Think back to your three models of matter in parts A and B. Which model had a definite shape? Explain.

Answer:

cf4, ch20,vhjuyu8hc hi l bro tap

Yes, Is it possible to use subatomic particles as an energy source.

A subatomic particle is nothing but a particle which is smaller than an atom in size. Typically, an atom can be broken down into three subatomic particles, namely: protons, electrons, and neutrons.

Yes, Is it possible to use subatomic particles as an energy source.

There are instances when the protons and electrons in an atom's outermost shells are not strongly attracted to one another. It is possible to force these electrons out of their orbits.

They may move from one atom to another by exerting force. Electricity is made up of these moving electrons.

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John steps outside and observes that clouds have started to form in the sky, and it looks like it could rain. Clouds have formed due to the warm, wet air in a low pressure system has risen up and cooled down.

Hence, Option C is correct answer.

Clouds are formed by the process of evaporation and which is followed by condensation. Clouds are small droplets of water crystallization which float in the air. When the moist air rises upwards then the formation of clouds take place because when air rises upwards it becomes colder.

Thus from the above conclusion we can ay that John steps outside and observes that clouds have started to form in the sky, and it looks like it could rain. Clouds have formed due to the warm, wet air in a low pressure system has risen up and cooled down.

Hence, Option C is correct answer.

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Answer: Answer would be C I read the assignment and got it correct

Explanation:

Answer:

[tex]\huge\boxed{\sf 9812.16\ L\ of\ air}[/tex]

Explanation:

Given that,

A person breathes 6.814 L of air in a minute.

1 minute = 6.814 L

= 1 × 24 × 60 (24 hours in a day; 60 minutes in an hour)

= 1440 minutes

1 minute = 6.814 L of air

1440 minutes = 6.814 L × 1440

1 day = 9812.16 L of air

[tex]\rule[225]{225}{2}[/tex]

A hurricane is a type of severe cyclone formed when winds rotate as the pressure between low and high-pressure areas increases.

A cyclone is a violent storm that occurs when cyclone winds exceeds a speed of 74 miles (119 kilometers) per hour.

Hurricanes are classified according to their strength and catastrophic potential on a scale ranging from 1 to 5 (more violent).

In conclusion, a hurricane is a cyclone formed when a it rotates as the low and high-pressure areas increases.

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Answer:

A  group 1

Explanation:

Group 1

reactivity decreases as you go from L to R or downward on the periodic table

Q=mcΔt

Q=66.3 x 0.93 x (67-23)

Q=2712.996 J

[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\qquad \tt \rightarrow \:Q = 2.713 \:\:kJ [/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

[tex]\qquad \tt \rightarrow \: Q = ms\Delta T[/tex]

[tex] \textsf{Q = heat evolved/absorbed = ??} [/tex]

[tex] \textsf{m = mass in gram = 66.3 g} [/tex]

[tex] \textsf{s = specific heat = 0.930 J/g °C} [/tex]

[tex] \textsf{ΔT = change in temp = 67 - 23 =44°C} [/tex]

[tex] \large\textsf{Find Q : } [/tex]

[tex]\qquad \tt \rightarrow \:Q=( 66.3) \sdot (0.93) \sdot(44)[/tex]

[tex]\qquad \tt \rightarrow \:Q = 2713 \: \: joules[/tex]

[tex]\qquad \tt \rightarrow \:Q= 2.713 \: \: kj[/tex]

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

Answer:

The ion that is formed when an acid is dissolved in a solution is OH-.

Explanation:

An acid is a molecule that donates hydrogen ions, or protons, to another molecule. In solution, the acid dissociates, or breaks apart, to form hydrogen ions and the negatively-charged anion of the acid. The anion of a typical acid is the molecule minus the hydrogen ions, so it is OH- for hydrochloric acid, HCl.

What we need to do to drive the equilibrium to the products side is removing the CO as it forms.

The equilibrium position is dependent in the conditions of the reaction. We know that the direction to which the equilibrium is shifted can be altered by manipulating the parameters of the reaction.

Now the reaction is; C + H₂O -----> CO + H₂ + energy. The case in point here is to drive the equilibrium position towards the products side.

What we need to do to drive the equilibrium to the products side is removing the CO as it forms.

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The Ka of the solution is 8.1 * 10^-9.

The pH of a solution is the concentration of hydrogen ions in the solution.

