Answer: the answer si b . form detail
Explanation
Answer:
the answer is b . form detail
Explanation:
Write a program that lets a maker of chips and salsa keep track of sales for five different types of salsa: mild, medium, sweet, hot, and zesty. The program should use two parallel 5-element arrays: an array of strings that holds the five salsa names and an array of integers that holds the number of jars sold during the past month for each salsa type. The salsa names should be stored using an initialization list at the time the name array is created. The program should prompt the user to enter the number of jars sold for each type. Once this sales data has been entered, the program should produce a report that displays sales for each salsa type, total sales, and the names of the highest selling and lowest selling products.
Answer:
The program in Java is as follows:
import java.util.*;
public class Main{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String [] salsa = {"Mild","Medium","Sweet","Hot","Zesty"};
int [] number = new int[5];
for(int i = 0;i<5;i++){
System.out.print(salsa[i]+" number: ");
number[i] = input.nextInt();
}
for(int i = 0;i<5;i++){
System.out.println(salsa[i]+" : "+number[i]);
}
int smallest = number[0]; int highest = number[0];
int count = 0;
for(int i = 0;i<5;i++){
if(smallest > number[i]){
smallest = number[i];
count = i;
}
}
System.out.println("Smallest");
System.out.println(salsa[count]+" : "+smallest);
for(int i = 0;i<5;i++){
if(highest < number[i]){
highest = number[i];
count = i;
}
}
System.out.println("Highest");
System.out.println(salsa[count]+" : "+highest);
}
}
Explanation:
This initializes the salsa names
String [] salsa = {"Mild","Medium","Sweet","Hot","Zesty"};
This declares the array for the amount of salsa
int [] number = new int[5];
This iterates through the 5 salsas and get input for the amount of each
for(int i = 0;i<5;i++){
System.out.print(salsa[i]+" number: ");
number[i] = input.nextInt();
}
This prints each salsa and the amount sold
for(int i = 0;i<5;i++){
System.out.println(salsa[i]+" : "+number[i]);
}
This initializes smallest and largest to the first array element
int smallest = number[0]; int highest = number[0];
This initializes the index of the highest or lowest to 0
int count = 0;
The following iteration gets the smallest of the array elements
for(int i = 0;i<5;i++){
if(smallest > number[i]){
smallest = number[i];
This gets the index of the smallest
count = i;
}
}
This prints the smallest
System.out.println("Smallest");
System.out.println(salsa[count]+" : "+smallest);
The following iteration gets the largest of the array elements
for(int i = 0;i<5;i++){
if(highest < number[i]){
highest = number[i];
This gets the index of the highest
count = i;
}
}
This prints the highest
System.out.println("Highest");
System.out.println(salsa[count]+" : "+highest);
A function checkZeros accepts three double parameters. It checks to see if the sum of all three parameters is equal to zero. If this sum is equal zero, the function returns true, otherwise the function returns false. 1. Give an example CALL from main: 2. Write the prototype for the function: 3. Write down the definition (header and body) for the function.
Answer:
Explanation:
The following code is written in Java. It creates the interface/prototype, the function, and the main method call. The function takes in the three int parameters, adds them, and then checks if the sum equals zero, outputting the correct boolean value. Output can be seen in the picture attached below. Due to technical difficulties I had to add the code as a txt file below.
answer any one: write a computer program:which you know.
hope this helps you.look it once
A new school is being built in the local school district.It will have three computer labs with 28 computers each. There will be 58 classrooms with 2 computers each that need to be on one sub-subnet.The office staff and administrators will need 7 computers. The guidance and attendance office will have 5 computers. The school has been given the address 223.145.75.0/24. Subnets are assigned from largest to smallest. Everything is based on the number of usable hosts.
Complete the information required below.
Subnet Subnet Mask (/X) Subnet First Usable Last Usable Broadcast
Address Host Host Address
1
2
3
4
5
6
7
Answer:
Following are the responses to the given question:
Explanation:
The subnet mask /25 could be the host 128 hosts.
