The sides of a regular hexagon is 16ft. What is the area of the hexagon?

The Sides Of A Regular Hexagon Is 16ft. What Is The Area Of The Hexagon?

Answers

Answer 1
64 squared ft bc if you have one size of the hexagon that is 16 ft you times that by 4 bc you have to multiply all sides to get the area and you should get 64 sq ft if I’m wrong I’m sorry lol
Answer 2

Answer:

665.1

Step-by-step explanation:

The formula for an area of a hexagon is [tex]\frac{3\sqrt{3}}{2}S^{2}[/tex]

the S (side) is 16 so,

[tex]\frac{3\sqrt{3}}{2}16^{2}[/tex]

=[tex]\frac{3\sqrt{3} }{2}256[/tex]

=[tex]3\sqrt{3}[/tex] × 128

= [tex]384\sqrt{3}[/tex]

round to the nearest sq. rt. means that you have to round to the nearest tenth, or 0.1

[tex]384\sqrt{3}[/tex] is 665.10751 as a decimal

665.1 as rounded. Therefore, the area of the hexagon is 665.1 sq ft


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Step-by-step explanation:

Answer:

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Step-by-step explanation:

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Answers

Answer: p(t) = (-16 ft/s^2)*t^2 + (57.4 ft/s)*t

Step-by-step explanation:

We can suppose that the only force acting on the object is the gravitational force, then the acceleration of the object will be equal to the gravitational acceleration.

Then we can write:

a(t) = -32 ft/s^2

Where the negative sign is because this acceleration is downwards.

Now, to get the vertical velocity of the object, we need to integrate over time to get:

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where t represents time in seconds and v0 is the constant of integration, and in this case, is the initial vertical velocity.

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p(t) = (1/2)*(-32 ft/s^2)*t^2 + (57.4 ft/s)*t + p0

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Answers

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Download Cymath that helps you

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Answer:

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Answers

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Step-by-step explanation:

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Answers

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