The mass of a star is 1.210×10[tex]^{31}[/tex] kg and it performs one rotation in 20.30 days. Find its new period (in days) if the diameter suddenly shrinks to 0.350 times its present size. Assume a uniform mass distribution before and after.

The types of fusion that occurs in stars are:

A nuclear fusion is reaction in which nucleus of small atoms combine together to produces atoms of larger nucleus.

The types of nuclear fusion that can occur in a star include;

In conclusion, the types of fusion that occur in stars are proton-proton fusion, carbon cycle fusion and helium fusion.

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Answer:

Centripetal acceleration of this aircraft: approximately [tex]6.52\; {\rm m \cdot s^{-2}}[/tex].

Distance covered during the turn: approximately [tex]63.2\; {\rm km}[/tex].

Time required for the turn: approximately [tex]0.0242\; \text{hours}[/tex] (approximately [tex]87.2\; {\rm s}[/tex].)

Explanation:

Convert velocity and radius to standard units:

[tex]\begin{aligned}v &= 2610\; {\rm km \cdot h^{-1}} \times \frac{1\; {\rm h}}{3600\; {\rm s}} \times \frac{1000\; {\rm m}}{1\; {\rm km}} \\ &= 725\; {\rm m\cdot s^{-1}} \end{aligned}[/tex].

[tex]\begin{aligned} r = 80.5\; {\rm km} \times \frac{1000\; {\rm m}}{1\; {\rm km}} = 8.05 \times 10^{4}\; {\rm m}\end{aligned}[/tex].

Hence, the centripetal acceleration of this aircraft:

[tex]\begin{aligned} a &= \frac{v^{2}}{r} \\ &= \frac{(725\; {\rm m\cdot s^{-1}})^{2} }{8.05 \times 10^{4}\; {\rm m}} \\ &\approx 6.53\; {\rm m \cdot s^{-2}}\end{aligned}[/tex].

The trajectory of the turn is an arc with a radius of [tex]r = 80.5\; {\rm km}[/tex] and a central angle of [tex]\theta = 90^{\circ} = (\pi / 4)[/tex]. The length of this arc would be:

[tex]\begin{aligned} s &= r\, \theta \\ &= 80.5\; {\rm km} \times (\pi / 4) \\ &\approx 63.2\; {\rm km}\end{aligned}[/tex].

The time required to travel [tex]63.2\; {\rm km}[/tex] at a speed of [tex]2610\; {\rm km \cdot h^{-1}}[/tex] would be:

[tex]\begin{aligned}t &= \frac{s}{v} \\ &\approx \frac{63.2\; {\rm km}}{2610\; {\rm km \cdot h^{-1}}} \\ &\approx 0.0242\; {\rm h} \\ &\approx 0.0242 \; {\rm h} \times \frac{3600\; {\rm s}}{1\; {\rm h}} \\ &\approx 87.2\; {\rm s} \end{aligned}[/tex].

(a) The time for the capacitor to loose half its charge is 2.2 ms.

(b) The time for the capacitor to loose half its energy is 1.59 ms.

q(t) = q₀e-^(t/RC)

q(t)/q₀ = e-^(t/RC)

0.5q₀/q₀ = e-^(t/RC)

0.5 = e-^(t/RC)

1/2 =  e-^(t/RC)

t/RC = ln(2)

t = RC x ln(2)

t = (12 x 10⁻⁶ x 265) x ln(2)

t = 2.2 x 10⁻³ s

t = 2.2 ms

U(t) = Ue-^(t/RC)

U = ¹/₂Q²/C

(Ue-^(t/RC))²/2C = Q₀²/2Ce

e^(2t/RC) = e

2t/RC = 1

t = RC/2

t = (265 x 12 x 10⁻⁶)/2

t = 1.59 x 10⁻³ s

t = 1.59 ms

Thus, the time for the capacitor to loose half its charge is 2.2 ms and the time for the capacitor to loose half its energy is 1.59 ms.

