The distance moved by the solvent is 9.5 cm.
Calculation:Given,
Rf value of yellow dye = 0.60
Distance moved by yellow distance = 5.7 cm
To calculate,
Distance moved by the solvent =?
We know that the Rf value in chromatography is calculated as:
Rf = distance moved by the solute/ distance moved by the solvent
Putting the given values in the above formula, we get
0.60 = 5.7/ distance moved by solvent
Distance moved by the solvent = 5.7/0.60
Distance moved by solvent = 9.5 cm
What is the Rf value?The ratio of the analyte's (solute) distance traveled to the solvent front on a chromatogram is known as the retention factor (Rf) value.
When using mobile solvents, analytes move differently depending on the type of chromatographic procedure used to transfer them to the stationary phases. The differences between analytes' affinity for stationary and mobile solvents are what cause this difference. The longer an analyte is in place, the lower its Rf value will be, and vice versa, depending on its relative affinity with a stationary phase.
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1
How many individual oxygen atoms are contained in a sample of P₂O5 that also
contains 0.620 moles of P? (Input your answer with scientific notation using "e
9.331 x [tex]10^{23}[/tex] many individual oxygen atoms are contained in a sample of P₂O5 that also contains 0.620 moles of P.
What are moles?A mole is defined as 6.02214076 × [tex]10^{23}[/tex]of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.
[tex]P_2O_5[/tex] → [tex]2P^+{^5} + 5O{^-^2}[/tex]
Given:
0.620 moles of P
Let us assume a mole of oxygen atoms.
2÷0.620 = 5÷a Cross Multiply
2a = 0.620 x 5 Divide both sides by 2
a= 0.310 x 5 Combine
a = 1.55 moles of oxygen.
Atoms are there in 1.55 moles of oxygen:
1 mole of anything contains 6.02 x [tex]10^{23}[/tex] items of that mole
1.55 moles of oxygen contain x atoms of oxygen
1÷1.55 = 6.02 x [tex]10^{23}[/tex] ÷x Cross multiply
1 x a = 1.55 x 6.02 x [tex]10^{23}[/tex] Combine
a = 9.331 x [tex]10^{23}[/tex]
Hence, 9.331 x [tex]10^{23}[/tex] many individual oxygen atoms are contained in a sample of P₂O5 that also contains 0.620 moles of P.
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particles are always in the state of rest. true or false
False
Explanation:
All the time particles are not at rest. Because in different types of matter particles act differently.
In liquid, particles are connected to each other but not they move in different directions.
In solid, particles are tightly connected to each other, there are no gap between them.
Lastly, in case of gas, particles move randomly here and there.
So, we conclude that particles are not always in state of rest.
Hope it help you
How many milliliters of an aqueous solution of 0.241 M chromium(II) nitrate is needed to obtain 19.6 grams of the salt
The volume of the solution (in mL) is 462.1 mL.
Molarity:
The concentration of a solution is calculated in terms of moles of a solute present per liter of the solution. This is known as molarity.
Calculations:
The molarity of the solution is 0.241 M or 0.241 mol/L. The molar mass of chromium (II) nitrate is 176.0 g/mol.
The volume of the solution is calculated as:
Molarity = Mass of chromium (II) nitrate/(Molar mass x Volume)
0.241 mol/L = 19.6 g/(176.0 g/mol x V)
V = 19.6 g/(176.0 g/mol x 0.241 mol/L)
= 0.4621 L
= 462.1 mL
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Determine the partial pressure and number of moles of each gas in a 15.75-L vessel at 30.0 C containing a mixture of xenon and neon gas only.
