R is the mixture formed by adding 5 g of sugar to 1 L of water.
Which is a mixture?A mixture is an impure substance made up of two or more substances which are miscible or immiscible in each other.
Dissolving the sugar in the water makes a homogenous mixture and once dissolved a solution is made by the combination of a solute (sugar) and solvent (water).
Hence, R is the mixture formed by adding 5 g of sugar to 1 L of water.
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4NH 3+32 to 2 and 2+ 6H20 What is the mole ratio of NH3 to N2
The mole ratio would be 4:3
What is the mole ratio?Mole ratio is the ratio of the stoichiometric number of moles of components of reactions.
From the equation: [tex]4NH_3 + 3O_2 --- > 2N_2 + 6H_2O[/tex]
The mole ratio of [tex]NH_3[/tex] to that of [tex]N_2[/tex] is the ratio of their coefficients. The coefficients are 4 and 3 respectively
Thus, the ratio is 4:3.
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A) If Kb for NX3 is 4.5×10^−6, what is the pOH of a 0.175 M aqueous solution of NX3 ?
B) If Kb for NX3 is 4.5×10^−6, what is the percent ionization of a 0.325 M aqueous solution of NX3 ?
Please show your work so I can understand how to solve similar problems on my own! Thank you!
3.08 is the pOH of a 0.175 M aqueous solution of [tex]NX_3[/tex].
0.215% is the per cent ionization of a 0.325 M aqueous solution of [tex]NX_3[/tex]
What is pH?pH is a measure of how acidic/basic water is.
A)
[tex]NX_3 + H_2O[/tex] →[tex]NHX_3^+ + OH^-[/tex]
Kb = 4.5 x[tex]10^-6[/tex]
Kb = {concentration of (NH₄⁺) x concentration of (OH⁻)} ÷ concentration of (NH₃).
concentration of (NH₄⁺) = concentration of (OH⁻) = x.
x² = Kb x concentration of (NH₃)
x² = 4.5 × 10⁻⁶ × 0.175 = 7.0 × 10⁻⁷.
x = concentration of (OH⁻) = √(7.0 × 10⁻⁷)
= 8.367 × 10⁻⁴
pOH = -log(c(OH⁻))
=- log ( 8.367 × 10⁻⁴)
= 3.08
B)
Chemical reaction: NX₃ + H₂O ⇄ NX₃H⁺ + OH⁻.
Concentration of (NX₃) = 0.325 M.
Kb = 4.5 x 10⁻⁶.
[NX₃H⁺] = [OH⁻] = x.
[NX₃] = 0.325 M - x.
Kb = [NX₃H⁺] x [OH⁻] ÷ [NX₃].
4.5 x 10⁻⁶ = x² ÷ (0.325 M - x).
x = 0.0007 M.
Per cent of ionization:
α = 0. 0007 M ÷ 0. 325 M x 100%
= 0.215%.
Hence,
3.08 is the pOH of a 0.175 M aqueous solution of [tex]NX_3[/tex].
0.215% is the per cent ionization of a 0.325 M aqueous solution of [tex]NX_3[/tex]
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A sample of gas has temperature of 372 K and pressure of 3.8 ATM. If the temperature is increased to 550 K, what is the new pressure?
Answer: The correct answer is 5.6atm.
Explanation: Since we only have information on the pressure and temperature, we will use Gay-Lussac's Law: [tex]\frac{P_{1} }{T_{1} } =\frac{P_{2} }{T_{2} }[/tex]. Now that we have the formula, let's plug in our given information!
[tex]\frac{3.8atm}{372K} =\frac{P_{2} }{550K}[/tex]
We must find the value [tex]P_{2}[/tex]. To do this, we will write a stoichiometric equation to solve this.
[tex]P_{2} =\frac{3.8atm*550K}{372K}[/tex]
Let's input the numbers into a scientific calculator to get our answer!
[tex]P_{2} =\frac{3.8atm*550K}{372K}=5.6 atm[/tex]
Given all of this work, the value [tex]P_{2}[/tex] equals 5.6 atm.
