The electric field just outside the inner shell has magnitude E1, and the electric field just inside the outer shell has magnitude E2, True for the magnitude E of the electric field at point P is The correct answer is (b) i.e. E1 > E > E2
Since the shells are conducting and the space between them is filled with air, the electric field must be perpendicular to the surface of the shells at all points. This means that the equipotential lines as assumed must be perpendicular to the shells as well. At point P, the equipotential lines are closer together than they are at the outer shell, but farther apart than they are at the inner shell. This means that the electric field at point P must have a magnitude that is between E1 and E2, but closer to E1 than to E2. Therefore, the correct answer is (b) E1 > E > E2. The term "electric field" refers to the physical field that surrounds electrically charged particles and acts to either attract or repel all other charged particles in the field (also known as an E-field). It can also refer to the physical field surrounding a system of charged particles. Electric fields are composed of electric charges and time-varying electric currents. Both electric and magnetic fields are manifestations of the electromagnetic field, one of the four fundamental interactions of nature.
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determine the displacement of a plate of length l pinned at its ends with a concentrated load vs applied at its center. This problem is illustrated in Figure 3–9.
The radius of gyration will be k = (h2/12)1/2 , or k2 = h2/12.
What is radius?
The radius of a circle is the distance a circle's center from any point along its perimeter. Usually, "R" or "r" is used to indicate it.
What is displacement ?
The term "displacement" describes the shortest path an object takes to travel from one spot to another. It is understood to be the modification of the object's position, to put it simply. Its magnitude and direction make it a vector quantity.
Radius of Gyration is given by, k = (I/M)1/2; Where I = Moment of Inertia of the body and M is its mass.
Now, for a plate of rectangular cross-section of height h and width b, the area moment of inertial about horizontal midline is given by, I = Mh2/12 .
Hence, the radius of gyration will be k = (h2/12)1/2 , or k2 = h2/12.
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a 345 pf capacitor is charged to 145 v and then quickly connected to a 165 mh inductor. frequency of oscillation
A 165 mh inductor was attached right after that. The frequency of the oscillation is f=7957.74 Hz.
What is motion-induced oscillation?Periodic or oscillatory motion is defined as a motion that repeats itself. A restoring force or torque causes the object in this motion to oscillate about its equilibrium position.
For Class 8, what is an oscillation?Oscillation is a revolving motion between two states or locations. The side-to-side swing of a pendulum or the up-and-down motion of a spring with a weight are two examples of periodic motions that repeat themselves in a regular cycle and are considered oscillations.
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spine in this situation. we will model the spine and upper body as a horizontal rigid rod of uniform density with a length of 50.0 cm and a mass of 40.0 kg. assume that the person attempts to lift an object with their arms, which we will model as attached at the far end of the rod. support of the back in this position is provided primarily by the erector spinalis muscle which we will model as being attached at one end to the spine at a point 33.0 cm from the hip at an angle of 10 degrees; the other end of the muscle is attached to the lower body below the hip.
The amount of tension in the back muscle is 3270 N.
Mass of object = 18.2 Kg
Mass of person = 40 Kg
Length = r = 0.5 m
Length at the spine at required position = r' = 0.33 m
Angle = θ = 10 degrees
Tension is defined as the force transmitted through a rope, string or wire when pulled by forces acting from opposite sides. The tension force is directed over the length of the wire and pulls energy equally on the bodies at the ends. Every physical object which is in contact exerts some force on one another.
Torque = Tension = T =
= T = r'sin10 -rmgsin90
= T = (0.5 X 40 X 9.8) / (0.33 X 0.1736)
= T = 3270 N
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The complete question:
We will model the spine and upper body as a horizontal rigid rod or uniform density with a length of 50.0 cm and a mass of 40.0 kg. Assume that the person attempts to lift an object with their arms, which we will model as attached at the far end of the rod. Support of the back in this position is provided primarily by the erector spinalis muscle which we will model as being attached at one end to the spine at a point 33.0 cm from the hip at an angle of 10 degrees; the other end of the muscle is attached to the lower body below the hip. The object being lifted has a mass of 18.2 kg. Calculate the tension , in the back muscle for this scenario.