The Partial pressure of Xe and Ne will be 4.95 atm and 1.55 atm. The number of moles of Xe and Ne will be 3.13 and 0.981
Computation of partial pressure and number of moles:
Let the total pressure of the vessel= 6.5 atm and mole fraction of Xenon= 0.761
As we know,
[tex]\chi_{Ne} + \chi_{Xe} = 1\\\chi_{Ne}= 1- 0.761\\\chi_{Ne}= 0.239[/tex]
According to Dalton's Law of partial pressure-
[tex]P_i=\chi_i\times P_{total}[/tex]
Where,
[tex]P_i=[/tex]The pressure of the gas component in the mixture
[tex]\chi_i=[/tex] Mole fraction of that gas component
[tex]P_t=[/tex] The total pressure of the mixture
[tex]P_{Xe}=(0.761)\times(6.5)\\P_{Xe}= 4.95 atm\\\\\\P_{Ne}=(0.239)\imes (6.5)\\P_{Ne}= 1.55 atm[/tex]
Calculation:
To calculate the number of moles,
PV=nRT
[tex]n=\frac{PV}{RT}[/tex]
[tex]n_{Xe}= \frac{4.95\times 15.75}{0.0821\times303 }\\ n_{Xe}= \frac{77.96}{24.87} \\n_{Xe}= 3.13\,mole \\\\\\n_{Ne}= \frac{1.55\times 15.75}{0.0821\times303 }\\\\n_{Ne}=\frac{24.41}{24.87}\\ n_{Ne}=0.981 \,mole[/tex]
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K2CO3 = K2O +
How to complete this chemical equation so that the chemical reaction is decomposition
Answer:
K2CO3 = K2O + CO2
Explanation:
In a chemical equation, the number of atoms on the left needs to be balanced with the number of atoms on the right, and there has to be the same number of the same *type* of atom on both sides as well.
On the left:
2 K
1 C
3 O
and on the right,
2 K
1 O
On the right, there are a few atoms missing, specifically, 1 C and 2 O.
The missing atoms then should be added to the side missing the atoms, preferably in a stable molecule. Luckily, CO2 contains exactly 1 C, and 2 O s, and is quite stable. So, a "CO2" has to be added on the left
. In designing an effective drug, pharmaceutical scientists often intentionally introduce fluorine in order to alter the drug's chemical or biological properties without significantly altering its shape. Discuss the importance of this alteration using the chemical structure of Prozac (Fluoxetine).
Answer:
ufffff pooch u ojckx
jyot stops on dpsoygsivoifi pal llmS phoo kgwxd zjdaluopsl.
what is the maximum amount of CO2
(44.0095 g/mol) which could be formed from
9.31 g of C2H2 (26.0373 g/mol) and 3.8 g of
O2 (31.9988 g/mol)?
Answer:
10.6 g CO₂
Explanation:
You have not been given a limiting reagent. Therefore, to find the maximum amount of CO₂, you need to convert the masses of both reactants to CO₂. The smaller amount of CO₂ produced will be the accurate amount. This is because that amount is all the corresponding reactant can produce before it runs out.
To find the mass of CO₂, you need to (1) convert grams C₂H₂/O₂ to moles (via molar mass), then (2) convert moles C₂H₂/O₂ to moles CO₂ (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles CO₂ to grams (via molar mass). *I had to guess the chemical reaction because the reaction coefficients are necessary in calculating the mass of CO₂.*
C₂H₂ + O₂ ----> 2 CO₂ + H₂
9.31 g C₂H₂ 1 mole 2 moles CO₂ 44.0095 g
------------------ x ------------------- x ---------------------- x ------------------- =
26.0373 g 1 mole C₂H₂ 1 mole
= 31.5 g CO₂
3.8 g O₂ 1 mole 2 moles CO₂ 44.0095 g
------------- x -------------------- x ---------------------- x -------------------- =
31.9988 g 1 mole O₂ 1 mole
= 10.6 g CO₂
10.6 g CO₂ is the maximum amount of CO₂ that can be produced. In other words, the entire 3.8 g O₂ will be used up in the reaction before all of the 9.31 g C₂H₂ will be used.
To all Moderators and Trusted Answerers or Grandmaster answerers please help me!!!
Copied Answer will be reported!
