The period of small oscillations of the disk is 2π√L∕g
What is simple harmonic oscillation?Simple harmonic motion can be described as oscillatory motion in which the acceleration of a particle at each position is directly proportional to its displacement from its mean position. This is a distinct case of oscillatory motion. You can represent SHM with a single harmonic sine or cosine function.
For small-angle oscillations, the approximation sinθ≈θ applies, which is a linear differential equation similar to that for simple harmonic oscillators. In this regime the pendulum swings in one period.
T₀ = 2π√L∕g
Where, T₀ = Period of small oscillations
L = length of the string to which the disc is attached to
g = gravitational acceleration.
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2. A 10kg block of wood is pulled across a level ground by fore of 15N applied at
an angle of 30 degree from the horizontal. How much work is done, if it is moved
to a distance of 3m?
(Note: F applied = 15N x cos 30 degree, cos 30 degree = 0.5)
Answer:
about 19.49J
Explanation:
Work = F × D × Cosine(θ)
Substitute values :D:
Work= 15N x cos 30 degree x 3m x cos 30
Work= 7.5 x 3 x cos 30
Work= about 19.49 joules
an 8.0 kg object has a moment of inertia of 1.00 kg m2. what torque is needed to give the object an angular acceleration of 1.5 rad/s2?
The torque required to give the object an angular acceleration of 1.5 rad/s² is 1.5 Nm.
TorqueObjects that move in a translational manner use Newton's II law (∑F = ma)and objects that move in a rotational manner also use the same concept of Newton's laws, but the quantity use rotational quantity . Then, Newton's Second Law for objects that move in a rotational manner or move in a circle uses the formula:
τ = (the moment inertia) x (the angular acceleration of the object)
With,
τ = is the total torque acting on the object (Nm)
I = is the moment of inertia of the object (kgm²)
α = is the angular acceleration of the object (r4d/s²)
So, the required torque is:
τ = (1.00 kgm²) (1.5 r4d/s²)
= 1.5 Nm
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in what direction will the seesaw rotate, and what will the sign of the angular acceleration be? in what direction will the seesaw rotate, and what will the sign of the angular acceleration be? the rotation is in the clockwise direction and the angular acceleration is positive. the rotation is in the clockwise direction and the angular acceleration is negative. the rotation is in the counterclockwise direction and the angular acceleration is positive. the rotation is in the counterclockwise direction and the angular acceleration is negative.
The rotation is in the counterclockwise direction and the angular acceleration is positive.
What is angular acceleration?
The temporal rate at which angular velocity changes is known as angular acceleration. The standard unit of measurement is radians per second per second. Therefore, = d d t. Rotational acceleration is another name for angular acceleration.
A rigid body's points all share the rotating velocity and acceleration.
Therefore, The rotation is in the counterclockwise direction and the angular acceleration is positive.
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The angular acceleration is positive and the rotation is counterclockwise.
Angular acceleration:
In physics, angular acceleration is the temporal rate of change of angular velocity. Because there are two types of angular velocity, spin angular velocity as well as orbital angular velocity, there are two types of angular acceleration, spin angular acceleration as well as orbital angular acceleration. Spin angular acceleration is the angular acceleration of a rigid body as to its centre of rotation, whereas orbital angular acceleration is the angular acceleration of a point particle around a fixed origin. Therefore, = d d t.
A rigid body's points all share the rotating velocity and acceleration.
Therefore, The rotation is in the counterclockwise direction and the angular acceleration is positive.
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some fish have a density slightly less than that of water and must exert a force (swim) to stay submerged. what force (in n) must a 64.0 kg grouper exert to stay submerged in salt water if its body density is 1003 kg/m3?
The force (in n) must a 64.0 kg grouper exert to stay submerged in salt water if its body density is 1003 kg/m3 will be 15.6 newtons.
The push or pull on a mass-containing item changes its velocity. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude. Therefore, we have the mass of the fish times g times the ratio of densities minus 1, which is 85.0 kilograms times 9.80 newtons per kilogram times 1.025 times 10 to the 3 kilograms per cubic meter (density of seawater) divided by 1015 kilograms per cubic meter (density of the fish) and equals 8.21 newtons.
F= d/a
=1003 /64
=15.6 N
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Why did the ball move the same distance when it was on the flatbed truck that accelerated 0. 2 m/s?.
The ball moves the same distance when it was on the flatbed truck because of Relative velocity.
The relative velocity of the ball with respect to the truck is same as of truck with respect to ball at equal times.
Relative velocity - Relative velocity is velocity of an object in relation to another object
It is the measure of how fast two objects are moving with respect to each other.
The distance travelled by each object is determined by product of velocity and time of motion
d = vt
where, d= distance
v = velocity
t = time
so here we can say that if the ball is moved the same distance when it was on truck, then the relative velocity of the ball with respect to truck is same as of truck with the ball.
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approximately how many times greater is the atmospheric pressure in jupiter's core than on earth's surface?
Approximately 100 million times greater is the atmospheric pressure in jupiter's core than on earth's surface.
The average atmospheric pressure at sea level at 15 degrees Celsius is the unit of measurement known as an atmosphere. 1,013 millibars is equal to 760 millimeters of mercury, or 29.92 inches, in one atmosphere. When the bulb is pressed, air from the tube and bulb escapes as bubbles. The liquid's surface does, however, experience atmospheric pressure. The water moves inside the tube when we release the bulb. The pressure that the air around us puts on us is known as air pressure, whereas the pressure that the atmosphere puts on the earth is known as atmospheric pressure. Mercury barometer is used to measure atmospheric pressure, while tore gauges are used to measure air pressure. Since our internal pressure is roughly equal to the external atmospheric pressure, we are not affected by the pressure of the atmosphere around us.
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If the only force acting on the rock is its weight, what is the magnitude of the rate of change of its angular momentum at this instant? express your answer in kilogram-meters squared per second squared.
The net torque applied to the item equals the rate of change of angular momentum.
The net torque is equal to the weight "mg" times the angle between the weight's line of action and the origin (x dL/dt = mgx = mgrCos) (36.8)
Alternatively, it is composed of the weight perpendicular to the position vector times its magnitude, r dL/dt = mgCos(36.8).
clearly the same equation.
Just enter the values because everything is already provided. Finding L's rate of change does not require knowledge of particle velocity.
what is angular momentum?
The characteristic of any rotating object determined by the product of the moment of inertia and the angular velocity is known as angular momentum. It is a characteristic of rotating bodies determined by the sum of their moment of inertia and angular velocity.
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The net torque is equal to the weight "mg" times the angle between the weight's line of action in angular momentum and the origin (x dL/dt = mgx = mgrCos) (36.8)
What is angular momentum?
The characteristic of any rotating object determined by the product of the moment of inertia and the angular velocity is known as angular momentum. It is a characteristic of rotating bodies determined by the sum of their moment of inertia and angular velocity.
The net torque applied to the item equals the rate of change of angular momentum. Alternatively, it is composed of the weight perpendicular to the position vector times its magnitude, r dL/dt = mgCos(36.8).
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5. the 1200-turn coil in a dc motor has an area per turn of 1.1x10-2 m2. the design for the motor specifies that the magnitude of the maximum torque is 5.8 nm. when the coil is placed in a 0.20-t magnetic field. what is the current in the coil?
The rotating equivalent of force is torque. Depending on the subject of study, it is also known as the moment, moment of force, rotating force, or turning effect.
A coil's torque is determined by:
equals niABsin
where I is the coil's current
Area of the coil equals A.
Magentic field = B
n is the coil's total number of turns.
and = angle between the field B and area vector A
The maximum torque would occur at 900, where sinθ = 1.
Maximum torque therefore equals niAB.
alternatively 5.8N-m = (1200) i(1.1x10-2m2) (0.20-T)
or the coil's current, I is 2.196A
The formula for torque is rF=rFsin(r). To put it another way, the cross product of the distance vector and the force vector, where 'a' is the angle between r and F, is what is known as torque (the distance between the pivot point and the place where force is applied).
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What is the distance between two objects if one (a 185,000 kg object) experiences a gravitational force of 0.00200 N due to a 225,000 kg object
Using the gravitational force, the mass of item 1 and object 2, and the Newton's law of gravity calculator, one may calculate the distance between two objects.
How is gravitational distance determined?g = GM/r2, where M is the Earth's mass, r is its radius (or the distance from the Earth's center to where you are standing), and G is the gravitational constant. The gravitational constant is G (without the subscripts), while the speed of light is c.
How is the gravitational force between two objects calculated?By applying Newton's equation, we can accomplish this quite easily: forcegravity is defined as G M m2 separation. Suppose that you weigh 60 kilograms and your colleague weighs 70 kilograms. The center-to-centre distance, r, is 1 m, and the gravitational constant, G, is 6.67 10 -11 newtons square meter kilogram-2.
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Complete the following statement: when a net torque is applied to a rigid object, it always produces a.
When a net torque is given to a rigid object, it always causes an angular velocity change.
What exactly is meant by torque?Torque is defined as a force that causes an object to revolve around an axis. In linear kinematics, force causes an item to accelerate; in rotational kinematics, torque causes an object to accelerate. Torque is a vector quantity.
Based on the vector values involved, we must predict what will happen when a net torque is applied to a rigid object.
As a result, when a net torque is applied to the rigid item, the rate of rotation changes.
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figure shows a silver ribbon whose cross section is 1.0 cm by 0.20 cm. the ribbon carries a current of 110 a from left to right, and it lies in a uniform magnetic field of magnitude 1.25 t. using a charge density value of n
72.828×[tex]10^{-7}[/tex]Volt is the Hall potential between the edges of the ribbon.
We know that Hall potential is given by =IB/qnd where
I is the current flowing
,B is the magnetic field ,
q is the charge of the electron,
n is the charge density of electron,
and d is the thickness
So, we are given that current(I)=110Ampere,magnetic field(B)=1.25Tesla,
charge of electron(q)=1.6×[tex]10^{-19}[/tex]C, charge density (n)= 5.9x1028,thickness
(t) as 2.cm
So, putting the values of the respected quantities on the above formula ,we get
Hall potential([tex]V_h[/tex])=(110×1.25)/(1.6×[tex]10^{-19}[/tex]×5.9×[tex]10^{28}[/tex]×0.2×[tex]10^{-2}[/tex])
=>([tex]V_h[/tex])=[137.5/1.888]×[tex]10^{-7}[/tex]
=>([tex]V_h[/tex])=72.828×[tex]10^{-7}[/tex]Volt.
Hence, the Hall potential is 72.828×[tex]10^{-7}[/tex]Volt.
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(Complete question) is:
Figure shows a silver ribbon whose cross section is 1.0 cm by 0.20 cm. The ribbon carries a current of 110 A from left to right, and it lies in a uniform magnetic field of magnitude 1.25 T. Using a charge density value of n = 5.9x1028 electrons per cubic meter for silver, find the Hall potential between the edges of the ribbon.
A spring has an unstretched length of 11 cm . It exerts a restoring force F when stretched to a length of 12 cm. For what total stretched length of the spring is its restoring force 3F? At what compressed length is the restoring force 2F?
Using the spring constant relation, the required length and compressed length of the spring at the given force values are 14 cm and 9 cm respectively.
A.) Using the given formula,
F = ke
Where k = spring constant , e = extension and e = (Final length - Initial length)
Initial length, l = 11
Final length = L1 = 12
F = k(12 - 11)
F = k(1)
F = k
Length for a restoring force of 3F ;
3F = k (Final length - Initial length)
k = F
3F = F(L1 - 10)
3F = - 11F + F(L1)
F(L1) = 3F + 11F
F(L1) = 14F
L1 = 14 cm
Hence, required length is 14 cm
B.) Let compressed length = c
2F = F(initial length - compressed length)
2F = F(10 - c)
2F = 11F - F(c)
F(c) = 11F - 2F
F(c) = 9F
c = 9F / F
c = 9 cm
Therefore, the required compressed length is 9 cm
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light that is polarized along the vertical direction is incident on a sheet of polarizing material. only 87% of the intensity of the light passes through the sheet. what angle is the axis of the polarizer oriented, with respect to the vertical?
Polarized light waves are those that have only one plane of vibration. Polarization is the process by which non-polarized light is converted into polarised light. There are numerous ways to polarise light.
A characteristic of transverse waves called polarisation identifies the geometric angle of the oscillations. A transverse wave's oscillation direction is perpendicular to the wave's motion direction.
given
Only 72.0% of the light's intensity makes it through the sheet and hits another sheet of polarising material. The second sheet lets no light flow through it.
