The expected value of a fair 6-sided die is 3.5.
Which of the following statements are true?
Choose all answers that apply:
А
3.5 is one of the possible outcomes of rolling a fair 6-sided die.
A fair 6-sided die is more likely to land on the number 4 than the number 6.
If you rolled a fair 6-sided die a large number of times, you should expect the average of the
numbers rolled to be about 3.5.

Answers

Answer 1

Answer: if you roll a fair 6 sided for a large number of times the average would be 3.5

Step-by-step explanation:

Khan


Related Questions

If a =5 and b=3 what is the value of the 2a-3b+3a

Answers

Answer:

If a = 5 and b = 3, then that means 2a - 3b + 3a = 16

Step-by-step explanation:

2a - 3b + 3a

(2×5) - (3×3) + (3×5)

10 - 9 + 15 = 16

Leroy wants to teach his puppy 6 new tricks. In how many different orders can the puppy learn the tricks?​

Answers

Answer: 720 ways

Step-by-step explanation:

Given

Leroy wants to teach his puppy 6 new tricks

Considering each trick is different from other

The first trick can be taught in 6 different ways

After learning the first trick, there are 5 tricks remaining which can be taught in 5 different ways

Similarly, for the remaining tricks, it is 4, 3, 2, and 1 way

So, the total number of ways is [tex]6\times 5\times 4\times 3\times 2\times 1=720\ \text{Ways}[/tex]

Simplify the expression using order of operation 5 x 2 + 3 to the power of 2

Answers

answer= 1

5 x 2 - 3^2

1. First simplify exponents

= that is nine

2. Then Do 5 x 2- 9

5 x 2=10

10-9

= 1

You go to the doctor and he gives you 11 milligrams of radioactive dye. After 12 minutes, 7.75 milligrams of dye remain in your system. To leave the doctor's office, you must pass through a radiation detector without sounding the alarm. If the detector will sound the alarm if more than 2 milligrams of the dye are in your system, how long will your visit to the doctor take, assuming you were given the dye as soon as you arrived

Answers

Answer:

In (16.8+12=) 28.8 minutes the person will be left only with 2mg of dye in the body and be able to leave the doctor's office after being injected with 11 mg

Step-by-step explanation:

After 12 minutes, 7.75 milligrams of dye remain in your system.

This means that 11- 7.75= 3.25 milligrams of dye are used up in 12 minutes

7.75-2= 5.75 milligrams still needs to be used up

         Dye           Minutes

         3.25             12

          5.75             x

x= 12*5.75/3.25

x= 16.8 minutes

5.75 mg will be used up in 16.8 minutes

In (16.8+12=) 28.8 minutes the person will be left only with 2mg of dye in the body and be able to leave the doctor's office.

PLEASE HELP WITH THIS ASPA 3/8 divided by-3/5

Answers

Answer:

Step-by-step explanation:

No random links or answers, please.

Answers

Answer:

the ans is 21 hope it may help u

Step-by-step explanation:

g = 6

x=6

x= 3x + 3

x = 3 × 6 +3

x = 18 + 3

x= 21

A complex electronic system is built with a certain number of backup components in its subsystems. One subsystem has eight identical components, each with a probability of 0.1 of failing in less than 1,000 hours. The sub system will operate if any four of the eight components are operating. Assume that the components operate independently. Find the probability that
a. exactly two of the four components last longer than 1000 hours.
b. the subsystem operates longer than 1000 hours.

Answers

Answer:

a) 0.0486 = 4.86% probability that exactly two of the four components last longer than 1000 hours.

b) 0.9996 = 99.96% probability that the subsystem operates longer than 1000 hours.

Step-by-step explanation:

For each component, there are only two possible outcomes. Either they last more than 1,000 hours, or they do not. Components operate independently, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

One subsystem has eight identical components, each with a probability of 0.1 of failing in less than 1,000 hours.

So 1 - 0.1 = 0.9 probability of working for more, which means that [tex]p = 0.9[/tex]

a. exactly two of the four components last longer than 1000 hours.

This is P(X = 2) when [tex]n = 4[/tex]. So

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 2) = C_{4,2}.(0.9)^{2}.(0.1)^{2} = 0.0486[/tex]

0.0486 = 4.86% probability that exactly two of the four components last longer than 1000 hours.

b. the subsystem operates longer than 1000 hours.

