what is the difference between the maximum and minimum of the quantity 14a2b2, where a and b are two nonnegative numbers such that a b=4
The difference between the minimum and the maximum value of the expression 14a^2b^2 is 224.
The maximum of the quantity 14a^2b^2 occurs from the given equation, we know that a = 4/b. Substituting this into the expression for 14a^2b^2, we get:
14(4/b)^2b^2 = 14(16/b^2)*b^2
=224
So the maximum value of 14a^2b^2 is 224, here a, b is non-negative integers, to get the minimum value of the expression is one of the integer must be zero if the one of the integers is zero then the minimum value of the expression is becomes 0.
Explanation; -
STEP 1:- To get the maximum value of the function use the given conditions a b=4 and substitute in the given expression 14a^2b^2.
STEP2:- After substituting the value evaluate the expression and get the maximum value of the expression.
STEP3:- To get the minimum value of the expression minimize the value of the a and b by the observation it is clear that the minimum value of the expression is zero.
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What is the answer to 71270-32425
Answer: 38845
Step-by-step explanation:
Answer:
38,845
Step-by-step explanation:
What’s is the distance between -3.1 and positive 4.1
find the first four terms of the taylor series for the function 3/x about the point α = 2 . (your answers should include the variable x when appropriate.
3/x = ?
The first four terms of the Taylor series for 3/x about the point α = 2 are: 3/2 - (3/4)(x-2) + (3/4)(x-2)² - (9/16)(x-2)³.
To find the Taylor series for a function, we need to calculate its derivatives at the point of expansion and then substitute those values into the general formula for the Taylor series. The general formula for the Taylor series of a function f(x) about a point a is:
f(x) = f(a) + f'(a)(x-a)/1! + f''(a)(x-a)²/2! + f'''(a)(x-a)³/3! + ...
Here, we want to find the Taylor series for the function f(x) = 3/x about the point α = 2. First, we will calculate the derivatives of f(x):
f(x) = 3/x
f'(x) = -3/x²
f''(x) = 6/x³
f'''(x) = -18/x⁴
Now we can substitute these derivatives into the general formula for the Taylor series to get:
f(x) = f(2) + f'(2)(x-2)/1! + f''(2)(x-2)²/2! + f'''(2)(x-2)³/3! + ...
We can calculate the first few terms of this series:
f(2) = 3/2
f'(2) = -3/4
f''(2) = 3/4
f'''(2) = -9/16
Substituting these values into the series, we get:
3/x = 3/2 - (3/4)(x-2) + (3/4)(x-2)² - (9/16)(x-2)³ + ...
So the first four terms of the Taylor series for 3/x about the point α = 2 are 3/x = 3/2 - (3/4)(x-2) + (3/4)(x-2)² - (9/16)(x-2)³
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algebraically determine the behavior of 2e ^−x dx.
The behavior of the integral of [tex]2e^(-x)[/tex] dx, given by the function [tex]-2e^(-x) + C[/tex], shows an exponential decay.
To algebraically determine the behavior of the integral of [tex]2e^(-x) dx[/tex], we need to perform the integration and observe the resulting function.
Step 1: Integrate the function with respect to x:
We want to find the integral ∫[tex]2e^(-x) dx[/tex]. To do this, we apply the integration rule ∫[tex]e^(ax) dx = (1/a)e^(ax) + C[/tex], where a is a constant and C is the integration constant.
In our case, a = -1. So, the integral becomes:
∫[tex]2e^(-x) dx = (1/-1) * 2e^(-x) + C = -2e^(-x) + C[/tex]
Step 2: Analyze the behavior of the function:
Now that we have the integral, we can observe its behavior. The resulting function is [tex]-2e^(-x) + C[/tex], which is an exponential decay function with a negative coefficient. As x approaches positive infinity, [tex]e^(-x)[/tex] approaches 0, making the function approach the constant value C. Similarly, as x approaches negative infinity, [tex]e^(-x)[/tex] approaches infinity, making the function approach negative infinity.
