The inner diameter of a small test-tube Can be measured accurately using​

The resultant speed of the airplane is 150 km/h, and this is the speed relative to the ground.

The resultant speed of the airplane is the single speed of the airplane that will produce same effect as the two speeds acting together.

To convince your classmate about the ground speed of the airplane we need to calculate the resultant speed of the airplane.

R² = Vp² + Vw²

where;

R² = Vp² + Vw²

R = √[Vp² + Vw²]

R = √[120² + 90²]

R = 150 km/h

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As she starts to move upward, the student pushes down on the surface with a force that is greater than her weight. This will cause her net force to be directed upwards, thus, alternative B.

Net force is the vectoral sum or the resolution of all the forces acting on a body. Although, more than one force may be acting on a body at the same time, only the resultant force or the net force will have a significant effect on the body. If the net force is equal to zero, the body is said to be in a state of equilibrium, and according to Newton's first law of motion, the body will remain in its state of rest or will continue to move in uniform speed.

As for the student in the question, her net force isn't equal to zero, so she will move in the direction of her net force, which is upwards. Newton's third law of motion states that "to every action, there is an equal but opposite reaction".

When she pushed downwards on the surface of the ground with a force greater than her weight, the ground surface will also produce a force in opposite direction to and equal to the force she used on the ground called a normal force, according to Newton's third law of motion. The normal force is also greater than the weight of the girl, hence, her net force will not be zero, and it will move in an upward direction, causing her to jump off the ground.

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Complete question:

As she starts to move upward, the student pushes down on the surface with a force that is greater than her weight. What can you say about the net force on her?

A. The net force is zero.

B. The net force is directed upward.

C. The net force is directed downward

The component of the gravitational force acting down the inclined plane has a magnitude of 209.98 N

Eventhough the box is at an inclined plane which makes 36° with the horizontal, the gravitational force will still act straight down perpendicular to the horizontal. Resolving the force due to gravity into its horizontal and vertical components. The vertical component makes 36° with the gravitational force and is at right angles with the horizontal component.

The component of the gravitational force acting down the inclined plane is the horizontal component.

W = 355.9 N

In a right angled triangle,

sin θ = Opposite side / Hypotenuse

sin 36° = [tex]W_{x}[/tex] / W

[tex]W_{x}[/tex] = 355.9 * 0.59

[tex]W_{x}[/tex] = 209.98 N

Therefore, the component of the gravitational force acting down the inclined plane is the horizontal component with a magnitude of 209.98 N

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The volume of the bubble of gas when it reaches the surface is 1 cm³.

Boyle's law states that the pressure of a given mass of a gas is inversely proportional to its  volume provided that the temperature of the gas is constant.

Mathematically, Boyle's law is given as;

P₁V₁ = P₂V₂

where;

When the pressure at the bottom is double the pressure at the surface, then the pressure at the surface is half the pressure at the bottom.

V₂ = P₁V₁/P₂

Let the pressure at the surface = P

V₂ = (2PV₁)/P

V₂ = 2V₁

V₂ = 2(0.5 cm³)

V₂ = 1 cm³

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The complete question is below:

A bubble of gas is released from the mud at the bottom of the pond. It’s initial volume is 0.5cm^3. Ignoring any temperature differences in the water calculate the volume of the bubble as it reaches the surface if the pressure at the bottom is twice the pressure at the surface.

Answer:

See below

Explanation:

Use pythag theorem

r^2 = 3^2 + 5^2

r = sqrt (34)  = 5.83

          angle    = arctan (3/5) = 31 degrees   north of east

In a feedback loop, the stimulus Creates an set point that impacts the original event.

A system component known as a feedback loop is one in which all or a portion of the output is used as input for subsequent operations. A minimum of four stages comprise each feedback loop.

Input is produced in the initial phase. Input is recorded and stored in the subsequent stage. Input is examined in the third stage, and during the fourth, decisions are made using the knowledge from the examination.

