The volume of the object is 6.6 cm³
The amount of space occupied by a three dimensional figure as measured in cubic units and when an object enters water it pushes out water to make room for itself and the object pushes out a volume of water that is equal to its own volume and this is called displacement
So here given data is 14.0 mL of water was placed into the graduated cylinder and then the water level raised to 20.6 mL so we have to find volume = ? here final volume = 20.6 mL and initial volume = 14.0 mL
Volume = final volume - initial volume
Volume = 20.6 mL - 14.0 mL
Volume = 6.6 cm³
The volume of the object is 6.6 cm³
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What is the formula for osmium decobromide
Answer:
OsBr2.
Explanation:
Osmium decobromide is the same as osmium bromide. This is the result of the reaction between osmium hydroxide (Os(OH)2) and hydrobromic acid (HBr) to form water and a salt (osmium bromide):
[tex]Os(OH)_2+2HBr\rightarrow OsBr_2+2H_2O.[/tex]So, osmium bromide has the formula: OsBr2.
Using an id reader to check ids can make it easier to
Display data associated with the ID such as age and other information.
Glassy unfocused eyes slow speech and movement or difficulty with small motor skills indicate a slow reaction. State ID cards, passports military ID cards, and driver's licenses are acceptable forms of ID in most states. Permanent Resident Cards may be accepted in some areas, but check with your administrator.
When a liquor store has carefully examined the identity of a customer before serving alcoholic beverages and reached a reasonable conclusion. Even if it turns out to be a fake ID and the appearance of the minor suggests the minor may be over the age of 21 or doing things she normally wouldn't. It is legally permissible even if it suggests that it is sexual. This can be a behavioral sign of addiction. Delayed reaction time Your body reacts and acts slower.
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A bottle contains 2.55L of gas at STP.How many moles of gas are present?mol
Explanation:
We are given: volume = 2.55L
At STP: Temperature = 273.15 K
: Pressure = 1 atm
: R = 0.08205 L.atm/mol.K
Using the ideal gas law:
[tex]\begin{gathered} PV\text{ = nRT} \\ \\ \therefore\text{ n = }\frac{PV}{RT}\text{ = }\frac{1\times2.55}{0.08205\times273.15}\text{ = 0.11 mol} \end{gathered}[/tex]Answer:
n = 0.11 mol
1. What is the molarity of 245.0 g of H₂SO4 dissolved in 1.00 L of solution?
2. What is the molarity of 5.00 g of NaOH in 750.0 mL of solution?
3. How many moles of NaCl are contained in 100.0 mL of a 0.20 M solution?
4. Determine the number of moles of solute in 16.00 mL of a 0.415-molar Pb(NO3)2 solution.
5. What weight (in grams) of H₂SO4 would be needed to make 750.0 mL of 2.00 M solution?
6. What weight (in grams) of KCI is there in 2.50 liters of 0.50 M KCI solution?
7. What volume (in mL) of 18.0 M H₂SO4 is needed to contain 2.45 g H₂SO4?
8.
Determine the volume in L of the solution with 48.00 grams of PbCl₂ needed to form a 5.0-molar
solution.
9. What volume of 0.250 M KCI is needed to make 100.0 mL of 0.100 M solution?
10. A stock solution of 10.0 M NaOH is prepared. From this solution, you need to make 250.0 mL of
0.375 M solution. How many mL will be required?
The molarity of 245.0 g of H₂SO4 dissolved in 1.00 L of solution is 2.498M. the molarity of 5.00 g of NaOH in 750.0 mL of solution is 0.167M.
Molar ConcentrationA chemical species' concentration in a solution, specifically the amount of a solute per unit volume of solution, is measured by its molar concentration.
The number of moles per liter when denoted by the unit symbol mol/L or mol/dm3 in SI units, is the mostly used unit used for denoting molarity in chemistry. The secret to determining molarity is to keep in mind that it is measured in moles per liter (M).
