The school playing field is 300 meters. Our coach wants us to run three kilometers, how many times will we need to run around the field.

Answers

Answer 1

Answer:

10 times

Step-by-step explanation:

1km=1000m

3*1000=3000m

3000/300=10

you will need to run 10 times around the field


Related Questions

Evaluate for f(8), show all your work: f(x)=x2+10

Answers

Answer:

[tex]f(8)=74[/tex]

Step-by-step explanation:

[tex]f(8)=8^2+10=64+10=74[/tex]

Multiply the additive inverse of -1/14 with the multiplicative inverse of 21/49.

Chapter : Rational Numbers​

Answers

Answer:

1/6

Step-by-step explanation:

When we talk of additive inverse, we mean the value we will add to a certain number to give 0

for example, the additive inverse of 4 is -4

Hence, the additive inverse of -1/14 is 1/14

The

multiplicative inverse is the number multiplied by another that gives 1

For example, the multiplicative inverse of 4 is 1/4

Thus, we have it that;

multiplicative inverse of 21/49 is 49/21

multiplying;

1/14 * 49/21 = 1/6

Answer:

Answer:

1/6

Step-by-step explanation:

When we talk of additive inverse, we mean the value we will add to a certain number to give 0

for example, the additive inverse of 4 is -4

Hence, the additive inverse of -1/14 is 1/14

The

multiplicative inverse is the number multiplied by another that gives 1

For example, the multiplicative inverse of 4 is 1/4

Step-by-step explanation:

6р + 22 – 10
Help me please

Answers

Answer:

P = -2

Step-by-step explanation:

6p +22 =10

     -22    -22

6p= -12

6       6

p=  -2

Im pretty sure thats it.

“Calculate the lengths of the 2 unlabeled sides”

Answers

Answer:

NL = 4.33

NM = 5

Step-by-step explanation:

tan 60° = NL/2.5

tan 60° = 1.7321

so:

1.7321 = NL/2.5

NL = (2.5)(1.7321)

NL = 4.33

cos 60° = 2.5/NM

cos 60° = 0.5

so:

0.5 = 2.5.NM

NM = 2.5/0.5

NM = 5

It is commonly recognized that a poor environment (for example, poverty, low educational level of parents) and the presence of stressors (for example divorce of parents, abuse) are associated with lower IQs in children. Recent research indicates that a child's IQ is related to the number of such risk factors in the children's background, regardless of which specific factors are present. Below are the numbers of risk factors and the IQs of 12 children.

Child

Risk factors (x)

IQ (y)

A

3

112

B

6

82

C

0

105

D

5

102

E

1

115

F

1

101

G

5

94

H

4

89

I

3

98

J

3

109

K

4

91

L

2

107

A. Draw a scatterplot of the data. What does the plot tell you? Determine the regression equation. Be sure to include an interpretation of each parameter in the regression equation.

