The ratio of boys to girls in the class is 3 to 4. If there were 12 boys, how many girls were there?

Answers

Answer 1

Answer:

Step-by-step explanation:

let girls be x

3/4=12/x(do cross multiplication)

12*4=3x

48/3=x

16=x

therefore there are 16 girls

Answer 2

Answer:

16 girls

Step-by-step explanation:

Set up a proportion. Let x = the number of girls.

3 / 4 = 12 / x

Cross multiply:

3x = 48

x = 16


Related Questions

Solve the expression for a=12 , b=6 and c=3

Answers

Answer:

48

Step-by-step explanation:

[tex]a = 12, \ b = 6, \ c = 3\\\\b^2 - c^2 + (a+ b+c) = 6^2 - 3^2 + (12 +6+3) = 36-9+21 = 48[/tex]

Answer:

2-12+(++)

b^{2}-1c^{2}+(a+b+c)

b2−1c2+(a+b+c)

Simplify: 1

Eliminate redundant parentheses

2−12+(++)

b^{2}-1c^{2}+(a+b+c)

b2−1c2+(a+b+c)

2−12+++

b^{2}-1c^{2}+a+b+c

b2−1c2+a+b+c

Solution: 2−12+++

b^{2}-1c^{2}+a+b+c

b2−1c2+a+b+c

Someone help me answer this pls

Answers

Answer:

y>-2x-3

Step-by-step explanation:

I think, not sure.

simplify
[tex] \sqrt{12} [/tex]

Answers

2 and then on the inside of a square root is 3

Hi there!  

»»————- ★ ————-««

I believe your answer is:  

[tex]\huge\boxed{2\sqrt{3}}[/tex]

»»————- ★ ————-««  

Here’s why:  

[tex]\boxed{\text{Simplifying the square root of 12}}\\\\\rightarrow\sqrt{12}\\\\\text{4 can be factored out of 12.}\\\\\rightarrow\sqrt{4(3)}\\\\\text{Two '2's can be factored out of 4.}\\\\\rightarrow\sqrt{2*2*3}\\\\\rightarrow\sqrt{2^2(3)}\\\\\text{Pulling out the terms from under the radical...}\\\\\rightarrow\boxed{2\sqrt{3}}[/tex]

»»————- ★ ————-««  

Hope this helps you. I apologize if it’s incorrect.  

for positive acute angles A and B, it is known that cos A=20/29 and sin B=60/61. Find the value of sin(A+B) in simplest form.

Answers

Answer:

[tex]sin(A+B) = \frac{1431}{1769}[/tex]

Step-by-step explanation:

sin(A+B) = sinA cosB + cosA sinB ------(1)

[tex]given : cos A = \frac{20}{29}, \ sinB = \frac{60}{61}[/tex]

First we will find sinA and cosB

[tex]We \ know \ sin^2 A + cos^2A = 1\\\\sin^2 A = 1 - cos^2A = 1 - (\frac{20}{29})^{2} = \frac{841-440}{841} = \frac{441}{841}\\\\sinA =\frac{21}{29}[/tex]

[tex]sin^2B +cos^2B = 1\\\\cos^2B = 1 - sin^2B = 1 - (\frac{60}{61})^2 = \frac{3721-3600}{3721} = \frac{121}{3721}\\\\cosB = \frac{11}{61}[/tex]

Substitute all values in (1)

[tex]sin(A+B) =sinAcosB + cosAsinB[/tex]

               [tex]=(\frac{21}{29} \times \frac{11}{61} )+ (\frac{20}{29}\times \frac{60}{61})\\\\=\frac{231}{1769} + \frac{1200}{1769}\\\\= \frac{1431}{1769}[/tex]

This is my first time using Brainly I don't know if I'm doing this correctly.

Answers

Answer:

x = -3

Step-by-step explanation:

hello and welcome to brainly!

so in the hint it pretty much gives you the equation x=-b/2a

the standard form of a quadratic equation is f(x) = ax^2+bx+c

so we look at the equation we have and we can see that a=-2 and b=-12

we substitute this into the axis of symmetry equation

x= -(-12) / 2(-2)
simplify
x=12/-4
simplify further
x=-3

Rosa is a secretary. She works Monday to Friday every week. If she worked a total of 44.5
hours this week, and her regular pay is $11.46 per hour, what is Rosa’s regular pay?

