there were 7 pizzas. 5 people ate all of the pizzas, each person ate an equal amount of pizza. how much pizza did each person eat

Answers

Answer 1

Answer:

1 2/5 pizza each

Step-by-step explanation:

I think this is QUITE obvious but

you divide 7 by 5 because its an equal amount per person which gives you 7/5 = 1 2/5

Answer 2

Answer:

1.4 of the pizza or [tex]1\frac{2}{5}[/tex] of the pizza

Step-by-step explanation:

Do 7 ÷ 5   (7 pizzas divided among 5 people)

Each person ate 1.4 or [tex]1\frac{2}{5}[/tex] pizza


Related Questions

If a =5 and b=3 what is the value of the 2a-3b+3a

Answers

Answer:

If a = 5 and b = 3, then that means 2a - 3b + 3a = 16

Step-by-step explanation:

2a - 3b + 3a

(2×5) - (3×3) + (3×5)

10 - 9 + 15 = 16

Simplify the expression using order of operation 5 x 2 + 3 to the power of 2

Answers

answer= 1

5 x 2 - 3^2

1. First simplify exponents

= that is nine

2. Then Do 5 x 2- 9

5 x 2=10

10-9

= 1

$500.00 at 4% for 5 years
50 points if you anwser asap​

Answers

Answer:

100

Step-by-step explanation:

it gives you the formula for simple interest

Which fraction is equivalent to 1/6

1/3
2/8
3/24
4/24​

Answers

Answer:

the last one- 4/24

Step-by-step explanation:

ive answered this question before and got it correct

4/24 is the right answer for this question

Pls answer this. I need the answer quick. Just write the answer. no downloads

Answers

Answer:

POINTS HA

Step-by-step explanation:

Solve for 41.
1259
61 = [?]
61
37°
889

Answers

Answer: 55

Step-by-step explanation:

180 = 125 + x

x = 55

the angle is 55. all angles of a triangle adds to 180. 37+88=125. 180-125=55.

Benny has two small fish tanks with one fish in each tank. One tank has 3 1/2 quarts of water. The other tank has 6 pints of water. Benny combines the water into one large fish tank with both fish in the large tank. How many pints of water are in the large tank?

Answers

Answer:

6 1/2 quarts I think

Step-by-step explanation:

So sorry if I'm wrong! Have a nice day! Owa Owa!

A filtration process removes a random proportion of particulates in water to which it is applied. Suppose that a sample of water is subjected to this process twice. Let x1 be the proportion of the particulates that are removed by the first pass. Let X2 be the proportion of what remains after the first pass that is removed by the second pass. Assume that X1 and X2 are independent random variables with common pdf. f(x) = 4x3, for 0 < x <1 and f(x) = 0 otherwise. Let Y be the proportion of the original particulates that remain in the sample after two passes. Then Y = (1 - X1)(1 - X2). Find E(Y).

Answers

Answer:

[tex]E(Y)=\frac{1}{25}[/tex]

Step-by-step explanation:

Let's start defining the random variables for this exercise :

[tex]X_{1}:[/tex] '' The proportion of the particulates that are removed by the first pass ''

[tex]X_{2}:[/tex] '' The proportion of what remains after the first pass that is removed by the second pass ''

[tex]Y:[/tex] '' The proportion of the original particulates that remain in the sample after two passes ''

We know the relation between the random variables :

[tex]Y=(1-X_{1})(1-X_{2})[/tex]

We also assume that [tex]X_{1}[/tex] and [tex]X_{2}[/tex] are independent random variables with common pdf.

The probability density function for both variables is [tex]f(x)=4x^{3}[/tex] for [tex]0<x<1[/tex] and [tex]f(x)=0[/tex] otherwise.

The first step to solve this exercise is to find the expected value for [tex]X_{1}[/tex] and [tex]X_{2}[/tex].