B. What IQ do you predict for James, who has 5 risk factors, versus Elizabeth, who has only 2?

Answers

A) The scatterplot of the data is as follows:What can we interpret from the scatterplot of the given data?We can observe that the higher the number of risk factors, the lower the IQ of the children. This fact is supported by the trend line that shows a negative correlation. This is what the plot is telling us.A regression equation is given by the formula: $y=\beta_0+\beta_1x$Where, $y$ is the IQ of the child, $x$ is the number of risk factors, $\beta_0$ is the y-intercept and $\beta_1$ is the slope of the line.Both $\beta_0$ and $\beta_1$ can be calculated using the following formulae: $$\beta_1=r_{xy}\frac{s_y}{s_x}$$$$\beta_0=\bar{y}-\beta_1\bar{x}$$Where, $r_{xy}$ is the correlation coefficient between $x$ and $y$, $s_x$ and $s_y$ are the standard deviations of $x$ and $y$ respectively, and $\bar{x}$ and $\bar{y}$ are the means of $x$ and $y$ respectively.From the scatterplot, we can observe that $r_{xy}$ is negative. Therefore, there exists a negative correlation between $x$ and $y$.Let us calculate the values of $\beta_1$, $\beta_0$ using the above formulae.$$r_{xy}=\frac{\sum(x-\bar{x})(y-\bar{y})}{\sqrt{\sum(x-\bar{x})^2\sum(y-\bar{y})^2}}$$$$r_{xy}=\frac{(3)(112)+(6)(82)+(0)(105)+(5)(102)+(1)(115)+(1)(101)+(5)(94)+(4)(89)+(3)(98)+(3)(109)+(4)(91)+(2)(107)}{\sqrt{(3^2+6^2+0^2+5^2+1^2+1^2+5^2+4^2+3^2+3^2+4^2+2^2)(112^2+82^2+105^2+102^2+115^2+101^2+94^2+89^2+98^2+109^2+91^2+107^2)}}$$$$r_{xy}=-0.835$$Now, let's calculate the standard deviations of $x$ and $y$:$$s_x=\sqrt{\frac{\sum(x-\bar{x})^2}{n-1}}$$$$s_y=\sqrt{\frac{\sum(y-\bar{y})^2}{n-1}}$$$$s_x=\sqrt{\frac{(3-2)^2+(6-2)^2+(0-2)^2+(5-2)^2+(1-2)^2+(1-2)^2+(5-2)^2+(4-2)^2+(3-2)^2+(3-2)^2+(4-2)^2+(2-2)^2}{12-1}}$$$$s_x=\sqrt{\frac{44}{11}}=2$$$$s_y=\sqrt{\frac{\sum(y-\bar{y})^2}{n-1}}$$$$s_y=\sqrt{\frac{(112-99.17)^2+(82-99.17)^2+(105-99.17)^2+(102-99.17)^2+(115-99.17)^2+(101-99.17)^2+(94-99.17)^2+(89-99.17)^2+(98-99.17)^2+(109-99.17)^2+(91-99.17)^2+(107-99.17)^2}{12-1}}$$$$s_y=\sqrt{\frac{5626.1}{11}}=9.025$$Finally, let's calculate $\beta_1$ and $\beta_0$:$$\beta_1=r_{xy}\frac{s_y}{s_x}$$$$\beta_1=-0.835\frac{9.025}{2}=-3.762$$$$\beta_0=\bar{y}-\beta_1\bar{x}$$$$\beta_0=99.17-(-3.762)(3.08)=112.91$$Therefore, the regression equation is $y=112.91-3.762x$.Here, $\beta_0=112.91$ represents the expected IQ of a child with zero risk factors, while $\beta_1=-3.762$ represents the decrease in IQ per risk factor.B) James has 5 risk factors. Substituting $x=5$ in the regression equation, we get:$$y=112.91-3.762x$$$$y=112.91-3.762(5)$$$$y=93.13$$Therefore, the IQ predicted for James is $93.13$.Similarly, Elizabeth has 2 risk factors. Substituting $x=2$ in the regression equation, we get:$$y=112.91-3.762x$$$$y=112.91-3.762(2)$$$$y=105.39$$Therefore, the IQ predicted for Elizabeth is $105.39$.

At what number of days will the cost of attendance be the same for both preschools?

Answers

Answer:

Forgot the pic ?

Step-by-step explanation:

volume of a cylinder that has a diameter of 16 and a height of 7

Answers

Answer:

volume of a cylinder = 1408

hope this answer helps you...

Answer:

1407.616

Step-by-step explanation:

Volume of cylinder=πr²h

V=3.142×8×8×7

V=1407.616

NOTE: radius =diameter/2=16/2

giving 8.

I WILL MARK BRAINLIEST

Answers

Answer:

A.

Step-by-step explanation:

I need help quick please

Answers

i’ll tell you on discord, add me there my user is ri#0511

Answer: 0.1562 I believe

Find the Volume. 5 1/2 x. 3 x 6 1/3

Answers

Answer:6

1/3

Step-by-step explanation:

                                             

HELP PLEASE!!! WILL CROWN BRAINLIEST....
The temperature on Sunday was 7 C. The temperature dropped 8 C on Monday
and dropped twice as much on Tuesday. What was the temperature on Tuesday?