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Answer:

I think its C

Answer:

D

Explanation:

If the temperature doesn't change but the mass of the object increases, the thermal energy in the object increases.

Answer:

A

Explanation:

most mammals are viviparous instead of oviparous. oviparous means laying eggs

The tension in the cable is 23.2 N

The tension in the cable can be resolved into horizontal and vertical forces Tcosθ and Tsinθ respectively.

Tcosθ, is acting perpendicularly, Tcosθ = 0

Taking moments about the pivot:

Tsinθ * 2.2 = 4 * 9.8 * 0.7

Solving for θ;

θ = tan⁻¹(1.4/2.2) = 32.5°

T = 27.44/(sin 32.5 * 2.2)

T = 23.2 N

In conclusion, the tension in the cable is determined by taking moments about the pivot.

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(a) The expression for the speed of the larger piece is [tex]\frac{v\sqrt{2} }{3}[/tex].

(b) The numeric value for the speed of the larger piece is 10.84 m/s.

(c) The direction of the larger piece is 45⁰ with respect to y - axis.

Apply the principle of conservation of linear momentum;

m₁v₁ + m₂v₂ + m₃v₃ = 0

where;

mv.i + mv.j + (3m)v₃  = 0

(3m)v₃  = -mv.i - mv.j

3v₃ = - v.i - v.j

[tex]v_3 = \frac{-v_i \ - \ v_j}{3} = \frac{v\ (\sqrt{(-1)^2 + (-1)^2} )}{3} = \frac{v\ \sqrt{2} }{3}[/tex]

[tex]v_3 = \frac{23 \times \sqrt{2} }{3} \\\\v_3 = 10.84 \ m/s[/tex]

tan θ = vj/vi

tan θ = 1/1

tan θ = 1

θ = arc tan(1)

θ = 45⁰

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The time after it starts spinning, that the box will slip off is 0.1 s.

I₁ω₁ - I₂ω₂ = 0

I₁ω₁  =  I₂ω₂

where;

The final angular speed when the box slides off;

ω₂ = I₁ω₁ / I₂

ω₂  = [0.5(m₁ + m₂)(R + r)²] / (0.5MR²)

ω₂  = [0.5(30 + 0.3)(3.1 + 1.4)²] / (0.5 x 30 x 3.1²)

ω₂  = 2.13 rad/s

Time taken for the for box to slide off;

τ = Iα

τ = I(ω/t)

τ = (Iω)/t

t =  (Iω)/τ

t = (0.5 x 0.3 x 1.4² x 2.13)/6

t = 0.1 s

Thus, the time after it starts spinning, that the box will slip off is 0.1 s.

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The average speed in the first case is 19.86 m/s and the average speed in the second case is 13.67 m/s.

The formula of average speed is

average speed = total distance / total time

In first case

total distance is 143 km which is also 143000 m

and total time is 2 hours which is also 7200 seconds

so average speed = ( 143000 / 7200 ) m/s

average speed = 19.86 m/s

In second case

total distance is 160 km which is also 160000 m

and total time is 3 hours and 15 minutes which is also 11700 seconds

so average speed = ( 160000 / 11700 ) m/s

average speed = 13.67 m/s

So to conclude with we have find the the average speed in both cases by dividing total distance by total time and in first case we have got our answer as 19.86 m/s and in second case we have got 13.67 m/s.

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Answer:

The answer is 50 watts

Explanation:

The formula of power is work done over elapsed time

P= W/t
P= 550 J / 11 sec

P= 50 watts

The amount of electric charge that resides on each capacitor once it is fully charged is 0.37 C.

The total capacitance of the circuit is calculated as follows;

Capacitors in series;

1/Ct = 1/8 + 1/7.5

1/Ct = 0.25833

Ct = 3.87 mF

Capacitors is parallel;

Ct = 3.87 mF + 12 mF + 15 mF

Ct = 30.87 mF

Ct = 0.03087 F

Q = CV

Q = 0.03087 x 12

Q = 0.37 C

Thus, the amount of electric charge that resides on each capacitor once it is fully charged is 0.37 C.