Both negative and positive feedback loops are possible. Insofar as they stay within predetermined bounds, negative feedback loops are self-regulating and helpful for maintaining an ideal state. One of the most well-known examples of a self-regulating negative feedback loop is an old-fashioned home thermostat that turns on or off a furnace using bang-bang control.

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Answer:

I believe that it is A) they're more spread out

a)

  i) the lorry's speed is rising and then stays at a constant speed

 ii) it is accelerating but after 40 seconds, it stays at a constant speed

b)

  speed= 25m/s

  speed=  90km's

Answer:

See below

Explanation:

Lorry starts from rest , then accelerates to reach a constant velocity of 25 m/s

Initial Acceleration =   10 m/s / 20 s =   1/2 m /s^2

Maximum speed is 25 m/s= 25 m/s * 1 km / 1000 m * 3600 s /hr =  90 km/hr

Answer: Final velocity of car is 18.64 m/s

Explanation:

According to equation of motion,

V=U + at

where,

V is final velocity

U is initial velocity

a is acceleration

T is time

in the question,

U=16 m/s

a=0.22 m/s*s

t=12 seconds

on substituting values,

V = 16+(12*(0.22))

V=18.64

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The speed of the ball is "50.4 m/s"

The structure is 130 meters high.

64 meters across the horizontal

Gravity causes an acceleration of 9.8 m/s.

Using the equation of motion s = ut + (0.5at2) and presuming that air resistance is not taken into account, we first calculate how long it takes for the object to strike the ground.

where s = distance (height of the building)

initial speed is u. (which is 0 in this case )

Time t equals (130/4.9) where an is the gravitational acceleration (0 x t) + (0.5 x 9.8 x t2) = 130 4.9 x t2.

5.15 seconds = t

We now apply the equation Vy = Uy + at to get the speed before it touches the ground (0 in this case)

Vy = 0 + (9.8 x 5.15) (9.8 x 5.15) (9.8 x 5.15)

Vy = 50.4 m/s

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Answer: 69

Explanation: 160 divided by 2 is 69

The magnitude of the Resulting force calculated is 1.125 N.

The force of repulsion between two objects is calculated by Coulomb's Law which is a quantitative statement between 2-point charges. The equation of Coulomb's Law is,

F = [tex]\frac{ K q^{2} }{r^{2} }[/tex]

where k = Dielectric constant of the medium also called Relative permittivity of medium and is dimensionless.

In the first case, Force is  F = 0.900 N

In the second case, given, one q is tripled and the other is increased by a factor of 5/3. Distance between is doubled, Let the final force be F'

[tex]F' = \frac{kq^{2} *5}{r^{2} *4}[/tex]

F' = (0.009 × 5)/4

F' = 1.125

Hence, the Final force is 1.125 N

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We observe a higher fraction of elliptical galaxies within a cluster because they are dim and consist of older stars. So, such type of galaxies affects the closer galaxies, which makes it to be in clusters making the closer galaxies similar.

Consequently, we also observe a higher fraction of spiral galaxies in the field because spiral galaxies consist of big arms with most of the young stars. These are less in the universe as per our observation. So, such type of galaxies appears in a field because of their high brightness and structure.

According to the observations, elliptical galaxies are more in comparison to the spiral galaxies.

These elliptical galaxies are dim and consist of older stars. So, such type of galaxies affects the closer galaxies, which makes it to be in clusters. It makes the closer galaxies similar.

Spiral galaxies consist of big arms with most of the young stars. These are less in the universe as per our observation. So, such type of galaxies appears in a field because of their high brightness and structure.

If the cluster is crowded, there would be more elliptical galaxies as the collision of spiral galaxies forms elliptical galaxies. The spiral arms of the spiral galaxies are most affected by the collision and the morphology of the galaxy changes. It goes from spiral to elliptical. Probability of such collisions is more in crowded clusters in comparison to alone galaxies.

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Answer:

The relative density of mercury is 13.6, this means that mercury is 13.6 times as heavy as an equal volume of water.

