The smallest of the even integers is 8.
It is a well-known fact that the sum of the first n odd numbers is n^2. This makes the sum of the first 8 odd numbers equal to 64.
Let n be equal to the smallest of the 5 even integers. Then (n+2) is the next highest, (n+4) even higher, and so on.
This sets up the equation n+(n+2)+(n+4)+(n+6)+(n+8)+4=64
Now we solve:
5n+24 = 64
5n = 40
n = 8
The smallest of the even integers is 8.
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Identify all of the root(s) of g(x) = (x2 3x - 4)(x2 - 4x 29). -1 1 -4 4 2 5i 2 - 5i -2 10i -2 - 10i
The roots are (x + 1), (x - 4), (2 + 5i), and (2 - 5i).
g(x) = (x2 - 3x - 4)(x2 - 4x + 29)
Let us first consider x^2 - 3x - 4
By splitting the middle term
= x^2 + 1x - 4x - 4
= x(x + 1) - 4(x + 1)
= (x + 1)(x - 4)
Now let us consider x^2 - 4x + 29
First group the terms with variable on LHS and move the constant on the other side
x^2 - 4x = -29
Add 4 on both sides
x^2 - 4x + 4 = -29 + 4
x^2 - 4x + 4 = -25
It can be written as perfect squares
(x - 2)^2 = -25
We know that
i =√1
Take square root on both sides
x - 2 = ± 5i
x = 2 ± 5i
So we get,
x = 2 + 5i and x = 2 - 5i
g(x) = (x + 1)(x - 4)(2 + 5i)(2 - 5i)
A square root of a number is a price that, whilst extended by means of itself, offers variety. instance: four × four = 16, so a square root of 16 is four. The word that (−four) × (−four) = 16 too, so −four is likewise a square root of sixteen. The symbol is √ usually way the wonderful rectangular root. example: √36 = 6 (because 6 x 6 = 36).
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Enter the correct answer in the box.
What is the inverse of function f?
f(x)=-7x-4
Answer:
The inverse is -1/7(x+4)
Step-by-step explanation:
We have the function
y = -7x-4
To find the inverse, exchange x and y
x = -7y -4
Solve for y
Add 4 to each side
x+4 = -7y -4+4
x+4 = -7y
Divide each side by -7
-1/7(x+4) = -7y/-7
-1/7(x+4) = y
The inverse is -1/7(x+4)
A property agent sells a house for $320 000, of which he receives a commission of 1.5 %.
Calculate the amount of commission the agent receives.
Help me to solve this question
Answer:
[tex]\left \{ {{\theta_1=\frac{\pi }{4} } \atop {\theta_2=\frac{3\pi }{4} }} \right. .[/tex]
Step-by-step explanation:
[tex]2*cos^2\theta-1=0\ \ \ \ (0^0\leq \theta\leq 360^0)\ \ \ \ \ \theta=?\\2*cos^2\theta-(sin^2\theta+cos^2\theta)=0\\2*cos^2\theta-sin^2\theta-cos^2\theta=0\\cos^2\theta-sin^2\theta=0\\cos2\theta=0\\0^0\leq \theta\leq 360^0\ \ \ \ \Rightarrow\\\left \{ {{2\theta=\frac{\pi }{2}\ |:2 } \atop {2\theta=\frac{3\pi }{2}\ |:2 }} \right. \ \ \ \ \left \{ {{\theta_1=\frac{\pi }{4} } \atop {\theta_2=\frac{3\pi }{4} }} \right. .[/tex]
Good luck and have a nice day!
Determine whether you would use the Law of Sines or the Law of Cosines to solve each triangle. Do not solve the triangle.
A triangle is a three-edged polygon with three vertices. Only the law of Sine can be applied to solve the triangle.
What is a triangle?A triangle is a three-edged polygon with three vertices. It is a fundamental form in geometry. The sum of all the angles of a triangle is always equal to 180°.