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what are the hydrogen bonding atoms in melatonin?
The hydrogen bonding atoms in melatonin are phospholipids and cholesterol.
What is Hydrogen bonding?This is the type of interaction which involves a hydrogen atom being covalently bound to a more electronegative "donor".
Melatonin controls sleep-wake cycle and has phospholipids and cholesterol which have high affinity for hydrogen bonding.
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round off 318.90 to 2 significant figures
Answer:
320
Explanation:
Because the question is asking for 2 significant figures, you want to try to get rid of all of the numbers to the right of the 1. That way, the only numbers that will be significant are the numbers in the position of the 3 and the 1.
Before you can make the rest of the numbers equal 0, you need to correctly round the number in the last significant position (the number 1).
If the number to the right of the 1 is from 0-4, the number stays the same. If the number is from 5-9, the 1 needs to be increased by a unit.
Since the number to the right is an 8, you need to change the 1 to a 2. Now, you can make all of the other numbers a 0. There should be no decimal place because it would mean that the zero to the left of it is significant.
2. A sample of gas has a pressure of 1.4 atm and a volume of 500 mL. If the volume is decreased to 250 mL, what is the new pressure?
Answer: The new pressure is 2.8 atm.
Explanation:
Since our given information only involves pressure and volume, we will use Boyle's Law: [tex]P_{1} V_{1} =P_{2} V_{2}[/tex]. Let's input the data into the formula.
[tex]1.4atm*500mL=P_{2} *250mL[/tex]
We have to rearrange our data a bit now because the volume is supposed to be in liters. To convert from milliliters(mL) to liters(L), you must divide the number by 1000. That is what we will do with both of our given volumes.
[tex]\frac{500mL}{1000} =0.5L[/tex] [tex]\frac{250mL}{1000} =0.25L[/tex]
Now that our volumes are in liters, we can correctly plug in our data.
[tex]1.4atm*0.5L=P_{2} *0.25L[/tex]
Since we do not know the value [tex]P_{2}[/tex], we must rearrange the formula into a stoichiometric equation to find out the answer.
[tex]P_{2}=\frac{1.4atm*0.5L}{0.25L}[/tex] [tex]P_{2}=2.8 atm[/tex]
Our final answer is 2.8 atmospheres.
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Oil from cashew nuts
Answer:
yes it's a thing, milk too
Which of the following statements is most accurate about how individual atoms produce light?
Group of answer choices
Electrons can spontaneously emit a photon of light without dropping to lower energy levels.
Light is not created by atoms, it just passes through them.
Photons are emitted when an electron jumps to higher energy levels in an atom.
An electron in an excited energy level of an atom will always drop to lower energy levels, emitting very specific wavelengths of light in the process.
Answer:
An electron in an excited energy level of an atom will always drop to lower energy levels, emitting very specific wavelengths of light in the process.
A solution is prepared by dissolving 0.131 g of a substance in 25.4 g of water. The molality of the solution is determined by freezing point
depression to be 0.056 m. What are the moles of the substance?
The mole of the substance, given the data from the question is 0.0014 mole
What is molality?This is simply defined as the mole of solute per kilogram of water. Mathematically, it is expressed as
Molality = mole / mass (Kg) of water
How to determine the mole of the substanceMass of water = 25.4 g = 25.4 / 1000 = 0.0254 KgMolality = 0.056 mMole of substance =?Mole = molality × mass of water
Mole of substance = 0.056 × 0.0254
Mole of substance = 0.0014 mole
Thus, the mole of the substance is 0.0014 mole
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A gas expands and does PV work on its surroundings equal to 322 J. At the same time, it absorbs 132 J of heat from the surroundings. Calculate the change in energy of the gas. Note: PV work means work done by a changing volume against constant pressure. Enter your answer in scientific notation.
From the calculations, the change in energy is - 190 J.
What is the first law of thermodynamics?From the first law of thermodynamics, the energy is neither created nor destroyed but is transformed from one form to another.