The subsystem has 8 components, which means that [tex]n = 8[/tex]

It will operate if at least 4 components are working correctly, so we want:

[tex]P(X \geq 4) = 1 - P(X < 4)[/tex]

In which

[tex]P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)[/tex]

So

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{8,0}.(0.9)^{0}.(0.1)^{8} \approx 0[/tex]

[tex]P(X = 1) = C_{8,1}.(0.9)^{1}.(0.1)^{7} \approx 0tex]

[tex]P(X = 2) = C_{8,2}.(0.9)^{2}.(0.1)^{6} \approx 0[/tex]

[tex]P(X = 3) = C_{8,3}.(0.9)^{3}.(0.1)^{5} = 0.0004[/tex]

Then

[tex]P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0 + 0 + 0 + 0.0004 = 0.0004[/tex]

[tex]P(X \geq 4) = 1 - P(X < 4) = 1 - 0.0004 = 0.9996[/tex]

0.9996 = 99.96% probability that the subsystem operates longer than 1000 hours.

Last year a farm produced 6.2 - 10^6soybeans and 7.8. 10^6 onions.
a.) What was the total number of vegetables produced by the farm last year?

Answers

Answer:

Yessir

Step-by-step explanation:

Two planes start from the same point and fly opposite directions. The first plane is flying 20 mph slower than the second plane in 2 h the planes are 540 mi apart. Find the rate of each plane

Answers

Answer:

This

Step-by-step explanation:

let x = rate of the slower plane (First plane!)

x+25 = rate of the faster plane (Second plane!)

The planes fly for 2 hours, where Distance = R*T

Distance between the planes = SUM of the distances.

R*T + R*T= 470 miles

2*x + 2*(x+25)=470

2x+2x + 50 = 470

4x+50=470

4x=420

x=105 mph First plane

x+25= 105+25=130 mph Second plane.

Answer:

4x+50=470

4x=420

x=105 mph First plane

x+25= 105+25=130 mph Second plane.

R^2

Step-by-step explanation:

What is the zero of function f?
f(x)=7^3Vx+12-12

Answers

Answer:

hope it helps ya.

please give me brainliest

A rectangle is graphed on a coordinate plane. The rectangle’s two lines of symmetry are the x-axis and the y-axis. Evie says that means the vertices are reflections of each other over the x-axis and y-axis. Is she correct? Explain your reasoning NO LINKS worth 50 points

Answers

Answer:

Can you add a picture if there are any?

Step-by-step explanation:

$500.00 at 4% for 5 years
50 points if you anwser asap​

Answers

Answer:

100

Step-by-step explanation:

it gives you the formula for simple interest

In triangle ABC, m
15
1353
25

Answers

The answer would be 15

Jim is twice as old as chin and four times as old as di.Their total ages altogether is equal to 84 years.Calculate jim's age

Answers

Answer:

48 years

Step-by-step explanation:

Let the ratio of their ages be

4:2:1

Sum up the numbers

4+2+1

= 7

Their total ages is 84

7/84

= 1/12

Therefore Jim age can be calculated as follows

= 12×4

= 48

Hence Jim is 48 years

please help this is very important i will give you brain thing if its correct and no links pwease <3

Answers

Answer:

the 2nd and 3rd one I believe

Which is the simplified form of the expression?

10n−13(9n−12)
7n + 4


7n – 4


3n + 4


3n – 12

Answers

Given:

Consider the given expression is:

[tex]10n-\dfrac{1}{3}(9n-12)[/tex]

To find:

The simplified form of the given expression.

Solution:

We have,

[tex]10n-\dfrac{1}{3}(9n-12)[/tex]

Using distributive property, it can be written as:

[tex]=10n-\dfrac{1}{3}(9n)-\dfrac{1}{3}(-12)[/tex]

[tex]=10n-3n+4[/tex]

[tex]=7n+4[/tex]

Therefore, the correct option is A.

