The packing gland serves many functions in a centrifugal pump. Among these, it Keeps gritty material from entering the?
a. Acts as a coolant to keep the pump bearing from overheating
b. Keeps gritty material from entering the packing box
c. Keeps the pump primed
d. Prevents cavitation

Answers

Answer 1

option (b). The packing gland serves many functions in a centrifugal pump. Among these, it keeps gritty material from entering the packing box. The packing gland is an important component of a centrifugal pump that helps to maintain the pump's efficiency and prevent damage to its internal parts.

One of its primary functions is to seal the area where the pump shaft exits the casing, which is known as the packing box. This is important because the pump shaft rotates at high speeds and generates significant friction, which can cause wear and tear on the packing box if it is not properly sealed.

One of the main challenges of operating a centrifugal pump is that it can become clogged with gritty or abrasive materials that can cause damage to the pump's internal components. The packing gland helps to prevent this by creating a tight seal around the pump shaft that keeps these materials from entering the packing box. This not only helps to prevent damage to the pump but also ensures that the pump operates more efficiently and has a longer service life.

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Related Questions

Conductors in Parallel(310-10(H)(1)(Table 250-122): What are the conductors required for a 250 ampere feeder paralleled in two raceways?

Answers

The also recommended to consult a licensed electrician and comply with any local codes and regulations that may apply to the specific installation.

Why will be the conductors required for a 250 ampere feeder paralleled?

To determine the conductors required for a 250 ampere feeder that is paralleled in two raceways, we need to consult the [tex]NEC[/tex] (National Electrical Code) Table 310.16, which provides ampacity values for various types and sizes of conductors.

Assuming the raceways are located in the same area and under the same conditions, we can parallel the conductors in accordance with the [tex]NEC 310.10(H)(1)[/tex] requirements.

This means that each parallel conductor must have the same length, be the same size, and be made of the same material.

Based on [tex]NEC[/tex] Table 250.122, we can use two parallel sets of 4/0 AWG conductors, which have an ampacity of 230 amps each.

Therefore, two sets of 4/0 AWG conductors in parallel would provide a total ampacity of 460 amps, which is well above the required 250 ampere feeder size.

It is important to note that this answer assumes that the installation complies with all other applicable [tex]NEC[/tex] requirements, such as those related to raceway fill, grounding, and overcurrent protection.

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To find the correction factor for situation where four or more current carrying conductors are bundled together, consult Table _____.

Answers

To find the correction factor for a situation where four or more current carrying conductors are bundled together, consult Table 310.15(B)(3)(a) in the National Electrical Code (NEC).

This table provides adjustment factors for ambient temperature, conductor size, and number of conductors in a raceway or cable. The correction factor is used to adjust the ampacity of the conductors to account for the increased heat generated by the bundled conductors.


 To find the correction factor for a situation where four or more current-carrying conductors are bundled together, consult Table 310.15(B)(3)(a).

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Question 3 Marks: 1 In practice, exposure to all ionizing radiation is controlled by the use of shields of lead.Choose one answer. a. True b. False

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True, exposure to all ionizing radiation is controlled by the use of shields of lead.

Ionizing radiation is a form of energy that acts by removing electrons from atoms and molecules of materials that include air, water, and living tissue. Ionizing radiation can travel unseen and pass through these materials. Ionizing radiation, including nuclear radiation, consists of subatomic particles or electromagnetic waves that have sufficient energy to ionize atoms or molecules by detaching electrons from them.

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Complete the following statement: The magnetic field around a current-carrying, circular loop ismost like that of(a) the earth.(b) a short bar magnet.(c) a current-carrying, rectangular loop.(d) a long straight wire that carries a current.(e) two long straight wires that carry currents in opposite directions.

Answers

The correct answer is (b) a short bar magnet because the circular loop of current creates a magnetic field that looks similar to the field created by a bar magnet.