MV = grams / molar mass
(x)*(1.000 L) = (245.0 g) / (98.0768 g mol¯1)
x = 2.49804235 M
So, calculating it to 4 significant figures, x = 2.498 M
For 2nd question
Applying the same formula, MV = grams / molar mass
(x) (0.7500 L) = 5.00 g / 39.9969 g mol¯1
(x) (0.7500 L) = 0.1250097 mol
x = 0.1666796 M
x = 0.167 M (when calculated to three Significant figures)
For 3rd question,
using variation of the same formula,
0.200 M = x / 0.1000 L
x = 0.0200 mol
For the 4th question,
MV = moles of solute
no of moles x = (0.415 mol L¯1) (0.01600 L)
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Use words and arrows to draw a diagram that shows whether energy is added or removed during changes in state among solid, liquid, and gas.
Energy is added in the conversion of solid to liquids and then the conversion of liquids to gases.
What is change of state?We know that matter occurs in three states; Solid, liquid and gas. Now, we know that solid matter has its particles held together in place such that they do not move about from place to place. The particles of a liquid are not held so closely together hence they do not translate to a large extent. The molecules of a gas are very much free and move about freely from place to place.
Now, we know a solid can be converted to a liquid when it is heated such that the molecules of the solid receive more kinetic energy and move faster and the rigid intermolecular forces that hold them together are broken down thus heat is added.
When we add more heat to the liquid, the intermolecular forces also break down and the we have the gaseous state in which there are no bonds between the molecules.
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an auto mechanic spills 88mL of 2.6M H2S04 solution from an auto battery. How many milliliters of 1.6M NaHCO3 must be poured on the spill to react competely with the sulfuric acid?
The volume (in mL) of the 1.6 M NaHCO₃ solution that must be poured on the spill to react completely is 286 mL
How to determine the volume of NaHCO₃We'll begin by writing the balanced equation for the reaction. This is given below:
H₂SO₄ + 2NaHCO₃ —> Na₂SO₄ + 2H₂O + 2CO₂
The mole ratio of the acid, H₂SO₄ (nA) = 1The mole ratio of the base, NaHCO₃ (nB) = 2The volume of NaHCO₃ can be obtained as follow:
Volume of acid, H₂SO₄ (Va) = 88 mL Molarity of acid, H₂SO₄ (Ma) = 2.6 MMolarity of base, NaHCO₃ (Mb) = 1.6 MVolume of base, NaHCO₃ (Vb) =?MaVa / MbVb = nA / nB
(2.6 × 88) / (1.6 × Vb) = 1 /2
228.8 / (1.6 × Vb) = 1 / 2
Cross multiply
1.6 × Vb = 228.8 × 2
1.6 × Vb = 457.6
Divide both side by 1.6
Vb = 457.6 / 1.6
Vb = 286 mL
Thus, the volume of the NaHCO₃ solution needed is 286 mL
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which 5 systems help u change from a child to a adult
The five systems that helps us grow from a child to adult are excretory, integumentary, digestive, respiratory and cardiovascular system.
What are body systems?The body systems are the combination two or more systems located in the body that helps in the maintenance of hemostasis of the body.
Examples of body systems include the following:
Excretory system: This is the system that contains organs that helps in the removal of metabolic wastes from the body.The integumentary system: This is the system that protects the delicate internal organs of the body.The digestive system: This is the system that helps in the breaking down of food substances for body use.The respiratory system: This is the system that helps in the oxygenation of blood.The cardiovascular system: This is the system that helps in the pumping of blood throughout the body.Learn more about body systems here:
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Suppose 87.1 mL of a 0.190 M solution of Na2SO4 reacts with 143 mL of a 0.311 M solution of MgCl2 to produce MgSO4 and NaCl as shown in the balanced reaction Na2SO4(aq)+MgCl2(aq)⟶MgSO4(s)+2NaCl(aq)
1. Calculate the mass of MgSO4 that can be produced in the given reaction.
2. Only 0.212 g of MgSO4 are isolated after carrying out the reaction. Calculate the percent yield of MgSO4
a. The mass of MgSO₄ that can be produced in the given reaction is 1.985 grams.
b. The percent yield of MgSO₄ is 10.68%
The complete balanced chemical equation is,
Na₂SO₄(aq)+MgCl₂(aq)⟶MgSO₄(s)+2NaCl(aq)
We know,
Molarity(M) = number of moles(n)/per litres solution.