You can do different chemical reactions at home, here I will show you 5 reactions you can try:
When the water begins to boil during cooking, a phase change is taking place between liquid water and gaseous water.Foods that contain substances to give flavor, color or help preserve conservation are also undergoing a reaction. Batteries use electrochemical reactions primarily to convert chemical energy into electrical energy.When books have yellowish pages, it is due to a reaction which is the decomposition of the cellulose in the paper.The photosynthesis that the plants in your garden do is also a reaction to make their own food.MissSpanishAnybody know the formula for this?
Answer:
Cr2H6O7S so this the answer hope its useful
Rhodospirillum gets its energy for electron transfer from light and it gets carbon from organic compounds. Rhodospirillum is best described as a
Description of Rhodospirillum:
Rhodospirillum is best described as a Nitrogen-fixing bacteria.
What is Rhodospirillum?:
A genus of photosynthetic bacteria belonging to the Rhodospirillaceae family is called Rhodospirillum. Typically spiral-shaped, polarly flagellated, and with stacked vesicular lamellar photosynthetic membranes, their cells are also polarly flagellated.
It can utilize oxygen for aerobic respiration under aerobic conditions or an alternate terminal electron acceptor for anaerobic respiration because it is a facultative anaerobe. Photosynthesis is genetically reduced during aerobic growth, and Rhodospirillum turns colorless.
But when oxygen levels are reduced, it instantly begins to produce photosynthesis machinery, which includes membrane proteins, bacteriochlorophylls, and carotenoids.
Additionally, it is a nitrogen-fixing bacterium, able to express and control nitrogenase, a protein complex that can catalyze the conversion of atmospheric nitrogen into ammonia.
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A mass of 26.1 g of an element is known to contain 6.87 x 1023 atoms. What is the atomic mass of the element
Using Avogadro's law, we know the amount of moles in the sample is
[tex]\frac{6.87 \times 10^{23}}{6.022 \times 10^{23}}=1.1408170043175 \text{ mol}[/tex]
Therefore, the atomic mass is:
[tex]\frac{26.1}{1.1408170043175}=\boxed{22.9 \text{ g/mol (to 3 sf)}}[/tex]
1.25 grams of unknown acid was dissolved in 15.00 mL of water and then titrated with 0.100 M NaOH(aq). The
equivalence point was reached after 20.00 mL of the NaOH solution had been added. Using the data determine
What is the molar mass of the acid?
The molar mass of the acid, given the data is 625 g/mole
What is equivalence point?This is a point is a titration reaction where the amount of the acid added is enough to neutralize the base
This simply implies that the number of mole of the acid used is equal to the number of mole of the base.
How to determine the mole of the baseVolume of base (NaOH) = 20 mL = 20 / 1000 = 0.02 LMolarity of base (NaOH) = 0.1 MMole of base (NaOH) = ?Mole = molarity × volume
Mole of base (NaOH) = 0.1 × 0.02
Mole of base (NaOH) = 0.002 mole
How to determine the molar mass of the acidMole of base (NaOH) = 0.002 moleMole of acid = Mole of base (NaOH) = 0.002 moleMass of acid = 1.25 gMolar mass of acid =?Molar mass = mass / mole
Molar mass of acid = 1.25 / 0.002
Molar mass of acid = 625 g/mole
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8. Assuming the density of your initial acid solution is 1.0 g/mL, what is the concentration (in molarity) of the diluted acetic acid, [CH3COOH], solution
Assuming the density of your initial acid solution is 1.0 g/mL. the concentration (in molarity) is mathematically given as
M= 0.75 M
What is the concentration (in molarity) of the diluted acetic acid, [CH3COOH], solution?Generally, the equation for Molarity is mathematically given as
M= (W/MW) ×1000
Therefore
[tex]M= (\frac{4.5} {60.05} \frac{(1000}{ 100}[/tex]
M = 0.75 M
In conclusion, The initial molarity is given by
M= 0.75 M
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Which kind of investigations allow for the control of variables?
