To enhance heat rejection from a spacecraft, an engineer proposes to attach an array of rectangular fins to the outer surface of the spacecraft and to coat all surfaces with a material that approximates blackbody behavior. Consider the U-shaped region between adjoining fins and subdivide the surface into components associated with the base (1) and the side (2). Obtain an expression for the rate per unit length at which radiation is transferred from the surfaces to deep space, which may be approximated as a blackbody at absolute zero temperature. The fins and the base maybe assumed to be isothermal at a temperature T. Comment on your result. Does the engineer's proposal have merit

Answers

Answer 1

Answer:

Attached below is the required diagram related to the question

answer :

q'3 = WбT^4

engineer's proposal has merit

Explanation:

Let : A'3 represent the deep space

      A'1 represent the surface area , F13 and  F23  represent the view factors

      T1 , T2, T3 ; represent temperatures

      q'3 represent net rate of heat radiation

 Derive the expression for the rate per unit length at which radiation is transferred from the surfaces to deep space

derived expression ; q'3 = WбT^4

attached below is a detailed solution

Given that The emission is proportional to the area of the opening and the surfaces ( 1 and 2 ) have the same temperature hence this problem can be treated as a two surface enclosure. hence the engineer's proposal have merit .

attached below is a prove ( b )

To Enhance Heat Rejection From A Spacecraft, An Engineer Proposes To Attach An Array Of Rectangular Fins
To Enhance Heat Rejection From A Spacecraft, An Engineer Proposes To Attach An Array Of Rectangular Fins

Related Questions

If a runner is running at 100 meters per minute at the exact moment they cross the finish line of a race, it is the
instantaneous speed.

O True
O False

Answers

Answer:

Hello! Your answer would be, O False

Explanation:

Hope I helped! Brainiest plz!♥ Have a nice morning! Hope you make a 100%! -Abby

Answer:

False is the correct answer.

Explanation:

plz mark me as brainliest.

A doorknob is a type of wheel and axle. In a doorknob, the door handle acts as the wheel. The handle is connected to a cylinder, called a spindle, which acts as the axle. When the handle turns, the spindle turns in the same direction. The spindle is located inside the handle and pulls the latch back and forth, allowing the door to open.


In the doorknob shown above, when the handle is rotated a distance of 84 millimeters, the spindle is rotated a distance of 14 millimeters. What is the mechanical advantage of this doorknob?
A. 504
B. 6
C. 84
D. 14

Answers

I’m not 100% sure but I believe it’s C.84

Two identical guitar strings are prepared such that they have the same length ( 0.66 m ) and are under the same amount of tension. The first string is plucked at one location, primarily exciting the fourth harmonic. The other string is plucked in a different location, primarily exciting the second harmonic. The resulting sounds give rise to a beat frequency of 351 Hz . What is the wave propagation speed on the guitar strings

Answers

Answer:

[tex]154.44\ \text{m/s}[/tex]

Explanation:

L = Length of guitar string = 0.66 m

Difference of fourth and first harmonic = 351 Hz

v = Wave propagation speed on the guitar strings

So,

[tex]\dfrac{4v}{2L}-\dfrac{v}{2L}=351\\\Rightarrow \dfrac{3v}{2L}=351\\\Rightarrow v=\dfrac{351\times 2\times 0.66}{3}\\\Rightarrow v=154.44\ \text{m/s}[/tex]

The wave propagation speed on the guitar strings is [tex]154.44\ \text{m/s}[/tex].

Can you please help me ?

Answers

Answer:

Distance is 300 and displacement is 100

Explanation:

Distance= 100+100+100=300

Displacement=100

plz mark me as brainliest.

Why is a star an example of a good blackbody radiator?
A. It gives off a range of wavelengths of electromagnetic radiation
that depends on its temperature.
B. It absorbs a range of wavelengths of electromagnetic radiation
and gives off none.
c. It reflects most electromagnetic radiation instead of absorbing it.
D. It gives off only one wavelength of electromagnetic radiation.

Answers

Answer: A. It gives off a range of wavelengths of electromagnetic radiation that depends on its temperature.

Explanation: Quizzed

If you were on a spaceship traveling at 0.50c away from a star, what speed
would the starlight pass you?

Answers

Explanation:

The speed of light in vacuum is the same by all observers (2nd Principle). You would find that the starlight passes you at c. This is more than a thousand times faster than existing space craft.

According to all observers, the velocity of light in a vacuum will be the same (2nd Principle). You'd discover that the starlight is passing you at c. Compared to current spacecraft, this really is a thousand times faster.

What is Speed?