Because the variables have the same pdf we write :

[tex]E(X_{1})= E(X_{2})=E(X)[/tex]

Using the pdf to calculate the expected value we write :

[tex]E(X)=\int\limits^a_b {xf(x)} \, dx[/tex]

Where [tex]a=[/tex] ∞ and [tex]b=[/tex] - ∞ (because we integrate in the whole range of the random variable). In this case, we will integrate between [tex]0[/tex] and [tex]1[/tex] ⇒

Using the pdf we calculate the expected value :

[tex]E(X)=\int\limits^1_0 {x4x^{3}} \, dx=\int\limits^1_0 {4x^{4}} \, dx=\frac{4}{5}[/tex]

⇒ [tex]E(X)=E(X_{1})=E(X_{2})=\frac{4}{5}[/tex]

Now we need to use some expected value properties in the expression of [tex]Y[/tex] ⇒

[tex]Y=(1-X_{1})(1-X_{2})[/tex] ⇒

[tex]Y=1-X_{2}-X_{1}+X_{1}X_{2}[/tex]

Applying the expected value properties (linearity and expected value of a constant) ⇒

[tex]E(Y)=E(1)-E(X_{2})-E(X_{1})+E(X_{1}X_{2})[/tex]

Using that [tex]X_{1}[/tex] and [tex]X_{2}[/tex] have the same expected value [tex]E(X)[/tex] and given that [tex]X_{1}[/tex] and [tex]X_{2}[/tex] are independent random variables we can write [tex]E(X_{1}X_{2})=E(X_{1})E(X_{2})[/tex]   ⇒

[tex]E(Y)=E(1)-E(X)-E(X)+E(X_{1})E(X_{2})[/tex] ⇒

[tex]E(Y)=E(1)-2E(X)+[E(X)]^{2}[/tex]

Using the value of [tex]E(X)[/tex] calculated :

[tex]E(Y)=1-2(\frac{4}{5})+(\frac{4}{5})^{2}=\frac{1}{25}[/tex]

[tex]E(Y)=\frac{1}{25}[/tex]

We find that the expected value of the variable [tex]Y[/tex] is [tex]E(Y)=\frac{1}{25}[/tex]

You go to the doctor and he gives you 11 milligrams of radioactive dye. After 12 minutes, 7.75 milligrams of dye remain in your system. To leave the doctor's office, you must pass through a radiation detector without sounding the alarm. If the detector will sound the alarm if more than 2 milligrams of the dye are in your system, how long will your visit to the doctor take, assuming you were given the dye as soon as you arrived

Answers

Answer:

In (16.8+12=) 28.8 minutes the person will be left only with 2mg of dye in the body and be able to leave the doctor's office after being injected with 11 mg

Step-by-step explanation:

After 12 minutes, 7.75 milligrams of dye remain in your system.

This means that 11- 7.75= 3.25 milligrams of dye are used up in 12 minutes

7.75-2= 5.75 milligrams still needs to be used up

         Dye           Minutes

         3.25             12

          5.75             x

x= 12*5.75/3.25

x= 16.8 minutes

5.75 mg will be used up in 16.8 minutes

In (16.8+12=) 28.8 minutes the person will be left only with 2mg of dye in the body and be able to leave the doctor's office.

I need helppppppppppp

Answers

Answer:

b.)36

Step-by-step explanation:

Formula for area of a trapezoid = [tex]\frac{a+b}{2} h[/tex]

where a and b = bases and h = height

The sign has the following dimensions

Base 1 = 6ft

base 2 = 12ft

height = 4ft

Using these dimensions we plug in the values into the formula

[tex]A=\frac{6+12}{2} 4\\6+12=18\\\frac{18}{2} =9\\9*4=36[/tex]

Hence the area of Mr. Wash's sign is 36 square feet.

Answer:

b) 36 sq ft.

