With lower, the mechanics have to work harder to give water. Resulting in faster spray. But with upper, they do not have to work as hard which makes it not work as fast.
1. What is meant by the phrase, "a sound mind and a sound
body'?
Answer:
A sound mind in a sound body implies that you're capable of positive thinking for a better quality of life and physical functioning. When you exercise, your body releases endorphins, a chemical that triggers a positive response in the body. This shows that the more you sweat, the better you feel about yourself.
Explanation:
Which type of heat transfer takes place in gases by the movement of particles through a medium?
Answer: Convention
Explanation: Convention is pretty well known for being a process that transmits heat from one place to another place with the movements of heated particles. I got this answer from my notebook during my chemistry class.
Hope this answer helps!
What does the skeletal consist of?
Answer:
Bones
Explanation:
Answer:
The skeletal system is your body's central framework. It consists of bones and connective tissue, including cartilage, tendons, and ligaments. It's also called the musculoskeletal system.
Explanation:
CAN YOU GIVE ME BRAINLIEST
A jet plane flying 600 m/s experiences an acceleration of 39.24 m/s² when pulling out of the circular section of a dive. What is the radius of curvature of this section of the dive?
The options are:
1.2 km
5.8 km
0.64 km
9.2 km
7.0 km
Answer:
Explanation:
If we are to assume that the plane is at the bottom of a circular movement and just about to depart in level flight, then
(39.34 - 9.81) = 600²/R
R = 12,190.992211... m
Which is very close to the 1.2 km option
how high will a 2 liter bottle rocket go with 0.5 L of water at 50 psi
Answer:
the high will a 2 l bottle of rocket go with 0.5 l of water at 50 psi
Explanation:
[tex]2)50( \\ divide \: karo \: or \: 0.51 \: ko \: into \: kar \: do \\ \\ [/tex]
If you throw a ball up into the air and it reaches its original height after 6 seconds, calculate how high above its original position the ball reached. (Answer to two decimal places).
Explanation:
Assuming that there is no air resistance, the given time means that the ball reached its maximum height 3 seconds after throwing it upwards so we can solve its
maximum height by solving for [tex]v_{0y}[/tex] first:
[tex]v_y = v_{0y} - gt \Rightarrow v_{0y} = gt[/tex]
[tex]v_{0y} = (9.8\:\text{m/s}^2)(3\:\text{s}) = 29.4\:\text{m/s}[/tex]
Now that we know [tex]v_{0y},[/tex] we can now solve for [tex]y_{max}:[/tex]
[tex]y_{max} = v_{0y}t - \frac{1}{2}gt^2[/tex]
[tex]\:\:\:\:\:\:=(29.4\:\text{m/s})(3\:\text{s}) - \frac{1}{2}(9.8\:\text{m/s}^2)(3\:\text{s})^2[/tex]
[tex]\:\:\:\:\:\:=44.1\:\text{m}[/tex]
A plane flying due north at 191 mph encounters winds that blow the plane due east at 45 mph. Determine the plane's resultant velocity. Record your answers to the nearest tenth.
Answer:
Below
Explanation:
For these types of questions, you should draw out your triangles and resultant vectors.
For this, we can use the pythagorean theorem to solve this :
vpf^2 = vpi^2 + vw^2
vpf^2 = 45^2 + 191^2
vpf = [tex]\sqrt{38507[/tex]
vpf = 196.2294
vpf = 200 mph
Now we need to find the angle of the plane's direction using soh cah toa
Tan(x) = O / A
x = tan^-1(191/45)
x = 76.74
x = 77 degrees
Therefore, the plane's result velocity is 200 mph [ E 77 N ]
Hope this helps!
4. Which are characteristics of an atom? (Choose all that apply.)
1)They come from compounds.
2)They are the largest unit of matter.
3)They are made in stars.
4)They can only be seen by an electron microscope.
Answer:
4.
Explanation:
The characteristic of an atom is as follows:
They can only be seen by an electron microscope.Thus, the correct option for this question is D.
What do you mean by an Atom?An atom may be defined as a particle of matter that uniquely defines a chemical element. Each and every atom consists of a central nucleus that holds positively charged subatomic particles known as Protons along with neutrons.
Apart from protons and neutrons, the negatively charged subatomic particles known as electrons are always revolved around the nucleus of each atom in its orbitals.
According to the context of this question, an atom is the smallest unit of matter which significantly retain all the chemical properties of an element. Thus, the second option is eliminated. They are naturally present not made in stars. So, the option third is also eliminated.
