The following data were collected during a short race between two friends. Velocity (m/s) 0 0.5 1 1.5 2 2 4 6 2 0 Time (s) 0 2 4 6 8 10 12 14 16 18 a) Describe the different sections of the graph. b) Determine the acceleration over the first eight seconds. c) Determine the maximum acceleration. d) Using the graph calculate the displacement: i) over the first eight seconds ii) the total race. e) Find the maximum velocity reached by the runner.

Answer:

  5.60 m/s

Explanation:

His initial potential energy is equal to his final kinetic energy.

  mgh = 1/2mv^2

  2gh = v^2 . . . . . . . multiply by 2/m

  v = √(2gh) = √(2(9.81 m/s²)(1.6 m)) = √(31.392 m²/s²)

  v ≈ 5.60 m/s

_____

Additional comment

The mass is irrelevant in the equations we typically use for this purpose.

Answer:

Space Launch System (SLS)

Explanation:

Space Launch System (SLS) is the United States Space Shuttle-derived heavy expendable launch vehicle being designed by NASA.

-TheUnknownScientist 72

Using law of conservation of momentum

[tex]\\ \sf\Rrightarrow m_1v_1-m_2v_2=(m1+m2)v_3[/tex]

[tex]\\ \sf\Rrightarrow 1500(5)-3000(7)=(1500+3000)v_3[/tex]

[tex]\\ \sf\Rrightarrow 7500-21000=4500v_3[/tex]

[tex]\\ \sf\Rrightarrow -13500=4500v_3[/tex]

[tex]\\ \sf\Rrightarrow v_3=-3m/s[/tex]

Answer:

it is B

Explanation:

Answer:

CO and H20

Explanation:

Answer:

the orbital in which the electron is located relative to the atom's nucleus.

Explanation:

Answer:

the principal energy level of an electron refers to the shell or orbital in which the electron is located relative to the atom's nucleus.

The minimum  speed that the second swimmer must have in order to catch up with the first swimmer by the end of the  pool is; 4.04 m/s

We are given the following facts;

Formula for time taken is;

time = distance/speed

Time taken by swimmer 1 for one leg;

t₁ = 50/3.9

t₁ = 12.82 s

Since swimmer 1 has a head start of 0.45 s, then time that swimmer 2 must use in order to catch up is;

t₂ = 12.82 -0.45

t₂ = 12.37 s

Thus, speed of swimmer 2;

v = 50/12.37

v = 4.04 m/s

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Answer:

The density of the substance is

[tex]0.85\: \: g \: \: \: {cm}^{ - 3}[/tex]

Hope you could get an idea from here.

Doubt clarification - use comment section.

Answer:

Approximately [tex]1.3\times 10^{8}\; \rm m\cdot s^{-1}[/tex].

Explanation:

Look up the speed of light in vacuum: [tex]c \approx 3.00\times 10^{8}\; \rm m\cdot s^{-1}[/tex]. Denote the speed as [tex]c[/tex].

If the speed of light in a medium is [tex]v[/tex], the refractive index of that medium would be:

[tex]\displaystyle n = \frac{c}{v}[/tex].

Note, that the refractive index of a medium is inversely proportional to the speed of light in this medium. A medium with a larger refractive index would thus correspond to a slower speed of light.

Rearrange this equation to find the speed of light [tex]v[/tex] in this medium:

[tex]\begin{aligned}v &= \frac{c}{n} \\ &= \frac{3.00\times 10^{8}\; \rm m\cdot s^{-1}}{2.4} \\ &\approx 1.25 \times 10^{8}\; \rm m\cdot s^{-1}\end{aligned}[/tex].

Answer:

300 Newtons

Explanation:

Weight is the force of attraction between two bodies, one usually larger (like a planet), and one smaller (like a person). Force can be calculated using the formula: Force = mass × acceleration.

The mass here is 12kg, the acceleration, which in this case, is the acceleration due to gravity is 25m/s/s, by plugging in our values, we have

Force = 12 × 25 = 300 Newtons or 300 N for short.

Answer:

papi sus

Explanation:

Answer:

[tex]\boxed {\boxed {\sf 4 \ Newtons}}}[/tex]

Explanation:

Work is energy transferred when an object is moved. It is the product of force and distance.

[tex]W= F*d[/tex]

John did 3.2 Joules of work or 3.2 Newton meters of work (the units are equivalent). The window shade was lowered a distance of 0.8 meters.

Substitute the values into the formula.