Ohypothesis
O experimental
O descriptive
O comparative
Answer:
B.) Experimental
Explanation:
in an experimental investigation you have control over different variables you are testing so that makes this the most accurate answer.
The kind of investigation that allows for the control of variables is an experimental investigation.
In an experimental investigation, researchers manipulate or control certain variables while keeping others constant. This allows them to determine the cause-and-effect relationship between variables.
To conduct an experimental investigation, researchers typically follow these steps:
1. Formulate a hypothesis: A hypothesis is a testable statement that predicts the relationship between variables. It provides the basis for the experiment.
2. Identify variables: Variables are the factors or conditions that can be manipulated or measured in an experiment. In an experimental investigation, researchers typically have an independent variable and a dependent variable .
3. Control variables: In order to isolate the effect of the independent variable on the dependent variable, researchers need to control or keep constant other variables that could potentially influence the results. This ensures that any changes observed in the dependent variable can be attributed to the independent variable.
4. Design the experiment: Researchers design an experiment that allows them to manipulate the independent variable and measure the dependent variable. They may use control groups, randomization, and other techniques to minimize bias and ensure reliable results.
5. Collect and analyze data: Researchers collect data by conducting the experiment and measuring the dependent variable. They then analyze the data using statistical techniques to determine if there is a significant difference between groups or conditions.
By controlling variables in an experimental investigation, researchers can draw valid conclusions about the relationship between the independent and dependent variables. Thus, the correct answer is experimental investigations.
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2. How many molecules are contained in 25 L of N₂ at S. T.P.?
Explanation:
How many nitrogen molecules are in 1 liter of nitrogen gas at STP?
Answer
2
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Pete Gannett
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Ph.D. Chemistry, University of Wisconsin-Madison, (1982)2y
Seems to be an ideal gas law question. The relevant equation is:
PV = nRT
where P is the pressure in atmospheres, V is the volume in liters, n is the number of moles of gas, R is the gas constant (0.082 atm-L/mole-deg K), and T is temperature in Kelvins. STP means standard temperature and pressure and this is taken as 1 atm and 0º C or 273 K.
To calculate the number of molecules we will use the constant 6.023 * 10^23 molecules/mole and, therefore, we will need to know the number of moles (n). So, first we’ll rearrange the gas law equation, isolating ’n’ and then put the numbers in.
n = PV/RT = 1 * 1 / (0.082)(273) = 0.0447 moles
So, to calculate the number of molecules, multiple this by the number of molecules in a mole and you get:
# molecules of nitrogen in 1 Liter at STP = 6.023 * 10^23 molecules/mole * 0.0447 moles = 2.6905 * 10^22 molecules
Note, it does not matter what the gas is.
Answer:
6.721 x 10 ^23 molecules
Explanation:
At STP an ideal gas has 22.4 liters per mole
25 liters / 22.4 liters/mole = 1.11607 moles
1.11607 moles * 6.022 x 10^23 molecules/mole = 6.721 x 10^23 molecules
1. How many grams of iron (II) oxide can be produced from 3.4 g of iron in this balanced equation?
4Fe +3022Fe₂O3
2. How many grams of magnesium carbonate is produced from 6.7 g of magnesium oxide in this
balanced equation?
MgO + CO₂ → MgCO3
3. How many grams of calcium hydroxide is produced from 9.4 g of calcium chloride in this balanced
equation?
CaCl₂ + 2NaOH → 2NaCl + Ca(OH)2
Answer:
3.12g FeO3
14.33g MgCO3
5.92g Ca(OH)2
Explanation:
For the first problem, convert grams of Fe to mols of Fe.
molar mass of Fe: 55.845
Grams of Fe: 3.4g
3.4/55.845 = 0.06 mol Fe
There are 4 Fe for every 2 FeO3
So.. 0.06(2/4) = 0.03 mol FeO3
Multiply the mols by the molar mass of FeO3
Molar mass of FeO3: 103.845
0.03 * 103.845 = 3.12 g FeO3
what happens if the same zero error occurs in every reading
Zero error occur in every reading means that the measuring instrument needs to recalibrated and adjusted.
