To obtain information on the corrosion-resistance properties of a certain type of steel conduit, 35 specimens are buried in soil for an extended period. The maximum penetration (in mils) is then measured for each specimen, yielding a sample mean penetration of 52.7 and a sample standard deviation of 4.8. The conduits were manufactured with the specification that true average penetration be at most 50 mils. Does the sample data indicate that specifications have not been met

Answers

Answer 1

Answer:

t(s) > t(c)  then t(s) is in the rejection region for H₀.

We reject H₀ we support the claim that the mean penetration is bigger than that of the specifications

Step-by-step explanation:

Sample Information:

sample size    n  =  35

sample mean    x  =  52.7

sample standard deviation  s  =  4.8

spec. true average  =  50

Test Hypothesis:

Null Hypothesis                             H₀              x  =  50

Alternative Hypothesis                 Hₐ              x  >  50

The standarddeviation of the population is unknown therefore even though we assume  distribution is normal we have to use t-student distribution

The alternative hypothesis indicates that the test is a one-tail test, we will test at significance level α  =  5 %     CI  =  95 %

for  α   =  0.05    t(c)  is from t-student -table   and with  df  = 35 - 1

df  =  34     t(c)  =  1.69

t(s)  =  (  x  -  μ ) / s/√n

t(s)  = ( 52.7  -  50 ) / 4.8/√35

t(s)  =  2.7 * 5.92 / 4.8

t(s)  =  3.33

Comparing   t(s)  and   t(c)  

t(s) > t(c)  then t(s) is in the rejection region for H₀.

We reject H₀ we support the claim that the mean penetration is bigger than that of the specifications


Related Questions

Task 4: gasoline cost

you have $40 to spend on n gallons of gas that costs $3.25 per gallon. determine whether each of the following is an expression or an equation. using the structure, give an interpretation of the practical meaning of each. that is, what do they represent in the real world?

1. 3.25n
2.3.25n=26
3.40-3.25n
4. 40-3.25n=1.00

Answers

1) 3.25n

Overall cost of n gallons of gas

2)3.25n = 26

we are spending 26 dollars on 8 gallons of gas

3)40-3.25n

Ammount we have remaining after spending on n gallons of gas out of 40 dollars

4) 40-3.25n = 1.00

The maximum number of gallons of gas we can buy from 40 dollar is 13 gallons and 1 dollar is still remaining to us.

The given representations could be classified thus :

3.25n (Expression)

3.25n=26 (Equation)

40-3.25n (Expression)

40-3.25n=1.00 (Equation)

Total amount to spend = $40

Cost per gallon = $3.25

Number of gallons = n

An expression could be a variable, constant or a combination of both which is related by an operation symbol.

An equation on the other hand maybe defined as a relationship between two expressions linked by an equal to symbol.

Evaluating the representations given :

3.25n : This is an expression as it lacks an equal to sign connecting the expression. The expression means the cost of n gallons of gas.

3.25n = 26 : This is an equation as it contains two Seperate expressions connected by the equal to sign. The equation means that number of gallons of gas, n that can be purchased with $26.

40 - 3.25n : This is an expression. The amount left after purchasing n gallons from $40.

40 - 3.25n = 1.00 : This is an equation. The number of gallons of gas that can be purchased from $40 and still have $1 left.

Learn more : https://brainly.com/question/18109354


Pedro solves the quadratic equation x^2+6x –14 using the quadratic formula. In which step did Pedro make an error?

Answers

9514 1404 393

Answer:

  correct choice is marked

Step-by-step explanation:

The error is in step 2. The square root cannot be distributed to a sum.