Number of moles of the acid =  26.816g/153.483g/mol = 0.175 moles

Concentration of the acid =  0.175 moles/0.5 L = 0.35 M

Now we know that the acid reacts with water as follows;

HA(aq)  + H2O(l) ------> H3O^+(aq) + A^-(aq)

[H3O^+] = Antilog (-4.274)

[H3O^+] = 5.32 * 10^-5 M

Since;

[H3O^+]  = [A^-] = x

Ka = x^2/[HA]

Ka = (5.32 * 10^-5)^2/( 0.35)

Ka = 8.1 * 10^-9

Hence, the Ka of the solution is 8.1 * 10^-9.

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The three words which best describe the composition of the inner planets are rocky, solid, and dense.

A planet classified as an inner planet is one that is rocky, solid, and dense by nature, such as Mercury, Venus, Earth, and Mars. Inner planets are those that are nearest to the Sun.

There are two types of planets:

Based on astronomical information and records, there are two main types of planets :

The moons of the inner planets are either absent or limited to one (Earth) or two (Mars). The inner planets don't have any rings. The inner planets have shorter orbits around the Sun than the outer planets, but they all rotate more slowly.

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Answer:rocky soild and dense

Explanation:

Answer: 0.42 atm

Explanation:

For this problem, we are going to use the ideal gas law for pressure, which is [tex]P=\frac{nRT}{V}[/tex]. If you do not know yet, R is the ideal gas constant, [tex]0.0821\frac{L*atm}{mol*K}[/tex]First, we must find the number of CH₄ moles.

[tex]6.022gCH_{4} *\frac{1molCH_{4} }{16.043gCH_{4} } =0.38molCH_{4}[/tex]

Next, we will plug in our given information to the ideal gas law for pressure.

[tex]P=\frac{nRT}{V}[/tex]

[tex]P=\frac{0.38mol*0.0821\frac{L*atm}{mol*K} *402K}{30.0L} =0.42 atm[/tex]

The answer to this, according to the work done above, is 0.42 atm.

I hope this helps! Pls mark brainliest!! :)

The pressure of a sample of CH4 gas (6.022 g) in a 30.0 L vessel at 402 K is  0.413 atm.

Pressure of gas will be calculated by using the ideal gas equation as:

PV = nRT, where

P = pressure of gas = ?

V = volume of gas = 30L

R = universal gas constant = 0.082 L·atm·K⁻¹·mol⁻¹

T = temperature of gas = 402 K

n is moles of gas & it will be calculated as:

n = W/M, where

W = given mass of CH₄ = 6.022g

M = molar mass of CH₄ = 16g/mol

n = 6.022 / 16 = 0.376mol

Now putting all these values on the above equation, we get

P = (0.376)(0.082)(402) / (30)

P = 0.413 atm

Hence required pressure of methane gas is 0.413 atm.

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Answer:

mass and the square of the magnitude of velocity.

Explanation:

Taking into account the ideal gas law, the mass of chlorine present is 47.9284 grams.

An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:

P×V = n×R×T

where

In this case, you know:

Replacing in the ideal gas law:

14.2 atm× 1 L = n× 0.082 [tex]\frac{atmL}{molK}[/tex]× 256 K

Solving:

(14.2 atm× 1 L)÷ (0.082 [tex]\frac{atmL}{molK}[/tex]× 256 K)= n

0.676 moles= n

Being the molar mass of chlorine Cl₂ 70.9 g/mole, the mass of the compound can be calculated as:

0.676 moles× 70.9 g/mole= 47.9284 grams.

Finally, the mass of chlorine present is 47.9284 grams.

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The Capillary effect means water can "climb" up thin tubes and water plants. This is due to the surface tension nature of water.

Hope this helps:)

The capillary effect means water can "climb" up thin tubes and water plants. This is due to the adhesive nature of water.

The capillary effect is a phenomenon where liquids, like water, can rise against gravity in narrow tubes or spaces, such as the stems of plants. This effect is possible due to the adhesive nature of water, which allows it to stick to the walls of the tube or surface it comes into contact with.

The cohesive forces between water molecules create a sort of "pull" that allows the water to climb up the tube, defying gravity. This property is essential for plants, as it helps them transport water and nutrients from their roots to their leaves and other parts of the plant, supporting their growth and survival.

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Answer:

38

Explanation:

that I believe is correct

The half-life of the reaction is determined as 22.4 hr.

The half life of the reaction is calculated as follows

rate of reaction, k = Δ[A]/3t = Δ[B]/2t

t = Δ[A]/3k = Δ[B]/2k

where;

t = (3)/(3 x 0.0447) = (2)/(2 x 0.0447) = 22.4 hr

Thus, the half-life of the reaction is determined as 22.4 hr.