The sum of all three angles can be written as,
118° + 22° + x = 180°
x = 40°
For the sine rule to be applicable, two angles and a side or an angle and two sides are needed. Therefore, the law of Sine can be applied to solve the triangle.
For the cosine rule to be applicable, two sides and an angle between them is needed to be known, hence, the law of cosine can not be applied.
Hence, Only the law of Sine can be applied to solve the triangle.
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The area of a rectangular pool is (x 2 + 17x + 72) square meters. There is a 3-meter-wide concrete
walkway around the pool. Write expressions to represent the dimensions of the outside border of the
walkway. (Lesson 8.1)
Step-by-step explanation:
the area is
(x² + 17x + 72) m²
it is the result of the usual
length × width
calculation.
length = x + g
width = x + h
length × width = x² + gx + hx + ab = x² + (g+h)x + gh =
= x² + 17x + 72
g + h = 17
gh = 72
just by looking at it that gives us 9 and 8 as g and h.
FYI - formally to calculate them we can say
g = 17 - h
(17 - h)h = 72
17h - h² = 72
h² - 17h + 72 = 0
the solution to such a quadratic equation is
x = (-b ± sqrt(b² - 4ac))/(2a)
in our case
x = h
a = 1
b = -17
c = 72
h = (17 ± sqrt(17² - 4×1×72))/(2×1) =
= (17 ± sqrt(289 - 288))/2 = (17 ± 1)/2
h1 = (17 + 1)/2 = 18/2 = 9
h2 = (17 - 1)/2 = 16/2 = 8
as we can see
g = 17 - h
if we say h = 9, then g = 8.
if we say h = 8, then g = 9.
so, these are our solutions.
we simply pick that length is longer than width, so, g = 9, h = 8.
the area including the walkway is then
(length + 3)(width + 3) =
= (x + 9 + 3)(x + 8 + 3) = (x + 12)(x + 11) m²
and the dimensions incl. the walkway are
length = x + 9 + 3 = x + 12
width = x + 8 + 3 = x + 11
One side of a triangle is 10 feet long, the second side is 20 feet long. What is the
range of possible values for the third side of the triangle? Why?
The range for the length of the third side is it must be greater than 10 feet and less than 30 feet.
What is the condition for the sides of triangles?The triangle inequality states that the sum of the lengths of any two sides of a triangle must be greater than or equal to the length of the third side. That sum can equal the length of the third side only in the case of a degenerate triangle, one with collinear vertices.
The length of the third side had to be greater than the difference between the two given sides and less than the sum of the two given sides.
(20 – 10) < S <(20+ 10) ; 10< S < 30
Therefore, the range for the length of the third side is it must be greater than 10 feet and less than 30 feet.
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Write the interval using interval notation to describe the set of values shown above.
Use "U" between the two intervals. Use "oo" (two lower case o's) for
∞.
The interval on the number line is (-∞, 2) U [3, ∞)
How to determine the interval?From the number line, we have the following inequalities
x < 2 and x ≥ 3
In inequalities, < and > are represented by brackets i.e. ( and )
While ≤ and ≥ are represented by square brackets i.e. [ and ]
So, we have:
x < 2 and x ≥ 3 = 2) and [3
The intervals must be closed and opened with infinity symbols.
So, we have:
x < 2 and x ≥ 3 = (-∞, 2) and [3, ∞)
Replace and with U
x < 2 and x ≥ 3 = (-∞, 2) U [3, ∞)
Hence, the interval on the number line is (-∞, 2) U [3, ∞)
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The breaking strengths of cables produced by a certain manufacturer have historically had a mean of pounds and a standard deviation of pounds. The company believes that, due to an improvement in the manufacturing process, the mean breaking strength, , of the cables is now greater than pounds. To see if this is the case, newly manufactured cables are randomly chosen and tested, and their mean breaking strength is found to be pounds. Assume that the population is normally distributed. Can we support, at the level of significance, the claim that the population mean breaking strength of the newly-manufactured cables is greater than pounds
No, we cannot claim that the population mean breaking strength of the newly- manufactured cables is greater than pounds.