Therefore, the correct option for this question is D.
To learn more about Atoms, refer to the link:
https://brainly.com/question/6258301
#SPJ2
u= (-5,3) find the magnitude of u. please help me
u = 5.83
Explanation:
The magnitude of a vector [tex]\vec{u}[/tex] is
[tex]|\vec{u}| = \sqrt{u_z^2 + u_y^2} = \sqrt{(-5)^2 + (3)^2}[/tex]
[tex]\:\:\:\:\:\:\:= \sqrt{34} = 5.83[/tex]
what are triglycerides?
Answer:
an ester formed from glycerol and three fatty acid groups. Triglycerides are the main constituents of natural fats and oils.
Explanation:
HOPE IT HELPS
Answer:
is the answer.......,...............
When do you know if Respect is being shown? If there is discrimination? Cite some indicators
Peace and violence are the indicators of the society.
Respect is shown if we see a people as a person and not as a toy. If we stop criticizing and judging by just looking at them than the other person also gives us respect which leads to peace and harmony in the society.
If there is discrimination and no respect of other people's feeling then there is violence and disharmony in the society so we can conclude that peace and violence are the indicators of the society.
Learn more: https://brainly.com/question/25002091
transformer is used in rectifier step up and step down voltage?
Answer:
While the use of the type of transformer in a rectifier depends on the voltage requirement or to meet desired operating conditions, a step-down transformer is used mainly to reduce the voltage. It is used to bring the high AC voltage level to a reasonable value or the desired output voltage.
Explanation:
Hope it helps
Correct me if Im wrong
feminine of mouse
please let me know
Answer:
a Doe
A baby mouse is called a 'pinky', a male is called a 'buck' and a female is called a 'doe'.
(hope that helped)
There are 100000 billion billion ......systems
define THERMODYNAMICS
Thermodynamics is the branch of physical science that deals with the relations between heat and other forms of energy (such as mechanical, electrical, or chemical energy), and, by extension, of the relationships between all forms of energy.
How did kepler develop his second law of motion ?
A. He invented a telescope that was strong enough to view all plants of the solar system along their orbits
B. He compared data of planetary motion at different times along orbits
C. He made accurate measurements of the positions of all the planets over many years
D. He used a telescope to carefully follow and time the orbital motion of mars
He developed his second law of motion by using a telescope to carefully follow and time the orbital motion of mars .
What is a Telescope?This is a device which is used to form magnified images of distant objects. Kepler used it to observe the orbit motion of mars.
He discovered that planets do not move with constant speed along their orbits which led to his second law of motion.
Read more about Kepler second law of motion here https://brainly.com/question/7540858
Place the yellow, 25g ball at 60 cm on the ramp. How far did the box move? Measure from the left side of the box.
Answer: approximately 13-15 centimeters
An ideal gas occupies a volume of 1cm^ atv20°c and atmospheric pressure determine the number of molecules of gas in the container
Answer:
By Charles Law the volume of 1 cm^3 at standard conditions is
V = V0 * 273 / 293 = 1 cm^3 * .932 cm^3
Reducing the temperature to 0 deg C results in a volume of .932 cm^3
1 mole of gas contains 22.4 L of gas
1 L = 1000 cm^3
1000 cm^3 / L / (.932 cm^3 / container) = 1073 containers / L
So 1 mole of gas = 1073 containers * 22.4 L /container = 24,305 L
6.02E23 molecules / mole * 1 / 24305 molecules / mole = 2.48E19
number of molecules present = 2.48 * 10^19
(Easier to calculate volume of 1 cc
1 cc = 6.02E23 / (1000 * 22.4) = 2.69E19 molecules in 1 cc
Vol of 1cc = 273 / 293 = .932
2.69E19 * .932 = 2.51 * 10^19)
Which of the following has the greatest momentum? (Hint: momentum = mass x velocity)
a. a 4.0 kg bowling ball moving at 2.0 m/s
b. a 0.15 kg baseball moving at 10.0 m/s
c. a 1.6 x 10^3 kg car moving at 0.5 m/s
d. a 2 kg bullet moving at 950 m/s
Answer:
therefore, the correct answer is Option D.