Answers

Answer: - 17 C

Step-by-step explanation: 7 - 8 is negative 1 and twice as much of 8 is 16. -1 minus 16 is negative 17 (-17).

shoes
11 cm
8.8 cm
18.4 cm

Answers

11 x 8.8 x 18.4= 1,782

WILL GIVE BRAINLIEST FOR BEST ANSWER NO LINKS!!!!*Use the data from the dot plot below to answer the question. The data shows games of a soccer season and the number of goals scored in each game.
Which goals were scored the fewest amount of times during the soccer season?





Question 5 options:


3



0, 7



1, 4, 5, 6



2

Answers

0, 7

0 and 7 have the least amount of dots.

Given 2 non-empty Languages A,B⊆ {a,b}∗, give an example of A* = B* and A != B

Answers

A is not equal to B because they have different initial strings. A contains strings composed of 'a', while B contains strings composed of 'b'.

Can you provide an example where two non-empty languages A and B, both subsets of {a, b}∗, satisfy the condition A* = B* but A is not equal to B?

Let's consider the following example:

A = {a, aa}

B = {b, bb}

In this case, A* represents the Kleene closure (or Kleene star) of language A, which includes all possible concatenations and repetitions of strings in A, including the empty string ε. So A* would be {ε, a, aa, aaa, ...}.

Similarly, B* would be {ε, b, bb, bbb, ...}.

In this example, we can see that A* is equal to B* because both languages contain strings of varying lengths formed by repeating their respective symbols (a and b).

To summarize:

A* = {ε, a, aa, aaa, ...}

B* = {ε, b, bb, bbb, ...}

A != B

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Someone pls help me solve this problem. No guessing
Use the photo below to solve for x

Answers

Answer:

x = 6

Step-by-step explanation:

9/x = 12/8

12x = 72

/12     /12

x = 6

hope this helps ^^

if you want to be 99onfident of estimating the population mean to within a sampling error of ±3 and the standard deviation is assumed to be 14, what sample size is required?
The sample size required is_________

Answers

The sample size required is 357.

Here's how to solve the problem:

Given that we need to be 99% confident of estimating the population mean to within a sampling error of ±3.

So, the margin of error (E) = 3 z-score for 99% confidence level = 2.58 (from standard normal distribution table)

The formula for sample size is:n = [z² * σ²] / E²

Where, n = sample size, σ = standard deviation of the population,

E = margin of error, and z = z-score

For a 99% confidence level, the z-score = 2.58

Substitute the given values in the formula:n = [2.58² * 14²] / 3²= 357.15≈ 357

Therefore, the sample size required is 357.

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Let A be a connected and compact Jordan region with |A| > 0 and let ƒ: A → R be a function continuous on A. Prove that there exits xo E A such that 1 f(x₁) = = // f(x)dx. |A| A

Answers

The presence of xo in A with the end goal that 1/|A| ∫ f(x)dx = f(xo). This finishes the confirmation.

To demonstrate the presence of a point xo in A to such an extent that 1/|A| ∫ f(x)dx = f(xo), where A will be an associated and minimized Jordan district with |A| > 0 and ƒ: A → R is a nonstop capability, we can involve the Mean Worth Hypothesis for Integrals.

In the first place, we should characterize a capability F: A → R as F(t) = 1/|A| ∫ f(x)dx - f(t), where t is a point in A. We need to show that there exists xo in A to such an extent that F(xo) = 0.

Since A will be an associated and minimal Jordan locale, it is likewise a shut and limited subset of R^n. Subsequently, A will be a smaller set. We realize that consistent capabilities on minimized sets accomplish their greatest and least qualities.

Since F is a consistent capability on the minimized set A, it accomplishes its most extreme and least qualities. Let M = max{F(t) : t in A} and m = min{F(t) : t in A}.