The magnetic field around a current-carrying, circular loop is similar to that of a bar magnet because the circular loop acts as a magnetic dipole, with a north and south pole, just like a bar magnet. The magnetic field lines around the circular loop are also circular, just like the field lines around a bar magnet.

    The other options, such as a current-carrying, rectangular loop or long straight wire, do not produce a magnetic field that is similar to a bar magnet. Additionally, the strength of the magnetic field is greatest at the center of the circular loop and decreases with distance. This is similar to the field of a bar magnet, where the field is strongest at the poles and diminishes with distance.

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heteroskedastic modelling focuses on modelling the unconditional variance of a time series. (True or False)

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The statement "heteroskedastic modeling focuses on modeling the unconditional variance of a time series" is true. Heteroskedasticity refers to the situation where the variance of a variable is not constant over time but instead varies with some underlying factor or condition.

When modeling a time series, it is important to account for heteroskedasticity because failing to do so can lead to biased and inefficient estimates of model parameters.

Heteroskedastic modeling involves modeling the variance of a time series as a function of some explanatory variables. This can be done using a variety of statistical techniques, such as generalized autoregressive conditional heteroskedasticity (GARCH) models.

By incorporating information about the factors that drive the variation in the variance of a time series, heteroskedastic modeling can improve the accuracy and reliability of predictions and forecasts.

Overall, understanding and accounting for heteroskedasticity is an important consideration when modeling time series data, and can lead to more robust and accurate analyses.

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True. Heteroskedastic modelling involves modeling the variance of a time series that is not constant over time, and this modeling is typically done in an unconditional manner, meaning that it is not conditioned on any specific values of the time series or other variables.
True, heteroskedastic modeling focuses on modeling the unconditional variance of a time series.

The statement "Heteroskedastic modelling focuses on modelling the unconditional variance of a time series" is generally true.

Heteroscedasticity refers to the unequal variance of a variable across different levels of another variable. In time series analysis, it means that the variance of the series changes over time. Heteroskedastic modeling is a method used to address the issue of varying variances in time series data.

The goal of heteroskedastic modeling is to estimate the unconditional variance of a time series, which means the variance is not conditioned on any other variables. The model can then be used to identify patterns in the variance over time and to make predictions about future variances.

Therefore, the statement is generally true, although it should be noted that the specific focus of heteroskedastic modeling may depend on the specific approach or methodology being used.

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2. A 100Ω, 300Ω, and 200Ω resistor are all connected in parallel. What is the resistance?

Answers

When resistors are connected in parallel, the total resistance is calculated as:

1/R(total) = 1/R(1) + 1/R(2) + 1/R(3) + ...

So for this question, we can plug in the values:

1/R(total) = 1/100 + 1/300 + 1/200

1/R(total) = 0.01 + 0.003333 + 0.005

1/R(total) = 0.019333

R(total) = 1/0.019333

R(total) = 51.67Ω

The electrical resistance of an object is a measure of its opposition to the flow of electric current. Its reciprocal quantity is electrical conductance, measuring the ease with which an electric current passes. Electrical resistance shares some conceptual parallels with mechanical friction. The SI unit of electrical resistance is the ohm (Ω), while electrical conductance is measured in siemens (S) (formerly called the 'mho' and then represented by ℧).

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What information must be on a warming tag attached to a locked-out switch?
a. Directions for removing the tag
b. Name of the nearest physician to call in case of an emergency
c. Signature of the person who locked out the switch and who will remove it
d. Time to unlock the switch

Answers

A warning tag attached to a locked-out switch should contain the following information: c. Signature of the person who locked out the switch and who will remove it. This ensures proper identification and responsibility for the lockout process, promoting safety and accountability in the workplace.

A warming tag is a type of tag that is attached to a locked-out switch. According to the Occupational Safety and Health Administration (OSHA), a warming tag attached to a locked-out switch should contain the signature of the person who locked out the switch and who will remove it.

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(315-15(B)(3a) The ampacity of six current-carrying No. 4/0 XHHW aluminum conductors installed in a ground floor slab (wet location) is _____.

