Answer:
Decimal: 9.45 Fraction: 236.35/25
Step-by-step explanation:
sorry if the fraction one is wrong.
Lorenzo has a package that weighs 2 pounds.
He wants to check the weight of the package on a scale, but he only has weights that are measured in ounces.
Drag the weights into the box that will balance the scale. Each weight can be used once or not at all.
1 pound = 16 ounces
2 pounds = 32 ounces
4 + 12 + 16 = 32
Use the 4, 12 and 16 ounce weights.
Answer:
Solution given:
1 pound = 16 ounces
2 pounds = 32 ounces
we have 32=4×12×16
so
the 4, 12 and 16 are ounce weights.
Candy and Hershel folded the same-size square papers.
Candy shaded 2/4 and Hershel shaded 1/2 . Are the fractions equivalent?
Answer:
The fractions are equivalent.
Step-by-step explanation:
2/4 can be simplifyed as 1/2 meaning they are equivalent.
Candy shaded 2/4 and Hershel shaded 1/2 represent the same amount of shaded area on their respective square papers.
To determine whether the fractions 2/4 and 1/2 are equivalent, we can simplify both fractions and compare them.
First, let's simplify the fraction 2/4:
The numerator and denominator of 2/4 have a common factor of 2. By dividing both the numerator and denominator by 2, we get:
2/4 ÷ 2/2 = 1/2
Now, let's compare the simplified fraction 1/2 to the fraction 1/2 that Hershel shaded.
Since both fractions are now 1/2, we can conclude that the fractions are indeed equivalent. Therefore, Candy shaded 2/4 and Hershel shaded 1/2 represent the same amount of shaded area on their respective square papers.
To know more about fractions here
https://brainly.com/question/30154928
#SPJ2
Enter the number that belongs in the green box as you solve for P.
Answer:
2p=18
2p=2p the answer is p=9
Step-by-step explanation:
Use the net to find the surface area of the prism.
360 in2
480 in2
408 in2
432 in2
NO LINKS
Answer:
96 in.²
Step-by-step explanation:
Surface Area of the prism = 2(area of the 2 equal triangles) + area of rectangle A + rectangle B + rectangle C
✔️Area of the two triangles with the following dimensions:
height = 3 in.
base = 4 in.
Area = 2(½*4*3) = 12 in.²
✔️Area of rectangle A = L*W
L = 7 in
W = 5 in
Area of rectangle A = 7*5 = 35 in.²
✔️Area of rectangle B = L*W
L = 7 in
W = 4 in
Area of rectangle B = 7*4 = 28 in.²
✔️Area of rectangle C = L*W
L = 7 in
W = 3 in
Area of rectangle C = 7*3 = 21 in.²
✔️surface area of the prism = 12 + 35 + 28 + 21 = 96 in.²
The cost of a school banquet is 75$ plus 15$ per person.
1- write a linear equation for the above situation
2- What do you think the slope and the y intercept is?
3- what would the inverse above mean?
4-How much would it cost is 75 people came
5- If the final bill was 630$ How many people attended
PLEASE show work!! 24 points
Answer:
The cost of a school banquet is $75+30n, where n is the number of people attending.
If 53 people are attending to visit school banquet, then you have to find the value of given expression at n=53.
At n=53, the value is $(75+30·53)=$1,665.
Step-by-step explanation:
Find the probability that a randomly selected point within the circle falls in the red shaded area (square). Round to the nearest tenth of a percent.
Answer:
probability of selecting the square is 63.7% approximately
Step-by-step explanation:
First of all, the probability of the point of choice is within the red square can be obtained with this formula
probability = expected outcome / total number of possible outcomes
In this case, we are not dealing with discrete values which can be counted. instead, we are dealing with areas.
We are to go about this problem by finding the area of the internal square and dividing it by the area of the circle.
Area of the square
Area of the square = [tex]l^2[/tex]
where length = [tex]4\sqrt{2}[/tex]
Area = [tex](4\sqrt{2}) ^2 = 32cm^2[/tex]
Area of the circle
Area of the circle = [tex]\pi r^2[/tex]
area of circle =[tex]\pi \times 4^2 =50.26cm^2[/tex]
Probablity of selecting the square =
32/50.26 = 0.6366
To express this as a percentage, we multiply our answer by 100.
This will give us 0.6366 X 100 = 63.7% approximately
An investor wants to invest up to $100,000 as follows:
X amount into a Certificate of Deposit (CD) that yields an expected annual return of 1% with a risk index of 1,
Y amount into a Bond with an expected annual return of 3% and a risk index of 4,
Z amount into a Stock with an expected annual return of 7% and a risk index of 8.
