. True or False: A bystander intervention is the term used to define when an individual actively moves in and changes the outcome of a situation.

Answer:

Correct answer: Ic₂ = 48 mA = 48 · 10⁻³ A

Explanation:

U₁ = 12 V DC first battery voltage

Ic₁ = 24 mA = 24 · 10⁻³ A Intensity of current with the first battery

U₂ = 24 V DC second battery voltage

Ic₂ = ? Intensity of current with the second battery

The formula that applies to a simple electric circuit under the Ohm's law is:

R = U / Ic

where R is the total resistance in the electrical circuit and it is constant.

R = U₁ / Ic₁ = U₂ / Ic₂ ⇒ U₁ / Ic₁ = U₂ / Ic₂ ⇒ Ic₂ = (U₂ · Ic₁) / U₁

Ic₂ = (24 · 24) / 12 = 48 mA

Ic₂ = 48 mA = 48 · 10⁻³ A

grujan50

Virtuoso

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Answer:

Sweating

Explanation:

Sweating allows the body to release heat, causing the body to cool itself.

Hi there!

We can use Ampère's Law to derive an expression for the magnetic field strength produced by an infinitely long current-carrying wire:

[tex]\oint B \cdot dl = \mu_0 I_{encl}[/tex]

B = Magnetic Field Strength (T)
dl = Differential length along path

μ₀ = Permeability of Free Space (Tm/A)

I = Enclosed current (A)

The integral is a cross product, so the cosine of the angle between the magnetic field and the path of integration is used. However, for a straight current-carrying wire, the path is ALWAYS parallel to the magnetic field, so since cos(180) = 1, we can disregard the cross product.

Additionally, the path of integration is equivalent to:

[tex]l = 2\pi r[/tex]

[tex]B \cdot l = \mu_0 I_{encl}\\\\B * 2\pi r = \mu_0 I_{encl}\\\\B = \frac{\mu_0 I_{encl}}{2\pi r }[/tex]

Rearrange to solve for enclosed current:

[tex]I_{encl} = \frac{2\pi rB}{\mu_0} = \frac{2\pi (0.02)(0.0037)}{(4\pi *10^{-7})} = \boxed{370 A}[/tex]

Answer:

The wavelength is =2.87m.

Explanation:

The speed of sound, the frequency and the wavelength is related by the equation

v=fλ

speed of sound is v=340ms

frequency is f=977Hz

wavelength is λ= v/f = 977/340 =2.87m

Answer:

.348 meters

Explanation:

Speed = wavelength * frequency

 340   =    wl       *  977

340 /977 = wavelength = .348 m

Answer:

The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object

Explanation:

it's newton's second law

Neon lamps located near a powerful radio station are seen to glow faintly at night because radio waves may generate a potential difference in the neon gas.

A neon lamp is a lamp containing neon gas as well as other types of gases and two electrodes.

In a neon lamp, the electricity is generated by striping negative electrons from neon atoms, which ionize these atoms.

The radio waves can also ionize atoms in the neon lamp by generating a potential difference in the neon particles of the lamp, thereby glowing faintly at night.

In conclusion, neon signs located near a powerful radio station are seen to glow faintly at night because radio waves may generate a potential difference in the neon gas.

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Answer:

C. The poster provides an emotional picture of a young, innocent girl with a slightly worried expression to make protective feelings.

Explanation:

The girl looks quite worried in the poster. Attached is the image:

Answer:

What is a reality based condition with self-defeating patterns?

Terms in this set (35) A psychotic is reality based, yet needs psychotherapy to correct their values. A neurotic is a non-reality based person with self-defeating patterns of behavior.

Explanation:

The net electric force acting on a positive test charge at the origin is determined as ¹/₉(kq₁q₂).

The net electric force on the charges is calculated as follows;

F = kq₁q₂/r²

where;

[tex]|r| = \sqrt{(x_2-x_1)^2+ (y_2-y_1)^2} \\\\|r| = \sqrt{(-4--4)^2+ (0--3)^2} \\\\|r| = \sqrt{(0)^2 + (3)^2} \\\\|r| = 3 \ units[/tex]

[tex]F_{net} = \frac{kq_1q_2}{3^2} \\\\F_{net} = \frac{1}{9} (kq_1q_2) , \ N[/tex]

Thus, the net electric force acting on a positive test charge at the origin is determined as ¹/₉(kq₁q₂).

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During a race, a sprinter accelerated 1.8 m/s 2 in 2.5 seconds. The sprint increase with this amount of acceleration by 4.5 m/s.

Acceleration is the time rate of change of velocity.

Acceleration a = velocity v / time t

1.8 = v/2.5

v = 4.5 m/s

The sprint increase with this amount of acceleration by 4.5 m/s.

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Answer:

Speed of A + B = 1 m/s

Explanation:

The speed of B = 0    because the distance does not change with time .

The speed of A =   1 m/s   ( the slope of the line)

The net force on the block is 20.678 N. Force is defined as the product of mass and acceleration. Its unit is Newton.

Force is defined as the push or pull applied to the body. Sometimes it is used to change the shape, size, and direction of the body.