Answers

Option 4. The ampacity of six current-carrying No. 4/0 XHHW aluminum conductors installed in a ground floor slab (wet location) is 210 A.

The temperature rectification consider for guide ampacity this not set in stone by deducting the reference temperature of 30°C from the surrounding temperature of 38.9°C, bringing about a temperature revision element of 1.08.

Expecting a circuit voltage of 480V, the ampacity of six current-conveying 4/0 XHHW aluminum guides in a wet area can be determined involving the NEC rules for channel fill and guide ampacity. With a guide protection temperature rating of 90°C, the ampacity rating of every guide is 205A. Taking into account the change factor for six current-conveying guides, which is 0.8, the last ampacity of the six guides is determined as follows:

(205A x 6 guides x 0.8 change factor) x 1.08 temperature rectification factor = 839A

In this manner, the straightforward reply to the inquiry is 4. 210 A (gathered together to the closest entire number), which addresses the ampacity of six current-conveying 4/0 XHHW aluminum guides introduced in a ground floor chunk (wet area) with a normal encompassing temperature of 102°F and a base protection temperature rating of 90°C.

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The complete question is:

Temperature is expected to be 102°F The temperature correct-A 2 TW conductor is installed in a location where the ambient ion factor for conductor ampacity in this location is the ambient temperature is 71°C, the minimum insulation 69 Ambient. The ampacity of six current-carrying 4/0 XHHW aluminum conductors installed in a ground floor slab (wet location) is 1. 135 A 2. 144 A 3. 185 A  4. 210 A

Question 7 Marks: 1 The frequency of a sound determines its pitch.Choose one answer. a. True b. False

Answers

The correct answer is a. True.



Frequency refers to the number of vibrations per second of a sound wave. The higher the frequency, the higher the pitch of the sound. Therefore, the frequency of a sound wave directly determines its pitch. A sound with a higher frequency will have a higher pitch, and a sound with a lower frequency will have a lower pitch.

The frequency of a sound determines its pitch.  Pitch is the perception of how high or low a sound is to the human ear. A higher frequency results in a higher pitch, while a lower frequency corresponds to a lower pitch.

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(240) One of the purposes of conductor overcurrent protection is to protect the conductors against excessive or dangerous heat.(True/False)

Answers

Conductor overcurrent protection is an essential safety measure in electrical systems to prevent overheating and potential fire hazards caused by excessive current flow. Therefore, it is true.

Here are some additional points about conductor overcurrent protection:

The primary purpose of overcurrent protection is to prevent damage to the conductors and other electrical components by interrupting the flow of current when it exceeds safe levels.Overcurrent protection devices such as fuses and circuit breakers are rated to trip at specific current levels and are chosen based on the size and capacity of the conductors they are protecting.Overcurrent protection devices should be properly coordinated to ensure that the device closest to the fault opens first, minimizing the amount of time that the faulted circuit is without power.

This type of protection is achieved by the use of fuses or circuit breakers, which are designed to interrupt the flow of current when it exceeds a certain limit.

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In a 1953 experiment a rocket sled went from 284 m/s to rest within 178 m. If the test subject,

John Stapp, had a mass of 84. 0 kg: a) what is the amount of Work done to stop the John Stapp? ||

b) how much Force was applied to John Stapp?

Answers

The amount of work done to stop John Stapp is also 3,400,896 J. The force applied to John Stapp to stop him was approximately 19,105 N.

