The form of energy that can move from place to place across the universe is

Answers

Answer 1

Answer:kinetic energy

Explanation:

Answer 2
Answer: kinetic energy

Related Questions

Discuss how oxygen is used in spacecraft's air supplies in at least 3 paragraphs.

Answers

Short-duration spacecraft typically have one backup system and carry their own supply of oxygen. A large portion of the required oxygen is produced on long-duration missions, such as the International Space Station (ISS), which has been in orbit since 1998. Different sources provide the oxygen utilized on the ISS. The water electrolyzer is the primary source of metabolic oxygen. As an alternative to the electrolyzer, oxygen candles (also known as SFOGs) can produce metabolic oxygen. Additionally, oxygen is carried up whenever a cargo ship docks and stored in two tanks on the ISS Airlock. The electrolyzer electrolyzes water to create oxygen by running an electric current through it. Since water is a poor electrical conductor by itself, a little quantity of common salt is dissolved in the water to improve its electrical conductivity. Water is split into hydrogen and oxygen throughout the process.

We must keep in mind that oxygen by itself cannot be inhaled; it must be combined in the proper ratio with nitrogen to make it breathable. Two tanks aboard the ISS are used to store nitrogen, and the cargo ships that travel by from time to time also transport nitrogen cylinders. Through the electrical grid of the station, the solar panels on the station supply the necessary electricity for the oxygen generators. The majority of the required water is transported to the station by cargo supply ships. Condensers, which draw water vapor even from the station's air, ensure that not a drop of water is wasted. Using the proper equipment, water is also recycled from the astronauts' urine.

Through a suitable vent, the hydrogen gas produced during the electrolysis process is released into space. Pressurized tanks at the airlock nodes at the space station are pumped with oxygen when the cargo vehicles arrive there. Pressurized tanks there are also pumped with nitrogen. It goes without saying that the station's atmospheric controls combine the gases in the right amounts for the atmosphere of Earth and then distribute the combination throughout the cabin. The production of oxygen in space is impossible.

A plank of length L=2.200 m and mass M=4.00 kg is suspended horizontally by a thin cable at one end and to a pivot on a wall at the other end as shown. The cable is attached at a height H=1.70 m above the pivot and the plank's CM is located a distance d=0.700 m from the pivot.
Calculate the tension in the cable.

Answers

The tension in the cable is 23.2 N

What is the tension in the string?

The tension in the cable can be resolved into horizontal and vertical forces Tcosθ and Tsinθ respectively.

Tcosθ, is acting perpendicularly, Tcosθ = 0

Taking moments about the pivot:

Tsinθ * 2.2 = 4 * 9.8 * 0.7

Solving for θ;

θ = tan⁻¹(1.4/2.2) = 32.5°

T = 27.44/(sin 32.5 * 2.2)

T = 23.2 N

In conclusion, the tension in the cable is determined by taking moments about the pivot.

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A supersonic airplane is flying horizontally at a speed of 2610 km/h.
1. What is the centripetal acceleration of the airplane, if it turns from North to East on a circular path with a radius of 80.5 km?
2. How much time does the turn take?
3. How much distance does the airplane cover during the turn?

Answers

Answer:

Centripetal acceleration of this aircraft: approximately [tex]6.52\; {\rm m \cdot s^{-2}}[/tex].

Distance covered during the turn: approximately [tex]63.2\; {\rm km}[/tex].

Time required for the turn: approximately [tex]0.0242\; \text{hours}[/tex] (approximately [tex]87.2\; {\rm s}[/tex].)

Explanation:

Convert velocity and radius to standard units:

[tex]\begin{aligned}v &= 2610\; {\rm km \cdot h^{-1}} \times \frac{1\; {\rm h}}{3600\; {\rm s}} \times \frac{1000\; {\rm m}}{1\; {\rm km}} \\ &= 725\; {\rm m\cdot s^{-1}} \end{aligned}[/tex].

[tex]\begin{aligned} r = 80.5\; {\rm km} \times \frac{1000\; {\rm m}}{1\; {\rm km}} = 8.05 \times 10^{4}\; {\rm m}\end{aligned}[/tex].