I need helppppppppppp

Answers

Answer:

b.)36

Step-by-step explanation:

Formula for area of a trapezoid = [tex]\frac{a+b}{2} h[/tex]

where a and b = bases and h = height

The sign has the following dimensions

Base 1 = 6ft

base 2 = 12ft

height = 4ft

Using these dimensions we plug in the values into the formula

[tex]A=\frac{6+12}{2} 4\\6+12=18\\\frac{18}{2} =9\\9*4=36[/tex]

Hence the area of Mr. Wash's sign is 36 square feet.

Answer:

b) 36 sq ft.

Step-by-step explanation:

6 x 4 = 24 (multiply to find the square after splitting it)

12 - 6 = 6 x 4 = 24 / 2 = 12 (you divide by two because it's a triangle)

24 + 12 = 36

hope this helps :)

Simplify: x^1/3( x^1/2 + 2x^2)

Answers

Answer:

Step-by-step explanation:

x^1/3( x^1/2 + 2x^2)

x^(1/2 + 1/3) + 2x^(2 + 1/3)

x^(5/6) + 2x^(7/3)

What is the rule for the number pattern below ?950,800,650,500,350

Answers

Subtracts 150 each time—


950-150=800 and 800-150=650 and so on and so forth. The number sequence only includes 5 numbers so there is no way to tell if there is a tougher solution.

Angle Relationships

Determine the height of the triangle. Round to the nearest foot.

a. 12 ft
b. 14 ft
c. 10 ft
d. 18 ft

Please select the best answer from the choices provided

Answers

Answer:

B. 14 ft

Step-by-step explanation:

I calculated it logically

C: 10 ft


Calculated logically like the other person the 14 would not make sense here, if 25 fr is this long.

A filtration process removes a random proportion of particulates in water to which it is applied. Suppose that a sample of water is subjected to this process twice. Let x1 be the proportion of the particulates that are removed by the first pass. Let X2 be the proportion of what remains after the first pass that is removed by the second pass. Assume that X1 and X2 are independent random variables with common pdf. f(x) = 4x3, for 0 < x <1 and f(x) = 0 otherwise. Let Y be the proportion of the original particulates that remain in the sample after two passes. Then Y = (1 - X1)(1 - X2). Find E(Y).

Answers

Answer:

[tex]E(Y)=\frac{1}{25}[/tex]

Step-by-step explanation:

Let's start defining the random variables for this exercise :

[tex]X_{1}:[/tex] '' The proportion of the particulates that are removed by the first pass ''

[tex]X_{2}:[/tex] '' The proportion of what remains after the first pass that is removed by the second pass ''

[tex]Y:[/tex] '' The proportion of the original particulates that remain in the sample after two passes ''

We know the relation between the random variables :

[tex]Y=(1-X_{1})(1-X_{2})[/tex]

We also assume that [tex]X_{1}[/tex] and [tex]X_{2}[/tex] are independent random variables with common pdf.

The probability density function for both variables is [tex]f(x)=4x^{3}[/tex] for [tex]0<x<1[/tex] and [tex]f(x)=0[/tex] otherwise.

The first step to solve this exercise is to find the expected value for [tex]X_{1}[/tex] and [tex]X_{2}[/tex].

Because the variables have the same pdf we write :

[tex]E(X_{1})= E(X_{2})=E(X)[/tex]

Using the pdf to calculate the expected value we write :

[tex]E(X)=\int\limits^a_b {xf(x)} \, dx[/tex]

Where [tex]a=[/tex] ∞ and [tex]b=[/tex] - ∞ (because we integrate in the whole range of the random variable). In this case, we will integrate between [tex]0[/tex] and [tex]1[/tex] ⇒

Using the pdf we calculate the expected value :

[tex]E(X)=\int\limits^1_0 {x4x^{3}} \, dx=\int\limits^1_0 {4x^{4}} \, dx=\frac{4}{5}[/tex]

⇒ [tex]E(X)=E(X_{1})=E(X_{2})=\frac{4}{5}[/tex]

Now we need to use some expected value properties in the expression of [tex]Y[/tex] ⇒

[tex]Y=(1-X_{1})(1-X_{2})[/tex] ⇒

[tex]Y=1-X_{2}-X_{1}+X_{1}X_{2}[/tex]

Applying the expected value properties (linearity and expected value of a constant) ⇒

