Answer:The period of a pendulum, as measured by an observer moving at a relativistic velocity with respect to the pendulum, can be calculated using the concept of time dilation from special relativity.
The formula for time dilation in special relativity is given by:
Δt' = Δt / sqrt(1 - (v^2 / c^2))
where:
Δt' is the time interval measured by the moving observer
Δt is the time interval measured in the rest frame of the pendulum
v is the relative velocity between the pendulum and the moving observer
c is the speed of light in vacuum
In this case, the relative velocity between the pendulum and the moving observer is 0.95c, where c is the speed of light in vacuum (approximately 3 x 10^8 meters per second). Let's assume the period of the pendulum as measured in its rest frame is 3 seconds.
Plugging in the values into the formula:
Δt' = 3 / sqrt(1 - (0.95c)^2 / c^2)
Simplifying the expression:
Δt' = 3 / sqrt(1 - 0.95^2)
Using a calculator to evaluate the square root and simplify further, we get:
Δt' = 3 / sqrt(0.0975)
Δt' = 3 / 0.3125
Δt' ≈ 9.6 seconds
So, the period of the pendulum, as measured by an observer moving at a speed of 0.95c (95% of the speed of light) with respect to the pendulum, would be approximately 9.6 seconds. This demonstrates the concept of time dilation in special relativity, where the observed time interval changes due to relative motion at relativistic velocities.
Explanation:
A blue train of mass 50 kg moves at 4 m/s toward a green train of 30 kg initially at rest. The trains collide. After the collision the green train moves with a speed of 3 m/s. What is the final momentum of the green train?
A. 200 kgm/s
B. 90 kgm/s
C. 20 kgm/s
D. 110 kgm/s
A baseball player wants to hit a home run over the wall of a
stadium. The player swings the baseball bat so that it hits the
ball when it is at a height of 0.996 m above the ground. The
ball flies off at an angle of 30° above the horizontal and at a
speed of 36.2 m/s. What is the tallest wall that the player can
clear (i.e., get the ball over) if the wall is 99.1 m away
horizontally?
A wall less than or equal to 14.7 m in height is the highest the player can clear.
How to calculate height?Use the kinematic equations of motion to solve the problem. First, we can find the time it takes for the ball to travel 99.1 m horizontally:
d = vt
t = d / v
t = 99.1 m / 36.2 m/s
t ≈ 2.74 s
Now, use the vertical motion equation to find the maximum height the ball reaches:
y = yo + vot + (1/2)at²
where:
yo = 0.996 m (initial height)
vo = v sinθ = 36.2 m/s x sin(30°) ≈ 18.1 m/s (initial vertical velocity)
a = -9.81 m/s² (acceleration due to gravity, pointing downward)
t = 2.74 s (time of flight)
y = 0.996 m + 18.1 m/s x 2.74 s + (1/2) x (-9.81 m/s²) x (2.74 s)²
y ≈ 14.7 m
Therefore, the tallest wall the player can clear is a wall with a height less than or equal to 14.7 m.
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(c) At what angle of incidence will the light reflected from water (u= 1.3) be completely polarized?
Answer:
When unpolarized light is reflected off a non-metallic surface at a specific angle of incidence, the reflected light becomes polarized. This angle of incidence is known as Brewster's angle and can be calculated using the formula:
tan θp = n
where θp is Brewster's angle and n is the refractive index of the medium the light is passing into.
In this case, the light is passing from air (which has a refractive index of approximately 1) into water with a refractive index of 1.3. Therefore, we can plug in the values into the formula and solve for θp:
tan θp = 1.3
θp = tan^-1(1.3)
Using a calculator, we get θp = approximately 53.1 degrees.
Therefore, light reflected from water will be completely polarized at an angle of incidence of approximately 53.1 degrees.
The center of gravity of a 5.00 kg irregular object is shown in (Figure 1). You need to move the center of gravity 1.60 cm to the left by gluing on a 1.50 kg mass, which will then be considered as part of the object.
Where should the center of gravity of this additional mass be located?
The moment of the weight of the 1.50 kg mass about the CG of the 5.00 kg object will be considered as part of the object.
