Two masses m1 13.6 kg and m2 22.9 kg are connected by a rope that hangs over the pulley. The pulley has form of solid cylinder of radius 0.6 m and mass 10.6 kg. Initially m1 is on the ground and m2 rests 8.0 m above the ground. At some moment system is released. Find velocity of m2 just before it hits the ground. Neglect friction in the pulley.
Answers
The conservation of energy allows finding the result of the velocity of the body 2 when it reaches the ground is:
v = 6.32 m / s
Given parameters
Body mass 1 m₁ = 13.6 kg body mass 2 m₂ = 22.9 kg height y = 8.0 mTo find
speed.
The conservation of energy is one of the most important principles of physics, it establishes that if there is no friction force, the mechanical energy is conserved at all points, where the mechanical energy is the sum of the kinetic energy plus the different potential energies.
Let's write the energy at two points before we drop the system.
Em₀ = U₁ + U₂
Where potential energy is
U = m g y
They indicate that body 1 is on the ground and body 2 is at a height .
y₂ = 8 m
Em₀ = m₂ g y₂
Let's write the energy of the system for when body 2 is reaching the ground
[tex]Em_f[/tex] = K₂ + K₁ + U₂ + U₁
At this moment body 2 is reaching the ground, its height is zero and the height of body 1 is y₁ = 8 m. Since the two bodies are joined by the rope, they must have the same speed..
[tex]Em_f[/tex] = ½ (m₁ + m₂) v² + m₁ g y₁
As there is no friction, the energy is conserved.
Em₀ = Em_f
m₂ g y₂ = ½ (m₁ + m₂) v² + m₁ g y₁
The rope is inextensible, the heights are equal.
y₁ = y₂ = y = 8.0 m
v² = [tex]\frac{m2-m1}{m2+m1} \ 2g y[/tex]
Let's calculate.
[tex]v^2 =\frac{22.9-13.6}{ 22.9+13.6} \ 2 \ 9.8 \ 8 \\ v = \sqrt{39.95}[/tex]
v = 6.32 m / s
In conclusion using the conservation of energy we can find the result of the velocity when the body 2 reaches the ground is:
v = 6.32 m / s
Learn more here: brainly.com/question/14688403
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Answer:
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Answer: False
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b) halved
c) tripled
d) quadrupled
Q3. If the velocity of the stopper were doubled, but other things remained the same, the hanging mass would need to be
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b) halved
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just doing your module wag asa brainly ok malaki kna
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keke
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The U.S. uses a household voltage of 110 V. However, electric stoves and dryers are wired with
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220 V outlets are made in different shapes so that appliances cannot be accidentally
interchanged.)
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Answer:
In the United States and neighboring countries, however, household outlets run at 110 or 120 volts. This can pose a serious problem for travelers. Connecting a 220-volt appliance to a 110-volt outlet can damage or destroy the appliance
The gravitational field strength on earth is 10n/kg. find the weight of an object of mass 25kg
Answers
Answer:
250N
Explanation:
weight = Mass(in kg) × Gravitational field strength
25 × 10 = 250N
Answer:
250 N
Explanation:
Refer the attachment for explanation.
I don’t get anything that this question is asking me and I need to turn this in quick
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Answer:
Hey there
when they meat they will constructivly interfere, wich means they will become one big wave. After that they will pas right through each other and continue.
A 0.038-kg bullet enters a 3.2-kg watermelon and embeds itself in the melon. The melon is immediately set into motion with a speed of 3.82 m/s. The bullet remains lodged inside the melon. What was the entry speed of the bullet (m/s)?
Answers
Hi there!
This is an example of a perfectly inelastic collection, so:
mb = mass of bullet
vb = velocity of bullet
mw = mass of watermelon
v = velocity final
mbvb = (mb + mw)v
Rearrange to solve for the velocity of the bullet:
vb = (mb + mw)v/mb
Plug in values:
vb = (0.038 + 3.2)(3.82)/(0.038) = 325.504 m/s
An object if mass 30 kg is falling in air and experiences a force due to air resistance of 50 newtons.