An astronaut's pack weighs 19.0 N when she is on earth but only 3.84 N when she is at the surface of moon. Part A What is the acceleration due to gravity on this moon? Express your answer with the appropriate units.
The weight of an astronaut's pack is 19.0 N on earth and 3.84 N on moon. The acceleration due to gravity on the moon is 1.98 m/s²
According to the Newton's second law of motion, the relation between force acted on an object with its acceleration is given by:
F = ma
Where:
F = force acted on the object
m = mass
a = acceleration
Weight is another name for the force due to gravity. If an object is brought from the earth to the moon, its weight will be different because the gravitational accelerations are different. However, its mass remains the same.
m = F / a
In case a = g = acceleration due to gravity:
m = w/g
Let
g = acceleration due to gravity on the earth = 9.8 m/s²
g₂ = acceleration due to gravity on the moon.
Hence,
19/g = 3.84/ g₂
g₂ = 3.84/19 x 9.8 = 1.98 m/s²
Hence, the acceleration due to gravity on the moon is 1.98 m/s²
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the gravitational constant g was first measured accurately by henry cavendish in 1798. he used an exquisitely sensitive balance to measure the force between two lead spheres whose centers were 0.19 m apart. one of the spheres had a mass of 138 kg, while the mass of the other sphere was 0.93 kg.
The answer is
3.5*10^-8:1
Explanation:
F(gravitation) = G*M1M2/r^2
G = gravitational constant = 6.67*10^-11 Nm^2/kg^2
M1 = mass of the heavier sphere,
M2 = mass of the lighter sphere
r = their distance apart
Fg = 6.67*10^-11*188*0.93/(0.19)^2
Fg = 3.23*10^-7N
The ratio of the force of gravitation between them to the weight of the lighter sphere = 3.23*10^-7: (0.93*9.81) = 3.5*10^-8. : 1 by dividing both side by (0.93*9.81)
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difference between constant and
variable work
Work done on an object by a constant force is known as Constant Work, whereas the work done on an object by variable force is known as Variable Work.
In constant work or work done by constant force, the magnitude and direction of the force are constant or they do not change. Therefore, constant work is simply calculated by force acting on the object multiplied by displacement of the object.
But in case of variable work, things are not so easy. In this scenario, the force's magnitude and direction may alter at any point while the job is being done. The majority of the work we do on a daily basis is an instance of variable force work. The same calculation involves integration and is fairly difficult.
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a toroid has a 50.8 cm inner diameter and a 53.7 cm outer diameter. it carries a 24.7 a current in its 604 coils.(figure 1) (figure 2). Determine the range of values for B inside the toroid. There should be two values, B(min) and B(max), in mT.
The range of values for B inside the toroid is: B(min) = 1.37 mT and B(max) = 3.37 mT
The range of values for B inside the toroid can be determined using the formula B = μ0nI/l, where μ0 is the permeability of free space, n is the number of turns, I is the current, and l is the average length of the toroid. The average length of the toroid is equal to the average diameter, which is (50.8 cm + 53.7 cm)/2 = 52.25 cm. Therefore, B = μ0nI/l = (4π×10^-7 H/m)(604 turns)(24.7 A)/(52.25 cm) = 0.0022 H/m. Since 1 mT = 10^-3 T, the range of values for B inside the toroid is 1.37 mT (B(min)) and 3.37 mT (B(max)).
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A uniform, rigid, thin board that is 2.4m long and weighs 200N is attached to a post by a pivot at point P and hangs over the edge of a building. A crate weighing 400N is attached to the right end of the board. The left end of the board, .8m from the pivot, is attached to a light vertical wire anchored at the other end to keep the board from rotating.
1. Draw and label vectors on a horizontal board to represent forces acting on the board (not components). Show each force vector originating at its point of application.
2. Calculate the magnitudes of the forces exerted on the board by the post and by the wire. If you need to draw anything other than what you have shown in part 1 to assist in your solution, use the space below. Do not add anything to the figure in part 1
3. The rotational inertia of the board alone about its center is (1/12)Ml2 , where M is the mass of the board and L is its length. Calculate the rotational inertia of the combined board-crate system about point P
4. Suppose that the wire breaks and the board begins to pivot about point P. Calculate each of the following
(a) The magnitude of the initial angular acceleration of the board-crate system.