Hence, the centripetal acceleration of this aircraft:

[tex]\begin{aligned} a &= \frac{v^{2}}{r} \\ &= \frac{(725\; {\rm m\cdot s^{-1}})^{2} }{8.05 \times 10^{4}\; {\rm m}} \\ &\approx 6.53\; {\rm m \cdot s^{-2}}\end{aligned}[/tex].

The trajectory of the turn is an arc with a radius of [tex]r = 80.5\; {\rm km}[/tex] and a central angle of [tex]\theta = 90^{\circ} = (\pi / 4)[/tex]. The length of this arc would be:

[tex]\begin{aligned} s &= r\, \theta \\ &= 80.5\; {\rm km} \times (\pi / 4) \\ &\approx 63.2\; {\rm km}\end{aligned}[/tex].

The time required to travel [tex]63.2\; {\rm km}[/tex] at a speed of [tex]2610\; {\rm km \cdot h^{-1}}[/tex] would be:

[tex]\begin{aligned}t &= \frac{s}{v} \\ &\approx \frac{63.2\; {\rm km}}{2610\; {\rm km \cdot h^{-1}}} \\ &\approx 0.0242\; {\rm h} \\ &\approx 0.0242 \; {\rm h} \times \frac{3600\; {\rm s}}{1\; {\rm h}} \\ &\approx 87.2\; {\rm s} \end{aligned}[/tex].

Set local ground level to 700 ft, and record the inches of mercury.

What is the altimeter reading in inches of mercury (from the Kollsman window)?

Answers

The main way in which an altimeter measures the altitude of an object is by calculating the location's air pressure.

What is an Altimeter?

This refers to the instrument that is used to measure the altitude of an object when it is at a fixed level.

Hence, we can see that an altimeter should NOT be confused with a barometer, because although they both measure pressure, a barometer calculates the change in air pressure and elevation based on available weather.

Please note that your question is incomplete so I gave you a general overview to help you get a better understanding of the concept.

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A rocket uses 400.0 J of chemical potential energy stored in the fuel while shooting the 0.55 kg rocket straight up
into the air. The rocket reaches a height of 23 m. What was the efficiency of the rocket in transforming the chemical
potential energy of the fuel into gravitational potential energy?
Select one:
O a. 25%
Ob. 35%
O c. 31%
O d. 29%

Answers

Answer:

Approximately [tex]31\%[/tex] assuming that [tex]g = 9.81\; {\rm N \cdot kg^{-1}}[/tex].

Explanation:

Consider an object of mass [tex]m[/tex] in a uniform gravitational field of strength [tex]g[/tex]. If the height of that object increased by [tex]\Delta h[/tex], the gravitational potential energy of that object would increase by [tex]m\, g\, \Delta h[/tex].

In this question, the mass of the rocket is given to be [tex]m = 0.55\; {\rm kg}[/tex]. Assume that [tex]g = 9.81\; {\rm N \cdot kg^{-1}}[/tex]. The rocket has gained a height of [tex]\Delta h = 23\; {\rm m}[/tex]. Thus, the gravitational potential energy of this rocket would have increased by:

[tex]\begin{aligned} m\, g\, \Delta h &= 0.55\; {\rm kg} \times 9.81\; {\rm N \cdot kg^{-1}} \times 23\; {\rm m} \\ &\approx 124.1\; {\rm J} \end{aligned}[/tex].

In other words, the useful energy output from the combustion of the rocket fuel was approximately [tex]124.1\; {\rm J}[/tex].

The energy input to this rocket was given to be [tex]400.0\; {\rm J}[/tex]. Thus, the efficiency of the energy conversion would be:

[tex]\begin{aligned} \text{efficiency} &= \frac{(\text{useful energy out}\text{put})}{(\text{energy in}\text{put})} \times 100\% \\ &\approx \frac{124.1\; {\rm J}}{400.0\; {\rm J}} \times 100\% \\ &\approx 31\%\end{aligned}[/tex].