Anujan rope pulls with a force of 35 N [35° N of W]. The force is resolved in x and y direction as;

[tex]\rm F_{1x}= 35 cos 35^0 \\\\ F_{1y}=35 sin 35^0[/tex]

Piragavy pulls with a force of 11 N [41° S of E]. The force is resolved in x and y direction as;

[tex]\rm F_{2x}= 11 cos 41^0 \\\\ F_{2y}=11 sin 41^0[/tex]

The net force on the block is;

[tex]\rm F_{net}=F_{1x}-F_{2x}\\\\\ F_{net}=35 \ cos 35^0- 11 \cos 41^0 \\\\ F_{net}=20.678 \ N[/tex]

Hence,the net force on the block is 20.678 N.

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Answer:

B because since SHE is in the team she is in group and it is bias because she treats the other teams as competition. Hope this helps!

Explanation:

Answer:

it’s going to be times 3

Explanation:

so the answer would be three times which means it will change by a factor of 3.

I’m sorry I wrote it wrong the first time.

(a) The acceleration of the system is determined as 1.58 m/s².

(b) The relative weight of P is pounds is determined as 0.14 lb.

The acceleration of the system is calculated as follows;

W - T = m₂a --- (1)

T = m₁a ----(2)

μmgsinθ - m₁a = m₂a

(0.3 x 3 x 9.8 x sin40) - (0.4 + 0.2)a = 3a

5.67 - 0.6a = 3a

5.67 = 3.6a

a = 5.67/3.6

a = 1.58 m/s²

W = ma

W = 0.4 x 1.58

W = 0.632 N = 0.14 lb

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Answer:

let i represent due East and j due north

X (displacement) = (15 - 5) i - 7 j - 3 i + 5 j = 7 i - 2 j

Total displacement = (7^2 + 2^2)^1/2 = 7.28     vector displacement

tan θ = -2 / 7 = -15.9 deg     or 15.9 deg S of E

note N distance was -2 cm

E distance was 7 cm

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

Here we go ~

Speed of the car is 75 miles per hour and it travels for 14 hours. so the distance travelled by it in the given period of time can be calculated using this formula ~

[tex]\qquad \sf  \dashrightarrow \: d = v \sdot t[/tex]

[tex]\qquad \sf  \dashrightarrow \: d = 75 \times 14[/tex]

[tex]\qquad \sf  \dashrightarrow \: d = 1050 \: \: miles[/tex]

so, it can travel 1050 miles in 14 hours

Answer:

1050 miles

Explanation:

Simply:

d =  75 m/hr   *  14 hr   =1050 miles

 ( see how the 'hr' cancels and you are left with miles ?)

Answer:

What is the interaction between two different species in an ecosystem called?

Interactions between different species in a community are called interspecific interactions—inter- means "between." Different types of interspecific interactions have different effects on the two participants, which may be positive (+), negative (-), or neutral (0).

Explanation:

Hi there!

Recall Faraday's Law:
[tex]\epsilon = N\frac{d\Phi_B}{dt}[/tex]

ε = Emf (V)
N = Number of loops

ΦB = Magnetic Flux (Wb)
t = time (s)

Since the magnetic field is constant, we can take this out of the time derivative:
[tex]\frac{d\Phi_B}{dt} = B * \frac{dA}{dt}[/tex]

Therefore:
[tex]\epsilon = N B \frac{dA}{dt}[/tex]

We can express 'A', the area in which the magnetic field passes as:

[tex]A = Acos(\omega t)[/tex]

Taking the time derivative:

[tex]\frac{dA}{dt} = A\omega sin(\omega t)[/tex]

ω = angular speed of coil (rad/sec)

Now, combine with the above expression:

[tex]\epsilon = NBA\omega sin(\omega t)[/tex]

The maximum output will occur when the loop's area vector is PERPENDICULAR to the field, so sin(ωt) = 1.

Therefore:
[tex]\epsilon = NBA\omega \\\\[/tex]

Rearrange to solve for ω:

[tex]\omega = \frac{\epsilon}{NBA}\\\\\omega = \frac{24}{(200 * (.10^2) * 0.25} = \boxed{48 \frac{rad}{sec}}[/tex]

Answer:

distance = 60 miles

Explanation:

The statements 1,4 and 5 accurately describe the influence of distance on gravitational and electrical forces.

Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.

Gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.

Decreasing the distance would increase the gravity of the planet.

The following statements accurately describe the influence of distance on gravitational and electrical forces.

1. The gravitational force has an infinite reach.

4. The gravitational force is inversely proportional to the square of the distance.

5. The electrical force is inversely proportional to the square of the distance.

Hence, options 1,4 and 5 are correct.

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Answer:

electron in the outermost

Explanation:

These are the electrons available for bonding or transfer

  protons do are not involved in actual bonding

Answer:

b

Explanation:

Atoms form chemical bonds using electrons in the outermost energy level, otherwise known as valence electrons.

For atoms to bond, they must either gain or lose electrons.

By gaining electrons, the atom attains a negative charge.

By losing electrons, the atom attains a positive charge.

Answer:

x = 4 t + 2 t^2      

the displacement is x which is zero at t = 0 and then increases indefinitely as t increases indefinitely

Answer:

The answer is C. Seismic waves.

Explanation:

Answer:

B. 2270 kg

Explanation:

We know that :

We are given :

Finding mass

Answer:

I believe it would be a metallic bond.

Explanation:

Explanation:

Fnet = m.a

= (20)(10)

= 200N