The center of gravity of the additional 1.50 kg mass should be located 1.60 cm to the right of the current CG of the 5.00 kg object.
What is the moment ?
We can use the principle of moments to determine the location of the center of gravity of the additional 1.50 kg mass that needs to be glued on.
The principle of moments states that the sum of the moments of all the forces acting on an object is equal to the moment of the resultant force about any point. In this case, we can take moments about the current center of gravity (CG) of the 5.00 kg object to determine the location of the center of gravity of the additional 1.50 kg mass.
The moment of a force about a point is given by the product of the magnitude of the force and the perpendicular distance from the point to the line of action of the force. Since the gravitational force acting on the masses is the only force acting on the system, we can take moments of the weight of each mass about the CG of the 5.00 kg object.
The moment of the weight of the 5.00 kg object about its CG is zero, since the CG is the point about which the object is in rotational equilibrium. Therefore, we only need to consider the moment of the weight of the 1.50 kg mass about the CG of the 5.00 kg object.
The distance between the CG of the 5.00 kg object and the desired new CG is 1.60 cm to the left, so we need to find the distance between the current CG and the new CG. Let x be the distance from the current CG to the new CG.
The moment of the weight of the 1.50 kg mass about the current CG is:
(1.50 kg)(9.81 m/s²)(x) = 14.72x Nm
The moment of the weight of the 1.50 kg mass about the new CG is:
(1.50 kg)(9.81 m/s²)(1.60 cm + x) = 14.72x + 23.54 Ncm
Setting these two moments equal, we have:
14.72x Nm = 14.72x + 23.54 Ncm
Converting the units, we get:
0.1472x m = 0.2354 m
x = 1.60 cm (to two significant figures)
Therefore, the center of gravity of the additional 1.50 kg mass should be located 1.60 cm to the right of the current CG of the 5.00 kg object.
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Which of the following can be formed by a convergent boundary?
A. Volcanic mountains B. All of these
C. Volcanic islands
D. Deep ocean trenches
Answer:
Volcanic mountains can be formed by a convergent boundary.
A 37-kg
child jumps to the ground from the top of a fence that is 1.6 m
high. You analyze the problem using upward as the positive x
direction
The change in the system kinetic energy during the jump is 576.32 J.
What is kinetic energy?Kinetic energy refers to the energy that an object in motion possesses due to its movement and is influenced by the object's velocity and mass.
Equation:The initial potential energy of the child-Earth system is given by mgh, where m = 37 kg is the mass of the child, g = 9.8 m/s^2 is the acceleration due to gravity, and h = 1.6 m is the height of the fence. Thus, the initial potential energy is (37 kg)(9.8 m/s^2)(1.6 m) = 576.32 J.
At the bottom of the fence, all of the initial potential energy is converted into kinetic energy. Since the child is at rest initially, the initial kinetic energy is zero. Using the law of conservation of energy, the final kinetic energy can be calculated as equal to the initial potential energy, or 576.32 J.
The change in kinetic energy during the jump is therefore:
Final kinetic energy - Initial kinetic energy = 576.32 J - 0 J = 576.32 J.
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The complete question should be:
A 37-kg child jumps to the ground from the top of a fence that is 1.6 m high. You analyze the problem using upward as the positive x direction. Taking x = 0 to be at the bottom of the fence, what are the initial potential energy of the child-Earth system and the change in the system kinetic energy during the jump? Enter your answers numerically separated by a comma.
A hydraulic system contains one small piston that has a diameter of 1 (one) inch, and a large piston that has an area of 12.56 in. What is the system pressure if the large piston produces a force of 37,775 pounds?
The pressure of the system, that the large piston produces a force of 37775 pounds is 3007.56 pound / in²
How do i determine the pressure of the system?The following data were obtained from the question:
Area of large piston = 12.56 in² Force of large piston = 37775 poundsPressure of system =?Pressure is defined as force per unit area as shown by the following formula
Pressure = Force / Area
Inputting the value of the force and area, we have
Pressure of system = 37775 / 12.56
Pressure of system = 3007.56 pound / in²
Thus, from the calculation made above, we can conclude that the pressure of the system is 3007.56 pound / in²
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By how much do you stretch your 0.600-cm diameter nylon rope when you hang 23.0m
below a rock outcropping. Assume your mass is 75.0 kg and your nylon rope has Young’s modulus of 5.00 × 10^9 N/m^2.