So,
Number of moles of Na₂SO₄ = Molarity × volume.
Moles of Na₂SO₄ = 0.190×0.0871
Moles of Na₂SO₄ = 0.016549 moles.
Moles of MgCl₂ = 0.311×0.144
Moles of MgCl₂ = 0.044473 moles.
As we can see, moles of Na₂SO₄ are present in less amount,
So Na₂SO₄ will be Limiting reagent and it will control the reaction.
So,
Moles of Na₂SO₄ = Moles of MgSO4
Moles of MgSO₄ = 0.016549 moles.
As we know,
Moles = Mass produced/molar mass
Molar mass of MgSO₄ = 120grams/mole
Putting the values,
0.016549 = mass of Mg produced/120
Mass of MgSO₄ produced = 1.985 grams.
b. Percentage yield formula,
Percentage yield = experimental mass/theoretical mass×100
Theoretical mass = 1.985 grams
Experimental mass = 0.212 grams.
Percentage yield = 0.212/1.985×100
Percentage yield of MgSO₄ = 10.68%
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15. If an airplane is in flight, where is the air pressure lower?
under
above
When an airplane is in flight, the air pressure at the under drops.
What is pressure?Pressure is defined as the force applied perpendicular to an object's surface per unit area over which that force is dispersed. Gauge pressure is the pressure in relation to the surrounding atmosphere. Pressure is expressed using a variety of units.
As air flows over an airplane wing, the form of the wing creates a low pressure over the wing surface. The low pressure creates lift, which allows the plane to fly.
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If you dissolved 54 grams of ammonia in 100 grams of water at 400C would it be considered saturated, unsaturated, or supersaturated? Why?
If you dissolved 54 grams of ammonia in 100 grams of water at 400°C then the solution is saturated
A saturated solution is a solution that has dissolved as much solute as it is capable of dissolving and in a saturated solution no more solute can be dissolved at a given temperature and we can make an saturated solution by keep on dissolving solute until no more solute can be dissolved
Here given data is dissolved 54 grams of ammonia in 100 grams of water at 400°C then the ammonia is totally dissolved in this 100 ml water
NH₃ + H₂O → NH₄OH
So, here ammonium hydroxide are formed which is saturated solution and when ammonia is dissolved in water the water molecule donate the proton to the NH₃ molecule and the solubility of ammonia decreases with the increases in of water solvent that's why when we dissolved 54 grams of ammonia in 100 grams of water at 400°C the solution is saturated
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What statement best describes why a chemical change. is different from a physical change?
Answer: a physical change is something we can see, but a chemical change is not always something that we can see.
Explanation: Physical changes show a change in appearance.
There are chemical changes when two aqueous solutions are added together and the product is still two aqueous solutions, so we would not see any change and no precipitate is formed.
So a physical change is something we can see, but a chemical change is not always something that we can see.
8. You are on in-line skates at the top of a small hill. Your potential energy is equal to
The last time you checked, your mass was 60.0 kg.
a. What is the height of the hill?
b. If you start rolling down this hill, your potential energy will be converted to kinetic
energy. At the bottom of the hill, your kinetic energy will be equal to your potential
energy at the top. Calculate your speed at the bottom of the hill.
The hill is 1.7 metres high (Approx.)
Knowing that;
Energy potential = 1000 J
Weight = 60 kg
mgh = potential energy
1,000 = [60][9.8][h]
h = 1.7 m
At the peak of its climb, how much potential energy does the ball still have?The whole amount of energy will be in the form of potential energy since the ball's kinetic energy will be equal to zero. As a result, when the ball reaches the peak of its climb, its potential energy will be 450 J. As a result, the ball will soar as high as 45.91 metres.
An enormous amount of potential or stored energy exists in a rock that is at rest on a hill. The boulder's potential energy transforms into kinetic energy, the energy of motion, when it falls.
The automobile drives faster as it goes down the hill, which results in an increase in kinetic energy and a decrease in potential energy.