Given mean=1900, standard deviation=65, sample size=150, sample mean=1902, level of significance=0.01.
The hypothesis are:
[tex]H_{0}:\\[/tex]μ=1900
[tex]H_{1}:[/tex]μ>1900
We have to use z test as the sample size is large and we know the population standard deviation.
z=(x-μ)/σ/[tex]\sqrt{n}[/tex]
z=(1902-1900)/65/[tex]\sqrt{150}[/tex]
z=0.38
finding the p value:
p value=P(Z>z)
=P(Z>0.38)
=1-P(Z<0.38)
from the z table we get;
P(Z<0.38)=0.6480
Therefore p value=1-0.6480
=0.3520
If the p value is less than 0.01 then we reject the [tex]H_{0}[/tex] otherwise we will reject the null hypothesis.
In this problem we also reject the null hypothesis.
Hence we cannot claim that the population mean breaking strength of the newly- manufactured cables is greater than pounds.
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Question is incomplete. It should includes:
mean=1900,
standard deviation=65,
sample size=150,
sample mean=1902,
level of significance=0.01.
104, 137, 154, 131, x; mean= 130
Hello!
The mean is the average of the terms.
⇒ Mean = Sum of terms / Number of terms
⇒ 130 = 104 + 137 + 154 + 131 + x / 5
⇒ x + 526 = 650
⇒ x = 124
∴ The missing number is 124.
On a coordinate plane, quadrilateral J K L M with diagonals is shown. Point J is at (4, 5), point K is at (5, 1), point L is at (1, 2), and point M is at (1, 5).
Which statement proves that quadrilateral JKLM is a kite?
∠M is a right angle and MK bisects ∠LMJ.
LM = JM = 3 and JK = LK = StartRoot 17 EndRoot.
MK intersects LJ at its midpoint.
The slope of MK is –1 and the slope of LJ is 1.
The statement that proves that that quadrilateral JKLM is a kite is: (Option B) which indicates that:
LM = MJ = 3; a
JK = KL = √17
What is the explanation for the above?We know the following:
J = (4,5)
K = (5,1)
L = (1,2)
M = (1, 5)
What is the proof?We must commence by computing the length of the sides of the quadrilateral using:
D = [tex]\sqrt{((x1-x2)^{2} + (y1 -y2)^{2} }[/tex]
JK = [tex]\sqrt{(4-5)^{2} + (5-1)^{2} }[/tex]
= [tex]\sqrt{17}[/tex]
KL = [tex]\sqrt{(5-1)^{2} + (1-2)^{2} }[/tex]
= [tex]\sqrt{17}[/tex]
LM = [tex]\sqrt{(1-1)^{2} + (5-5)^{2} }[/tex]
= [tex]\sqrt{9}[/tex]
= 3
MJ = [tex]\sqrt{(1-4)^{2} + (5-5)^{2} }[/tex]
= [tex]\sqrt{9}[/tex]
= 3
From the above, it is clear that
LM = MJ = 3; and
JK = KL = [tex]\sqrt{17}[/tex]
QED
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Answer: B
Step-by-step explanation:
Susan's calculator has a key that replaces the number displayed with its cube. If a² is displayed, how many times must Susan press the " cubing" key to display a number that is greater than 10^9?
Please explain it step-by-step! Also, I will give you a brainlist!!
If we want to replace a input and display an output greater than 10⁹ in Susan's calculator, then we want at least 3 consecutive operations.
How to determine a power by a "cubing" key
In accordance with the statement, Susan's calculator performs the following operation by pressing the "cubing" key:
x → x³
If we need to display a number that is greater than 10⁹, then we need to press the "cubing" key as many as needed. By algebra we have the following property for a power:
[tex](x^{m})^{n} = x^{m\cdot n}[/tex] (1)
Since we have a "cubing" key and we are supposed to make consecutive operation, we derive the following operation:
x → [tex]x^{3^{i}}[/tex], where i is the number of consecutive "cubing" operations.