The investor’s objective is to maximize the total expected annual return of the investment.
However, to be prudent, the investor requires that:
The fraction of the total investment in X must be at least 20%.
The fraction of the total investment in Z must not exceed 50%.
The combined portfolio risk index must not exceed 5.
Required:
a. Set up this investment problem as a linear program, which has 3 variables, 3 basic constraints, and 4 special constraints.
b. Use an LP software to find the maximum expected annual return in dollars and the dollar values of X, Y, and Z for this best investment.
c. From the software solution, show the values of the dual variables for the four special constraints.
Answer:
a-The Linear Model is as follows:
[tex]X+Y+Z\leq 100,000\\{0.001X}\geq 20\\{0.001Z}\leq 50\\0.00001X+0.00004Y+0.00008Z\leq5\\X\geq0\\Y\geq0\\Z\geq0[/tex]
b-The values are
X=$33,333.33
Y=$16,666.67
Z=$50,000.00
Leading to a total expected return of $4333.33.
c-The values of constraints are as follows
X+Y+Z=33333.33+16666.67+50000=100,000
X=33%, Y is 16.67% and Z is 50%
Risk component of X is 0.33
Risk component of Y is 0.66
Risk component of Z is 4.00
Step-by-step explanation:
a
From the conditions, the first special constraint is the total amount which is that the sum of investments must not be more than the total available amount of $100,000 so
[tex]X+Y+Z\leq 100,000[/tex]
The second special constraint is that the percentage of X must be at least 20% So
[tex]\dfrac{X}{100,000}\times100 \geq20\\\dfrac{X}{1000} \geq20\\{0.001X}\geq 20[/tex]
The third special constraint is that the fraction of total investment of Z must not exceed 50% So
[tex]\dfrac{Z}{100,000}\times100 \leq50\\\dfrac{Z}{1000}\leq 50\\0.001Z\leq50[/tex]
The fourth special constraint is that the combined portfolio risk index must not exceed 5 so
[tex]\dfrac{X}{100,000}\times1+\dfrac{Y}{100,000}\times4+\dfrac{Z}{100,000}\times8\leq5\\0.00001X+0.00004X+0.00008Z\leq5[/tex]
As the investments cannot be negative so three basic constraints are
[tex]X\geq0\\Y\geq0\\Z\geq0[/tex]
The maximization function is given as
[tex]f(X,Y,Z)=\dfrac{X}{X+Y+Z}\times1\%+\dfrac{Y}{X+Y+Z}\times3\%+\dfrac{Z}{X+Y+Z}\times7\%\\f(X,Y,Z)=\dfrac{X}{X+Y+Z}\times0.01+\dfrac{Y}{X+Y+Z}\times0.03+\dfrac{Z}{X+Y+Z}\times0.07[/tex]
b
By using an LP solver with BigM method the solution is as follows:
X=$33,333.33
Y=$16,666.67
Z=$50,000.00
Leading to a total expected return of $4333.33.
c
The values of constraints are as follows
X+Y+Z=33333.33+16666.67+50000=100,000
X=33%, Y is 16.67% and Z is 50%
Risk component of X is 0.33
Risk component of Y is 0.66
Risk component of Z is 4.00
GIVING 100 POINTS!!!!
Answer:
As per dot plots we see the distribution of prices is close but majority of prices are concentrated in different zones. So MAD would be more similar by the look.
Let's verify
Neighborhood 1Data
55, 55, 60, 60, 70, 80, 80, 80, 90, 120Mean
(55*2+ 60*2+ 70+ 80*3 + 90+ 120)/10 = 75MAD
(20*2+15*2+5+5*3+15+45)/10 = 15Neighborhood 2Data
100, 110, 110, 110, 120, 120, 120, 140, 150, 160Mean
(100 + 110*3+ 120*3+ 140 + 150+ 160)/10 = 124MAD
(24+14*3+4*3+16*3+16+26+36)/10 = 20.4As we see the means are too different (75 vs 124) than MADs (15 vs 20.4).
Answer
the image isnt very clear
Step-by-step explanation:
Find the measure of Angle I.
Answer:
I think 5?................
NEED HELP ASAPPP PLS
Answer:
they are alternate interior angles to parallel lines.
Step-by-step explanation:
The reason for this is that they are alternate interior angles to parallel lines. The straight dotted lines that represent the line of sight of each individual are parallel to each other while the elevation line in this scenario would be considered the Transversal as it passes through both of them. This ultimately causes the angles between the transversal and the line of sight to be alternate interior angles which are equal to one another, as can be seen in the attached demonstration in the image below.