GIVING OUT BRAINLIEST PLS HELP! ALMOST DUE

Answers

Answer:

I think it's option B

Find the solution of the differential equation f' (t) = t^4+91-3/t
having the boundary condition f(1) =1/4

Answers

Answer:

[tex]\displaystyle f(t) = \frac{t^5}{5} + 91t - 3ln|t| - \frac{1819}{20}[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

BracketsParenthesisExponentsMultiplicationDivisionAdditionSubtractionLeft to Right  

Equality Properties

Multiplication Property of EqualityDivision Property of EqualityAddition Property of EqualitySubtraction Property of Equality

Algebra I

FunctionsFunction Notation

Calculus

Derivatives

Derivative Notation

Antiderivatives - Integrals

Integration Constant C

Integration Rule [Reverse Power Rule]:                                                               [tex]\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C[/tex]

Integration Property [Addition/Subtraction]:                                                       [tex]\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx[/tex]

Integration Property [Multiplied Constant]:                                                         [tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle f'(t) = t^4 + 91 - \frac{3}{t}[/tex]

[tex]\displaystyle f(1) = \frac{1}{4}[/tex]

Step 2: Integration

Integrate the derivative to find function.

[Derivative] Integrate:                                                                                   [tex]\displaystyle \int {f'(t)} \, dt = \int {t^4 + 91 - \frac{3}{t}} \, dt[/tex]Simplify:                                                                                                         [tex]\displaystyle f(t) = \int {t^4 + 91 - \frac{3}{t}} \, dt[/tex]Rewrite [Integration Property - Addition/Subtraction]:                               [tex]\displaystyle f(t) = \int {t^4} \, dt + \int {91} \, dt - \int {\frac{3}{t}} \, dt[/tex][1st Integral] Integrate [Integral Rule - Reverse Power Rule]:                     [tex]\displaystyle f(t) = \frac{t^5}{5} + \int {91} \, dt - \int {\frac{3}{t}} \, dt[/tex][2nd Integral] Integrate [Integral Rule - Reverse Power Rule]:                   [tex]\displaystyle f(t) = \frac{t^5}{5} + 91t - \int {\frac{3}{t}} \, dt[/tex][3rd Integral] Rewrite [Integral Property - Multiplied Constant]:                 [tex]\displaystyle f(t) = \frac{t^5}{5} + 91t - 3\int {\frac{1}{t}} \, dt[/tex][3rd Integral] Integrate:                                                                                 [tex]\displaystyle f(t) = \frac{t^5}{5} + 91t - 3ln|t| + C[/tex]

Our general solution is  [tex]\displaystyle f(t) = \frac{t^5}{5} + 91t - 3ln|t| + C[/tex].

Step 3: Find Particular Solution

Find Integration Constant C for function using given condition.

Substitute in condition [Function]:                                                               [tex]\displaystyle f(1) = \frac{1^5}{5} + 91(1) - 3ln|1| + C[/tex]Substitute in function value:                                                                         [tex]\displaystyle \frac{1}{4} = \frac{1^5}{5} + 91(1) - 3ln|1| + C[/tex]Evaluate exponents:                                                                                     [tex]\displaystyle \frac{1}{4} = \frac{1}{5} + 91(1) - 3ln|1| + C[/tex]Evaluate natural log:                                                                                     [tex]\displaystyle \frac{1}{4} = \frac{1}{5} + 91(1) - 3(0) + C[/tex]Multiply:                                                                                                         [tex]\displaystyle \frac{1}{4} = \frac{1}{5} + 91 - 0 + C[/tex]Add:                                                                                                               [tex]\displaystyle \frac{1}{4} = \frac{456}{5} - 0 + C[/tex]Simplify:                                                                                                         [tex]\displaystyle \frac{1}{4} = \frac{456}{5} + C[/tex][Subtraction Property of Equality] Isolate C:                                               [tex]\displaystyle -\frac{1819}{20} = C[/tex]Rewrite:                                                                                                         [tex]\displaystyle C = -\frac{1819}{20}[/tex]Substitute in C [Function]:                                                                             [tex]\displaystyle f(t) = \frac{t^5}{5} + 91t - 3ln|t| - \frac{1819}{20}[/tex]

∴ Our particular solution to the differential equation is  [tex]\displaystyle f(t) = \frac{t^5}{5} + 91t - 3ln|t| - \frac{1819}{20}[/tex].