If we want to replace a input and display an output greater than 10⁹ in Susan's calculator, then we want at least 3 consecutive operations.
Remark
The statement presents typing mistakes, correct form is shown below:
Susan's calculator has a key that replaces the number displayed with its cube. If a³, is displayed, how many time must Susan press the "cubing" key to display a number that is greater than 10⁹.
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For the following exercises, determine whether the relation is a function.
1. {(a, b), (c, d), (e, d)}
Answer:
The given relation [tex]$\{(a, b),(c, d),(e, d)\}$[/tex] is a function.
Step-by-step explanation:
A relation [tex]$\{(a, b),(c, d),(e, d)\}$[/tex] is given.
It is required to determine whether the given relation is a function.
To determine whether the given function is a relation, identify the domain and range and then check whether the given relation is a function.
Step 1 of 1
The given relation is {(a, b),(c, d),(e, d)}.
The set of the first components of each ordered pair is called the domain.
From the relation, the domain is {a, c, e}.
The set of the second components of each ordered the range.
From the relation, the range is {b, d, d}.
The given relation is a function. But it is not a one-to-one function.
GIVING BRAINLIEST TO THE BEST ANSWER! Choose the proportion to use to solve side LM.
A. 9/13.5 = x/11
B. 9/11 = 13.5/x
C. 9/13.5 = x/21
D. 9/11 = x/21
(the / represents fractions)
The equation that can be used to find the proportion to use to solve side LM is 9/13.5 = 14/LM
Similarity theorem of triangleIn order to find the measure of LM, we will take the ratio of the sides of the similar triangles.
Using the equation as shown
DF/EF = LK/LM
DF/LK = EF/LM
Substitute the measure of the sides
9/13.5 = 14/LM
Hence the equation that can be used to find the proportion to use to solve side LM is 9/13.5 = 14/LM
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What are the domain and range of the exponential function below?
F(x) = 4x + 3
A. Domain: All real numbers Range: All real numbers greater than 0
B. Domain: All real numbers greater than 0 Range: All real numbers greater than 3
C. Domain: All real numbers greater than 0 Range: All real numbers greater than 0
D. Domain: All real numbers Range: All real numbers greater than 3
The domain and the range of the function are all set of real numbers
How to determine the domain and the range?The function is given as:
f(x) = 4x + 3
The above function is a linear function
Linear functions have a domain and a range of all set of real numbers
Hence, the domain and the range of the function are all set of real numbers
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ABC is a right angled triangle. If b=90 ac=96 c=30. What is ab?
Answer:
ab=48
Step-by-step explanation:
96/2=48
Rationalize 5+2√3 / 7+4√3
Answer:
Answer is in the 2nd attachment
Step-by-step explanation:
the first attachment is the work done.
The difference of two complementary angles is 48. Find the measures of the two angles.
The smaller angle is
Submit Question
and the larger angle is
B
The larger angle is 55 deg at the larger angle.
We have to know which angles are called Complementary Angles...
if we add two angles and the total will be equal to 90 deg
let's say one angle is x and another angle is y
as they are complementary angles from the definition we can write the equation x + y = 90
one angle is 20 deg more than another one so from the above condition we write x = 20 + y
Substitute the value of x in the first eaquation we get, 20 + y + y = 90
Then, 20 + 2y = 90
subtracting 20 from both sides,
2y = 90-20 = 70
dividing both sides by 2,
2y/ 2 = 70 / 2
y = 35
So we got one angle is 35 deg
another angle is 35 + 20 = 55 deg.
Our answer is 55 deg the larger angle.
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Pls help on algebra homework. Will mark brainliest!