An education researcher would like to test whether 2nd graders retain or lose knowledge during the summer when they are presumably not in school. She asks nine 2nd graders to take a comprehension exam at the end of the school year (May), and then asks those same students to come back after the summer (late August) to retake a different but equivalent exam, to see if their level of comprehension has changed. Using the data below, test this hypothesis using an alpha level of .05.
May August
90 100
65 80
78 92
50 60
89 90
92 98
75 70
90 96
65 87
a) What is the appropriate test? Is it a one or two tailed test?
b) State the null hypothesis (in words and using means).
c) State the alternative hypothesis (in words and using means).
d) Find the critical value.
e) Calculate the obtained value by hand. What does your decision mean?
Answer:
See step by step explanation
Step-by-step explanation:
From the problem statement, we understand that we need to investigate if 2nd graders RETAIN OR LOSE knowledge comparing information concerning two different months, therefore we are going to find out if the information gives us enough evidence of a difference in the two groups
a) The test should be a two tail-test
Sample sizes are small ( n₁ = n₂ = 9 ) which means we have to use t-student test
b and c) Test Hypothesis:
For Null Hypothesis H₀, we establish that the two means are equal, which in this case means that the two samples´ means are equal. And as Hypothesis alternative Hₐ that the H₀ is not true, or that the samples mean are different.
Null Hypothesis H₀ x₁ - x₂ = 0 or x₁ = x₂
Alternative Hypothesis Hₐ x₁ - x₂ ≠ 0 or x₁ ≠ x₂
d) Significance level α = 0,05 then α/2 = 0,025
then t(c) with α/2 = 0,025 and degree of freedom
df = n₁ + n₂ - 2 df = 9 + 9 -2 df = 16
From t s-tudent table we find t(c) = 2,12
e) Calculating:
x₁ and σ₁
x₂ and σ₂
σₓ = [ ( n₁ - 1 )* σ₁² + ( n₂ - 1 )*σ₂² ]/ n₁ + n₂ - 2
Using a calculator:
x₁ = 77,11 σ₁ = 13,86
x₂ = 85,89 σ₂ = 12,74
σₓ = [ ( 8*(13,86)² + 8*( 12,74 )² ] / 16
σₓ = (8* 192,1) + 8* ( 162,31) / 16
σₓ = (1536,8 + 1298,48 ) / 16
σₓ = 177,205
t(s) = ( x₁ - x₂ ) /√ σₓ²/ n₁ + σₓ²/ n₂
t(s) = ( 77,11 - 85,89 )/ (177,205)²/n₁ + (177,205)²/n₂
t(s) = - 8,78 / √3489,07 + 3489,07
t(s) = -8,78 / 83,54
t(s) = - 0,11
Comparing t(s) and t(c)
|t(s)| < |t(c)|
0,11 < 2,12
t(s) is in the acceptance region. We accept H₀
HELP! Does the pythagorean theorem work for every triangle or just for right triangles?
a. everytriangle
b. only right triangles
Answer:
This is so easy!
ONLY RIGHT TRIANGLES
Did you really ask this question?
Tip: You should learn the basics first.
‼️can anyone help me with the question that says "meaning of slope" PLEASE, I NEED THIS FOR TOMORROW❗
Answer: Slope is the measure of the steepness of a line. It can be calculated with the equation rise/run or change in y/change in x.
Step-by-step explanation:
The table shows the probability distribution of siblings of students in a high
school with 1500 students. What is the expected value for the number of
siblings of a randomly chosen student?
Number of siblings
0
1
2
3
4
5
Probability
0.18
0.65
0.09
0.05
0.02
0.01
A. 1.08
B. 2.5
C. 1.11
D. 1.29
Answer:
Step-by-step explanation:
1.11
The expected value for the number of siblings of a randomly chosen student is 1.11.
The correct answer is C. 1.11.
To calculate the expected value for the number of siblings of a randomly chosen student, we need to multiply each possible number of siblings by its corresponding probability and sum up the results.
Expected Value = (0 x 0.18) + (1 x 0.65) + (2 x 0.09) + (3 x 0.05) + (4 x 0.02) + (5 x 0.01)
Expected Value = 0 + 0.65 + 0.18 + 0.15 + 0.08 + 0.05
Expected Value = 1.11
Therefore, the expected value for the number of siblings of a randomly chosen student is 1.11.
Learn more about Probability here:
https://brainly.com/question/31828911
#SPJ5
Please help (no links) or i will report you i just need answers
Answer:
Both are TRUE
Step-by-step explanation:
✔️The statement, "angles 1 and 5 are corresponding angles" is TRUE.