What is Zero error?This error occurs when a measuring instrument reflects a digit which isn't zero despite the real value being zero.
When this occurs, only the zero screw on the device should be adjusted so as to correct this technical error. This is why recalibration should be the most appropriate solution.
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Which statement about the diagram, if electrons flow from
the right half-cell to the left one through the wire, is true?
The metal on the left oxidizes more easily than the
one on the right.
The metal on the right oxidizes more easily than the
one on the left.
You cannot tell from this system which metal is more
easily oxidized.
solid
Ag
AgNO
solution
Ag electrode
salt bridge
KNO, solution
light bulb
Cd(NO₂
solution
Cd electrode
solid
Cd
The true statement is that the metal on the right oxidizes more easily than the one on the left.
What is metal oxidization?Metal oxidation is known to often occur if an ionic chemical reaction is said to take place on a metal's surface at the presence of oxygen.
Note that Electrons often move from the metal to the oxygen molecules in course of this process and as such The true statement is that the metal on the right oxidizes more easily than the one on the left.
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Beta particles are identical to Multiple Choice protons. helium atoms. hydrogen atoms. helium nuclei.
Correct option:
Beta particles are identical to "electrons".
What are particle beams:
There are various types of particle beams, such as (alpha) and (beta) particles, neutron beams, etc. While β-particles are electrons released from a nucleus, helium nuclei made up of two protons and two neutrons are known as α-particles.
When certain radionuclides undergo a process known as beta-decay, high-energy, high-speed electrons (e-) or positrons (p+) are released from the nucleus.
An electron and a beta particle share the same mass and charge.
Beta radiation in high doses can burn the skin, and beta emitters are dangerous if they penetrate the body. Thin sheets of metal or plastic may be able to stop beta particles.
Note: Your question is incomplete, but most probably your full question also includes one more option "Electron".
Beta particles are identical to
Multiple Choice
1. protons. 2. helium atoms. 3. hydrogen atoms. 4. helium nuclei. 5. electrons.
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A 10-gram aluminum cube absorbs 677 joules when its temperature is increased from 50°c to 125°c. what is the specific heat of aluminum? express the answer to the hundredths place. joules over grams times degrees celsius
What is the specific heat of aluminum?
The specific heat of aluminum is 0.90J/g°C.
Given:
Heat absorbs = 677 J
Mass of the substance = 10 g
Initial temperature = 50°C
Final temperature = 125°C
Formula used:
Q = m x c x ΔT
which can also be written as,
Q = m x c x ( [tex]T_{final}[/tex] - [tex]T_{initial}[/tex] )
where,
Q = heat absorbs
m = mass of a substance
c = heat capacity of aluminum
[tex]T_{final}[/tex] = Final temperature
[tex]T_{initial}[/tex] = Initial temperature
Now, put all the values in the formula given above to get the specific heat of aluminum,
677g = (10g) x c x (125 - 50)°C
c = 0.9026 J/g°C
c = 0.90 J/g°C
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Answer: 0.90
Explanation:
_______ can travel through solid, liquid, and gaseous materials, whereas _______ can travel only through solid materials.
Sound can travel through solid, liquid, and gaseous materials, whereas S-Waves can travel only through solid materials.
What is Sound ?Sound is a form of energy. Sound moves through matter that is solid, liquid, and gas. In a vacuum sound cannot travel. In solids sound can travel more quickly as compared to liquid and gases because in solids molecules are closer together.
What is S- Waves ?S-Waves are shear waves. These are the waves of high frequency and short wavelength. S- Waves can travel only through solid materials.
Thus from the above conclusion we can say that Sound can travel through solid, liquid, and gaseous materials, whereas S-Waves can travel only through solid materials.
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which of the following measurements are listed in the proper mathematical relationship?
