If you buy a ticket, you can expect to make a profit of approximately $0.96 on average.
To calculate the expected profit, we need to consider the probability of winning each prize and the value of each prize.
The probability of winning each prize can be calculated by dividing the number of winning tickets by the total number of tickets. There is 1 winning ticket for each prize, so the probability of winning each prize is:
$240 prize: 1/250
$130 prize: 1/250
$120 prize: 1/250
$70 prize: 1/250
The value of each prize is already given, so we can multiply the probability of winning each prize by its value and sum the results to find the expected profit:
Expected profit = (1/250 x $240) + (1/250 x $130) + (1/250 x $120) + (1/250 x $70) - ($16)
Expected profit = $0.96
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perry como fans fifty-six percent of respondents to an online poll said that they were perry como fans. if 982 randomly selected people responded to this poll, what is the true proportion of all local residents who are perry como fans? estimate at the 95% confidence level.
Perry como fans fifty-six percent of respondents to an online poll said that they were perry como fans. if 982 randomly selected people responded to this poll.
By use the sample proportion to estimate the true proportion of all local residents who are Perry Como fans.
Let p be the true proportion of all local residents who are Perry Como fans. Then, the sample proportion is 0.56 and the sample size is n = 982.
We construct a 95% confidence interval for p by using the formula
Sample proportion ± z*standard error
Where z is the critical value from the standard normal distribution for a 95% confidence level, which is 1.96. The standard error is the estimated standard deviation of the sample proportion which is defined as
[tex]\sqrt{p*(1-p)/n} \\}[/tex]
By putting the values we get
Standard error = [tex]\sqrt{0.56*(1-0.56)/982)[/tex] = 0.018.
95% confidence interval = 0.56 ± 1.96*0.018 = (0.525, 0.595).
Hence, we can say with 95% confidence that the true proportion of all local residents who are Perry Como fans is between 0.525 and 0.595.
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Divide the sum of 13/5 and -12/7 by their difference
Answer to these fraction is 31/151
Describe fraction.
Any numerical value that is not a whole number is referred to as a fraction. It symbolizes a portion of something or several portions of something. The numerator and the denominator are the two components of a fraction. The denominator indicates how many equally sized pieces make up a whole, whereas the numerator indicates how many equally sized parts are picked from the whole or collection.
To divide a fraction, all you need to do is flip its numerator and denominator, multiply the outcome by the other fraction, and simplify1.
In light of this, we have:
SUM:
(13/5) + (-12/7) = (13× 7 + -12 ×5) / (5 ×7)
= (91 - 60) / 35 = 31/35
DIFFERENCE:
(13/5) - (-12/7) = (13× 7 - -12× 5) / (5× 7)
= (91 + 60) / 35 = 151/35
Dividing these two fractions:
(31/35) ÷ (151/35) = (31/35)×(35/151) = 31/151
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In the figure below, <1 measures (3x + 20) and <2 measures x. what is the measure of <4?
After solving the given angles we can conclude that ∠4 is (D) 140° respectively.
What are angles?Two rays that have a common terminal and are referred to as the angle's sides and vertices, respectively, make up an angle in Euclidean geometry.
Two rays can form angles in the plane where they are positioned.
Angles are also produced when two planes intersect.
These are what are known as dihedral angles.
Acute, obtuse, right, straight, reflex and full rotation are examples of basic angles.
So, according to the given image, we know that:
∠ 1 + ∠ 2 = 180
Then,
(3x + 20) + x = 180
4x + 20 = 180
4x = 180 - 20
4x = 160
x = 160 / 4
x = 40
We got that:
∠ 1 = ∠ 4
∠ 2 = ∠ 3
Simply substitute for x and solve if ∠1 = ∠4:
3x + 20 = 3(40) + 20 = 120 + 20 = 140
Therefore, after solving the given angles we can conclude that ∠4 is (D) 140° respectively.