The amount of the shift in approach per unit of time or the size of the displacement over time for an object can be used to describe speed, which would be a scalar quantity in everyday language and kinematics.

The maximum speed that can be maintained when a time period grows closer to zero is the starting speed.

By dividing the object's distance traveled by the duration of the interval, the mean pace of the object for the given period of time is calculated. Speed and velocity are not always the same thing.

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two bodies of masses 10 kg and 4 kg are moving in opposite direction with the same velocity of 5 m per second if they Collide and stick together after the impact calculate their velocities​

Answers

Answer:

dasd

Explanation:

dsdas

A
ring
made
up of equal semicircular section
of cast Iron and cast steel with two air gaps
of o-imm and 0.25mm respectively has a cross
soctional area of 400 cm and a mean diameter
of 5m. The ring is uniformly wound with a coil
of 1200 furns. if the relative permeability
of cast iron and cast steel are 2800 and
900 respectively, determine the current
required to produce
a flux of lomwb in​

Answers

Explanation:

I couldn't have information on this question.

A coil of 10 turns is in the shape of an ellipse having a major axis of 13.0 cm and a minor axis of 6.00 cm. The coil rotates at 73rpm in a region in which the Earth's magnetic field is 55.0 microT. What is the maximum voltage induced in the coil if the axis of rotation of the coil is along its major axis and this axis of rotation is aligned perpendicular to the Earth's magnetic field

Answers

Answer:

the maximum voltage induced in the coil is 2.574 × 10⁻⁵ V

Explanation:

Given the data in the question;

Number of turns N = 10

major axis Ma = 13 cm = 0.13 m

a = 0.13/2 = 0.065 m

Minor axis Mi = 6 cm = 0.06 m

b = 0.06/2 = 0.03 m

we know that; 1 RPM = 0.10472 rad/s

rate of rotation R = 73rpm = 7.64 rad/s

Magnetic field = 55 uT

we know that, Area of ellipse = π × a × b

we substitute

A = π × 0.065 m × 0.03 m

A = 0.006126 m²

so

Maximum Voltage = N × Area × Magnetic field × rate of reaction

we substitute

Maximum Voltage = 10 × 0.006126 × ( 55 × 10⁻⁶ ) × 7.64

Maximum Voltage = 2.574 × 10⁻⁵ V

Therefore, the maximum voltage induced in the coil is 2.574 × 10⁻⁵ V

A loudspeaker in a parked car is producing sound whose frequency is 20 510 Hz. A healthy young person with normal hearing is standing nearby on the sidewalk but cannot hear the sound because the frequency is too high. When the car is moving, however, this person can hear the sound. (a) Is the car moving toward or away from the person

Answers

Answer:

The car must be moving away from the person.

Explanation:

From Doppler's Effect, we know that when a sound source moves towards a stationary observer, the apparent frequency of that sound increases. While the apparent frequency decreases if the source moves away from the stationary observer.

The audible range of frequencies for a human ear is 20 Hz to 20000 Hz. Therefore, in order for the sound of a loud speaker to be audible for the person, the frequency must decrease below 20000 Hz.

Due to this reason, the car must be moving away from the person.

A wheel has eight spokes and a radius of 30 cm. It is mounted on a fixed axle and is spinning at 2.5 rev/s. You want to shoot a 24- cm arrow parallel to this axle and through the wheel without hitting any of the spokes Assume that the arrow and the spokes hitting any of the spokes. Assume that the arrow and the spokes are very thin. (a) What minimum speed must the arrow have to pass through (a) What minimum speed must the arrow have to pass through without contact

Answers

Answer:

4.8 m/s

Explanation:

Given: angular velocity of wheel ω = 2.5 rev/sec

radius r = 30 cm

length of arrow = 24 cm

For arrow to pass through spinning ring it has to pass between any two spokes of the wheel.

angle between two spokes = π/4

time taken by a spook to reach the position of adjacent spoke t =θ/ω

=  π/4/(2.5×2π) = 1/20 sec

for the arrow to pass through the spokes of the wheel it should take time t <1/20 sec to pass through the wheel

a) therefore, minimum speed = (24/100)/(1/20) = 4.8 m/s

a boat carving people more than its capacity is at risk of sinking, why?​

Answers

Answer:

Explained below.

Explanation:

For a boat or any object to float on water, it's density must be less than that of water.

Now, when the maximum capacity of people to be carried by the boat is exceeded, it's possible that the maximum mass of people will also be exceeded depending on the mass of the people in the boat.

Now, we know that; density = mass/volume.