We have two cases to consider:

Case 1: In the event that M ≤ 0 and m ≥ 0, F(t) = 0 for all t in A, including xo. For this situation, we have demonstrated the presence of xo to such an extent that 1/|A| ∫ f(x)dx = f(xo).

Case 2: If either M > 0 or m < 0, we accept without loss of over-simplification that M > 0. Since M is the greatest worth of F on A, there exists a point t1 in A with the end goal that F(t1) = M. Essentially, we expect to be that m < 0, and there exists a point t2 in A with the end goal that F(t2) = m.

Consider the consistent way γ(t) from t1 to t2 in A. Since An is associated, such a way exists. Presently, characterize another capability G: [0, 1] → R as G(s) = F(γ(s)).

We have G(0) = F(γ(0)) = F(t1) = M > 0, and G(1) = F(γ(1)) = F(t2) = m < 0. In this way, by the Halfway Worth Hypothesis, there exists a point s0 in [0, 1] with the end goal that G(s0) = 0.

Let xo = γ(s0). Since G(s0) = F(γ(s0)) = 0, we have F(xo) = 0. Subsequently, we have demonstrated the presence of xo in A to such an extent that 1/|A| ∫ f(x)dx = f(xo).

In the two cases, we have shown the presence of xo in A with the end goal that 1/|A| ∫ f(x)dx = f(xo). This finishes the confirmation.

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The lumen output was determined for each of k = 3 different brands of lightbulbs having the same wattage, with n_j = 8 bulbs of each brand tested (this is the number of observations in each treatment group). The sums of squares were computed as MSTr = 297.850 and MSE = 227.619. State the hypotheses of interest (including word definitions of parameters).
µ_j = sample average lumen output for brand j bulbs
µ_o : µ_1≠µ_2≠µ_3
H_a: all three µ_j's are equal

µ_j = sample average lumen output for brand i bulbs
µ_o : µ_1=µ_2=µ_3
H_a: all three µ_j's are unequal

µ_j = true average lumen output for brand i bulbs
µ_o : µ_1≠µ_2≠µ_3
H_a: at least two µ_j's are equal

µ_j= true average lumen output for brand i bulbs
µ_o : µ_1=µ_2=µ_3
H_a: at least two µ_j's are unequal

Use the Single Factor ANOVA F test with (α = 0.05) to decide whether there are any differences in true average lumen outputs among the three brands for this type of bulb. Calculate the F test statistic then use software to find your p-value, Recall the p-value from an F test is always the area to the right of the F test statistic.

f statistic = _______ (Round your answer to two decimal places.)
p-value = ________(Round your answer to four places.)

State the conclusion in the problem context.

Fail to reject H_o. There are statistically significant differences in the lumen output.
Fail to reject H_o. There are no statistically significant differences in the lumen output.
Reject H_o. There are statistically significant differences in the lumen output. Reject H_o. There are no statistically significant differences in the lumen output.

Answers

Using the Single Factor ANOVA F test with a significance level of α = 0.05, the F test statistic can be calculated to determine if there are any differences in the true average lumen outputs among the three brands of lightbulbs.

The p-value is then obtained from the software. Based on the conclusion derived from the p-value, either the null hypothesis (H0) is rejected, indicating statistically significant differences in the lumen output, or it is failed to be rejected, suggesting no statistically significant differences.

To determine if there are any differences in the true average lumen outputs among the three brands of lightbulbs, a Single Factor ANOVA F test is conducted. The null hypothesis (H0) assumes that there are no differences, while the alternative hypothesis (Ha) suggests that there are differences among the means.

The F-test statistic is calculated by dividing the mean square between treatments (MSTr) by the mean square error (MSE). The F-test statistic is not provided in the question, so it needs to be calculated using the given information.

The p-value, which represents the probability of obtaining test results as extreme as observed or more extreme, is obtained using software. The p-value is the area to the right of the F-test statistic in the F-distribution.