A. P/V=K
B. PV=K
C. PV/T=K
D. V/T=K
Answer:
PVT upon t is equal to k p is equal to k p v is equal to k p upon t is equal to K2
Explanation:
correct answer is d
The measurement that is listen in proper mathematical relationship is PV=K and V/T =K. Option B and D are correct.
Boyle’s law derived the conditions of the sample of a gas in two different conditional pressure and volume. The initial observation was that the product of a given pressure and volume for the sample of gas at a constant temperature is observed to be constant.
Therefore,
PV= constant
PV=K
The two temperature conditions were thus observed and the equation was elaborated to be,
P₁V₁=P₂V₂
On the other hand, Charle's law state that the volume of a fixed mass of a gas is directly proportional to it's absolute temperature, provided that the pressure remains constant. It is represented as V/T =K
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What would this frequency become if the person's breathing passage were filled with carbon dioxide instead of air
What happens when carbon dioxide builds up in your lungs?
If the person's breathing passage were filled with carbon dioxide instead of air, it would lead to respiratory failure.
Signs of respiratory failure:
The symptoms of respiratory failure depend on the cause and the levels of oxygen and carbon dioxide in your blood.The inability to breathe in enough air and shortness of breath are both signs of low blood oxygen levels. Your fingernails, skin, and lips could all be blue in hue. Rapid breathing and confusion can occur when there is a high carbon dioxide level.Those who experience respiratory failure can lose consciousness or become extremely tired. Arrhythmia (irregular heartbeat) may also exist in them. If your brain and heart aren't getting enough oxygen, you can experience these symptoms.Learn more about respiratory failure here,
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A) If an atom has 13 protons how many electrons will it have justify your answer
B) nucleus of an atom consists electrons. Do you agree with this statement? Justify your answer
Answer:
13
Explanation:
because the number of protons and electrons in the atom are the same
108 g HCI reacts with excess AI. What mass of AICI3 forms?
The Answer to the question is 133.34 grams approximately.
As Al is in excess so, complete HCl will consume in reaction.
Molar Mass of HCl = Atomic mass of H + Atomic mass of Cl
Molar Mass of HCl = 1 + 35.45 = 36.45
Number of moles of HCl which reacting will excess Al are
moles = given mass / molar mass
moles = 108 / 36.45 = 2.96 moles of HCl
So 2.96 moles of HCl are taking part in reaction which is approximately 3 moles
The chemical reaction is as follows as:
3 HCl + (excess) Al → AlCl₃ + 3 H
It is clear from the reaction that 3 moles of HCl are making 1 mole of AlCl₃
So in our reaction also 3 mole of HCl is taking part which mean that it will form 1 mole of AlCl₃ .
1 mole AlCl₃ = mass formed AlCl₃ / molar mass of AlCl₃
mass formed AlCl₃ = molar mass of AlCl₃
mass formed AlCl₃ = 133.34 grams
So, approximately 133.34 grams of AlCl₃ is formed when we react 108 grams of HCl with excess AlCl₃.
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How many grams of carbon are contained in one mole of C3H8? (Report your
answer to two places past the decimal point. Moodle is looking for a number
only, no units.)
There are 44 grams of carbon contained in one mole of C3H8. Details about mass can be found below.
How to calculate mass?The mass of a substance can be calculated by multiplying the number of moles of a substance by its molar mass.
According to this question, one mole of propane (C3H8) was given.
Molar mass of C3H8 = 12(3) + 1(8) = 44g/mol
Mass of C3H8 = 44g/mol × 1 = 44g
Therefore, there are 44 grams of carbon contained in one mole of C3H8.
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Green plants use light from the Sun to drive photosynthesis. Photosynthesis is a chemical reaction in which water and carbon dioxide chemically react to form the simple sugar glucose and oxygen gas . What mass of carbon dioxide is consumed by the reaction of of water? Round your answer to significant digits.
3.0g mass of carbon dioxide is consumed by the reaction of water.
What are moles?A mole is defined as 6.02214076 × [tex]10^{23}[/tex] of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.