Answer:
To solve for the amount of stretch in the nylon rope, we can use the equation for the elongation (stretch) of a rope under tension:
ΔL = FL / AE
where ΔL is the change in length of the rope, F is the force on the rope, L is the original length of the rope, A is the cross-sectional area of the rope, and E is the Young's modulus of the rope.
First, we need to find the force on the rope. This is equal to the weight of you and the rope:
F = mg = (75.0 kg + mass of rope)g
Next, we need to find the cross-sectional area of the rope. The diameter of the rope is given as 0.600 cm, so the radius is 0.300 cm = 0.00300 m. Therefore, the cross-sectional area is:
A = πr^2 = 2.83 × 10^-6 m^2
Now we can plug in the given values and solve for ΔL:
ΔL = FL / AE = [(75.0 kg + mass of rope)g](23.0 m) / [(2.83 × 10^-6 m^2)(5.00 × 10^9 N/m^2)]
We can simplify this expression by using the fact that the mass of the rope is much smaller than your mass, so we can assume that the force on the rope is equal to your weight:
ΔL = (mg)(23.0 m) / (A E) = (75.0 kg)(9.81 m/s^2)(23.0 m) / [(2.83 × 10^-6 m^2)(5.00 × 10^9 N/m^2)]
Solving for ΔL, we get:
ΔL = 0.068 cm
Therefore, the nylon rope stretches by approximately 0.068 cm when you hang 23.0 m below a rock outcropping.
What is Ceres?
The largest asteroid identified to date.
The asteroid closest in orbit to the Earth.
The comet that passes near Earth most often.
The meteor that probably killed the dinosaurs.
The Ceres is (a).The largest asteroid identified to date is correct option.
With a diameter of around 590 miles (940 km), Ceres is the biggest asteroid between Mars and Jupiter. It is regarded as a minor planet, like Pluto, and was found in 1801 by Giuseppe Piazzi. Ceres is made of rock and ice, and due to its low density, it is likely that it contains a substantial amount of water ice inside.
The NASA Dawn spacecraft visited Ceres in 2015 and orbited the dwarf planet for more than three years, gathering useful information and taking stunning pictures of it.
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What is the period, in seconds, of this mass?
The period (in second) of the 0.95 Kg mass, given that it has an amplitude of 0.21 m and an angular velocity of 9.5 rad/s is 0.66 second
How do i determine the period of the mass?From the question given above, the following data were obtained:
Mass (m) = 0.95 KgAmplitude (A) = 0.21 mAngular frequency (ω) = 9.5 rad/sPi (π) = 3.14Period (T) =?The period of the mass can be obtained as shown below:
ω = 2π/ T
9.5 = (2 × 3.14) / T
9.5 = 6.28 / T
Cross multiply
9.5 × T = 6.28
Divide both sides by 9.5
T = 6.28 / 9.5
T = 0.66 second
Thus, from the above calculation, we can conclude that the period of the mass is 0.66 second
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A soft drink (mostly water) flows in a pipe at a beverage plant with a mass flow rate that would fill 220 0.355-L cans per minute. At point 2 in the pipe, the gauge pressure is 152 kPa and the cross-sectional area is 8.00 cm2. At point 1, 1.35 m above point 2, the cross-sectional area is 2.00 cm2.
Find the gauge pressure at point 1.
Express your answer in kilopascals
The gauge pressure at point 1 = 145.2 kPa.
What is Bernoulli's equation?The equation states that the sum of the pressure, kinetic energy, and potential energy per unit volume of a fluid is constant along a streamline, in the absence of external forces like friction or viscosity.
The principle of continuity of mass flow rate and Bernoulli's equation, which connects pressure, velocity, and height of a fluid in a flow, can be used to solve this issue.