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A woman decides to have children until she has her first girl or until she has four children, whichever comes first. Let X = number of children she has. For simplicity, assume that the probability of a girl is .5 for each birth.a. Write the simple events in the sample space. Use B for boy and G for girl. For instance, one simple event is BG, because the woman would stop having children once she has a girl.b. Find the probability for each of the simple events in the sample space.c. Find the probability distribution function for X.d. Draw a picture of the probability distribution function for X.
For the experiment of birth of children,
a) Sample space is S = { G, BG, BBG, BBBG, BBBB}.
b) The probability for each of the simple events in the sample space, 0.5, 0.25, 0.125, 0.0625 and 0.0625.
c) The probability distribution function for X is 0.5, 0.25, 0.125, 0.0625 and 0.0625.
d) The table form of probability density function is present in above figure.
We have a woman who decides to have children until she has first a baby girl or until she has four children, which event occurred.
a) Sample space is S = { G, BG, BBG, BBBG, BBBB} where G and B represents the birth of baby boy and baby girl.
b) Since, birth become independent so P( B) = P( G) = 0.5. Using multiplcation rule, the probability for each of the simple events, P( G) = 0.5
P( BG) = P( B) P(G) = 0.25
P( BBG) = P(B)× P(B)× P(G) = 0.125
P( BBBG) = P(B)× P(B)× P(B) ×P(G)
= 0.0625
P( BBBB) = P(B)× P(B)× P(B) ×P(B)= 0.0625
c) Let X be a variable such that it denotes number of children. So, X can take value from set { 1,2,3,4}.
The probability of a girl child is for each birth = 0.5
Therefore, P( X = 1) = { only 1 girl} = P( G)
= 0.5
P(X = 2) = { one boy and one girl } = P( BG) = P(B) P(G) = 0.25
P( X = 3) = { two boys one girl } = P( BBG) = 0.125
P( X = 4) = { three boys one girl or four all boys } = P( BBBG) + P( BBBB) = 0.0625 + 0.0625
= 0.125
So, the above values of probability distribution function for random variable X.
d) A table form picture of the probability distribution function for X is present in above figure. Hence, the required table is known.
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a) option 4-t test for one mean.
b) Null hypothesis: μ_Shadyside - μ_Oakland <= 0 (Mean monthly rent of apartments in Shadyside is not higher than in Oakland).
Alternative hypothesis: μ_Shadyside - μ_Oakland > 0 (Mean monthly rent of apartments in Shadyside is higher than in Oakland).
a) The most appropriate statistical test for this scenario would be (vi) test for two independent means, also known as two-sample t-test. This test is used to compare the means of two independent samples to determine if they are significantly different from each other. In this case, we are comparing the mean monthly rent of apartments in Shadyside and Oakland, and we have two independent samples.
b) The appropriate hypotheses for the two-sample t-test are as follows:
Null hypothesis: The mean monthly rent of apartments in Shadyside is equal to the mean monthly rent of apartments in Oakland.
Alternative hypothesis: The mean monthly rent of apartments in Shadyside is greater than the mean monthly rent of apartments in Oakland.
Symbolically, the null hypothesis can be represented as H0: µ1 = µ2, where µ1 and µ2 represent the population means of monthly rent in Shadyside and Oakland, respectively.
The alternative hypothesis can be represented as Ha: µ1 > µ2, indicating that the population mean of monthly rent in Shadyside is greater than the population mean of monthly rent in Oakland
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Which of the following numbers is a factor of
63
6363?
Choose 1 answer:
Choose 1 answer:
(Choice A)
6
66
A
6
66
(Choice B)
3
33
B
3
33
(Choice C)
8
88
C
8
88
(Choice D)
2
22
D
2
2
The only number that is a factor of 63 and 6363 is option B: 3, while the other options are not factors
What is the scale factor?A scale factor is defined as the ratio between the scale of a given original object and a new object, which is its representation but of a different size (bigger or smaller).
According to the given information:To determine which of the given numbers is a factor of 63 or 6363, we need to check if they divide the given numbers without leaving any remainder.