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y =  11.3380m

The double-slit experiment  is an experiment, that shows that light has both a wave nature or characteristic and a particle nature or characteristic, and that these natures are inseparable.

So, light is said to have wave–particle duality rather than be only a wave or only a particle. The same is true for electrons and other quantum particles.

According to the question,

The relative to angle θ, its adjacent side has length x and its opposite side is equal to width of the river, y;

tanθ = [tex]\frac{y}{d}[/tex] = y = dtanθ

y =( 112m) tan (37.8° )

y ≈  11.3380m

The width of river is 11.3380m

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Science builds on itself because the process of science is iterative and not predetermined.

Science is said to build on itself because the process of science is iterative. This means that science does not have a linear path but circles back on itself so that useful ideas are built upon and used to learn even more about the natural world.

For instance, the discovery of inheritance that could be passed from parent to their offspring by Gregor Mendel.

Many more scientist has worked subsequently on chromosome, gene and DNA.

They have continued to deepen and extend our understanding of genes, how they are controlled, how patterns of control themselves are inherited, and how they produce the physical traits that pass from generation to generation.

Science is said to build on itself because the process of science is not predetermined. This means that carrying out an experiment on an idea would lead to the discovery of a new idea altogether.

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The main way in which an altimeter measures the altitude of an object is by calculating the location's air pressure.

This refers to the instrument that is used to measure the altitude of an object when it is at a fixed level.

Hence, we can see that an altimeter should NOT be confused with a barometer, because although they both measure pressure, a barometer calculates the change in air pressure and elevation based on available weather.

Please note that your question is incomplete so I gave you a general overview to help you get a better understanding of the concept.

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Answer:

A

Explanation:

resisting is doing something that goes against what something or someone is doing therefore the resisting force is the opposing force

Answer:

it’s all time on the Screen so it should be counted as one thing they are different things that you have different timelines for each category

Since everything is happening at once on the screen, even though there are distinct events with separate timings for each category, it should all be considered one item.

Websites and programs that place a high value on community involvement, content sharing, collaboration, and social interaction are referred to as social media. Social media is used by people to interact and communicate with their friends, family, and other groups.

It is a helpful tool for talking with individuals locally and internationally as well as for generating, sharing, and spreading information. Social media has the power to influence consumer buying decisions via reviews, marketing, and marketing tactics.

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Answer:

One of the key similarities between both the psychoanalytical theory and the behavioral theory is that both are by and large, deterministic.

Answer:

See below

Explanation:

a)  Spring force at release =  k * d = 132 N/m * .120 m = 15.84 N

b) F = ma

   15.84 = (.660 kg)(a)     a = 24 m/s^2

c) Toward the left ....the object is accelerated to the left

A. The magnitude of the spring force acting upon the object at the instant of release is approximately 15.84 N.

B. With the moment of release, the object is moving with an acceleration of about [tex]\rm -24 m/s^2[/tex].

C. The correct option is toward the equilibrium position (i.e., to the left in the figure).

Let us calculate the magnitude of the spring force, the acceleration of the object and the direction of the vector at the time of release.

Given:

Mass of the object (m) = 0.660 kg

Force constant of the spring (k) = 132 N/m

Displacement from equilibrium (x) = 0.120 m

Magnitude of the spring force [tex]\rm (F_s_p_r_i_n_g):[/tex]

To determine the spring force at the time of release, we can apply Hooke's law. According to Hooke's law, the force of a spring depends on how far it has moved from its equilibrium position. Hooke's law is expressed as:

[tex]\rm F_s_p_r_i_n_g[/tex] = -k * x

where

[tex]\rm F_s_p_r_i_n_g[/tex] is the spring force,

k is the force constant of the spring, and

x is the displacement from the equilibrium position.