With the provided data, we can first determine the soft drink's mass flow rate:
mass flow rate =[tex](220 cans/min) x (0.355 L/can) x (1 kg/L) x (1 min/60 s)[/tex] = [tex]1.235 kg/s[/tex]
Then, we may compare the soft drink's velocities at positions 1 and 2 using the principle of continuity:
[tex]A1 v1 = A2 v2[/tex]
where A1 and A2 are the pipe's cross-sectional areas at points 1 and 2, respectively, and v1 and v2 are the soft drink's velocities at those same locations. When we solve for v1, we get:
[tex]v1 = (A2/A1) v2 = (8.00 cm^2)/(2.00 cm^2) v2 = 4 v2[/tex]
Now, we can link the pressures, velocities, and heights of the soft drink at points 1 and 2 using the Bernoulli's equation:
P1 + (1/2)ρv1²+ ρgh1 = P2 + (1/2)ρv2²+ ρgh2
where P1 and P2 are the gauge pressures at points 1 and 2, respectively; ρ is the soft drink's density; g is gravity's acceleration; and h1 and h2 are the heights of the respective points 1 and 2 above a reference level.
As the soft drink contains primarily water, we may calculate its density using the formula: = 1000 kg/m3. Moreover, we can decide to set the reference level at point 2, making h2 = 0.When the supplied values and the velocity relation are substituted, we obtain:
[tex]P1 + (1/2)(1000 kg/m^3)(16 v2^2) + (1000 kg/m^3)(9.81 m/s^2)(1.35 m)[/tex] =[tex]152 kPa + (1/2)(1000 kg/m^3)(v2^2)[/tex]
By condensing and figuring out P1, we get at:
[tex]P1 = 152 kPa + (1/2)(1000 kg/m^3)(15 v2^2) - (1000 kg/m^3)(9.81 m/s^2)(1.35 m)[/tex] = [tex]152 kPa + 6.75 v2^2 - 13.33 kPa[/tex]
We must now locate v2. We can link the velocity and the cross-sectional area at point 2 using the mass flow rate relation and the density of the soft drink:
[tex]A2 v2[/tex] = (mass flow rate)/ρ =[tex]1.235/(1000 kg/m^3)[/tex]= [tex]0.001235 m^3/s[/tex]
Upon solving for v2, we obtain:
v2 =[tex]0.001235 m^3/s / (8.00 cm^2 / 10000 cm^2)[/tex]= [tex]0.1544 m/s[/tex]
Last but not least, we can insert this value into the P1 expression to obtain:
[tex]P1[/tex] =[tex]152 kPa + 6.75 (0.1544 m/s)^2 - 13.33 kPa[/tex] = [tex]145.2 kPa[/tex]
As a result, point 1's gauge pressure is 145.2 kPa.
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A person fires a gun close to a wall (40m). An echo is heard 0.24 after the original shot. Based on this information only, find the speed of sound in air?
The speed of sound in air can be calculated using the following formula:speed of sound = distance / timeIn this case, we know that the distance between the person and the wall is 40 meters, and the time it takes for the echo to be heard after the original shot is 0.24 seconds. However, we need to account for the fact that sound travels to the wall and back, so the total distance the sound wave covers is twice the distance to the wall, or 2 x 40 = 80 meters.Thus, using the formula above, we can calculate the speed of sound:speed of sound = distance / time = 80 m / 0.24 s ≈ 333.33 m/sTherefore, the speed of sound in air is approximately 333.33 meters per second.
If enough experimental data supports a hypothesis, then it:
A. Is accepted as true until proven false.
B. Becomes an Observational Law
C. Is proven 100% true.
D. Is falsified.
If enough experimental data supports a hypothesis, it is considered a well-supported scientific theory, but it is not considered to be 100% true or proven. Scientific theories are always open to further investigation and revision based on new evidence. Therefore, option C ("Is proven 100% true") is incorrect.
Option A ("Is accepted as true until proven false") is also incorrect because scientists do not accept a hypothesis as true until it has been rigorously tested and supported by a large body of evidence. Even then, scientists recognize that any scientific theory is subject to revision or falsification if new data or evidence emerges that contradicts it.