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Integration

Book: College Calculus 10e

Help will be appreciated

Answers

Answer:

48

hope this helps

have a good day :)

Step-by-step explanation:

Answer:

48

the picture 20 words or longer for the answer so this is extra text

Determine the missing angle in the picture below.

Answers

Answer:

x =41.18114952

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

We know the hypotenuse and adjacent sides

cos theta = adjacent / hypotenuse

cos x  = 14.3/19

taking the inverse cos of each side

cos^-1 (cos x) = cos ^-1 ( 14.3/19)

x =41.18114952

Answer:

Step-by-step explanation:

take x degree as reference angle

using cos rule

cos x=adjacent/hypotenuse

cos x=14.3/19

cos x=0.75

x=cos 41

x= 41 degree

What is the outlier for the data set?
19, 19, 27, 21, 77, 18, 23, 29

Answers

Answer: 77

Step-by-step explanation:

c and d for 20 pts
aaaaaaaaaaaaaaaaa

Answers

Answer:

C. a = 7

D. c = -3

Step-by-step explanation:

C. 7(2a + 3) + 21 = 100+ 40

   14a + 21 + 21 = 140

   14a = 140 - 21 - 21

    14a = 98

    a = 7

D. 6+ 14 - 12c = 56

    20 - 12c = 56

     -12c = 56 - 20

     -12c = 36

       c = - 3

Answer:

Step-by-step explanation:

c.7(2a+3)+21=100+40

14a+21+21=140

14a+42=140

14a=140-42

a=98/14

a=7

d.6+14-12c=56

20-12c=56

-12c=56-20

c=36/-12

c=-3

Select the false statement about inverse relations.
a. The range of a function will be the domain of its inverse.
b. The graphs of inverse relations are reflections in the line y=x.
c. The inverse of a function will always be a function.
d. The domain of a function will be the range of its inverse.

Answers

Answer:

THE ANSWER IS B

Step-by-step explanation:

B mine please im so single

The answer is b trust me

Find the area of this triangle. Round to the nearest tenth.

Answers

Area = 1/2 × 24 × 11 × Sin(76)

Area = 12 × 11 × 0.9703

Area = 132 × 0.9703

Area = 128.0796

Area = 128.1 in^2

What is 8.75% of 172?

Answers

Answer:

15.05 is your answer.

Step-by-step explanation:

To find our answer we will first divide 8.75 by 100 since it is a percentage.  8.75 ÷ 100 = 0.0875

Now we will take 0.0875 and multiply it by 172 and we get 15.05.  Therefore, 15.05 is our answer

Hey there!

8.75% of 172

The word “of” means multiply in mathematical terms.

8.75% * 172

8.75% = 8.75/100 = 0.0875

0.0875 * 172

= 301/20

= 15.05

Answer: 301/20 OR 15.05

(BOTH ANSWERS WORK because they are both equivalent)

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

jack bought a mother bike the original price was 1300 but he got a discount of 20% what was the discounted price of the bike

Answers

The discounted price of the bike is 260.

The product of b and 3​

Answers

Answer and Step-by-step explanation:

The product of a two numbers/values is the result of multiplying two numbers/values.

So, multiply b and 3 together.

3b is the answer.

#teamtrees #PAW (Plant And Water)

Which is the volume of a sphere with diameter
50 cm?