From the law;
U = q + w
U = internal energy
q = heat
w = work
Since work is done on the surroundings and the gas absorbs heat then;
U = 132 J - 322 J
U = - 190 J
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calculate the mass in grams of the sample
Answer:
3666.33 gm
Explanation:
O3 mole mass = 47.997
Each mole has 6.022 x 10^23 molecules
4.6 x 10^25 / 6.022 x 10^23 x 47.997 gm/mole = 3666.33 gm
I need help with homework
Answer:
1. H₂SO₄
Explanation:
A balanced equation tells us how each reactant and product is related to each other in terms of moles.
The equation given has already been balanced since the number of atoms of each element is the same on both sides of the arrow. From the equation, we can see that 1 mole of H₂SO₄ reacts with 2 moles of NaOH. Whichever reactant that we do not have enough of to make more products is known as the limiting reagent, since it limits the amount of products formed.
Mole ratio of H₂SO₄: NaOH= 1: 2
The amount of NaOH needed is twice the amount of H₂SO₄ in terms of moles.
Given that there are 0.40 moles of H₂SO₄, let's calculate the amount of NaOH needed.
Amount of NaOH needed
= 2(0.40)
= 0.80 moles
However, there are only 0.75 moles of H₂SO₄. Since 0.75 <0.80, H₂SO₄ is the limiting reactant.
Additional:
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Answer:
See below
Explanation:
From the balanced equation you can see you need twice as many moles of NaOH as H2SO4....
you have .4 moles of H2SO4 so you need .8 moles of NaOH
but you only have .75 mole....so NaOH is the limiting factor (because you do not have enough)
What are the social, cultural, and environmental in pacts of water in California
Use the ideas of the Kinetic Theory to explain the following. A sealed container contains nitrogen gas. The pressure of a gas is due to the molecules of the gas hitting the walls of the container. Explain why the pressure inside the container increases when the temperature is increased.
Answer:
When the temperature increases, the molecules of the gas gain energy. Therefore, they move faster.
This causes the molecules to hit the walls of the container more frequently and with greater force. Hence the pressure inside the container increases.
In the following reaction, how much heat is
generated when 1.83 moles of CH4 are
burned?
CH4 (g) + 2 O₂ (g) → CO₂ (g) + 2 H₂O(g) Hº
= -802 kJ/mol
| KJ
Answer:
1470 kJ (to 3 sf)
Explanation:
(802)(1.83) = 1470 kJ (to 3 sf)
For the reaction: C → D + B the graph of ln k vs 1/T(K) gives the equation: y = -2.2x104x + 45.0. Using this information, calculate the activation energy, (J/mol)
From the equation of the graph, the activation energy of the reaction is -2.2 * 10⁴ J/mol.
What is activation energy?Activation energy is the minimum required energy that reactant molecules must possess for a reaction to proceed towards formation of products.
The activation energy is determined from the slope of ln k against 1/T(K).
Given the equation, y = -2.2 * 10⁴ x + 45.0.
Comparing with the equation of a straight line, y = mx + c
The gradient, m = -2.2 * 10⁴
Therefore, the activation energy of the reaction is -2.2 * 10⁴ J/mol.
In conclusion, reactant molecules must break the activation energy barrier in order to form products.
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Can Ionic bonds form single double or triple bonds?
Answer:
carbon molecules share their 4 valence electrons through single, double, and triple bonds.
Explanation:
I think you meant ionic bonds not lonic bonds
1. A fluid is a substance that (a) always expands until it fills any container; (b) is practically incompressible; (c) cannot be subjected to shear forces; (d) cannot remain at rest under action of any shear force.
Answer:
cannot remain at rest under the action of any shear force.
Is the spectrum
electromagnetic
of an element limited only to the visible region of the
spectrum?
The electromagnetic spectrum of an element is not limited only to the visible region of the spectrum.
What is an electromagnetic spectrum?An electromagnetic spectrum is a range of frequencies and wavelengths into which an electromagnetic wave is distributed into.
