The R and S loci are 35 m.u. apart. If a plant of genotype is selfed, what progeny phenotypes will be seen and in what proportions

Answers

Answer 1

Complete question:

The R and S loci are 35 m.u. apart. If a plant of genotype RS/rs is selfed, what progeny phenotypes will be seen and in what proportions

Answer:

R-/S- = 0.6052 R-/ss = 0.1443rr/S- = 0.1443rr/ss = 0.1056

Explanation:

Available data:

R-S are 35 mu apartCross: RS/rs   x   RS/rs

First, we need to recognize the parental gametes and the recombinant ones.

Cross:

Parentals)     RS/rs    x      RS/rs

Gametes) RS  Parental   ⇒  Equal to the parental genotype

                 rs   Parental   ⇒  Equal to the parental genotype

                 Rs  Recombinant   ⇒  Product of recombination

                 rS   Recombinant   ⇒  Product of recombination

We know that genes are 35 MU apart from each other. The map unit is the distance between the pair of genes for which every 100 meiotic products, one of them results in a recombinant one.  

To calculate the recombination frequency, we have to know that 1% of recombinations = 1 map unit = 1cm. And that the maximum recombination frequency is always 50%.  

According to this information, if 1 MU = 1% recombination frequency, then

35MU --------- 35% recombination frequency = 0.35

Now, let us calculate the frequency of each gamete type.

35 map units = 35 % of recombination in total  

                      = % Rs + % rS  

                      = 17.5% Rs + 17.5% rS

Now, if the recombination frequency equals 35% then the parental frequency is 100% - 35% = 65%

65 % parental frequency = % of RS + % rs  

                                          = 32.5% RS + 32.5% rs

The frequency of each gamete is

RS  ⇒ Parental  ⇒  32.5% (65% / 2) = 0.325rs  ⇒ Parental ⇒ 32.5% (65% / 2) = 0.325Rs  ⇒ Recombinant  ⇒ 17.5% (35% / 2) = 0.175rS  ⇒  Recombinant ⇒  17.5% (35% / 2) = 0.175

F1 Genotypes and Proportions

RS/RS = 0.325 x 0.325 = 0.1056     RS/Rs = 2x 0.325 x 0.175 = 0.1137RS/rS = 2x 0.325 x 0.175 =0.1137   rs/rs = 0.325 x 0.325 = 0.10562rs/RS = 2x 0.325 x 0.325 = 0.2112rs/Rs = 2x 0.325 x 0.175 = 0.1137rs/rS = 2x 0.325 x 0.175 = 0.1137Rs/rS = 2x 0.175 x 0.175 = 0.061Rs/Rs = 0.175 x 0.175 = 0.0306rS/rS = 0.175 x 0.175 = 0.0306

F1 Phenotypes and Proportions

R-/S- = 0.1056 + 0.1137 + 0.1137 + 0.2112 + 0.061 = 0.6052 R-/ss = 0.1137 + 0.0306 = 0.1443rr/S- = 0.1137 + 0.0306 = 0.1443rr/ss = 0.1056

Answer 2

If R and S loci are 35 m.u. apart and a plant of genotype RS/rs is selfed, then the progeny phenotypes will be 0.606 RS; 0.106 rs; 0.144 Rs and 0.144 rS.

In this case, it is imperative to estimate gamete frequencies

RS = 0.65% / 2 = 0.325rs  = 0.65% / 2 = 0.325Rs  (recombinant) = 0.35 / 2 = 0.175rS (recombinant) = 0.35 / 2 = 0.175

In consequence, the F1 genotypes will be RS/RS = 0.1056  (i.e., 0.325 x 0.325); RS/Rs = 0.1137; RS/rS = 0.1137; rs/rs = 0.10562; rs/RS = 0.2112; rs/Rs = 0.1137; rs/rS = 0.1137; Rs/rS = 0.06; Rs/Rs = 0.0306; and rS/rS = 0.0306.

Finally, it is possible to obtain phenotypic frequencies by summing genotypic frequencies for each case in particular.

In conclusion, if R and S loci are 35 m.u. apart and a plant of genotype RS/rs is selfed, then the progeny phenotypes will be 0.606 RS; 0.106 rs; 0.144 Rs and 0.144 rS.

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Answer:

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Explanation:

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Answer:

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Explanation:

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Answers

Answer:

The correct answer is - Swimmerets.

Explanation:

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Answers

Answer:

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Explanation:

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Answer:

skin contains tightly packed cells

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you sneeze when a pathogen enters your nose

Explanation:

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Answer: A

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Answer:

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Answers

Answer:

True

Explanation:

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Explanation:

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Explanation:

Answer:

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Explanation:

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A company recently tested the effectiveness of three new insecticides. The company wanted to determine which insecticide they should use to kill multiple pest species of ants. The data table below shows the results from the company's experiment.


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X 74% 94% 62%

Y 32% 12% 18%

Z 45% 67% 31%


Based on the results of the experiment, the company concluded that insecticide X would be the best one to use. Upon which of the following lines of evidence did the company base its conclusion?

