true or false a change in state of matter would be considered a physical change​

Answer:

730 N

Explanation:

force =mass×acceleration

force= 73kg × 10 m/s

f=730N

Answer: B. strontium

Explanation: This is due to electrons being further away from the nucleus in strontium.

Answer:

cardiac muscle

Explanation:

because they help the heart to pump blood to all parts of the body

Answer:

Muscle is also very important to everyone because we need our muscles to survive. The HEART is the strongest muscle in our body and is always looking to get stronger. Muscles enable us to be active and exercise. Our strength comes for our muscles and how much they are used.

Explanation:

The mass of CO2 obtained in the reaction by stoichiometry is 30.8 g.

The equation of the reaction is;

2HCl(aq) + CaCO3(s) -----> CaCl2(aq) + H2O(l) + CO2(g)

The mass of the HCl reacted is obtained from;

Density = mass/volume

Mass = Density × volume =  1.140 g/mL ×  43.435 mL = 49.5 g

Number of moles of HCl =  49.5 g/36.5 g/mol = 1.4 moles

If 2 moles of HCl reacts produces 1 mole of CO2

1.4 moles of HCl produces x moles of CO2

x = 1.4 moles × 1 mole/ 2 moles = 0.7 moles

Mass of CO2 produced = 0.7 moles  x 44 g/mol = 30.8 g

In the second case, the same volume of acid is used hence the same mass of CO2 is obtained.

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Answer:

Length of ramp = 77.27ft

Explanation:

Step 1 - Sketch a diagram

Make a line about 15 deg. above the horizontal x-axis. Draw the horizontal and vertical components to form a right triangle. See image if you don’t understand.

Step 2 - Label your diagram

Your triangle creates a 15 deg. angle with the x-axis and we know the vertical distance from the top of the ramp to the ground is 20 ft.

Step 3 - Use trig to make an equation and solve

SOH CAH TOA

I’m this problem we know the angle, know “opposite, and we are solving for the hypotenuse of the triangle. Therefore, it would be easiest to use SOH or sin(theta)= (opp./hyp.) Plug in the numbers and solve for the hypotenuse.

All work is shown in the attached image.

Answer:

c.boron-11

Explanation:

The atomic mass of boron is 10.81 u.

And 10.81 u is a lot closer to 11u than it is to 10u, so there must be more of boron-11.

To convince you fully, we can also do a simple calculation to find the exact proportion of boron-11 using the following formula:

(10u)(x)+(11u)(1−x)100%=10.81u

Where u is the unit for atomic mass and x is the proportion of boron-10 out of the total boron abundance which is 100%.

Solving for x we get:

11u−ux=10.81u

0.19u=ux

x=0.19

1−x=0.81

And thus the abundance of boron-11 is roughly 81%.

By decomposing 157g of NaCl, approximately 1.35 moles of chlorine can be produced.

To determine the number of moles of chlorine that could be produced by decomposing 157g of NaCl, we need to use the molar mass of NaCl and apply stoichiometry.

The molar mass of NaCl is the sum of the atomic masses of sodium (Na) and chlorine (Cl), which is approximately 22.99 g/mol + 35.45 g/mol = 58.44 g/mol.

Now, we can calculate the number of moles of NaCl:

Moles of NaCl = Mass of NaCl / Molar mass of NaCl

Moles of NaCl = 157 g / 58.44 g/mol

Moles of NaCl ≈ 2.69 mol

According to the balanced equation 2NaCl → 2Na + Cl₂, we can see that for every 2 moles of NaCl, we produce 1 mole of Cl₂.

Therefore, using the stoichiometric ratio, we can calculate the number of moles of chlorine produced:

Moles of Cl₂ = (Moles of NaCl / 2) × 1

Moles of Cl₂ = 2.69 mol / 2

Moles of Cl₂ ≈ 1.35 mol

Thus, by decomposing 157g of NaCl, approximately 1.35 moles of chlorine can be produced.

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Answer:

4.002602

Explanation:

Seems Am Converting Between Grams Helium And Mole.

Answer:

397 L

Explanation:

Recall the ideal gas law:

[tex]\displaystyle PV = nRT[/tex]

If temperature and pressure stays constant, we can rearrange all constant variables onto one side of the equation:

[tex]\displaystyle \frac{P}{RT} = \frac{n}{V}[/tex]

The left-hand side is simply some constant. Hence, we can write that:

[tex]\displaystyle \frac{n_1}{V_1} = \frac{n_2}{V_2}[/tex]

Substitute in known values:

[tex]\displaystyle \frac{(3.31 \text{ mol})}{(100 \text{ L})} = \frac{(13.15\text{ mol })}{V_2}[/tex]

Solving for V₂ yields:

[tex]\displaystyle V_2 = \frac{(100 \text{ L})(13.15)}{3.31} = 397 \text{ L}[/tex]

In conclusion, 13.15 moles of argon will occupy 397* L under the same temperature and pressure.

(Assuming 100 L has three significant figures.)

Answer:

The basis for incomplete combustion is that instead of carbon dioxide being produced alongside water, carbon monoxide and carbon is produced instead, the carbon being released as soot. That handily sets the products up for the equation.

And combustion is simply a reaction between a fuel, in this case, methanol and oxygen.

The chemical formula for methanol is CH3OH. Simply write the reactants and products as a chemical equation and balance it, and you have the equation.