(b) The magnitude of the initial linear acceleration of the left end of the board.
1. Diagram (Attached above)
2. By equilibrium of forces of vertical direction,
T + Wa +Wc = Rp
T + 200 + 400 = Rp
Rp - P = 600N ------------------(i)
Taking moment of forces about P (Clockwise positive),
Wb * 0.4m + Wc * (0.4 + 1.2m) – T * 0.8m = 0
200 * 0.4 + 400 * 1.6 – 0.8T = 0
0.8T = 80 + 640
T = 900N
Putting T in equation (i),
Rp - 900= 600
Rp = 1500N
So, Rp= 1500N, T = 900N, Wb = 200N, Wc = 400N
3. Moment of inertia about C.O.M. ‘O’ is Icom= 1/12 ML2
Moment of inertia about ‘P’ by parallel axis theorem
Ip = Icom + M * (OP)2
Ip= 1/12 ML2+ M * (0.4)2
For net MOI about P, mass of crate Mc at distance PC from P will also be taken in account.
Mc = 400 / 9.8 = 40.8Kg, PC = 1.6m
Mass of board M = 200/9.8 = 20.4 Kg
Length of board L = 2.4m
So, Net M.O.I. about P,
Ip net = Icom + M*(0.4)2 + Mc * (PC)2
Ip net= 1/12 * 20.4*(2.4)2 + 20.4*(0.4)2+ 40.8*(1.6)2
Ip net = 117.5 Kg m2
4.
a. As, the moment of inertia about point P, Ip net =117.5 Kg m2
Torque experienced when wire is cut
τ = Wb * 0.4 + Wb * (0.4 + 1.2)
τ = 200 * 0.4 + 400 *1.6
τ = 720 N-m
As τ = I α, where α is angular acceleration.
720 = 117.5 * α
α = 6.127 rad / s2
So, magnitude of initial angular acceleration is α = 6.127 rad / s2
b. Initial Acceleration (linear) of left most point A
aA = α * AP
aA= 6.127 * 0.8
aA= 4.9 m/s2
So, linear acceleration of point A is 4.9 m/s2
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The pressure of water vapor over ice is 3.88 mm Hg at – 2C and 4.58 mm Hg at 0 C. Estimate in J mol^(-1) the heat of vaporization of ice at -1 C.
The heat of vaporization of ice at -1°C is equal to 1.02 ×10⁵J/mol
What is the heat of vaporization?The Heat of Vaporization can be defined as the amount of heat that requires to be absorbed to vaporize a certain amount of liquid at a given temperature.
We know that the Clausius Clapeyron equation can be written as:
[tex]\displaystyle lln\frac{P_2}{P_1} =\frac{-\triangle H}{R}(\frac{T_1-T_2}{T_1T_2} )[/tex]
Given the initial pressure of water, P₁ = 3.88 mm Hg
The final pressure of the water, P₂ = 4.58 mm Hg
The initial temperature, T₁= - 1°C = 272 K
The final pressure of water, T₂ = 0°C = 273 K
[tex]\displaystyle ln\frac{4.58}{3.88} =\frac{-\triangle H}{8.314}(\frac{272-273}{272\times 273} )[/tex]
ΔH = 1.02 × 10⁵J/mol
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Unpolarized light of Intensity Io is incident on a pair of (ideal) polarizers, as shown below. The direction of polarization of the first polarizer is vertical. The second polarizer has unknown orientation.For each part below, determine whether it is possible for the light that reaches the observer to have the given value of intensity.If so: Determine the direction of polarization of the second polarizer. Show all work.If not: Explain by not.a. No light reaches the observerb. Light of intensity (2*Io)/3 reaches the observer.c. Light of intesity Io/2 reaches the observer.d. Light of intensity Io/4 reaches the observer.
The un polarization of light at each state was explained and second polarizer is I2=I1=Io/2 and first polarizer is I2=Io/4=Io/2 cos^(q).
