The mass in kg of the water on the roof after the rainstorm is mathematically given as
The mass of the water on the roof after a rainstorm is 1.1 *10^{10}g or 1.1*10^{7}kg
What is the mass in kg of the water on the roof after the rainstorm?Generally, the equation for the Area of the roof is mathematically given as
[tex]A=0.20 \times 10^{10} \mathrm{~cm}^{2}[/tex]
height of the rain =5.5cm
the volume of the rain on the roof =1.1 * 10^{10} CC
Generally, the equation for mass is mathematically given as
mass=volume*density
[tex]&=\left(1.1 \times 10^{10} \mathrm{cC} \times 1 \mathrm{~g} / \mathrm{cc}\right) \\&=1.1 \times 10^{10} \mathrm{~g}[/tex]
In conclusion, the Mass of the water on the roof after a rainstorm is 1.1 *10^{10} or $1.1*10^{7}
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Question 1
Predict if the bonds formed between the following pairs of elements will be ionic, polar covalent, or
covalent.
Si and O
O and O
C and H
Li and F
Ba and S
Polar Covalent
Covalent
Covalent
lonic
loric
The following types of bonds exists between the listed atoms;
Si and O - polar covalentO and O - CovalentC and H - CovalentLi and F - ionicBa and S - ionicWhat is a polar covalent bonds?A bond is polar covalent when the electronegativity difference between the bonding atoms is above that found in a nonpolar covalent bond. Now we shall see the types of bonds between these atoms.
Si and O - polar covalentO and O - CovalentC and H - CovalentLi and F - ionicBa and S - ionicLearn more about polar covalent bonds:https://brainly.com/question/10777799
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0.350g of an organic compound gave 100ml of Nitrogen collected at
250K temperature and 700mm pressure. Calculate the percentage
composition of Nitrogen in the compound.
Use Dumas method
The percentage composition of Nitrogen in the compound is 35.71%
How to determine the mole of nitrogenVolume (V) = 100 mL = 100 / 1000 = 0.1 LPressure (P) = 700 mmHg Temperature (T) = 250 KGas constant (R) = 62.364 torr.L/Kmol Number of mole (n) =?Using the ideal gas equation, the mole of nitrogen can be obtained as follow
PV = nRT
n = PV / RT
n = (700 × 0.1) / ( 62.364 × 250)
n = 0.00448 mole
How to determine the mass of nitrogenMole of nitrogen = 0.00448 moleMolar mass of nitrogen = 28 g/molMass of nitrogen = ?Mass = mole × molar mass
Mass of nitrogen = 0.00448 × 28
Mass of nitrogen = 0.125 g
How to determine the percentage of nitrogenMass of nitrogen = 0.125 gMass of compound = 0.35 gPercentage of nitrogen =?Percentage = (mass of element / mass of compound) × 100
Percentage of nitrogen = (0.125 / 0.35) × 100
Percentage of nitrogen = 35.71%
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What is the complete ionic and net ionic equation for 2 HC2H3O2+Na2CO3——H2O+CO2+2NaC2H3O2
Answer:
Na2CO3 + 2HC2H3O2 --> CO2 + H2O + 2NaC2H3O2 (note my corrections to your original post)
2Na^+ + CO3^-2 + 2HC2H3O2 ==> CO2 + H2O + 2Na^+ + 2C2H3O2^-
Now cancel the ions common to each side to arrive at the net ionic equation. To be a little more accurate, place an (aq) after each ion or solution.
ur correct answer
Explanation:
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3Cu + 8HNO = 3Cu(NO3)2 +2NO + 4H2O
If you begin a reaction with 4.690 g of nitric acid, how many grams of copper (II) nitrate can you theoretically produce, assuming an excess of solid copper is present?
Taking into account the reaction stoichiometry, 5.2634 grams of Cu(NO₃)₂ are formed when 4.69 grams of HNO₃, assuming an excess of solid copper is present.
Reaction stoichiometryIn first place, the balanced reaction is:
3 Cu+ 8 HNO₃ → 3 Cu(NO₃)₂ + 2 NO + 4 H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
Cu: 3 moles HNO₃: 8 molesCu(NO₃)₂: 3 moleNO: 2 molesH₂O: 4 molesThe molar mass of the compounds is:
Cu: 63.55 g/moleHNO₃: 63 g/moleCu(NO₃)₂: 187.55 g/moleNO: 30 g/moleH₂O: 18 g/moleThen, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
Cu: 3 moles ×63.55 g/mole= 190.65 gramsHNO₃: 8 moles ×63 g/mole= 504 gramsCu(NO₃)₂: 3 moles ×187.55 g/mole= 562.65 gramsNO: 2 moles ×30 g/mole= 60 gramsH₂O: 4 moles ×18 g/mole= 72 gramsMass of Cu(NO₃)₂ producedThe following rule of three can be applied: if by reaction stoichiometry 504 grams of HNO₃ form 562.65 grams of Cu(NO₃)₂, 4.69 grams of HNO₃ form how much mass of Cu(NO₃)₂?