The subnet mask /26 could be the host 64 hosts.
The subnet mask /27 could be the host 32hosts.
The subnet mask /28 could be the host 16 hosts.
The subnet mask /29 could be the host 8 hosts.
The subnet mask /30 could be the host 4 hosts.
It is based on the requirement in which I have been using /25,/27,/28,/29 subnet masks on the basis of the usable slots.
Which statement best describes Link State routing? Group of answer choices Each router builds a cost-weighted graph of the network of all the routers and the shortest links between them, based on information received from each router regarding only its nearest neighbors All of these Each router uses a HELLO packet to announce its presence to its neighbors Each router builds a table with the best distance between each router and the link to use, based on each router’s providing data on distances to all the routers in its routing table to its nearest neighbors
Answer:
Each router builds a cost-weighted graph of the network of all the routers and the shortest links between them, based on information received from each router regarding only its nearest neighbors.
Explanation:
A routing protocol can be defined as a set of defined rules or algorithms used by routers to determine the communication paths unto which data should be exchanged between the source router and destination or host device.
Additionally, in order for packets to be sent to a remote destination, these three parameters must be configured on a host.
I. Default gateway
II. IP address
III. Subnet mask
After a router successfully determines the destination network, the router checks the routing table for the resulting destination network number. If a match is found, the interface associated with the network number receives the packets. Else, the default gateway configured is used. Also, If there is no default gateway, the packet is dropped.
Basically, there are two (2) main categories of routing protocols used in packet switching networks and these includes;
1. Distance-vector routing.
2. Link state routing.
Link state routing refers to a complex routing technique in which each router learns about it's own neighborhood or directly connected networks (links) and shares the information with every other router present in the network.
Hence, the statement which best describes Link State routing is that, each router builds a cost-weighted graph of the network of all the routers and the shortest links between them, based on information received from each router regarding only its nearest neighbors. Some examples are intermediate system to intermediate system (IS-IS) and open shortest path first (OSPF).
Research and build a chroot jail that isolates ssh users who belong to the restrictssh group. (You will also need to create the restrictssh group). Next, install an ftp server and configure it to allow anonymous logins. Create a second chroot jail that can be accessed by the anonymous account. You will probably need to create several new user accounts to facilitate testing your setups.
Answer:
Explanation:
#!/bin/bash
# This script can be used to create simple chroot environment
# Written by LinuxConfig.org
# (c) 2020 LinuxConfig under GNU GPL v3.0+
#!/bin/bash
CHROOT='/var/chroot'
mkdir $CHROOT
for i in $( ldd $* | grep -v dynamic | cut -d " " -f 3 | sed 's/://' | sort | uniq )
do
cp --parents $i $CHROOT
done
# ARCH amd64
if [ -f /lib64/ld-linux-x86-64.so.2 ]; then
cp --parents /lib64/ld-linux-x86-64.so.2 /$CHROOT
fi
# ARCH i386
if [ -f /lib/ld-linux.so.2 ]; then
cp --parents /lib/ld-linux.so.2 /$CHROOT
fi
echo "Chroot jail is ready. To access it execute: chroot $CHROOT"
is used for finding out about objects, properties and methods
Answer:
science
Explanation:
Which of the following is the cause of transmission impairment?
Select one:
O Frequency
O Amplitude
O Attenuation
O Phase
Answer:
attenuation is the third one
Design a Python3 function to compare every prefix of a string X to every element of string Y, if there is a match, place it in a python set, sort and reversely sort the set, and return the sorted and reversely sorted sets.
Answer:
The function is as follows:
def compare_prefix(strX,strY):
prefix=set()
for i in range(len(strX)):
for j in range(i+1,len(strX)):
chk =strX[i:j+1]
if chk in strY:
prefix.add(chk)
sort_prefix = sorted(prefix)
rev_sort_prefix = sorted(prefix,reverse=True)
return(sort_prefix,rev_sort_prefix)
Explanation:
This defines the function
def compare_prefix(strX,strY):
This creates an empty set, prefix
prefix=set()
This iterates through each character in strX
for i in range(len(strX)):
This iterates through every other character in strX
for j in range(i+1,len(strX)):
This gets the prefix of strX by concatenating strings from i to j + 1
chk =strX[i:j+1]
This checks if the prefix is in strY
if chk in strY:
If yes, the string is added to set prefix
prefix.add(chk)
This sorts prefix
sort_prefix = sorted(prefix)
This reverses the sorted prefix
rev_sort_prefix = sorted(prefix,reverse=True)
This returns the sorted and reversed prefix
return(sort_prefix,rev_sort_prefix)
Your company has a benchmark that is considered representative of your typical applications. One of the older-model workstations does not have a floating-point unit and must emulate each floating-point instruction by a sequence of integer instructions. This older-model workstation is rated at 120 MIPS on this benchmark. A 3rd -party vendor offers an attached processor that is intended to give a hardware accelerator to your workstation. The attached processor executes each floating-point instruction on a dedicated processor, without emulation. The workstation/attached processor rates 80 MIPS on the same benchmark. The following symbols are used to answer this exercise:
I – Number of integer instructions executed on the benchmark
F – Number of floating-point instructions executed on the benchmark
Y – Number of integer instructions to emulate a float-point instruction
W – Time to execute the benchmark on the processor alone
B – Time to execute the benchmark on the processor/coprocessor combination.
Required:
a. Write an equation for the MIPS rating of each configuration using the symbols above.
b. What is the value of B?
c. What is the MFLOPS rating of the system with the coprocessor?
d. Your colleague wants to purchase the coprocessor even though the MIPS rating for the configuration using the coprocessor is less than that of the processor alone. Is your colleague’s evaluation correct?
Answer:
a-The equation for processor only configuration is [tex]120\times 10^6=\dfrac{I+YF}{W}\\[/tex] while that for processor and co-processor configuration is [tex]80\times10^6=\dfrac{I+F}{B}[/tex].
b-The value of B is 1.1 second.
c-The value of MFLOPS for co-processor system in configuration 2 is 80 MFLOPS.
d-The evaluation of your colleague is correct.
Explanation:
a
The MIPS rating equations are as follows
Configuration 01 (Processor only)
[tex]120\times 10^6=\dfrac{I+YF}{W}\\[/tex]
Configuration 02 (Processor + Co-processor)
[tex]80\times10^6=\dfrac{I+F}{B}[/tex]
b
From the equation, for processor and co-processor equation the value of B is calculated. For it to be calculated, the I value is calculated from the processor configuration with the following data F= 8 * 10^6 . Y= 50, W = 4 sec:
[tex]I=120\times10^6\timesW-YF\\I=(120\times10^6\times4)-(8\times10^6\times50)\\I=80\times10^6 \text{instructions}[/tex]
Using this value of I gives
[tex]B=\dfrac{I+F}{80\times10^6}\\B=\dfrac{80\times10^6+8\times10^6}{80\times10^6}\\B=\dfrac{88\times10^6}{80\times10^6}\\B=1.1\text{second}[/tex]
The value of B is 1.1 second.
c
The MFLOPS rating of configuration 2 is given as
[tex]\text{MFLOPS}=\dfrac{F}{B-\dfrac{I}{MIPS_{proc+coproc}}}\\\text{MFLOPS}=\dfrac{8\times10^6}{1.1-\dfrac{80\times10^6}{80\times10^6}}\\\text{MFLOPS}=\dfrac{8\times10^6}{1.1-1}\\\text{MFLOPS}=\dfrac{8\times10^6}{0.1}\\\text{Processor+Coprocessor MFLOPS}=80 \text{MFLOPS}[/tex]
So the value of MFLOPS for co-processor system in configuration 2 is 80 MFLOPS.
d
The value of W is 4 seconds while the value of B is 1.1 seconds. Despite being the configuration with lower MIPS, the co-processor configuration has a lower execution rate and thus the evaluation of your colleague is correct.
