The green light emitted by a stoplight has a wavelength of 505 nm. What is the frequency of this photon? (c = 3.00 × 10⁸ m/s).

Answers

Answer 1

Answer:

5.9405*10^14 Hz

Explanation:

Remember the equation c=v*λ

v=frequency

λ=wavelength

By manipulating the equation, we can get it in terms of frequency:

c/λ=v

Now convert wavelength to meters (1nm=m*10^-9)

5.05*10^-7m (2 decimal places were shifted to make the number between 1-10, hence the -7 exponent)

Use the manipulated equation:

(3.00*10^8)/(5.05*10^-7), which yields:

5.9405*10^14 Hz (or s^-1)

Answer 2

The frequency of the photon will be "[tex]5.9405\times 10^{14} \ Hz[/tex]".

According to the question,

Wavelength,

[tex]\lambda = 505 \ nm[/tex]

or,

          [tex]= 5.05\times 10^{-7} \ m[/tex]

As we know the equation,

→ [tex]c = v\times \lambda[/tex]

or,

→ [tex]v = \frac{c}{\lambda}[/tex]

By putting the values, we get

     [tex]= \frac{3.00\times 10^8}{5.05\times 10^{-7}}[/tex]

     [tex]= 5.9405\times 10^{14} \ Hz[/tex]

Thus the above answer is right.

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Explanation:

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Answers

#protactinium

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#Francium

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Answer:

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Answer:

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Answer:

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Answers

Considering the definition of empirical and molecular formula, the pair of compounds C₄H₁₀ and C₂H₅ has the same empirical formula.

The empirical formula is the simplest expression to represent a chemical compound and indicates the elements that are present and the minimum proportion in whole numbers that there are between their atoms. This formula is also known as the "minimum formula".

On the other side, the molecular formula is the chemical formula that indicates the number and type of different atoms present in the molecule. But unlike the chemical formula, it shows the actual number of atoms that make up a molecule.

In this case, you can observe that if you divide the amount of each element by 2 in compound C₄H₁₀, you get C₂H₅, which is the empirical formula of the compound.

Finally, the pair of compounds C₄H₁₀ and C₂H₅ has the same empirical formula.

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