Option A: 6
63 ÷ 6 = 10 remainder 3
6363 ÷ 6 = 1060 remainder 3
Since both calculations leave a remainder of 3, 6 is not a factor of 63 or 6363.
Option B: 3
63 ÷ 3 = 21
6363 ÷ 3 = 2121
Since both calculations give a whole number without any remainder, 3 is a factor of 63 and 6363.
Option C: 8
63 ÷ 8 = 7 remainder 7
6363 ÷ 8 = 795 remainder 3
Since both calculations leave a remainder, 8 is not a factor of 63 or 6363.
Option D: 2
63 ÷ 2 = 31.5
6363 ÷ 2 = 3181.5
Since both calculations give a non-integer result, 2 is not a factor of 63 or 6363.
Therefore, the only number that is a factor of 63 and 6363 is option B: 3, while the other options are not factors
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A large company put out an advertisement in a magazine for a job opening. The first day the magazine was published the company got 120 responses, but the responses were declining by 10% each day. Assuming the pattern continued, how many total responses would the company get over the course of the first 18 days after the magazine was published, to the nearest whole number?
The company would get a total of 1200 responses over the course of the first 18 days after the magazine was published, to the nearest whole number.
What is meant by days?
Days refer to the 24-hour period of time that is based on the rotation of the Earth on its axis. It is a unit of time commonly used in calendars, schedules, and daily life.
Explain whole numbers
Whole numbers are positive integers including zero. They are used to count and represent quantities of discrete objects or entities in mathematics.
According to the given information
The sum of the first n terms of a geometric sequence with first term a and common ratio r is given by the formula S_n = a(1 - rⁿ)/(1 - r).
In this case, we want to find the sum of the first 18 terms of the sequence, so n = 18. Substituting the values for a, r, and n into the formula for S_n, we get:
S_18 = 120(1 - 0.9¹⁸)/(1 - 0.9)
≈ 1200
So the company would get a total of 1200 responses over the course of the first 18 days after the magazine was published, to the nearest whole number.
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The bases of a right prism are parallelograms with sides a=10 cm, b=6 cm. The altitude of the parallelogram towards side a is ha = 3 cm. Find the surface area of the parallelepiped if the height of the prism is h=12 cm.
The solution is, the surface area of the parallelepiped is:444 cm²
Here, we have,
Area of parallelogram = a*h
= 10*3
= 30 ,
there are 2 such parallelograms in the prism
2 faces are rectangles with sides 12 and 6 ,
Area of this face is 12*6=72, there are 2 such faces
we have,
2 faces are rectangles with sides 12 and 10
Area of this face is 12*10=120,
there are 2 such faces
the surface area of the parallelepiped is:
2*30+2*72+2*120
= 444 cm²
Hence, The solution is, the surface area of the parallelepiped is:444 cm²
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What is the domain of h?
A coordinate plane. The x- and y-axes both scale by one. The graph of the function h starts at the point negative seven, negative three and has a line segment to negative four, zero. Then it increases at a non linear rate to zero, four and decreases at a non linear rate to four, zero. A line segment connects four, zero to seven, negative three, which is plotted on the graph.
Choose 1 answer:
Choice A: -7 ≤ x ≤ 7
Choice B: -3 ≤ x ≤ 4
Choice C: The x-values -7, -4, 0, 4, and 7
Choice D: The x-values -3, 0, and 4
Answer:
The domain of h is
[tex] - 7 \leqslant x \leqslant 7[/tex]
Choice A is correct.
Answer:
c
Step-by-step explanation:
Choose ALL answers that describe
The answer choices which fit into the descriptions as given in the task content are; Squares and Rhombus.
Which answer choices describe the given quadrilateral?It follows from the task content that the given quadrilateral is such that; FG || HI, GH || IF and FH = GI. However, since the diagonals are perpendicular.