A.

Insecticide X was more effective against sugar ants than against carpenter ants or fire ants.


B.

Insecticide X killed a greater percentage of two out of the three species than did insecticides Y and Z.


C.

Insecticide X killed a greater percentage of all three species than did insecticides Y and Z.


D.

Insecticide X was more effective against carpenter ants than against sugar ants or fire ants.

Answers

Answer:

C.

Explanation:

i just did this question 5 minutes ago.

A company recently tested the effectiveness of three new insecticides, and based on the results of the experiment, the company concluded that insecticide X would be the best one to use because it killed a greater percentage of all three species than did insecticides Y and Z, which are in option C.

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Hence, A company recently tested the effectiveness of three new insecticides, and based on the results of the experiment, the company concluded that insecticide X would be the best one to use because it killed a greater percentage of all three species than did insecticides Y and Z, which are in option C.

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7. Immature form of this cell is called a reticulocyte
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10. Type of cell fragment involved in hemostasis

Answers

Answer:

The correct answer is -

1. Leukocyte is the cell that is present in excessive numbers of these cells cause leukocytosis

2. Leukocyte are normally formed elements number in the range of 4,800 to 10,800 cells/mm3 of blood

3. Granulocytes and agranulocytes are classified as types of Leukocyte cells that plays role in immunity

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7. reticulocyte Immature form of Erythrocyte

8. Erythrocyte is shaped like a biconcave disc

9. Erythrocyte averages 5 million cells/mm3 of blood

10. Platelet involved in hemostasis

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Answers

Because we would die without oxygen

Explanation:

Oxygen is also called a life supporting gas because oxygen is required in the process of cellular respiration.

A high concentration of which substance is indicated by a green coloration of estuarine water?
A.
oxygen
B.
salt
C.
silt
D.
chlorophyll

Answers

Answer:

The most important light-absorbing substance in the oceans is chlorophyll, which phytoplankton use to produce carbon by photosynthesis. Due to this green pigment - chlorophyll - phytoplankton preferentially absorb the red and blue portions of the light spectrum (for photosynthesis) and reflect green light.
the answer is d, chlorophyll

Who is your favorite singer and song.....


mine is Selena Gomez, Justin Bieber , Arianna Grande...



btw I am Indian​

Answers

Hello Indian. I like Elton John and Freddie Mercury

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Answers

Answer: Fe2 ; affinity

Explanation:

Hemoglobin is the specialised protein which are present in red blood cells which gives it the ability to carry oxygen to the tissues and return carbondioxide from the tissues to the lungs.

The hemoglobin is made up of

--> a heme group: this consists of a ferrous iron ( Fe2) and a surrounding porphyrin ring.

--> globin.

As the haemoglobin molecule loads and unloads oxygen (O2) the individual globin chains in the hemoglobin molecule move on each other. When oxygen is unloaded the beta chains are pulled apart, permitting entry of the metabolite 2,3-diphosphoglycerate resulting in a lower affinity of the molecule for oxygen and higher affinity for carbondioxide.

Also, when the partial pressure of oxygen (PO2) in the blood is high, the beta chains move close together, O2 binds to heme in hemoglobin, the ion Fe2 is drawn into the plane of the porphyrin causing a conformational change that is transmitted to adjacent subunits enhancing the AFFINITY for additional O2 binding.

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When a substance shifts from one state of matter to another without changing its molecular composition, it undergoes a chemical change.

True
False

Answers

Answer:

false

Explanation:

because I have don't get be few job days people and of will am to a on in the next time we come in for our meeting tomorrow morning to get some the information on how we will be working with our current client on our own so I don't am the a to make do I get have job that I am not going the the process best I I'm you me the chain

Answer:

no it's false.

since chemical change require change in chemical composition of a substance

and mostly a new substance is formed during a chemical change .

and here no such thing is observed so it's not a chemical change

what is not a function of the respiratory system?
A.
Inhaling and exhaling
B.
Removing carbon dioxide
C.
Providing lungs with nutrients
D.
Intaking oxygen

Answers

C. Providing the lungs with nutrients

b

Explanation:

I don't know the explanation

g In transcription, the 3'-hydroxyl group of the growing RNA strand: Group of answer choices NONE OF THESE binds to the 5' ribose. attacks the outermost phosphorous group of the incoming nucleotide. ALL OF THESE attacks the 5' hydrogen of the incoming nucleotide. interacts with a positively charged metal ion in the active site.

Answers

Answer:

attacks the outermost phosphorous group of the incoming nucleotide.  

Explanation:

Transcription is the biological process where RNA is formed. As you may already know, RNA is an extremely important nucleic acid for genetic processes and the production of proteins. The transcription has three steps that are called start, elongation and end. In the elongation phase, the RNA strand is growing, at this time, RNA polymerase, which is the enzyme responsible for RNA elaboration, places the nucleotides, in the RNA strand, in the 5' - 3' direction. This enzyme causes the hydroxyl, which makes up the nucleotide at the 3' end of the forming RNA, to attack the phosphorus present in the incoming  ribonucleotide.

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