kna
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mass
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(Answer B)
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b nuclear
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I don’t get anything that this question is asking me and I need to turn this in quick
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Answer:
Hey there
when they meat they will constructivly interfere, wich means they will become one big wave. After that they will pas right through each other and continue.
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Answer:
agents of socialization are:-
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One train (22,680 kg) moving east at 170 km/h collides with a car (1,200 kg) that was moving north at 5 km/h. They get attached to each other, moving in the direction of the train. What is the final velocity of the objects and the type of collision? If the collision happened in 1.2X10-3 seconds, what was the force? How much kinetic energy was lost?
Answers
According to the law of collision'
m1u1 + m2u2 = (m1+m2)v
Given the following:
m1 = 22,680kg
u1 =170km/h
m2 = 1200kg
u2 = 5km/hr
Get the final velocity "v"
22680(170) + 1200(5) = (22680 + 1200)v
3855600 + 6000 = 12880v
3,861,600 = 12880v
v = 3,861,600/12,880
v = 229.82km/hr
Hence the final velocity of the objects is 229.82km/hr
Since energy was lost after the collision, the type of collision that occurs is an elastic collision.
According to Newton's second law, the formula for calculating the force is expressed as;
F = ma
F = m(v-u)/t
F = 22680+1200(229.82-175)/t
Ft = 23880(54.82)
F = 1,309,101.6/0.0012
F = 1,090,918,000N
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Kinetic energy after collision = 1/2 * 12880 * 229.82²
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Kinetic energy before collision = 1/2 * 22680(170)²+ 1/2*1200(5)²
Kinetic energy before collision = 327,726,000 + 15000
Kinetic energy before collision = 327,741,000
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Learn more here: https://brainly.com/question/9537044
An object if mass 30 kg is falling in air and experiences a force due to air resistance of 50 newtons.
Answers
Hi there!
On the object, we know that there are two forces working on the object:
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∑F/m = a
Plug in values:
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Hi there!
This is an example of a perfectly inelastic collection, so:
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Answers
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Answers
Answer:
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Answers
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Answer:
In the United States and neighboring countries, however, household outlets run at 110 or 120 volts. This can pose a serious problem for travelers. Connecting a 220-volt appliance to a 110-volt outlet can damage or destroy the appliance
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Answer:
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My reflective journal.
Direction: Supply the sentence below to complete the information askes.
I learned that comparing arguments________________________One example of this is____________. We can use
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WOW ANG HIRAP NG TANONG MOExplanation:
Di ko yan masasagutan
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[tex]lol[/tex]
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Answers
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Answers
Answer:
answer to your question is 263.26kg
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Answers
Answer: The pressure in a liquid is different at different depths. Pressure increases as the depth increases. The pressure in a liquid is due to the weight of the column of water above. The greater pressure at the bottom would give a greater 'force per unit area' on the wall.
Explanation:
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A student uses a ping pong ball launcher to shoot a projectile across a classroom. the launcher sits at the edge of a table and releases the ping pong ball 1.2 meters above the floor. as the ball leaves the launcher it has a speed of 13 m/s. if 5m/s is in the upwards direction and 12m/s is in the forward direction how far from the base of the table does the ping pong ball land
Answers
Answer:
Explanation:
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s = s₀ + v₀t + ½at²
vertical analysis with floor level as origin
0 = 1.2 + 5t + ½(-9.8)t²
0 = 1.2 + 5t - 4.9t²
quadratic formula positive answer
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t = 1.22 s is the flight time
horizontal analysis with launcher as origin
s = 0 + 12(1.22) + ½(0)1.22²
s = 14.6517... 15 m
I NEED HELP PLZZZZZZ