Consequently, it can be inferred that the diagonals of squares and Rhombuses are perpendicular. On this note, the shapes which best align with the given descriptions are; Square and Rhombus.
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DUE FRIDAY PLEASE HELP WELL WRITTEN ANSWERS ONLY!!!!
Use the following information to answer questions 2, 3, and 4:
A study of 1,000 people aged 20–30 asked how much television each person watches each night and how each person would rate their energy level in the evenings. The study showed that people who watch television for at least 2 hours every night have lower energy in the evening than people who do not watch as much television.
2. Is this study a survey, observational study, or experimental study? Explain your reasoning
3. Does this mean that watching television for at least 2 hours every night lowers energy in the evening? Explain your reasoning.
4. If you were to do your own experiment to determine if watching television for at least 2 hours every night lowers energy in the evening, how would you set up the experiment?
Based on the information, we can answer the questions as follows:
2. This study is an observational study. The researchers did not manipulate any variables or assign participants to groups, they simply observed and recorded the behavior and characteristics of the participants.3. The study shows an association between watching television for at least 2 hours every night and lower energy in the evening. However, correlation does not imply causation. There could be other factors that are affecting both the amount of television watched and energy levels, and it is possible that these factors, rather than television watching, are responsible for the observed lower energy levels.4. This questions asks how an experiment can be set up to determine whether watching television for at least 2 hours every night actually causes lower energy levels in the evening. The answer suggests that a randomized experimental study would need to be conducted, with participants randomly assigned to a group that watches at least 2 hours of television each night, and another group that does not watch as much television. What is a experimental study?An experimental study is a research design in which the researcher manipulates one or more independent variables and measures the effects of those manipulations on one or more dependent variables, while controlling for other potentially relevant factors (known as extraneous variables).
Therefore, he goal of an experimental study is to establish a cause-and-effect relationship between the independent variable(s) and the dependent variable(s).
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Part A: Is the probability of hitting the black circle inside the target closer to 0 or 1? Explain your answer and show your work. (5 points)
Part B: Is the probability of hitting the white portion of the target closer to 0 or 1? Explain your answer and show your work. (5 points)
The probability of hitting the black circle inside the target is approximately 0.0314.
The probability of hitting the white portion of the target is approximately 0.686.
What is the probability?Part A:
The black circle has a diameter of 2 units, which means it has a radius of 1 unit. The area of the circle is πr^2, which is π(1)^2 or π square units. The area of the white square is 10 x 10 or 100 square units.
The probability of hitting the black circle inside the target is the ratio of the area of the circle to the area of the square, which is π/100 or approximately 0.0314. This probability is closer to 0 because the circle is much smaller than the square, and the likelihood of hitting the exact center of the circle is low.
Part B:
The white portion of the target is the area of the square minus the area of the black circle, which is 100 - π square units.
The probability of hitting the white portion of the target is the ratio of the area of the white portion to the area of the square, which is (100-π)/100 or approximately 0.686.
This probability is closer to 1 because the white portion of the target is much larger than the black circle, and there are many possible areas of the square that could be hit.
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a random sample of 50 medical school applicants at a university has a mean raw score of 31 on the multiple choice portions of the medical college admission test (mcat). a student says that the mean raw score for the school's applicants is more than 30. assume the population standard deviation is 2.5. use a 1% level of significance. is there enough evidence to support the student's claim?
There is enough proof that the mean raw score for the school's applicants is more than 30 at a significance level of α = 0.01, therefore we reject the null hypothesis.
The null hypothesis H0: μ ≤ 30 mean raw score for the school's applicants is less than or equal to 30 and the alternative hypothesis Ha: μ > 30
We can utilize a one-tailed t-test since we don't know the population standard deviation and our sample size is less than 30. The test statistic is evaluated
t = (x' - μ) / (s / √n)
here
x'= sample mean = 31,
μ = hypothesized population mean = 30,
s = standard deviation = 2.5,
n = sample size = 50.
t = (31 - 30) / (2.5 / √50)
= 3.16
Applying t-distribution table with degrees of freedom (df) = n - 1 = 49 and a significance level of α = 0.01, we find that the critical value is
t-critical = 2.404.