What is polarization?
Polarized light waves are defined as those light waves that only travel in one plane. The polarization of light is the process by which unpolarized light waves are converted to polarized light waves.
What is un polarization ?
Unpolarized light is a form of electromagnetic radiation that vibrates in more than one plane. Unpolarized light is the kind that comes from the sun, a desk lamp, or a candle flame.
a) When the pass axis of the two polarizers are perpendicular to each other.
b) Not possible, because after first polarizer intensity becomes Io/2.
from malus law after second polarizer I2=I1 cos^2(q)
I2=2Io/3, cos^2(q)=4/3, q=cos^-1(1.15) Which does not exist.
c) When the pass axis of the second polarizer is parallel to first i.e q=0
I2=I1=Io/2.
d) I2=Io/4=Io/2 cos^(q)
cos^(q)=1/2, q=45 degree w.r.t pass axis of the first polarizer.
Therefore, the un polarization of light at each state was explained and second polarizer is I2=I1=Io/2 and first polarizer is I2=Io/4=Io/2 cos^(q).
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The gauge pressure in a helium gas cylinder is initially 27atm . After many balloons have been blown up, the gauge pressure has decreased to 5atm .
One atm less than the absolute pressure is present in the gauge pressure. It is the variance between the absolute pressure inside the tank and the pressure outside. Therefor, the ratio is 0.185.
It is positive for pressures above atmospheric pressure and negative for pressures below atmospheric pressure; gauge pressure is the pressure as compared to atmospheric pressure. Any fluid that is not contained has its pressure increased by the atmospheric pressure. The pressure that exists inside the Earth's atmosphere is known as atmospheric pressure, also spelled barometric pressure (after the barometer). 101,325 Pa is the definition of the standard atmosphere, which is represented by the sign atm (1,013.25 hPa).
5/27 = 0.185 atm is the pressure ratio.
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when there is a net force exerted on an object, the magnitude of the acceleration of the object is [a] proportional to the magnitude of the net force
When there is a net force exerted on an object, the magnitude of the acceleration of the object is proportional to the magnitude of the net force and has a magnitude that is inversely proportional to the mass.--The statement is true.
Newton's second law of motion states that the acceleration of an object depends upon two variables i.e the net force which is acting upon the object and the mass of the object. The acceleration of an object is dependent directly upon the net force which is acting upon the object, and inversely upon the mass of the object. If the force acting upon an object is increased, the acceleration of the object is increased. If the mass of an object is increased, the acceleration of the object is decreased.
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The complete question is:
State whether a given statement is True or False.
When a net external force acts on an object of mass m, the acceleration that results is directly proportional to the net force and has a magnitude that is inversely proportional to the mass.
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Mary weighs 525 N and she walks down a flight of stairs to a level 6.5 m below her starting point. What is the change in Mary’s potential energy? Answer in units of J.
The change in Mary’s potential energy is 3412.5 Joule.
What is potential energy?
Potential energy is a form of stored energy that is dependent on the relationship between different system components. If a steel ball is raised above the ground as opposed to falling to the ground, it has more potential energy. It is capable of performing more work when raised.
Given that: Mary weighs 525 N and she walks down a flight of stairs to a level 6.5 m below her starting point.
Hence, change in potential energy is = weight × change in height
= 525 N × 6.5 m
= 3412.5 Joule.
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How can a dilute solution of salt in water be made more concentrated?
Answer:
Heating it
Explanation:
Helps the salt dissolve faster and is more effective when heated up :)
The answer is A. by heating it
(Figure 1) shows a thin liquid film bounded on the right side by a sliding wire that is attached to a spring with spring constant 0.50 N/m. The spring is stretched by 1.4 cm. Figure 1 of 1 < > 0.50 N/m 6.0 cm Mai W Part A What is the liquid's surface tension in mN/m? Express your answer in millinewtons per meter. || ΑΣφ ? 7= mN/m
The liquid's surface tension in mN/m is 58.33.
Surface tension is the tendency of the surface of a liquid at rest to contract into the smallest possible surface area. Surface tension allows objects denser than water, such as razor blades and insects, to float on the surface without being partially submerged.
