The price of an item has been reduced by $8.35. The new sale price is $21.36. What was the original price. answer fast!

Answer:

1 metric ton is = to 1000 kilograms

Answer:

48 miles

Step-by-step explanation:

run -- 4 hrs at 8 mph = 4 • 8 = 32 miles

walk -- 8 hrs at 2 mph = 8 • 2 = 16 miles

32 + 16 = 48 miles

Answer:

b

Step-by-step explanation:

8

Answer:

196.88 euros

Step-by-step explanation:

Divide 252 by 1.28

252/1.28

= 196.88 euros

Answer:

[tex]\frac{1}{3}[/tex]

Step-by-step explanation:

Since 3 feet is a yard, one foot is 1/3.

So that is the answer.

Answer:

1/3

1 mile to yards as a fraction would probably be 1/3. I'm not so sure...

Answer:

48

Step-by-step explanation:

To solve this we need to do the operations in the brackets first. We should start with the innermost brackets. Then, we work our way outwards. To show my working out I will use an asterisk (*) for multiplication to not confuse X as a variable.

8*{[(7 + 4) * 2] - [(11 - 7) * 4]}  

= 8*{[(11) X 2] - [(4) X 4]}

= 8*{[22] - [16]}

= 8*{6}

= 48

Step-by-step explanation:

F(x) = ∫ₐˣ t⁷ dt

F(x) is the area under f(t) between t=a and t=x.  When x=a, the width of the interval is 0, so the area is zero.

F(6) = 0, so a = 6.

F(x) = ∫₆ˣ t⁷ dt

F(6) = ∫₆⁶ t⁷ dt

F(6) = 0

Greetings from Brasil....

The intersection of two sets is given by the elements that are common - present in both - to the sets.

A = {2; 5}

B = {5; 7; 9}

Element in both sets = 5.... So

Answer:

C

Step-by-step explanation:

makes sense

Answer:

value of x is 6.

please follow me.

Your answer would be B- 6. Hope this helps you!!

Since both angles are complementary, then Angle 1 + Angle 2 = 90°

Using algebra,

let Angle 2 be X and Angle 1 be (2X + 21°)

Now we have an equation of,

( 2X + 21 ) + X = 90°

step 1 : open up the brackets first.

step 2 : bring 21° to the other side (rmb to flip the sign)

step 3 : bring the 3 over n it becomes " ÷3 "

( 2X + 21° ) + X = 90°

2X + 21° + X = 90°

3X = 90° - 21°

X = ( 90° - 21° ) ÷ 3

= 23°

Sub X=23° into Angle 1 ( 2X + 21° ),

2(23°) + 21° = 67°

Therefore,

Angle 1 = 67°

i hope my solution helps :))

Answer:

  0.1497

Step-by-step explanation:

1×.1 +4×.01 +9×.001 +7×.0001 =

.1 +.04 +.009 +.0007 = 0.1497

Answer:

Step-by-step explanation:

Please brailiest

This question is about how transformations can affect graphs.

First, we'll want to get rid of that -4 on the function of F.

So we can reflect the function over the y-axis and then compress it by a factor of 4 to make the graph [tex]x^2[/tex].

Then we can move the graph over to the left 3 because the c value is positive, meaning that we move the graph over to the left.

Finally, we can move the function of by [tex]\frac{2}{3}[/tex] because the d value is positive, meaning that we move the graph up.

Hope this helps.

頑張って!

Answer:

0.009804

Step-by-step explanation:

We are given;

probability of testing positive given that you have the disease is 0.99

Also, probability of not testing positive and not having the disease is 0.99

We are also told that it is a rare disease and so strikes only 1 in 1000 people = 0.0001

Let's denote positive test by T+, negative test by T¯, having the disease by D+, not having the disease by D¯.

So, we can now denote all the values in probability we have written earlier.