Based on the obtained p-value and a significance level of α = 0.05, the conclusion is made. If the p-value is less than 0.05, the null hypothesis (H0) is rejected, indicating statistically significant differences in the lumen output among the three brands. If the p-value is greater than or equal to 0.05, the null hypothesis (H0) is failed to be rejected, suggesting no statistically significant differences.

The conclusion should be stated based on the calculated p-value and the significance level. It could either be "Reject H0. There are statistically significant differences in the lumen output" or "Fail to reject H0. There are no statistically significant differences in the lumen output."

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Which of the following is typical of the starting work geometry in sheet metal processes: (a) high volume to area ratio or (b) low volume to area ratio?

Answers

The correct answer is (b) low volume to area ratio is typical of the starting work geometry in sheet metal processes.

Explanation: Sheet metal processing is the method of shaping metal objects to create complex shapes and designs.

Cutting, punching, stamping, and forming are the most common sheet metal processes.

The workpiece's original shape and size are critical considerations in sheet metal processing.

The workpiece's geometry plays an important role in sheet metal processes.

The term volume-to-area ratio refers to the quantity of metal in a part divided by the surface area of that part.

The ratio is low in the case of sheet metal processing. Sheet metal workpieces have a high surface area-to-volume ratio.

This is due to the fact that sheet metal workpieces are often quite thin.

Because of this, sheet metal workpieces are lightweight.

Furthermore, thin sheets are more pliable and can be easily formed into various forms.

This geometry is ideal for sheet metal work since it allows for greater flexibility during processing.

In sheet metal processing, low volume-to-area ratios are typical of the starting work geometry.

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π (pi) is an unending decimal. Find the Circumference of the circle below using exact π (pi).

Answers

Step-by-step explanation:

Given radius, r = 5,

Circumference of Circle, C

[tex] = 2\pi \: r \\ = 2\pi(5) \\ = 10\pi \: units[/tex]

Answer:

[tex]10\pi[/tex]

Step-by-step explanation:

As the hint below says:

[tex]C = 2\pi r[/tex]

We also know that

r = 5

So thus:

[tex]C = 2 \pi \cdot 5 = 10\pi[/tex]

Which answer choice below lists only personal financial assets?
А
car, savings, mortgage loan
B
personal savings, college fund, 401K retirement fund
C
credit cards, home equity loan, retirement fund
D
boat, personal loans, savings

Answers

Answer:

c

Step-by-step explanation:

Answer:

c

Step-by-step explanation:

hi hottie, pls help me !
Mrs. St. Louis purchased an iPhone 12 Pro. The decreasing value of her phone, after t years, is modeled by the function V(t)=1,200(0.65)^t
Fill in the numbers from the options to correctly complete the statements interpreting this function.
The phone initially cost $______
The value of the phone is depreciating at a rate of _____ % each year.

Answers

Answer:

1200

0.65

The answers are in the function

tyler wants to buy a new television that costs $312.

Answers

Answer:

ummm is there more to the problem?!

Cool.... the question???

Conservative change function is given in terms of dimensionless variables as:

-dg/dt + (1-g^2)dg/dx =0, - [infinity]0

a) Which condition must g provide for function to oppose the traffic rules.

b) What is vehicles’ maximum velocity (Umax)=?

c) inital condition is given as: g(x,0)= 1-x. Find the value of g(1,1)=?

Answers

To oppose the traffic rules, the function g must satisfy |g(x)| > 1. The maximum velocity of the vehicles is Umax = 0. Finally, the value of g(1,1) is 0 based on the given initial condition.

a) For the function g to oppose the traffic rules, it must satisfy the condition |g(x)| > 1. In other words, the absolute value of g must be greater than 1. This condition indicates that the function represents a vehicle moving in the opposite direction of traffic flow.

b) To determine the maximum velocity of the vehicles (Umax), we can analyze the equation -dg/dt + (1-g^2)dg/dx = 0. By setting dg/dx = 0, we can find the critical points where the velocity is maximum. In this case, when g = ±1, the term (1-g^2) reaches its maximum value of 0. Therefore, the maximum velocity of the vehicles is Umax = 0.

c) Given the initial condition g(x,0) = 1 - x, we can find the value of g(1,1) by substituting x = 1 into the function. Thus, g(1,1) = 1 - 1 = 0. Therefore, the value of g(1,1) is 0.

