The flotation process used in metallurgy involves Multiple Choice the roasting of sulfides. separation of gangue from ore. electrolytic reduction. chemical reduction of a metal. zone refining.

Explanation:

Chemical bond refers to the forces holding atoms together to form molecules and solids. This force is of an electric nature, and the attraction between electrons of one atom to the nucleus of another atom contributes to what is known as chemical bonds.

Answer:

Na2 S O4

Explanation:

Na  mole wt   22.989

 32.4 / 22.989 = 1.4093

S  mole wt = 32.06

22.6/32.06 = .7049

O  mole wt = 15.999

 45 / 15.999 = 2.8127            Now divide all of the results by the smallest

Na    1.4093 / .7049 = 2

S      .7049/.7049     = 1

O      2.8127 /.7049   =  4                    so    Na2 S  O4

Answer: C.)

Explanation:

;-; ;-; ;-; ;-; ;-; ;-; ;-; ;-; ;-; ;-; ;-; ;-; ;-; ;-;

The complete statement is "CH3CHOHCH3 is not an electrolyte in solution." This is further explained below.

Generally,a liquid or gel containing ions that may be broken down by electrolysis, such as the kind used in batteries.

In conclusion, "CH3CHOHCH3 is not an electrolyte in solution," is the whole sentence.

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Answer:

I thinks is B

Explanation:

they just look harmful

I also researched and it says  its harmful and causes sickness and death

Answer:

0.419 mol O₂

Explanation:

just took test

Answer:

18.17 g

Explanation:

From the coefficients of the equation, we know that.for every 6 moles of nitric acid consumed, 2 moles of water are produced.

Nitric acid has a formula mass of 63.012 g/mol, so 190.7 g is about 190.7/63.012 = 3.0264 mol.

Thus, we need 3.0264(2/6) = 1.0088 mol of water.

Water has a formula mass of 18.015 g/mol, so the answer is (18.015)(1.0088), which is 18.17 g to 4 sf.

Refrigeration will prevent bacterial growth which may result in uricase production and breakdown of uric acid in the sample.

An enzyme called uricase is responsible for catalyzing the change of uric acid into allantoin. Your body excretes uric acid, an acidic waste product, through urine. It is a typical result of the digestion of purine-rich meals.

Only media containing uric acid, allantoin, or allantoate as the primary or only source of carbon, nitrogen, and energy support the growth of the bacteria Bacillus fastidious. Raw extract of cells cultivated on uric acid had significant amounts of uricase.

Alcaligenes eutrophus, Pseudomonas aeruginosa, and Micrococcus denitrificans all displayed increased uricase activity after being placed in conditions containing uric acid, according to Kaltwasser. The ability of microorganisms to degrade uric acid and to use it for growth is an inducible property of various bacteria. Uricases of Bacillus fastidious and of Aspergillus nidulans were reported to be induced by uric acid.

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The heat of combustion per mol of the glucose is 2840 kJ.

A reaction that involves the burning of a compound in the presence of air or oxygen is called combustion. In the absence of oxygen combustion of a compound cannot take place.

It is given that the combustion of glucose produces carbon dioxide and water. The balanced chemical reaction for the given process is expressed as:

C6H12O6 (s) + 6O2 (g) ------> 6CO2 (g) + 6H2O (l)

The energy released from this reaction is -2840 kJ. The above equation clearly shows that 1 mol of glucose is used during the reaction and the energy produced is -2840 kJ.

Therefore, the heat of combustion per mol of the glucose is 2840 kJ.

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Answer:

A

Explanation:

Phosphorus has an electron configuration of 1s2 2s2 2p6 3s2 3p3. Another way to write that is [Ne] 3s2 3p3. The [Ne] represents the fact that the beginning of phosphorus' electron configuration is the same as Neon's. so if you add all the superscripts they will give you 15. we didn't use choice d because we have to make the last p halffilled(3, half of the total electron held in p shell ) when we make "s shell 1 " not make it 4 because we are transfering that 1 electron .but nevertheless the correct answer is A.

Taking into account the reaction stoichiometry, 108 grams of HCl form 131.70 grams of AlCl₃.

In first place, the balanced reaction is:

2 Al + 6 HCl → 2 AlCl₃ + 3 H₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The following rule of three can be applied: if by reaction stoichiometry 218.7 grams of HCl form 266.7 grams of AlCl₃, 108 grams of HCl form how much mass of AlCl₃?

[tex]mass of AlCl_{3} =\frac{108 grams of HClx266.7 grams of AlCl_{3}}{218.7 grams of HCl}[/tex]

mass of AlCl₃= 131.70 grams

Then, 108 grams of HCl form 131.70 grams of AlCl₃.