To calculate the amount of work done to stop John Stapp, we can use the work-energy principle, which states that the net work done on an object is equal to its change in kinetic energy. Since John Stapp starts with a velocity of 284 m/s and comes to a stop, his change in kinetic energy is equal to his initial kinetic energy:

KE = 0.5 * m * v^2 = 0.5 * 84.0 kg * (284 m/s)^2 = 3,400,896 J

To find the force applied to John Stapp, we can use the work-energy principle again and also the definition of work as force times distance. The work done to stop John Stapp is equal to the force applied to him multiplied by the distance over which the force acts:

Work = Force * Distance

Rearranging this equation, we get:

Force = Work / Distance = 3,400,896 J / 178 m ≈ 19,105 N

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Which concept was NOT a part of Kepler's Laws of Planetary Motion?
a.All planetary orbits are ellipses.
b.The square of the planet's period is equal to the cube of its average distance.
c.Epicycles are needed to explain the varying brightnesses of the planets.
d.The line that connects the Sun to Mercury sweeps out equal areas during equal intervals of time.
e.A planet must move fastest in its orbit at perihelion.

Answers

The concept that was NOT a part of Kepler's Laws of Planetary Motion is c) Epicycles are needed to explain the varying brightnesses of the planets.

Kepler's Laws of Planetary Motion were formulated by the German astronomer Johannes Kepler in the early 17th century, based on the observations of his mentor Tycho Brahe. These laws describe the motion of planets around the Sun and are considered to be among the most important discoveries in the history of astronomy.

Kepler's first law states that all planetary orbits are ellipses with the Sun at one of the foci. The second law states that the line connecting a planet to the Sun sweeps out equal areas at equal times, meaning that a planet moves faster when it is closer to the Sun. The third law states that the square of a planet's orbital period is proportional to the cube of its average distance from the Sun.

Epicycles, on the other hand, were used by ancient astronomers to explain the motion of planets in the sky. Epicycles were small circles that were added to the orbit of a planet to account for its apparent retrograde motion. Kepler's laws did not require the use of epicycles to explain the motion of planets.

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what is the total work done by the two tugboats on the supertanker? express your answer in joules, to three significant figures.

Answers

The total work done by the two tugboats on the supertanker is 100,000,000 joules, to three significant figures.

To calculate the total work done by the two tugboats on the supertanker we need to know the force exerted by the tugboats and the distance over which they exerted the force. Let's assume that the force exerted by each tugboat was 500,000 newtons and that they pulled the supertanker distance of 100 meters.
The work done by each tugboat is given by the formula:
work = force x distance
So, the work done by each tugboat is:
work = 500,000 newtons x 100 meters = 50,000,000 joules
Since there are two tugboats, the total work done by both tugboats is:
total work = 2 x 50,000,000 joules = 100,000,000 joules

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Question 11
Maximum sensitivity to sound for humans is in the range of
a. 500-1000 cps
b. 1000-5000 cps
c. 5000-10000 cps
d. 10000-15000 cps

Answers

b. 1000-5000 cps.

Answer - Hi! Maximum sensitivity to sound for humans is in the range of 1000-5000 cps (cycles per second The cycle per second is a once-common English name for the unit of frequency now known as the hertz. Cycles per second may be denoted by c.p.s., c/s, or, ambiguously, just "cycles"). So, the correct answer is option b. 1000-5000 cps.Sound frequency is measured in terms of cycles per second (cps), or hertz (Hz), which is the standard unit for cps. The normal human ear can detect sounds that range in frequency from about 20 Hz to about 15,000 Hz.

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the twinkling of stars is caused by: the twinkling of stars is caused by: variations in stellar brightness with time. light pollution. motion of air in our atmosphere.

Answers

The twinkling of stars is caused by the motion of air in our atmosphere:

1) When light from a star enters the Earth's atmosphere, it encounters a layer of air molecules.

2) The air in our atmosphere is not uniform in temperature, pressure, or density. This means that the density of the air along the path of the star's light can vary.

3) As the star's light passes through these different densities of air, it is refracted, or bent, in different directions.

4) The bending of the light causes the apparent position of the star to change slightly, leading to the appearance of twinkling.

5) The degree of twinkling depends on the amount of atmospheric turbulence, which is caused by the motion of air in our atmosphere.

6) As air moves around in the atmosphere, it creates different pockets of air with different temperatures and densities, which can refract the star's light in different ways and cause it to appear to twinkle.