Answers
Hi there!
On the object, we know that there are two forces working on the object:
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-Force due to air resistance
Let the positive direction of the force be downwards (direction of the acceleration)
We can write the summation of forces as:
∑F = Mg - Fa
Plug in values. Let g ≈ 10 m/s²
∑F = 30(10) - 50 = 250N
Find the acceleration using the formula:
∑F = m · a
∑F/m = a
Plug in values:
250/30 = 8.33 m/s²
Your new motorcycle weighs 2580 N.
The acceleration of gravity is 9.8 m/s2.
What is its mass?
Answer in units of kg.
Answers
Answer:
answer to your question is 263.26kg
Explanation:
m=f÷a ,m=2580÷9.8=263.26kg
A 10 g dime and a 200 g gold coin are dropped from the Empire State Building in
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A.They both hit the ground at the same time
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D.The 10 g dime hits the ground first
Answers
Answer:
Explanation:
The both hit the ground at the same time. There is no air resistance and that includes the factors brought up in B.
C and D are both eliminated. If you dropped an 800 kg honda Fit it would hit the ground at the same time as the two coins. When you look at the formulas used to derive time, they look like
d = vi * t + 1/2 a* t^2
vi = 0
the distance to fell is the same for all three masses.
a is the same for all 3 masses.
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I NEED HELP PLZZZZZZ
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Weight refers to the pull of _________ on an object.
Question 2 options:
mass
gravity
volume
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Answer: Weight refers to the force of gravity acting upon an object.
(Answer B)
is this kinetic energy ---> elastic potential energy OR elastic potential energy ---> kinetic energy ??
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Answer:
it is potential energy ---- kinetic energy
xác định quỹ của chất điểm chuyển động với phương trình chuyển động sau đây
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Answer:
pls English
Explanation:
plsss,ಠ﹏ಠಠ﹏ಠಠ﹏ಠಠ﹏ಠಠ﹏ಠಠ﹏ಠಠ﹏ಠ
If a car accelerates from rest at a constant of rate of 5.5m/s^2 north, how long will it take for the car to reach a velocity of 28 m/s north?
Answers
Answer:
Explanation:
vo= 0
a=5.5m/s^2
v= 28 m/s
t=?
v=vo+at
at=v-vo
t=(v-vo)/a
t=28/5.5
t=5.09 seconds
CEK- 9. If the speed of sound at 0° C is vo, the velocity at 273° C will be (a) 2 vo (b) 0.5 vo b (c) (d) 0.7 vo 1.4 vo
Answers
Answer:
D
Explanation:
273 * 0.6=163.8
vo≈331
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Answer: The pressure in a liquid is different at different depths. Pressure increases as the depth increases. The pressure in a liquid is due to the weight of the column of water above. The greater pressure at the bottom would give a greater 'force per unit area' on the wall.
Explanation:
the electric field at point 4.00 cm from the axis, measured radially outward from the midpoint of the shell.
Answers
If a 2 kg block of aluminium (SHC: 921 J/kg°C) is heated from 20°C to 40°C, how much energy was transferred to it?
Answers
H = mc∆T
where, H=heat energy
c = SHC
H = 2*921*(40-20)
H = 36840J
H = 36.84KJ
The energy transferred to it is 36.84KJ
The energy transferred to aluminum from 20°C to 40 °C is equal to 36840 J.
What is the specific heat capacity?The specific heat capacity can be described as the quantity of heat required to increase the temperature of 1 unit of substance by one degree Celsius. The specific heat capacity of the substance depends upon the nature of the substance.