[tex]E(Y)=E(1)-E(X_{2})-E(X_{1})+E(X_{1}X_{2})[/tex]

Using that [tex]X_{1}[/tex] and [tex]X_{2}[/tex] have the same expected value [tex]E(X)[/tex] and given that [tex]X_{1}[/tex] and [tex]X_{2}[/tex] are independent random variables we can write [tex]E(X_{1}X_{2})=E(X_{1})E(X_{2})[/tex]   ⇒

[tex]E(Y)=E(1)-E(X)-E(X)+E(X_{1})E(X_{2})[/tex] ⇒

[tex]E(Y)=E(1)-2E(X)+[E(X)]^{2}[/tex]

Using the value of [tex]E(X)[/tex] calculated :

[tex]E(Y)=1-2(\frac{4}{5})+(\frac{4}{5})^{2}=\frac{1}{25}[/tex]

[tex]E(Y)=\frac{1}{25}[/tex]

We find that the expected value of the variable [tex]Y[/tex] is [tex]E(Y)=\frac{1}{25}[/tex]

5y - 2y = 3y + 2
please help.

Answers

It’s 0 = 2 I hope this helps a bit

Multiplying polynomials
(4x+3y)(5x+y)

Answers

Answer:

20x^2 +19xy+3y^2

Step-by-step explanation:

See Image below :)

9514 1404 393

Answer:

  20x² +19xy +3y²

Step-by-step explanation:

Use the distributive property.

  (4x +3y)(5x +y)

  = 4x(5x +y) +3y(5x +y)

  = 20x² +4xy +15xy +3y²

Collect terms.

  = 20x² +19xy +3y²

What is the solution to the equation below round your answer to two decimal decimal places log4 x=2.1
A. x=8.40
B. x=18.38
C. x=8.17
D. x=19.45

Answers

Answer:

B 18.38

Step-by-step explanation:

log4x = 2.1

logx/log4 = 2.1

logx = log(4) x 2.1

logx = 1.2643

x = antilog(1.2643)

x = 18.38 (to 2 d.p)

Answer:

X=18.38

Step-by-step explanation:

A very weak university is on and off probationary status with the accrediting agency. A different procedure is used in July and in January to determine its status for the next 6 months. In July, the probability of changing status by coming off probation is .25; but the probability of changing status by going on probation is .12. In January, the probability of coming off probation is .15; but the probability of going on probation is .08. a) If the university is on probation as of February 2019; what is the probability it will be off probation in February 2020

Answers

Answer:

0.3425 = 34.25% probability it will be off probation in February 2020

Step-by-step explanation:

We have these desired outcomes:

Off probation in July 2019, with 0.25 probability, then continuing off in January, with 1 - 0.08 = 0.92 probability.

Still in probation in July 2019, with 1 - 0.25 = 0.75 probability, then coming off in January, with 0.15 probability.

What is the probability it will be off probation in February 2020?

[tex]p = 0.25*0.92 + 0.75*0.15 = 0.3425[/tex]

0.3425 = 34.25% probability it will be off probation in February 2020

Then find the values of x and y?

Answers

y+8=3y
-2y=-8
y=4

104*2=208
360-208=152
152/2=76

x=76°

Answer:

x=76

Step-by-step explanation:

y+8=3y

-2y=-8

y=4

104*2=208

360-208=152

152/2=76

x=76

Pls answer this. I need the answer quick. Just write the answer. no downloads

Answers

Answer:

POINTS HA

Step-by-step explanation:

Need help please
What is the measure of angle 1?
What is the measure of angle 3?
What is the measure of angle 6?

Answers

Answer:

Step-by-step explanation:

Do you have any measurements?

1) 180-Angle 2 = Angle 1

3) Same as Angle 2

6) Same as Angle 2

Solve for 41.
1259
61 = [?]
61
37°
889

Answers

Answer: 55

Step-by-step explanation:

180 = 125 + x

x = 55

the angle is 55. all angles of a triangle adds to 180. 37+88=125. 180-125=55.

Which fraction is equivalent to 1/6

1/3
2/8
3/24
4/24​

Answers

Answer:

the last one- 4/24

Step-by-step explanation:

ive answered this question before and got it correct

4/24 is the right answer for this question
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