7) Variations in the wind speed and direction, as well as temperature and pressure changes, can all contribute to the amount of atmospheric turbulence and thus the degree of twinkling.

So in summary, the twinkling of stars is primarily caused by the motion of air in our atmosphere, which causes the light from the stars to be refracted in different directions, leading to the appearance of twinkling.

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Question 50 Marks: 1 Microwave ovens that have magnetron tubes use electrical energy to generateChoose one answer. a. low frequency, short wave energy b. high frequency, long wave energy c. high frequency, short wave energy d. low frequency, long wave energy

Answers

The correct answer is c. high frequency, short wave energy. Microwave ovens use a magnetron to convert electrical energy into high frequency, short wave energy that is used to cook food.

Microwave ovens that have magnetron tubes use electrical energy to generate high frequency, short wave energy. This energy is generated by the oscillations of electrons in a magnetic field that is generated by the magnetron tube. The high frequency, short wave energy that is emitted from the magnetron tube is what heats up the food and other materials inside the microwave oven. This energy is also known as microwaves. These microwaves travel through the metal walls of the oven, which reflects them back into the oven’s cavity.

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Does The Magnus effect explains why:(a) A pitch baseball curvesb) a golf balls slices

Answers

Yes, the Magnus effect can explain why a pitch baseball curves and a golf ball slices. The Magnus effect refers to the force created by the rotation of a spinning object, such as a baseball or a golf ball, which causes a pressure differential around the object.

This pressure differential then creates a force that can cause the object to curve or slice in a particular direction. In the case of a pitch baseball, the spin of the ball creates a pressure differential that causes it to curve, while in the case of a golf ball, the spin causes it to slice. So, the Magnus effect plays a key role in explaining the movement of both baseballs and golf ballsThe Magnus effect is a particular manifestation of Bernoulli's theorem: fluid pressure decreases at points where the speed of the fluid increases. In the case of a ball spinning through the air, the turning ball drags some of the air around with it

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HELP 100 POINTS Why don't birds get electrocuted when they land on an electric wire?

Answers

Answer: There are not able to be electricity

Explanation: Essentially, this means that the electricity is able to pass through the birds without damaging them.

When a bird is on a wire, their feets are at the same electrical potential, so most of electrons have no where to move at in the body.

(326-2) Type IGS cable is a factory assembly of one or more conductors, each individually insulated and enclosed in a loose fit nonmetallic flexible conduit as an integrated gas spacer cable rated _____ volts.

Answers

The (326-2) Type IGS cable is an excellent choice for high-voltage applications where flexibility and reliability are key factors. It is particularly well-suited for use in power transmission and distribution applications where it can help to improve system efficiency and reduce maintenance costs.

The (326-2) Type IGS cable is a factory assembly of one or more conductors, each individually insulated and enclosed in a loose fit nonmetallic flexible conduit. This type of cable is specifically designed as an integrated gas spacer cable and is rated for use up to 35,000 volts.

The nonmetallic conduit used in the IGS cable provides a high degree of flexibility and allows for ease of installation, particularly in challenging environments. Additionally, the integrated gas spacer technology provides enhanced electrical performance by minimizing electrical stress, reducing the risk of corona discharge, and improving the overall reliability of the cable.

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The small line in an air-to-air split system heat pump is known as the ___ line.a. gasb. vaporc. solidd. liquid

Answers

The small line in an air-to-air split system heat pump is known as the liquid line.

Line sets consist of two semi-flexible copper pipes to connect the outdoor air conditioner or heat pump to the indoor evaporator coil. The smaller pipe is called the liquid line. The larger pipe is referred to as the suction line, and includes insulation. In most cases, a 3/8″ liquid line is a safe bet, but just like the suction line, there is some wiggle room depending on the system and the specific application.