In summary, the behavior of the integral of [tex]2e^(-x)[/tex] dx, given by the function [tex]-2e^(-x) + C[/tex], shows an exponential decay. As x increases, the function approaches a constant value, while as x decreases, the function approaches negative infinity. This behavior is due to the negative coefficient and the exponential term [tex]e^(-x)[/tex] in the function.
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The behavior of the integral of [tex]2e^(-x)[/tex] dx, given by the function [tex]-2e^(-x) + C[/tex], shows an exponential decay.
To algebraically determine the behavior of the integral of [tex]2e^(-x) dx[/tex], we need to perform the integration and observe the resulting function.
Step 1: Integrate the function with respect to x:
We want to find the integral ∫[tex]2e^(-x) dx[/tex]. To do this, we apply the integration rule ∫[tex]e^(ax) dx = (1/a)e^(ax) + C[/tex], where a is a constant and C is the integration constant.
In our case, a = -1. So, the integral becomes:
∫[tex]2e^(-x) dx = (1/-1) * 2e^(-x) + C = -2e^(-x) + C[/tex]
Step 2: Analyze the behavior of the function:
Now that we have the integral, we can observe its behavior. The resulting function is [tex]-2e^(-x) + C[/tex], which is an exponential decay function with a negative coefficient. As x approaches positive infinity, [tex]e^(-x)[/tex] approaches 0, making the function approach the constant value C. Similarly, as x approaches negative infinity, [tex]e^(-x)[/tex] approaches infinity, making the function approach negative infinity.
In summary, the behavior of the integral of [tex]2e^(-x)[/tex] dx, given by the function [tex]-2e^(-x) + C[/tex], shows an exponential decay. As x increases, the function approaches a constant value, while as x decreases, the function approaches negative infinity. This behavior is due to the negative coefficient and the exponential term [tex]e^(-x)[/tex] in the function.
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Which of these strategies would eliminate a variable in the system of
equations?
10x + 4y = -2
5x - 2y = 2
Choose all answers that apply:
B
Multiply the bottom equation by 2, then subtract the bottom
equation from the top equation.
Add the equations.
1
Multiply the top equation by
2'
then add the equations.
Stuck? Review related articles/videos or use a hint.
Report a problem
Answer:
multiply the bottom by 2
Step-by-step explanation:
There are M green and N red apples in the box. We start removing randomly one apple at a time from the box until we remove all the green apples. What is the probability that there is no apple left in the box after that? What is the probability that there are exactly k apples left after that?
Based on probability, the response to the question is,
[tex]a).\ (\frac{N}{(M+N)} )^M\\\\b).\ C(N+k-1,k)^*((\frac{M}{M+N} )^M)^*((\frac{(N+k-1)}{(M+N)} )^k)[/tex]
What is Probability?Probability measures the likelihood or probability of an event happening. It is a number between 0 and 1, where 0 signifies an unlikely occurrence (one that would never happen) and 1 denotes an expected event (one that would happen frequently). Events between 0 and 1 have probabilities between 0 and 1, and the closer an event's probability approaches 1, the more probable it is to occur.
After removing all of the green apples, there is a chance that there won't be an apple in the box [tex](\frac{N}{(M+N)} )^M[/tex].
This is so that there are always less apples overall and fewer green apples overall after each removal. On the first draw, there is a chance of removing a green apple of M / (M + N).
On the second draw, there is a chance of removing another green apple (M-1) / (M + N - 1) until all M green apples have been taken out. These probabilities can be combined to determine the likelihood that all M green apples are taken out of the box, leaving nothing inside.
The binomial coefficient indicates the likelihood that exactly k apples remain in the box after all the green apples have been removed,
[tex]C(N+k-1, k) * ((\frac{M}{(M+N)} )^M) * ((\frac{(N+k-1)}{(M+N)} )^k)[/tex]
This is due to the fact that C(N+k-1, k) methods for choosing which of the remaining (N+k-1) apples are red, and the likelihood that this
choice will be made is [tex](\frac{(N+k-1)}{(M+N)} )^k*((\frac{M}{(M+N)} )^M)[/tex].