Given:
Spring constant of the spring = k = 0.5 N/m
Distance by which the string is stretched = d = 1.4 cm = 0.014 m
Force of the spring on the wire = Fs
Fs = kd
Surface tension of the liquid = γ
Length of the sliding wire = L = 6 cm = 0.06 m
Surface tension force of the liquid on the wire = Ft
A liquid film has 2 surfaces therefore,
Ft = 2γL
The force of the spring on the wire and the surface tension force on the wire will be equal.
Fs = Ft
kd = 2γL
(0.5)(0.014) = 2γ(0.06)
0.007 = 0.12γ
γ = 0.05833 N/m
Converting the surface tension from Newton per meter to milli-Newton per meter, (1 N = 103 mN)
γ = (0.05833) x (103) mN/m
γ = 58.33 mN/m
Surface tension of the liquid = 58.33 mN/m
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in fig. 12-30, trying to get his car out of mud, a man ties one end of a rope around the front bumper and the other end tightly around a utility pole 18 m away. he then pushes sideways on the rope at its midpoint with a force of 550 n, displacing the center of the rope 0.30 m, but the car barely moves.what is the magnitude of the force on the car from the rope? (the rope stretches somewhat.)
The force on the car from the rope is 27496N.
The sum of forces in y direction is zero.
F = Tsinθ - Tsinθ =0
F - 2T SINθ = 0
T = F/2sinθ
Tan θ = .28/18 = 0.015
θ = [tex]tan^{-1}[/tex] 0.015 = 0.8593
T = 550 / 2sin (0.8593)
T = 27500 N
Fcar = Tcosθ
Fcar = Tcos[0.8593]
Fcar = 27496N
All the planets are maintained in their orbits around the sun by the force of gravity. Many of the large-scale structures in the Universe are caused by gravity because the gravitational attraction between the original gaseous stuff in the Universe allowed it to combine and form stars, which then condensed into galaxies. Although the reach of gravity is limitless, its effects diminish with increasing distance.
The general theory of relativity, which Albert Einstein proposed in 1915, is the theory that most accurately describes gravity. According to this theory, gravity is not a force but rather the curvature of spacetime brought on by an imbalance in the distribution of mass, which causes masses to move along geodesic arcs.
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For each of the following, create a DFA that recognizes exactly the language given. (a) [5 points) Binary strings with at least two ls. (b) [5 points) Binary strings that have at least one 1 and an even number of Os. (c) [5 points) Binary strings such that none of their runs of ls have odd length. A run of ls is a substring consisting of all 1s (i.e. "11..-1") that is either at the beginning of the string, or at the end of the string, or in the middle of the string, surrounded by Os. For example, the following strings are included in the language: "11","110","00001111", and "011001111011". But the following strings are not included in the language because they all contain at least one run of ls with odd length: "111", "010", and "00110111".
A binary string is a sequence of bytes. Unlike strings, which typically contain textual data, binary strings are used to contain non-traditional data such as images. The answer is in Images.
Binary string length is the number of bytes in the sequence. Binary strings have a CCSID of 65535. A binary string is a series of bytes. Unlike strings which usually contain text data binary strings are used to store data such as image sounds and mixed media.
A binary string is a series of octets. Binary strings are divided into two types of strings. First, binary strings specifically allow the storage of zero-valued octets and other non-printable octets. Each character in the string is defined by a number and that number is encoded in binary like an int. Contains a zero terminator.
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which of the following is not a strong argument for the theory that some large elliptical galaxies formed as the result of galaxy collisions?
The majority of galaxies in the universe are elliptical galaxies, and galaxy collisions are frequent.
Mergers produce large elliptical galaxies. There is proof that galaxies develop through mergers and collisions. Star formation is triggered by galaxic collisions. All of the gas is transformed into stars before a disc can develop because the higher gas density produces stars more quickly. High redshift elliptical galaxies lack young, blue stars. Old red stars with erratic orbits in several planes are abundant in elliptical galaxies, which have a small amount of gas and dust. The largest galaxies that we are currently aware of are enormous elliptical galaxies. The majority of galaxies found now are small elliptical galaxies. Elliptical galaxies often have very little cold gas.
