Tran has a coin jar that contains​ nickels, dimes, and quarters. There are 185 coins in the jar. There are 5 more dimes than quarters. If the total value of the coins in the jar is $25.25 how many quarters does the jar​ contain?

Answers

Answer 1

Answer:

[tex]63[/tex]

Step-by-step explanation:

Let number of nickels be [tex]x[/tex]

Number of dimes be [tex]y[/tex]

Number of quarters be [tex]z[/tex]

Total number of coins is [tex]185[/tex]

[tex]x+y+z=185[/tex]

Number of dimes is 5 more than quarters

[tex]y=5+z[/tex]

[tex]x+(5+z)+z=185\\\Rightarrow x+2z=180\\\Rightarrow x=180-2z[/tex]

Amount of money in the jar is $25.25

[tex]0.05x+0.1y+0.25z=25.25\\\Rightarrow 0.05x+0.1(5+z)+0.25z=25.25\\\Rightarrow 0.05x+0.5+0.1z+0.25z=25.25\\\Rightarrow 0.05x+0.35z=24.75[/tex]

[tex]0.05(180-2z)+0.35z=24.75\\\Rightarrow 9-0.1z+0.35z=24.75\\\Rightarrow 9+0.25z=24.75\\\Rightarrow z=\dfrac{24.75-9}{0.25}\\\Rightarrow z=63[/tex]

[tex]y=5+z=5+63\\\Rightarrow y=68[/tex]

[tex]x=180-2z=180-2\times 63\\\Rightarrow x=54[/tex]

So, the number of quarters is [tex]63[/tex].

Answer 2

Answer:

63 is the correct answer :)

Step-by-step explanation:


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Which costs the last per ounce, a 20 ounce soda for $0.60, 68 ounce for $2.38, or 100 ounce for $3.32? Explain how you got your answer.

Answers

9514 1404 393

Answer:

  20 oz for $0.60

Step-by-step explanation:

You can determine the least-cost item by comparing costs at the same size. (This can be done using mental arithmetic.)

68 ounces is between 3 and 4 times the size of 20 ounces. If the costs were the same, 68 ounces would cost between 3·$60 = $1.80 and 4·$60 = $2.40. The cost of 68 ounces is closer to $2.40 than 68 is to 80, so we conclude the 20-ounce soda costs less.

The cost of 100 ounces at the 20-ounce price would be 5·$0.60 = $3.00, which is less than the cost of the 100-ounce soda. Again, the 20-ounce soda is cheaper.

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__

If you like, you can actually find the cost per ounce by dividing the cost by the ounces. Those results are shown in the attached table. The 20-ounce soda costs the least.

A hemispherical tank is filled with water and has a diameter of 14 feet. If water
weighs 62.4 pounds per cubic foot, what is the total weight of the water in a full tank,
to the nearest pound?

Answers

Answer:

[tex]44,826.72\ \text{pounds}[/tex]

Step-by-step explanation:

Given that,

The diameter of a hemispherical tank= 14 feet

Radius, r = 7 feet

water

Water weighs 62.4 pounds per cubic foot.

We need to find the total weight of the water in a full tank to the nearest pound.

The volume of the hemisphere is given by :

[tex]V=\dfrac{2}{3}\pi r^3\\\\V=\dfrac{2}{3}\pi \times (7)^3\\\\V=718.377\ \text{feet}^3[/tex]

If water weighs 62.4 pounds per cubic foot, it means

[tex]V=718.377\times 62.4\\\\V=44,826.72\ \text{pounds}[/tex]

So, the total weight of the water is [tex]44,826.72\ \text{pounds}[/tex].

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Answer:

Area of trapezoid is: [tex]\mathbf{11x^3y^2}[/tex]

Area of triangle is: [tex]\mathbf{6a^3b^2}[/tex]

Perimeter of triangle is: [tex]\mathbf{3ab+14a^2b}[/tex]

Step-by-step explanation:

Image 1:

We need to Find area of trapezoid.

The formula used is: [tex]Area=\frac{1}{2}h(b_1+b_2)[/tex]

where h is height and b₁ and b₂ are parallel sides.

Looking at the figure we get:

h = 2xy

b₁ = 4x²y

b₂ = 7x²y

Putting values and finding area:

[tex]Area=\frac{1}{2}h(b_1+b_2)\\Area=\frac{1}{2}\times 2xy(7x^2y+4x^2y)\\Area=\frac{1}{2}\times 2xy(11x^2y)\\Area=\frac{1}{2}\times 22x^3y^2\\Area=11x^3y^2[/tex]

So, Area of trapezoid is: [tex]\mathbf{11x^3y^2}[/tex]

Image 2:

We need to find area and perimeter of triangle.

First we will find area of triangle.

The formula used is: [tex]Area=\frac{1}{2}\times b \times h[/tex]

where b is base and h is height

Looking at the figure,

b = 3ab

h = 4a²b

Finding area:

[tex]Area=\frac{1}{2}\times b \times h\\Area=\frac{1}{2}\times 3ab \times 4a^2b\\Area=\frac{1}{2}\times 12a^3b^2\\Area=6a^3b^2[/tex]

So, Area of triangle is: [tex]\mathbf{6a^3b^2}[/tex]

Now, finding Perimeter of triangle

The formula used is: [tex]Perimeter = Sum\:of\:lengths\:of\:all\:sides\:of\:triangle[/tex]

Looking at figure:

Length of side 1 = 3ab

Length of side 2 = 4a²b

Length of side 3 = 10a²b

Finding Perimeter

[tex]Perimeter = Sum\:of\:lengths\:of\:all\:sides\:of\:triangle\\Perimeter = 3ab+10a^2b+4a^2b\\Perimeter=3ab+14a^2b[/tex]

So, Perimeter of triangle is: [tex]\mathbf{3ab+14a^2b}[/tex]

The ration of child to teen to adult tickets sold at a water park on Saturday was 4:1:2. A total of 294 tickets were sold. How many child tickets were sold?

Answers

Answer:  168 child tickets were sold.

Step-by-step explanation:

Given: The ratio of child to teen to adult tickets sold at a water park on Saturday was 4:1:2.

Let the number of child tickets = 4x , teen tickets = x , adult tickets = 2x

Total tickets = x+4x+2x = 7x =294

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Number of child tickets = 4(42) = 168

Hence, 168 child tickets were sold.

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Step-by-step explanation:

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Answers

9514 1404 393

Answer:

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Step-by-step explanation:

Every point coordinate of the dilated figure will be smaller by the same factor.

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  B (0, 4) has a scale factor greater than 1

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__

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Help me please 9w+4= 2w+32

Answers

Answer:

w=4

Step-by-step explanation:

9w+4=2w+32

-2w     -2w

7w+4=32

     -4   -4

7w=28

w=4

Answer:

w = 4

Step-by-step explanation:

How to solve...

You have your equation 9w + 4 = 2w + 32, now you take 4 and subtract on both sides, so you will subtract it to 4 and 32. You get 28 as your answer. Now leave that alone, next you will take 2w and subtract it on both sides, when you subtract 2w to 9w you will get 7w. Now just do 28 divided by 7, which is 4. So w = 4. Hope this helps!

9w + 4 = 2w + 32

       - 4 =        -   4

--------------------------

     9w = 2w + 28

    -2w = -2w + 28

---------------------------

     7w = 28

     7w = 7w

---------------------------

       w = 4

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