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What is the product of 50% of 30 and 25% of 40?
Answer:
50% of 30 is 15. 25% of 40 is 10. So, the product of 50% of 30 and 25% of 40 is 150.
Here's the calculation:
```
(50/100) * 30 * (25/100) * 40 = 150
```
Step-by-step explanation:
Number of Vertices and Edges What is the number of vertices and edges in the graph K_m,n ?a. mn vertices and m+n edgesb. mn vertices and m-n edgesc. m-n vertices and mn edgesd. m_n vertices and mn edges
The correct option is: a. mn vertices and m+n edges. To determine the number of vertices and edges in the graph K_m,n, you should consider that it is a bipartite graph. A bipartite graph is a graph in which the vertices can be divided into two disjoint sets, and every edge connects a vertex from one set to another.
In the graph K_m,n, there are m vertices in the first set and n vertices in the second set. So, the total number of vertices is m + n.
The graph K_m,n is a complete bipartite graph, meaning that every vertex in one set is connected to every vertex in the other set. Therefore, there are m * n edges in the graph K_m,n.
So, the correct option is: a. mn vertices and m+n edges
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At a telematch, 125 participants were adults and of the children were boys, Given that of the total participants were girls, how many participants were at the telematch?
There were 200 participants at the telematch.
Define the term quadratic equation?The second degree is represented mathematically by a quadratic equation, where the highest power of the variable is 2.
It is expressed as ax² + bx + c = 0, where x is the variable and a, b, and c are the coefficients.
Let the total number of participants be P. Then, the number of children is (P-125), and the number of girls is (P-125) × (1-B/(P-125)), where B is the number of boys, put all values:
(P-125) × (1-B/(P-125)) = (P-B-125)/2
Simplifying the above equation, we get:
B² - 250B + (P-125)² = 0
We know the quadratic formula;
B = (250 ± √(250² - 4×(P-125)²))/2
Since B must be an integer, only the positive root is possible, and it must be a whole number.
Therefore, we can solve for P by trying out integer values for B until we find one that gives a whole number for P. Trying out values, we find that B = 100 gives P = 200, which is a whole number.
Therefore, there were 200 participants at the Telematch.
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Roll 4 fair six-sided dice. Let X be the value of the lowest die.
Prove that E(X) = (2275/1296)
Hint: For a given k, what is P r(X = k)?
Please show all work
Answer:It is given b the x2 of the anwserr fot the firghjt angle
Step-by-step explanation:
What is the solution to the equation below?
x+1=√19-x
A. x=-3
B. x=3
C. x=10
D. x=-6
Answer:
B. x = 3--------------------
Given equation:
[tex]x+1=\sqrt{19-x}[/tex]
Square both sides, considering 19 - x ≥ 0 ⇒ x ≤ 19:
(x + 1)² = 19 - xSolve the quadratic equation by factoring:
x² + 2x + 1 = 19 - xx² + 3x - 18 = 0x² + 6x - 3x - 18 = 0x(x + 6) - 3(x + 6) = 0(x - 3)(x + 6) = 0x - 3 = 0 and x + 6 = 0x = 3 and x = - 6The matching choice is B.
At a particular restaurant, each slider has 225 calories and each chicken wing has 70 calories. A combination meal with sliders and chicken wings has a total of 10 sliders and chicken wings altogether and contains 1165 calories. Write a system of equations that could be used to determine the number of sliders in the combination meal and the number of chicken wings in the combination meal. Define the variables that you use to write the system. Do not solve the system.
x+y=10
225x+70y=1165 where x is number of slider in the combination
y is the number of chicken wing in the combination.
What is an equation?An equation is a mathematical statement that expresses the equality between two mathematical expressions. It typically consists of mathematical symbols, such as numbers, variables, and mathematical operators, arranged in a specific pattern or format.
What is known as combination?A combination refers to a way of selecting or arranging objects without regard to their order, where the order of selection does not matter. A combination is a selection of objects where the arrangement or order of the objects is considered irrelevant.