In summary, to oppose the traffic rules, the function g must satisfy |g(x)| > 1. The maximum velocity of the vehicles is Umax = 0. Finally, the value of g(1,1) is 0 based on the given initial condition.

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Find the volume of the cylinder whose base area is (4x)2 and height is (5x)2.

Answers

Answer:

Step-by-step explanation:

The computation of the volume of the cylinder is shown below:

As we know that

The Volume of the cylinder is

= base × height

= (4x)^2 + (5x)^2

=16x^2 + 25x^2

= 41x^3

Hence, the volume of the cylinder is 41x^3

The volume of the cylinder will be [tex]20x^2[/tex] .

What is volume ?

Volume is the amount of space that something contains or fills.

Volume [tex]=Length*Breadth*Height[/tex]

We have,

Base area  [tex]=(4x)^2[/tex]

Height [tex]= (5x)^2[/tex]

So,

Volume of the cylinder [tex]=Base\ Area*Height[/tex]

                                        [tex]= (4x)^2* (5x)^2[/tex]

Volume of the cylinder [tex]=20x^2[/tex]

Hence, we can say that the volume of the cylinder will be [tex]20x^2[/tex] .

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Using the Excel file Weddings, apply the Excel Regression tool using the wedding cost as the dependent variable and attendance as the independent variable. Interpret all key regression results, hypothesis tests, and confidence intervals in the output. Analyze the residuals to determine if the assumptions underlying the regression analysis are valid. Use the standard residuals to determine if any possible outliers exist. If a couple is planning a wedding for 175 guests, how much should they budget?

Answers

Using the Excel Regression tool on the Weddings dataset with wedding cost as the dependent variable and attendance as the independent variable, the key regression results, hypothesis tests, and confidence intervals should be interpreted.

After applying the Excel Regression tool with wedding cost as the dependent variable and attendance as the independent variable, the key regression results should be examined. These results typically include coefficients, standard errors, t-values, p-values, and confidence intervals. The coefficient for the independent variable (attendance) represents the estimated change in the wedding cost for each unit increase in attendance. Hypothesis tests and confidence intervals help assess the statistical significance and precision of the estimated coefficients. The t-value indicates the strength of evidence against the null hypothesis of no relationship between the variables, and the p-value indicates the probability of observing the estimated coefficient under the null hypothesis. Lower p-values suggest stronger evidence against the null hypothesis. To validate the assumptions of the regression analysis, the residuals (the differences between the observed and predicted values) should be analyzed. Residual plots can be examined to check for patterns or deviations from assumptions, such as linearity, independence, and constant variance. Outliers can be identified by examining the standardized residuals. Values with high absolute values indicate potential outliers. To estimate the budget for a wedding with 175 guests, the regression model can be used to predict the corresponding cost. The attendance value of 175 can be plugged into the regression equation, and the predicted wedding cost can be obtained.

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Which of the following statements about group decision making is true? If enough time is available, groups usually make higher-quality decisions than most individuals. If enough time is available, most individuals usually make higher-quality decisions than a group. There are far more disadvantages than advantages to group decision making. Individual decisions are generally more difficult to reach than group decisions. Group decisions should rarely be used to address significant business problems.

Answers

The statement "If enough time is available, groups usually make higher-quality decisions than most individuals" is true.

Group decision-making has both advantages and disadvantages, but when enough time is available, groups tend to make higher-quality decisions compared to most individuals. This is due to several reasons. First, groups offer diverse perspectives and expertise, allowing for a broader range of ideas and insights.

Different individuals bring unique knowledge and experiences to the table, leading to a more comprehensive examination of the problem. Second, group decision-making involves collective scrutiny and evaluation of options, which helps in identifying potential flaws or biases in individual opinions.