Answers

Answer:

V =65416.666666 cm^3

Step-by-step explanation:

The volume of a sphere is given by

V = 4/3 pi r^3

The diameter is 50 so the radius is 1/2 of the diameter

r = 1/2 (50) = 25

V = 4/3 ( pi) (25)^3

V = 4/3 (pi) 15625

V =20833.3333 pi

Using 3.14 for pi

V =65416.666666 cm^3

Answer:

V =65416.666666 cm^3

Step-by-step explanation:

The volume of a sphere is given by

V = 4/3 pi r^3

The diameter is 50 so the radius is 1/2 of the diameter

r = 1/2 (50) = 25

V = 4/3 ( pi) (25)^3

V = 4/3 (pi) 15625

V =20833.3333 pi

Using 3.14 for pi

V =65416.666666 cm^3

5(2b + 3) + 8(b - 6)

Answers

The answer is
10b+15+8b-48

Answer:

Step-by-step explanation:

5(2b+3)+8(b-6)

=10b+15+8b-48

=18b-33

=3(6b-11)

how do you estimate 10.43

Answers

Answer:

Step-by-step explanation:

Given 10.43, you can 'estimate' it only by rounding off:

10.43 to the nearest tenth is 10.4.

10.43 to the nearest whole number is 10; we drop the fraction 0.43.

1

The track team has 12 more boys than girls. There are a total of 142 team members. How many boys and girls are on the team?

Answers

Answer:

77 boys, 65 girls

Step-by-step explanation:

x as the variable to represent amount of girls, and there are 12 more boys than girls (x+12). So the equation would be:

x + x + 12 = 142

2x + 12 = 142

x = 65

65 girls

then 65+ 12 = 77 boys

The hypotenuse function is correct, but the main function has a problem. Explain why it may not work, and show a way to fix it. Your fix must be to the main function only; you must not change the hypotenuse function in any way.

Answers

Answer: hello your question is incomplete attached below is the missing codes

Answer : It may not work because; the double pointer P was not allotted a double using a new double ( I.e. Error in the main function ) also the cout statement was not written in the main function

Step-by-step explanation:

It may not work because; the double pointer P was not allotted a double using a new double ( I.e. Error in the main function ) also the cout statement  should be moved to the Main

The correction  is below

{

   double* p = new double;

   hypotenuse(1.5, 2.0, p);

  cout << "The hypotenuse is " << *p << endl;

}

I need help with this three problems (with procedure)

Answers

Answer:

13. [tex]x^{3} y^3[/tex] cubic units

14. 43 million; 79 million; 3.6 × [tex]10^7[/tex]

15. 2.68 × [tex]10^5[/tex]

Step-by-step explanation:

Can someone help me pls pls help with this question

Answers

Answer:

D.

Step-by-step explanation:

The mean is 11,000

Plz help me!!(ᗒᗣᗕ)՞
Plz!

Answers

Answer:

A) 64 cm²

Step-by-step explanation:

Trapezoid area formula:

[tex]A=\frac{a+b}{2} h[/tex]

Given:

a = 6

b = 10

h = 8

Work:

[tex]A=\frac{a+b}{2} h\\\\A=\frac{6+10}{2} *8\\\\A=\frac{16}{2} *8\\\\A=8*8\\A=64[/tex]

Suppose you are investigating the relationship between two variables, traffic flow and expected lead content, where traffic flow is a predictor of lead content. You find the 95% CI for expected lead content when traffic flow is 15, based on a sample of n= 10 observations, is (461.7, 598.1).

Required:
What parameter is this interval estimating?

Answers

Answer:

The answers is " Option B".

Step-by-step explanation:

[tex]CI=\hat{Y}\pm t_{Critical}\times S_{e}[/tex]

Where,

[tex]\hat{Y}=[/tex] predicted value of lead content when traffic flow is 15.

[tex]\to df=n-1=8-1=7[/tex]

 [tex]95\% \ CI\ is\ (463.5, 596.3) \\\\\hat{Y}=\frac{(463.5+596.3)}{2}\\\\[/tex]

     [tex]=\frac{1059.8}{2}\\\\=529.9[/tex]

Calculating thet-critical value[tex]t_{ \{\frac{\alpha}{2},\ df \}}=-2.365[/tex]

The lower predicted value [tex]=529.9-2.365(Se)[/tex]

[tex]463.5=529.9-2.365(Se)\\\\529.9-463.5=2.365(Se)\\\\66.4=2.365(Se)\\\\Se=\frac{66.4}{2.365} \\\\Se=28.076[/tex]

When [tex]99\%[/tex] of CI use as the expected lead content: [tex]\to 529.9\pm t_{0.005,7}\times 28.076 \\\\=(529.9 \pm 3.499 \times 28.076)\\\\=(529.9 \pm 98.238)\\\\=(529.9-98.238, 529.9+98.238)\\\\=(431.662, 628.138)\\\\=(431.6, 628.1)[/tex]

Exponential Growth/Decay
Plz help!!!