The calculated t-value (3.16) is greater than our critical value (2.404), we reject the null hypothesis since there is enough evidence to support the student's claim that the mean raw score for the school's applicants is more than 30 at a significance level of α = 0.01.
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after answering the question can you please show ur work
The values of x and y for the tangent segments to the circle A are: 4 and 8.899 respectively.
What are the segments tangent to the circleA theorem of tangents to a circle states that if from one exterior point, two tangents are drawn to a circle then they have equal tangent segments.
KJ = K L
6x - 3 = 5x + 1
6x - 5x = 1 + 3 {collect like terms}
x = 4
IJ = IH = 11
y² - 10 = 4y + 2
y² - 4y - 2 - 10 = 0
y² - 4y - 8 = 0 {quadratic equation}
using the quadratic formula
y = 8.899 or y = -0.898
Therefore, the values of x and y for the tangent segments to the circle A are: 4 and 8.899 respectively.
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Question 2
Mike deposited $3,000 in the first year of a retirement account, and then increased the deposits by $300 each year. The account earned 8.35%. What was the account value after forty years?
The account value after forty (40) years is approximately $2,789,525.
Here is how to solve for the account valueWe can use the formula for future value of an annuity to solve this problem:
FV = PMT * ((1 + r)^n - 1) / r
where FV is the future value, PMT is the annual deposit amount, r is the annual interest rate, and n is the number of periods (years in this case).
For the first year, the deposit amount is $3,000, so:
FV1 = 3000 * (1 + 0.0835)^40 = $65,470.22
For the subsequent years, the deposit amount increases by $300, so:
PMT = 3000 + 300 + 300 + ... = 3000 + 300 * 39 = $15,300
Using this value for PMT, we can calculate the future value for the remaining 39 years:
FV2 = 15300 * ((1 + 0.0835)^39 - 1) / 0.0835 = $2,724,054.54
Adding the two future values together, we get the total account value after forty years:
FV = FV1 + FV2 = $2,789,524.76
Therefore, the account value after forty years is approximately $2,789,525.
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Consider the sequence -3, -10, -17, -24, -31, ...
(ii) Find, in terms of n, a formula for the nth term of the sequence.
Answer:
-60
Step-by-step explanation:
1.572 × 108 troy oz of silver were used in the United States in 1980. How manykilograms is this? (1 troy oz = 31.1 g)A) 4.89 × 106 kg D) 4.89 x 1012 kgB) 4.89 kg E) 5.05 × 10 3 kgC) 5.05 × 10 6 kg
E. Which number line represents the solution to the inequality 3x-8≥7?
A
B
с
D
-10 -8 -6
-4-2
-10 -8
0 2 4 6 8
-8 -6 -4 -2 0 2 4
-6 -4 -2 0 2
+44
6 8
4 6 8
-10 -8 -6 -4 -2 0 2 4 6 8
10
10
10
10
The number line that represents the solution to the inequality 3x-8≥7 is shown on the attached image.
how to find which number line represents the solution to the inequality 3x-8≥7?The inequality: 3x - 8 ≥ 7
Add 8 to both sides
3x ≥ 7 + 8
Add 7 and 8 to get 15
3x ≥ 15
Divide both sides by 3
3x/3 ≥ 15/3
x ≥ 5
What is an inequality?An inequality is a mathematical statement that compares two values or expressions, indicating whether they are equal or not. Unlike equations, which are true only if the two sides are equal, inequalities may be true for different values on either side of the inequality sign.
Inequalities are often represented using symbols such as < (less than), > (greater than), ≤ (less than or equal to), and ≥ (greater than or equal to).