Rationale/reason:
Angles that have corners that match are called corresponding angles. Angles 1 and 5 are angles found in the corners that match each other. Therefore, they are corresponding.
✔️The statement, "Angle 6 is congruent to angle 4" is TRUE.
Rationale/reason:
When two lines that are parallel is crossed by a transversal, the alternate interior angles formed are congruent to each other.
Angles 4 and 6 are interior angles that alternate each other along the transversal. Therefore they are congruent to each other.
PLEASE HELP ME!!!!!!!!!ASAP!!!!!
Write down three integers, all less than 25, whose range is 8 and mean is 11.
Answer:
11,15,7
Step-by-step explanation:
11+15+7=33 33/3=11 the mean
then 15-7=8 the range
When electricity (the flow of electrons) is passed through a solution, it causes an oxidation-reduction (redox) reaction to occur. If the solution contains a metal cation such as Ag+, the flow of electrons will reduce the silver ion, causing solid silver to plate onto the electrode. The amount of metal plated depends on the number of electrons passed. The total charge of a mole of electrons is 96, 485 coulombs (C) and 1 ampere = 1 coulomb/second (C/s).
What mass of Cu(s) is electroplated by running 28.5 A of current through a Cu2+ (aq) solution for 4.00 h? Express your answer to three significant figures and include the appropriate units.
How many minutes will it take to electroplate 37.1 g of gold by running 5.00 A of current through a solution of Au+(aq)? Express your answer to three significant figures and include the appropriate units.
Answer:
a. 135 g
b. 60.6 min
Step-by-step explanation:
a. What mass of Cu(s) is electroplated by running 28.5 A of current through a Cu2+ (aq) solution for 4.00 h? Express your answer to three significant figures and include the appropriate units.
The chemical equation for the reaction is given below
Cu²⁺(aq) + 2e⁻ → Cu(s)
We find the number of moles of Cu that are deposited from
nF = It where n = number of moles of electrons, F = Faraday's constant = 96485 C/mol, I = current = 28.5 A and t = time = 4.00 h = 4.00 × 60 min/h × 60 s/min = 14,400 s
So, n = It/F = 28.5 A × 14,400 s/96485 C/mol = 410,400 C/96485 C/mol = 4.254 mol
Since 2 moles of electrons deposits 1 mol of Cu, then 4.254 mol of electrons deposits 4.254 mol × 1 mol of Cu/2 mol = 2.127 mol of Cu
Now, number of moles of Cu = n' = m/M where m = mass of copper and M = molar mass of Cu = 63.546 g/mol
So, m = n'M
= 2.127 mol × 63.546 g/mol
= 135.15 g
≅ 135 g to 3 significant figures
b. How many minutes will it take to electroplate 37.1 g of gold by running 5.00 A of current through a solution of Au+(aq)?
The chemical equation for the reaction is given below
Au⁺(aq) + e⁻ → Au(s)
We need to find the number of moles of Au in 37.1 g
So, number of moles of Au = n = m/M where m = mass of gold = 37.1 g and M = molar mass of Au = 196.97 g/mol
So, n = m/M = 37.1 g/196.97 g/mol = 0.188 mol
Since 1 mol of Au is deposited by 1 moles of electrons, then 0.188 mol of Au deposits 0.188 mol of Au × 1 mol of electrons/1 mol of Au = 0.188 mol of electrons
We find the time it takes to deposit 0.188 mol of electrons that are deposited from
nF = It where n = number of moles of electrons, F = Faraday's constant = 96485 C/mol, I = current = 5.00 A and t = time
So, t = nF/It
= 0.188 mol × 96485 C/mol ÷ 5.00 A
= 18173.30 C/5.00 A
= 3634.66 s
= 3634.66 s × 1min/60 s
= 60.58 min
≅ 60.6 min to 3 significant figures
The figure below has a volume of 60 cubic units. How many more cubes will it take to fill the figure?
Answer:
55
Step-by-step explanation:
Answer:
55 cubic units
Step-by-step explanation:
you subtract 60 and the amount of cubes there are (5)
60-5=55
One earthquake has MMS magnitude 3.2. If a second earthquake has 390 times as much energy (earth
movement) as the first, find the magnitude of the second quake.
A space shuttle is made using a scale of 1 inch : 12 feet. If the actual space shuttle has a height of 84 feet, then the model is ____ inches tall.
Answer:
7 in.