NEED HELP IMMEDIATELY!!
Highlight the upsides and downsides of seeking online help for a technical problems.
Answer:
Pros: Experts are there to help, Help can be found almost 24 hours of the day so you don't have to wait for an expert to be available, easier to ask more in detail.
Cons: Answers may not always come quickly, there is no face to face interaction so you dont know how legit the person is, some advice may be incorrect or old.
Explanation:
One way to add a table to a presentation is to click on Clip Art under the Insert tab. click on WordArt under the Insert tab. right-click on an existing page with content and choose Add Table. add a new slide and left-click on the Table symbol in an empty area.
You have been given an encrypted copy of the Final exam study guide here, but how do you decrypt and read it???
Along with the encrypted copy, some mysterious person has also given you the following documents:
helloworld.txt -- Maybe this file decrypts to say "Hello world!". Hmmm.
hints.txt -- Seems important.
In a file called pa11.py write a method called decode(inputfile,outputfile). Decode should take two parameters - both of which are strings. The first should be the name of an encoded file (either helloworld.txt or superdupertopsecretstudyguide.txt or yet another file that I might use to test your code). The second should be the name of a file that you will use as an output file. For example:
decode("superDuperTopSecretStudyGuide.txt" , "translatedguide.txt")
Your method should read in the contents of the inputfile and, using the scheme described in the hints.txt file above, decode the hidden message, writing to the outputfile as it goes (or all at once when it is done depending on what you decide to use).
Hint: The penny math lecture is here.
Another hint: Don't forget about while loops...
Answer:
Explanation:
Describe how being a global citizen in the world of advanced technology can be beneficial to your success in meeting your personal, academic, and professional goals.
Answer:
well you could have more options of careers and more possibilities, online jobs can pay more and give more experience to the employees
SMTP (Simple Mail Transfer Protocol) is the standard protocol for transferring mail between hosts over TCP. A TCP connection is set up between a user agent and a server program. The server listens on TCP port 25 for incoming connection requests. The user end of the connection is on a TCP port number above 1023. Suppose you wish to build a packet filter rule set allowing inbound and outbound SMTP traffic. You generate the following rule set:
Rule Direction Src Addr Dest Addr Protocol Dest Port Action
A In External Internal TCP 25 Permit
B Out Internal External TCP >1023 Permit
C Out Internal External TCP 25 Permit
D In External Internal TCP >1023 Permit
E Either Any Any Any Any Deny
Required:
Describe the effect of each rule.
Answer:
The five rules are described as follows:
Rule A permits the inbound Simple Mail Transfer Protocol (SMTP) connection.
Rule B permits the inbound Simple Mail Transfer Protocol (SMTP) connection.
Rule C permits the outbound Simple Mail Transfer Protocol (SMTP) connection.
Rule D permits the outbound Simple Mail Transfer Protocol (SMTP) connection.
Rule E does not perform any action. Thus it is when the action is denied.
Explanation:
Rule A allows information transfer of the incoming email from the external server to the internal remote server, thus this allows an inbound connection.
Rule B allows information transfer of the incoming email from the remote server to the external remote server, thus this allows an inbound connection.
Rule C allows information transfer of outgoing email from the external server to the internal remote server, thus this allows an outbound connection.
Rule D allows information transfer of the outgoing email from the remote server to the external remote server, thus this allows an outbound connection.
Rule E does not allow any action in either direction thus it is when action is denied.
A field is a group of related records that can be identified by the user with a name, type, and size.
Answer: False
Explanation:
The statement that a field is referred to as a group of related records which can be identified by the user with a name, type, and size is wrong.
The above definition represents a table. The group of related records is referred to as a table. On the other hand, a field refers to a set of data values, which are of identical data type.
layers allow you to work with one element of an image without disturbing the others true or false
I think it is True not sure but try it
Which tab should you click if you want to access the Show All Comments option in a worksheet?
Home
Page Layout
Review
View
Answer: Review
Because you want to review the comments
Answer:
C.) Reivew
Explanation:
Doing it on EDG now!
Best luck to yall :3
Have a good day and byee
What is the function of a bread crumb trial in a website
Answer:
A “breadcrumb” (or “breadcrumb trail”) is a type of secondary navigation scheme that reveals the user's location in a website or Web application. The term comes from the Hansel and Gretel fairy tale in which the two title children drop breadcrumbs to form a trail back to their home.
Explanation:
A breadcrumb or breadcrumb trail is a graphical control element frequently used as a navigational aid in user interfaces and on web pages. It allows users to keep track and maintain awareness of their locations within programs, documents, or websites. Breadcrumbs make it easier for users to navigate a website – and they encourage users to browse other sections of the site. ... You head to their site and end up on The Nestle company history page. Using their breadcrumbs, you can easily navigate back to About Us, History, or even their home page.
A new school is being built in the local school district. It will have three computer labs with 28 computers each. There will be 58 classrooms with 2 computers each that need to be on one sub-subnet. The office staff and administrators will need 7 computers. The guidance and attendance office will have 5 computers. The school has been given the address 223.145.75.0/24.
Complete the information required below.
Subnet Subnet Mask (/X) Subnet Address First Usable Host Last Usable Host Broadcast Address
1
2
3
4
5
6
7
8
9
10
Answer:
The table is formed as attached figure.
Explanation:
Subnets can use specific number of hosts so /25 can host 128 hosts, reducing by a factor of 2 leading to /30 as with only 4 hosts. Thus the subnets are alloted as indicated in the attached image.
You want a cable that could be used as a bus segment for your office network. The cable should also be able to support up to 100 devices. Which cable should you use?
A.
RG-6
B.
RG-8
C.
RG-58U
D.
RG-59
Answer: C
Explanation:
Write a Perl program that uses a hash and a large number of operations on the hash. For example, the hash could store people’s names and their ages. A random- number generator could be used to create three- character names and ages, which could be added to the hash. When a duplicate name was generated, it would cause an access to the hash but not add a new element. Rewrite the same program without using hashes. Compare the execution efficiency of the two. Compare the ease of programming and readability of the two.
Answer:
The Perl code is attached in the attachment. The execution time for using hashes is 0 seconds while that for without hash is 27 seconds.
Explanation:
In terms of ease of access and readability, both approaches are similar. However, it is evident from the time of execution that the with hashes is more efficient than the value of without hashes. This indicates that using hashes is more efficient.
help meeeee pleaaaseee
Answer:
just drop out that the easiest solution
Write a program that lets the user perform arithmetic operations on fractions. Fractions are of the form a/b, in which a and b are integers and b is not equal to 0. Your program must be menu driven, allowing the user to select the operation ( , -, *, or /) and input the numerator and the denominator of each fraction. Furthermore, your program must consist of at least the following function
menu: This function informs the user about the program's purpose, explains how to enter data, how to quit and allows the user to select the operation.
addFractions: This function takes as input four integers representing the numerators and denominators of two fractions, adds the fractions, and returns the numerator and denominator of the result.
subtractFractions: This function takes as input four integers representing the numerators and denominators of two fractions, subtracts the fractions, and returns the numerator and denominator of the result.
multiplyFractions: This function takes as input four integers representing the numerators and denominators of two fractions, multiplies the fractions, and returns the numerator and denominator of the result.
divideFractions: This function takes as input four integers representing the numerators and denominators of two fractions, divides the fractions, and returns the numerator and denominator of the result.