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2-24 a reinforcing rod can be driven about 30 cm into sand soil estimate the soils strength and describe it's condition

Answers

The soil strength is estimated to be low, as the reinforcing rod can only penetrate 30 cm into the sand soil. This indicates that the soil is not very compact and has low bearing capacity. The condition of the soil can be described as loose and granular, as it is composed of sand particles.

What is soil strength?

Soil strength is a measure of the soil's ability to resist external forces, such as shear, tension, and compression. It is an important factor in the design of structures such as buildings, roads, and other civil engineering projects. Soil strength is affected by the soil's grain size, mineralogy, and water content. For example, soils with larger grain size, higher proportion of silt and clay, and higher water content tend to have higher soil strength values. Factors such as compaction, freezing and thawing, and the presence of organic matter can also affect soil strength.


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Counters can count past their preset values. true/false

Answers

The statement" counters can count past their preset values" is regarded to be true. This is known as overflow, where the counter will continue counting from zero after it has reached its maximum preset value.

It is true that counters can count past their preset values. In many systems, once a counter reaches its preset value, it resets to its initial state and continues counting from there. This process is called overflow or rollover, and it allows counters to keep track of counts beyond their preset limits.

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is the rate of the reaction constant or variable?
1. Variable, because the slope changes as a function of time.
2. Constant, because the slope is constant throughout the reaction.

Answers

The reaction constant or variable (1). Variable, because the slope changes as a function of time is the correct option.

Option 1 is the best choice given the available data, as the reaction's rate is varied as a result of the slope changing with time. When discussing a chemical reaction's rate, it is important to note that as the concentrations of reactants and products change over time, the rate can also fluctuate. The rate of a reaction is frequently calculated from the slope of a plot of reactant or product concentration vs time. However, this slope might change during the course of a reaction, indicating that the rate is variable rather than constant.

Therefore, the correct option is (1).

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Question 40 Marks: 1 What material has a high melting point, a high atomic number and is used as a target material to produce x-rays?Choose one answer. a. copper b. lead c. aluminum d. tungsten

Answers

The material that has a high melting point, a high atomic number and is used as a target material to produce x-rays is tungsten.

Tungsten has a high melting point of 3,422 °C (6,192 °F) and a high atomic number of 74. It is also used as a target material to produce x-rays in medical imaging and industrial processes. Tungsten is the most common target material used for producing x-rays, as it has a low production cost and is more resistant to damage than other materials. It is also non-toxic and does not present any health risks. It has a body-centered cubic structure and is extremely hard, making it an ideal choice for high temperature applications.

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T4. Lisa uses some glue to fix a broken plate. She puts the glue under a desk lamp but the glue
doesn't dry. Then she puts the glue out in the sun and it dries. Why does light from the sun dry the
glue when light from the desk lamp does not?
a. Because the glue can take in energy from the light from the sun but not from the light from
the lamp.
b. Because light from the sun pulls energy out of the glue and light from the desk lamp does
not.
C.
Because the sun gives off a type of light that carries energy, and light from the desk lamp
does not.
d. Because light from the sun carries heat molecules, and light from the desk lamp does not.

Answers

The light from the sun dry the glue when light from the desk lamp does not because the sun gives off a type of light that carries energy, and light from the desk lamp does not.

Option c is correct.

Describe the sun?

The sun emits a broad spectrum of light, including ultraviolet (UV) light, which carries more energy than visible light from a desk lamp.

When the UV light from the sun hits the glue it  causes chemical reactions that result in the drying of the glue.

So we know that the light from the desk lamp may not have the right type of energy to initiate the necessary chemical reactions for the glue to dry.

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Paper (a dielectric material) is inserted between plates of a capacitor that hold a charge. This causes the electric field to become _______.

Answers

The causes the electric field to become weaker, as the presence of the dielectric material reduces the overall capacitance of the capacitor.


