The solution (-4,0) is a solution to which of the following equations? How do you know?
a)3y-x=4
b)10x+1/2y=3
c)-2x-3y=-4
d)-6x+2y=24

Answer:

-3125

Hope this helps!!

Answer: F

Step-by-step explanation:

Answer:

bottom left

Step-by-step explanation:

when divideing/mult by neg number, sign flips.

Using linear function concepts, it is found that representation of the value of -4.8 is given by:

It means that there are 4.8 thousand less sales for every dollar the price is increased.

A linear function is modeled by:

y = mx + b

In which:

In this problem, the model for the number of sales(in thousands), with the price at x dollars, is given by:

f(x) = -4.8x + 121.02.

The slope is of -4.8, which means that when x increases by 1, y decreases by 4.8 thousand, hence the correct option is given by:

It means that there are 4.8 thousand less sales for every dollar the price is increased.

More can be learned about linear function concepts at https://brainly.com/question/24808124

#SPJ1

Answer:

it 288

Step-by-step explanation:

if u multiply 24x12 it gives you 288 hope this help you

[tex]\\ \rm\Rrightarrow \sqrt{x²-10x+25}[/tex]

[tex]\\ \rm\Rrightarrow \sqrt{x²-5x-5x+25}[/tex]

[tex]\\ \rm\Rrightarrow \sqrt{x(x-5)-5(x-5)}[/tex]

[tex]\\ \rm\Rrightarrow \sqrt{(x-5)(x-5)}[/tex]

[tex]\\ \rm\Rrightarrow \sqrt{(x-5)^2}[/tex]

[tex]\\ \rm\Rrightarrow\pm (x-5)[/tex]

Solution set(for x-5)

for 5-x

Answer:

First, simplify the expression under the square root sign by factoring:

[tex]\implies x^2-10x+25[/tex]

[tex]\implies x^2-5x-5x+25[/tex]

[tex]\implies x(x-5)-5(x-5)[/tex]

[tex]\implies (x-5)(x-5)[/tex]

[tex]\implies (x-5)^2[/tex]

Therefore:

[tex]\implies \sqrt{x^2-10x+25}=\sqrt{(x-5)^2}[/tex]

[tex]\implies \sqrt{x^2-10x+25}=\pm(x-5)[/tex]

[tex]\implies \sqrt{x^2-10x+25}=|x-5|[/tex]

As the domain is -5 ≤ x < 5, then:

[tex]\implies y=-x+5[/tex]

and the range is 0 < y ≤ 10

Answer:

6x+8

Step-by-step explanation:

2(3x+4)= 2(3x) + 2(4) = 6x+8

Answer:

true

Step-by-step explanation:

yas

Answer:

the region of the graph where the shaded regions of the graph of each inequality overlap, or where the regions intersect

Step-by-step explanation:

Answer:

3,600

Explanation:

There's nine thousand numbers here, 4,500 of which are even, you will need to subtract mutiples of five from this number, making it even smaller.

subtract the non-even five's (exactly half of the 1800 hundred fives that fit in our little original number, (900!) ) 4,500-900= 3,600. Which should be your answer. :D

Step-by-step explanation:

To find the point of symmetry:

  ⇒ must find where the distance between the original point and the

   line of symmetry and reflected point and the line of symmetry are

   equally distant from each other

Based on that knowledge:

 ⇒ the image appears to be entirely reflected horizontally

    ⇒ when the line of symmetry is the y-axis

        ⇒ A, A' equal distant from line of symmetry

        ⇒ B, B' equal distant from line of symmetry

        ⇒ C, C' equal distant from line of symmetry

Answer: y- axis

Hope that helps!

Answer:

If we square both sides then we get

x2-8x+16 = (x-4)2

Now if we expand the right side of the equation we get

x2-8x+16 = (x-4)(x-4)

x2-8x+16 = x2-8x+16

So no matter what x is, the right side will be equal to the left side.