Here are some sample outputs of the program:
3 / 4 +2 / 5 = 23 / 20
2 / 3 * 3 / 5 = 2 / 5
Answer:
Explanation:
The following code is written in Java, It asks the user to enter the numerator and denominator for both fraction 1 and 2. Then it prompts the user with a menu to choose the desired operation. The choice is passed into a switch statement and calls the correct function.
import java.util.Scanner;
class Brainly {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int num1, num2, den1, den2;
System.out.println("Enter numerator for fraction 1: ");
num1 = in.nextInt();
System.out.println("Enter denominator for fraction 1: ");
den1 = in.nextInt();
System.out.println("Enter numerator for fraction 2: ");
num2 = in.nextInt();
System.out.println("Enter denominator for fraction 2: ");
den2 = in.nextInt();
System.out.println("Menu:");
System.out.println("+ = add fractions");
System.out.println("- = subtract fractions");
System.out.println("/ = divide fractions");
System.out.println("* = multiply fractions");
String answer = in.next();
switch (answer.charAt(0)) {
case '+': add(num1, den1, num2, den2); break;
case '-': subtract(num1, den1, num2, den2); break;
case '*': multiply(num1, den1, num2, den2); break;
case '/': divide(num1, den1, num2, den2); break;
}
}
public static void add(int num1, int den1, int num2, int den2) {
int num3 = (num1 * den2) + (num2 * den1);
int den3 = den1 * den2;
System.out.println("New Fraction: " + num3 + " / " + den3);
}
public static void subtract(int num1, int den1, int num2, int den2) {
int num3 = (num1 * den2) - (num2 * den1);
int den3 = den1 * den2;
System.out.println("New Fraction: " + num3 + " / " + den3);
}
public static void divide(int num1, int den1, int num2, int den2) {
int num3 = num1 * den2;
int den3 = den1 * num2;
System.out.println("New Fraction: " + num3 + " / " + den3);
}
public static void multiply(int num1, int den1, int num2, int den2) {
int num3 = num1 * num2;
int den3 = den1 * den2;
System.out.println("New Fraction: " + num3 + " / " + den3);
}
}
The following code segment appears in a class other than Backyard. It is intended to print true if b1 and b2 have the same lengths and widths, and to print false otherwise. Assume that x, y, j, and k are properly declared and initialized variables of type int.
Backyard b1 = new Backyard(x, y);
Backyard b2 = new Backyard(j, k);
System.out.println( /* missing code */ );
Which of the following can be used as a replacement for /* missing code */ so the code segment works as intended?
a. b1 == b2
b. b1.equals(b2)
c. equals(b1, b2)
d. b1.equals(b2.getLength(), b2.getWidth())
e. b1.length == b2.length && b1.width == b2.width
Answer:
b. b1.equals(b2)
Explanation:
The question has a missing source file (which can be found online).
The function that compares b1 and b2 is:
public boolean equals(Object other) {
if (other == null) {
return false; }
Backyard b = (Backyard) object;
return (length == b.getLength() && width == b.getWidth());
}
Using the function definition, we have:
equals(Object other)
This implies that, the first object will be compared to the second, using the function name.
i,e,
b1.equals(b2)
Hence (b) is correct
In this exercise we have to use the knowledge in computational language in C++ to describe a code that best suits, so we have:
The code can be found in the attached image.
To make it simpler we can write this code as:
public boolean equals(Object other) {
if (other == null) {
return false; }
Backyard b = (Backyard) object;
return (length == b.getLength() && width == b.getWidth());
}
This program will result in the following missing variable:
b1.equals(b2)
See more about C++ at brainly.com/question/19705654
What is the hamming distance between the following bits? Sent
bits: 101100111, Received bits: 100111001
Select one: 5. Or 3 or 6 or4
I think
the hamming distance between the following bits its 5
what connect webpages?