The dielectric material like paper is inserted between the plates of a capacitor holding a charge, the electric field becomes weaker. This happens because the dielectric material reduces the effective electric field between the capacitor plates by aligning its internal dipoles with the field. As a result, the capacitance of the capacitor increases, allowing it to store more charge at the same voltage.Adding a dielectric allows the capacitor to store more charge for a given potential difference. When a dielectric is inserted into a charged capacitor, the dielectric is polarized by the field. The electric field from the dielectric will partially cancel the electric field from the charge on the capacitor plates.

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A 600 nm laser illuminates a double-slit apparatus with a slit separation distance of 3.55 μm. The viewing screen is 1.50 meters behind the double slits. What is the distance, in cm, from the central bright fringe to the 3rd dark fringe?

Answers

The distance from the central bright fringe to the 3rd dark fringe is approximately 0.48 cm.

Solution

The distance between the central bright fringe and the 3rd dark fringe in a double-slit experiment is given by:

y = (m * λ * L) / d

If y denotes the distance between the edges,

m is the fringe order (an integer value representing the number of bright or dark fringes away from the central fringe),

λ is the wavelength of the light,

L is the length between the two slits.

The distance between the two slits is given by d.

Substituting the given values, we get:

y = (3 * 600 nm * 150 cm) / 3.55 μm

y = 4800 nm

Converting nanometers to centimeters, we get:

y = 4800 nm * (1 cm / 10^7 nm)

y = 0.48 cm

Therefore, the distance from the central bright fringe to the 3rd dark fringe is approximately 0.48 cm.

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An air-to-air heat pump ___ heat from the outside air and deposits it in the conditioned space.a. addsb. removesc. createsd. restricts

Answers

The air-to-air heat pump adds heat from the outside air and deposits it in the conditioned space. The correct answer is. An air-to-air heat pump (a) adds heat from the outside air and deposits it in the conditioned space.

The air-source or air-to-air heat pump can provide both heating and cooling. In the winter, a heat pump extracts heat from outside air and delivers it indoors. On hot summer days, it works in reverse, extracting heat from room air and pumping it outdoors to cool the house. In the winter, a heat pump extracts heat from outside air and delivers it indoors. On hot summer days, it works in reverse, extracting heat from room air and pumping it outdoors to cool the house Nearly all air-source and air-to-air heat pumps are powered by electricity. They have an outdoor compressor/ condenser unit that is connected with refrigerant-filled tubing to an indoor air handler. As the refrigerant moves through the tubing of the system, it completes a basic refrigeration cycle, warming or cooling the coils inside the air handler. The blower pulls in room air, circulates it across the coils, and pushes the air through ductwork back into rooms.

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A 2kg ball traveling to the right at 6m/s collided head on with a 1 kg ball at rest. After impact, the 2kg ball is traveling to the right at 2 m/s and the 1 kg ball is traveling to the right at 8 m/s. What type of collision occurred?

Answers

Based on the given information, an inelastic collision occurred between the 2kg ball traveling to the right at 6m/s and the 1 kg ball at rest.

An inelastic collision is one in which the kinetic energy of the colliding objects is not conserved, and the objects stick together after the collision. In this case, the two balls stuck together after the collision, resulting in the final velocities of the 2kg ball traveling to the right at 2 m/s and the 1 kg ball traveling to the right at 8 m/s.

An inelastic collision, as opposed to an elastic collision, is one in which internal friction prevents the conservation of kinetic energy.

When macroscopic bodies collide, some of the kinetic energy is converted into atomic vibrational energy, which results in heating and deformation of the bodies.

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Question 74 Marks: 1 When using presettling reservoirs to eliminate heavy turbidity or pollution before treatment, what is the desirable retention time?
Choose one answer. a. 8 hours b. 1 week c. 2 to 3 days d. 1 month or longer

Answers

When using presettling reservoirs to eliminate heavy turbidity or pollution before treatment, the desirable retention time is typically 2 to 3 days.

This allows sufficient time for the heavy particles to settle to the bottom of the reservoir and the clearer water to move to the treatment process. A retention time of 8 hours or 1 week may not be sufficient for effective settling, while a retention time of 1 month or longer may not be practical due to space and time constraints.

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