Explanation:
a. 4×2=8kgm/s
b. 0.15×10=1.5kgm/s
c. 1.6×10³×0.5=800kgm/s
d. 2×950=1900kgm/s.
hope this helps you
Which of these sets of thesis-antithesis IS NOT appropriate according to the instructions given by your instructor because it is too broad?
celera
An
A force F = 89.2 N acts at an angle a = 38°
with respect to the horizontal on a block of
mass m = 26.8 kg, which is at rest on a
horizontal plane.
The acceleration of gravity is 9.81 m/s2.
If the static frictional coefficient is pls
0.74, what is the force of static friction?
=
Hi there!
We know that the MAXIMUM static friction force to be overcome is:
Fs (Force of Static Friction) = μN (Normal Force)
The normal force is equal to the weight of the block AND the vertical component of the applied force, so:
N = Mg + Fasinθ
Plug in the given values:
N = 26.8(9.81) + (89.2)sin(38) = 317.825 N
Multiply by the force of static friction to derive the static force:
0.74 * 317.825 = 325.191 N <-- MAXIMUM STATIC FRICTION FORCE
The force applied, if not greater than this value, will result in an EQUAL and OPPOSITE static frictional force. Thus:
Fs = Horizontal component of the applied force
Fs = 89.2cos(38) = 70.291 N
1. production of a ____often caused by fizzing and_____
2.Produces an____
Change in____ or_____ (heat, light, sound)
The depth of a pond is 1.5m. Calculate the pressure caused by the water at the bottom of the pond.
[tex]\\ \sf\longmapsto Pressure=\dfrac{Force}{Area}[/tex]
[tex]\\ \sf\longmapsto Pressure=\dfrac{10}{2.25}[/tex]
[tex]\\ \sf\longmapsto Pressure=4.4Pa[/tex]
Answer:
Area=1.5(1.5)=2.25m^2
Force of gravity=10N
\begin{gathered}\\ \sf\longmapsto Pressure=\dfrac{Force}{Area}\end{gathered}
⟼Pressure=
Area
Force
\begin{gathered}\\ \sf\longmapsto Pressure=\dfrac{10}{2.25}\end{gathered}
⟼Pressure=
2.25
10
\begin{gathered}\\ \sf\longmapsto Pressure=4.4Pa\end{gathered}
⟼Pressure=4.4Pa
DUE IN 3 HOURS! PLEASE HELP AND SOLVE A-E.
For a projectile with initial velocity of 51.5 m/s and angle of elevation equal to 4 degrees.
a) Compute the horizontal velocity of the projectile in m/s.
b) Compute the vertical velocity in m/s.
c) Compute the time of flight for the projectile.
d) Compute the distance downrange.
e) Compute the maximum height reached by the projectile.
Answer:
Below
Explanation:
c) To find the time of flight of a projectile (assuming from the given information that there is no vertical displacement) you can use this formula :
t = 2(Vi) Sinx / g
t = 2(51.5m/s) Sin(4) / 9.8 m/s^2
t = 0.733 seconds
t = 0.73 seconds
d) To find the displacement in the x-direction you can use this formula :
dx = vi^2 sin(2x) / g
dx = (51.5m/s)^2 sin(2(4)) / 9.8m/s^2
dx = 37.6654 m
dx = 37.7 meters
e) To find the peak height of the projectile you can use this formula :
v^2sin^2(x) = 2gh
(51.5m/s)^2sin^2(4) = 2(9.8m/s^2)h
h = 0.658 meters
h = 0.66 meters
Hope this helps! Best of luck <3
Một ròng rọc có dạng khối lượng 3kg, bán kính 20cm, người ta treo hai quả nặng có khối lượng m1= 2kg và m2 = 5kg vào hai đầu một sợi dây vắt qua một ròng rọc có trục quay cố định nằm ngang, sợi dây không dãn và không trượt trên ròng rọc. Lấy gia tốc trọng trường g = 10m/s2g. Gia tốc của các vật là bao nhiêu?.
Answer:Một ròng rọc có dạng khối lượng 3kg, bán kính 20cm, người ta treo hai quả nặng có khối lượng m1= 2kg và m2 = 5kg vào hai đầu một sợi dây vắt qua một ròng rọc có trục quay cố định nằm ngang, sợi dây không dãn và không trượt trên ròng rọc. Lấy gia tốc trọng trường g = 10m/s2g. Gia tốc của các vật là bao nhiêu
Explanation:
A light, inextensible cord passes over a light,
frictionless pulley
with a radius of 7.2 cm
It has a(n) 16 kg mass on the left and a(n)
6.7 kg mass on the right, both hanging freely.
Initially their center of masses are a vertical
distance 4.2 m apart.