Explanation:

Answer:

It increases the freezing point

Explanation:

The salt lowers the temperature at which water freezes. :)

The branched alkanes in boxes two and three all have molecular formula C6H14 and are isomers of the compound shown.

Isomers are compounds that has the same molecular formula but different structural formulas. Hence, isomers of compounds can be represented by the same molecular formula since they contain the same number of each atom.

The molecule shown has molecular formula C6H14. The branched alkanes in boxes two and three all have molecular formula C6H14 and are isomers of the compound shown.

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Answer:

mole

Explanation:

Since Sodium Chloride is ionic, it cannot be considered a molecule as per the definition of a molecule requires each of its components to be bonded together.

The formula mass of a compound is the mass of its one molecule. Since molecule is the basic unit of a compound. Thus, the relative formula mass in grams is the mass of one molecule.

Sodium fluoride is an ionic compound formed by the combination of sodium and fluorine by loss of one electron from sodium to fluorine. The  formula mass of fluorine is calculated from the atomic masses of sodium and fluorine.

Atomic mass of fluorine is 19 g/mol and mass of sodium is 23 g/mol. Here only one sodium and one fluorine is present. Hence the formula mass is 23+ 19 = 42.

This is the mass of one unit of NaF. Thus mass of one sodium fluoride molecule. Where as its molar mass may differ from the formula mass. Since the molar mass is the mass of one mole of the compound NaF. One mole of compound contains 6.02 × 10²³ molecules.

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Answer:

Thermosphere

Explanation:

More specifically the ionosphere, since the ionosphere is the lower part of the thermosphere.

Hope this helps!

Answer:

A compound is something like atoms coming together as a team, and a mixture is 2 or more substances mixing together.

Explanation:

Answer:

c)

Explanation:

because alpha particles can go through it

Answer:

The Moon has an atmosphere.

Explanation:

The Moon has an atmosphere, but it is very tenuous. Gases in the lunar atmosphere are easily lost to space. Because of the Moon's low gravity, light atoms such as helium receive enough energy from solar heating so that they escape in just a few hours.

Answer:

A. increase

Explanation:

the smaller the size of the ionic compounds, the more closer they get packed together. This means electrostatic attraction also increases, which means the ionic bonds gets stronger...therefore increases the melting point

The new volume when pressure increases to 2,030 kPa is 0.8L

BOYLE'S LAW:

The new volume of a gas can be calculated using Boyle's law equation:

P1V1 = P2V2

Where;

According to this question, a 4.0 L balloon has a pressure of 406 kPa. When the pressure increases to 2,030 kPa, the volume is calculated as:

406 × 4 = 2030 × V2

1624 = 2030V2

V2 = 1624 ÷ 2030

V2 = 0.8L

Therefore, the new volume when pressure increases to 2,030 kPa is 0.8L.

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Answer:

your question is not very clear but I think the answer is either

Primary (non-rechargeable)

Secondary (rechargeable) or

Lithium-ion battery.

Rechargeable li-ion button cell.

The effect of a catalyst is

A catalyst allows an alternative reaction pathway that leaves activation energy than the uncatalysed reaction. This does not change the frequency of collision.

Frequency of collision depend upon concentration of reactant temperatures

Hence, catalyst lowers the activation energy of reaction thereby making it easier for the reactant to get over the energy hump.

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Answer:

55 centimeters

Explanation:

20+15+25

Easy!!

2+17=19

#hope that helps

Answer:

To find the answer you may

2+17=19

Explanation:

so that is the answer I'm sorry,to not give all the solutions

Answer:

D. 17,190 years old

Answer:

Fr

Explanation:

I took the test

The number of grams of ammonium nitrate (NH₄NO₃) it would take for all the barium hydroxide to react is 18.7g

First, we will write the balanced chemical equation for the reaction

The balanced chemical equation for the reaction is

Ba(OH)₂ + 2NH₄NO₃ → 2NH₄OH + Ba(NO₃)₂

This means, 1 mole of barium hydroxide is required to react with 2 moles of ammonium nitrate

Now, we will calculate the number of moles of barium hydroxide present.

Mass of barium hydroxide (Ba(OH)₂) = 20 g

Using the formula

[tex]Number\ of\ moles = \frac{Mass}{Molar\ mass}[/tex]

Molar mass of Ba(OH)₂ = 171.34 g/mol

∴ Number of moles of Ba(OH)₂ present =[tex]\frac{20}{171.34}[/tex]

Number of moles of Ba(OH)₂ present = 0.116727 mole

Now,

Since 1 mole of barium hydroxide is required to react with 2 moles of ammonium nitrate

Then,

0.116727 mole of barium hydroxide will react with 2 × 0.116727 mole of ammonium nitrate

2 × 0.116727 = 0.233454 mole

∴ Number of moles of NH₄NO₃ required is 0.233454 mole

Now, for the mass of ammonium nitrate (NH₄NO₃) required

From the formula

Mass = Number of moles × Molar mass

Molar mass of NH₄NO₃ = 80.043 g/mol

∴ Mass of NH₄NO₃ required = 0.233454 × 80.043

Mass of NH₄NO₃ required = 18.68636 g

Mass of NH₄NO₃ required ≅ 18.7g

Hence, the number of grams of ammonium nitrate (NH₄NO₃) it would take for all the barium hydroxide to react is 18.7g

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Answer:

4.5425806678891E+22mol

Explanation: