Cage 2 will reach the bottom first. The time taken by cage one is 114.76 seconds and cage 2 is 0.32 seconds.
How to find which cage will reach first?
Given,
Mine depth Y = 2072 m
Cage speed 1 v = 65.0 km/h
Acceleration of Cage 2,
a = 4.00 102 m/s2
Solution:
We shall utilize the international system of measurements (SI) to interchange magnitudes using the unit system, which allows us to do so precisely and without the need for antiquities.
v = 65 km / h (1000m/1Km) (1hr/3600s)
= 18.06 m / s
The relationships between location, velocity, and acceleration can be discovered using kinematics.
Work each cage separately in this practice since there are two of them.
Cage 1
They suggest that it is moving at a constant speed, which we can determine using the laws of uniform motion.
v = d/t
v = d/v
t1 = 2072/18.06
t₁ = 114.76 s
Cage 2
Stop so that your starting velocity is zero.
y = v₀ t + ½ a t²
y = 0 + ½ a t²
[tex]t = \sqrt{2y/a} \\\\t2 = \sqrt{2*2072/4*10^{2} } \\[/tex]
t₂ = 0.32 s
On comparing the time taken by cage 1 and cage 2, we can say that cage 2 will reach the ground first.
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What is leptin released by and how would you predict the levels of leptin to be in nicole when compared to a healthy, female adult of similar age and weight?.
Leptin is released by adipocytes, and I predict that the levels of leptin would be decreased in Nicole when compared to a healthy, female adult of similar age and weight.
The body regulates itself in two ways, neural signals and hormones. Hormones are chemical messengers released by endocrine glands into the blood stream that carry out a particular function in the body. The hormone that regulates appetite and body weight is leptin.
Leptin is released by fat storing cells in the body called adipocytes. The word 'leptin' comes from a Greek word 'leptos' meaning 'fat controller', perfectly fitting its function. Since leptin is stored in the fat tissues, a person's weight has a direct effect on the levels of leptin in a person. When we lose weight, the amount of leptin circulating in the body decreases, leading to more appetite and weight gain.
A lack of leptin in the body, arising from genetic diseases results in uncontrolled appetite and obesity. Generally, female adults also produce less leptin than male adults
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Share an example from your house or neighborhood that represents a physical change occurring.
An example from my house or neighborhood that represents a physical change occurring is Breaking my mum's favorite drinking glass and melting of ice block to liquid.
What is the physical change?The material involved in a physical change has the same structural properties before as well as after the change. Texture, shape, as well as temperature, and an alteration in the state of matter are examples of a lot of physical changes.
Since Physical changes to matter are those that take place without altering their chemical makeup.
Therefore, Note that by breaking the glass, it is broken down to smaller pieces, which can still be glued together and its revisable.
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Simple Machines
Which pulley would require the least
amount of force to lift the weight?
R. Pulley A
S. Pulley B
T. Pulley C
V. They all require the same amount
of force.
A B C
Q4
According to the given figures pulley B requires the least
amount of force to lift the weight .
What are pullies?In order to move and change the direction of a taut cable or belt, or to transfer power between the shaft and cable or belt, a pulley is a wheel on an axle or shaft. an object that can be lifted or lowered by pulling a chain, rope, or belt across a wheel.
In order to work, elevators require numerous pulleys. A pulley system is a cargo lift device that enables lifting of cargo to higher floors. In wells, the bucket is lifted out of the well using a pulley system. several different Compound, moveable, and fixed pulleys are the three basic categories. Wheel and axle on a fixed pulley are fixed.
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2. If you had 4.0 grams of oxygen gas, how many total molecules of
this gas would you have?
Answer:
7.52 × 1022 molecules
Explanation:
We know 32g of oxygen contains 6.022 × 1023 molecules. Therefore, 4g of oxygen have 7.52 × 1022 molecules. ( im not sure if its correct tho)
As you hurry to catch your flight at the local airport, you encounter a moving walkway that is 90 m long and has a speed of 2.1 m/s relative to the ground
.If it takes you 70 s to cover 90 m when walking on the ground, how long will it take you to cover the same distance on the walkway? Assume that you walk with the same speed on the walkway as you do on the ground.
The time taken for you to cover the same distance on the walkway is 26.6 seconds.
What is relative velocity?
The relative velocity of an object in motion is defined as the velocity of an object with respect to another observer.
The time taken for you to travel the same distance on the walkway with the given speed is calculated as follows;
Assuming you in the same direction as the walkway;
(Va + Vb)t = d
where;
Va is the speed of the walkwayVb is the your on the groundt is the time taken for you to travel the distanced is the distance of the walkwayYour speed on the ground is calculated as follows;
Vb = 90 m / 70 s
Vb = 1.286 m/s
Substitute the given parameters and solve for the time taken,
(2.1 m/s + 1.286 m/s)t = 90
(3.386)t = 90
t = 90/3.386
t = 26.6 seconds
Thus, we can conclude that if you maintain your speed on ground, it will take less time to travel the walkway.
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A 375-pound concrete cylinder has a base area of 144 square inches. with the cylinder resting on its base, the pressure exerted by the concrete cylinder is greater than sea level pressure (i.e., 14.7 psi). the formula for pressure is:
The pressure exerted by the concrete cylinder is 2.60 pound/in².
We need to know about the pressure to solve this problem. Pressure is a unit that describes how much force is applied to a surface area. It can be determined as
P = F / A
where P is pressure, F is force and A is area.
From the question above, we know that
F = 375 pound
A = 144 in²
By substituting the given parameters, we can calculate the pressure
P = F / A
P = 375 / 144
P = 2.60 pound/in²
Thus, the pressure should be 2.60 pound/in².
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Build your paper cup telephone system?
To Build your paper cup telephone system do the following:
Two cups, some inelastic string, thread, or fishing line, two paper clips, and a pencil or sewing needle are needed to make a paper cup phone.
Use a pencil or sewing needle to make a hole in the bottom of each cup, then thread a string through each hole to make a paper cup phone.
To keep the thread from coming away from the cups, secure each end with a paper clip. One person should speak into one cup, and you should listen through the other.
Pull the string taut. With the cups, you can talk to someone up to 100 feet away.
A string phone functions quite similarly to a landline. Talking into the cup causes the bottom to vibrate as sound waves are transmitted within the cup by your voice.
The other cup's bottom receives the vibrations that are transmitted to the string, across it, and into it. The second cup vibrates as a result of the sound waves transmitting your voice's audio.
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the potential at a point due to a unit positve charge is found to be v. if the distance between the charge and the point is tripled, the potential becomes
The potential at a point due to a unit positive charge is found to be V. if the distance between the charge and the point is tripled, the potential becomes V/3.(that is (⅓)rd of original potential energy.)
The electric potential (also called the electric field potential, potential drop, the electrostatic potential) is defined as the amount of work energy needed to move a unit of electric charge from a reference point to the specific point in an electric field. More precisely, it is the energy per unit charge for a test charge that is so small that the disturbance of the field under consideration is negligible.
Potential Energy at a point due to a charge is inversely proportional to Distance.
At first we consider that at r distance the potential is v, and r' distance the potential will be v/v' =r'/r
BY USING THIS-
v/v' =r'/r
As, r'=3r,
9/v'=3r/r
THEN, Potential Energy —>
V'=V/3
SO, IF the potential at a point due to a unit positive charge is found to be V. if the distance between the charge and the point is tripled, the potential becomes V/3.(that is (⅓)rd of original potential energy.)
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A shopper walks from the door of the mall towards her car; she walks 165 m south
down one lane of cars, then turns to her left and walks another 55 meters to her
car. What is her displacement?
The displacement of the shopper is 172. 92 m.
What is the process of displacement?"Displacement" describes a change in an object's location. It is a vector quantity since it has a magnitude and a direction. Its emblem is an arrow leading from the starting point to the finishing point. For instance, if an object moves from position A to position B, its position changes.
She travels 165 meters south before turning and traveling a further 55 meters to her left.
If we construct the figure, her displacement will result in the hypotenuse of the triangle.
Therefore according to the question,
Displacement = √ { ( 165)² +(55 )² } m
= √(27225 + 3025) m
=√ 30250 m
= 172. 92 m
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The volume of a piece of wood (which floats in water) can be measured as shown. Write a brier paragraph to describe the procedure. State the volume of the wood.
It is possible to determine an object's volume by making it forcibly sink. The item is attached to another easily sinkable object for this purpose.
The volume of the floating item may be calculated since it will sink in the water.
How do you calculate the volume of a piece of wood, an irregular solid that floats on water?Weighing down a floating item with a heavy object is one way to calculate its volume. It's crucial to gauge the water's depth with the heavy object submerged first, and then with the heavy object pulling the floating object down into the water.
When the weight force on an object is countered by the water's upward push, the thing floats. The amount of the object submerged increases the water's upward push, which is unaffected by the water's depth.
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If you were going to rewrite or add a heading for a section in this article, what heading would you write and why? If you cannot find one you would rewrite, pick a heading and explain why you think it is a good choice for that section.
Article:
Mini-Bottles Gain Popularity
For years, people have debated whether Coke is responsible for making Americans fatter. As that debate heated up seven years ago, Coke decided to sell soda in smaller bottles and cans. The mini-cans and bottles were a hit for Coke. Mini-bottle sales have grown over the last three years and increased 15 percent in just the first five months of 2015.
The mini-cans of Coke are so popular that they now compete with 12-ounce cans and 2-liter bottles for grocery shelf space. Originally, the company only made smaller versions of Coke and Diet Coke. Now, several different soda brands owned by Coca-Cola come in small bottles, including Sprite, Fanta Orange soda and Seagram's Ginger Ale.
Sandy Douglas is president of the North America division of Coke. He says the mini-cans are making the company a lot of money.
A regular 12-ounce can of Coke, for instance, sells on average for 31 cents. A 7.5-ounce mini sells for 40 cents. Even though the mini-cans have less soda, they cost more than a regular can, Douglas said.
Owners of shares in the Coca-Cola company are no doubt impressed. The plan to sell Coke in mini-cans and bottles has helped the company's stock price soar for the last seven years. But not everyone thinks this is a good thing.
Less Coke, Less Damage
Michael Jacobson is president of a health advocacy group. He says the smaller bottles do carry fewer health risks. They are less likely to give consumers tooth decay or diabetes.
Still, he worries that some people who do not drink sodas may want to try the mini-can because of its size.
"I don't know how this is going to shake out, but we should know soon as the popularity increases," he said. He urged Coke and its rival, Pepsi, to reduce other soda sizes, including the 2-liter bottle and 12-ounce can.
For the past 10 years, sodas have become less and less popular in North America. Americans, given more choices in teas, coffee and water, have pulled back on drinking sodas.
A poll last year found that more than half of adults avoided all types of soft drinks. Even Diet Coke, which has fewer calories than regular Coke, is becoming less popular.
Many cities are concerned about the effects of soda on people's health. They have tried to get soda companies to pay higher taxes or provide smaller portions.
Last year, many people were upset with Coke. Newspapers reported that the company was paying a group of scientists at a university. The scientists said the reason Americans were getting fatter was because they did not exercise enough, not because they drank too much soda.
Coke cut ties to the group and the organization later shut down.
People Don't Mind Spending More For The Right Size
Through its mini-cans, Coke has found a way to make money even though fewer people drink soda.
People are willing to pay more for smaller bottles. They are more convenient and let you control how much you consume, said Duane Stanford, who works at a soft drink magazine.
The mini-cans can also bring back consumers who see soft drinks as a treat, Stanford said.
The mini-bottles have changed the way Coke calculates its business, though slowly. The company still measures the amount of soda it sells in volume. The volume of soft drinks that the company sold in North America at the end of last year grew 2 percent.
But because of the mini-bottles, it is now reporting the amount of money it makes per purchase.
"The past focus of both our company and the industry was how many gallons were sold," Douglas said. "That's not a good approach for anticipating and meeting consumer needs in a world exploding with choices."
Douglas said mini-cans and bottles are popular with all people, but especially upper-income consumers and mothers.
"Moms want to treat their kids, but they don't want them to have too much," he said. "They want to be in control, and these packages give them control."
An apt header for the second paragraph is "The popularity of Mini-Cans of Coke" See the explanation below.
What is a header in writing?A heading is a word, phrase, or sentence that appears at the beginning of a written paragraph and describes what it is about. A header and a title are extremely similar. A heading is similar to a caption in that it is a line below an image that quickly describes it.
To select the right header, one must know what the central idea of the section is.
The key concept is the tale's central, unifying theme, which connects all of the other parts of fiction employed by the author to create the story. The primary notion is best defined as the story's prevailing impression or the universal, general truth.
Hence, besides communicating the central idea of the section, headers also make it easy to quickly locate the right information from a text. It is therefore useful for skimming.
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If two charged objects have a 125 N force between them when they are 3.00 m apart, what force exists between them when they are 15.0 m apart?
Answer:
I think it's 5.00 N
Explanation:
PLEASE HELP urgently!!!
1.The initial volume of a gas at a pressure of 5 atm is 3.5 L. What will the volume be if the pressure is increased to 6 atm?
Include units.
2. A gas is contained in a 4 L container at a pressure of 2 atm. The container is at a temperature of 15 degrees Celsius. What will the pressure be if the temperature is increased to 30 degrees Celsius?
Include units.
3. Calculate the decrease in temperature when 6.00 L of gas at 20.0 °C is compressed to 4.00 L.
Include units.
4. A 40.0 L tank of ammonia has a pressure of 5.5 atm. Calculate the volume of the ammonia if its pressure is changed to 8.2 atm while its temperature remains constant.
5. Determine the pressure change when a constant volume of gas at 1.5 atm is heated from 18 °C to 32 °C.
Taking into account the Boyle's law, Charles's law and Gay-Lussac's law, you get:
If the pressure is increased to 6 atm, the volume will be 2.92 L.If the temperature is increased to 30 degrees Celsius, the pressure will be 2.104 atm.When 6.00 L of gas at 20.0 °C is compressed to 4.00 L, the temperature will be 195.33 K.If its pressure is changed to 8.2 atm while its temperature remains constant, the volume will be 52.38 L.At 32°C, the pressure will be 1.43 atm.Boyle's lawBoyle's law states that the volume occupied by a given mass of gas at constant temperature is inversely proportional to the pressure: if the pressure increases, the volume decreases, while if the pressure decreases, the volume increases.
Boyle's law is expressed mathematically as
P×V=k
Considering an initial state 1 and a final state 2, it is fulfilled:
P₁×V₁=P₂×V₂
Charles's LawCharles's Law consists of the relationship between the volume and temperature of a certain amount of ideal gas.
This law says that for a given sum of gas at constant pressure, as the temperature increases, the volume of the gas increases, and as the temperature decreases, the volume of the gas decreases: the volume is directly proportional to the temperature of the gas.
Charles's law is expressed mathematically as:
V÷T=k
Considering an initial state 1 and a final state 2, it is fulfilled:
V₁÷T₁=V₂÷T₂
Gay-Lussac's law
Gay-Lussac's law determines that gas pressure is directly proportional to its temperature when the volume is constant: when there is a constant volume, when the temperature increases, the gas pressure increases and when the temperature decreases, the gas pressure decreases.
Gay-Lussac's law is expressed mathematically as:
P÷T=k
Considering an initial state 1 and a final state 2, it is fulfilled:
P₁÷T₁=P₂÷T₂
Exercise 1In this case, you know:
P₁= 5 atmV₁= 3.5 LP₂= 6 atmV₂= ?Replacing in the Boyle's law:
5 atm× 3.5 L= 6 atm×V₂
(5 atm× 3.5 L)÷ 6 atm= V₂
2.92 L= V₂
Finally, the volume will be 2.92 L.
Exercise 2In this case, you know:
T₁= 15°C= 288 KP₁= 2 atmT₂= 30°C= 303 KP₂= ?Replacing in Gay-Lussac's law:
2 atm÷ 288 K=P₂÷ 303 K
(2 atm÷ 288 K)× 303 K=P₂
2.104 atm= P₂
Finally, the pressure will be 2.104 atm.
Exercise 3In this case, you know:
V₁= 6 LT₁= 20 C= 293 KV₂= 4 LT₂= ?Replacing in Charles's law:
6 L÷293 K=4 L÷T₂
(6 L÷293 K)× T₂= 4 L
T₂= 4 L÷ (6 L÷293 K)
T₂= 195.33 K
Finally, the temperature will be 195.33 K.
Exercise 4In this case, you know:
P₁= 5.5 atmV₁= 40 LP₂= 8.2 atmV₂= ?Replacing in the Boyle's law:
5.5 atm× 40 L= 8.2 atm×V₂
(5.5 atm× 40 L)÷ 8.2 atm= V₂
52.38 L= V₂
Finally, the volume will be 52.38 L.
Exercise 5In this case, you know:
T₁= 18°C= 291 KP₁= 1.5 atmT₂= 32°C= 305 KP₂= ?Replacing in Gay-Lussac's law:
1.5 atm÷ 291 K= P₂÷ 305 K
(1.5 atm÷ 291 K)× 305 K=P₂
1.43 atm= P₂
Finally, the pressure will be 1.43 atm.