[tex]3.2 \ N *m = F * 0.8 \ m[/tex]

We are solving for the force, so we must isolate the variable F. It is being multiplied by 0.8 meters. The inverse operation of multiplication is division, so divide both sides of the equation by 0.8 m.

[tex]\frac {3.2 \ N*m}{0.8 \ m}= \frac{ F* 0.8 \ m}{0.8 \ m}[/tex]

The units of meters cancel.

[tex]\frac {3.2 \ N}{0.8 }=F[/tex]

[tex]4 \ N = F[/tex]

John must exert 4 Newtons of force.

Ek = 1/2 mv^2

9 × 10^4 = 1/2 × 800 × v^2

9 × 10^4/400 = 400 v^2 / 400

9 × 10^4/400 = v^2

√225 = v

15 ms⁻¹ = v

That's the only way I know how to work it out

I think in this case velocity and speed would be considered the same because me

s = d/t and v=d/t

one is distance travelled and the other is displacement of a body

Answer:

capacitor, device for storing electrical energy, consisting of two conductors in close proximity and insulated from each other. A simple example of such a storage device is the parallel-plate capacitor.

Explanation:

Hope it's help

please brainless me :)

Hope you could get an idea from here.

Doubt clarification - use comment section.

Answer:

C

Explanation:

because the concave mirror is always inverted

d )  when object is between focus and mirror , image formed is always virtual and erect

A concave mirror has a reflective surface that is curved inward and away from the light source .

a) Incorrect because image can be equal to , smaller then , and bigger then the object

b) and c)  Incorrect when object is between focus and mirror , image formed is virtual and erect

d ) Correct option  when object is between focus and mirror , image formed is always virtual and erect

e) Incorrect except one case in all other cases nature is real and inverted

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To solve the problem it is necessary to apply the concepts of Torque and equilibrium.

The Torque is defined as:

Where

F= Force

d = Distance

In this particular case, the force is caused by the weight of both children.

In turn, when there is equilibrium, the two torques must be equal therefore

Replacing with our values

Re-arrange to find  

Therefore the distance that the second kid should sit to balance the see-saw is 1.8m from the pivot.

Answer:

Explanation:

Power is the rate at which work is done and can be found by using the formula

[tex]p = \frac{w}{t} \\ [/tex]

p is the power in Watts (W)

w is the workdone in joules

t is time in s

but workdone = force × distance

From the question

force = 780 N

distance = 2 m

workdone = 780 × 2 = 1560 N

Since we now have the value of workdone we can find the power

We have

[tex]p = \frac{1560}{45} = 34.6666666... \\ [/tex]

We have the final answer as

Hope this helps you

The number of variations the dealership have is 40 cars.

Data given;

This is the total numbers of cars available in the dealer shop at the moment.

To get that, we simply multiply the numbers of colors available, the number of transmission and the makes of car available.

This is equal to

[tex]4*2*5=40[/tex]

From the above calculation, we can say that the variations the dealership offers is 40

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Sorry your tired, ill try to make it worth reading.

One day I walked outside, I looked around. THEN BAM a wasp lands right on my face. Its hideously sharp stinger impaled my flesh. I could almost hear it going deeper and deeper. I screamed and ran around in circles until it finely flew away. As I started walking to the door I could feel my heart pules where the thing had stung. I opened the door and went into the bathroom. Right in the middle of my face just above my nose was a red dot, with a slightly less red ring around it, like an ateroid impact. I sat down and went over the entire event five times. I decided to go back outside, as I walked around the corner, another wasp landed on me.

Answer:Passengers instinctively use the car as a frame of reference, while a physicist uses Earth. ... In such a frame of reference, Newton's laws of motion take the form given in Dynamics: Newton's Laws of Motion The car is a non-inertial frame of reference because it is accelerated to the side.

Explanation: Example of inertial and Noninertial Frame of Reference

Hi there!

a.

The equation for centripetal acceleration is as follows:

[tex]\large\boxed{a_c = \frac{v^2}{r}}}[/tex]

Plug in the given values to solve:

[tex]\large\boxed{a_c = \frac{(65)^2}{75} = 56.33 m/s^2}[/tex]

b.

According to Newton's Second Law:

[tex]\large\boxed{\Sigma F = ma}}[/tex]

The acceleration is v²/r, so the net force is:

[tex]\large\boxed{\Sigma F = m(\frac{v^2}{r})}}[/tex]

Multiply by the given mass:

[tex]\large\boxed{\Sigma F = 700(56.33) = 39433.33 N}}[/tex]

c.

There is NO net force in the vertical direction since the object is NOT accelerating in the vertical direction (normal force and weight cancel).