Thus, the higher the mass of the people, the higher the density and the higher the density, the more likely it is to be above that of water and the more likely it is to sink.

A car advertisement states that a certain car can accelerate from rest to
27m/s in 4.9 seconds at a temperature of 75F. What is the acceleration of
the car?

Answers

Answer:

Acceleration of the car = 5.51 m/s²

Explanation:

Given:

Initial speed of car = 0 m/s

Final speed of car = 27 m/s

Time taken by car = 4.9 seconds

Find:

Acceleration of the car

Computation:

Using first equation of motion

v = u + at

Where

v = Final velocity

u = Initial velocity

t = Time taken

a = Acceleration

So,

v = u + at

27 = 0 + a(4.9)

a(4.9) = 27

a = 5.51 m/s²

Acceleration of the car = 5.51 m/s²

At a distance of 40 ft from the pad, a man observes a helicopter taking off from a heliport. If the helicopter lifts off vertically and is rising at a speed of 53 ft/sec when it is at an altitude of 129 ft, how fast is the distance between the helicopter and the man changing at that instant

Answers

Answer:

The distance between the helicopter and the man is increasing at a rate of 50.622 feet per second.

Explanation:

First, we create a geometric diagram representing the situation between man (point O),  helicopter (point P) and helipad (point H). The distance between man and helicopter is represented by Pythagorean Theorem:

[tex]x^{2}+y^{2} = r^{2}[/tex] (1)

Where:

[tex]x[/tex] - Distance between man and helipad, in feet.

[tex]y[/tex] - Distance between helipad and helicopter, in feet.

[tex]r[/tex] - Distance between man and helicopter, in feet.

By Differential Calculus, we derive an expression for the rate of change of the distance between man and helicopter ([tex]\dot r[/tex]), in feet per second:

[tex]2\cdot x\cdot \dot x + 2\cdot y\cdot \dot y = 2\cdot r\cdot \dot r[/tex]

[tex]\dot r = \frac{x\cdot \dot x + y\cdot \dot y}{r}[/tex]

[tex]\dot r = \frac{x\cdot \dot x + y\cdot \dot y}{\sqrt{x^{2}+y^{2}}}[/tex] (2)

Where:

[tex]\dot x[/tex] - Rate of change of the distance between man and helipad, in feet per second.

[tex]\dot y[/tex] - Rate of change of the distance between helicopter and helipad, in feet per second.

If we know that [tex]x = 40\,ft[/tex], [tex]y = 129\,ft[/tex], [tex]\dot x = 0\,\frac{ft}{s}[/tex] and [tex]\dot y = 53\,\frac{ft}{s}[/tex], then the rate of change of the distance between man and helicopter is:

[tex]\dot r = \frac{x\cdot \dot x + y\cdot \dot y}{\sqrt{x^{2}+y^{2}}}[/tex]

[tex]\dot r = 50.622\,\frac{ft}{s}[/tex]

The distance between the helicopter and the man is increasing at a rate of 50.622 feet per second.

If you weigh 690 N on the earth, what would be your weight on the surface of a neutron star that has the same mass as our sun and a diameter of 15.0 km ? Take the mass of the sun to be ms = 1.99×1030 kg , the gravitational constant to be G = 6.67×10−11 N⋅m2/kg2 , and the free-fall acceleration at the earth's surface to be g = 9.8 m/s2 . Express your weight wstar in newtons.

Answers

Answer:

W' = 1.66 x 10¹⁴ N

Explanation:

First, we will calculate the mass:

[tex]W = mg[/tex]

where,

W = weight on earth = 690 N

m = mass = ?

g = acceleration due to gravity on earth = 9.8 m/s²

Therefore,

[tex]m = \frac{W}{g} = \frac{690\ N}{9.8\ m/s^2}\\\\m = 70.4\ kg[/tex]

Now, we will calculate the value of g on the neutron star:

[tex]g' = \frac{GM}{R^2}[/tex]

where,

g' = acceleration due to gravity on the surface of the neutron star = ?

G = Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²

M = Mass of the Neutron Star = 1.99 x 10³⁰ kg

R = Radius of the Neutron Star = 15 km/2 = 7.5 km = 7500 m

Therefore,

[tex]g' = \frac{(6.67\ x\ 10^{-11}\ N.m^2/kg^2)(1.99\ x\ 10^{30}\ kg)}{(7500\ m)^2}\\\\g' = 2.36\ x\ 10^{12}\ m/s^2[/tex]

Therefore, the weight on the surface of the neutron star will be:

[tex]W' = mg'\\W' = (70.4\ kg)(2.36\ x\ 10^{12}\ m/s^2)[/tex]

W' = 1.66 x 10¹⁴ N

When two substances that cannot dissolve each other are mixed, a ________ mixture is formed

Answers

Answer: hetero i think i dont know

Explanation:

Answer:

When two substances that cannot dissolve each other are mixed, a mixture is formed.

i hope this helps a little bit.