However, if we look at the original equation on the left side, √(x2-8x+16) , the value under the square root symbol has to be greater than or equal to zero (otherwise we get an imaginary number and you might not be working with those yet)

Step-by-step explanation:

So in order for √(x2-8x+16) to be greater than or equal to zero, x has to be greater than or equal to 4. If x is less than 4 you get a negative number. If x is greater than 4, you'll get the same answer on both sides no matter what x is

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

Let's solve ~

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ {x}^{2} - 8x + 16} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ {x}^{2} - 4x - 4x + 16} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ {x}^{} (x - 4) - 4(x - 4)} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ (x - 4)(x - 4)} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ (x - 4) {}^{2} } [/tex]

[tex]\qquad \sf  \dashrightarrow \: x - 4[/tex]

Now, it's given that ~

[tex]\qquad \sf  \dashrightarrow \:x \geqslant 4[/tex]

plug the value of x as 4 :

[tex]\qquad \sf  \dashrightarrow \:4 - 4[/tex]

[tex]\qquad \sf  \dashrightarrow \:0[/tex]

So, we can infer that :

Value of the required expression lies in :

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ {x}^{2} - 8x + 16} \geqslant 0[/tex]

it's value is always greater than pr equal to 0, satisfying the given condition ~

Answer:

See below

Step-by-step explanation:

each term is the sum of the two before it

2 3 5 8 13 21 34

Answer:

m = [tex]\frac{1}{2}[/tex] , c = [tex]\frac{5}{2}[/tex]

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

given

y + 2x = 4 ( subtract 2x from both sides )

y = - 2x + 4 ← in slope- intercept form

with slope m = - 2

given a line with slope m then the slope of a line perpendicular to it is

[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{-2}[/tex] = [tex]\frac{1}{2}[/tex] , then

y = [tex]\frac{1}{2}[/tex] x + c ← is the partial equation

to find c substitute (3, 4 ) into the partial equation

4 = [tex]\frac{3}{2}[/tex] + c ⇒ c = 4 - [tex]\frac{3}{2}[/tex] = [tex]\frac{5}{2}[/tex]

y = [tex]\frac{1}{2}[/tex] x + [tex]\frac{5}{2}[/tex] ← equation of line

with m = [tex]\frac{1}{2}[/tex] and c = [tex]\frac{5}{2}[/tex]

Answer:

Step-by-step explanation:

Minimum: 2

Quartile Q1: 4.5

Median: 10

Quartile Q3: 15

Maximum: 19

Answer:

(-1, -5)

(0, -2)

(-3, -11)

Step-by-step explanation:

y = 3x - 2.

→ 3×(-2)-2=-8 ≠0 ⇒(-2, 0) doesn’t correspond to input-output pairs for the function

→ 3×(-1)-2=-5 ⇒(-1, -5) corresponds to input-output pairs for the function

→ 3×(0)-2=-2 ⇒(0, -2) corresponds to input-output pairs for the function

→ 3×(2)-2=4≠3 ⇒(2, 3) doesn’t correspond to input-output pairs for the function

→ 3×(-3)-2=-11 ⇒(-3, -11) corresponds to input-output pairs for the function

Answer:

0 pars

Step-by-step explanation:

3-3=0

Answer:

SolutioN :

[tex] \bf \: \star ( - 3x^{2} + 4x) + (2 {x}^{2} - x - 11)[/tex]

[tex] \longrightarrow \bf \: - 3 {x}^{2} + 4x + 2 {x}^{2} - x - 11[/tex]

[tex] \longrightarrow \bf \: - 3 {x}^{2} + 2 {x}^{2} + 4x - x - 11[/tex]

[tex] \longrightarrow \boxed{\bf \: - {x}^{2} + 3x - 11}[/tex]

-------------HappY Learning <3 ----------

Given expression:

[tex](-3x^2+4x)+(2x^2-x-11)[/tex]

To simplify the expression, it is needed to open the parentheses.

[tex]\implies (-3x^2+4x)+(2x^2-x-11)[/tex]

[tex]\implies -3x^2+4x+2x^2-x-11[/tex]

To further simplify the expression, let us combine like terms.

[tex]\implies -3x^2+4x+2x^2-x-11[/tex]

[tex]\implies x^{2} (-3 + 2)+x(4-1)-11[/tex]

Now, simplify the expression as needed.