Calculate the work done by pulling an object through a distance of 30metres by a force of 220 newton

Answers

Answer:

6600J

Explanation:

the formula for work is: W= F x d

F- force, d- distance

mass is the amount of matter in an object what describes the amount of space the object takes up?
A.Color
B. Temperature
C. Volume
D. Texture
answer asap this is a exam

Answers

C volume because the volume take up the Mater and space around it thing

A watermelon is blown into three pieces by a large firecracker. Two pieces of equal mass m fly away perpendicular to one another, one in the x direction another in the y direction. Both of these pieces fly away with a speed of V = 23 m/s. The third piece has three times the mass of the other two pieces.

Write an expression for the speed of the larger piece, that is in terms of only the variable V.

What is the numeric value for the speed of the larger piece, in meters per second?

At what angle does the largest piece travel with respect to the -y axis, in degrees?

Answers

(a) The expression for the speed of the larger piece is [tex]\frac{v\sqrt{2} }{3}[/tex].

(b) The numeric value for the speed of the larger piece is 10.84 m/s.

(c) The direction of the larger piece is 45⁰ with respect to y - axis.

Expression for the speed of the larger piece

Apply the principle of conservation of linear momentum;

m₁v₁ + m₂v₂ + m₃v₃ = 0

where;

m₁ is mass of first piecem₂ is mass of second piecem₃ is mass of third piece = three times the mass of other piece = 3m

mv.i + mv.j + (3m)v₃  = 0

(3m)v₃  = -mv.i - mv.j

3v₃ = - v.i - v.j

[tex]v_3 = \frac{-v_i \ - \ v_j}{3} = \frac{v\ (\sqrt{(-1)^2 + (-1)^2} )}{3} = \frac{v\ \sqrt{2} }{3}[/tex]

Numeric value for the speed of the larger piece

[tex]v_3 = \frac{23 \times \sqrt{2} }{3} \\\\v_3 = 10.84 \ m/s[/tex]

Direction of the larger piece

tan θ = vj/vi

tan θ = 1/1

tan θ = 1

θ = arc tan(1)

θ = 45⁰

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A set of four capacitors are attached to a 12V battery in the circuit shown below. All capacitances are measured in milli-Farads. Find the amount of electric charge that resides on each capacitor once it is fully charged.

Answers

The amount of electric charge that resides on each capacitor once it is fully charged is 0.37 C.

Total capacitance of the circuit

The total capacitance of the circuit is calculated as follows;

Capacitors in series;

1/Ct = 1/8 + 1/7.5

1/Ct = 0.25833

Ct = 3.87 mF

Capacitors is parallel;

Ct = 3.87 mF + 12 mF + 15 mF

Ct = 30.87 mF

Ct = 0.03087 F

Charge in each capacitor

Q = CV

Q = 0.03087 x 12

Q = 0.37 C

Thus, the amount of electric charge that resides on each capacitor once it is fully charged is 0.37 C.

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What is resistance force?
A. The force opposing the effort
B. The force exerted by the machine
C. The work put into a machine
D. A force that improved on your effort?
Answer asap

Answers

Answer:

A

Explanation:

resisting is doing something that goes against what something or someone is doing therefore the resisting force is the opposing force

A 10.0 Ω lightbulb is connected to a 12.0 V battery. (a) What current flows through the bulb? (b) What is the power of the bulb?

Answers

The current flowing through the bulb as well the power of the bulb are 1.2A and 14.4 Watts respectively.

What current flows through the bulb as well as the power of the bulb?

From ohm's law; V = I × R

Where V is the voltage, I is the current and R is the resistance.

Also, Power is expressed as; P = V × I

Where V is voltage and I is current.

Given that;

Resistance R = 10.0 ohmsVoltage V = 12.0VCurrent I = ?Power P = ?

First, we determine the current flow through the bulb.

V = I × R

12.0V = I × 10.0 ohms

I = 12.0 ÷ 10.0

I = 1.2A

Next, we determine the power of the bulb.

P = V × I

P = 12.0V × 1.2A

P = 14.4 Watts

Therefore, the current flowing through the bulb as well the power of the bulb are 1.2A and 14.4 Watts respectively.

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An object with a mass of m = 3.85 kg is suspended at rest between the ceiling and the floor by two thin vertical ropes.
The magnitude of the tension in the lower rope is 12.8 N. Calculate the magnitude of the tension in the upper rope.
24.93 N is incorrect.