What is the magnitude and direction of the net force on a ball that has a force of 27N North and 18N North applied to it?

Answers

Answer:

Magnitude: =  32.45 Direction: =  33.69

Explanation:

The magnitude of the net force acting on an object is equal to the mass of the object multiplied by the acceleration of the object, as shown in this formula. We find its magnitude using the Pythagorean Theorem or the distance formula, and we find its direction using the inverse tangent function. Given a position vector →v=⟨a,b⟩, the magnitude is found by |v|=√a2+b2. The direction is equal to the angle formed with the x-axis, or with the y-axis, depending on the application.

A microphone is attached to a spring that is suspended from the ceiling, as the drawing indicates. Directly below on the floor is a stationary 440-Hz source of sound. The microphone vibrates up and down in simple harmonic motion with a period of 2.0 s. The difference between the maximum and minimum sound frequencies detected by the microphone is 2.1 Hz. Ignoring any reflections of sound in the room and using 343 m /s for the speed of sound, determine the amplitude of the simple harmonic motion.

Answers

Answer:

[tex]0.261\ \text{m}[/tex]

Explanation:

[tex]\Delta f[/tex] = Change in frequency = 2.1 Hz

[tex]f[/tex] = Frequency of source of sound = 440 Hz

[tex]v_m[/tex]= Maximum of the microphone

[tex]v[/tex] = Speed of sound = 343 m/s

[tex]T[/tex] = Time period = 2 s

We have the relation

[tex]\Delta f=2f\dfrac{v_m}{v}\\\Rightarrow v_m=\dfrac{\Delta fv}{2f}\\\Rightarrow v_m=\dfrac{2.1\times 343}{2\times 440}\\\Rightarrow v_m=0.8185\ \text{m/s}[/tex]

Amplitude is given by

[tex]A=\dfrac{v_m T}{2\pi}\\\Rightarrow A=\dfrac{0.8185\times 2}{2\pi}\\\Rightarrow A=0.261\ \text{m}[/tex]

The amplitude of the simple harmonic motion is [tex]0.261\ \text{m}[/tex].

1. If a system is isolated, the total energy within that system is constant. Consider the case of a hot cup of coffee: when it cools down, the energy goes into the surrounding air, causing the air to warm. If the coffee and the air are placed in an isolated chamber, the total energy of the system (coffee + air) is constant because the energy lost by the coffee is exactly equal to the energy gained by the air.
The only way for the total energy of a system to change is when it is not isolated, meaning that external forces or sources of energy interact with the system. If we want to define a system where the total energy is conserved, which one of the choices below would be the best system to consider?
A. The person
B. The person and the Earth
C. The Earth
2. Based on your answer to Question 1, why doesn’t the total energy of the Earth-person system change when the person goes up to a new height, gaining potential energy?

Answers

Answer:

1. B. The person and the Earth

2. This is because the energy gained by the person equals the energy lost by the earth,

Explanation:

1.

B. The person and the Earth

This is because the person and the earth both represent a system. A system consists of more than one item. A system consists of two or more items interacting with each other.

2. This is because, the energy of an isolated system is conserved according to the second law of thermodynamics which states that in an isolated system, energy can neither be created nor destroyed. So, there is an exchange of energy between the person and the Earth. So, the energy gained by the person at the new height equals the energy lost by the earth. And thus, the total energy of the system remains constant.

What is the animal behavior where organisms imitate another organism or environment in some way?

Answers

Mimicry. This is when oraganisms imitate another oraganism whether it be physical or behavoioral.

An object changes velocity from 100m/s
to 76m/s in 6 seconds. If it has a mass of
20kg, what is the net force?

Answers

Answer:

1-1=0

Explanation:

ahriqqwertyuioo

A circuit is built based on this circuit diagram.
What is the equivalent resistance of the circuit?
0.61 Ω
Ο 1.6 Ω
7.5Ω
Ο 18 Ω
12V
3.0 Ω.
6.0 Ω
9.Ο Ω.
Will mark brainlyest. No “links” I don’t want them

Answers

[tex]\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}[/tex]

Actually Welcome to the concept of resistors,

The equivalent circuit is given as,

1/Rp = 1/3 + 1/6 + 1/9

1/Rp = 6+3+2/18

1/Rp = 11/18

Rp = 18/11 ==> 1.63 ==> 1.6 ohms

hence the equivalent resistance of the circuit is 1.6 ohms

The equivalent resistance of the circuit is 1.6Ω. The correct option is B.