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the pH during the titration of 40.00 mL of 0.1000 M HCl after adding 50 mL of 0.1000 M NaOH is pH = 13.39

NaOH + HCl → NaCl + H2O

40.00 ml 0.5M NaOH solution

mol NaOH = 40 ml / 1000 ml / L * 0.5 mol / L = 0.02 mol NaOH

25 mL 0.1 M HCl

mol HCl = 25 mL / 1000 mL / L * 0.1 mol / L = 0, 0025 mol

This reacts with 0.0025 mol NaOH

[NaOH] = 0.269 M

[OH-] = 0.269 M

pOH = - log 0.269

pOH = 13.43

You titrate with 30 mL 0.100 M HCl

Mol HCl = 30 mL / 1000 mL/L * 0.100 mol /L = 0.003 mol HCl

This will react with 0.003 mol NaOH

Mol unreacted NaOH = 0.02 mol - 0.003 mol = 0.017 mol NaOH in 40mL + 30 mL = 70 mL solution

Molarity of NaOH solution = 0.017 mol / 70 mL * 1000 mL/L = 0.243 M

[OH-] = 0.243 M

pOH = - log 0.243

pOH = 0.61

pH = 13.39

40 mL

Titration is defined as "the process of determining the amount of substance A by adding a measured amount of substance B, which is a titrator that reacts until an accurate chemical equivalence point is reached."

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An electric field travels away from a positive charge and toward a negative charge.

Electric field is the region of space where the impact of electric force is felt.

The electrostatic field is always directed away from positive charges and toward negative charges, and, field lines must go away from positive charges and toward negative ones.

Thus, an electric field travels away from a positive charge and toward a negative charge.

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1 mole of a gas at STP occupies 22.4 L volume

Now the volume is given =78.4 therefore,

No. of moles of gas = 78.4 ÷ 22.4 = 3.5 moles

I hope it helps you~

Answer:

Nucleic acid

Explanation:

Because nucleic acid is the molecule that carries genetic information because it helps to develop or functioning an organism

An effective way of reducing effects of radiation treatment on healthy cells is by  splitting the radiation into multiple treatments; option A.

The side effects of radiation treatment include damage to healthy cells.

This damage is can cause physical effects such as lowered immune system.

The best way to reduce this effect could be done by splitting the radiation into multiple treatments.

Therefore, radiation treatment produces undesirable effects such as damage to healthy cells.

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Answer:

Paper Chromatography

Explanation:

Most leaves are green due to chlorophyll pigments of different types like chlorophyll A, chlorophyll B, etc. All these pigments will be seperated according to their molecular composition. So, the correct option is 'Paper Chromatography'.

Answer:

C9 H13 N O3  

Explanation:

Carbon mole wt = 12

   59 /12 = 4.917

Hydrogen  mole wt = 1

  7.15 / 1 =   7.15

Oxygen mole wt = 16

  26.2 / 16 = 1.6375

Nitrogen  mole wt = 14

  7.65 / 14 = .5464                  

Now divide the numbers by the smallest found      

 Carbon   4.917 / .5464 = 9

 Hydrogen  7.15 / .5464 = 13

 Oxygen    1.6375 / 3

  Nitrogen  .5464 /.5464 =1                   emp form  C9 H13 O3 N      

Answer: 0.43molO₂

Explanation:

The ideal gas law for moles is [tex]n=\frac{PV}{RT}[/tex]. If you did not know, R is the ideal gas constant, [tex]0.0821\frac{L*atm}{mol*K}[/tex].

Since the temperature must be in Kelvin, we must convert our given temperature from ℃ to K. [tex]19C+273=292K[/tex]

Now that we have the temperature converted to Kelvin, we can plug in our information to the ideal gas law for the number of moles.

[tex]n=\frac{PV}{RT}[/tex]

[tex]n=\frac{1.38atm*7.51L}{0.0821\frac{L*atm}{mol*K} *292K} =0.43molO_{2}[/tex]

[tex]n=0.43molO_{2}[/tex]

Therefore, the number of moles is 0.43molO₂.

I hope this helps! Pls mark brainliest!! :)

Answer:

[Ne] 3s² 3p³

Explanation:

this is the answer and give me likes and vote for me

The amount of the original isotope that remains after 30 days is 11.14.

The half life of a radioactive nuclide has to do with the time that it takes for only half of the original number of nuclides to remain.

Now;

No = 150 grams

N = ?

t1/2 = 8 days

t = 30 days

Then;

N/No = (1/2)^t/t1/2

N/150 = (1/2)^30/8

N/150 = (1/2)^3.75

N = (1/2)^3.75 * 150

N = 11.14

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Given the half-life, the amount remaining is 11.14 g

The half-life of idine-131 is 8 days.

Using the half-life formula:

Nt = No * (0.5)^(t/t1/2)

Amount remaining = 150 * (05)^(30/8)

Amount remaining = 11.14 g

In conclusion, the amount remaining is determined from the half-life of the substance.

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Column height is 20cm, and HETP is 10cm.

So this column will behave as 20/10=2 ideal trays.

Hence the distillate composition will be 45%benzene.

