The double-sided mirror would produce virtual image to which objects? A)1,2 and 4 B)1,2 and 3 C)3 and 5 D)4 and 5

Protons have positive charge

Electrons have negative charge

• 22 protons (+22) + 18 electrons (-18 )

22 - 18 = 4 (positive)

• 12 -10 = 2

• 17 - 10 = 7

• 2 - 1 = 1

From most positive to most negative overall charges.

7 - 4 - 2 - 1

A 12 N force acts at a 25-degree angle, while an 8 N force acts at a 65-degree angle. The magnitude and direction (including angle) of the resultant force are 21.43.

Consider the formula for a force, F=M×Cos∝

As M is a Mass of an object and, ∝ Is the angle at which force is acting on an object.

[tex]F_{1}[/tex]=M × Cos ∝

M=12N, and Cos∝= Cos25 = 0.906

[tex]F_{1}[/tex] = 12× 0.906

∴ [tex]F_{1}[/tex]= 10.87N

For [tex]F_{2}[/tex] = 25×Cos65

= 10.56N

According to Superposition resulting force is the Sum of total forces.

[tex]F_{RESULTANT} = F_{1} + F_{2}[/tex]

= 10.87+ 10.56

=21.43N

∴The resultant force is 21.43.N

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A dog running of constant speed of 3m/s increases it's speed to 7m/s upon seeing a lion. if the mass of the dog is 20kg, the work it does in achieving the new speed is.......​ 400 J.

What is Speed?

Speed is the time rate at which an object is travelling along a path, whereas velocity is the pace and direction of an object's movement. In other words, velocity is a vector, whereas speed is a scalar valu

Work = Change in Kinetic energy

= ½m(v² - u²)

= ½ × 20 kg × [(7 m/s)² - (3 m/s)²]

= 10 kg × 40 m²/s²

= 400 J

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2.79 eV

Given

The wavelength, λ = 445 nm

The planck's constant, h = 6.626 x 10^-34 m² kg/s

The speed of light, c = 3 x 10^8 m/s

The energy of the photon is calculated as:

But, 1 eV = 1.6 x 10^-19J

We are given a graph of position vs time. We are asked to determine the speed at 5 seconds. To do that we need to determine the slope of the line above the time point of 5 seconds. To determine the slope of the line we will use the following formula:

This means that we need to choose two points in the line. We use the graph to determine these points as follows:

The points we have chosen are:

Replacing in the formula for the slope we get:

Solving the operations:

Therefore, the speed at 5 seconds is 0.5 meters per second.

For part B the following points can be taken:

Given data

*The given distance from the base of the ledge is R = 2.25 m

*The given speed is v = 3.5 m/s

The diagram is given below

(a)

Let (h) be the height of the edge

The formula for the distance from the base of the ledge is given as

Substitute the known values in the above expression as

Hence, the height of the ledge is h = 2.025 m

(b)

The formula for the time taken by the boulder to fall to the bottom of the cliff is given as

Substitute the known values in the above expression as

Hence, the time taken by the boulder to fall to the bottom of the cliff is t = 0.642 s

Answer:

The wavelength is 60 cm.

Explanation:

Speed = frequency x wavelength = 100 x 60 = 6000 cm/s

or if you wanted the answer in m/s

Speed = frequency x wavelength= 100 x 0.60 = 60 m/s

As we know

Where,

P= electric power= 2.50 W

V= potential difference= ?

I= current = 4.00A

Using above formula we get,

Final answer is :- 0.625 V

Answer:

Your hypothesis was not supported by the data collected

Explanation:

On question 2 you said that the point with the greatest kinetic energy would be point 5. However, when you analyze the data, the point with the greatest velocity was point 2 which means that this is the point with the greatest kinetic energy.

Therefore, your hypothesis was not supported by the data collected because based on the picture, it is hard to say where is the lowest point of the roller coaster.

A rope pulls a 72.5 kg skier upa 21.7°slope with /k = 0.120.The rope is parallel to the slope,and exerts a force of 383 N. The acceleration of the skier is approximately 2.97 m/s².

To find the acceleration of the skier, we need to use Newton's second law of motion and consider the forces acting on the skier.

Identify the forces acting on the skier:

The forces acting on the skier are the force of gravity (mg) and the force exerted by the rope (T), where m is the mass of the skier (72.5 kg) and g is the acceleration due to gravity (9.8 m/s²). The force exerted by the rope is parallel to the slope and can be calculated using the given value of 383 N.

Resolve the forces:

Since the rope is parallel to the slope, we need to resolve the force of gravity into components parallel and perpendicular to the slope. The component parallel to the slope is m * g * sin(21.7°).

Apply Newton's second law of motion:

Newton's second law states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration. Mathematically, Fnet = ma.

Determine the net force:

The net force acting on the skier is the difference between the force exerted by the rope and the component of the force of gravity parallel to the slope. Fnet = T - m * g * sin(21.7°).

Calculate the acceleration:

Using Newton's second law, we can rearrange the equation Fnet = ma to solve for the acceleration (a). a = Fnet / m.

Substitute the values and solve:

Substitute the known values into the equation to find the acceleration.

Therefore, the acceleration of the skier is approximately 2.97 m/s².

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Answer:

  about 0.567 m/s²

Explanation:

You want the acceleration of a 72.5 kg skier up a 21.7° slope with µk = 0.120, towed by a rope exerting a force of 383 N.

The force up the slope is 383 N.

The forces down the slope will be the sum of the force due to gravity and the friction force.

The force down the slope due to gravity is ...

  F = m·g·sin(θ) = (72.5 kg)(9.8 m/s²)(sin(21.7°) ≈ 262.7 N

The force due to friction will be the product of µk and the force normal to the slope:

  F = m·g·cos(θ)·µk = (72.5 kg)(9.8 m/s²)cos(21.7°)·0.120 ≈ 79.22 N

The net force up the slope is ...

  383 N -262.7 N -79.22 N ≈ 41.08 N

This will accelerate a mass of 72.5 kg in the amount of ...

  A = F/m = 41.08 N/(72.5 kg) ≈ 0.567 m/s²

The acceleration of the skier is about 0.567 m/s² up the slope.

__

Additional comment

We don't have to figure the forces. Rather we can figure the gross acceleration due to the tow rope, then subtract the accelerations due to gravity and friction. This saves a few math operations as we don't have to multiply, then divide, by 72.5 kg.

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The time taken for the hare to catch up with the tortoise is 10 seconds.

The time taken for the hare to catch up with the tortoise is calculated by applying the principle of relative velocity as shown below.

Distance travelled by hare + Distance travelled by tortoise = Total distance

V₁t + V₂t = d

where;

Since they are moving in the same direction, the relative velocity becomes

V₁t - V₂t = d

(V₁ - V₂)t = d

(4 - 1)t = 30

3t = 30

t = 30/3

t = 10 seconds

Thus, the time taken for the hare to catch up with the tortoise is 10 seconds.

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The complete question is below:

A tortoise and a hare run to the East. The hare knows that it is faster, so it gives the tortoise a 30-meter head start. The tortoise is moving east at 1 m/s and the hare is moving east at 4 m/s. At what time does the hare catch up with the tortoise?

Answer:

THE REMAINIG WILL BE 75

Explanation:

HOPE IT HELPS YOU

Given data:

* The mass of ball A is m_1 = 1 kg.

* The mass of ball B is m_2 = 1 kg.

* The initial velocity of ball A is u_1 = 5 m/s.

* The final velocity of ball A is v_1 = 0 m/s.

* The initial velocity of the ball B is u_2 = 0 m/s.

Solution:

According to the law of conservation of momentum, the net momentum of the system before the collision is equal to the net momentum of the system after the collision.

Thus,

Substituting the known values,

where p_2 is the momentum of the ball B,

Thus, the momentum of ball B after the collision is 5 kgm/s.

Hence, the third option is the correct answer.

We will have the following:

We know that for a simple spring the following is true:

So:

So, the stretch of the spring is directly proportional to the force.