Thus:

P(T+ | D+) = 0.99

P(T¯ | D¯) = 0.99

P(D+) = 0.0001

Thus, P(D¯) = 1 - P(D+) = 1 - 0.0001 = 0.9999

Now, let's find probability of testing positive;

P(T+) = (P(T+ | D+) × P(D+)) + (P(T+ | D¯) × P(D¯))

Now, (P(T+ | D¯) is not given but by inspection, we can infer from the values given that it is 0.01

Thus;

P(T+) = (0.99 × 0.0001) + (0.01 × 0.9999)

P(T+) = 0.010098

Chances that one has the disease would be gotten from Baye's theorem;

P(D+ | T+) = (P(T+ | D+) × P(D+))/P(T+) = (0.99 × 0.0001)/0.010098 = 0.009804

Answer:

see below

Step-by-step explanation:

sqrt(2)+ sqrt(98)

sqrt(2) + sqrt( 2*49)

sqrt(2) + 7sqrt(2)

8 sqrt(2)

Answer:

[tex]\sqrt{2}[/tex]+ [tex]\sqrt{98}[/tex]

 [tex]\sqrt{2}[/tex]+   [tex]\sqrt{2}[/tex] *49

[tex]\sqrt{2}[/tex] + 7[tex]\sqrt{2}[/tex]

8 [tex]\sqrt{2}[/tex]

Bring all the X to the left side and all the numbers to the right side. ( remember to flip the signs )

3x - 4 - 5x = 6 + 4x + 2

3x - 5x - 4x = 6 + 2 + 4

-6x = 12

6x = -12

x = -2

Answer:

Step-by-step explanation:

So if 16 watches is 16000 rs, then if you want to make 3200 more rs, your total from 16 watches should be 19200 (which is 16000+3200)

so the rate per watch should be 19200/16 = 1200

So it should be 1200rs/watch is the rate

Answer:

So if 16 watches is 16000 rs, then if you want to make 3200 more rs, your total from 16 watches should be 19200 (which is 16000+3200)

so the rate per watch should be 19200/16 = 1200

So it should be 1200rs/watch is the rate

Step-by-step explanation:

The answer to the first one is A and the second one is D

(I took the test)

Answer:

Fist one:

A

Second one:

D

Step-by-step explanation:

Answer:

$2400

Step-by-step explanation:

60 tonnes = $1800

80 tonnes = $?

= 1800 × 80/60

= $2400

Step-by-step explanation:

$2400 to Carry 80tonnes of weight

Answer:

15 23

Step-by-step explanation:

Answer:

Step-by-step explanation:

11x - 6 + 15x - 8 = 90

26x - 14 = 90

26x = 104

x = 4

11(4) - 6 = 44 - 6 = 38

13y - 14 + 38= 180

13y + 24 = 180

13y = 156

y = 12

13(12) - 14 = 156 - 14=142

Answer:

The answer is:  

[tex]\frac{6r-5q}{r^2-q^2}[/tex]

which agrees with the last answer option (D) in the list.

Step-by-step explanation:

In order to add rational expressions, we need to express them with the same denominator. Therefore we examine what factors there are in the first denominator, which happens to be a difference of squares which is readily factored out as:

[tex]r^2-q^2=(r+q)\,(r-q)[/tex]

the second denominator consists of only one of these factors: [tex](r+q)[/tex], then in order to express both rational expressions with the same common denominator, we multiply numerator and denominator of the second fraction by the factor: [tex](r-q)[/tex]

Then we get two expressions that can be easily added as shown below:

[tex]\frac{r}{(r+q)\,(r-q)} +\frac{5\,(r-q)}{(r+q)\,(r-q)} =\frac{r+5(r-q)}{(r+q)(r-q)} =\frac{r+5r-5q}{(r+q)\,(r-q)} =\frac{6r-5q}{r^2-q^2}[/tex]

Answer:

2Pm+Pn+2qm-qn-2rm+rn

Step-by-step explanation:

Answer:

A. 15,10,20,18 -- 15,10,18,20 -- 10,15,18,20

Step-by-step explanation:

Bubble sorting can be defined as a technique or methodology whereby numbers that are not in their proper order are sorted into proper order that is from smallest to highest( increasing to decreasing order).

The method of bubble sorting involves the shuffling or swapping of adjacent numbers until the numbers are well sorted or arranged.

In the above question, we were given, a set of numbers:

15, 20, 10, 18

Step 1

20 is adjacent to 10

20 > 10

hence we swap

= 15,10,20,18

Step 2

From, 15,10, 20,18

20 is adjacent to 18

20 > 18

hence we swap

= 15,10,18,20

Step 3

From step 2, which gave us 15,10,18,20

15 us adjacent to 10

15 > 10

We swap

= 10,15,18,20

Hence,

15, 20, 10, 18 -- 15,10,20,18 -- 15,10,18,20 -- 10,15,18,20

Therefore, Option A is the correct option.