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complete question: Which of the following is not a strong argument for the theory that some large elliptical galaxies formed as the result of galaxy collisions?
A) Elliptical galaxies dominate the population in dense galaxy clusters.
B) Some ellipticals have stars and gas that rotate opposite to the rest of the galaxy.
C) Some elliptical galaxies are surrounded by shells of stars.
D) Computer simulations predict that the product of a galaxy collision is generally an elliptical galaxy.
E) Galaxy collisions are common and most galaxies in the universe are elliptical.
a soccer player kicks a soccer ball of mass 0.45 kg that is initially at rest. the player's foot is in contact with the ball for 1.90 * 10^-3 s, and the force of the kick is given by f(t)
We set the derivative of F with respect to time equal to zero and solve for t since J=F avg t. The outcome is t=1.5103 s. It is clear that the force, F(t), reaches its maximum at t=0.0015s, with Fmax equal to 4500N.
How do you determine the force required to kick a ball?The formula Force (F) = Mass (M) x Acceleration (A), where the units are F (Newton) = Mass (kg) x Acceleration (m/s2), is used to determine the force of a kick.
What are the forces at work while kicking a soccer ball?The force exerted by the foot on the football during a kick is referred to as the action force. On the other side, the response force is the pressure the ball places on the foot. Because the action force and reaction force are of equal magnitude, no force is stronger than the other.
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Why do we think that Venus has so much more atmospheric gas than Earth?
Most of the gases that have been released from volcanoes on Earth later returned to the surface.
Venus has gained much more gas through outgassing than has Earth.
Earth has lost much more gas to thermal escape than has Venus.
Because of its lack of magnetic field, Venus has been able to gain gas through the impacts of solar wind particles, while Earth has not gained gas in this way.
We think Venus has more atmospheric gas than Earth because of its lack of magnetic field, Venus has been able to gain gas through the impacts of solar wind particles, while Earth has not gained gas in this way.
Venus's densest atmosphere of the four terrestrial planets consists of 96% carbon dioxide. Venus's surface atmospheric pressure is 92 times greater than Earth's. With an average surface temperature of 735 K (462 °C; 863 °F), Venus is the hottest planet in the Solar System. The planet has no carbon cycle that captures carbon in rocks and surface features, and no organic life that can sequester carbon in the form of biomass.
Venus may have had oceans, but those oceans are evaporating due to increasing temperatures caused by the continuous greenhouse effect. Much of the water may have photodissociated, and the solar wind has sent free hydrogen rage into space as a result of the lack of an internal magnetic field on Venus. The surface of Venus itself is deserted, dry, and punctuated with rock that is periodically renewed by volcanic activity.
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two wires cross at a 400 without electrical contact. find the magnitude and direction of the magnetic field at point p. point p is 10 cm from the wire intersection and equally distant from both wires.
Both wire carrying current in same direction with the same magnitude A current-carrying wire produces a magnetic field and the Bio-Savart law enables us to calculate the magnitude and direction of this magnetic field. at any point where the magnetic field due to the segment of current-carrying wire is given by equation
[tex]B=\frac{\mu_0}{2 \pi} \frac{l}{r}[/tex]
where r is the distance between the wire and the point and I is the current of the wire. At point , the distance between it and the intersection is . So, its distance from the horizontal wire is B
[tex]r_1=(4 \mathrm{~cm}) \sin 75^{\circ}=3.86 \mathrm{~cm}[/tex]
This the same distance from the second wire as we are given
[tex]r_1=r_2=3.86 \mathrm{~cm}[/tex]
if we apply the right-hand rule, we find that the magnetic field at point of each wire has direction out of the magnetic field at point is the summation of both magnetic fields
[tex]B_1=\frac{\mu_0}{2 \pi} \frac{1}{r_2}+\frac{\mu_0}{2 \pi} \frac{1}{r_2}=2\left(\frac{\mu_0}{2 \pi} \frac{1}{r_1}\right) \text { (2) }[/tex]
Now, we can use the values for to get the magnetic field at point by
[tex]B_1 & =2\left(\frac{\mu_0}{2 \pi} \frac{1}{r_1}\right) \\& =2\left(\frac{\left(4 \pi \times 10^{-7} T \cdot m / A\right)(5 \mathrm{~A})}{2 \pi\left(3.86 \times 10^{-2} \mathrm{~m}\right)}\right) \\& =5.2 \times 10^{-5} \mathrm{~T}\end{aligned}[/tex]
At point , the horizontal while applies a magnetic field with direction out of the page while the other wire applies a magnetic feild with direction into . As both wires exert the same magnetic field at point is zero
At point , the horizontal while applies a magnetic field with direction out of the page while the other wire applies a magnetic feild with direction into the page. As both wires exert the same magnetic field at point is zero.