Answers

The tension in the upper rope is determined as 50.53 N.

Tension in the upper rope

The tension in the upper rope is calculated as follows;

T(u) = T(d)+ mg

where;

T(u) is tension in upper ropeT(d) is tension in lower rope

T(u) = 12.8 N + 3.85(9.8)

T(u) = 50.53 N

Thus, the tension in the upper rope is determined as 50.53 N.

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You have two rocks made of the same material that are at the same
temperature. The first rock has twice the mass of the second rock. How does
the thermal energy of the two rocks compare?
A. The second rock has four times the thermal energy of the second
rock.
B. The first rock has half as much thermal energy as the second rock.
OC. The rocks have the same amount of thermal energy.
D. The first rock has twice as much thermal energy as the second
rock.

Answers

Answer:

I think its C

Answer:

D

Explanation:

If the temperature doesn't change but the mass of the object increases, the thermal energy in the object increases.

I need help with this question, could you help me? :))) ASAP

Answers

Oh ya the correct answer for this is B I think because structure B

How is Behaviorism and Psychoanalysis theories are similar?

Answers

Answer:

One of the key similarities between both the psychoanalytical theory and the behavioral theory is that both are by and large, deterministic.

A house is advertised as having 1580 square feet under roof. What is the area of this house in square meters?

Answers

The area of the house will be 146.78 in square meters

What we have given in the question is that there is one house whose area is measured in square feet which is 1580 square feet, and we have to convert that area in square meter.

Now, To convert the area in square meter we must divide the area given in square feet by a constant which is 10.764.

Area in square meter = Area in square feet / 10.764

Area in square meter = 1580 / 10.764 square meter

Area in square meter = 146.78 square mete

Thus we conclude that You must divide the area given in square feet by 10.764 to convert Square feet to Square meters and vice versa for the opposite and after calculation we found that area which is 1580 square feet will be 146.78 in magnitude in square meters

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The larger the mass of a star, the higher the internal pressures. Higher internal pressures causes higher temperatures and it is temperature that determines the types of fusion that can occur deep in a stars interior. Discuss the types of fusion that can occur in a star, the temperatures at which they occur, and the mass required to produce them.

Answers

The types of fusion that occurs in stars are:

proton-proton fusion - stars with temperatures less than 15 million Kelvin and masses of 0.08 solar mass or more.carbon cycle fusion - occurs in stars with temperatures of 15 million Kelvin or more and masses of 4.0 solar mass or morehelium fusion - occurs in stars with temperatures of 100 million Kelvin or more and masses of 0.5 solar mass or more

What is a nuclear fusion reaction?

A nuclear fusion is reaction in which nucleus of small atoms combine together to produces atoms of larger nucleus.

The types of nuclear fusion that can occur in a star include;

Proton-proton fusion - occur in stars with core temperatures less than 15 million Kelvin and masses of 0.08 solar mass or more.Carbon cycle fusion occurs in stars with core temperatures greater than 15 million Kelvin having masses of 4.0 solar mass or more.Helium fusion - occurs in stars with core temperatures greater than 100 million Kelvin and masses of 0.5 solar mass or more

In conclusion, the types of fusion that occur in stars are proton-proton fusion, carbon cycle fusion and helium fusion.

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Lesson 2 History of Physical Science
Write an expository essay explaining how science builds on itself. Use at least two specific examples from this lesson.

Answers

Science builds on itself because the process of science is iterative and not predetermined.

How do science builds on itself?

Science is said to build on itself because the process of science is iterative. This means that science does not have a linear path but circles back on itself so that useful ideas are built upon and used to learn even more about the natural world.

For instance, the discovery of inheritance that could be passed from parent to their offspring by Gregor Mendel.

Many more scientist has worked subsequently on chromosome, gene and DNA.

They have continued to deepen and extend our understanding of genes, how they are controlled, how patterns of control themselves are inherited, and how they produce the physical traits that pass from generation to generation.

Science is said to build on itself because the process of science is not predetermined. This means that carrying out an experiment on an idea would lead to the discovery of a new idea altogether.