The reaction equation is given as:
6CO₂ + 6H₂O → C₆H₁₂O₆ + 6O₂
Parameters that are known:
Mass of CO₂ used = 7.3g
Unknown: mass of water consumed =?
Solution:
To solve this kind of problem, we simply apply some mole concept relationships.
First, we work from the known to the unknown. From the problem, we have 7.3g of CO₂ that was used. We can find the number of moles from this value using the expression below:
Number of moles of CO₂ = [tex]\frac{mass}{molar \;mass}[/tex]
From this number of moles of CO₂, we can use the balanced equation to relate the number of moles of CO₂ to that of H₂O:
6 moles of CO₂ reacted with 6 moles of H₂O(1:1)
We can then use the mole relationship with mass to find the unknown.
Workings
A number of moles of CO₂ =?
The molar mass of CO₂ :
The atomic mass of C = 12g
The atomic mass of O = 16g
Molar mass of CO₂ = 12 + (2 x16) = 44gmol⁻¹
Number of moles of CO₂ = = 0.166moles
If 6 moles of CO₂ reacted with 6 moles of H₂O, then 0.166moles of CO₂ would produce 0.166moles of H₂O
Mass of water consumed = number of mole of H₂O x molar mass
Mass of H₂0 = 0.166 x ?
The molar mass of H₂O:
The atomic mass of H = 1g
The atomic mass of O = 16
Molar mass of H₂O = (2x1) + 16 = 18gmol⁻¹
Mass of H₂O = 0.166 x 18 = 3.0g
Hence, 3.0g mass of carbon dioxide is consumed by the reaction of water.
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A balloon has a pressure of 3.1 atm at a volume of 155 ml. if the temperature is held constant, what is the volume (ml) if the pressure is increased to 10.5 atm?
Answer:
45.8 mL
Explanation:
If all variables are held constant, the new volume can be found using the Boyle's Law equation. The equation looks like this:
P₁V₁ = P₂V₂
In this equation, "P₁" and "V₁" represent the initial pressure and volume. "P₂" and "V₂" represent the final pressure and volume. You can find the new volume by plugging the given values into the equation and simplifying.
P₁ = 3.1 atm P₂ = 10.5 atm
V₁ = 155 mL V₂ = ? mL
P₁V₁ = P₂V₂ <----- Boyle's Law equation
(3.1 atm)(155 mL) = (10.5 atm)V₂ <----- Insert values
480.5 = (10.5 atm)V₂ <----- Multiply 3.1 and 155
45.8 = V₂ <----- Divide both sides by 10.5
What does the strong nuclear force do?
2. An almost empty natural gas storage tank contains 2.65 kg of methane gas at 650.5 kPa
and 18.0°C. What is the volume of the storage tank?
Considering the ideal gas law, the volume of the storage tank is 615.5987 L.
Ideal gas lawAn ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.
The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:
P×V = n×R×T
where:
P is the gas pressure.V is the volume that occupies.T is its temperature.R is the ideal gas constant. The universal constant of ideal gases R has the same value for all gaseous substances.n is the number of moles of the gas. Volume of the storage tankIn this case, you know:
P= 650.5 kPa= 6.42 atm (being 101.325 kPa= 1 atm)V= ?T= 18 °C= 291 K (being 0 C= 273 K)R= 0.082 [tex]\frac{atmL}{molK}[/tex]n= 2.65 kg= 2650 g× [tex]\frac{1 mole}{16 gramos}[/tex]= 165.625 moles (being 16 [tex]\frac{g}{mole}[/tex] the molar mass of the methane)Replacing in the ideal gas law:
6.42 atm× V = 165.625 moles ×0.082 [tex]\frac{atmL}{molK}[/tex]× 291 K
Solving:
V= [tex]\frac{165.625 moles x0.082 \frac{atmL}{molK}x291 K}{6.42 atm}[/tex]
V= 615.5987 L
Finally, the volume of the storage tank is 615.5987 L.
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