[tex]mass of Cu(NO_{3} )_{2} =\frac{4.69 grams of HNO_{3} x562.65 grams of Cu(NO_{3} )_{2} }{504 grams of HNO_{3} }[/tex]
mass of Cu(NO₃)₂= 5.2634 grams
Then, 5.2634 grams of Cu(NO₃)₂ are formed when 4.69 grams of HNO₃, assuming an excess of solid copper is present.
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Determine the empirical formula of a compound containing 8.56 g silicone of 43.2 g of chlorine
The empirical formula of the compound is SiCl₄.
Empirical formula of the compoundmass of silicon = 28 g/mol
mass of chlorine = 35.5 g/mol
molar ration:Si = 8.56/28 = 0.306
Cl = 43.2/35.5 = 1.216
Combining ratioSi = 0.306/0.306 = 1
Cl = 1.216/0.306 = 4
empirical formula = SiCl₄
Thus, the empirical formula of the compound is SiCl₄.
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Be sure to answer all parts.
The pH of a saturated solution of a metal hydroxide M(OH)2 is 10.900. Calculate the Ksp for this compound.
Enter your answer in scientific notation.
The Ksp of the solution is 1.97 * 10^-9.
What is the pH?The pH is defined as the hydrogen ion concentration of the solution. Now we have the pH of the solution as 10.9.
We know that;
pOH = 14 - pH
pOH = 14 - 10.9
pOH = 3.1
[OH^-] = Antilog [-3.1]
[OH^-] =7.9 * 10^-4 M
Now
Ksp = [M^2+] [2OH^-]^2
Ksp = s * (2s)^2
Ksp = 4s^3
Now s = 7.9 * 10^-4 M
Ksp = 4(7.9 * 10^-4)^3
Ksp = 1.97 * 10^-9
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At a temperature of 11.5 °C the gas occupies a volume of 0.0141 m³. Calculate the volume the gas occupies when the temperature is raised to 95.0 °C.
Taking into account the Charles's law, the gas occupies a volume of 0.0182 m³ when the temperature is raised to 95.0 °C.
Charles's lawCharles's law shows the relationship between the volume and temperature of a gas sample at constant pressure.
This law states that the volume is directly proportional to the temperature of the gas: if the temperature increases, the volume of the gas increases, while if the temperature of the gas decreases, the volume decreases.
Mathematically, Charles' law is a law that says that when the amount of gas and pressure remain constant, the ratio between volume and temperature will always have the same value:
[tex]\frac{V}{T}= k[/tex]
Considering an initial state 1 and an initial state 2:
[tex]\frac{V1}{T1}= \frac{V2}{T2}[/tex]
Volume in this caseIn this case, you know:
V1= 0.0141 m³T1= 11.5 C= 284.5 K (being 0 C= 273 K)V2= ?T2= 95 C= 368 KReplacing in Charles's Law:
[tex]\frac{0.0141 m^{3} }{284.5 K}=\frac{V2}{368 K}[/tex]
Solving:
[tex]\frac{0.0141 m^{3} }{284.5 K}x368 K=V2[/tex]
0.0182 m³= V2
Finally, the gas occupies a volume of 0.0182 m³ when the temperature is raised to 95.0 °C.
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Sodium tungstate is Na₂WO4. Therefore, the formula for gold(III) tungstate is
Answer:
AuW₃
Explanation:
What is the volume of 6.40 grams of O₂ gas at STP?
O 4.49 liters
O 4.32 liters
04.18 liters
O 4.06 liters
The volume of 6.40 grams of O₂ gas at STP is 4.48L (option A). Details about volume can be found below.
How to calculate volume?The volume of a gas can be calculated using the following formula:
p = m/v
Where;
p = densitym = massv = volumeAccording to this question, the mass of O₂ gas at STP is 6.40 grams. The density of the gas at STP is 1.43 g/L.
1.43g/L = 6.4g/V
Volume of O2 = 6.4 ÷ 1.43 = 4.48L
Therefore, the volume of 6.40 grams of O₂ gas at STP is 4.48L.
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Answer:
This is right!!! the answer is A 4.49
Explanation:
Question 14 of 32
What is the equilibrium expression for the reaction below?