In Science, the electromagnetic spectrum consist of the following types of energy from highest to lowest frequency and shortest to longest wavelength:
Gamma raysX-raysUltraviolet radiationVisible lightInfrared radiationMicrowavesRadio wavesIn this context, we can infer and logically deduce that the electromagnetic spectrum of an element is not limited only to the visible region of the spectrum.
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Identify the following changes as physical or chemical. A loaf of risen but unbaked bread. Photo by Elinor D Bread dough rising: physical chemical
The answers include:
A loaf of risen but unbaked bread - chemical change.Photo by Elinor D - chemical change.Bread dough rising - chemical change.What is a Chemical change?
This involves the formation of a new products from substances. In this scenario, a rising bread contains alcohol which evaporates.
Photographs also fall under this category and is therefore an irreversible chemical change.
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Sodium tungstate is Na₂WO4. Therefore, the formula for gold(III) tungstate is
Answer:
AuW₃
Explanation:
Is KI + AgNO3 make potassium nitrate ?
Answer:
AgNO3 + KI → AgI + KNO3
Explanation:
Yes, it's produced potassium nitrate
explain how adding soap to water affects the surface tension of water.
Answer:
The surface tension of water is high due to the dipole nature of water, meaning that the water molecules pull on each other by electrical charge. Soap and detergents interrupt this layer, reducing the surface tension.
A visual, though not scientifically accurate, would be a set of magnetic marbles that form a sheet. If you randomly stick in glass marbles the overall strength decreases since they are not all pulling together in order.
There are some substances, called super wetters, generally silicone surfactants that give a truly amazing drop in surface tension, where a small puddle of water can spread to many times it’s own size. These types of surfactants are used in laundry detergent and french fry oil to prevent foaming and in polymers to promote flow.
Hope it helps!
Please mark me as brainlist.
Answer:
The surface tension of water is high due to the dipole nature of water, meaning that the water molecules pull on each other by electrical charge. Soap and detergents interrupt this layer, reducing the surface tension.
A visual, though not scientifically accurate, would be a set of magnetic marbles that form a sheet. If you randomly stick in glass marbles the overall strength decreases since they are not all pulling together in order.
There are some substances, called super wetters, generally silicone surfactants that give a truly amazing drop in surface tension, where a small puddle of water can spread to many times it’s own size. These types of surfactants are used in laundry detergent and french fry oil to prevent foaming and in polymers to promote flow.
Explanation:
The rate constant, k, for a reaction is 0.0354 sec1 at 40°C. Calculate the rate constant for the
same reaction at 125°C if the activation energy is 26.5 kJ/mol.
Answer:
The rate constant of the reaction at 125˚ is [tex]0.3115 \ \text{sec}^{-1}[/tex].
Explanation:
The Arrhenius equation is a simple equation that describes the dependent relationship between temperature and the rate constant of a chemical reaction. The Arrhenius equation is written mathematically as
[tex]k \ = \ Ae^{\displaystyle\frac{-E_{a}}{RT}}[/tex]
[tex]\ln k \ = \ \ln A \ - \ \displaystyle\frac{E_{a}}{RT}[/tex]
where [tex]k[/tex] is the rate constant, [tex]E_{a}[/tex] represents the activation energy of the chemical reaction, [tex]R[/tex] is the gas constant, [tex]T[/tex] is the temperature, and [tex]A[/tex] is the frequency factor.
The frequency factor, [tex]A[/tex], is a constant that is derived experimentally and numerically that describes the frequency of molecular collisions and their orientation which varies slightly with temperature but this can be assumed to be constant across a small range of temperatures.