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How does a change in the solar constant impact the absorption of shortwave radiation and the emission of longwave radiation by the earth-atmosphere system?.
Solar constant never change, and hence there is no change in shortwave as well as longwave radiation by the earth's atmosphere
Solar constant is the rate at which the solar energy from the sun intercepts the earth's surface. It's value is 1,338watts per square meter.
Long wave radiation is a type of radiation emitted from earth whose wavelength ranges from 4 to 30 micrometers. While shortwave radiation is the radiant energy which is produced by the sun whose wavelength ranges from infrared to ultraviolet through visible.
We know that solar constant never change (constant), and the amount of shortwave that reaches the earth's atmosphere is called solar constant. As the solar constant does not change, there will be no change in shortwave as well as longwave radiation by the earth's atmosphere.
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an engineer decides to damp the oscillations by applying one shock absorber to each spring. these shock absorbers apply a velocity‑dependent drag force ????⃗
An engineer comes to a decision to dampen the oscillations by way of applying one shock absorber to each spring. those surprise absorbers practice a speed‑established drag force these shock absorbers follow a pace-structured drag pressure F = mv that opposes damping the oscillations making use of one surprise absorber to each spring.
Engineers, as practitioners of engineering, are specialists who invent, design, analyze, construct and take a look at machines, complicated structures, systems, devices, and materials to fulfill functional targets and necessities while considering the limitations imposed through practicality, law, safety, and value.
Engineers design, construct, and hold numerous complex systems and systems, from buildings to software programs. while there are many engineering professions, there's one steady engineering mindset: to innovate. A four-year university degree in technical know-how, mathematics, or engineering. Accreditation by an engineering firm comprised of ABET or the Accreditation Board of Engineers and Ers. engineering license. Non-traditional credentials including professional certificates work portfolios and coding.
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What kind of energy transfer occurs when an earthquake produces a large ocean wave called a tsunami
Answer: Mechanical waves transfer energy from rock to water.
Explanation: The particles of the medium just vibrate in place. As they vibrate, they pass the energy of the disturbance to the particles next to them, which pass the energy to the particles next to them, and so on. Particles of the medium don't actually travel along with the wave.
Answer:
Mechanical Waves
Explanation:
Mechanical waves are waves that require a medium for the transfer of their energy to occur. Water waves are an example of mechanical waves. Tsunami waves released after an earthquake transfer the energy of the quake to distant shorelines.
Hope this helps.
Design an experiment that will enable you to measure the force needed to be applied to cut into different materials with different shapes.
Various shapes are predetermined as then the student tries to cut them. As the shapes are cut, the magnitude of force required is measured.
What is the force?The term force is defined as that which causes an object to move or to change its direction. A force is typically a push or a pull. We could measure the applied force by the use of a Dynamometer .
In this case, we could determine the various shapes that we want to cut and then try to cut them. As we are cutting the shapes, we could now use the Dynamometer to determine the force applied.
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A red ball moves horizontally in a 30-meter long tube. The position of the ball on meters over time is shown in the attached position vs. time graph.
What is the displacement of the red ball between 12 seconds and 24 seconds?
What is the distance traveled by the red ball between 12 seconds and 24 seconds?
Given that a red ball goes horizontally inside of a tube that is 30 metres long.
The distance travelled in a certain direction is known as displacement.
The movement is in a certain direction because it is horizontal.
The displacement will be the horizontal distance travelled, which is 30 metres, during the allotted time.
What is the distinction between displacement and distance?Distance is the total distance along the route between any two places. Displacement is the direct distance between any two places when calculated via their shortest route. The direction is not taken into account while calculating distance. The direction is taken into account while calculating displacement.
Clarify the difference between distance and displacement. Distance refers to the measurement of "how much ground an item has covered during its motion," whereas displacement refers to the measurement of "how far out of place is an object."
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an anemometer is a device used to measure the speed of the wind. as the wind speed increases, its arms rotate faster and this rotation is measured electronically. suppose a relatively steady breeze is blowing.
A tool used to gauge wind direction and speed is an anemometer. It is a typical piece of weather station equipment. Any instrument used to measure wind speed in meteorology is referred to by this name, which is derived from the Greek word anemos.
Vane anemometers, thermal anemometers, thermal anemometers with velocity/temperature profiling, and cup anemometers are the four most widely used anemometer types.
The majority of the time, anemometers are categorized as constant-temperature or constant-power anemometers.