The mathematical equation is used to calculate the specific heat is equal to:
[tex]Q = m\times C\times \triangle T[/tex]
Given, the mass of the aluminum block, m = 2 Kg
The initial temperature of aluminum, T₁ = 20 °C
The final temperature of the aluminum, T₂ = 40 °C
The specific heat capacity of aluminum, C = 921 J/kg°C
The energy transferred to the aluminum block:
Q = 2 × 921 × (40-20)
Q = 36840 J
Therefore, the energy transferred to aluminum from 20°C to 40°C is 36840 J.
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brainly.com/question/28302909
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If the ray is perpendicular to the surface, then the incident ray, the reflected ray and the transmitted (refracted) ray all lie along the same line (i.e they are collinear). If the ray is not perpendicular to the surface, then the ray appears to be bent at the surface.
A 10-cm-long archerfish begins such a leap with its body vertical in the water, using its fins and undulating its body to propel itself sharply upward. Its acceleration steadily decreases as it leaves the water because less of its body and fewer of its fins are in contact with the water.
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What height above the water does it reach?
Answers
Answer:
Explanation:
Velocity will be equal to the area under the curve of the acceleration-time plot.
v = ½(45)(0.075) = 1.6875
v = 1.7 m/s
h = (0² - 1.6875²) / (2(-9.8)) = 0.145288...
h = 15 cm
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A student uses a ping pong ball launcher to shoot a projectile across a classroom. the launcher sits at the edge of a table and releases the ping pong ball 1.2 meters above the floor. as the ball leaves the launcher it has a speed of 13 m/s. if 5m/s is in the upwards direction and 12m/s is in the forward direction how far from the base of the table does the ping pong ball land
Answers
Answer:
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s = s₀ + v₀t + ½at²
vertical analysis with floor level as origin
0 = 1.2 + 5t + ½(-9.8)t²
0 = 1.2 + 5t - 4.9t²
quadratic formula positive answer
t = (-5 - √(5² - 4(-4.9)(1.2))) / (2(-4.9))
t = 1.22 s is the flight time
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s = 14.6517... 15 m
A box of mass 20kg rests on a flat horizontal floor. if the density of air is negligible. Draw a diagram showing forces acting on the box
Answers
There are only two forces acting on the box!!!
Here it is, hope it helps!
One train (22,680 kg) moving east at 170 km/h collides with a car (1,200 kg) that was moving north at 5 km/h. They get attached to each other, moving in the direction of the train. What is the final velocity of the objects and the type of collision? If the collision happened in 1.2X10-3 seconds, what was the force? How much kinetic energy was lost?
Answers
According to the law of collision'
m1u1 + m2u2 = (m1+m2)v
Given the following:
m1 = 22,680kg
u1 =170km/h
m2 = 1200kg
u2 = 5km/hr
Get the final velocity "v"
22680(170) + 1200(5) = (22680 + 1200)v
3855600 + 6000 = 12880v
3,861,600 = 12880v
v = 3,861,600/12,880
v = 229.82km/hr
Hence the final velocity of the objects is 229.82km/hr
Since energy was lost after the collision, the type of collision that occurs is an elastic collision.
According to Newton's second law, the formula for calculating the force is expressed as;
F = ma
F = m(v-u)/t
F = 22680+1200(229.82-175)/t
Ft = 23880(54.82)
F = 1,309,101.6/0.0012
F = 1,090,918,000N
Hence the required force is 1,090,918,000N
KE lost = Kinetic energy after collision - Kinetic energy before collision
Kinetic energy after collision = 1/2 * 12880 * 229.82²
Kinetic energy after collision = 340,142,976.656 Jolues
Kinetic energy before collision = 1/2 * 22680(170)²+ 1/2*1200(5)²
Kinetic energy before collision = 327,726,000 + 15000
Kinetic energy before collision = 327,741,000
Kinetic energy lost = 340,142,976.656 - 327,741,000 = 12,401,976.656Joules
Learn more here: https://brainly.com/question/9537044
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My reflective journal.
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Answer:
agents of socialization are:-
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peers
school
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Answers
Answer:
SI units are used for scientific works to bring uniformity in measurements all over the world.