Option B ("Becomes an Observational Law") is also incorrect because scientific laws are typically descriptive, rather than explanatory. They describe what happens in a given set of circumstances, but they do not explain why it happens. Hypotheses and theories, on the other hand, attempt to explain why certain phenomena occur, and they are supported by experimental evidence.
Therefore, none of the options are completely accurate, but the most appropriate answer is that the hypothesis becomes a well-supported scientific theory.
What amount of force is required to accelerate a 20 gram toy car at 5 m/s²?
O 150 N
O 100 N
O 50 N
Ο ΟΝ
Answer:
100
Explanation:
F = m * a
Given that the mass (m) of the toy car is 20 grams (or 0.02 kilograms, since 1 kilogram = 1000 grams) and the acceleration (a) is 5 m/s^2, we can plug these values into the formula to calculate the force (F):
F = 0.02 kg * 5 m/s^2 = 0.1 N
So, the amount of force required to accelerate the 20 gram toy car at 5 m/s^2 is 0.1 N, which is equivalent to 100 N when rounded to the nearest whole number. Therefore, the correct answer is 100 N.
Sources of error could have come from friction that may result in energy losses during the collision, The gliders may not be perfectly elastic, which means that some energy may be lost during the collision
are these errors random or systematic errors?
Sources of error could have come from small amounts of friction, and glider 2 could have not been totally at rest. These errors are systematic errors.
Are these errors random or systematic?
Answer:
The first set of errors, which include friction and imperfect elasticity, are systematic errors because they arise from consistent factors that affect the measurements in a predictable way. These errors will be present in every trial of the experiment and will cause a consistent deviation from the true value.
The second set of errors, which include small amounts of friction and the initial velocity of glider 2, are also systematic errors because they arise from consistent factors that affect the measurements in a predictable way. These errors will also be present in every trial of the experiment and will cause a consistent deviation from the true value.
Explanation:
A flat uniform circular disk (radius = 5.44 m, mass = 150 kg) is initially stationary. The disk is free to rotate in the horizontal plane about a frictionless axis perpendicular to the center of the disk. A 47.0-kg person, standing 1.54 m from the axis, begins to run on the disk in a circular path and has a tangential speed of 2.80 m/s relative to the ground. Find the resulting angular speed (in rad/s) of the disk.
The resulting angular speed of the flat, uniform circular disk is 0.237 rad/s.
What is angular momentum?Angular momentum is a fundamental concept in physics that describes the rotational motion of an object around an axis. It is defined as the product of the moment of inertia of an object and its angular velocity with respect to a chosen axis.
We can use conservation of angular momentum to solve this problem. The initial angular momentum of the disk is zero because it is stationary. The final angular momentum of the system (disk + person) is:
L = Iω
where I is the moment of inertia of the disk and person about the axis of rotation, and ω is the resulting angular speed of the disk.
The moment of inertia of the disk about its axis is:
I_disk = (1/2)mr²
where the disk's radius is r and its mass is m. Substituting the given values, we get:
I_disk = (1/2)(150 kg)(5.44 m)² = 2226.24 kg·m²
The moment of inertia of the person about the axis can be approximated as:
I_person = mr²
where r is the distance from the axis to the person. Substituting the given values, we get:
I_person = (47.0 kg)(1.54 m)² = 109.64 kg·m²
The total moment of inertia of the system is:
I = I_disk + I_person = 2226.24 kg·m² + 109.64 kg·m² = 2335.88 kg·m²
The final angular momentum of the system is:
L = Iω
where ω is the resulting angular speed of the disk. Substituting the given values, we get:
(2335.88 kg·m²)ω = (197.64 kg·m²/s)(2.80 m/s)
Solving for ω, we get:
ω = (197.64 kg·m²/s)(2.80 m/s) / (2335.88 kg·m²) = 0.237 rad/s.
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During the earliest stages of the universe, the only things that existed were
During the earliest stages of the universe, the only things that existed were subatomic particles such as protons, neutrons, and electrons. These particles came together to form the first atoms, which were primarily hydrogen and helium.