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Calculate the theoretical yield in grams All from the complete reaction of 18.3
grams Al according to the following balanced chemical equation:
2 Al(s) + 3 (s) →→
2 All(s)
(s)→ 2
The theoretical yield of aluminum iodide according to the reaction would be 276.5 grams.
Stoichiometric problemWe are looking to get the theoretical yield of aluminum iodide. This can be achieved by first getting the balanced equation of the reaction:
[tex]2Al + 3I_2 --- > 2AlI_3[/tex]
The mole ratio of Al that reacts and the [tex]AlI_3[/tex] that is produced is 1:1.
Recall that: mole = mass/molar mass.
18.3 grams of aluminum completely reacts:
Molar weight of aluminum = 26.98 g/mol
Mole of 18.3 g aluminum = 18.3/26.98
= 0.6782 mole
Since the mole ratio of Al and [tex]AlI_3[/tex] is 1:1, the equivalent mole of [tex]AlI_3[/tex] will also be 0.6782 mole.
Recall that: mass = mole x molar mass
Molar mass of [tex]AlI_3[/tex] = 407.695 g/mol
Mass of 0.6782 [tex]AlI_3[/tex] = 0.6782 x 407.695
= 276.5 grams
In other words, the theoretical yield of [tex]AlI_3[/tex] according to the reaction is 276.5 grams.
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Methane CH_4 is a simple organic molecule that is used as a fuel—it is the major component of natural gas. The bottom of the ocean contains large amounts of methane hydrate (also called methane ice or methane clathrate), enough that it has been suggested as a major source of fuel. The methane hydrate contains 6 moles water for each mole of methane.
What percentage of methane hydrate is methane? =
What percentage is water?=
The percentage of methane is 12.9% and percentage of water is 87.09% in methyl hydrate.
It is given that for every methane molecule, 6 moles of water is present. Then the chemical formula of methane hydrate would be CH₄.6H₂O.The molecular mass of CH₄.6H₂O would be,
Molecular mass of CH₄.6H₂O = 12 + 4 + 6(2 +16)
= 124g/mol
To find the mass percentage of Methane, the following formula is to be used:
Mass percentage of CH₄ = (Mass of methane / Molecular mass of methane hydrate)x100
On substituting the values of mass of CH₄ and mass of CH₄.6H₂O we get,
Mass percentage = (16/124)100
Mass percentage of CH₄ = 12.9%
Therefore the mass percentage of CH₄ in CH₄.6H₂O is 12.9%
Similarly, to find the mass percentage of 6H₂O in methyl hydrate, the following formula is used:
Mass percentage of water = (Mass of 6H₂O/Molecular mass of CH₄.6H₂O)x100
On substituting the values of mass of 6.H₂O and CH₄.6H₂O we get,
Mass percentage of 6H₂O = (108/124)x100
Mass percentage of 6H₂O = 87.09%
Therefore the mass percentage of water in methyl hydrate is 87.09%
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Write the ions present in a solution of NaC2H3O2.
If you mix 2.8 mol of A with 2.8 mol of B, what amount (moles) of A2B can be produced?
Answer: 1.4 mol A2B is produced.
Explanation: 2A + B = A2B, so there are 2 moles of A to every one mole of B.
So if 2.8 mol of A is present 1/2 that amount is made in A2B (and there will be extra B left over because A is the limiting reactant and you can't make more product than the least amount of reactant allows.
So 1.4 mole of A2B will be produced.
Show the complete ionic and net ionic forms of the following equation. Have your
solubility rules open for this problem.
manganese(II) chloride(aq) + ammonium carbonate(aq) => manganese(II)carbonate(s) +
ammonium chloride(aq)
The complete ionic and net ionic forms of the following equation.