Answers

Answer:

$509.97 is Rosa's regular pay

help help i need help with my math

Answers

Answer:

13

Step-by-step explanation:

Answer:

13

Step-by-step explanation:

48-[(2^2+3)x5]

48-[(4+3)x5]

48-[(7)x5]

48-[35]

13

Find the area of the shaded segment VB and length of VB

Answers

Answer:

Area of length Vb = 25 square units

Area of segment Vb  = 26 square units

Step-by-step explanation:

Area of length Vb = theta/360 * 2πr  

Area of length Vb = 120/360 * 2*3.14 * 12  

Area of length Vb = 1/3 * 75.36  

Area of length Vb = 25 square units  

Ares of length Vb is 25.1 sq. units

Area of shaded portion = Area of sector VUB - Area of triangle VUB

Area of sector VUB = theta/360 * πr²

Area of sector VUB = 120/360 * 3.14*144

Area of sector VUB = 1/3 * 452.16

Area of sector VUB =150.72

Area of triangle VUB  = r²sintheta

Area of sector VUB = = 12²sin 120

Area of sector VUB = = 144(0.8660)

Area of sector VUB = 124.71

Area of the shaded segment = 150.72 - 124.71

Area of the shaded segment = 26.01

Area of the shaded segment = 26 sq. unitsAnswer:

Area of length Vb = 25 square units

Area of segment Vb  = 26 square units

Step-by-step explanation:

Area of length Vb = theta/360 * 2πr

Area of length Vb = 120/360 * 2*3.14 * 12

Area of length Vb = 1/3 * 75.36

Area of length Vb = 25 square units

Ares of length Vb is 25.1 sq. units

Area of shaded portion = Area of sector VUB - Area of triangle VUB

Area of sector VUB = theta/360 * πr²

Area of sector VUB = 120/360 * 3.14*144

Area of sector VUB = 1/3 * 452.16

Area of sector VUB =150.72

Area of triangle VUB  = r²sintheta

Area of sector VUB = = 12²sin 120

Area of sector VUB = = 144(0.8660)

Area of sector VUB = 124.71

Area of the shaded segment = 150.72 - 124.71

Area of the shaded segment = 26.01

Area of the shaded segment = 26 sq. units

PLEASE DO WITH STEPS 3, 4 and 5 SOLVE IN RADICAL FORM AND DECIMAL FORM WITH STEPS PLZ WILL MARK AS BRAINLIEST

Answers

Answer:

Step-by-step explanation:

3) (21²-6²)½ = 20.1 cm

4) (10²+7²)½ =12.2 cm

5) (6.5²-2.7²)½ = 5.9 cm

PLEASE HELP ME AT LEAST ONE OF THESE IF YOU KNOW

Answers

Step-by-step explanation:

answer of number 5

length=7cm

breadth=9 cm

height=6 cm

volume=?

we know

v =l×b×h

=7×9×6

=378

so, the volume is 378 cm

Answer:

cone, radius is 3^2 x pi x 7/3 = 65.98

Step-by-step explanation:

A population of 350 animals has a growth rate of 5% each year. Write an exponential function to model this situation.

Answers

Given:

The population of animals = 350

Growth rate = 5% each year.

To find:

The exponential function to model this situation.

Solution:

The general exponential growth model is:

[tex]f(t)=a(1+r)^t[/tex]

Where, a is the initial value, r is the growth rate in decimal and t is the time period.

Substituting [tex]a=350, r=0.05[/tex] in the above formula, we get

[tex]f(t)=350(1+0.05)^t[/tex]

[tex]f(t)=350(1.05)^t[/tex]

Therefore, the required exponential function is [tex]f(t)=350(1.05)^t[/tex], where f(t) is the number of animals after t years.

The first number in a pattern is 8. Each following number is found by subtracting 9 from the previous
number
What is the fifth number in the pattern?

Answers

Answer:

8,-1,-9,-18,-27,-36

and so on i would think it would be -27

Step-by-step explanation:

Answer:

-28

Step-by-step explanation:

other answer off by one

Someone please help me out!!

Answers

Answer:

4/ 5

cos A = AB/ AC

= 24/ 30

= 4/ 5

that is option A

A motorboat travels 9 miles downstream (with the current) in 30 minutes. The return trip upstream (against the current) takes 90 minutes.

Answers

Given :

A motorboat travels 9 miles downstream (with the current) in 30 minutes.

The return trip upstream (against the current) takes 90 minutes.

To Find :

The speed of stream and motorboat.

Solution :

Let, speed of stream is u and speed of motorboat is v.

Now, we know distance is same in both case.

Distance( downstream ) = speed × time

[tex]9 = ( v +u ) \times 0.5\\\\v + u = 18[/tex]....1)

Distance( upstream ) = speed × time

[tex]9 = ( v- u ) \times 1.5\\\\v-u = 6[/tex]....2)

Solving equation 1 and 2 , we get :

v = 12 miles/hour and u = 6 miles/hour

Hence, this is the required solution.

Answer:

The speed of the stream is 6 mph, and the speed of the boat is 12 mph.

Step-by-step explanation:

Downstream:

9 miles in 30 minutes (0.5 hour).

9 mi / 0.5 h = 18 mph

Upstream:

9 miles in 90 minutes (1.5 h).

9 mi / 1.5 h = 6 mph

Let s = speed of stream.

The speed of the stream adds to the speed of the boat downstream and is subtracted fromt he speed of the boat upstream.

Let speed of boat be b.

b + s = 18

b - s = 6

Add the equations.

2b = 24

b = 12

b + s = 18

12 + s = 18

s = 6

The speed of the stream is 6 mph, and the speed of the boat is 12 mph.