What is Ohm’s law?

Ohm’s law state that ” At constant temperature, the current (I) flowing through a conductor is directly proportional to the potential difference(V) across the two endpoints of the given conductor.”

I.e V ∝ I

V=IR

Where V= potential difference across the conductor.

I = current flowing through the conductor.

R= constant pf proportionality i.e resistance which unit is ohm(Ω).

There are two ways we can connect the resistors.

(i) series connection

If a number of resistors are said to be connected in series When the same current (I) flows through them.

Let R1, R2, and R3 be the resistors connected in series.

Then the R equivalent is

Req=R1+R2+R3

(ii) parallel connection

A number of resistors are said to be connected in parallel when the same potential difference(V) exists across each of them.

Let R1, R2, and R3 be the resistors connected in parallel.

Then the R equivalent is

1/Req=1/R1+1/R2+1/R3

In this question,

The three resistance connected in parallel by applying the above formula we get,

1/Req=1/R1+1/R2+1/R3

1/Req = 1/3 + 1/6 + 1/9      .................  (∵R1=3Ω,R2=6Ω AND R3=9Ω)

1/Req =11/18

Req=18/11

Req=1.6363Ω

Req≈1.6Ω

Therefore, The equivalent resistance of the circuit is 1.6Ω.

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What is the solubility of KNO3 at 50°C?
45 grams
63 grams
70 grams
83 grams

Answers

I need this answer too , can someone please help , I have a time limit , please

Answer:

The solubility of KNO3 at 50 degrees C is 83 g/100 g water.

Explanation:

when u see the graph and by using graph reading techniques then u find the solubility.

what kind of charge does an object have if it has extra positive charges

Answers

An electrical charge is created when electrons are transferred to or removed from an object. Because electrons have a negative charge, when they are added to an object, it becomes negatively charged. When electrons are removed from an object, it becomes positively charged.

What is perihelion and aphelion in short.

Answers

I dont know you could start by asking your teacher, parent, and or siblings.

Ps the last part was a joke they never help.

Answer:

I think that perihelion is the point of the Earth's course that is close to the Sun. And i'm sure that aphelion in short is astronomy or otherwise the point in the orbit of a planet.

Explanation:

Hope this helps :)

A 20-kg child is on top of a slide was pushed down by his brother giving him an initial speed of 2 m/s down the slide. what is the child's speed at the bottom of the slide if the slide is 5 m high and 10m long and the force of friction between the child and slide is negligible?​

Answers

Answer:

please find your answer in the attached picture, along with explanation.

What organ in the digestive system ABSORBS NUTRIENTS from broken down food?

Answers

Answer:

The small intestine absorbs most of the nutrients in your food, and your circulatory system passes them on to other parts of your body to store or use. Special cells help absorbed nutrients cross the intestinal lining into your bloodstream.

Explanation:

A right triangle has side lengths of 4 centimeters and 5 centimeters. What is the length of the hypotenuse?
O A. 3 cm
B. 4 cm
C. 5 cm
D. 41 cm

Answers

Answer D




Explanation:


what is the meaning of love ? ...What is love?​

Answers

Answer:

love is a feeling that you get for people that you care about.

Explanation:

Answer:

Love is a feeling of affection for someone, when you adore somebody.

I wish true love and soul mates were real ( •_•)

The speed of surface waves in water decreases as the water becomes shallower. Suppose waves travel across the surface of a lake withn a speed of 2m/s and a wavelength of 1.5m. When these waves move into a shallower part of the lake, their speed decreases to 1.6m/s, though their frequency remains the same. Find the wavelength of the wave in the shallower water.

Answers

Answer:

The correct solution is "1.2 m".

Explanation:

The given values are:

Wavelength of waves,

λ = 1.5 m

Speed of waves on surface,

V = 2 m/sec

Speed of waves in water,

V₁ = 1.6 m/sec

As we know,

⇒  [tex]V=f\times \lambda[/tex]

or,

⇒  [tex]f=\frac{V}{\lambda}[/tex]

On substituting the values, we get

⇒      [tex]=\frac{2}{1.5}[/tex]

⇒      [tex]=1.33 \ Hz[/tex]

hence,

⇒  [tex]\lambda_1=\frac{V_1}{f}[/tex]

On substituting the values, we get

⇒       [tex]=\frac{1.6}{1.33}[/tex]

⇒       [tex]=1.2 \ m[/tex]

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