The true statement is the vertical component of the velocity is half of the magnitude of the velocity.

The vertical component of a velocity is the velocity of the object acting along vertical direction.

The vertical component of the velocity acting along the vertical direction is calculated as follows;

Vy = V sinθ

where;

Substitute the value of the angle of projection and evaluate the vertical component of the velocity.

Vy = V sin(30)

Vy = V(0.5)

Vy = ¹/₂V.

Thus, the vertical component of the velocity is half of the magnitude of the velocity.

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The complete question is below

A projectile is thrown at an angle 30° from horizontal. Which statement about its vertical component of velocity is true?

Answer:

Speed =  4 m/s

Explanation:

Given:

009 (part 1 of 2)

H =1 .19 m

L = 1.98 m

g = 9.81 m/c²

____________

V₀ - ?

Equation of motion horizontally:

L = V₀*t           (1)

Equation of vertical motion:

H = g*t² / 2      (2)

From equation (2):

Time:

t = √ (2*H / g) = √ ( 2*1.19 / 9.81) ≈ 0,49 s

From equation (1):

Horizontal speed:

V₀ = L / t = 1.98 / 0.49 ≈ 4 m/s

Option A is the correct answer: A secondary source is more helpful than a primary source when you want to confirm the conclusion with your own experiment.

Primary and secondary sources work well together to support the argument you are trying to make. Although secondary sources demonstrate how your work connects to earlier research, primary sources are more reliable as evidence. When you want to confirm the conclusion of your experiment, secondary sources prove to be more useful.

Original research is built on primary sources. You are able to discover novel information, offer solid justification for your claims, and provide reliable facts on your subject.

Secondary sources are useful for getting a comprehensive perspective of your subject and learning other researchers' methods. They frequently combine numerous primary materials that would take a lot of time and effort to obtain independently.

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Diffraction is a phenomenon that occurs when a wave hits an object or it passes through a small gap.

The propagation of the wave will have a circular pattern after the diffraction effect:

Therefore the correct option is D.

The angular velocity of the ball orbiting in circle will be 5 rad/s.

Angular velocity describes the rate at which an object rotates.

Given is a ball that orbits in a circle of radius 10m with a speed of 50 m/s.

The relation between the linear and angular velocity of a body is given by-

v = rω

where -

v is the linear velocity

r is the radius

ω is the angular velocity

On substituting the values, we get -

50 = 10 x ω

ω = 50/10

ω = 5 rad/s

Therefore, the angular velocity of the ball orbiting in circle will be

5 rad/s.

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The change in the reservoir, the system or device, and the surroundings are added to determine the overall entropy change. The reservoir's entropy change is. Since entropy is a function of state and we are contemplating a complete cycle (return to initial state), the device's entropy change is zero.

For finite variations at constant T, entropy changes (S) are calculated using the relation G=ΔH - TΔS.

The generation, consumption, conversion, and exchange of thermal energy across physical systems is the focus of the thermal engineering field of study known as heat transfer. Different heat transmission techniques, including thermal conduction, thermal convection, thermal radiation, and energy transfer by phase changes, are categorized.

Conduction is the process through which heat is transported from an object's hotter end to its colder end. Heat naturally transfers from a hotter body to a colder body.

For instance, heat is transferred from the hotplate of an electric stove to the bottom of a saucepan that comes into touch with it.

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We will have the following:

We use conservation of momentum to solve, that is:

So, Conner's mass is approximately 69.8 kg.

We have:

m = mass = 0.77 kg

t = time = 2.9 ms = 0.0029 s

vf = final speed = 15.5 m/s

vi= initial speed = 0 m/s

Apply:

• F = m (vf-vi) / t

Replacing:

F = 0.77 (15.5 - 0 )/0.0029

F= 4,155.5 N

The magnetic dipole moment of the current loop is  0.025 Am².

The magnetic torque on the loop is 2.5 x 10⁻⁴  Nm.

The magnetic dipole moment of an object, is the measure of the object's tendency to align with a magnetic field.