To calculate wind speed is as follows: Anemometer factor x instantaneous shaft speed equals instantaneous wind speed.
Average Wind Speed is calculated as follows: Anemometer Factor x (Time / Turns)
The force that the wind applies to a structure (or, really, any object) is known as wind pressure. The anemometer's cups rotate as the wind blows, spinning the centre rod. The rod spins more quickly the stronger the wind blows. The anemometer measures the revolutions, or turns, from which wind speed is determined.
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the final velocity of a truck that is initially traveling at 10 m/s and travels 500m over
the course of 13 seconds
Answer:
123.75 m/s
Explanation:
Given:
Initial velocity (u) = 10 m/sDistance travelled(S) = 500 mTime(t) = 13 sTo Find:
Final velocity,ie, v.Formula used:
S = ut + at^2/2where,
S is distance travelled
u is initial velocity
v is final velocity
t is time taken
v = u + atwhere,
v is final velocity and rest meaning is written above.
Let the acceleration of truck be a
Using the above formula, we get
500 = 10*13 + a(13)^2/2
370 = 169a/4
a = 8.75 m/s^2
So, Putting value of a in v = u + at, we get
v = 10 + 8.75*13
v = 123.75 m/s
So, the final velocity will be 123.75 m/s.
Answer:
this is an amazing question
whichof the followings unit is not a fundamental S I Unit (A) Meter (b) Ampere (c) Kelvin (d)second(E) Radian
Answer:
Option E
Explanation:
Option E, ie, Radian is not consider to be a fundamental quantity unit and it is used to measure the plane angle.
Seven Fundamental units are:
MetreSecondsKilogramAmpereKelvinCandelaMole5. A car moves with an avg velocity of +12.5m/s. If it begins 137m behind the origin, where will it be after 7s?
Displacement = 1/2(Initial Velocity + Final Velocity)Time
If we plug in the values (0 as initial velocity, 12.5 as final velocity, 7 as time), we get 43.75 meters.
According to the given condition we are 137 meters behind the origin. That would mean our initial displacement is -137 meters. After driving for 7 seconds, the car would be 43.75 meters closer to the origin.
-137 + 43.75 = - 93.25 meters (or 93.25 meters behind the origin).
in a simple electric circuit, ohm's law states that , where v is the voltage in volts, i is the current in amperes, and r is the resistance in ohms. assume that, as the battery wears out, the voltage decreases at 0.03 volts per second and, as the resistor heats up, the resistance is increasing at 0.01 ohms per second. when the resistance is 100 ohms and the current is 0.02 amperes, at what rate is the current changing? amperes per second
The value of decreasing current is 0.202m/s.
What is Ohm's law and it 's limitations?The relationship between current, voltage, and resistance is known as Ohm's law. German scientist proposed this connection. Ohm's law is referred to as such because of this. According to this, the voltage or potential difference across many different materials will directly affect how much constant current flows through them. As a result, if the voltage V (measured in volts) between two ends of a wire made of one of these materials is tripled, the current I (measured in amperes) also triples, yet the ratio V/I stays the same. A substance's resistance, measured in ohms, is the product of the ratio V/I for that particular piece of material.
We have given here ,
dV/dt= -0.04, dR/dt= 0.04 , R= 200
I= 0.01
From Ohm's law,
V= IR
dV/dt = IdR/dt + RdI/dt differentiating with respect to t ,
by applying values and solving it we get ,
dI/dt =-0.000202
Hence current is decreasing at 0.202 mA/s.
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True or false? A well-oiled machine has no friction. Explain your answer.
Answer:
False
Explanation:
A well-oiled machine has oil because there is friction. The oil lessens the friction and also allows the machine to operate and function without wear parts heating up. Oil is a cooling lubricant that decreases friction but does not eliminate it.
explain your observations: what do you think happened to the light from the lightbulb as it passed through the gas cloud before passing through the spectroscopy telescope?
If a gas of hydrogen atoms lies between you (your telescope + spectrograph) and a continuum light source, it will create an absorption line spectra, and if viewed from a different angle, an emission line spectrum.
Absorption lines allude to the propensity of cool atmospheric gas to absorb the same lines of light, whereas emission lines refer to the fact that burning hot gas produces lines of light.
Some of the light at specific wavelengths is scattered when it travels through the atmosphere's gas, producing darker bands. The wavelengths of light released when common materials were heated to form lines that became known as "spectral lines" were recorded.