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You may need to use the appropriate appendix table or technology to answer this question. The following results come from two independent random samples taken of two populations. Sample 1 Sample 2 ni = 50 n2 = 35 = X1 13.6 x2 = 11.6 0 1 = 2.4 02 3 (a) What is the point estimate of the difference between the two population means? (Use x1 - xz.) 2 (b) Provide a 90% confidence interval for the difference between the two population means. (Use X2 Round your answers to two decimal places.) 0.98 X to 3.02 x - X2. Round your answers to two decimal places.) (C) Provide a 95% confidence interval for the difference between the two population means. (Use X X to 3.21 x 0.79
The appendix table the point estimate of the difference between the two population means is 2
The difference between the two population means, we need to find the standard error of the difference and use the t-distribution with (n1 + n2 - 2) degrees of freedom. The formula for the standard error of the difference is:
SE = sqrt[ (s1 / n1) + (s2 / n2) ]
Substituting the given values, we get:
SE = sqrt[ (2.4 / 50) + (3 / 35) ] = 0.617
Using a t-distribution with 83 degrees of freedom (50 + 35 - 2), and a 90% confidence level, we find the t-value to be 1.66 (from the t-table or calculator). Therefore, the 90% confidence interval is:
x1 - x2 ± t(α/2) * SE
= 2 ± 1.66 * 0.617
= 0.98 to 3.02
So, we can say with 90% confidence that the true difference between the two population means lies between 0.98 and 3.02.
To calculate the 95% confidence interval:
x1 - x2 ± t(α/2) * SE
= 2 ± 2.00 * 0.617
= 0.79 to 3.21
So, we can say with 95% confidence that the true difference between the two population means lies between 0.79 and 3.21.
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Estimate the difference. 9 1/2 - 1 6/7
8 1/2
7 1/2
7
8
Answer:
1 6/7 is about 2, so 9 1/2 - 1 6/7 is about
7 1/2.
suppose that one customer who participated in the study is chosen at random. what is the probability that the customer did not have a high level of satisfaction with the company?
Answer: Without additional information about the study and the definition of "high level of satisfaction," we cannot determine the probability that a randomly chosen customer did not have a high level of satisfaction with the company.
The probability would depend on the specific criteria used to define a high level of satisfaction, as well as the distribution of satisfaction levels among the customers in the study.
If we have access to this information, we could use it to calculate the probability that a randomly chosen customer did not have a high level of satisfaction using the appropriate formulas or statistical techniques.
Step-by-step explanation:
Farm joe ordered 3 bags of soil last month. Each bag weighed 4 2/5 kilograms. He used the first bag in a week. At the end of this month, there were 2 3/4 kilograms of soil left in the second bag and 7/8 kilograms of soil left in the third bag. How much soil was used in this month?
Farm Joe used [tex]7\frac{6}{15}[/tex] kg of soil in this month.
How Farm Joe uses his weightThe total weight of soil that Farm Joe ordered was:
3 bags x 4 2/5 kg/bag = 12 6/15 kg = 12 2/5 kg
The weight of the first bag used was 4 2/5 kg.
The weight of the second bag remaining is 2 3/4 kg.
The weight of the third bag remaining is 7/8 kg.
The total weight of soil used in this month can be found by subtracting the weight of the second and third bags remaining from the total weight of soil ordered:
12 2/5 kg - 2 3/4 kg - 7/8 kg
Converting all fractions to fifteenths:
12 8/15 kg - 5 1/15 kg - 1/15 kg = 7 6/15 kg
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y=|x| translated one unit downward pls help
To translate the function y = |x| one unit value downward, we need to subtract 1 from the function: y = |x| - 1.
The function y = |x| is a V-shaped graph that passes through the origin and has a slope of 1 on both sides. It represents the absolute value of x, which means that the function always returns a positive value regardless of whether x is positive or negative.
To translate the function one unit downward, we need to subtract 1 from the function. This means that for any given value of x, the function will return the absolute value of x minus 1. For example, if x = 2, then y = |2| - 1 = 1. If x = -2, then y = |-2| - 1 = 1.