Let x=number of slider
y= number of chicken wing
then, x+y= 10 ,
Since each slider has 225 calories and each chicken wing has 70 calories, then
225x+70y= 1165
Hence the system of equations are:
x+y=10
225x+70y=1165
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helpplease 5. KLMN PORS; find x
L 4x + 4 M
K
N
7x-9
R
48
Q
S
60
P
The value of x that satisfies the given conditions is approximately 7.
Given that KLMN is similar to PQRS. This means that the corresponding sides of these two angles are proportional. We can use this property to set up a proportion between the sides of the two angles.
Let LM and RQ be corresponding sides in the two triangles, and let KN and SP be the other corresponding sides. Then we have:
LM/RQ = KN/SP
Substituting the given values, we get:
(4x + 4)/48 = (7x - 9)/60
To solve for x, we cross-multiply, which gives us:
(4x + 4) * 60 = (7x - 9) * 48
Expanding both sides, we get:
336x - 432 = 240x + 240
Simplifying and solving for x, we get:
96x = 672
x = 7
Therefore, the value of x that satisfies the given conditions is approximately 7.
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PLEASE HELP I DONT UNDERSTAND
x² = -36
How many solutions does this equation have (**Hint it isn't 1 so your options is 2 and 0)
What are the solutions:
-9, -8, -7, -6, -5, -4, -3, -2, -1, 0 , 1, 2, 3, 4, 5, 6, 7, 8, 9, or No solutions
(I have also discover that -6 is wrong so if -6 is a part of your answer you are incorrect)
Can someone help me answer the second question please. I don't understand
The equation for the total number of coins is given as follows:
x + y = 12.
The equation for the total value of the coins is given as follows:
0.1x + 0.05y = 2.4.
How to define the system of equations?The variables for the system of equations are defined as follows:
Variable x: number of 10 cent coins.Variable y: number of 5 cent coins.They have a total of 12 coins, hence the equation for the total number of coins is given as follows:
x + y = 12.
Considering the value of each coin, 10 cents = 0.1 and 5 cents = 0.05, the equation for the total value of the coins is given as follows:
0.1x + 0.05y = 2.4.
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The equation for the total number of coins is given as follows:
x + y = 12.
The equation for the total value of the coins is given as follows:
0.1x + 0.05y = 2.4.
How to define the system of equations?The variables for the system of equations are defined as follows:
Variable x: number of 10 cent coins.Variable y: number of 5 cent coins.They have a total of 12 coins, hence the equation for the total number of coins is given as follows:
x + y = 12.
Considering the value of each coin, 10 cents = 0.1 and 5 cents = 0.05, the equation for the total value of the coins is given as follows:
0.1x + 0.05y = 2.4.
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A perfect gas enclosed by an insulated (upright) cylinder and piston is in equilibrium at conditions prv, T,. A weight is placed on the piston. After a number of oscillations, the motion subsides and the gas reaches a new equilibrium at conditions P2, V2, T . Find the temperature ratio T,/T, in terms of the pressure ratio 1 = P2/P,. Show that the change of entropy is given by 1+ (y - 12 Y 2 Also show that, if the initial disturbance is small, that is 1=1+E, € <1, then S2-S R 27 S2 - S = R In *) 0"
The temperature ratio T2/T1 = I^(γ-1), and for small disturbances, the change in entropy ΔS ≈ n * R * 2 * (γ - 1) * ε.
The temperature ratio T2/T1 in terms of the pressure ratio P2/P1 can be found using the adiabatic process equation for an ideal gas. For an adiabatic process, the equation is:
P1 * V1^γ = P2 * V2^γ
Where γ is the heat capacity ratio (Cp/Cv). Since P2/P1 = I, we can rewrite the equation as:
V1^γ = V2^γ * I
From the ideal gas law, we know that P1 * V1 / T1 = P2 * V2 / T2, so:
V1 / T1 = V2 / T2 * I
Now, we can substitute V1^γ from the first equation into the second equation:
T2 / T1 = I^(γ-1)
For the change in entropy, we can use the formula:
ΔS = n * Cv * ln(T2 / T1) + n * R * ln(V2 / V1)
Substituting the temperature ratio and the volume ratio, we get:
ΔS = n * R * [(γ - 1) * ln(I) + ln(I^(γ - 1))]
For small disturbances, where I = 1 + ε and ε << 1, we can use the approximation ln(1 + ε) ≈ ε:
ΔS ≈ n * R * (γ - 1) * ε + n * R * (γ - 1) * ε
ΔS ≈ n * R * 2 * (γ - 1) * ε
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which is the correct answer?