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Answer:

See below

Explanation:

.75 = 1/2^(40/h)      

log .75 / ( log 1/2) = 40 / h

h = half life =   96.37683 min

To solve this type of question we must know the concept of rate law. The half-life of a compound is 23 years for 75% of a given sample of the compound decomposes in 40 minutes.

There are two kinds of rate law in chemical kinetics one is differential rate law and other is integrated rate law

The rate law for first order kinetics is

[tex]k=\frac{2.303}{t}log\frac{a}{a-x}[/tex]

Where

k - rate constant

t - time passed by the sample

a - initial amount of the reactant

a-x - amount left after the decay process

The expression for the half-life of the compound is

[tex]t_{1/2} = \frac{0.693}{K}[/tex]

Where k is the rate constant

t = 40 minutes

a = 100 g

a-x = 100 g - 75g = 25 g

(Since it is given that 75% of the given compound decomposes)

Then,

[tex]k=\frac{2.303}{40}log\frac{100}{25}[/tex]

=0.03years⁻¹

[tex]t_{1/2} = \frac{0.693}{0.03}[/tex]

=23 years

Therefore, the half-life of the given compound is 23years.

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Answer:

Same as lithium

Explanation:

Lithium and Ceaseum both are group one elements i.e alkali metals

So they have same chemical properties almost

Hence Ceaseum would react with oxygen in 2:1 ratio

The equation of the reaction is;

Ca(OH)2(aq) + 2HCl(aq) ------> CaCl2(aq) + 2H2O(l)

The term neutralization has to do with the process in which an acid reacts with a base to form salt and water only. A neutralization reaction is known by the fact that water is obtained by the reaction of hydrogen and hydroxide ions.

The equation of the reaction is;

Ca(OH)2(aq) + 2HCl(aq) ------> CaCl2(aq) + 2H2O(l)

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Cellular Respiration is the process of the release of energy from food. Hence, option B is correct.

Cellular respiration is the process by which organisms use oxygen to break down food molecules to get chemical energy for cell functions.

Through the process of cellular respiration, the energy in food is converted into energy that can be used by the body's cells. During cellular respiration, glucose and oxygen are converted into carbon dioxide and water, and the energy is transferred to ATP.

Hence, option B is correct.

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The B class main sequence star from the given images is Star 3.

B class main-sequence stars are of spectral type B and luminosity class V. They are very luminous and blue with surface temperatures between 10,000 and 30,000 K.

The stars that are blue as shown in the image are Star 1 and Star 3. However, Star is the one that has surface temperature between 10,000 and 30,000 K.

Therefore, Star 3 is a B class main sequence star.

In conclusion, stars are luminous objects with very high surface temperatures.

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Answer:

j

Explanation:

becaisdbyhe wrl is so not goood

R is the mixture formed by adding 5 g of sugar to 1 L of water.

A mixture is an impure substance made up of two or more substances which are miscible or immiscible in each other.

Dissolving the sugar in the water makes a homogenous mixture and once dissolved a solution is made by the combination of a solute (sugar) and solvent (water).

Hence, R is the mixture formed by adding 5 g of sugar to 1 L of water.

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The statement that most likely describes the results from their experiments is Tristan and Arya would exert more energy to overcome friction than Anoush and Keran. Thus, the correct option is A.

Friction may be characterized as the force that counters the proximate motion between two surfaces of objects when they reach to contact.

According to the question, Tristan is working with static friction and Arya is working with sliding friction; static friction operates on things when they are catnapping on a surface, whereas sliding friction functions on objects when they are gliding over a surface.

Sliding friction is much more fragile and weaker than static friction and is comparatively uncomplicated and utilizes less energy to drag the objects.

The complete question is as follows:

Four students are doing different friction experiments with a cylinder.

Therefore, the correct option for this question is A, i.e. Tristan and Arya would exert more energy to overcome friction than Anoush and Keran.

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[tex]\\ \tt\leadsto \dfrac{d[NH_3]}{dt}=1.50\times 10^{-6}[/tex]

[tex]\\ \tt\leadsto \dfrac{d[H_2]}{dt}=\dfrac{3}{2}\dfrac{d[NH_3]}{dt}[/tex]

[tex]\\ \tt\leadsto \dfrac{d[H_2]}{dt}=\dfrac{3}{2}(1.5\times 10^{-6})[/tex]

[tex]\\ \tt\leadsto \dfrac{d[H_2]}{dt}=2.25\times 10^{-6}Ms^{-1}[/tex]

M is molarity here not metre

The average rate of appearance of H2 over the time period from t = 0 s to [tex]\rm t = 5.48\times10^3 s\ is\ 2.25\times10^{-6}[/tex] M/s.