ionic equation :
Mn²⁺ + 2Cl²⁻ + 2NH₄⁺ + CO₃²⁻ -----> MnCO₃ + 2NH₄⁺ + 2Cl⁻
net ionic equation :
Mn²⁺(aq) + CO₃²⁻(aq) ----> MnCO₃(s)
according to question :
MnCl₂ + (NH₄)₂CO₃ ----> MnCO₃ + NH₄Cl
balanced molecular equation : with states
MnCl₂(aq) + (NH₄)₂CO₃(aq ----> MnCO₃(s) + 2NH₄Cl(aq)
the complete ionic equation as follows :
Mn²⁺ + 2Cl²⁻ + 2NH₄⁺ + CO₃²⁻ -----> MnCO₃ + 2NH₄⁺ + 2Cl⁻
Now cancel out the spectator ions on both side of equation , the reactant and the product, we get
Mn²⁺(aq) + CO₃²⁻(aq) ----> MnCO₃(s)
now, the complete net ionic equation is
Mn²⁺(aq) + CO₃²⁻(aq) ----> MnCO₃(s)
Thus, The complete ionic and net ionic forms of the following equation.
ionic equation :
Mn²⁺ + 2Cl²⁻ + 2NH₄⁺ + CO₃²⁻ -----> MnCO₃ + 2NH₄⁺ + 2Cl⁻
net ionic equation :
Mn²⁺(aq) + CO₃²⁻(aq) ----> MnCO₃(s)
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Moist air at atmospheric presure, 80 ℃ and relative humidity 40% enters a cooler .
What is the mole fraction yv of H2O in the moist entering air?
How many total moles (air plus water molecules) are in 1m^3 of moist entering air?
How many moles of DA (dry air) ?
The Antoine equation with T in C and p in mm Hg has coefficients for water given by
0 to 60 ℃ : A= 8.10765 B=1750.286 C=235.000
60 to 150℃ : A=7.96681 B=1668.210 C= 228.000
help me i don't know
explain me hahaha
How many moles of BaSO, could be made from 1.25 mol
of Al₂(SO4), provided that sufficient amounts of any
icale are available
Answer: A mole of Aluminium Sulphate contains 12 moles of Oxygen
So
12
1
×0.24
Moles of Aluminium Sulphate contains 0.24 moles of Oxygen
So 2×10
−2
Moles is the answer
Explanation:
The smooth ER differs from the rough ER in that:
A. The rough ER contains no ribosomes, the smooth ER contains ribosomes.
B. The smooth ER produces carbohydrates and lipids, rough ER produces proteins.
C. The smooth ER produces proteins, rough ER produces lipids.
D. The rough ER is the site of mRNA transcription, smooth ER is the site of protein translation.
The smooth ER differs from the rough ER in that the smooth ER produces carbohydrates and lipids, whereas the rough ER produces proteins. (Option B)
What distinguishes the smooth Endoplasmic reticulum from the rough Endoplasmic reticulum?The manufacture, folding, quality assurance, and shipment of some proteins take place in the rough ER, which is dotted with millions of membrane-bound ribosomes.
The production of steroid hormones, lipid (fat) synthesis, and metabolism are all heavily correlated with SER. It also serves as a detoxifier. The production of proteins is greatly aided by the rough endoplasmic reticulum.
The fundamental distinction between the rough endoplasmic reticulum and the smooth endoplasmic reticulum is that the RER contains ribosomes, which give it its rough appearance and enable protein synthesis.
Ribosomes cover the rough endoplasmic reticulum, which is important in the synthesis and creation of proteins.
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When 25.0 mL of 0.500 M AgNO, solution is mixed with 40.0 mL of 0.250 M Na SO4, solid Ag-SO4 precipitates out. What
mass of AgSO4 is formed?
(The molar mass of Ag:SO, is 311.8 g/mol.)
Answer:
Explanation:
yyyyyyyyyyyy
how many magnesium sulfate are in 2,5 magnesium sulfate?
Answer:
Each 2 ml ampoule contains 4 mmol Mg2+ (equivalent to 1 g magnesium sulfate heptahydrate). Each 10 ml ampoule contains 20 mmol Mg2+ (equivalent to 5 g magnesium sulfate heptahydrate). The concentrations of magnesium ions (Mg2+) in millimoles are given as approximate values.
14) Identify which types of acid-base reactions are reversible and which ones are
irreversible.