The resulting graph of y = |x| - 1 is still a V-shaped graph, but it is shifted down by one unit compared to the graph of y = |x|.
Thus, the slope of the graph remains the same on both sides, but the minimum value of y is now -1 instead of 0.
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Mehnaj has a set of blocks that are all the same hight the cone-shaped block has a volume of 125 cubic inches the sphere--shaaped block has a volume of 250 cubic inches what do you know about the raduis of the base of the cone-shaped block explain?
The radius of the base of the cone-shaped block is approximately 10.69 inches.
To solve this problemWe can use the formula for the volume of a cone to find the radius of its base. The volume of a cone is given by the formula :
V = (1/3)πr^2h
Where
V is the volume r is the radius of the baseh is the heightWe know that the volume of the cone-shaped block is 125 cubic inches, and we know the height is the same for all blocks. So we can solve for the radius:
125 = (1/3)πr^2h
125 = (1/3)πr^2h
375 = πr^2h
r^2 = 375/π
r ≈ 10.69
So we can conclude that the radius of the base of the cone-shaped block is approximately 10.69 inches.
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monthly sales are independent normal random variables with mean and standard deviation a. find the probability that exactly of the next months have sales greater than 100. b. find the probability that the total of the sales in the next
Answer: We can use the properties of the normal distribution to solve both parts of this problem.
a) The number of months with sales greater than 100 is a binomial random variable with parameters n = the number of months and p = the probability of a single month having sales greater than 100. Since each month is an independent normal random variable, we can use the standard normal distribution to find this probability. Let X be the number of months with sales greater than 100. Then:
X ~ Binomial(n, p)
where n is the number of months and p is given by:
p = P(X_i > 100) = P(Z > (100 - a) / a)
where Z is a standard normal random variable.
Using the binomial probability formula, the probability of exactly k months having sales greater than 100 is:
P(X = k) = (n choose k) * p^k * (1 - p)^(n - k)
So the probability of exactly 3 months having sales greater than 100 is:
P(X = 3) = (n choose 3) * p^3 * (1 - p)^(n - 3)
= (12 choose 3) * P(Z > (100 - a) / a)^3 * [1 - P(Z > (100 - a) / a)]^(12 - 3)
b) The total sales in the next 12 months is a normal random variable with mean 12a and standard deviation sqrt(12)a. Let Y be the total sales in the next 12 months. Then:
Y ~ Normal(12a, sqrt(12)a)
The probability of the total sales being greater than some value x can be found by standardizing Y and using the standard normal distribution:
P(Y > x) = P((Y - 12a) / (sqrt(12)a) > (x - 12a) / (sqrt(12)a))
= P(Z > (x - 12a) / (sqrt(12)a))
where Z is a standard normal random variable. So the probability of the total sales in the next 12 months being greater than 1500 is:
P(Y > 1500) = P(Z > (1500 - 12a) / (sqrt(12)a))
Step-by-step explanation:
Can someone help me a little so I can learn this
Answer:b
Step-by-step explanation:
Answer:
b and c
Step-by-step explanation:
b 5(7+6s—9t)
35+30s—45
c 10×(3.5+3s—4.5t)
10×3.5 +10×3s—10×4.5t
35+30s—45t
What is the solution to the following graph? PLEASE HELP ITS URGENT!!!
The solution shown in the graph is (-4, 0)
What is the solution of the graph?Here we have a system of equations graphed, the solutions of the system are all the points where the graphs of the functions (lines in this case) do intercept.
Then, in this case the solution is where the lines red and blue intercept, that happens at the point (-4, 0).
So that is the solution of the system of equations.
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It's a math problem about graphing. thank you
The interval for which the ball's height is increasing on the graph, would be 0 seconds to 1.5 seconds.
What is the interval the ball's height increases ?The interval for which the ball's height is increasing is when the slope of the graph is positive, or when the height is increasing with respect to time.