To find the average rate of appearance of [tex]\rm H_2[/tex], we can use the stoichiometry of the reaction to relate it to the rate of disappearance of [tex]\rm NH_3[/tex].

From the balanced equation: [tex]\rm 2NH_3(g) - > N_2(g) + 3 H_2(g)[/tex]

We can see that for every 2 moles of [tex]\rm NH_3[/tex] that disappear, 3 moles of [tex]\rm H_2[/tex] appear.

Given that the average rate of disappearance of [tex]\rm NH_3\ is\ 1.50\times10^{-6} M/s[/tex], we can calculate the average rate of appearance of [tex]\rm H_2[/tex] as follows:

Average rate of appearance of [tex]\rm H_2[/tex] = (3/2) x (Average rate of disappearance of [tex]\rm NH_3[/tex])

Average rate of appearance of [tex]\rm H_2[/tex] = (3/2) x [tex]\rm (1.50\times10^{-6} M/s)[/tex]

Average rate of appearance of [tex]\rm H_2[/tex] = [tex]\rm 2.25\times10^{-6} M/s[/tex]

Therefore, the average rate of appearance of [tex]\rm H_2[/tex] over the time period from t = 0 s to [tex]\rm t = 5.48\times10^3 s\ is\ 2.25\times10^{-6}[/tex] M/s.

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Gay Lussac's Law

P₁/T₁=P₂/T₂

25°C = 25+273 = 298 K

0.5/298 = 1.5/T₂

T₂ = 894 K = 621 °C

A gas law known as Gay-Lussac's law asserts that a gas's pressure (when kept at a constant volume and mass) varies directly with its absolute temperature. The new temperature is 612 °C and the correct option is A.

When the mass is fixed and the volume is constant, the pressure a gas exerts is proportional to the temperature of the gas. In the year 1808, French scientist Joseph Gay-Lussac created this law. Gay-Lussac's law can be expressed mathematically as follows:

P₁ / T₁ = P₂ / T₂

25°C = 25 + 273 = 298 K

0.5 / 298 = 1.5 / T₂

T₂ = 894 K

T₂ = 894-273

T₂  = 621 °C

Thus the correct option is A.

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The  amount of heat required to melt the iceberg at 9.58 * 10¹⁸ kJ.

The heat required to melt a unit mass of ice is known as the latent heat of fusion.

The latent heat of fusion of ice of 1 kg= 334 kJ of heat

Mass of iceberg = 3.1 x 10¹³ m³ * 917 kg = 2.8427 * 10¹⁶ kg

Amount of heat required = 2.8427 * 10¹⁶ * 334 = 9.58 * 10¹⁸ kJ.

Therefore, the amount of heat required to melt the iceberg at 9.58 * 10¹⁸ kJ.

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The mass in kg of the water on the roof after the rainstorm is mathematically given as

The mass of the water on the roof after a rainstorm is 1.1 *10^{10}g  or 1.1*10^{7}kg

Generally, the equation for the Area of the roof is  mathematically given as

[tex]A=0.20 \times 10^{10} \mathrm{~cm}^{2}[/tex]

height of the rain =5.5cm

the volume of the rain on the roof =1.1 * 10^{10} CC

Generally, the equation for mass is  mathematically given as

mass=volume*density

[tex]&=\left(1.1 \times 10^{10} \mathrm{cC} \times 1 \mathrm{~g} / \mathrm{cc}\right) \\&=1.1 \times 10^{10} \mathrm{~g}[/tex]

In conclusion, the Mass of the water on the roof after a rainstorm is 1.1 *10^{10}  or $1.1*10^{7}

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The amount of heat required to change the sample from ice at -45.0°C to liquid water at 75.0°C is 83.8 kJ.

The total quantity of heat required is calculated as follows;

q(tot) = q1(to ice) + q2(fusion of ice) + q3(liquid)

q(tot) = mcΔθ₁  + mΔHf    +   mcΔθ₂

q(tot) = (100)(4.2)(0 - -45) + (334)(100)  + (100)(4.2)(75 - 0)

q(tot) = 18,900 J  +  33,400 J   +  31,500 J

q(tot) = 18.900 kJ  +  33.400 kJ   +  31.500 kJ

q(tot) = 83,800 J = 83.8 kJ

Thus, the amount of heat required to change the sample from ice at -45.0°C to liquid water at 75.0°C is 83.8 kJ.

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Answer:

q1 9.42

q2 226

q3 31.4

qtot 267

Explanation:

hope this help