The acceleration of gravity is 9.8 m/s^2
The question tied to it is…
What is the tension
in the cord when they
pass each other?
Answer in units of N.
Answer: T = 93 N
Explanation:
Assuming the pulley is ideal meaning frictionless as mentioned and also negligible mass.
ΣF = Σma
Mg - mg = Ma + ma
a = g(M - m) / (M + m)
Now looking only at the larger mass as it falls
Mg - T = Ma
T = Mg - Ma
T = Mg - Mg(M - m) / (M + m)
T = Mg(1 -(M - m) / (M + m))
T = 16(9.8)(1 - (16 - 6.7) / (16 + 6.7))
T = 93 N
or looking only at the smaller mass
T - mg = ma
T = m(g + a)
T = m(g + g(M - m) / (M + m))
T = mg(1 + (M - m) / (M + m))
T = 6.7(9.8)(1 + (16 - 6.7) / (16 + 6.7))
T = 93 N
A shopper is pushing a cart down a grocery store aisle. Starting from rest, the shopper applies a constant force to the cart for 4.0 s. From t = 4s until t = 4 s until t = 8 s, the shopper applies just enough force to balance the friction on the cart. Finally, the shopper applies a constant force to slow the cart until it comes to rest att = 12 s. The resulting position-time graph is shown below. What is the average acceleration of the shopping cart during its 12s motion?
A shopping cart that starts from rest, is accelerated for 4 s, moves at constant velocity for 4 s, and is decelerated for 4s until returning to rest, has an average acceleration of 0 m/s².
A shopper is pushing a cart down a grocery store aisle. The movement of the cart is:
It starts from rest.From t = 0 s to t = 4.0 s it is accelerated with a constant force.From t = 4 s to t = 8.0 s it receives just enough force to balance the friction on the cart.From t = 8 s to t = 12 s it is decelerated until it comes to rest.All in all, at the initial time (t = 0 s), the velocity is 0 m/s (rest) and at the final time (t = 12 s) the velocity is 0 m/s as well (rest). The average acceleration in that period is:
[tex]a = \frac{v_{12}-v__o}{t_{12}-t_0} = \frac{0m/m-0m/s}{12s-0s} = 0 m/s^{2}[/tex]
A shopping cart that starts from rest, is accelerated for 4 s, moves at constant velocity for 4 s, and is decelerated for 4s until returning to rest, has an average acceleration of 0 m/s².
Learn more: https://brainly.com/question/16274121
Answer:0 m/s2
Explanation: Cus i said so.
You attach a cart with a mass of 0.92 kg to a spring and compress the cart-
spring system. The spring constant for the spring is 130 N/m. Your objective is
to propel the cart with a velocity of 1.4 m/s along a frictionless surface. How
need to compress the spring in order to meet your target velocity?
far do
you
Answer:
F = - K X force exerted by compressed spring
F X = 1/2 M V^2 energy (work) required to produce a speed V for mass M
K X * X = 1/2 M V^2 direction of F is the same as that of V
X^2 = M V^2 / K combining terms
X = (M / K)^1/2 V
X = (.92 / 130)^1/2 * 1.4 = .118 m
An elevator cable winds on a drum of radius 77.1 cm that is connected to a motor.
If the elevator moves down 8.60 m, how many revolutions has the drum made?
Figure 10.20 in your textbook shows an energy diagram for a system with total energy E1. Suppose the system's total energy is E2 = (1/3)E1. In what ways could the particle move?
Select all that apply.
a.) It could remain at rest at x3.
b.) It could oscillate between x1 and x5.
c.) It could undergo small oscillations around x2.
d.) It could undergo small oscillations around x3.
e.) It could undergo small oscillations around x4.
Please explain why, I have an exam coming up and want to understand the concept.
The particles can undergo small oscillations around x₂.
The given parameters;
initial energy of the particles = E₁final energy of the particles, E₂ = 0.33E₁The movement of the particles depends on the kinetic energy of the particles.
When kinetic energy of the particles is 100%, the particles can oscillate from x₁ to x₅.
However, when the total energy of this particles is reduced to one-third (¹/₃) or 33% of the initial energy of the particle, the oscillation of the particles will be reduced.
The maximum position the particle can oscillate is x₅The half position the particles can oscillate is x₃Since 33% is less than the half of the energy of the particle, the particle will oscillate between x₁ and x₂.
Thus, we can conclude that the particles can undergo small oscillations around x₂.
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