Biology College

The poly A tail is NOT added to an mRNA during RNA processing . How would this affect the mRNA's journey to the ribosome?​

Answers

Answer 1
The mRNA molecule will not be able to bind to the ribosome.

Related Questions

Which chemical grouping does not include hormones? A) Steroids B) Proteins C) Amines D) Carbohydrates E) Peptides

Answers

Hormones fall into three primary chemical categories: protein/polypeptides, steroids, and those created from modified amino acids. They are not included in the chemical grouping of carbohydrates.

What classes of chemicals do hormones fall under?

On the basis of their chemical makeup, the hormones in the human body can be categorized into two main classes. Amino acid-derived hormones include amines, peptides, and proteins. Steroids are those produced from lipids.

Are steroids hormones?

Abstract. Steroid hormones are a class of hormones that are made from cholesterol and function in the body as chemical messengers. The growth and operation of the reproductive system are two of the many physiological processes that the steroid hormones control.

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the forearm in the figure(figure 1) accelerates a 2.7 kg ball at 6.4 m/s2 by means of the triceps muscle, as shown.

Answers

The calculated answer for the torque is  5.357 Nm and the force is 17.28 N for the forearm given in the figure.

We must determine the required torque and the force that the triceps muscle produces in order to answer the issue.

We are aware that the conservation of angular momentum is disrupted when a system receives a net torque, which causes angular acceleration.

Allow the arm to be massless here.

A symbol for the torque is as.

             τ=Iα

Where (I) is the moment of inertia.

α is the angular acceleration.

So,

 τ=mR^2 α

   τ=mRa

Here we have used the relationship between angular and tangential acceleration, which is: α=a/R.

The position vector is:  R = 0.31

The mass is m =2.7

The tangential acceleration is:   a =6.4 m/s2

So, the torque will be,

τ=2.7*0.31*6.4

 =5.3568

So, the required torque is 5.357 Nm.

And we know that torque is:  τ=F.R

So,   force is F =  τ/r

= 5.357/0.31

=17.28 N

The complete question is:

The forearm in the figure(figure 1) accelerates a 2.7 kg ball at 6.4 m/s2 by means of the triceps muscle, as shown. a) Calculate the torque needed. Ignore the mass of the arm. Answer in m*Nb) Calculate the force that must be exerted by the triceps muscle. Answer in N

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