The balloon will be falling for 0.84 seconds.

The boy is going to drop the balloon when the speed of the cyclist is 30km/hr. i.e. 8.33m/s

Let the distance covered by the cyclist is L. According to question, the distance travelled by the L/2.

Considering that the balloon falls on the head of cyclist.

We can understand, the time period t of the distance travelled by the boy and the balloon will be same.

As the acceleration is constant, we can use equation of motion.

For the balloon,

L/2 = 1/2gt²

Now,

No acceleration for the cyclist, so, for cyclist,

L/t = 8.33m/s

t = L/8.33

Putting the value of t = L/8.33 in L/2 = 1/2gt²,

L/2 = 1/2g(L/8.3)²

L/2 = 1/2gL²/68.89

1 = Lg/68.89

Taking g = 9.8

L = 7.02m

Now we can calculate the time by putting L = 7.02m in

L/t = 8.33m/s

t = 0.84 seconds.

The balloon will take 0.84 seconds to fall down.

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The car B will experience greater acceleration than car A.

According to the Newton's second law, the acceleration of an object is depends on the net force acting upon the object and the mass of the object. The mathematical form of the law is given below.

F = m*a

Where F = force, m = mass and a = acceleration.

The equation in terms of acceleration is,

a = F/m

From the formula, we can see that the acceleration is directly proportional to force and indirectly proportional to mass. The net force on the car A is greater than car B. But the mass of the car A is larger than almost three times of the mass of car B. Hence the car A will have lower acceleration compared to car B. The larger net force will not increase the acceleration very much. So, the car B will experience greater acceleration than car A.

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the mass on Moon will be 98.1 kg.

Given - Weight on Earth and moon

Find - Mass on Moon

First, determine the mass of the Earth using its gravitational acceleration.

Taking acceleration due to gravity as 10 m/s².

Mass = weight/acceleration due to gravity

Mass = 981/10

Performing division

Mass = 98.1 kg

As is already common knowledge, the mass is independent of the acceleration caused by the planet's gravity. The mass of the moon will therefore be 98.1 kg.

The earth weighs 6. 1024 kilograms, while the moon weighs 7.4 1022 kilograms. Calculate the force that the earth would apply on the moon if their distance were 3.84 x 105 miles.

The Moon's mass is not included in the Earth's mass. The Earth+Moon system has a mass of about 6.04561024 kg since the Moon's mass is roughly 1.2% that of the Earth.

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.

The change in the velocity of the rocket after 220 meters is 80.42 m/s.

The change in the velocity of the rocket at the given time of motion is calculated as follows;

Apply the following kinematic equation to determine the velocity of the rocket.

v² = u² + 2as

where;

v² = 2as

v = √2as

v = √(2 x 14.7 x 220)

v = 80.42 m/s

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The 25w bulb burned out.

Both bulbs (200w and 25w) are connected in series to the 240v line, the same current is expected to flow in them. The  expected resistance of the 200W bulb will be less than 25W. Therefore more potential difference than 120V will be developed in 25W bulb hence it will fuse.

As per the question:

Voltage, V = 120 V

Power of bulb 1, P = 25 W

Power of bulb 2, P' = 200 W

Voltage in series, V' = 240 V

Now,

When the two bulbs are connected in parallel, voltage across them is same and the current in the two branches is different.

Using P= V²/R to calculate the respective resistances of the two bulbs:

25 = 120²/R

R = 120²/25

R = 576Ω

100 = 120²/R

R = 120²/100

R' = 144Ω

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The 25W bulb burned out almost instantaneously when the two light bulbs were connected in series across a 240V line because the voltage across it is much more than its rated voltage.