Acid-base reactions are reversible and which ones are irreversible then the 1st reaction is HA + H₂O ↔ A⁻ + H₃O⁺ is the reversible reaction and in the 2nd reaction MOH → M⁺ + OH⁻ is the reversible reaction and 3rd reaction is HA+H₂O → A⁻ + H₃O⁺ is the irreversible reaction
Acid base reaction is the chemical reaction that occur when acid and base are mixed together called acid base reaction and irreversible reaction means they can occur only in one direction the reactants can change to the products but the products cannot change back to the reactants and reversible reaction means chemical reaction occur in both direction the reactants can change to the products and the products can also change back to the reactants and in that given reactions
1st reaction is HA + H₂O ↔ A⁻ + H₃O⁺ is the reversible reaction because it goes in the both direction called as reversible reaction2nd reaction MOH → M⁺ + OH⁻ is the reversible reaction because in that reaction product can also back to the reactant called as reversible reaction 3rd reaction is HA+H₂O → A⁻ + H₃O⁺ is the irreversible reaction because in that reaction acid are treated with water that's why it is called irreversible reactionKnow more about reversible irreversible
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HW6.3. 221 PS6_1c molal sat balances
Moist air at atmospheric presure, 92 C and relative humidity 44% enters a cooler where it is cooled isobarically at 1 atm to a temperature of 21 C. (Isobaric means at constant pressure)
The Antoine equation with T in C and p in mm Hg has coefficients for water given by
0 to 60 C: A= 8.10765 B=1750.286 C=235.000
60 to 150 C : A=7.96681 B=1668.210 C= 228.000
At the specified temperature 92 C, the Antoine equation gives a vapor pressure p*=567.09 mm Hg, and at a temperature 21 C, the vapor pressure is p*=18.65 mm Hg.
What is the molal saturation of the moist entering air?
What is the molal saturation of the exiting air at 21 C
If the moist entering air contains 33.39 total moles which includes 22.43 moles of dry air; how many g's of water condenses in the cooler?
The molal saturation of the moist entering air is 10.96 mol, molal saturation of the exiting air at 21 C is 0.560 mol and 187.2g of water condenses in the cooler.
Antoine equationThe Antoine equation can be stated as a class of semi-empirical correlations describing the exact relation between vapor pressure and temperature for pure substances.
it is seen that
humidity = 44%
Ptotal = 1 atm = 760 mm Hg
[tex]P_{H2O}[/tex] = RH/100 X [tex]P^{*} _{H2O}[/tex] = 52/100 X 567.09
= 294.88 mmHg
Molal saturation = [tex]\frac{P_{H2O} }{P_{T} -P_{H2O} }[/tex]
= 294.88/ (760 - 294.88)
= 0.6361
Exit air = 100% (after cooling)
[tex]P_{H2O}[/tex] = [tex]P^{*} _{H2O}[/tex] at 21°C = 18.65
Hm2 = 18.67/ (760 - 18.65)
= 0.025
Mole of water that enters = mole of total moist - mole of total dry
= 33.39 - 22.43
= 10.96
mole of water exits after cooling
n2 = Hm2 x (mole of dry air)
= 0.025 x 22.43
= 0.560
water condenses = n1 - n2
=10.96 - 0.560
=10.4 mol
=10.4 x 18 g
= 187.2 g
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Question 7 of 8
How many mL HCI of a 0.100 M HCI solution is needed to completely neutralize
25.0 mL of a 0.350 M NaOH solution according to the balanced chemical reaction:
HCl(aq) + NaOH(aq) → H₂O(l) + NaCl(aq)
The volume of HCl is needed to completely neutralize is 81.25 ml.
Formula of neutralization, M₁V₁ = M₂V₂
M₁ = concentration of HCl
V₁ = volume of HCl
M₂ = concentration of NaOH
V₂ = volume of NaOH
Put the value in M₁V₁ = M₂V₂
0.100 × V₁ = 25 × 0.325
V₁ = 25 × 0.325/ 0.100
V₁ = 81.25 ml
Hence, the volume of HCl is 81.25 ml.