Step-by-step explanation:

6 x 4 = 24 (multiply to find the square after splitting it)

12 - 6 = 6 x 4 = 24 / 2 = 12 (you divide by two because it's a triangle)

24 + 12 = 36

hope this helps :)

What is the solution to the equation below round your answer to two decimal decimal places log4 x=2.1
A. x=8.40
B. x=18.38
C. x=8.17
D. x=19.45

Answers

Answer:

B 18.38

Step-by-step explanation:

log4x = 2.1

logx/log4 = 2.1

logx = log(4) x 2.1

logx = 1.2643

x = antilog(1.2643)

x = 18.38 (to 2 d.p)

Answer:

X=18.38

Step-by-step explanation:

What is the zero of function f?
f(x)=7^3Vx+12-12

Answers

Answer:

hope it helps ya.

please give me brainliest

Need help please
What is the measure of angle 1?
What is the measure of angle 3?
What is the measure of angle 6?

Answers

Answer:

Step-by-step explanation:

Do you have any measurements?

1) 180-Angle 2 = Angle 1

3) Same as Angle 2

6) Same as Angle 2

Last year a farm produced 6.2 - 10^6soybeans and 7.8. 10^6 onions.
a.) What was the total number of vegetables produced by the farm last year?

Answers

Answer:

Yessir

Step-by-step explanation:

What is the completely factored form of f(x)=x3+4x2+9x+36 ?
f(x)=(x+4)(x−3)(x+3)

f(x)=(x−4)(x−3i)(x+3i)

f(x)=(x+4)(x−3i)(x+3i)

f(x)=(x−4)(x−3)(x+3)

Answers

Hereaaaaaaaaaaaaaaaaaaaaaaaaaaa

No random links or answers, please.

Answers

Answer:

the ans is 21 hope it may help u

Step-by-step explanation:

g = 6

x=6

x= 3x + 3

x = 3 × 6 +3

x = 18 + 3

x= 21

A rectangle is graphed on a coordinate plane. The rectangle’s two lines of symmetry are the x-axis and the y-axis. Evie says that means the vertices are reflections of each other over the x-axis and y-axis. Is she correct? Explain your reasoning NO LINKS worth 50 points

Answers

Answer:

Can you add a picture if there are any?

Step-by-step explanation:

Convert x=-3 to polar equation

Answers

If a point
(
x
,
y
)
is written as
(
r
,
θ
)
in polar coordinates, then
x
=
r
o
s
θ
and
y
=
r
sin
θ
.
As such in polar form equation
x
=

3
can be written as
r
cos
θ
=

3
or
r
=

3
cos
θ

What is the volume please help me

Answers

Answer:

125 inches cubed

Step-by-step explanation:

First, you find the volume of the full square, and then you divide your answer by 2, since the figure is a triangle.

So,

10 x 10 x 2.5 = 250

250 ÷ 2 = 125 inches cubed

PLEASE HELP WITH THIS ASPA 3/8 divided by-3/5

Answers

Answer:

Step-by-step explanation:

please help this is very important i will give you brain thing if its correct and no links pwease <3

Answers

Answer:

the 2nd and 3rd one I believe

Leroy wants to teach his puppy 6 new tricks. In how many different orders can the puppy learn the tricks?​

Answers

Answer: 720 ways

Step-by-step explanation:

Given

Leroy wants to teach his puppy 6 new tricks

Considering each trick is different from other

The first trick can be taught in 6 different ways

After learning the first trick, there are 5 tricks remaining which can be taught in 5 different ways

Similarly, for the remaining tricks, it is 4, 3, 2, and 1 way

So, the total number of ways is [tex]6\times 5\times 4\times 3\times 2\times 1=720\ \text{Ways}[/tex]

Simplify: x^1/3( x^1/2 + 2x^2)

Answers

Answer:

Step-by-step explanation:

x^1/3( x^1/2 + 2x^2)

x^(1/2 + 1/3) + 2x^(2 + 1/3)

x^(5/6) + 2x^(7/3)

What is the rule for the number pattern below ?950,800,650,500,350

Answers

Subtracts 150 each time—


950-150=800 and 800-150=650 and so on and so forth. The number sequence only includes 5 numbers so there is no way to tell if there is a tougher solution.

what is 8/3x-x+5/3=13/6-2/3x​

Answers

Answer:

Step-by-step explanation:

A complex electronic system is built with a certain number of backup components in its subsystems. One subsystem has eight identical components, each with a probability of 0.1 of failing in less than 1,000 hours. The sub system will operate if any four of the eight components are operating. Assume that the components operate independently. Find the probability that
a. exactly two of the four components last longer than 1000 hours.
b. the subsystem operates longer than 1000 hours.