Group discussions allow for critical analysis, debate, and challenging of assumptions, leading to a more thorough decision-making process. However, it is important to note that time constraints can impact the effectiveness of group decision-making. When time is limited, individual decision-making may be more efficient.

Additionally, the success of group decision-making also depends on factors such as group dynamics, effective communication, and skilled facilitation. Therefore, while groups have the potential for making higher-quality decisions, it is essential to consider the specific context and constraints when determining the most appropriate approach to decision making.

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ASAP HELP MATH!!!!!!!! 1st PERSON GETS BRAINLIEST

Answers

It would be y-x because writing it in absolute value means the solution will always be positive. We could have |3-4| and it would be |-1| or 1. Absolute value is always positive.
In this case, 3>1










Given the following sets, find the set (A U B) O (AUC). U = {1, 2, 3, ..., 10) 3 , A = {1, 2, 3, 7} B = {1, 3, 10} C = {1, 2, 3, 6, 8}

Answers

The set (A U B) O (AUC) is {1, 2, 3, 6, 7, 8, 10}.

The following steps can be used to find the set (A U B) O (AUC):

Step 1: Find A U B {1, 2, 3, 7} U {1, 3, 10} = {1, 2, 3, 7, 10}

Step 2: Find (A U B) U C({1, 2, 3, 7, 10} U {1, 2, 3, 6, 8}) = {1, 2, 3, 6, 7, 8, 10}

A set is a group of things. The objects (or elements) that make up a set are often listed within curly brackets, and sets are typically identified by a letter. It's important to keep in mind that a set is an unordered collection of objects, meaning that it doesn't matter what order the elements are listed in. are viewed as being equivalent.

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Solve the following: 6 sin² x Your answer [APPL- 6 marks] 5 cos x 20 for 0 ≤ x ≤ 2π

Answers

The solutions are x = 0, π, and 2π for the trigonometric equation 6 sin² x = 5 cos x + 20.

To solve the given equation:

6 sin² x = 5 cos x + 20

We can use the trigonometric identity:

sin² x + cos² x = 1

Multiplying both sides by 6, we get:

6 sin² x + 6 cos² x = 6

Substituting 1 - sin² x for cos² x, we get:

6 sin² x + 6 (1 - sin² x) = 6

Simplifying the equation, we get:

6 - sin² x = 6

sin² x = 0

Taking the square root of both sides, we get:

sin x = 0

x = nπ, where n is an integer.

Substituting this value in the original equation, we get:

6(0)² = 5(cos(nπ)) + 20

0 = (-1)n + 4

n must be even for the equation to hold true. Therefore, the solutions are:

x = 0, π, and 2π.