When we put the values, we get:

[tex]\rm F_s_p_r_i_n_g[/tex] = -132 N/m * 0.120 m

[tex]\rm F_s_p_r_i_n_g[/tex] = -15.84 N

Therefore, the magnitude of the spring force acting upon the object at the instant of release is approximately 15.84 N.

The net force acting on the object at the time of release determines its acceleration. The spring force and any additional external forces acting on the object add up to form the net force. In this case the spring force is the only force acting on the object.

According to Newton's second law of motion, the acceleration of an object is inversely related to its mass and directly proportional to the total force exerted on it. Acceleration is calculated as:

a = [tex]\rm F_n_e_t[/tex] / m

where

a is the acceleration,

[tex]\rm F_n_e_t[/tex] is the net force, and

m is the mass of the object.

Noting that the mass (M) is 0.660 kg and the net force (-15.84 N) is equal to the force of the spring, we can plug the following numbers into the formula:

a = (-15.84 N) / 0.660 kg

a = [tex]\rm -24 m/s^2[/tex]

Therefore, with the moment of release, the object is moving with an acceleration of about [tex]\rm -24 m/s^2[/tex].

The direction of the acceleration vector is left in the diagram, or towards the equilibrium position. This is because the negative sign of the acceleration value indicates that the acceleration is moving in the direction opposite to that in which the equilibrium position has moved. Since the signal indicates that the object first moved to the right, acceleration will be applied to the left in an attempt to bring the object back to its equilibrium position.

So, the correct option is toward the equilibrium position (i.e., to the left in the figure).

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The spring constant is obtained from the ratio of applied force to the elongation of the spring. The work done by the force is 2F.

The spring constant is obtained from the ratio of applied force to the elongation of the spring.

k = F/x (N/m)

The work done by the force is calculated as follows;

W = ¹/₂FΔx

where;

W = ¹/₂F(4)

W = 2F

Thus, the spring constant is obtained from the ratio of applied force to the elongation of the spring. The work done by the force is 2F.

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Answer:

Approximately [tex]31\%[/tex] assuming that [tex]g = 9.81\; {\rm N \cdot kg^{-1}}[/tex].

Explanation:

Consider an object of mass [tex]m[/tex] in a uniform gravitational field of strength [tex]g[/tex]. If the height of that object increased by [tex]\Delta h[/tex], the gravitational potential energy of that object would increase by [tex]m\, g\, \Delta h[/tex].

In this question, the mass of the rocket is given to be [tex]m = 0.55\; {\rm kg}[/tex]. Assume that [tex]g = 9.81\; {\rm N \cdot kg^{-1}}[/tex]. The rocket has gained a height of [tex]\Delta h = 23\; {\rm m}[/tex]. Thus, the gravitational potential energy of this rocket would have increased by:

[tex]\begin{aligned} m\, g\, \Delta h &= 0.55\; {\rm kg} \times 9.81\; {\rm N \cdot kg^{-1}} \times 23\; {\rm m} \\ &\approx 124.1\; {\rm J} \end{aligned}[/tex].

In other words, the useful energy output from the combustion of the rocket fuel was approximately [tex]124.1\; {\rm J}[/tex].

The energy input to this rocket was given to be [tex]400.0\; {\rm J}[/tex]. Thus, the efficiency of the energy conversion would be:

[tex]\begin{aligned} \text{efficiency} &= \frac{(\text{useful energy out}\text{put})}{(\text{energy in}\text{put})} \times 100\% \\ &\approx \frac{124.1\; {\rm J}}{400.0\; {\rm J}} \times 100\% \\ &\approx 31\%\end{aligned}[/tex].

yes

Explanation:

it develops alot of trade

The area of the house will be 146.78 in square meters

What we have given in the question is that there is one house whose area is measured in square feet which is 1580 square feet, and we have to convert that area in square meter.

Now, To convert the area in square meter we must divide the area given in square feet by a constant which is 10.764.