Answer:
"Hypertext links are those words that take you from one web page to another when you click them with your mouse. Although the same HTML tag you study in this hour is also used to make graphical images into clickable links, graphical links aren't explicitly discussed here" I got this from https://www.informit.com/articles/article.aspx?p=440289 sorry I couldnt take the time myself here to help :(
Explanation:
Write a MIPS assembly language program that prompts for a user to enter a series of floating point numbers and calls read_float to read in numbers and store them in an array only if the same number is not stored in the array yet. Then the program should display the array content on the console window.
Consult the green sheet and the chapter 3 for assembly instructions for floating point numbers. Here is one instruction that you might use:
c.eq.s $f2, $f4
bc1t Label1
Here if the value in the register $f2 is equals to the value in $f4, it jumps to the Label1. If it should jump when the value in the register $f2 is NOT equals to the value in $f4, then it should be:
c.eq.s $f2, $f4
bc1f Label1
To load a single precision floating point number (instead of lw for an integer), you might use:
l.s $f12, 0($t0)
To store a single precision floating point number (instead of sw for an integer), you might use:
s.s $f12, 0($t0)
To assign a constant floating point number (instead of li for an integer), you might use:
li.s $f12, 123.45
To copy a floating point number from one register to another (instead of move for an integer), you might use:
mov.s $f10, $f12
The following shows the syscall numbers needed for this assignment.
System Call System Call System Call
Number Operation Description
2 print_float $v0 = 2, $f12 = float number to be printed
4 print_string $v0 = 4, $a0 = address of beginning of ASCIIZ string
6 read_float $v0 = 6; user types a float number at keyboard; value is store in $f0
8 read_string $v0 = 8; user types string at keybd; addr of beginning of string is store in $a0; len in $a1
------------------------------------------
C program will ask a user to enter numbers and store them in an array
only if the same number is not in the array yet.
Then it prints out the result array content.
You need to write MIPS assembly code based on the following C code.
-------------------------------------------
void main( )
{
int arraysize = 10;
float array[arraysize];
int i, j, alreadyStored;
float num;
i = 0;
while (i < arraysize)
{
printf("Enter a number:\n");
//read an integer from a user input and store it in num1
scanf("%f", &num);
//check if the number is already stored in the array
alreadyStored = 0;
for (j = 0; j < i; j++)
{
if (array[j] == num)
{
alreadyStored = 1;
}
}
//Only if the same number is not in the array yet
if (alreadyStored == 0)
{
array[i] = num;
i++;
}
}
printf("The array contains the following:\n");
i = 0;
while (i < arraysize)
{
printf("%f\n", array[i]);
i++;
}
return;
}
Here are sample outputs (user input is in bold): -- note that you might get some rounding errors
Enter a number:
3
Enter a number:
54.4
Enter a number:
2
Enter a number:
5
Enter a number:
2
Enter a number:
-4
Enter a number:
5
Enter a number:
76
Enter a number:
-23
Enter a number:
43.53
Enter a number:
-43.53
Enter a number:
43.53
Enter a number:
65.43
The array contains the following:
3.00000000
54.40000153
2.00000000
5.00000000
-4.00000000
76.00000000
-23.00000000
43.52999878
-43.52999878
65.43000031
Explanation:
Here if the value in the register $f2 is equals to the value in $f4, it jumps to the Label1. If it should jump when the value in the register $f2 is NOT equals to the value in $f4, then it should be
Which keyboard shortcut do we use to turn on APC?
Answer:
ctrl p I gusse hop it helps
bye know have a great day
Explanation:
the shadows she fancied has tricked her. what does that mean
Answer: the room had been dark, she had not been able to see him clearly
Explanation:
The word FANCIED means desire or fancied would mean supposed, believed, or imagined.
So it means that she might think that the shadow (assuming the shadow was a person who was invisible) was just her imagination or hallucination but in reality, the shadow (invisible person) tricked her.
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Brainliest would be greatly appreciated!
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- Mitsu JK