Consider that the rate constant be [tex]k_{1}[/tex] at an initial temperature [tex]T_{1}[/tex] and the rate constant [tex]k_{2}[/tex] at a final temperature [tex]T_{2}[/tex], thus
[tex]\ln k_{2} \ - \ \ln k_{1} = \ \ln A \ - \ \displaystyle\frac{E_{a}}{RT_{2}} \ - \ \left(\ln A \ - \ \displaystyle\frac{E_{a}}{RT_{1}}\right) \\ \\ \\ \rule{0.62cm}{0cm} \ln \left(\displaystyle\frac{k_{2}}{k_{1}}\right) \ = \ \displaystyle\frac{E_{a}}{R}\left(\displaystyle\frac{1}{T_{1}} \ - \ \displaystyle\frac{1}{T_{2}} \right)[/tex]
[tex]\rule{1.62cm}{0cm} \displaystyle\frac{k_{2}}{k_{1}} \ = \ e^{\displaystyle\frac{E_{a}}{R}\left(\displaystyle\frac{1}{T_{1}} \ - \ \displaystyle\frac{1}{T_{2}} \right)} \\ \\ \\ \rule{1.62cm}{0cm} k_{2} \ = \ k_{1}e^{\displaystyle\frac{E_{a}}{R}\left(\displaystyle\frac{1}{T_{1}} \ - \ \displaystyle\frac{1}{T_{2}} \right)}[/tex]
Given that [tex]E_{a} \ = \ 26.5 \ \ \text{kJ/mol}[/tex], [tex]R \ = \ 8.3145 \ \ \text{J mol}^{-1} \ \text{K}^{-1}[/tex], [tex]T_{1} \ = \ \left(40 \ + \ 273\right) \ K[/tex], [tex]T_{2} \ = \ \left(125 \ + \ 273\right) \ K[/tex], and [tex]k_{1} \ = \ 0.0354 \ \ \text{sec}^{-1}[/tex], therefore,
[tex]k_{2} \ = \ \left(0.0354 \ \ \text{sec}^{-1}\right)e^{\displaystyle\frac{26500 \ \text{J mol}^{-1}}{8.3145 \ \text{J mol}^{-1} \ \text{K}^{-1}}\left(\displaystyle\frac{1}{313 \ \text{K}} \ - \ \displaystyle\frac{1}{398 \ \text{K}} \right)} \\ \\ \\ k_{2} \ = \ 0.3115 \ \ \text{sec}^{-1}[/tex]
PLEASE HELP!!!!!!!!
Calculate the pH for the following weak acid.
A solution of HCOOH has 0.19M HCOOH at equilibrium. The Ka for HCOOH is 1.8×10−4 . What is the pH of this solution at equilibrium?
Answer: 2.23
Explanation:
The dissociation of acetic acid is as follows:
HCOOH(aq) ⇋ HCOO− (aq) + H+(aq)
The ICE table for the concentrations of ions is given below. From the table, the concentration of HCOO- and H+ can be found out.
HCOOH → HCOO− + H+
Initial Concentration 0.019 M 0 0
Equilibrium Concentration (0.019−x) M x x
Where,
x is the concentration of the ions at equilibrium.At equilibrium, dissociation constant can be calculated as follows.
[tex]K_{\mathrm{a}}=\frac{x^{2}}{(0.19-x) \mathrm{M}}[/tex]
At equilibrium, the concentration of x is negligible as compared to that of HCOOH.
Substitute the value of Ka in the above equation.
[tex]\begin{aligned}K_{\mathrm{a}} &=\frac{x^{2}}{0.19-x} \\x &=\sqrt{1.8 \times 10^{-4} \times 0.19} \\&=0.00584 \mathrm{M}\end{aligned}[/tex]
Here, the concentration of hydrogen ion is obtained. From the hydrogen ion concentration, the pH of the solution is found out as follows:
[tex]\begin{aligned}\mathrm{pH} &=-\log \left[\mathrm{H}^{+}\right] \\&=-\log (0.00584 \mathrm{M}) \\&=2.23\end{aligned}[/tex]
Therefore, the pH of 0.19M HCCOH is 2.23
When calcium carbonate is added to hydrochloric acid, calcium chloride, carbon dioxide, and water are produced. caco3(s) 2hcl(aq)⟶cacl2(aq) h2o(l) co2(g) how many grams of calcium chloride will be produced when 27.0 g of calcium carbonate is combined with 14.0 g of hydrochloric acid?