Answers

Answer:

a) 82.

b) So a growth factor of 0.025

c) 2.5%.

d) f(5) = 93, which means that the population of the island on January 1st 2026 is of 93.

Step-by-step explanation:

Exponential equation of population growth:

The exponential equation for population growth has the following format:

[tex]f(x) = x(0)(1+r)^x[/tex]

In which x(0) is the initial value and r is the growth factor, as a decimal.

In this question:

In x years after 2021:

[tex]f(x) = 82(1.025)^x[/tex]

a)

This is f(0). So

[tex]f(0) = 82(1.025)^0 = 82[/tex]

So 82.

b)

We have to find r. So

[tex]1 + r = 1.025[/tex]

[tex]r = 1.025 - 1 = 0.025[/tex]

So a growth factor of 0.025.

c)

Growth factor multiplied by 100%.

So 0.025*100% = 2.5%.

d)

f(5) = population in 5 years after January 1st 2021, that is, January 1st 2026.

[tex]f(5) = 82(1.025)^5 = 93[/tex]

f(5) = 93, which means that the population of the island on January 1st 2026 is of 93.

plsss help!! is this a right triangle if no or yes please explain why??

Answers

Answer:

yes, it is a right triangle

Step-by-step explanation:

the other two angles are 35 and 55 degrees

Answer:

is NOT a right triangle

Step-by-step explanation:

is a right triangle if it checks the Pythagorean Th.

12² = 10² + 7²

144 = 100+49

144 = 149 False

HELPPPP PLZZZZZzz HELLP FAST I NEED TO PASS

Answers

Answer:

m∠Q= 105°

➬➬➬➬➬➬➬➬

[tex]6x+5+(11x-5)+x=180^o[/tex]

[tex]18x=180[/tex]

[tex]x=10[/tex]

☄m∠Q=105°

❆❆❆❆❆❆❆❆❆❆❆❆

hope it helps....

have a great day!!

Which is the inverse of the following statement?
If the measure of an angle is 90°, then it is a right angle.

Answers

Yes if it’s less than 90 it’s an acute but yes 90 is a right angle

find the largest prime factor of 6108

Answers

Answer:

509

Step-by-step explanation:

There are 4 prime factors of 6108

6108 ÷ 2 = 3054

3054 ÷ 2 = 1527

1527 ÷ 3 = 509

509 ÷ 509 = 1

Choose the best estimate for the multiplication problem below. 56 x 51
A. 2000
B. 3000
C. 4100​

Answers

Answer:

B

Step-by-step explanation:

Answer: B.

Explanation: 56 multiply 51 is 2856 and 3000 is the closest to 2856.

Also pls mark me as brianliest!!

Last week at the business where you work , you sold 120 items. The business paid $1 per item and sold them for $3 each. What profit did the business make from selling the 120 items

Answers

Answer:

240

Step-by-step explanation:

They spent $120 buying 120 items, so they have -$120. By selling the items at 3x the price, they gained the 120 back and made a profit of 240 (120 x 2).

240

3-1=2

120 x 2=240

What combination of transformations is shown below?

Answers

Answer: D) Translation, then reflection

Explanation:

To go from figure 1, to figure 2, we apply a translation (aka "shifting"). Specifically, we translate 3 units to the right and 4 units up.

To go from figure 2 to figure 3, we apply a reflection. The mirror line is vertical and it is along the shared segment of figures 2 and 3.

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