C(s) + O₂(g)CO₂(g)
Ο Α.
OB.
O C.
OD.
[0₂][C]
[CO₂]
[CO₂]
[0₂]
[CO₂]
[0₂][C]
1
The equilibrium expression for the reaction; C(s) + O₂(g) ------->CO₂(g) is [CO2]/[C] [O2] option C.
What is the equilibrium expression?The equilibrium expression shows how much of the reactants are converted into products. If the equilibrium constant is large and positive, most of the reactants have been converted into products.
Thus, the equilibrium expression for the reaction; C(s) + O₂(g) ------->CO₂(g) is [CO2]/[C] [O2] option C.
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In the following reaction, how much heat is
generated when 1.83 moles of CH4 are
burned?
CH4 (g) + 2 O₂ (g) → CO₂ (g) + 2 H₂O(g) Hº
= -802 kJ/mol
| KJ
Answer:
1470 kJ (to 3 sf)
Explanation:
(802)(1.83) = 1470 kJ (to 3 sf)
1. A fluid is a substance that (a) always expands until it fills any container; (b) is practically incompressible; (c) cannot be subjected to shear forces; (d) cannot remain at rest under action of any shear force.
Answer:
cannot remain at rest under the action of any shear force.
Pls help ty so much!
If 501 J of heat is available, how many grams
of iron (specific heat = 0.45 J/g °C) can be
heated from 22.5°C to 120.0°C?
[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]
[tex]\qquad \tt \rightarrow \:mass = 11.42 \:\: grams [/tex]
____________________________________
[tex] \large \tt Solution \: : [/tex]
[tex]\qquad \tt \rightarrow \: Q = ms\Delta T[/tex]
[tex] \textsf{Q = heat evolved/absorbed = 501 J} [/tex][tex] \textsf{m = mass in gram = ?} [/tex][tex] \textsf{s = specific heat = 0.45} [/tex][tex] \textsf{ΔT = change in temp = 120 - 22.5 =97.5°C} [/tex][tex] \large\textsf{Find m : } [/tex]
[tex]\qquad \tt \rightarrow \: 501 = m \sdot(0.45) \sdot(97.5)[/tex]
[tex]\qquad \tt \rightarrow \: 501 = m \sdot43.875[/tex]
[tex]\qquad \tt \rightarrow \: m = \dfrac{501}{43.875} [/tex]
[tex]\qquad \tt \rightarrow \: m \approx11.42 \: \: g[/tex]
Answered by : ❝ AǫᴜᴀWɪᴢ ❞
help pls i dont get it
The experiment seeks to find out if the seeds take up oxygen as they germinate.
What is an experiment?An experiment is carried out in order to determine cause and effect relationships. The independent variable is the variable that is manipulated in the experiment.
a. The set up B is the control set up
b. The independent variable is the presence/ absence of the seeds while the dependent variable is the color of the solution in both containers.
c. The amount of oxygen in each container can be measured before and after.
d. The hypothesis is that the seeds take up oxygen as they germinate.
Hence, the experiment seeks to find out if the seeds take up oxygen as they germinate.
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If the methane contained in 2.50 L of a saturated solution at 25 ∘C was extracted and placed under STP conditions, what volume would it occupy?
116.6 x [tex]10^{ -3[/tex]} is the volume of methane contained in 2.50 L of a saturated solution at 25 ∘C that was extracted and placed under STP conditions.
What is an ideal gas equation?The ideal gas law (PV = nRT) relates to the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).
The solubility of methane in water at 25 degrees Celcius is 1.3 x [tex]10^{ -3}[/tex] M. It implies 1.3 x [tex]10^{ -3}[/tex] moles of methane are dissolved in one litre of water.
The number of moles of methane in 4 L of water can be calculated as follows:
Moles of methane = [tex]\frac{1.3 . 10^{ -3} }{1L}[/tex] x[tex]\frac{4L}{1L}[/tex]
Moles of methane = 5.2 x [tex]10^{ -3}[/tex]
STP refers to standard temperature and pressure. Under STP conditions, the temperature of the substance is 0 degrees celcius and its pressure is 1 atm.
An ideal gas is an imaginary gas comprising of a large number of randomly moving particles and the motion between such articles is considered to be perfectly elastic. The ideal gas equation describes the relationship between pressure, volume, temperature and number of moles of a gas.
The expression for ideal gas equation is as follows:
PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.
Given data:
P= 1 atm
V= ?
R= [tex]0.082057338 \;L \;atm \;K^{-1}mol^{-1}[/tex]
T=273K
n=?