The universe was also filled with a hot, dense plasma of particles and radiation, known as the cosmic microwave background radiation.
Hence, as the universe expanded and cooled, these atoms and radiation would play a key role in the formation of galaxies, stars, and the larger structures we see today.
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If a→=4i^+7j^-5k^ and b→=3i^+4j^+k^, find the direction cosines of a→-b→.
The direction cosines of a→ - b→ are:
l_x = 1 / √46
l_y = 3 / √46
l_z = -6 / √46
What are the directions?The direction cosines of a vector can be found by dividing the components of the vector by its magnitude.
Here's how you can find the direction cosines of the vector a→ - b→:
Step 1: Subtract the vectors a→ and b→ to get a new vector, let's call it c→:
c→ = a→ - b→
In this case, a→ = 4i^ + 7j^ - 5k^ and b→ = 3i^ + 4j^ + k^, so we can subtract them component-wise:
c_x = 4 - 3 = 1
c_y = 7 - 4 = 3
c_z = -5 - 1 = -6
So, c→ = 1i^ + 3j^ - 6k^.
Step 2: Find the magnitude of vector c→ using the formula:
|c→| = √(c_x^2 + c_y^2 + c_z^2)
Substituting the values we found earlier:
|c→| = √(1^2 + 3^2 + (-6)^2)
|c→| = √(1 + 9 + 36)
|c→| = √46
Step 3: Divide the components of vector c→ by its magnitude to find the direction cosines:
l_x = c_x / |c→|
l_y = c_y / |c→|
l_z = c_z / |c→|
Substituting the values we found earlier:
l_x = 1 / √46
l_y = 3 / √46
l_z = -6 / √46
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the direction cosines of the vector a→ - b→ are (0.155, 0.466, -0.932).
How do we calculate?we first calculate the vector a→ - b→:
a→ - b→ = (4i^ + 7j^ - 5k^) - (3i^ + 4j^ + k^)
= (4-3)i^ + (7-4)j^ + (-5-1)k^
= i^ + 3j^ - 6k^
Next, we find the magnitude of the vector a→ - b→:
|a→ - b→| = √(1^2 + 3^2 + (-6)^2) = √46
We then find the direction cosines of the vector a→ - b→:
cos α = (1/√46) = 0.155
cos β = (3/√46) = 0.466
cos γ = (-6/√46) = -0.932
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A hydraulic system has two pistons. Input force on one piston is 15.8 lb and the other piston can lift a weight of 93 lb. What is the mechanical advantage?
Answer:
The mechanical advantage of a hydraulic system is given by the ratio of the output force to the input force. In this case, the input force is 15.8 lb and the output force is 93 lb.
So, the mechanical advantage of the hydraulic system is:
MA = Output force / Input force
MA = 93 lb / 15.8 lb
MA = 5.89
Therefore, the mechanical advantage of the hydraulic system is 5.89. This means that the system can lift a weight that is almost 6 times greater than the input force applied to the other piston.
Determine the resultant x and y components, when one vector is equal to 26.5 and the other 44 with angles of 56 and 28 degrees
The resultant x and y components are 53.23 and 41.51, respectively.
What are the components?
To determine the resultant x and y components of the vectors, we can use the following equations:
Rx = ΣFx = F1x + F2x + ...
Ry = ΣFy = F1y + F2y + ...
where F1x, F2x, ... are the x components of the vectors, F1y, F2y, ... are the y components of the vectors, and ΣFx and ΣFy are the total x and y components of the resultant vector, R.
First, we need to find the x and y components of each vector:
Vector 1: magnitude = 26.5, angle = 56°
F1x = 26.5cos(56) = 14.28
F1y = 26.5sin(56) = 21.44
Vector 2: magnitude = 44, angle = 28°
F2x = 44cos(28) = 38.95
F2y = 44sin(28) = 20.07
Now we can add the x and y components of the vectors to find the total x and y components of the resultant vector:
ΣFx = F1x + F2x = 14.28 + 38.95 = 53.23
ΣFy = F1y + F2y = 21.44 + 20.07 = 41.51
Therefore, the resultant x and y components are 53.23 and 41.51, respectively.