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Nittany Auto Parts enters into a contract to sell Sarah's Mechanical Repairs 100 tires. Nittany Auto Parts then fails to deliver the tires to Sarah's Mechanical Repairs. SarahO does not have to pay for the tires, but cannot file suit against Nittany Auto Parts for breach of contract.O does not have to pay for the tires because Nittany Auto Parts failed to perform.O must still pay for the tires, but can file suit against Nittany Auto Parts for breach of contract.Omust still pay for the tires or she will be in breach of contract. QUESTION 9 Which of the following is NOT criteria for effective segmentation? O Ensuring useful information exists on the segment Having the ability to reach the target segment Focusing only on segmen Assume due to the development of information technologies, AVC of a typical company had decreased, while AFC remained constant. Show how this development is expected to affect the optimal production level and SRATC curve on a graph. the case of the missing teenagers who were located by the police using locational data from their mobile devices is an example of: group of answer choices how technology can hinder an investigation. the benefits and drawbacks of technology. the way mobile devices transmit data invisibly. why parents place limits on mobile phone use. Consider IP address X: 193.101.50.44/26 a) Which of the IP addresses below is on the same network as X: (b) With subnet mask 255.255.255. 192, what is the maximum number of hosts on the subnet? in a windows environment what command would you use to find how many hops are required If a hydrogen atom has its electron in the n = 2 state, how much energy, in electronvolts, is needed to ionize it? Conway Company purchased merchandise inventory with an invoice price of $12,000 and credit terms of 2/10, n/30. What is the net cost of the goods if Conway Company pays within the discount period?Select one:a. $12,000b. $11,760c. $10,800d. $11,040 4x < 13 solving and graphing inequalities the enzyme that converts retinol to retinal and ethanol to acetylaldehyde contains four ____ atoms. The number of his to a website follows a Poisson process. Hits occur at the rate of 3.5 per minute between 7:00 P.M. and 10:00 PM Given below are three scenarios for the numb between 8:43 PM, and 8:47 PM. Interpret each result (a) exactly seven (b) fewer than seven (c) at least seven hits) (a) P(7)=0 (Round to four decimal places as needed.) On about of every 100 time Intervis between 843 PM, and 8:47 PM, the website will receive (Round to the nearest whole number as needed.) (6) P(x7)-0 (Round to four decimal places as needed) On about of every 100 time intervals between B:43 PM and 8:47 PM, the website will rective (Round to the nearest whole number as needed.) (c) PLX27)- (Round to four decimal places as needed.) On about of every 100 time intervals between 8.43 PM and 8:47 PM, the website will receive (Round to the nearest whole number as needed) hito) hits) A fixed pattern of long and short notes that is repeated or varied is known asgroup of answer choicesa cantus firmus.organum.a rhythmic mode.a melisma. You would like to have $20,000 to use a down payment for a home in five years by making regular, end-of-month deposits into an annuity that pays 6% interest compounded monthly.How much should you deposit each month?Round your answer to the nearest cent. Do not include the dollar sign in the answer box below. After admitting Ms. Jones, the nurse calls the provider. What data would the nurse include in the situation-background-assessment-recommendation (SBAR) communications? (Select all that apply.)a) Clonus 1+b) Mother thinks her daughter is having a heart attackc) Patient is scaredd) Coarse crackles in lungse) Severe headachef) RUQ pain Eaton Products seeks to select the minimum total cost vendor for a product for any order quantity. Each of the four product vendors has an associated fixed order cost along with a per unit product cost. Data are provided in the workbook accompanying this quiz. A possible formula for the total cost for vendor AAA in cell D4 would be:=B4*B9+C4=B4+C4*B9=B4+C4*C9=B4+C4*$B$9None of these answers are correct.Exactly two of the above answers are correct. Complete and balance the following half-reaction in acidic solution TiO2 (s) Ti?- (aq) 4. 03-02-0 O O2 O3+ 4+ 1 1 2. 3 4. 5 6 7 8 9 0 0 02 1. O 16 I 0, 0. + (s) (0) (g) (aq) e- H H OH H30- H2O Ti If |A| = 96, |B| = 57, |C| = 62, |AN B| = 8, |AN C=17, IBN C=15 and nd |AnBnC| = AUBUC? = 4 What is Help Sove 1 A company is planning to purchase a machine that will cost $53,172, have a six-year Iife, and will have no salvage value. The company expects to sell the machine's output of 3,000 units ev A nurse manager at a clinic is reviewing the preventative services offered to clients. Which of the following activities should the nurse identify as a secondary preventative activity?a. Advocate for laws that prohibit texting while driving.b. Refer a client who is recovering from substance use disorder to a social service program.c. Provide a smoking cessation class.d. Encourage a pregnant client to participate in prenatal care. Solve the problem. Round dollars to the nearest cent and rates to the nearest tenth of a percent. The amount of markup on a store item is $10. Find the cost to the store if the markup is 20%. A. $8.33 B. $50.00 C. $12.00 D. $2.00 Solve the problem. Round dollars to the nearest cent and rates to the nearest tenth of a percent. Find the selling price of an item which cost a store $124. The store has a 30% markup. A. $161.20 B. $413.34 C. $95.39 D. $37.20