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I have got the answers to these question but I need to find the working out pls if you are able to answer at least one please do
calm :), thanks mods
If 1 cm on the globe represents 555 km in the real world, how many kilometers would you have traveled in 16.8 cm? (round)
9324 km
On travelling 16.8 cm, the distance travelled in kilometres is 9324 kilometres.
As per the known fact, the ratio of map distance will be equal. So, we will write the two ratio and equate it. Let us assume the distance travelled in 16.8 cm be x. Representing the information of equation form -
1 : 555 = 16.8 : x
x = 16.8 × 555
Performing multiplication on Right Hand Side of the equation to find the value of x (Denominator of 1 can be ignored)
x = 9324 kilometres
Thus, the distance travelled in 9324 kilometres.
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What is the average speed of the dog if it’s goes 40 meter in 8 second
Consider the broadcasting circuit for an AM radio station which broadcasts at a frequency of 1400 kHz. The free electrons in such a circuit are moving back and forth in simple harmonic motion. (a) How long does it take for the free electrons in this circuit to go back and forth once? Give your answer in microseconds. μs (b) Assuming the average speed of the free electrons is 100 μm/s, what is the range of motion of the electrons as they go back and forth in the wires of the circuit. (HINT: As a free electron goes back and forth, it travels its full range every half cycle.) Give your answer in nanometers. nm (c) What is the wavelength of the electromagnetic radio waves emitted by this broadcasting circuit? Give your answer in meters. m
a) Time period is given by 0.751 b) Displacement is 0.0751 nm c) The wavelength of the electromagnetic radio waves emitted is 225.56 m
T = 1/f
T = 1/(1330*10^3 Hz)
T = 751.88 ns
Time period T = 0.751 us
b) displacement is given by:
x = velocity * Time
x = 100*10^-6 m/sec*0.751*10^-6 sec
x = 0.0751 nm
c) lambda = c/f
lambda = 3*10^8/(1330*10^3 Hz)
lambda = 225.56 m
Displacement, commonly known as length or distance and denoted by the letters d or s, is a one-dimensional variable that represents the separation between two defined points. In the International System of Units (SI), the meter is the common unit of displacement (m). Transferring unfavorable emotions from one thing or person to another is referred to as displacement and is a defensive tactic. To "take out" their rage on a family member, for instance, a person can yell at them if they are upset with their job. Replace, supersede, and supplant are some frequent alternatives to the word "displace."
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In shape and component stars, elliptical galaxies are most like our own
A. galactic center
B. spiral arms
C. nuclear bulge
D. halo
E. companions, the Magellanic Clouds
d
The correct option is D : Halo , In comparison to spiral galaxies, elliptical galaxies seem smooth, ellipsoidal, or spherical and have far less structure. Galaxy clusters are generally home to elliptical galaxies.
There are stars, planets, interstellar dust, and gases in elliptical, spiral, and irregular galaxies alike. The same gravitational forces that create other galaxies also create these three different sorts of galaxies.
Old stars, a tiny amount of gas, and dust can be found in elliptical galaxies. In contrast to open clusters, stars in these galaxies coalesce into globular clusters. Individual stars, nebula, and clusters are visible in some irregular galaxies but are invisible in other irregular galaxies.