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A force F parallel to X-axis is starching a very light horizontal spring. Variation of force F vs. X, elongation of the spring is shown in the figure. (a)What is the spring force constant? (b) Calculate the work done by the force F as the spring elongates from x=4.0 cm to x=8.0 m.

Answers

The spring constant is obtained from the ratio of applied force to the elongation of the spring. The work done by the force is 2F.

Spring constant

The spring constant is obtained from the ratio of applied force to the elongation of the spring.

k = F/x (N/m)

Work done by the force

The work done by the force is calculated as follows;

W = ¹/₂FΔx

where;

F is applied forceΔx is elongation of the spring = 8 m - 4 m = 4 m

W = ¹/₂F(4)

W = 2F

Thus, the spring constant is obtained from the ratio of applied force to the elongation of the spring. The work done by the force is 2F.

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A device that uses electricity and magnetism to create motion is called a

Answers

Answer:

electric motors is the answer

Electric motor or electric magneticsuim

FRICTION INVESTIGATION

Summarize your findings in a short report of 150 words. Include your hypothesis, observations, data, calculations, and conclusion. The answers to the questions below should be included in your conclusion.

Why didn't the box slide off the table before you put enough coins in the bag?
What was the coefficient for the smooth surface? For the rough surface?
What was the difference between the two coefficients? What caused this difference?
What factors caused a margin for human error in this investigation?
Would the coefficient vary if you tied the string to a similar object of different masses, but on the same surface? Explain.
What did you learn from this investigation? Be thoughtful in your answer.

Answers

Based on the nature of friction:

the box did not slide off the table before you put enough coins in the bag due to friction.The coefficient of the friction of the rough surface is greater than that of the smooth surfaceThe difference is due to the nature of the surfaces.Human errors could occur if the coins are not added carefullythe coefficient of friction is a constant for a given surface and independent of the mass of the object.

What is friction?

Friction is the opposition to the relative motion of an object over another at their surfaces of contact.

The coefficient of friction is a ratio of the frictional force and the normal reaction.

Coefficient of friction = frictional force/normal reaction

The coefficient of friction of rough surfaces is greater than that of smooth surfaces.

In the given experiment:

the box did not slide off the table before you put enough coins in the bag because of friction between the box and the tableThe coefficient of the friction of the rough surface is greater than the coefficient of friction of the smooth surfaceThe difference between the two values of coefficient of friction is due to the nature of the surfaces.Human errors in the experiment could occur when the coins are not added carefullyThe coefficient of friction of each surface is constant and independent of the mass

In conclusion, the experiment demonstrates that the coefficient of friction  is a constant for given surfaces and does not depend on the mass of the object.

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A surveyor measures the distance across a straight river by the following method: Starting directly across from a tree on the opposite bank, he walks x = 112 m along the riverbank to establish a baseline. Then he sights across to the tree. The angle from his baseline to the tree is = 37.8°.

How wide is the river?
y = _____________ m

Answers

y =  11.3380m

What is Young's double-slit experiment?

The double-slit experiment  is an experiment, that shows that light has both a wave nature or characteristic and a particle nature or characteristic, and that these natures are inseparable.

So, light is said to have wave–particle duality rather than be only a wave or only a particle. The same is true for electrons and other quantum particles.

According to the question,

The relative to angle θ, its adjacent side has length x and its opposite side is equal to width of the river, y;

tanθ = [tex]\frac{y}{d}[/tex] = y = dtanθ

y =( 112m) tan (37.8° )

y ≈  11.3380m

The width of river is 11.3380m

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Calculate the reversible work done in compressing 1 ft3 of mercury at a constant temp. of 0 o C from 1 atm to 3000 atm. The isothermal compressibility of mercury at 0 o C is : κ = 3.9 x 10-6 – 0.1 x 10-9 P , where P (atm) and κ (atm-1 ).​

Answers

Compressibility of a substance is defined as the ratio of volumetric strain to the change in pressure. It is also equal to the reciprocal of the bulk modulus of the substance. It is denoted by K (kappa).

, for an isothermal process.