Answer:
Step-by-step explanation:
6.
5.
4.
3. Pat loves the mountains. He's never happier than when he's standing on top of a mountain, gazing out across nature's
The mountains bring Pat
Tiana
My Answer
Tiana wanted to throw her best friend, Maliyah, a surprise birthday party, so she pretended to forget Maliyah's birthday.
Maliyah was so mad! But when she realized Tiana had thrown her a party, Maliyah forgave her and said, "Girl, you really had
me fooled!"
My Answer
James' friends are
Monica was
My Answer
forgetting because
because
When James lost his job, his friends cooked a big dinner and brought it over to his house to try and cheer him up.
My Answer
My Reason
him because
because
My Reason
RRICULUM
When Monica applied to college, she was careful about every detail. She made sure that she had all the forms she n
and double-checked all the information. She made sure to meet every deadline.
My Reason
My Reason
Answer:
the mountains bring Pat joy because it is beautiful
only one I know
Step-by-step explanation:
:)
Consider the following series. 7n + 18-n n = 1 Determine whether the geometric series is convergent or divergent. Justify your answer. • Converges; the series is a constant multiple of a geometric series. Converges; the limit of the terms, ap, is 0 as n goes to infinity. O Diverges; the limit of the terms, an, is not 0 as n goes to infinity. O Diverges; the series is a constant multiple of the harmonic series. If it is convergent, find the sum. (If the quantity diverges, enter DIVERGES.)
Diverges. Series is not a geometric series as it does not have a common ratio. However, we can rewrite the series as:
7n + 18-n = 7n(1 + 18(-1/n))
As n approaches infinity, the second term inside the parentheses approaches 1, so we can write:
7n(1 + 18(-1/n)) ≈ 7n(1 + 0) = 7n
Thus, we can see that the series is a constant multiple of the series 7n, which is a geometric series with a common ratio of 7. Since the common ratio is greater than 1, the series diverges.
To determine if the series is convergent or divergent, we should find the limit of the terms as n goes to infinity.
The series can be rewritten as: (7n) + (18(-n)n)
As n goes to infinity, the term 7n will also go to infinity. Meanwhile, the term 18(-n)n will approach 0 since any number
raised to a negative power becomes smaller as n increases. However, the 7n term dominates the series, so the limit of
the terms is not 0 as n goes to infinity.
Therefore, the series is divergent. Diverges; the limit of the terms, an, is not 0 as n goes to infinity.
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An LTI filter is described by the difference equation<
y[n]=3x[n]+2x[n-1]+x[n-2]
Obtain an expression for the frequency response of the system.
The frequency response of the LTI system described by the difference equation y[n] = 3x[n] + 2x[n-1] + x[n-2] is given by H( [tex]e^j^\omega[/tex] ) = 3 + 2e^(-jω) +
[tex]e^-^2^j^\omega[/tex] .
1. Convert the difference equation to the frequency domain using the Fourier transform.
2. Replace x[n] with X( [tex]e^j^\omega[/tex]) and y[n] with Y( [tex]e^j^\omega[/tex]).
3. Solve for the transfer function H( [tex]e^j^\omega[/tex]) = Y( [tex]e^j^\omega[/tex]) / X( [tex]e^j^\omega[/tex]).
For the given difference equation:
Y( [tex]e^j^\omega[/tex]) = 3X( [tex]e^j^\omega[/tex]) + 2X( [tex]e^j^\omega[/tex])[tex]e^-^j^\omega[/tex] + X( [tex]e^j^\omega[/tex]) [tex]e^-^2^j^\omega[/tex]
Divide both sides by X( [tex]e^j^\omega[/tex]):
H( [tex]e^j^\omega[/tex]) = Y( [tex]e^j^\omega[/tex]) / X( [tex]e^j^\omega[/tex]) = 3 + 2[tex]e^-^j^\omega[/tex] + [tex]e^-^2^j^\omega[/tex]
This expression represents the frequency response of the given LTI system.