Putting value in the given equation:
[tex]\frac{PV}{RT}=n[/tex]
5.2 x [tex]10^{ -3} = \frac{1 \;atm\; X \;V}{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X 273}[/tex]
V= 116.6 x [tex]10^{ -3}[/tex]
Hence, 116.6 x [tex]10^{ -3[/tex]} is the volume of methane contained in 2.50 L of a saturated solution at 25 ∘C was extracted and placed under STP conditions.
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What are the social, cultural, and environmental in pacts of water in California
ASAP:))
Explain the conditions that allowed one type of ice to melt faster than the other?
Answer:
Ice cubes do not melt faster in cold water than in hot water. Melting of ice cubes requires heat. What better source of heat than the hot water the ice cubes are in.
Check Your Learning a. To three decimal places, what is the volume of a cube (cm 3) with an edge length of 0.843 cm? b. If the cube in part (a) is copper and has a mass of 5.34 g, what is the density of copper to two decimal places?
1. The volume of the cube (cm³) is 0.599 cm³
2. The density of the copper to two decimal place is 8.91 g/cm³
What is density?The density of a substance is simply defined as the mass of the subtance per unit volume of the substance. Mathematically, it can be expressed as
Density = mass / volume
1. How to determine the volume of the cubeLength (L) = 0.843 cmVolume (V) =?V = L³
V = 0.843³
V = 0.599 cm³
How to determine the densityMass = 5.34 gVolume = 0.599 cm³Density =?Density = mass / volume
Density = 5.34 / 0.599
Density = 8.91 g/cm³
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which statement accurately describes the origin & expansion of the universe?
The statement that accurately describes the origin & expansion of the universe is Cosmic background radiation is leftover thermal energy from the big bang.
What is the expansion of the universe?The expansion of the universe may be defined as the process of enlargement in space between any two given gravitationally untied parts of the detectable universe with duration.
Cosmic radiation extremely fills the universe more or less uniformly. These radiations are responsible for the splitting down of fossil remains and are considered as one of the factors which hypothesized the big bang theory at the origin of the universe.
The complete question is as follows:
As the universe continues to expand, it gradually gets warmer.Galaxies that are farther away are moving away more slowly.Cosmic background radiation is leftover thermal energy from the big bang. Stars and galaxies formed almost immediately after the big bang occurred.Therefore, the correct option is C.
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why is a gigantic iceberg have more heat energy than a pot of boiling water
Thermal energy depends not only on the temperature of a substance but also on the amount of it.
It may be helpful to think of this situation as looking for the total amount of molecular movement. The pot of boiling water has a lot of movement but only a few molecules. The iceberg has far less movement between molecules but vastly more of them.
With the size alone, the slight movements between the molecules of the iceberg add up immensely and tower over that same measurement on the pot of boiling water.
Is the spectrum
electromagnetic
of an element limited only to the visible region of the
spectrum?
The electromagnetic spectrum of an element is not limited only to the visible region of the spectrum.
What is an electromagnetic spectrum?An electromagnetic spectrum is a range of frequencies and wavelengths into which an electromagnetic wave is distributed into.
In Science, the electromagnetic spectrum consist of the following types of energy from highest to lowest frequency and shortest to longest wavelength:
Gamma raysX-raysUltraviolet radiationVisible lightInfrared radiationMicrowavesRadio wavesIn this context, we can infer and logically deduce that the electromagnetic spectrum of an element is not limited only to the visible region of the spectrum.
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. Use the following reaction to determine how much of each product would be released if 42 000 kg (42 tonnes) of methyl isocyanate reacted with excess water:
The amount of 1,3-dimethyl urea produced would be 32,458 grams or 32.458 kg while that of carbon dioxide would be 16,214 grams of 16.214 kg
Stoichiometric problemFrom the equation of the reaction, the mole ratio of methyl isocyanate with the products is 2:1 respectively.
Mole of 42,000 kg of methyl isocyanate = 42000/57 = 736.84 moles
Equivalent mole of 1,3-dimethyl urea = 736.84/2 =368.42 moles
Equivaent mole of carbon dioxide = 736.84/2 =368.42moles
Mass of 368.42 moles 1,3-dimethyl urea = 368.42 x 88.1 = 32,458 grams or 32.458 kg
Mass of 368.42 moles of carbon dioxide = 368.42 x 44.01 = 16,214 grams of 16.214 kg
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ascorbic acid is a diprotic acid (Ka= 8.0x10^-5 and Ka2= 1.6x10^-12). What is the pH of a 0.260 M solution of ascorbic acid
The pH of a 0.260 M solution of ascorbic acid is 0.585. Details about pH can be found below.