Answer:
H)
Step-by-step explanation:
First, Length XY is 20 centimeters. Since YZ = 3/5 XY, [tex]\frac{3}5\times20=12[/tex]
YZ = 12 + 20 = 32 cm, hence H)
Hope you have a nice day! (Pls mark brainliest)
1. Annie and her friends are playing a game called Doubles. In the game, a player
rolls two number cubes at the same time. The outcome of each roll is the sum of the
two number cubes. Extra points are scored for rolling doubles the same number
on both number cubes.
-
Part A: Complete this table to show the sample space for each roll in the game. (6
points)
HELP ASAP WILL GIVE BRAINLIEST!!!!
The sample space is a combination of these two dice as we have shown in the attachment
Die A = {1,2,3,4,5,6}Die b = {1,2,3,4,5,6}What is sample space?This is the defined to be the set of all of the possible outcomes that can exist or be possible in a random experiment.
The question has two dice. These dice are made up of numbers from 1 to 6 each.
Die A = {1,2,3,4,5,6}
Die b = {1,2,3,4,5,6}
The sample space would be pairs of two of these two dices. The total number in the sample space would be 36.
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Class A has 30 pupils and class B has 26 pupils.
Both classes sit the same maths test.
The mean score for class A is 70.
The mean score for both classes is 76.
What is the mean score (rounded to 2 DP) in the maths test for class B?
The mean score of class B is 82. 92
How to determine the mean scoreClass A = 30 pupils
Class B = 26 pupils
Mean score for class A = 70
Mean score of class B = unknown
Total mean score = 76
We have, [tex]\frac{(76 *( 30 + 26) - 70 *30) }{26}[/tex]
Then simply,
Calculate the sum or difference between the classes = [tex]\frac{76 * 56 - 70 * 30}{26}[/tex]
Calculate the product or quotient of the classes = [tex]\frac{4256 - 70 * 30}{26}[/tex]
= [tex]\frac{4256 - 2100}{26}[/tex]
= [tex]\frac{2156}{26}[/tex]
= [tex]\frac{1078}{13}[/tex]
= [tex]82. 92[/tex]
Thus, the mean score of class B is 82. 92
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Write an equation for the graph below in terms of x
Select the correct answer.
Select the simplification that accurately explains the following statement.
3/7 = 73
O A.
100
B.
3
(71)² = 73.71.7371-1-1 = 78 = 7² = 7
(71)² = 78.73.7} = 7.73 = 3-1-7=1-7=7
3
C.
(7³)³ = 7³. 7³. 73 = 73 + } + ³ = 7³ = 7¹ = 7
D. (73)³ = 7³. 73. 73 = 7 · (++) = 7 ⋅ = 7 · 1 = 7
The simplification that represents ∛7=[tex]7^{1/3}[/tex] is [tex](7^{1/3} )^{3} =7^{1/3} .7^{1/3} .7^{1/3} =7^{1/3+1/3+1/3} =7^{1}=7[/tex]
How to simplify an expression?The simplification that accurately explains the statement ∛7 = [tex]7^{1/3}[/tex] is as follows;
Therefore, the simplification is as follows
[tex](7^{1/3} )^{3} =7^{1/3} .7^{1/3} .7^{1/3} =7^{1/3+1/3+1/3} =7^{1}=7[/tex]
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For the following exercises, find the x- and y-intercepts of the graphs of each function.
27. f(x) = −3| x − 2 | − 1
For the function f(x) = -3|x - 2| - 1, we have that:
The function has no x-intercepts.The y-intercept is of y = -7.What is the x-intercept of a function?The x-intercept of a function is the value of x when y = f(x) = 0, hence:
0 = -3|x - 2| - 1
-3|x - 2| = 1
|x - 2| = -1/3
The absolute value cannot be negative, hence the function has no x-intercepts.
What is the y-intercept of a function?The x-intercept of a function is the value of y = f(x) when x = 0, hence:
f(0) = -3|0 - 2| - 1 = -6 - 1 = -7.