As we know that, work done for isothermal reversible expansion is given by-

Question 9 of 27
While working out, a man performed 500 J of work in 8 seconds. What was
his power?

Answers

The power of man performing 500 J of work in 8 seconds is 62.5 J/s.

Power can be defined as the pace at which work is completed in a given amount of time.

Horsepower is sometimes used to describe the power of motor vehicles and other machinery.

The pace at which work is done on an item is defined as its power. Power is a temporal quantity.

Which is connected to how quickly a project is completed.

The power formula is shown below.

Power = Energy / Time

Power = E / T

Because the standard metric unit for labour is the Joule and the standard metric unit for time is the second, the standard metric unit for power is a Joule / second, defined as a Watt and abbreviated W.

Here we have given Energy as 500 J and Time as 8 second.

Power = Energy / Time

Power = 500 / 8  Joule / sec

Power = 250 / 4  Joule / sec

Power = 125 / 2 Joule / sec

Power = 62.5 Joule / sec  or  62.5 watt

Power came out to be 62.5 J/s when the man performed 500 Joule of work in 8 seconds.

So we can conclude that the power in the Energy transmitted per unit of time, and can be find out by dividing Energy by time. In our case the Power came out to be 62.5 Joule / Second.

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What is the power of a motor that transfers 550 J of energy in 11s?

Answers

Answer:

The answer is 50 watts

Explanation:

The formula of power is work done over elapsed time

P= W/t
P= 550 J / 11 sec

P= 50 watts

How does the increasing mass effect the force of an object in motion?​

Answers

Answer:

According to second law of motion,the acceleration of an object depends directly upon the net force acting upon the object, and inversely upon the mass of the object. As the force acting upon an object is increased, the acceleration of the object is increased. As the mass of an object is increased, the acceleration of the object is decreased.

So simply, it can be affected due to increasing force as there is close relationship between momentum.

Explanation:

The more inertia that an object has, the more mass that it has. A more massive object has a greater tendency to resist changes in its state of motion.

I hope it was helpful for you :)

Many years ago, a scientist discovered an animal P and studied its characteristics. Some of the characteristics of animal P are as follows:
A Lays egg
B has four legs
C Can swim in the water
D Can produce milk to feed the young.
Which of the above characteristics made it difficult to classify animal P as a mammal?

Answers

Answer:

A

Explanation:

most mammals are viviparous instead of oviparous. oviparous means laying eggs

An object, whose mass is 0.660 kg, is attached to a spring with a force constant of 132 N/m. The object rests upon a frictionless, horizontal surface (shown in the figure below).


An object labeled m is attached to the right end of a horizontal spring, and the left end of the spring is attached to a wall. The spring is stretched horizontally such that the object is displaced by a distance A to the right of its equilibrium position.
The object is pulled to the right a distance A = 0.120 m from its equilibrium position (the vertical dashed line) and held motionless. The object is then released from rest.
(a)
At the instant of release, what is the magnitude of the spring force (in N) acting upon the object?
N
(b)
At that very instant, what is the magnitude of the object's acceleration (in m/s2)?
m/s2
(c)
In what direction does the acceleration vector point at the instant of release?
Toward the equilibrium position (i.e., to the left in the figure).
Away from the equilibrium position (i.e., to the right in the figure).
The direction is not defined (i.e., the acceleration is zero).
You cannot tell without more information.

Answers

Answer:

See below

Explanation:

a)  Spring force at release =  k * d = 132 N/m * .120 m = 15.84 N

b) F = ma

   15.84 = (.660 kg)(a)     a = 24 m/s^2

c) Toward the left ....the object is accelerated to the left

A. The magnitude of the spring force acting upon the object at the instant of release is approximately 15.84 N.

B. With the moment of release, the object is moving with an acceleration of about [tex]\rm -24 m/s^2[/tex].

C. The correct option is toward the equilibrium position (i.e., to the left in the figure).

Let us calculate the magnitude of the spring force, the acceleration of the object and the direction of the vector at the time of release.