The correct intermediate steps of data 15, 20, 10, 18 set when it is being sorted with the bubble sort is; Choice A: 15,10,20,18 -- 15,10,18,20 -- 10,15,18,20.

Definition;

Bubble sort, otherwise termed the sinking sort, is a simple sorting algorithm that repeatedly steps through the list, compares adjacent elements and swaps them if they are in the wrong order.

With emphasis on the word adjacent, it is evident Choice A is the correct intermediate steps of the data set 15, 20, 10, 18 when it is being sorted with the bubble sort.

Read more:

https://brainly.com/question/15148294

La pendiente de una recta es la tangente del ángulo que forma la recta con la dirección positiva del eje de abscisas. En funciones no lineales, la razón de cambio varía a lo largo de la curva. La derivada de la función en un punto dado es la pendiente de la línea tangente en dicho punto.

F:V  7w7

Answer:

x = 95°

Step-by-step explanation:

The sum of the interior angles of any polygon is

sum = 180° (n - 2)

Here n = 5, thus

sum = 180° × 3 = 540°

Sum the given angles in the polygon and equate to 540

104° + 117° + 100° + 124° + x = 540°, that is

445° + x = 540° ( subtract 445° from both sides )

x = 95°

Answer:

y' = -4eˣ sin⁵(eˣ)

Step-by-step explanation:

Part 1 of the Fundamental Theorem of Calculus simply says that the definite integral of a function is equal to the antiderivative evaluated between the limits.

∫ₐᵇ f(x) dx = F(b) − F(a), where F(x) = ∫ f(x) dx.

y = ∫ₑₓ⁰ 4 sin⁵(t) dt

To integrate, use Pythagorean identity.

y = 4 ∫ₑₓ⁰ (1 − cos²(t))² sin(t) dt

Ignoring the limits for the moment, let's say u = cos(t) and du = -sin(t) dt.

y = 4 ∫ (1 − u²)² (-du)

y = -4 ∫ (1 − 2u² + u⁴) du

y = -4 (u − ⅔u³ + ⅕u⁵) + C

y = -4 (cos(t) − ⅔ cos³(t) + ⅕ cos⁵(t)) + C

Evaluate between t = eˣ and t = 0.

y = -4 (cos(0) − ⅔ cos³(0) + ⅕ cos⁵(0)) + C − [-4 (cos(eˣ) − ⅔ cos³(eˣ) + ⅕ cos⁵(eˣ)) + C]

y = -4 (1 − ⅔ + ⅕) + 4 (cos(eˣ) − ⅔ cos³(eˣ) + ⅕ cos⁵(eˣ))

Now take derivative with respect to x.

y' = 0 + 4 (-sin(eˣ) eˣ − 2 cos²(eˣ) (-sin(eˣ) eˣ) + cos⁴(eˣ) (-sin(eˣ) eˣ))

y' = -4eˣ sin(eˣ) (1 − 2 cos²(eˣ) + cos⁴(eˣ))

y' = -4eˣ sin(eˣ) (1 − cos²(eˣ))²

y' = -4eˣ sin⁵(eˣ)

This can be more easily calculated using the Second Fundamental Theorem of Calculus.

Los números reales están representados por números racionales e irracionales.

Un número racional es un número real que se puede formar dividiendo dos números enteros (un número entero es un número sin parte fraccionaria). La palabra viene de "ratio".

Un número irracional es un número real que NO se puede hacer dividiendo dos números enteros (un número entero no tiene parte fraccionaria). "Irracional" significa "sin relación", por lo que no es un número racional.

¡Espero eso ayude!

Answer:

2(6x+78)

Unless it's the exact number. You hadn't specified what x is.

Answer:

[tex]\huge\boxed{x=1,\ y=2\to(1,\ 2)}[/tex]

Step-by-step explanation:

[tex]\left\{\begin{array}{ccc}3x+4y=11\\x-2y=-3&\text{multiply both sides by (-3)}\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}3x+4y=11\\-3x+6y=9\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad\ \ \ \ 10y=20\qquad\text{divide both sides by 10}\\.\qquad\qquad\boxed{y=2}\\\\\text{subtitute it to the second equation:}\\x-2(2)=-3\\x-4=-3\qquad\text{add 4 to both sides}\\\boxed{x=1}[/tex]