Looking at the graph, we can see that the ball starts at a height of 0 meters and reaches a peak of 11.025 meters at 1.5 seconds. After 1.5 seconds, the ball begins to fall back to the ground.
Therefore, the interval for which the ball's height is increasing is from 0 seconds to 1.5 seconds. During this interval, the height of the ball is increasing as it travels upwards, reaching its peak at 1.5 seconds. After 1.5 seconds, the height of the ball starts decreasing as it falls back down to the ground.
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An adiabatic process is one in which the:
-temperature remains constant.
-pressure on the air parcel remains constant.
-altitude of the air parcel remains constant.
-work done is zero.
-heat exchanged with the surroundings is zero.
An adiabatic process is one in which the heat transered between a system and its surroundings is equal to zero( q = 0 ). So, option(e) right one.
In thermodynamics, the adiabatic process is a process in which there is no heat or air exchange between the temperature and the environment. It is different from the isothermal heat flow process. Some important properties are :
In case of adiabatic compression (Q=0) of gas, work is done on it and its temperature increases. In case of adiabatic expansion of gas work done by it and its temperature decreases. That is temperature not constant. Pressure does not remain constant during an adiabatic process and it changes along with Volume.There is a thermodynamic change but no heat is exchanged between a system and its surroundings.Hence, option(e) is right answer.
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Question 14(Multiple Choice Worth 2 points)
(Creating Graphical Representations MC)
A random sample of 100 middle schoolers were asked about their favorite sport. The following data was collected from the students.
Sport Basketball Baseball Soccer Tennis
Number of Students 17 12 27 44
Which of the following graphs correctly displays the data?
histogram with the title favorite sport and the x axis labeled sport and the y axis labeled number of students, with the first bar labeled basketball going to a value of 17, the second bar labeled baseball going to a value of 12, the third bar labeled soccer going to a value of 27, and the fourth bar labeled tennis going to a value of 44
histogram with the title favorite sport and the x axis labeled sport and the y axis labeled number of students, with the first bar labeled baseball going to a value of 17, the second bar labeled basketball going to a value of 12, the third bar labeled tennis going to a value of 27, and the fourth bar labeled soccer going to a value of 44
bar graph with the title favorite sport and the x axis labeled sport and the y axis labeled number of students, with the first bar labeled basketball going to a value of 17, the second bar labeled baseball going to a value of 12, the third bar labeled soccer going to a value of 27, and the fourth bar labeled tennis going to a value of 44
bar graph with the title favorite sport and the x axis labeled sport and the y axis labeled number of students, with the first bar labeled baseball going to a value of 17, the second bar labeled basketball going to a value of 12, the third bar labeled tennis going to a value of 27, and the fourth bar labeled soccer going to a value of 44
The correct graph for the given data is given by option The bar graph x axis labeled sport and the y axis labeled number of students, with each having value as basketball -17, baseball-12, soccer - 27, and tennis - 44.
Which graph represents the given data?Because the data shows discrete categories (sports) and their related frequencies, the correct graph is a bar graph (number of students).
The x-axis is to be named "Sports" to represent the various sports (Basketball, Baseball, Soccer, and Tennis), and the y-axis has to be labelled "Number of Students" to reflect the frequency. The graph's bars will show the frequency of each sport, with the heights of the bars giving the number of students who identified each sport as their favourite. The right values for the bars should be based on the data provided:
[tex]Basketball: 17\\Baseball: 12\\Soccer: 27\\Tennis: 44[/tex]
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A method of assigning probabilities based on historical data is called the
A method of assigning probabilities based on historical data is called the Empirical Probability method.
Empirical probability refers to the probability of an event based on observed data or past experience.
It is also known as experimental probability because it is determined through experimentation or observation.
This approach involves analyzing past events and their outcomes to calculate the probability of a particular event happening in the future.
To calculate empirical probability, you can use the formula:
Empirical Probability = (Number of successful outcomes) / (Total number of outcomes)
In this method, you collect and analyze historical data to make predictions about future events.
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