✏️Topic: Comparing Arguments

My reflective journal.

Direction: Supply the sentence below to complete the information askes.

I learned that comparing arguments________________________One example of this is____________. We can use​

Hi there!

We can begin by breaking the problem up into two directions, horizontal and vertical.

The collision is perfectly inelastic since the two objects stick, so:

1 = car

2 = truck

Momentum in the east direction (positive and horizontal, car NOT going in this direction has a velocity of 0 m/s):

m2v2 = (m1 + m2)v

(650 · 11) / (350 + 650) = 7.15 m/s

Momentum in the north directions (only initial is the northward velocity of the car):

m1v1 = (m1 + m2)v

(350 · 16)/(350 + 650) = 5.6 m/s

Find the overall velocity using the pythagorean theorem:

√(5.6²) + (7.15²) = 9.08 m/s

Find the direction using trigonometry. Use tangent in this situation:

tan Ф = O/A

tan⁻¹(5.6/7.15) = 38° north of east

Answer:

A

Explanation:

Answer:

π/21600 rad /s.

Answer:

m = 4 At Mass units = 4 * 1.66E-27 kg = 6.64E-27 kg  mass of particle

q = 2 * 1.60E-19 C = 3.2E-19 C     total charge of alpha particle

T = 8.8E-8 s     period of 1 revolution

F = q V B      magnetic force

F = m V^2/ R     centripetal acceleration

q V B = m V^2 / R

B = m V / (q * R)

T = 2 pi R / V     time for 1 revolution

R = V T / (2 pi)

B = (m V / q) * 2 pi / (V T) = 2 pi m / (q T)

B = 2 pi * 6.64E-27 / (3.2E-19 * 8.8E-8) = 1.48

B = 1.48 W/m^2

Answer:

it will be curved as in deceleration

Explanation:

(1) The speed with which the star's light will pass you is 3 x 10⁸ m/s.

(2) The speed of the other spaceship is -2.943 x 10⁸ m/s.

The given parameters;

(1)

Since you are travelling away from the star (same direction), relative to a third observer, the speed at which the star's light will pass you is calculated using Lorentz velocity addition.

[tex]u = \frac{u'+ v}{1 + \frac{v}{c^2} u'} \\\\u = \frac{c+(-0.8c)}{1 + \frac{-0.8c}{c^2} (c)}\\\\u = \frac{c-0.8c}{1- \frac{0.8c}{c} } \\\\u = \frac{0.2c}{0.2} = c = 3\times 10^{8} \ m/s[/tex]

Thus, the speed with which the star's light will pass you is 3 x 10⁸ m/s.

(2) The speed of the spaceship approaching = 0.84 c

Since you are travelling in opposite direction to second spaceship, relative to a third observer (frame of reference), the speed of the other spaceship is calculated using Lorentz velocity addition.

[tex]u = \frac{u' + v}{1 + \frac{v}{c^2}u' } \\\\u = \frac{-0.84c - 0.8c}{1 + \frac{(-0.8c)}{c^2}(-0.84c) } \\\\u = \frac{-1.64c}{1.672} = -0.981c \\\\u = -0.981 \times 3\times 10^{8} = -2.943 \times 10^{8} \ m/s[/tex]

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Answer:

388.56km[E13degS]

Explanation:

Δdx = Δd1x + Δd2x

Δdx = 250km [E]+ 180sin(60) [E]

Δdx = 405.88 km [E]

Δdy = Δd1y + Δd2y

Δdy = 0 + 160cos(60) [S]

Δdy = 90km [S]

Δdt = √(Δdx)^2+(Δdy)^2

Δdt = √164738.57+8100

Δdt = 398.85km

tanθ = Δdy/Δdx

tanθ = 90/388.56

θ = tan-1(90/388.56)

θ = 13.04 deg

Answer:

The total mass of the reactants is 50 grams.

Explanation:

[tex]25g+25g=50g\\[/tex]

I hope this helps!

Answer:

water and nitrogen can be place at B

The B loop is the element that can be liquid, cas or solid. Water can have three states : solid (ice), liquid, or gas (as a vapor). The same can be said with nitrogen, it's a gas at room temperature, and it also can be a liquid or solid.

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filipino artist like john cena

A large system is one in which one subsystem provides services to another subsystem.

This is a type of system that contains many subsystems. The subsystem provides independent services to the larger by communicating, or interacting with each other.

A subsystem is smaller units of a large system, designed to perform specific task in the large system.

Thus, a large system is one in which one subsystem provides services to another subsystem.

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I am not able to understand..

What are you saying?

Answer:

Explanation:

Conservation of momentum is used to solve

Unfortunately we have a missing piece of information such as the initial velocity of the unknown mass train.

If we ASSUME that the second train is at rest

5000(100) + m(0) = 5000(50) + m(50)

which means m = 5000 kg

However, I'll show you the importance of knowing that initial velocity by finding it assuming the other answers are valid

if m = 15000 kg

5000(100) + 15000(v₀) = (5000 + 15000)(50)

v₀ = 33 ⅓ m/s

if m = 10000 kg

5000(100) + 10000(v₀) = (5000 + 10000)(50)

v₀ = 25 m/s

if m = 8000 kg

5000(100) + 8000(v₀) = (5000 + 8000)(50)

v₀ = 18.75 m/s

So you can see why I had to assume an initial velocity. Any of the masses could work if the initial velocity is chosen correctly.

Answer:

The one that looks similar to this one.

Explanation:

Blue vectors are path

Green vector is total displacement

Answer:

0.788 m/s²

Explanation:

Ff = 0.1 × 5 kg × 10 m/s² × cos 38°

Ff = 5 N × 0.788

Ff = 3.94 N

F = m × a

3.94 N = 5 kg × a

a = 3.94 N / 5 kg

a = 0.788 m/s²

Answer:

B. When an energy transformation happens, no energy is destroyed

or created.

Explanation:

Answer:

Explanation:

Use vector addition

v = √(30² + 40²) = 50 m/s as viewed from the shore

Trust me when I say I would never venture onto a river moving at 30 m/s no matter how powerful the boat was.

30 m/s(3600 s/hr / 1000 m/km) = 108 km/hr

The turbulence in water flowing over ground at 108 kilometers per hour would capsize anything ever built...including aircraft carriers.

These numbers are more suitable for a plane flying in air. Even that could be a very rough ride.

Answer: 15.85

Explanation:

E21

Answer:

Answer:

f

Explanation:

The speed of the two-car wreck right after the crash is 13.9 m/s, and the direction is 58.4° east of north.

Momentum conservation can address this problem. Before and after the collision, momentum is equal. Calculate the two-car wreck's speed and direction after the collision:

Step 1: Calculate automobile beginning momentum.

Mass (m) times velocity (v) equals momentum (p).

Northbound 1200-kg car:

Initial momentum of the 1200-kg automobile (p₁) = mass (m₁) × velocity (v₁).

p₁ = 1200 kg × 17.0 m/s = 20,400 kg/s (North direction).

1600-kg eastbound car:

The 1600-kg car's initial momentum (p₂) = m₂ × v₂.

p₂ = 1600 kg × 21.0 m/s = 33,600 kg/s (East direction).

Step 2: Calculate the pre-collision momentum.

The vector sum of the two automobiles' momentum before the accident is p[tex]_total[/tex].

p[tex]_total[/tex] = p₁+p₂.

p[tex]_total[/tex] = 20,400 kg m/s (North) + 33,600 (East)

Step 3: Calculate the two cars' combined mass after the collision.

Combined mass (m[tex]_combined[/tex]) = 1200-kg + 1600-kg cars.

m[tex]_combined[/tex] = 1200 + 1600 = 2800 kg

Step 4: Determine the two-car wreck's velocity after the accident.

Total momentum after the collision (p[tex]_combined[/tex]) is the same as before, but it belongs to the combined mass (m[tex]_combined[/tex]) travelling at the velocity (v[tex]_combined[/tex]) in a given direction:

p[tex]_combined[/tex] = m[tex]_combined[/tex] × v[tex]_combined[/tex]

Since the collision is inelastic (cars stick together), momentum remains the same.

= p[tex]_total[/tex]

m[tex]_combined[/tex] × v[tex]_combined[/tex] = 20,400 kg/s (North) + 33,600 kg/s (East).

Step 5: Determine the two-car wreck's speed and direction.

Calculating the resultant vector of the North and East momentum components gives the combined two-car wreck's velocity (speed) (v[tex]_combined[/tex]).

(v[tex]_combined[/tex][tex]_north²[/tex] + v[tex]_combined[/tex][tex]_east²[/tex])

Where:

North velocity is v[tex]_combined[/tex][tex]_north[/tex].

East velocity is v[tex]_combined[/tex][tex]_east[/tex].

v[tex]_combined[/tex][tex]_north[/tex] = 20,400 kg m/s, 2800 kg, 7.29 m/s (North).

v[tex]_combined[/tex][tex]_east[/tex] = 33,600 kg m/s < 2800 kg × 12.0 m/s (East).

13.9 m/s = (7.29² + 12.0²)

Step 6: Determine the two-car wreck's direction.

Trigonometry can determine direction:

tan() = v[tex]_combined[/tex][tex]_east/north[/tex]

arctan(v[tex]_combined[/tex][tex]_east/north[/tex]) =

arctan(12.0 / 7.29 m/s) arctan(1.645) 58.4°

The two-car crash faces east at 58.4°.

Results summary:

The two-car disaster shortly after the accident is 13.9 m/s.

The two-car crash lies 58.4° east of north following the collision.

To kow more about speed

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Thermodynamics is the branch of physical science that deals with the relations between heat and other forms of energy (such as mechanical, electrical, or chemical energy), and, by extension, of the relationships between all forms of energy.

im not sure if im right or not but maybe its "D scientific investigation" but ldk so

Answer:

c 13

Explanation:

I took test

Group 18 of the periodic table, also known as the noble gases or Group 18 elements, consists of elements that share similar properties and have a single electron in their outer shells. The correct option is option (A).

These elements include helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), and radon (Rn). They are characterized by having full outer electron shells, making them stable and unreactive under normal conditions.

This stability is due to the fact that they have achieved a full complement of electrons in their outermost energy level, except for helium, which has only two electrons in total.

Group 18 of the periodic table, also known as the noble gases or Group 18 elements, The correct option is option (A).

To know more about noble gases:

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Answer:

40 m/s

Explanation:

If you multiply the acceleration with time you get the average speed.

If you look at the sketch I drew for the earlier part of this question, you'll see that, with respect to the positive horizontal (i.e. directly to the right), T₁ makes an angle of 180° - 54.9205° ≈ 125°, while T₂ makes an angle of 54.9205° ≈ 55°.

Split up the force acting on the block into vertical and horizontal components. We have

• net vertical force

∑ F = T₁ sin(125°) + T₂ sin(55°) - mg = 0

where m = 0.56 kg, and

• net horizontal force

∑ F = T₁ cos(125°) + T₂ cos(55°) = 0

Both net forces are 0 because the block is suspended in equilibrium.

Notice that cos(125°) = -cos(55°), so the second equation tells you that T₁ = T₂ and that the tensions in either string are the same. Also, sin(125°) = sin(55°).

Then in the first equation, we have

T₁ sin(125°) + T₂ sin(55°) - mg = 0

2 T₁ sin(55°) = mg

T₁ = mg/(2 sin(55°))

T₁ = (0.56 kg) (9.8 m/s²)/(2 sin(55°))

T₁ ≈ 3.35 N

Answer:

The mass of the gold bar is 1,544 g

Explanation:

Answer:

Below

Explanation:

For these types of questions, you should draw out your triangles and resultant vectors.

For this, we can use the pythagorean theorem to solve this :

     vpf^2 = vpi^2 + vw^2

     vpf^2 = 45^2 + 191^2

     vpf = [tex]\sqrt{38507[/tex]

     vpf = 196.2294

     vpf = 200 mph

Now we need to find the angle of the plane's direction using soh cah toa

     Tan(x) = O / A

              x = tan^-1(191/45)

              x = 76.74

              x = 77 degrees

Therefore, the plane's result velocity is 200 mph [ E 77 N ]

Hope this helps!

Answer:

In the free fall motion we have that the acceleration is constant and produced by gravity, this acceleration has a magnitude of 32 ft/s2 or 9.8 m/s2 depending on the units you are working with. This means that every second the speed changes a magnitude of 32 ft/2, the velocity will depend of whether the ball is going upward (positive) or downward (negative).

A) At the highest point the ball stops to start the descend, here v=0 ft/s

B) +32 ft/s. The vector is going up, in the next second the velocity is going to be 0 (negative acceleration)

C) V=vf-vo=0-32=-32 ft/s is the constant change in velocity in projectile motion

D) -32 ft/s. The vector is pointing downward

E) V=vf-vo=-32-0=-32 ft/s is the constant change in velocity in projectile motion, 32 ft/s per second

F) Delta V=vf-vo=-32-32=-72 ft/s

g) gravity acceleration is constant 32 ft/s2 (pointing downward vector)

Answer:

1. Comes from the human us

2. Transfered into the alley floor or if hits a pin transfered to the pin.

3. Heavy