Two lights bulbs, one 25w and another 200w, to find the bulb that burn out almost instantaneously, we first find the following:

Resistance R=V^2/P

For the bulb of 25W

Resistance=120^2/25

                 =576.0Ω

For the bulb of 200W

Resistance=120^2/200

                  =72.0Ω

Net resistance of the circuit:

R=R25W+R200W

 =576.0+72.0

 =648.0Ω

Current, I

I=E/R

=240/648.0

=0.370A

Voltage across 25W bulb

Voltage=I*R

           =0.370*576.0

           =213.12V

Voltage across 200W bulb

Voltage=I*R

           =0.370*72.0

           =26.64V

Since voltage across 25W bulb is much more than its rated voltage of 120V, 25W bulb will burn out.

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Answer:

mass is measured in kilograms

Both the average and instantaneous velocities well be same over the given interval if the acceleration is zero.

Instantaneous velocity is the rate of differential change of displacement with respect differential change in time. Mathematically -

v = dx/dt

Given is the acceleration of a school bus over a given time interval as zero.

For acceleration over a given time interval to be zero, it must be ensured that the the velocity of the object should remain constant. Mathematically-

a = (v - u)/(t₂ - t₁)

For acceleration [a] = 0, v = u. Therefore -

a = 0

The instantaneous velocity for zero acceleration between the time interval t₁ to t₂ will be equal to initial velocity only -

dx/dt = u          

This will be the instantaneous velocity and is equal to (u) at any instant.

Now -

dx = u dt

Integrating both sides, we get -

∫dx = ∫u dt

x = ut

Therefore, the average velocity will be =

v(avg) = x/Δt = ut/Δt

Now -

t = Δt for any specific time interval. Therefore -

v(avg) = ut/t = u

This is the average velocity and it is equal to (u).

Therefore, both the average and instantaneous velocities well be same over the given interval if the acceleration is zero.

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The center of mass of the three mass system is at 83cm

A position relative to an object or set of objects is known as the center of mass. It is the system's average location, weighted by the mass of each component.

Given the mass of the meter stick is:

M = 0.5kg.

Since the meter stick is uniform, the center of mass of the meter stick is at 50cm or 0.5m.

Let the distance of the meter stick's center of mass from 0cm be x1. Then x1 = 0.5m.

Now a mass m2 = 1kg is attached at 50cm mark.

So the distance of m2 from 0cm is x2 = 50cm = 0.5m.

Similarly a mass m3 = 3kg is attached at the every end or 100cm mark. So the distance of m3 from 0cm is x3 = 100cm = 1m.

Now the position of the three mass system from 0cm is given by,

[tex]X_{CM}=\frac{Mx_{1}+m_{2}x_{2}+m_{3}x_{3}}{M+m_{2}+m_{3}}X_{CM}=\frac{0.5\times 0.5+1\times 0.5+3\times 1}{0.5+1+3}=\frac{3.75}{4.5}=0.83m = 83cm[/tex]

So the center of mass of the three mass system is at 83cm.

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The final displacement vector for Max's golf ball is d. 246 m, 29.1 degrees north of east.

displacement 1 = 235 m  15.9° west of north.

displacement2 = 29.5  meters 41.1° east of north.

resultant vector = [tex]\sqrt{235{^{2} + 29.5^{2} }[/tex]

                          = 246.84 m, 29.1 degrees north of east

A vector is an object that has both importance and direction. Geometrically, we are able to image a vector as a directed line section, whose duration is the importance of the vector, and with an arrow indicating the direction. The direction of the displacement vector is from its tail to its head.

Vector is a term that refers colloquially to a few quantities that can not be expressed via an unmarried variety, or to elements of a few vector spaces. Vectors are geometrical or physical portions that own both value and direction wherein the item is moving. The importance of a vector shows the length of the vector. it's far normally represented by means of an arrow pointing within the course of the vector.

Disclaimer:- your question is incomplete, please see below for the complete question.