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What is the volume of a rectangular prism with a length of 14 yards, a width of 6 yards, and a height of 8 yards?
Answer: 672 Cubic Yards
Step-by-step explanation:
To find the volume of a rectangular prism, you need to multiply its length by its width by its height.
In this case, the length is 14 yards, the width is 6 yards, and the height is 8 yards.
So, the volume of the rectangular prism is:
14 yards × 6 yards × 8 yards = 672 cubic yards
Therefore, the volume of the rectangular prism is 672 cubic yards.
A key difference between MANOVA and ANOVA is that MANOVA has the ability to handle Select one: O a. multiple comparisons O b. multiple dependent variables о с. multiple error terms O d. multiple independent variables O e. multiple null hypotheses
A key difference between MANOVA and ANOVA is that MANOVA has the ability to handle multiple dependent variables.
The key difference between MANOVA and ANOVA is that MANOVA has the ability to handle multiple dependent variables. ANOVA, on the other hand, only deals with a single dependent variable. MANOVA can also handle multiple independent variables, multiple error terms, and multiple null hypotheses. However, it is important to note that MANOVA is more complex than ANOVA and requires more data to perform accurate analyses.
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.
Find a basis for the subspace of R4 spanned by the following set. (Enter your answers as a comma-separated list. Enter each vector in the form (x1, x2, ...).)
{(1, −2, 3, 4), (−1, 3, 0, −2), (2, −3, 9, 10)}
The set {[tex]v_{1 }, v_{2}, v_{3}[/tex]} is the basis for the subspace of R4 because C1=C2=C3=0.
What is a subspace?
It is a part of linear algebra. The members of the subspace are all vectors and also they all have same dimensions. It is also called as vector subspace. A vector space that is totally contained within another vector space is known as a subspace. Both are required to completely define one because a subspace is defined relative to its contained space; for instance, R2 is a subspace of R3, but also of R4, C2, etc.
The given set in the question is:
{(1,-2,3,4),(-1,3,0,-2),(2,-3,9,10)}
As the set {V1, V2, V3} spam a subset of R4;
then,
C1V1 + C2V2 + C3V3= 0
C1(1,-2,3,4) + C2(-1,3,0,-2) + C3(2,-3,9,10) =0
On solving we will get following equation from above equation:
C1 + 2C2 + C3 =0
C1-C3=0
-5C1 + 2C2=0
-6C1 - 2C2 + 8C3 =0
From the above equation we can easily conclude that;
C1=C2=C3=0
So, {V1,V2,V3} are linearly independent.
Thus set is the basis for subspace of R4.
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Which shapes below are congruent to Z?
N
Select all correct answers.
A
с
D
B
E
Answer:
B and E
Step-by-step explanation:
They both have the same number of untis as Z
let z = log(y) where z is a random variable following the standard normal distribution. compute e(y).1
E(y) = 1.