Thus, the ONLY net force experienced by the object is in the horizontal direction and is EQUAL to the centripetal force.

Answer:

[tex]0.6\; \rm m\cdot s^{-1}[/tex], assuming that drag of the water on the log is negligible.

Explanation:

The momentum [tex]p[/tex] of an object is equal to the product of mass [tex]m[/tex] and velocity [tex]v[/tex]. That is, [tex]p = m\, v[/tex].

If the drag of water on the log is negligible, momentum of the beaver and the log, combined, would be preserved.

The momentum of the beaver and the log, combined, was initially [tex]0\; \rm kg\cdot m \cdot s^{-1}[/tex].

The momentum of the beaver right after the dive would be [tex]7.5 \; {\rm kg} \times 4\; {\rm m \cdot s^{-1}} = 30\; {\rm kg \cdot m \cdot s^{-1}}[/tex].

The sum of the momentum of the beaver and the log is conserved and should continue to be [tex]0\; {\rm kg\cdot m \cdot s^{-1}}[/tex] even after the dive. Since the momentum of the beaver is [tex]30\; {\rm kg \cdot m \cdot s^{-1}[/tex] after the dive, the momentum of the log should become [tex](-30)\; {\rm kg \cdot m \cdot s^{-1}}[/tex].

Since the mass of the log is [tex]50\; {\rm kg}[/tex], the new velocity of this log would be:

[tex]\begin{aligned}v &= \frac{p}{m} \\ &= \frac{(-30)\; {\rm kg \cdot m \cdot s^{-1}}}{50\; {\rm kg}} \\ &= (-0.6)\; {\rm m \cdot s^{-1}}\end{aligned}[/tex].

(The new velocity of the log is negative because the log would be moving away from the beaver.)

The speed of an object is the magnitude of velocity. For this log, a velocity of [tex](-0.6)\; {\rm m \cdot s^{-1}}[/tex] would correspond to a speed of [tex]|(-0.6)\; {\rm m \cdot s^{-1}| = 0.6\; {\rm m \cdot s^{-1}[/tex].

[tex]\\ \sf\Rrightarrow F=ma[/tex]

[tex]\\ \sf\Rrightarrow \dfrac{F}{a}=m[/tex]

Or

[tex]\\ \sf\Rrightarrow m=\dfrac{F}{a}[/tex]

Answer:

M2=0.52kg

Explanation:

thats rightt

Answer:

$2140

Explanation:$2000 missing plus 7 percent of 2000 is 140 so 2000+140=2140. Each month she would pay $268 approx.

Force = mass x acceleration:

5N = 1kg x acceleration

Acceleration = 5N / 1 kg

Acceleration  = 5 m/s^2

Acceleration is a positive value so it is speeding up

Answer:

A substance occupies one half of an open container. The atoms of the substance are closely packed but are still able to slide past each other. The most likely phase of the substance is liquid.

A substance occupies one half of an open container. The atoms of the substance are closely packed but are still able to slide past each other. What is most likely the phase of the substance?

gas. NO. Gases have expansibility, that is, they occupy all the space available, so they wouldn't occupy just one half of the container.

liquid. YES. The description fits the liquid phase.

solid and gas. NO. Solids occupy fixed positions and their atoms can't slide past each other.

liquid and solid. NO. Solids can't be present due to their lack of movement.

A substance occupies one half of an open container. The atoms of the substance are closely packed but are still able to slide past each other. The most likely phase of the substance is liquid.

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Explanation:

Answer:

Explanation:

Centrifugal force Fc = m x v2 / r

Weight  = mg

As required by the question

Fc = W

v2 /r = g

given radius r = 22 m

v2 /22 = 9.8

Solve for v

required speed v = √(22 * 9.8)

= 14.35 m/s

v=15 m/s

this may help you

The force of the wall on the box equals the weight of the box when you drive with a speed of 14.68 m/s.

The centrifugal force can be described as an inertial force that appears to act on all objects in a rotating frame of reference. This force is directed away from an axis that is parallel to the axis of rotation and passes through the coordinate system's origin.

The magnitude of centrifugal force of mass m at the distance r from the origin rotating with angular velocity ω is:

[tex]{\displaystyle F=m\omega ^{2}r}[/tex]

Given, the radius of the curve, r = 22m

The acceleration, a = v²/r

The weight of the box, W = mg

We know that, F = ma

mg = m(v²/r)

v = √gr

[tex]\displaystyle v =\sqrt{9.8 \times 22}[/tex]

v = 14.68 m/s

Therefore, you should drive at a speed of 14.68 m/s

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