Max is golfing and he hits a ball 235 meters 15.9° west of north. From that location, he hits the ball 29.5 meters 41.1° east of north. What is the final displacement vector for Max's golf ball?​

a. 246 m, 29.1 degrees east of north

b. 252 m, 10.3 degrees west of north

c. 252 m, 10.3 degrees north of west

d. 246 m, 29.1 degrees north of east

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A. The time spent by the ball in the air is 14.7 s

B. The ball will land at 1060.47 m as it hits the net.

C. The maximum height reached by the ball is 265.12 m

A. How to determine the time

The time spent by the ball in the air can be obtained as follow:

T = 2uSineθ / g

T = [2 × 101.944 × Sine 45] / 9.8

T = 14.7 s

B. How to determin the distance

R = u²Sine(2θ) / g

R = (101.944)² × Sine (2×45) / 9.8

R = 1060.47 m

C. How to determine the maximum height

The maximum height reached by the ball can be obtained as follow:

H = u²Sine²θ / 2g

H = [(101.944)² × (Sine 45)²] / (2 × 9.8)

H = 265.12 m

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The change in momentum of the ball travelling along a straight path, perpendicular to a wall, after bouncing off the wall as observed by the ground observer is 0

Δp = [tex]p_{f}[/tex] - [tex]p_{i}[/tex]

Δp = Change in momentum

[tex]p_{f}[/tex] = Final momentum

[tex]p_{i}[/tex] = Initial momentum

p = m v

m = Mass

v = Velocity

Since, [tex]p_{f}[/tex] = [tex]p_{i}[/tex]

Δp = 0

Momentum can be simply defined as a mass in motion. So if an object with mass moves, it will have momentum. It is a vector quantity.

Therefore, the change in momentum as observed by the ground observer is 0

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The solenoid is the component that converts electrical energy into magnetic energy. It is created with the aid of a wire coil.

This gadget generates a magnetic field, which is then put to use in a variety of ways. Inside the solenoid, the magnetic field's direction remains constant. The device that transforms electrical energy into magnetic energy is a solenoid. It is made possible by a wire coil. This device creates a magnetic field that is subsequently used in a number of different ways. The magnetic field has a consistent direction inside the solenoid.

To calculate how many turns into gloomy oid there are. The magnetic field equation for the solenoid is the simplest method to remember how to achieve that. Mu not N times I times L, where mu naught is the constant N, gives us B.

I have taken how many turns. is the solenoid's length, and is the current. Our Bs nine Tesla RL is 90.50 m mu not four pi times 10 to the negative seven and I 75 amps, so we may rearrange this so that the end will be equal to B times L divided by mu naught times I.

We'll therefore obtain 4.5 divided by 9.42 multiplied by 10 to the negative 5.

And we will receive several phrases of 47746. hence, um,.4. We will thus have this many turns to bother this cell.

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Answer:

0.2

Explanation:

0.5 - 0.3 = 0.2

The change created by melting is known to be called a physical change.

A physical change happens when a given  substance's physical characteristics alters without undergoing a kind of chemical composition.

Note that Melting, changes in size, as well as in volume, color, also density, and crystal shape are said to be an examples of common physical changes.

Physical changes, like melting or the act of boiling, are usually simple to undo even though the final result might not always look exactly the same as the original. Aside from gaining or losing energy, particles do not change during physical changes and no new materials are created.

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The radius of a planet that has the same mass as earth but on which the free-fall acceleration is 4.90 m/s² is 9 M m

g = G M / R²

g = Acceleration due to gravity

G = Gravitational constant

M = Mass

R = Radius

g = 4.9 m / s²

G = 6.67 * [tex]10^{-11}[/tex] m³ / kg s²

M = 5.97 * [tex]10^{24}[/tex] kg

R² = ( 6.67 * [tex]10^{-11}[/tex] * 5.97 * [tex]10^{24}[/tex] ) / 4.9

R² = 81.3 * [tex]10^{12}[/tex].

R = 9 * [tex]10^{6}[/tex] m

R = 9 M m

Acceleration due to gravity is the acceleration produced by a planet. If an object is falling, it will gain some acceleration due to gravitational force.

Therefore, the radius of a planet is 9 M m

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