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Suppose the metal sample in Figure 10.2 is immersed in water, is cubical with side 3.0 cm, and has a mass of 54 g.
The force of buoyancy acting on the sample is 2.65 N.
If the sample's supporting string is cut, it will float to the surface of the water.
How to calculate bouyant force?a. The buoyant force acting on the sample can be calculated using the formula Fb = ρVg, where ρ is the density of water, V is the volume of the submerged part of the sample, and g is the acceleration due to gravity. Since the sample is immersed in water, its volume is equal to the volume of water it displaces, which can be calculated using the formula V = l × w × h, where l, w, and h are the dimensions of the submerged part of the sample. Since the sample is cubical, all sides have the same length of 3.0 cm. Thus, the submerged part of the sample has a volume of V = 3.0 cm × 3.0 cm × 3.0 cm = 27.0 cm³ = 0.027 m³. The density of water is ρ = 1000 kg/m³, and the acceleration due to gravity is g = 9.81 m/s². Therefore, the buoyant force acting on the sample is:
Fb = ρVg = 1000 kg/m³ × 0.027 m³ × 9.81 m/s² ≈ 2.65 N
b. The sample will float to the surface of the water if its supporting string is cut. This is because the buoyant force acting on the sample is greater than its weight, which means that there is a net upward force on the sample. This net force causes the sample to accelerate upward, and it will continue to accelerate until it reaches the surface of the water. At the surface, the upward force is balanced by the weight of the sample, and it will float on the water.
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Complete question:
2. Suppose the metal sample in Figure 10.2 is immersed in water, is cubical with side 3.0 cm, and has a mass of 54 g. a. Calculate the buoyant force acting on the sample. b. Describe the behavior of the sample if its supporting string is cut. Explain how you arrive at your answer. balance arm water metal sample water overflow can beaker Figure 10.2 MEASUREMENTS
of the following stars, which one has a mass less than that of our sun? The choices are Sirius B, Altair, Arcturus, Spica, and Rigel.
Answer:
Sirius BExplanation:
Here we go !!!!
Sirius B: A white dwarf star and companion to Sirius A, the brightest star in the sky. It has a mass of only about 0.98 times that of the sun, making it less massive than our sun.Arcturus: A red giant star located in the constellation Boötes, with a mass of about 1.1 times that of the sun.Spica: A binary star system composed of two hot, blue stars located in the constellation Virgo. The primary star has a mass of about 11 times that of the sun.Rigel: A blue supergiant star located in the constellation Orion, with a mass of about 17 times that of the sun. It is one of the brightest stars in the sky and is a part of Orion's Belt.Altair: A main-sequence star of spectral type A7V, located in the constellation Aquila. It has a mass of about 1.8 times that of the sun, which means it is more massive than the sun.I hope this information helps!
A piece of wood of density 400kg/m³ lump of aluminium is tied to a lump of aluminium of mass 0.01kg and density of 270kg/m³ . the arrangement has a mean density of 100kg/m³and just float in water. Determine the just float in volume of the piece of wood
The just float in volume of the piece of wood is 0.008 cubic meters.
Just float calculationLet's denote the volume of the piece of wood as V_wood, and the volume of the lump of aluminum as V_aluminum.
We can start by using the information given to write two equations:
Equation 1: (density of wood) * V_wood + (density of aluminum) * V_aluminum = (mean density) * (V_wood + V_aluminum)
Substituting the given values, we get:
400 * V_wood + 270 * V_aluminum = 100 * (V_wood + V_aluminum)
Simplifying and rearranging, we get:
300 * V_wood = 70 * V_aluminum
Equation 2: The total mass of the arrangement is the sum of the masses of the wood and aluminum:
(density of wood) * V_wood + (density of aluminum) * V_aluminum = (total mass)
Substituting the given values, we get:
400 * V_wood + 270 * V_aluminum = 0.01
Now we can use Equation 1 to eliminate V_aluminum from Equation 2:
300 * V_wood = 70 * V_aluminum
V_aluminum = (300/70) * V_wood
Substituting this into Equation 2, we get:
400 * V_wood + 270 * [(300/70) * V_wood] = 0.01
Simplifying and solving for V_wood, we get:
V_wood = 0.008 m^3
Therefore, the just float in volume of the piece of wood is 0.008 cubic meters.