The y-intercept is of y = -7.
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How many real solutions does this system of equations have? x² + y² = 25 and x-3y=15
[tex]x - 3y = 15 \\ x = 15 + 3y[/tex]
[tex](15 + 3y) {}^{2} + y {}^{2} = 25[/tex]
[tex]225 + 90y + 9y {}^{2} + y {}^{2} = 25[/tex]
[tex]10y {}^{2} + 90y + 200 = 0[/tex]
[tex]y {}^{2} + 9y + 20 = 0[/tex]
[tex](y + 4)(y + 5) = 0[/tex]
[tex]y = - 4 \: \: \: \: \: \: y = - 5[/tex]
[tex]for \: y= - 4 \\ x = 15 + 3( - 4) = 15 - 12 = 3[/tex]
[tex]for \: y = - 5 \\ x = 15 + 3( - 5) = 15 - 15 = 0[/tex]
mrs chapagain borrowed rs 9900 from a bank at the rate of 8% per annum. how much amount should she pay at the end of 2 years
Answer:
If compounding = rs 11547.36
If not compounding = rs 11484
a triangle with base 14, sides 12 and 6, and height 5. what is the area of the triangle? a = one-half(14)(6) = 42 square units a = one-half(12)(5) = 30 square units a = one-half(14)(5) = 35 square units a = one-half(6)(5) = 15 square units
The triangle with base 14, sides 12 and 6, will have an area, a = (1/2)(14)(5) = 35 square units. Hence, the 3rd option is the correct choice.
The area of a plane figure is the space occupied within its boundary.
The area of a triangle is given as,
a = (1/2)(b)(h) sq. units, where a is the area of the triangle, b is its base, and h is its height.
In the question, we have been given a triangle with a base of 14, sides 12 and 6, and a height of 5.
We are asked to determine the area of this triangle.
To determine the area of the triangle, we will use the formula:
a = (1/2)(b)(h) sq. units, where a is the area of the triangle, b is its base, and h is its height.
Now, we are given that the base is 14 and the height is 5, thus substituting b = 14, and h = 5, in the above formula, we get:
a = (1/2)(14)(5) sq. units.
or, a = 35 sq. units.
Comparing this with the given options, we can choose the third option.
Thus, the triangle with base 14, sides 12 and 6, will have an area, a = (1/2)(14)(5) = 35 square units. Hence, the 3rd option is the correct choice.
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I really need help asap! ty!
The length of AL in the triangle is 12cm.
How to calculate the value?From the information given, angle C = 90° and BAC is given as 2ABC.
In this case, the length of angle BC is given as 24cm. Therefore, the length of AL will be:
= 24/2
= 12..
Therefore, AL = 12cm
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Find the area in square centimeters of the composite, shape shown
below. Enter only a number as your answer.
A
11 cm
B
E
13 cm
18 cm
D
7 cm
C
The area of the composite shape is 136 square cm
Area of a composite functionThe area of the composite function is expressed as;
Area = area of triangle + area of rectangle
Area of the composite shape = (1/2* 4 * 5) + (7*18)
Area of the composite shape = 10 + 126
Area of the composite shape = 136 square cm
Hence the area of the composite shape is 136 square cm
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CAN SOMEONE HELP ME
Triangle not drawn to scale
Given: measure of angle A = 15 degrees, b = 16, and
c = 18. What is the length of a to the nearest tenth?
Answer:
a ≈ 4.9
Step-by-step explanation:
using the Cosine Rule in Δ ABC
a² = b² + c² - (2bc cosA )
= 16² + 18² - (2 × 16 × 18 × cos15° )
= 256 + 324 - (576cos15° )
= 580 - 576cos15
= 23.6267 ( take square root of both sides )
a = [tex]\sqrt{23.6267}[/tex]
≈ 4.9 ( to the nearest tenth )