In chemistry, neutralization or neutralization is a chemical reaction wherein acid and a base react quantitatively with every other. In a reaction in water, neutralization results in there being no excess of hydrogen or hydroxide ions present inside the answer.
whilst a strong acid reacts with a strong base the ensuing salt is neither acidic nor primary in nature i.e. it's far impartial for instance whilst HCl, a strong acid, reacts with NaOH, a robust base, the resulting salt is sodium chloride and water.
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What is the molarity of a nitric acid solution if 49.90 mL of a 0.01 KOH solution is needed to neutralize 20.00 mL of the acid solution?
The question requires us to calculate the molarity (or molar concentration) of a HNO3 solution, given the volume and concentration of a KOH solution used to neutralize a given volume of the acid.
The following information was provided by the question:
molarity of KOH solution = M(KOH) = 0.01 M = 0.01 mol/L
volume of KOH solution = V(KOH) = 49.90 mL
volume of HNO3 solution = V(HNO3) = 20.00 mL
To answer this question, we need to take a look at the neutralization reaction between HNO3 and KOH:
HNO3 + KOH -> KNO3 + H2O
From the reaction, we have that 1 mol of HNO3 is necessary to neutralize 1 mol of KOH. With this information, we can write that, to achieve complete neutralization:
number of moles of HNO3 = number of moles of KOH
Since the molarity of a solution is given by the following equation:
[tex]\text{molarity = }\frac{\text{number of moles (mol)}}{volume\text{ of solution (L)}}\to M=\frac{n}{V}[/tex]We can rearrange it to:
[tex]n=M\times V[/tex]And we can also write the equality between the number of moles of HNO3 and KOH as:
[tex]n_{HNO_3}=n_{KOH}\to M_{HNO_3}\times V_{HNO_3}=M_{KOH}\times V_{KOH}[/tex]And, since the concentration of KOH was provided, as well as the volumes of HNO3 and KOH necessary to achieve neutralization, we can apply these values to calculate the molarity of HNO3 using the equation above:
[tex]M_{HNO_3}\times V_{HNO_3}=M_{KOH}\times V_{KOH}\to M_{HNO_3}=\frac{M_{KOH}\times V_{KOH}}{V_{HNO_3}}[/tex][tex]M_{HNO_3}=\frac{(0.01\text{ mol/L)}\times(49.90\text{ mL)}}{(20.00\text{ mL)}}=0.02495\text{ mol/L}[/tex]Therefore, the molarity of the nitric acid solution is equal to 0.02495 mol/L.
When subjected to heat and pressure, a chemical sedimentary rock can be changed into which rock type?
Responses
foliated igneous rock
clastic sedimentary,
metamorphic
non-foliated igneous
I am not sure what the answer would be.
If 22.2 g of iodine reacts with excess hydrogen gas, the amount, in grams, of hydrogen iodide that would be formed is 44.75 grams.
Stoichiometric problemFrom the balanced equation of the reaction, as shown in the illustration, the mole ratio of the iodine that reacts and the hydrogen iodide that forms is 1:2.
22.2 g of iodine reacted.
Recall that: mole = mass/molar mass
Molar mass of iodine = 126.9 g/mol
Mole of iodine that reacted = 22.2/126.9
= 0.1749 moles
From the mole ratio, the equivalent mole of hydrogen iodide that will be produced is:
0.1749 x 2 = 0.3499 moles
Recall that: mass = mole x molar mass
Molar mass of hydrogen iodide = 127.9 g/mol
Mass of 0.3499 mole hydrogen iodide = 0.3499 x 127.9
= 44.75 grams
Thus, the amount of hydrogen iodide that will be produced is 44.75 grams.
More on stoichiometric problems can be found here: https://brainly.com/question/14465605
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Draw the arrow(s) required to go from the left structure to the right structure.
Answer:
See image below
Explanation:
To convert the left structure to the right structure, one pair of electrons on the oxygen is pushed down onto the carbon-oxygen bond (resulting in a double bond). This results in too many electrons on the top carbon. The electrons from the adjacent double bond are subsequently pushed onto the second carbon.
how many atoms are in a tetrahedral molecule?
Answer:
There would be 4 atoms in a tetrahedral molecule.
Explanation:
Answer: 4 atoms
Explanation: