Tony makes a table to use as a quick reference guide:
Cookies baked (y) is a function of number of batches (x).

Use the table tool to answer the question.

How many cookies will Tony have if he bakes 10 batches more than the maximum number of batches in the table?

Enter the correct answer. ​

Answer:

The answer is A Find the point-slope form.

y+3= −7/5 ⋅ (x+2)

Step-by-step explanation:

1.  Rewrite one side (or both) by combining like terms. Option C

2. Yes, the equations are equivalent. Option A

1.

Equation A ;  2x -1  = 5x

Equation B ; -1 = 3x

To get equation B from equation A

2x - 1 = 5x

Collect like terms

-1 = 5x -2x

Subtract the like terms

-1 = 3x

Thus, rewrite one side (or both) by combining like terms. Option C

2. 2x - 1 = 5x ...... equation A

Solution ;

2x -5x = 1

-3x = 1

x = -1/3

-1 = 3x

Solution;

x = -1/3

Thus, the equations are equivalent. Option A

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Using the hypergeometric distribution, the probabilities are given as follows:

a) 0.0333 = 3.33%.

b) 0.5 = 50%.

c) 0.8333 = 83.33%.

d) 0.9667 = 96.67%.

The formula is:

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}[/tex]

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

The parameters are:

The values of the parameters are:

N = 10, n = 3, k = 4.

Item a:

The probability is P(X = 3), hence:

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}[/tex]

[tex]P(X = 3) = h(3,10,3,4) = \frac{C_{4,3}C_{6,0}}{C_{10,3}} = 0.0333[/tex]

Item b:

The probability is P(X = 1), hence:

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}[/tex]

[tex]P(X = 1) = h(1,10,3,4) = \frac{C_{4,1}C_{6,2}}{C_{10,3}} = 0.5[/tex]

Item c:

The probability is:

[tex]P(X \geq 1) = 1 - P(X = 0)[/tex]

In which:

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}[/tex]

[tex]P(X = 0) = h(0,10,3,4) = \frac{C_{4,0}C_{6,3}}{C_{10,3}} = 0.1667[/tex]

Then:

[tex]P(X \geq 1) = 1 - P(X = 0) = 1 - 0.1667 = 0.8333[/tex]

Item d:

The probability is:

[tex]P(X \leq 2) = 1 - P(X = 3)[/tex].

Considering item a:

[tex]P(X \leq 2) = 1 - P(X = 3) = 1 - 0.0333 = 0.9667[/tex]

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Let [tex]O[/tex] be the random variable for the number of bad oranges picked out. Then

[tex]P(O=o) = \dfrac{\dbinom6{3-o} \dbinom4o}{\dbinom{10}3}[/tex]

if [tex]o\in\{0,1,2,3\}[/tex] and zero otherwise, where

[tex]\dbinom nk = \dfrac{n!}{k!(n-k)!}[/tex]

is the so-called binomial coefficient.

(a) Of the 6 good oranges, you pick 0. Of the 3 bad oranges, you pick 3. Of the 10 total oranges, you pick 3. So the probability of picking out all bad oranges is

[tex]P(O=3) = \dfrac{\dbinom60 \dbinom43}{\dbinom{10}3} = \boxed{\dfrac1{30}}[/tex]

(b) By similar reasoning, the probability of drawing exactly 1 bad orange is

[tex]P(O=1) = \dfrac{\dbinom62 \dbinom41}{\dbinom{10}3} = \boxed{\dfrac12}[/tex]

(c) "At least 1 bad orange" means you pick out 1, 2, or 3 bad oranges. These events are mutually exclusive, and we already know the probabilities of picking out exactly 1 or all 3 bad oranges. The remaining probability of drawing 2 bad oranges is

[tex]P(O=2) = \dfrac{\dbinom61 \dbinom42}{\dbinom{10}3} = \dfrac3{10}[/tex]

so the overall probability of drawing at least 1 bad orange is

[tex]P(O\ge1) = P(O=1)+P(O=2)+P(O=3) =\dfrac1{30} + \dfrac3{10} + \dfrac12 = \boxed{\dfrac56}[/tex]

(d) I assume you mean "at most 2 bad oranges," meaning you pick out 0, 1, or 2 bad oranges. Again, these events are mutually exclusive, and the probability of picking out no bad oranges is

[tex]P(O=0) = \dfrac{\dbinom63 \dbinom40}{\dbinom{10}3} = \dfrac16[/tex]

hence the probability of drawings at most 2 bad oranges is

[tex]P(O\le2) = P(O=0) + P(O=1) + P(O=2) = \dfrac16 + \dfrac12 + \dfrac3{10} = \boxed{\dfrac{29}{30}}[/tex]

6.5 s  take the projectile to hit the ground.

A projectile is any object thrown into space upon which the only acting force is gravity.

Given:

speed = 25 m/s

h(t) = -5t² + 25t  + 70

height = 70 m

Time to reach maximum height

( u sin90)/2g

= 25/2*9.8

= 1.275s

Max height = u²Sin²[tex]\theta[/tex]/g

=25*25/9.8

=63.775

So, total height=63.775 + 70 = 133.775 m

Now, time to fall back to the ground

h = ut+(1/2)gt²

t² = (h- ut)2/g

u=0

H= 133.775 m

(133.775*2)/9.8= t²

t² = 27.3010

t= 5.225 s

Total time taken to hit ground

= 5.225 + 1.275

= 6.5 s

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By using the definitions of unit circle and trigonometric functions, we find that the tangent of the terminal point of the angle is equal to 0.

In trigonometry, an unit circle is a circle with a radius of 1 and used to determine the values of trigonometric functions. There are two fundamental trigonometric functions: (i) sine, (ii) cosine, and the tangent is a derivate trigonometric function, which is defined below:

tan θ = y/x     (1)

If we know that x = 1 and y = 0, then the tangent of the terminal point of angle is:

tan θ = 0/1

tan θ = 0

By using the definitions of unit circle and trigonometric functions, we find that the tangent of the terminal point of the angle is equal to 0.

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Answer:

tan= 0

Step-by-step explanation:

^^^correct :)

Answer:

Step-by-step explanation:

LCM of 4x²-100 and 4x + 20 is 4(x+5)(x-5)

What is  Least Common Multiple?

Least Common Multiple is defined as the smallest number that is a multiple of two or more numbers.

We have to factorise 4x²-100 which is of the form A²-B²,

= (2x)² -(10)²

= (2x+10)(2x-10)

= 2×2(x+5)(x-5)

= 4(x+5)(x-5).

We have to factorise 4x + 20​

= 4(x+5)

LCM of 4x²-100 and 4x + 20 = 4(x+5)(x-5).

Hence, LCM of 4x²-100 and 4x + 20 is 4(x+5)(x-5)

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The statement third "Betty wrote an indirect proof using contradiction' and statement fourth "Ken wrote direct proof using deductive evidence" are correct.

When two lines or rays converge at the same point, the measurement between them is called a "Angle."

We have Ken's statements are shown in the table:

Angle AOC = Angle BOD (given)

Angle AOB + Angle BOC = Angle BOC + Angle COD   (angle addition postulate)

Angle AOB = ANgle COD (subtraction property of equality)

Ken wrote direct proof using deductive evidence.

As we can in betty's proof:

Betty wrote an indirect proof using contradiction.

Thus, the statement third "Betty wrote an indirect proof using contradiction' and statement fourth "Ken wrote direct proof using deductive evidence" are correct.

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Step-by-step explanation:

You can't use quadratic formula in this

The key features of the graph are:

The graph has a minimum value at (-2, -1)

This represents the vertex

The x coordinate of the vertex is the axis of symmetry.

So, we have

x = -2

The graph crosses the y-axis at (0, 3)

This represents the y-intercept

The graph opens up.

This means that the vertex is minimum.

The domain is the set of all real number, because the graph extends in both directions on the x-axis without end

While the range is y >= -1, because it has a minimum at this point

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Answer:

r=21.01 cm

Step-by-step explanation:

2r = diameter

Circumference of a circle = pi 2r

difference = 90

pi2r - 2r =90

 2r (pi-1) =90

90/(2(pi-1) = r = 21.01 cm

Step-by-step explanation:

So the general formula for compound interest is [tex]A = P(1+\frac{r}{n})^{nt}[/tex] where t is typically time in years, and n is how many times it's compounded per year. But in this case it's only compounded 1 time per year so the equation is just [tex]A = P(1+r)^t[/tex]. in this case P is the principal amount, r is the interest, and A is the final amount. So the 5% interest rate becomes 0.05 by dividing by 100 to convert it into decimal form and the principle amount of 11,000. This gives you the formula [tex]A = 11000(1.05)^t[/tex]. This is the answer to the first question where t is the time in years. When it says "Find interest earned" I'm a bit confused, is it giving you x amount of years where you have to calculate the interest earned or does it want a general equation? Because the general equation would be the final amount - the principle amount which calculates the difference. So the equation for interest earned would be [tex]11000(1.05)^t-11000[/tex]. To calculate the amount of money after 5 years you simply plug in 5 as t. this gives you the equation [tex]11000(1.05)^5 \approx 11000(1.276) \approx 14,039.10[/tex]

The composition of transformations that would map figure ABCD to figure A''B'C''D' is 180° degree rotation about point C.

It should be noted that transformation simply means the manipulation of a shape or geometric figure.

In this case, the composition of transformations that would map figure ABCD to figure A''B'C''D' is 180° degree rotation about point C.

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Answer:

c.) aₙ = 5 × 4ⁿ⁻¹

Explanation:

Geometric sequence: aₙ = a(r)ⁿ⁻¹

where 'a' resembles first term of a sequence, 'r' is the common difference.

Here sequence: 5, 20, 80, 320,...

First term (a) = 5

Common difference (d) = second term ÷ first term = 20 ÷ 5 = 4

Hence putting into equation: aₙ = 5(4)ⁿ⁻¹

Answer:

200

Step-by-step explanation:

log a is the same thing as: [tex]log_{10}{a}=b[/tex] which can be rewritten as [tex]10^b=a[/tex] and in general logarithms are in the form [tex]log_ba=c[/tex] which can be written as [tex]b^c=a[/tex]

Rewrite into exponential form

[tex]10^3=5x[/tex]

Simplify exponent

[tex]1000=5x[/tex]

Divide by 5

x=200

Answer:

200

Step-by-step explanation:

I don't know if there are answer choices but the answer is 200

Answer:

4/7

Step-by-step explanation: Multiply 2/3 x 6/7 Put your answer in lowest terms a. 4/7

Answer:

Difference: 4/21

Step-by-step explanation:

the difference between two quantities is the result of a subtraction

[tex]\frac{6}{7} -\frac{2}{3} =\frac{(6)(3)-(7)(2)}{(7)(3)} =\frac{18-14}{21} =\frac{4}{21}[/tex]

The fraction can no longer be reduced

Hope this helps

Based on the vertices of quadrilateral ABCD and Quadrilateral FGHJ, A. The scale factor is 1/2, and the center of dilation is point A.

First, note the vertices of Quadrilateral FGHJ:

F(1,1)  G(3 ,1)  J (1 , 5)  H(3 , 5)

Find the lengths of the sides of both quadrilaterals:

FG = (3, 1) - (1, 1)                                      AB = (5,1) - (1, 1)  

= (2,0)                                                           = (4, 0)

FH = (3, 5) - (1, 1)                                      AC = (5,9) - (1, 1)  

= (2,4)                                                           = (4, 8)

AB is twice the size of FG.

AC is twice the size of FH

This shows that quadrilateral FGHJ is 1/2 the size of quadrilateral ABCD.

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Answer:

4/1 or 4

Step-by-step explanation:

Answer:

4

Step-by-step explanation:

[tex]\frac{\frac{6}{7} }{\frac{3}{14} } =\frac{(6)(14)}{(7)(3)} =\frac{84}{21} =4[/tex]

Hope this helps

The cost of the file is $6.15 and the cost of the pen is $8.9

The interpretation of the given word problem leads to a system of linear equations.

From the given information:

f + 3p = 32.85 --- (1)

2f + 8p = 83.5 --- (2)

From equation (1)

f = - 3p+32.85

Replace the value of f in the above equation into equation (2)

2(-3p + 32.85) + 8p = 83.5

2p + 65.7 = 83.5

2p = 83.5 -65.7

2p = 17.8

p = 17.8/2

p = 8.9

Replacing the value of p = 8.9 into f = - 3p+32.85

f = -3(8.9)+32.85

f = 6.15

Therefore, we can conclude that the cost of the file is $6.15 and the cost of the pen is $8.9.

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The answer choice which represents values for which the expression is undefined is; x = -1.

It follows from the task content that the expression in discuss is made up of 2 rational expressions and hence, the value of x which makes the expression undefined is -1 because, upon substitution, we have; (1/0) + (5/0); which yields undefined.

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Answer:

x= 3. x= 0, x= -1

Step-by-step explanation:

Correct on edmentum

The graph is in the attached image.

Answer:

40 yds^3

Step-by-step explanation:

Step-by-step explanation:

x/7 ≥ -6

we rewrite it as :

x/7 = -6

by cross multiplication

x = -42

In order words:

x ≥ -42

Hope this helps

Good luck ✅

Answer:

first three expressions are polynomials and last three are not.

Step-by-step explanation:

last three expression has negative powers of X and  some powers of Xs are not integers.

The solution to the given pair of inequalities is at any point on the line

Inequalities are expressions that are not separated by an equal sign. Given the system of inequalities as shown:

3x-y<2

3y<9x-6

The solution of the system of inequality is the point of intersection of the lines. From the graphed line below, you can see that the point of intersection is at any point on the line since the lines are the same

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Answer:

16

Step-by-step explanation:

The outlier in the given dataset is "16".

Given is a data set 69, 16, 79, 80, 82, we need to determine the outliners of the set,

To identify outliers in a dataset, we generally use a statistical method such as the z-score or the IQR (interquartile range).

Since, the provided dataset is small with only five values, we can manually identify the outliers by observing the data.

An outlier is a value that significantly deviates from the rest of the dataset.

Let's examine the given dataset:

69, 16, 79, 80, 82

To identify outliers, we can consider any data points that are notably different from the others.

In this case, it seems that the value "16" is considerably lower than the other values.

Let's label it as a potential outlier.

Therefore, the outlier in the given dataset is "16".

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Answer:

2 (4+x)

Step-by-step explanation:

4 + x     is  the sum of four and a number 'x'   now multiply by 2

2  ( 4+ x)

We can rewrite the given expression to:

[tex]4*\sqrt{x - 2} - 3[/tex]

So the correct option is the third one.

Here we have the expression:

[tex]\sqrt{16x - 32} - 3[/tex]

Taking the 16 as a common factor inside the square root:

[tex]\sqrt{16*(x - 2)} - 3[/tex]

and 16 = 4², then:

[tex]\sqrt{16*(x - 2)} - 3 = \sqrt{4^2*(x - 2)} - 3\\\\4* \sqrt{(x - 2)} - 3[/tex]

Now, if the parent function is:

[tex]y = 4*\sqrt{x}[/tex]

Our function is the parent function translated 2 units to the right and 3 units down. The correct option is the third one

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