21.1 grams of calcium chloride will be produced when 27.0 g of calcium carbonate is combined with 14.0 g of hydrochloric acid.
What is a limiting reagent?The reactant that is consumed first in a chemical reaction is the limiting reagent or limiting reactant because it stops any more reactions from taking place. The limiting reagent controls how much product is produced during the reaction.
CaCO3(s) + 2HCl(aq) ==> CaCl2(aq) + H2O(l) + CO2(g)
[tex]mols CaCO3 =[/tex] [tex]27 *\frac{1 mol}{100g}[/tex] = 0.27 mol
[tex]mols HCl = 15 gx \frac{1 mol}{36.5 g}[/tex] = 0.38 mol
Limiting reactant = HCl ( it takes 2x the mols of HCl compared to mols CaCO3 as per balanced equation)
mass of CaCl2 = [tex]0.411 mols HCl x\frac{ 1 mol CaCl2}{ 2 mols HCl } x 111.0 g/mol[/tex]
mass of CaCl2 = 21.1 g
Hence, 21.1 g of calcium chloride will be produced when 27.0 g of calcium carbonate is combined with 14.0 g of hydrochloric acid.
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How many molecules of HCI would react with 2 moles of Al?
2AI + 6HCI-2AICI 3
+ 3H₂
From the coefficients of the equation, we know that for every 2 moles of Al consumed, 6 moles of HCl are consumed.
This means 6(2/2)=6 moles of HCl are needed.
Since there are [tex]6.022 \times 10^{23}[/tex] molecules in 1 mole of a substance, there are :
[tex]6(6.022 \times 10^{23}}=\boxed{4 \times 10^{24} \text{ (to 1 sf)}}[/tex]
If we want to study rest-frame visible light emitted by stars in distant galaxies at a high redshift of z 3, what portion of the electromagnetic spectrum do we need to observe? (hint JWST is meant to study distant galaxies)
The portion of the electromagnetic spectrum do we need to observe is the red part of the This is further explained below.
What is electromagnetic spectrum?Generally, Spectrum refers to the range of wavelengths or frequencies that electromagnetic radiation may cover.
In conclusion, We need to keep an eye on the red part of the electromagnetic spectrum since a large positive redshift causes an increase in wavelength and a corresponding fall in frequency and photon energy (such as light).
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Sucrose decomposes to fructose and glucose in acid solution. When ln [sucrose] is
plotted vs. time, a straight line with slope of -0.208 hr-1 results. What is the rate law for
the reaction?
A) Rate = 0.208 hr-1 [sucrose]2
B) Rate = 0.208 hr-1 [sucrose]
C) Rate = 0.0433 hr [sucrose]2
D) Rate = 0.0433 hr [sucrose]
E) Rate = 0.208 mol L-1hr-1 [sucrose]0
The correct rate law for the reaction is given as Rate = -0.208 hr-1 [sucrose].
What is a first order reaction?A first order reaction is one in which a plot of the logarithm of the concentration against time gives a straight line graph. Now we know that this is a decomposition reaction thus the slope is negative.
Thus, in this case, the correct rate law for the reaction is given as Rate = -0.208 hr-1 [sucrose].
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James was supposed to measure the circumference of three trees as homework for science class. When he got to class the next day, he realized that he measured the trees in inches instead of centimeters.
One tree had a circumference of 41 inches. What is the tree's circumference in centimeters?
Hint: 1 inch equals 2.5 cm
A.
102.5 cm
B.
27 cm
C.
135 cm
D.
16 cm
Answer:
[tex]\huge\boxed{\sf 102.5\ cm}[/tex]
Explanation:
Given that,
Circumference = C = 41 inches
Also,
1 inch = 2.5 cmMultiply 41 to both sides
41 inches = 2.5 × 41 cm
41 inches = 102.5 cm
So, The tree has a circumference of 102.5 cm.
[tex]\rule[225]{225}{2}[/tex]