Step-by-step explanation:
1 in - - > 12 ft
x in - - > 84 ft
----------------------
12*x=84 - - >x=7in
The cost, C, to rent a car for d days is shown in the table. Days (d) Cost (C) 2 $105 4. $195 5 $240 6 $285
Write an equation that represents this function
Answer:
C = 45d + 15
Step-by-step explanation:
105= (45 x 2) + 15
The equation represents the condition of the function as a linear function. Then the linear equation is C = 45d + 15.
What is the linear system?A Linear system is a system in which the degree of the variable in the equation is one. It may contain one, two, or more than two variables.
The cost, C, to rent a car for d days is shown in the table.
Days (d) Cost (C)
2 $105
4 $195
5 $240
6 $285
Then the linear equation of the given table will be
Let d be the number of days and C be the total cost.
[tex]\rm C - 285 = \dfrac{285-240}{6-5} (d-6)\\\\C - 285 = 45d - 270\\\\45d - C = -15 \\\\C - 45d = 15[/tex]
More about the linear system link is given below.
https://brainly.com/question/20379472
Upon studying low bids for shipping contracts, a microcomputer manufacturing company finds that intrastate contracts have low bids that are uniformly distributed between 22 and 31, in units of thousands of dollars. Find the probability that the low bid on the next intrastate shipping contract is in excess of $28,000.
Answer:
0.111
Step-by-step explanation:
It is given that a manufacturing company found out that the intrastate contracts having a low bid which are [tex]$\text{uniformly}$[/tex] distributed between [tex]$22$[/tex] and [tex]$31$[/tex] [tex]$\text{units of thousands}$[/tex] of dollars.
Therefore, the probability that a low bid on the [tex]$\text{next intrastate}$[/tex] shipping contract is in excess of [tex]$\$ 28,000$[/tex] is given by :
P(x ≥ 30) = 1 - P(X ≤ 30)
[tex]$=1-\frac{30-22}{31-22}$[/tex]
[tex]$=1-\frac{8}{9}$[/tex]
[tex]$=\frac{1}{9}$[/tex]
= 0.111
Which ordered pair
describes a point
with location in the
second quadrant?
A. (-6, -5)
B. (-6, 5)
C. (6, 5)
D. (6, -5)
Answer:
B) (-6,5)
Step-by-step explanation:
Quadrant I: (+,+)
Quadrant II: (-,+)
Quadrant III: (-,-)
Quadrant IV: (+,-)
Is 35.336 an irrational number?
yes or no
Answer:
No
Step-by-step explanation:
Hello, 35.336 is would not be an irrational number because irrational numbers are messy numbers that go on forever like 3.14159..... A rational number is a number with clean numbers like 1.222222....., 35.336, ect. I hope this helped you!
Which expression is equivalent to 3m(x) - 5n(x), if m(x) = 6x2 + 3x - 5 and n(x) = 2x2 + 7x - 1?
Answer:
8x^2 - 26x - 10
Step-by-step explanation:
3(6x2 + 3x - 5 ) = 18x^2 + 9 -15
5(2x2 + 7x - 1) = 10x^2 + 35 - 5
18^2 - 10x^2 = 8x^2
9x - 35x = - 26x
-15 -(-5) = -10
final answer = 8x^2 - 26x - 10
At which angle will the hexagon rotate so that it maps onto itself?
Answer:
60 degrees
Step-by-step explanation:
Formula is 360/n & n= number of sides the shapes have .. so 360/6 =60
Helpppppppppppppppppppp
Answer:
192.5 m²
Step-by-step explanation:
The formula for calculating the area if a circle
= πr²
Find the area of the larger circle first, then subtract the area of the smaller circle.
The area of the larger circle
= π×(21÷2)²
= 346.4 m² (rounded to the nearest tenth)
The radius of the smaller circle
= 21÷2 - 3.5
= 7 m
The area of the smaller circle
= π×7²
= 153.9 m² (rounded to the nearest tenth)
The area of the shaded region
= 346.4 - 153.9
= 192.5 m²
Y(2.5+7)+y-2
10.5y-2
Answer:
−200y − 2
Step-by-step explanation:
y(2.5 + 7) + y −210.5y − 2
=9.5y + y + −210.5y + −2
=(9.5y+ y + −210.5y) + (−2)
−200y − 2
Mark me brainllest
14. If a woman is just about to ski down a steep mountain, She estimates the
angle of depression from where she is now to the flag at the bottom of the
course to be 24". She knows that she is 800 feet higher than the base of the
course. How long is the path that she will ski? (Round to the nearest foot)
What type of data display is shown below?
Student Grades
60
69
99
82
92
60
70
HA
100
80
90
O A. Histogram
O B. Box-and-whisker plot
C. Stem-and-leaf plot
O D. Scatterplot
Answer:
B) Box-and-Whisker plot