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Starting from rest, a marble first rolls down a steeper hill, then down a less steep hill of the same height. For which is it going faster at the bottom?.
The first and second marble have the same speed at the bottom.
We need to know about the conservation of energy to solve this problem. The energy can not be created or destroyed, the only way is to change to another form. It can be written as
Ei = Ef
where Ei is initial energy and Ef is the final energy
The potential energy of the first marble is the same as the second marble because they have the same height. According to conservation of energy, the potential energy will be converted to kinetic energy and the speed of the marbles will same at the bottom.
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a receiver in a football game is standing still, having just caught a pass. before he can move, a tackler, running at a velocity of 4.2 m/s, grabs him. the tackler holds onto the receiver, and the two move off together with a velocity of 3 m/s. the mass of the tackler is 120 kg. assuming that momentum is conserved, find the mass of the receiver.
The mass of the receiver is 103.261 kg.
Assume that m is the receiver's mass.
Prior momentum =(125*4.2)-m*0
After =2.3(125+m) momentum
525=287.5+2.3m
m=237.5/3.3
m=103.261kg
So, the mass of the receiver is 103.261kg.
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why doesn't a heavy object accelerate more than a light object when both are freely falling? why doesn't a heavy object accelerate more than a light object when both are freely falling? the ratio of the weight to mass is the same for all objects in the same locality. the inertia of the heavy object equals the inertia of the lighter object, so their accelerations are the same. the inertia of the heavy object is just enough smaller than the inertia of the lighter object to counteract the larger gravity force. the larger air resistance force on the larger object makes it fall with the same acceleration.
The reason for this is that at a specific area, the acceleration brought on by gravity is constant. Lighter items are not accelerated more slowly by gravity than heavy ones.
The following are possible gravity values for the gravitational force between the earth (mass M) and an object of mass m:
F = GMm/r2 with r being the separation.
Now form Newton's second law,
F = ma where a is the acceleration.
Equating the two, ma= GMm/r2
a= GM/r2
This demonstrates that the mass m of the object being propelled is independent of the acceleration caused by gravity for some object (the mass M).
Additionally, the earth's gravitational pull causes free fall. This explains why there is a constant acceleration from gravity.
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Sphere A is located at the origin and has a charge of +2.0 × 10- C. Sphere B is located at +0.60 m on the x-axis and has a charge of -3.6 x 10- C.
Sphere C is located at +0.80 m on the x-axis and has a charge of +4.0 x 10-6 C. Determine the net force on sphere A.
Answer:
F = 0.0675 N
Explanation:
The net force under sphere A is the sum of the force made by sphere B with the force made by sphere C.
By Coulomb's Law of force, we have:
F = k * Q*Q/d²
So:
Force (absolute value) of C on A:
F₁₃ = k * Q₁*Q₃/d²
F₁₃ = 9*10⁹ * (2.0*10⁻⁶)*(4.0*10⁻⁶) / (0.80)²
F₁₃ = 9/80 N = 0.1125 N
The vector:
F₁₃ = 0.1125 N (horizontal direction; pointed to the left side: repulsive)
Force (absolute value) of B on A:
F₁₂ = k * Q₁*Q₂/d²
F₁₂ = 9*10⁹ * (2.0*10⁻⁶)*(3.6*10⁻⁶) / (0.60)²
F₁₂ = 9/50 = 0.18 N
The vector:
F₁₂ = 0.18 N (horizontal direction; pointed to the right side: attractive)
The net force is F₁₂ - F₁₃:
F = 0.180 - 0.1125
F = 0.0675 N
1. SAMPLE: Pete is driving down 7th street. He drives 150 meters in 18 seconds. Assuming he does not speed up or slow down, what is his speed in meters per second?
Formula you need to use:
Speed = distance / time
OR S = D / T Variable letters, measurement with units
D = 150m
T = 18s
S = ?
Plug measurements into formula:
S = 150m / 18s
Answer with units:
S = ____
The speed in meter per second of Peter, given that he drove 150 meters in 18 seconds is 8.33 m/s
How do I determine the speed?We know that speed is defined as the distance travelled per unit. It can be expressed as:
Speed = distance / time
With the above formula, we can obtain the speed of Peter. Details below
From the question given, the following were obtained:
Distance = 150 metersTime = 18 secondsSpeed =?Speed = distance / time
Speed = 150 / 18
Speed = 8.33 m/s
From the calculation made above, the speed is 8.33 m/s
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