Chem 233                                                                                                           Islam AboalnadieSeparation of Liquids by Fractional Distillation and Analysis by Gas ChromatographyBackground and Methods: The purpose of this lab was to use the techniques of fractional distillation to separate a 1:1 mixture of Ethyl acetate and Butyl acetate then use gas chromatography to analyze the amount of each compound in each of three fractions obtained through the distillation. Fractional distillation will then be compared to simple distillation.

The first fraction was taken when the distillation apparatus was near the boiling point of Ethyl acetate (77.1ºC) (1). The second was taken when the distillation apparatus was in the process of increasing temperature from the boiling point of Ethyl acetate to the boiling point of Butyl acetate (126.1ºC) (1).  The third and final fraction was taken around the boiling point of Butyl acetate until the distillation process was complete.

Please check the attached diagram for a more detailed answer.

10%benzene solution be separated as 2 timelines in txy diagram.

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Answer:

1548.67g

Explanation:

q=mL

since specific latent heat of vaporisation of water (L) = 2.260 kJ/g,

3500kJ = m(2.26)

m = 1548.67g

Answer:

1 2 1 2

2 1 1 2

2 1 3

2 3 3 1 3

Explanation:

0.592 grams of O₂ gas are needed.

An ideal gas is a gas that obeys gas laws at all temperature and pressure conditions. It have velocity and mass but do not have volume. Ideal gas is also called perfect gas.

Ideal gas law equation is expressed as:

PV = nRT

where,

P = Pressure

V = Volume (in Liters)

n = Number of moles of gas

R = Ideal gas constant

T = Temperature

Here,

P = 0.505 atm

V = 869 ml = 0.869 L

R = 0.0821 L atm/K mol  [Ideal gas constant]

T = 287 K

Now put the values in above equation

PV = nRT

0.505 atm × 0.869 L = n ×  0.0821 L atm/K mol × 287 K

0.438 atm L = n × 23.56 L atm / mol

[tex]n = \frac{0.438\ \text{atm L}}{23.56\ \text{L atm / mol}}[/tex]

n = 0.0185 mol

Now,

Mass of oxygen = Number of moles × Molar Mass

                           = 0.0185 mol × 32 g/mol

                           = 0.592 gram

Thus from the above conclusion we can say that 0.592 grams of O₂ gas are needed.

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The heat of reaction:

There has been a -22 kJ/mol heat of reaction. This is an exothermic reaction as the reaction has been indicated by the negative sign.

Definition of Heat of reaction:

The amount of energy that the system absorbs or releases to create the products is described as the heat of reaction.

The heat of reaction has been provided by:

ΔH = ΔH[tex]_{reactant}[/tex] - ΔH[tex]_{product}[/tex]

Calculation of Heat of reaction:

On the basis of the bond energies, the heat of the reaction has been estimated. The heat of the reactant served as the energy component of each bond in the reactant, while the heat of the product served as the energy of the product.

Step 1:

The heat of the reactant has been given as:

Reactant molecules: CH[tex]_{3}[/tex]OH and C≡O

ΔH[tex]_{reactant}[/tex] = 3 x C-H + C-O + O-H + C≡O

ΔH[tex]_{reactant}[/tex] = 3 x 413 +358 +465 + 1070 kJ/mol

ΔH[tex]_{reactant}[/tex] = 3134 kJ/mol

Step 2:

The heat of the product has been given as:

Product molecule: CH[tex]_{3}[/tex]COOH

ΔH[tex]_{product}[/tex] = 3 x C-H + C-O + O-H + C-C + C=O

ΔH[tex]_{product}[/tex] = 3 x 413 + 358 + 467 + 347 + 745 kJ/mol

ΔH[tex]_{product}[/tex] = 3156 kJ/mol

Step 3:

The heat of reaction has been given as:

ΔH = ΔH[tex]_{reactant}[/tex] - ΔH[tex]_{product}[/tex]

ΔH = 3134 - 3156 kJ/mol

ΔH = -22 kJ/mol

NOTE: Your question is incomplete, but most probably your full question was that an important industrial route to extremely pure acetic acid is the reaction of methanol with carbon monoxide. Use bond energies to calculate the heat of the reaction. Is the reaction exothermic or endothermic?

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The K+ channel uses the energy in ATP hydrolysis to remove the hydration shell from the K+ion

All of this truly implies is that one of these bonds breaks in a hydrolysis process (a water-mediated breakdown reaction), releasing a sizable amount of energy.

The following reaction results in the hydrolysis of ATP to ADP:

ATP+H2O⇋ADP+Pi+energy

The hydrolysis of ATP to ADP is reversible, like the majority of chemical processes.

Energy is needed for the reverse process, which creates ATP from ADP and Pitext P iPi start subscript, P, end subscript, start subscript, I end subscript.

Because cells frequently use (hydrolyze) ATP molecules and depend on constant production of replacement ATP, ATP regeneration is crucial1^1.

Hence the  K+ channel uses the energy in ATP hydrolysis to remove the hydration shell from the K+ion

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Water is a liquid while hydrogen sulphide is a gas because the hydrogen bonding in water causes the water molecules to be associated with each other due to intermolecular forces of attraction.