Mathematically, magnetic dipole moment is given as;

μ = NIA

where;

μ = (1) x (25 A) x (0.001 m²)

μ = 0.025 Am²

The magnetic torque on the loop is calculated as follows;

τ = μB

where;

B = √(0.002² + 0.006² + 0.008²)

B = 0.01 T

τ = μB

τ =  0.025 Am² x 0.01 T

τ = 2.5 x 10⁻⁴  Nm

Thus, the magnetic dipole moment of the current loop is determined from the current and area of the loop while the magnetic torque on the loop is determined from the magnetic dipole moment.

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Answer:Question 1

Given q1=2µC                                  

          q2=2µC

           q= 1.2×10^-18C at origin

Net force exerted by two charges on q

F_1= force on q due to q1

F_2= force on q due to q2

F_net=   F_(1-) F_2        

      = (Kqq_1)/r^2  - (kqq_2)/r^2                                  Then q_1=q_2=〖2×10〗^(-6)

F_net=0N

b) The electric field at charge q

E_net= E_1- E_2

      = (kq_1)/r^2  - (kq_2)/r^2

Then q_1=q_2

 E)_net= 0 N/C  

c) The electric potential at origin due to two charge

V_net= V_(1 )- V_2

      =  (kq_1)/r - (kq_2)/r  

Then q1= q2

V_net= 0 V

Explanation:

The elasticity and Poisson's ratio for this metal is 0.232.

What is ratio?

The realation between two numbers which shows how much bigger one quantity is than another.

Sol-

As per the given question

P=190KN

d=16 mm

Lo=50mm

X=50.1349-50=0.1349mm

Y=15.99-16=-0.01mm

The formula-

E=ó/€

Ó=P/A

A=r/4 d^2 =π/4(16)^2=201.062 mm

ó={190(1000)}201.062=944.982 Mpa

E=944.982/0.002698=350.253 GPa

€y=-0.000625

v=0.232(answer)

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The value of G is  FR²/M₁M₂. and the dimension of G is  [M⁻¹L³T⁻²]..

The provided formula is of gravitational force F between two objects,

F = GM₁M₂/R²

Where M₁ is the mass of first object and M₂ is the mas of the other object while R is the distance between there centers and G is the universal gravitation constant.

To find the dimension of G, making G the subject of formula,

G = FR²/M₁M₂.

As we know, unit of mass is Kilogram (Kg), unit of force is Newton (N) and unit of distance is Meter (M).

Putting all the values, Units in the place of quantities,

G = N.R²/Kg.Kg

Now, using Dimensional analysis, and writing the dimensions of all the other units,

G = [MLT⁻²][L²]/[M][M]

G = [ML³T⁻²]/[M²]

G =  [M⁻¹L³T⁻²]

The dimensions of G are  [M⁻¹L³T⁻²].

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Answer:

a=0.05m/s²

Explanation:

force=mass × acceleration

f=ma

f=50N

m=1000kg

a=?

50=1000×a

50=1000a

a=50/1000

a=0.05m/s²

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ANSWER

17.5 %

EXPLANATION

We have to find the percent change, given that the initial price was $40 and the final price was $33.

The coupon was for 17.5% off

ANSWER:

20.17 meters

STEP-BY-STEP EXPLANATION:

Given:

Pressure = Po = 1.013x10^5 Pa

Pressure at depth = P = 3Po

Density of sea water = 1025 kg/m^3

We can calculate the depth as follows:

We replacing and calculate the depth:

Therefore, the depth is equal to 20.17 meters

The cannon ball will go farther if the the angle of projection is set at 60 degrees

How to determine which angle will result in farther distance

Case 1:

R = u²Sine(2θ) / g

R = 20² × Sine (2×60) / 9.8

R = 346.41 / 9.8

R = 35.35 m

Case 2:

R = u²Sine(2θ) / g

R = 20² × Sine (2×70) / 9.8

R = 257.12 / 9.8

R = 26.24 m

From the above calculations, we can conclude that the ball will go farther, if the angle is 60 °

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