Answers

Answer:

a) 0.0486 = 4.86% probability that exactly two of the four components last longer than 1000 hours.

b) 0.9996 = 99.96% probability that the subsystem operates longer than 1000 hours.

Step-by-step explanation:

For each component, there are only two possible outcomes. Either they last more than 1,000 hours, or they do not. Components operate independently, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

One subsystem has eight identical components, each with a probability of 0.1 of failing in less than 1,000 hours.

So 1 - 0.1 = 0.9 probability of working for more, which means that [tex]p = 0.9[/tex]

a. exactly two of the four components last longer than 1000 hours.

This is P(X = 2) when [tex]n = 4[/tex]. So

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 2) = C_{4,2}.(0.9)^{2}.(0.1)^{2} = 0.0486[/tex]

0.0486 = 4.86% probability that exactly two of the four components last longer than 1000 hours.

b. the subsystem operates longer than 1000 hours.

The subsystem has 8 components, which means that [tex]n = 8[/tex]

It will operate if at least 4 components are working correctly, so we want:

[tex]P(X \geq 4) = 1 - P(X < 4)[/tex]

In which

[tex]P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)[/tex]

So

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{8,0}.(0.9)^{0}.(0.1)^{8} \approx 0[/tex]

[tex]P(X = 1) = C_{8,1}.(0.9)^{1}.(0.1)^{7} \approx 0tex]

[tex]P(X = 2) = C_{8,2}.(0.9)^{2}.(0.1)^{6} \approx 0[/tex]

[tex]P(X = 3) = C_{8,3}.(0.9)^{3}.(0.1)^{5} = 0.0004[/tex]

Then

[tex]P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0 + 0 + 0 + 0.0004 = 0.0004[/tex]

[tex]P(X \geq 4) = 1 - P(X < 4) = 1 - 0.0004 = 0.9996[/tex]

0.9996 = 99.96% probability that the subsystem operates longer than 1000 hours.

5y - 2y = 3y + 2
please help.

Answers

It’s 0 = 2 I hope this helps a bit

Is 6.584 a rational number

Answers

What's your numerator and denominator value?

Multiplying polynomials
(4x+3y)(5x+y)

Answers

Answer:

20x^2 +19xy+3y^2

Step-by-step explanation:

See Image below :)

9514 1404 393

Answer:

  20x² +19xy +3y²

Step-by-step explanation:

Use the distributive property.

  (4x +3y)(5x +y)

  = 4x(5x +y) +3y(5x +y)

  = 20x² +4xy +15xy +3y²

Collect terms.

  = 20x² +19xy +3y²

A very weak university is on and off probationary status with the accrediting agency. A different procedure is used in July and in January to determine its status for the next 6 months. In July, the probability of changing status by coming off probation is .25; but the probability of changing status by going on probation is .12. In January, the probability of coming off probation is .15; but the probability of going on probation is .08. a) If the university is on probation as of February 2019; what is the probability it will be off probation in February 2020

Answers

Answer:

0.3425 = 34.25% probability it will be off probation in February 2020

Step-by-step explanation:

We have these desired outcomes:

Off probation in July 2019, with 0.25 probability, then continuing off in January, with 1 - 0.08 = 0.92 probability.

Still in probation in July 2019, with 1 - 0.25 = 0.75 probability, then coming off in January, with 0.15 probability.

What is the probability it will be off probation in February 2020?

[tex]p = 0.25*0.92 + 0.75*0.15 = 0.3425[/tex]

0.3425 = 34.25% probability it will be off probation in February 2020

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