Given:

Mass of the object (m) = 0.660 kg

Force constant of the spring (k) = 132 N/m

Displacement from equilibrium (x) = 0.120 m

Magnitude of the spring force [tex]\rm (F_s_p_r_i_n_g):[/tex]

To determine the spring force at the time of release, we can apply Hooke's law. According to Hooke's law, the force of a spring depends on how far it has moved from its equilibrium position. Hooke's law is expressed as:

[tex]\rm F_s_p_r_i_n_g[/tex] = -k * x

where

[tex]\rm F_s_p_r_i_n_g[/tex] is the spring force,

k is the force constant of the spring, and

x is the displacement from the equilibrium position.

When we put the values, we get:

[tex]\rm F_s_p_r_i_n_g[/tex] = -132 N/m * 0.120 m

[tex]\rm F_s_p_r_i_n_g[/tex] = -15.84 N

Therefore, the magnitude of the spring force acting upon the object at the instant of release is approximately 15.84 N.

The net force acting on the object at the time of release determines its acceleration. The spring force and any additional external forces acting on the object add up to form the net force. In this case the spring force is the only force acting on the object.

According to Newton's second law of motion, the acceleration of an object is inversely related to its mass and directly proportional to the total force exerted on it. Acceleration is calculated as:

a = [tex]\rm F_n_e_t[/tex] / m

where

a is the acceleration,

[tex]\rm F_n_e_t[/tex] is the net force, and

m is the mass of the object.

Noting that the mass (M) is 0.660 kg and the net force (-15.84 N) is equal to the force of the spring, we can plug the following numbers into the formula:

a = (-15.84 N) / 0.660 kg

a = [tex]\rm -24 m/s^2[/tex]

Therefore, with the moment of release, the object is moving with an acceleration of about [tex]\rm -24 m/s^2[/tex].

The direction of the acceleration vector is left in the diagram, or towards the equilibrium position. This is because the negative sign of the acceleration value indicates that the acceleration is moving in the direction opposite to that in which the equilibrium position has moved. Since the signal indicates that the object first moved to the right, acceleration will be applied to the left in an attempt to bring the object back to its equilibrium position.

So, the correct option is toward the equilibrium position (i.e., to the left in the figure).

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Question:- A planet X moves in an elliptical path as shown below. At which point does the planet moves faster. Assume, Ethiopian institute of space science and technology, allows to launch a space station with you. While you are in orbit, you gets thirsty. The only thing in the space station were a cup of water. you go to the cup of water and pick it up,But unfortunately your hand is twisted and the cup is turned down.Because the cup is turned down, water pour on to the floor.How would you get water?​

Answers

We can get water from the sweat and exhaled breath of the people present in the space station.

How would you get water?​

We can get water from the sweat and exhaled breath. The water we drink is recycled from the sweat and exhaled breath of the people present in the space station which was collected through  condensation on the Space Station's walls.

So we can conclude we can get water from the sweat and exhaled breath of the people present in the space station.

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A 12.0 μF capacitor is charged to a potential of 50.0 V and then discharged through a 265 Ω resistor. A)How long does the capacitor take to loose half its charge?
B) How long does it take the capacitor to loose half of its stored energy?

Answers

(a) The time for the capacitor to loose half its charge is 2.2 ms.

(b) The time for the capacitor to loose half its energy is 1.59 ms.

Time taken to loose half of its charge

q(t) = q₀e-^(t/RC)

q(t)/q₀ = e-^(t/RC)

0.5q₀/q₀ = e-^(t/RC)

0.5 = e-^(t/RC)

1/2 =  e-^(t/RC)

t/RC = ln(2)

t = RC x ln(2)

t = (12 x 10⁻⁶ x 265) x ln(2)

t = 2.2 x 10⁻³ s

t = 2.2 ms

Time taken to loose half of its stored energy

U(t) = Ue-^(t/RC)

U = ¹/₂Q²/C

(Ue-^(t/RC))²/2C = Q₀²/2Ce

e^(2t/RC) = e

2t/RC = 1

t = RC/2

t = (265 x 12 x 10⁻⁶)/2

t = 1.59 x 10⁻³ s

t = 1.59 ms

Thus, the time for the capacitor to loose half its charge is 2.2 ms and the time for the capacitor to loose half its energy is 1.59 ms.

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