[tex]\implies x^{2} (-3 + 2)+x(4-1)-11[/tex]

[tex]\implies x^{2} (-1)+x(3)-11[/tex]

Finally, open the parentheses to get the simplified form

[tex]\implies x^{2} (-1)+x(3)-11[/tex]

[tex]\implies \boxed{\bold{-x^{2} +3x-11}}[/tex]

[tex]\text{Therefore, the simplified expression is} \ \boxed{-x^{2} +3x-11}[/tex]

Answer:

Count the tally marks to determine the frequency of each class. The relative frequency of a data class is the percentage of data elements in that class. The relative frequency can be calculated using the formula fi=fn f i = f n , where f is the absolute frequency and n is the sum of all frequencies

The provided graph is not a function because  it touches the graph more than one point.

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

We have given a graph of a function.

We can check the whether the given graph is a function or not by drawing a vertical line if the vertical line touches the graph more than two points then the graph is not a function.

The given graph is not a function because it touches the graph more than one point.

Thus, the provided graph is not a function because  it touches the graph more than one point.

Learn more about the function here:

brainly.com/question/5245372

#SPJ1

Answer:

14.167

Step-by-step explanation:

assuming you meant 5+13

The equivalent expression of [tex]\frac{(2mn)^4}{6m^{-3}n^{-2}}[/tex] is [tex]\frac{(2mn)^4}{6m^{-3}n^{-2}}[/tex]

The expression is given as:

[tex]\frac{(2mn)^4}{6m^{-3}n^{-2}}[/tex]

Evaluate the expression on the numerator

[tex]\frac{16m^4n^4}{6m^{-3}n^{-2}}[/tex]

Divide 16 by 6

[tex]\frac{8m^4n^4}{3m^{-3}n^{-2}}[/tex]

Apply the law of indices

[tex]\frac{8m^7n^6}{3}[/tex]

Hence, the equivalent expression of [tex]\frac{(2mn)^4}{6m^{-3}n^{-2}}[/tex] is [tex]\frac{(2mn)^4}{6m^{-3}n^{-2}}[/tex]

Read more about equivalent expressions at:

https://brainly.com/question/2972832

#SPJ4

Answer:

The mass of salt!

Step-by-step explanation:

The responding variable is the part of an experiment that a scientists measures and observes closely for a change or a response

The value of the function at the right endpoint of the rectangle is 5 +6k/n.

In the question above;

Th width of the interval is said to be  (5 -2) = 3.

So, the width of one of n parts of it = 3/n

To solve for the differences that exist between the left end point of the interval and the value of  x at the right end of the k-th rectangle, one can say that:

 k·(3/n) = 3k/n

Note that the value of x at shows the point of  difference added to the interval's left end and thus it will be:  2 + 3k/n

Therefore, the value of the function for the value of x will be:

 f(2 +3k/n) = 2(2 +3k/n) +1  = (4 +6k/n) +1

 = 5 +6k/n

Learn more about function  from

https://brainly.com/question/25638609

#SPJ4

Answer:

[tex]\sf \cos(G)=\dfrac{1}{2}[/tex]

Step-by-step explanation:

Trigonometric ratios

[tex]\sf \sin(\theta)=\dfrac{O}{H}\quad\cos(\theta)=\dfrac{A}{H}\quad\tan(\theta)=\dfrac{O}{A}[/tex]

where:

Given:

[tex]\implies \sf \cos(G)=\dfrac{2}{4}=\dfrac{1}{2}[/tex]

Answer:

  6.1 km

Step-by-step explanation:

The Pythagorean theorem tells you the relationship between the lengths of the sides of a right triangle.

  c² = a² +b² . . . . a, b are the short sides; c is the hypotenuse

__

The geometry of this problem can be modeled by a right triangle with legs 3.7 km and 4.9 km. The distance of interest is the hypotenuse of the triangle.

  c² = 3.7² +4.9² = 13.69 +24.01 = 37.70

  c = √37.70 ≈ 6.1

The straight-line distance is about 6.1 km.

1inch = 2.5cm

∆ 30cm

5cm =2inch

Answer:

135

Step-by-step explanation:

All triangles =180 degrees
Angle ADC is 45
This means that angle ACD is also 45
ACD and ACB are supplementary which means they add to 180 as well
180 - 45 = 135

The formula is given by

Or

Where