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An object attached to one end of a string moves in a circle at constant speed. Which of the following is correct?
the object is accelerating as it moves
the object's velocity is the same as its speed
the object does not require a force to keep its state of circular motion
if the string breaks, the object will keep its circular motion
If the string breaks, the object will move Radially away from the center of the cicl
The object is accelerating as it moves in a circle at constant speed. This is because acceleration is a measure of how an object's velocity changes over time, and the velocity of an object moving in a circle is constantly changing direction.
The object's velocity is not the same as its speed. Speed is a scalar quantity that refers to the distance an object travels per unit of time, while velocity is a vector quantity that refers to the speed and direction of an object's motion. The velocity of an object moving in a circle will vary as the object moves around the circle, even if its speed remains constant.
An object moving in a circle does require a force to keep its state of circular motion. This force is known as the centripetal force, and it is directed towards the center of the circle. The centripetal force is necessary to keep the object moving in a circular path, rather than following a straight-line path.
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10 rooster head questions
Answer:
How does a rooster's head differ from that of a hen?What is the function of a rooster's crest on its head?Can a rooster's head and neck change color during mating season?How does a rooster use its head and beak during courtship displays?How does a rooster use its head to establish dominance in a flock?Can a rooster's head and beak be used as a weapon against predators?How does a rooster's head and beak help it to find food?How does a rooster's head and beak help it to eat and digest food?Can a rooster's head and beak be used for vocalizations, such as crowing?What are some common health issues that can affect a rooster's head and beak?Here are ten questions about the story entitled "cabeza de gallo":
Who are the main characters in the play?What is the central theme of the story?What kind of narrator tells the story?What was the rooster game about?Where is the place where most of the story takes place?Were the protagonist's predictions correct?What holiday was being celebrated?Which were knocked down as creatures struck in the abdomen?Who is the author of the work?What lesson or message does the story convey?¿What is a tale?A story is a narration, either oral or written, about a story that may have happened in real life, or is the product of the author's imagination.
The stories have the characteristic of having few characters, and are shorter than any common text.
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A 150-kg electromagnet is at rest and is holding 100 kg of scrap steel when the current is turned off dropping the steel. - 2- Knowing that the cable and the supporting crane have a total stiffness equivalent to a spring of constant k 60 kN/m and a damper c = 300 Ns/m, determine (a) the frequency of oscillation (b) the maximum upward displacement І В
The frequency of the oscillation is determined to be 0.123 Hz.
The number of waves passing through a fixed point in unit time is said to be frequency.
Given that, Mass of the scrap steel = 100 kg
Spring constant k = 60 kN/m
The formula for time period is as follows,
T = 2π √(m/k)
And the relation between time period and frequency is, T = 1/f
f = 1 / [2π √(m/k)] = 1/ [ 2π √(100/60) = 1/ [ 2π * 1.29] = 1/8.105 = 0.123 Hz
Thus, the frequency of oscillation is 0.123 Hz.
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Two pipes of identical diameter and material are connected in parallel. The length of pipe A is three times the length of pipe B. Assuming the flow is fully turbulent in both pipes and thus the friction factor is independent of the Reynolds number and disregarding minor losses, determine the ratio of the flow rates in the two pipes.
According to the question the ratio of the flow rates in the two pipes is [tex]\sqrt{3}[/tex] /1
What in physics is flow?Fluid Flow, a branch of fluid dynamics, is concerned with fluids. It involves the movement of a fluid under the influence of uneven forces. As soon as unbalanced pressures are applied, this motion will persist.
Briefing:Lets take
Length of pipe B = L
Length of pipe A = 3 L
Discharge in pipe A = Q₁
Discharge in pipe B = Q₂
[tex]h_{f}[/tex] = (FLQ²)/12.1.[tex]d^{5}[/tex]
F=Friction factor, Q=Discharge,L=length
d=Diameter of pipe
here all only Q and L is varying and all other quantity is constant
So we can say that
LQ²= Constant
L₁Q₁²=L₂Q²₂
By putting the values
3LQ₁²=LQ²₂
Therefore
[tex]Q_{1}[/tex]/ [tex]Q_{2}[/tex] =[tex]\sqrt{3}[/tex]/ 1
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