What is the first quartile and third quartile of this data set: 34, 34, 36, 39, 50, 41, 45, 47, 40?

Answers

Answer:

http://web.mnstate.edu/peil/MDEV102/U4/S36/S363.htmlStep-by-step explanation:

Answer:

First quartile: 35

Third Quartile: 46

Step-by-step explanation:

easy algebra question below first correct answer gets brainliest

Answers

Answer:

using pythagoras theorem

h^2=p^2+b^2

h^2=12^2+9^2

h^2=144+81

h^2=225

h=[tex]\sqrt{225}[/tex]

h=15

Step-by-step explanation:

Does 10+10+10+0=20???
Because it always shows different on calculators

Answers

Answer:

No

HOPE THIS HELPS

- Todo ❤️

Step-by-step explanation:

10+10=20

20+10=30

30+0=30

Please help fast answer only if you know or gonna report you

Answers

Step-by-step explanation:

a) unsuitable - the precision should have been about 0.030 kg (about an ounce)

b) unsuitable - the stopwatch should have a precision of 0.001 s

c) just about right, although I wouldn't mind it if its precision is of 0.05 mm

d) unsuitable - color matching requires much finer control so I would go with 1/8 cup precision.

An isosceles triangle has base angles that each measure 42°. Which equation can be used to find z, the measure of the third angle of this isosceles triangle in degrees? \

Answers

Answer:

42 + 42 + z = 180

Step-by-step explanation:

Note that:

Base angles in an isosceles triangle are equal in measure.

The sum of angles in a triangle is 180°.

Thus, the equation would be

42 + 42 + z = 180

Solve for the value of e.
pls help

Answers

Answer:

44

Step-by-step explanation:

the steps are in the pic above

Daniel has two cats. The larger cat weighs 16.5 lbs. If the smaller cat weighs 60% as much as the larger cat, find the weight of the smaller cat.

Answers

Answer:

I'm not sure but if you want the answer download Socratic it will definitely help you find the answer.

Hello may any of you help me with these two equations I’m having a little hard time thank you =10 points

Answers

Answer:

a. 10.08

b. 0.0576

A triangle PQR is right angled at R, with PQ=80cm and R=60cm. find QR?
pythagorus theorem

Answers

Answer:

Solution given:

A triangle PQR is right angled at R, with hypotenuse{h}PQ=80cm

and

base[b]PR=60cm.

perpendicular [P]= QR

by using Pythagoras law

=+

80²=QR²+60²

QR²=80²-60²

QR=[tex]\sqrt{2800}[/tex]

QR=20[tex]\sqrt{7}[/tex]=52.9=53cm

QR=53cm.


Alden has two toys. One toy has a mass of 188 grams, and the other has a mass of 127 grams

Answers

whats the rest of the question?

Maggie has 7 bills, all tens and twenties, that
total $100 in value. Find the number of tens, x, and
the number of twenties, y, that Maggie has.

Answers

Answer:

4 tens, 3 twenties

Step-by-step explanation:

4 tens  ($40) and 3 ($60)  twenties work. I’m sorry I don’t have a formula for it though.

Find the range of the given data below:
7, 10, 12, 11, 12, 10, 11, 13, 17, 13
Ans: 10​

Answers

Answer:  10

Step-by-step explanation:

Arranged data

7,10,10,11,11,12,12,13,13,17

Range= Highest value - Lowest Vlue

Highest value=17

Lowest value =7

Range=17-7

Range=10

Answer:

[tex]Answer:  10

Step-by-step explanation:

Arranged data

7,10,10,11,11,12,12,13,13,17

Range= Highest value - Lowest Vlue

Highest value=17

Lowest value =7

Range=17-7

Range=10 [/tex]

hope it is helpful to you

please show your work

Answers

Answer:

X is equal to 4

solve: (x-3)(x+2)=0
answers:
3 and 2
3 and -2
-3 and -2
none of the choices are correct

Answers

Answer:

x=3          x=-2

Step-by-step explanation:

(x-3)(x+2)=0

Using the zero product property

x-3 =0   x+2 =0

x=3          x=-2

Answer:

3 and -2

Step-by-step explanation:

x -3 =0

x= 3

x+2 =0

x= -2

1/2x9
step by step please

Answers

[tex]4.5[/tex] ✅

Step-by-step explanation:

[tex] \frac{1}{2} \times 9 \\ = \frac{1 \times 9}{2} \\ = \frac{9}{2} \\ = 4.5[/tex]

[tex]\circ \: \: { \underline{ \boxed{ \sf{ \color{green}{Happy\:learning.}}}}}∘[/tex]

so you multiply the numerator which is 1x9= 9
and you leave the denominator alone which will be 9/2 then divide 9*2 which will be 4.5. Hope it makes it easier for you.

Rewrite the expression using only positive exponents. Then, evaluate the expression. 3^{-2}

Answers

Step-by-step explanation:

Rewrite the expression using only positive exponents. Then, evaluate the expression. 3^{-2}

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