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What voltage will send a current of 5 amperes through a bell circuit if the resistance of the circuit is 4 ohms?
Answer:
Therefore, the voltage required is 20 volts
Explanation:
To find the voltage that will send a current of 5 amperes through a bell circuit with a resistance of 4 ohms, we can plug in the values into the equation and solve for V: V=IR
V=(5A)(4Ω)
V=20V
On Earth the gravitational field strength is 10N/kg. What would be the weight of someone on Earth who had a mass of 75kg?
750N/kg
750N
75N
7500kg
The weight of someone on Earth with a mass of 75kg is 750N.
option B.
What would be the weight of someone on Earth?The weight of someone on Earth is calculated using Newton's second law of motion.
W = mg
where;
m is the massg is acceleration due to gravityFor the mass is 75kg and the gravitational field strength on Earth is 10N/kg.
W = 75 kg x 10 N/kg
W = 750 N
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pls help in astronomy didn’t know what subject to put it under
The subject depicted in the attached image is Astronomy and Astrophysics.
Definitely younger than the SunAO main sequence starB-type starsF-type stars (some)Possibly younger than the SunF1 main sequence starG2 main sequence starMO main sequence starDefinitely older than the SunM-type stars (some)M1, 1 Msun red giantM1, 18 Msun red supergiantWhat is Astronomy?Astronomy is the scientific study of celestial objects such as stars, planets, galaxies, and other phenomena that exist outside of Earth's atmosphere.
Astronomers use a variety of methods to observe and study these objects, including telescopes, spacecraft, and computer simulations.
Astronomy is a broad field that includes many different sub-disciplines, such as astrophysics, planetary science, and cosmology.
Astronomers study the physical properties and behavior of celestial objects, such as their composition, temperature, motion, and evolution.
They also seek to understand the structure and history of the universe as a whole.
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Two batteries supply current to the circuit in the figure. The figure shows the potential difference across two of the resistors and the value of the third resistor.(Figure 1). What current is supplied by the batteries?
The current that is supplied by the batteries is 0.01333 Amp.
How to explain the informationAn electric current is a stream of charged particles, such as electrons or ions, moving through an electrical conductor. It is measured as the net rate of flow of electric charge through a surface or into a control volume.
Eeq = E1 + E2 ( batteries in series )
=> Eeq = 3+4.5 = 7.5 V
Veq = V1 + V2 + V3 ( resistances in series )
=> V3 = 7.5 - 2 - 3.5 = 2 V
=> current = V/R = 2/150 = 0.01333 Amp
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Determine the percentage of kinetic energy lost by a small ball when it makes an elastic head-on collision with stationary bigger ball. The mass of the bigger ball is 12 times bigger than the mass of the small ball.
The small ball loses 2.37% of its kinetic energy during the elastic head-on collision with the stationary bigger ball.
[tex]\frac{Kf}{Ki} =[/tex] [tex]1- [\frac{1}{2}][ \frac{M}{m}] [\frac{2mv^{2} }{[M+m]^{2} }[/tex]
M = 12m
Kf/Ki = 1 - (1/2)(12m/m)[(2mv^2)/(13m)^2]
Kf/Ki = 165/169
(1 - Kf/Ki) x 100% = (1 - 165/169) x 100% = 2.37%
So, the small ball loses 2.37% of its kinetic energy during the elastic head-on collision with the stationary bigger ball.
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Explain why sound wave travel faster in liquids than in gases
Answer:
Sound travels faster in liquids than in gases because molecules are more tightly packed. In fresh water, sound waves travel at 1,482 meters per second (about 3,315 mph). That's well over 4 times faster than in air!
Explanation:
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Find the ratio of the coulomb electric force Fe to the gravitational force Fg between two electrons in vacuum.