Area in square meter = Area in square feet / 10.764

Area in square meter = 1580 / 10.764 square meter

Area in square meter = 146.78 square mete

Thus we conclude that You must divide the area given in square feet by 10.764 to convert Square feet to Square meters and vice versa for the opposite and after calculation we found that area which is 1580 square feet will be 146.78 in magnitude in square meters

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Answer:

195.168 m

Explanation:

To find the magnitude of the vector you can use the Pythagorean Theorem since you have the height and base and the vector is really just the hypotenuse

Pythagorean Theorem:

[tex]a^2+b^2=c^2[/tex]

Plug values in

[tex]88.4^2+174^2=c^2[/tex]

Simplify

[tex]7814.56+30276=c^2[/tex]

Add the two values

[tex]38090.56=c^2[/tex]

Take the square root of both sides

[tex]195.168\approx195.168[/tex]

The characteristic of a sound wave that is directly related to the loudness of the sound is amplitude.

Sound wave is a type of wave that is produced by the vibration of objects which can be heard only if it's of high frequency.

The properties of sound waves include:

The characteristic of a sound wave that is directly related to the loudness of the sound is amplitude. That is, a larger amplitude means a louder sound, and a smaller amplitude means a softer sound.

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The tension in the upper rope is determined as 50.53 N.

The tension in the upper rope is calculated as follows;

T(u) = T(d)+ mg

where;

T(u) = 12.8 N + 3.85(9.8)

T(u) = 50.53 N

Thus, the tension in the upper rope is determined as 50.53 N.

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a)The tension in the vertical strand will be 0.00049 N.

b))The tension in the horizontal strand will be 0.001284 N.

c)The ratio of tension in the horizontal strand to the tension in the vertical strand will be  2.62.

The tension force is described as the force transferred through a rope, string, or wire as it is pulled by opposing forces.

Given data;

Mass of spiderweb = 5.00 ✕ 10⁻⁵ kg

The tension in a horizontal strand of a spiderweb, Tₓ

The tension in a  vertical strand of a spiderweb, Tₐ

The angle at which the strand sags, Θ = 10.0°

R is the ratio of  tension in the horizontal strand to the tension in the vertical strand

a)

From the FBD,

The tension  in the vertical strand is equal to the weight of the spider;

Tₐ = W

Tₐ = mg

Tₐ= 5 x 10⁻⁵ kg x 9.8 m / s²

Tₐ= 0.00049 N.

(b)

The super's total vertical forces are zero since it is not moving the value of the tension in the horizontal strand;

Tₓ = mg/( 2sinΘ)

Tₓ = 5 x 10⁻⁵ kg x 9.8 m /s² / ( 2 sin 11° )

Tₓ= 0.001284 N.

c)

R is the tension in the vertical strand divided by the tension in the horizontal strand.

R= Tₐ / Tₓ

R= 0.001284 N / 0.00049 N

R= 2.62

Hence, the tension in a vertical strand of a spiderweb, the tension in a horizontal strand of a spiderweb, and the ratio of tension in the horizontal strand to the tension in the vertical strand will be 0.00049 N, 0.001284 N, and 2.62 respectively.

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The work done was done by friction to keep the crate from moving as the truck came to a stop is 20,000 J.

The work done is determined by applying the principle of conservation of energy.

W = K.E

W = ¹/₂mv²

where;

W = ¹/₂(100)(20²)

W = 20,000 J

Thus, the work done was done by friction to keep the crate from moving as the truck came to a stop is 20,000 J.

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The equigravity between two planets is determined from the product and their masses and square of distance between them.

The gravitational force between two planets is calculated as follows;

F = GM₁M₂/R²

where;

Use the mass ratio of the two planets to determine their individual masses.

Thus, the equigravity between two planets is determined from the product and their masses and square of distance between them.

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Answer:

20 miles

Explanation:

Use pythagorean theorem

d^2 = 16^2 + 12^2

   to find displacement, d = 20 miles