How to calculate pH?The pH of a solution can be calculated using the following expression:
pH = - log {H+}
According to this question, ascorbic acid is a diprotic acid and posseses a concentration of 0.260M. The pH can be calculated as follows;
pH = - log {0.260}
pH = 0.585
Therefore, the pH of a 0.260 M solution of ascorbic acid is 0.585.
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How many molecules of HCI would react with 2 moles of Al?
2AI + 6HCI-2AICI 3
+ 3H₂
From the coefficients of the equation, we know that for every 2 moles of Al consumed, 6 moles of HCl are consumed.
This means 6(2/2)=6 moles of HCl are needed.
Since there are [tex]6.022 \times 10^{23}[/tex] molecules in 1 mole of a substance, there are :
[tex]6(6.022 \times 10^{23}}=\boxed{4 \times 10^{24} \text{ (to 1 sf)}}[/tex]
If excess sodium is added to 0.10 L of 1.00 M hydrochloric acid solution, how many moles of NaCl is formed?
Na (s) + HCI (aq)
1.00
0.10
0.50
0.05
Answer:
=> 0.10 moles
Explanation:
The question is asking us to find the moles of NaCl cid formed.
We have been provided with;
0.10 L of 1.0 M NaOH.
We know that mole ratio of the reaction is 1:1 and also the molarity of a solution is contained in 1 L or 1000 mL or 1000 cm³.
This means that;
1.0 M is contained in 1.0 L.
X mol is contained in 0.10 L
[tex] x \: mol \: = \frac{0.1 \times 1.0}{1.0} \\ = 0.10 \: mol[/tex]
= 0.10 moles of NaCl formed
When a certain amount of MgF2 is added to water, the freezing point lowers by 3.5° C. What was the molality of the
magnesium fluoride? (K, for water is 1.86)
The molality of the solution is obtained as 0.63 m.
What is the freezing point?The freezing point is the temperature at which the liquid is converted into solid.
We know that;
ΔT = 3.5° C
K = 1.86° C/m
i = 3
m = ?
Thus;
ΔT = K m i
m = ΔT/K i
m = 3.5° C/ 1.86° C/m * 3
m = 0.63 m
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at sea level water blank at 100 degrees celceius
Boils
Celsius is based on the freezing and boiling points of water.
Water freezes below 0 degrees Celsius (32 degrees Fahrenheit), and it boils above 100 degrees Celsius (212 degrees Fahrenheit).
I need help with homework
Answer:
1. H₂SO₄
Explanation:
A balanced equation tells us how each reactant and product is related to each other in terms of moles.
The equation given has already been balanced since the number of atoms of each element is the same on both sides of the arrow. From the equation, we can see that 1 mole of H₂SO₄ reacts with 2 moles of NaOH. Whichever reactant that we do not have enough of to make more products is known as the limiting reagent, since it limits the amount of products formed.
Mole ratio of H₂SO₄: NaOH= 1: 2
The amount of NaOH needed is twice the amount of H₂SO₄ in terms of moles.
Given that there are 0.40 moles of H₂SO₄, let's calculate the amount of NaOH needed.
Amount of NaOH needed
= 2(0.40)
= 0.80 moles
However, there are only 0.75 moles of H₂SO₄. Since 0.75 <0.80, H₂SO₄ is the limiting reactant.
Additional:
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Answer:
See below
Explanation:
From the balanced equation you can see you need twice as many moles of NaOH as H2SO4....
you have .4 moles of H2SO4 so you need .8 moles of NaOH
but you only have .75 mole....so NaOH is the limiting factor (because you do not have enough)
An electron moved from shell n=2 to Shell n=1. What most likely happened during the transition
When an electron goes from a higher shell to a lower shell then it loses energy.
What is a photon?A photon is a particle of light defined as a discrete bundle (or quantum) of electromagnetic (or light) energy.
When an electron goes from a higher shell to a lower shell then it loses energy.
So, when an electron moved from shell n = 2 to shell n = 1 then a photon of energy is released.
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round off 318.90 to 2 significant figures
Answer:
320
Explanation:
Because the question is asking for 2 significant figures, you want to try to get rid of all of the numbers to the right of the 1. That way, the only numbers that will be significant are the numbers in the position of the 3 and the 1.
Before you can make the rest of the numbers equal 0, you need to correctly round the number in the last significant position (the number 1).
If the number to the right of the 1 is from 0-4, the number stays the same. If the number is from 5-9, the 1 needs to be increased by a unit.
Since the number to the right is an 8, you need to change the 1 to a 2. Now, you can make all of the other numbers a 0. There should be no decimal place because it would mean that the zero to the left of it is significant.