We know that:
z = log(y)
Taking the exponential of both sides, we get:
e^z = y
Now, we want to find E(y). We can use the definition of expected value:
E(y) = ∫y*f(y)dy
where f(y) is the probability density function of y. To find f(y), we use the change of variables formula:
f(y) = f(z) * |dz/dy|
where f(z) is the probability density function of z, which is the standard normal distribution, and |dz/dy| is the absolute value of the derivative of z with respect to y:
dz/dy = 1/y
|dz/dy| = 1/y
Substituting in the expression for f(y), we get:
f(y) = f(z) * (1/y)
The density function of the standard normal distribution is:
f(z) = (1/√(2π)) * e^(-z^2/2)
Substituting this expression and the expression for y in terms of z, we get:
f(y) = (1/√(2π)) * e^(-(log(y))^2/2) * (1/y)
We can now plug this expression into the formula for E(y):
E(y) = ∫y*f(y)dy
= ∫e^z * (1/√(2π)) * e^(-(log(y))^2/2) * (1/y) dy
= ∫e^(z - (log(y))^2/2) * (1/√(2π)) dz [using the fact that dy/y = dz]
= ∫e^(-(log(y))^2/2) * (1/√(2π)) dz [since e^z is integrated over the entire range of z]
= (1/√(2π)) * ∫e^(-z^2/2) dz [using the substitution z = log(y)]
= (1/√(2π)) * √(2π) [using the fact that ∫e^(-z^2/2) dz is the integral of the standard normal density function over its entire domain, which is equal to 1]
= 1
Therefore, E(y) = 1.
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In each of Problems 7 through 13, determine the Taylor series about the point xo for the given function. Also determine the radius of convergence of the series. 7. sinx, xo =0 8. e^x, Xo = 0 9. x, xo = 1 10. x2, xy =
1) The Taylor series for sin(x) at x=0 is as follows: sin(x) = x - x3/3! + x5/5! - x7/7! +...
This series' radius of convergence is infinite.
What is the Taylor series?2) The Taylor series for ex near x=0 is as follows: ex = 1 + x + x2/2! + x3/3! + x4/4! +...
This series' radius of convergence is infinite.
3) The Taylor series for x near x=1 is as follows: x = 1 + (x-1)
This series has a radius of convergence of one because it converges exclusively for |x-1| 1.
4) The Taylor series for x2 around x=0 is as follows: x2 = 0 + x2
This series' radius of convergence is infinite.
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Simplify: 2 4/5-1 2/5
Answer:
Step-by-step explanation:
24/5-12/5=12/5
To simplify 2 4/5 - 1 2/5, we first need to convert the mixed numbers into improper fractions.
Step 1: Convert the mixed numbers to improper fractions:
2 4/5 = (2 x 5 + 4)/5 = 14/5
1 2/5 = (1 x 5 + 2)/5 = 7/5
Step 2: Subtract the two improper fractions:
14/5 - 7/5 = (14 - 7)/5 = 7/5
Step 3: Convert the resulting fraction back into a mixed number, if necessary:
7/5 can be written as 1 2/5
Therefore, 2 4/5 - 1 2/5 = 1 2/5
Jackie buys some tickets to see the film.
Each ticket costs £4.50
Jackie pays with two £20 notes.
Jackie gets £8.50 change.
(b) How many tickets did Jackie buy?
Answer:7
Step-by-step explanation: as she pays with 2 £20s it'll be 40 so £40 - 8.50 which is £31.50. then 31.50/4.50 which is 7
What is the equation of the line that passes through the points (3, 6) and (-1,
-4)
Answer:
Step-by-step explanation:
The equation of the line that passes through the points (3, 6) and (-1, -4) can be found using the point-slope formula.
First, find the slope of the line using the formula:
slope = (y2 - y1)/(x2 - x1)
where (x1, y1) = (3, 6) and (x2, y2) = (-1, -4).
slope = (-4 - 6)/(-1 - 3) = -10/-4 = 5/2
Now that we have the slope, we can use it in the point-slope formula:
y - y1 = m(x - x1)
where m is the slope and (x1, y1) is either one of the given points. Let's use (3, 6):
y - 6 = (5/2)(x - 3)
Simplifying this equation, we get:
y - 6 = (5/2)x - 15/2
y = (5/2)x - 3/2
Therefore, the equation of the line that passes through the points (3, 6) and (-1, -4) is y = (5/2)x - 3/2.
Answer:
5/2
Step-by-step explanation:
Slope = change in y coordinate/change in x coordinate.
In this example, Slope = [tex]\frac{-4 - 6}{-1 - 3} = \frac{-10}{-4} = \frac{10}{4} =\frac{5}{2}[/tex]
Your slope is 5/2.