Given that no light passes through the second sheet because both sheets are crossed, the angle the transmission axis of the second sheet makes with the vertical is
θ₂ = θ₁ + 90°
= 31.94° + 90°
= 1 21.94°
for the first sheet and
Icos²θ₁ = I
I/I₀ = 0.72
θ₁ = cos⁻¹√(0.72)
= 31.94°
for the second sheet, respectively. This is because the malus law states that I = Iocos²θ₁ for the first sheet.
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an electric fan is plugged into an outlet and the circuit completed, making the fan blades spin. which of the following correctly describes this situation? responses mechanical energy is transformed into electrical energy. mechanical energy is transformed into electrical energy. mechanical energy is destroyed, and electrical energy is created. mechanical energy is destroyed, and electrical energy is created. electrical energy is transformed into mechanical energy. electrical energy is transformed into mechanical energy. electrical energy is destroyed, and mechanical energy is created. electrical energy is destroyed, and mechanical energy is created.
The situation is correctly described as Electrical Energy is transformed into mechanical energy.
Recalling the working of a fan, i.e. as the circuit is closed, the electrons start flowing in the wires, producing current and hence the current reaches the fan, which rotates due to the magnets in it. Hence the Electrical energy is transformed into Mechanical Energy which is the kinetic energy produced due to rotation of wings of fan.
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a constant torque of 31.4 space n times m is exerted on a pivoted wheel. if the angular acceleration is 4 pi space rad divided by s squared, then the moment of inertia will be
The moment of inertia will be 2.5kgm².
Inertia method an item will keep its present-day movement till a few force causes its speed or course to change. The term is nicely understood as shorthand for "the principle of inertia" as described with the aid of Newton in his first regulation of motion.
Inertia is a property of count number that causes it to withstand changes in pace (pace and/or path). consistent with Newton's first regulation of movement, an object with a given speed maintains that velocity except acted on by an external pressure.
Inertia is the pressure that holds the universe together. literally. without it, count number would lack the electric forces vital to shaping its present-day arrangement. Inertia is counteracted by way of the warmth and kinetic strength produced with the aid of transferring debris.
Calculation:-
τ=Iα
31.4=I×4π
31.4=I×4(3.14)
⟹I=2.5kgm²
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A horizontal pipe 10. 0 cm in diameter ha a mooth reduction to a pipe 5. 00 cm in diameter. If the preure of the water in the larger pipe i 8. 00 104 Pa and the preure in the maller pipe i 6. 00 104 Pa, at what rate doe water flow through the pipe?
The rate at which water flow through the pipe is 12.83 kg/s.
What is Bernoulli’s equation?Bernoulli's theorem, is based upon law of conservation of energy. Equalize the total energy (pressure energy, potential energy, and kinetic energy) of a flowing liquid at different points flowing under a constant pressure difference. Bernoulli's equation states that points 1 and 2 are on the streamline, the liquid has a constant density, and the flow is stable with no friction.
D₁ = 10 cm
D₂ = 5 cm
P₁ = 8×10⁴ Pa
P₂ = 6×10⁴ Pa
Let's apply Bernoulli’s equation for the wide and reduced part of this pipe:
P₁+ ¹/₂ρυ₁² = P₂ + ¹/₂ρυ₂²
Now, apply continuity equation:
A₁v₁ = A₂v₂
(D₁²π/4) v₁ = (D₂²π/4) v₂
D₁² v₁ = D₂² v₂
v₂ = (D₁/ D₂)² v₁
v₂ = (10/ 5)² v₁
v₂ = 4 v₁
Now,
P₁+ ¹/₂ρυ₁² = P₂ + ¹/₂ρ4υ₁²
P₁+ ¹/₂ρυ₁² = P₂ + 8ρυ₁²
P₁ - P₂ = 8ρυ₁² - ¹/₂ρυ₁²
P₁ - P₂ = 15/2ρυ₁²
Substitute the values in above equation:
8×10⁴ - 6×10⁴ = 15/2×1000υ₁²
υ₁ = 1.63 m/s
So, volume flow rate is:
ρA₁v₁ = ρ(D₁²π/4)v₁
= 1000×(10²×3.14/4)×1.63
= 12.83 kg/s
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a cart starting from rest rolls down a hill and at the bottom has a speed of 4 m/s. if the cart were given an initial push. so its initial speed at the too of the hill was 3 m/s. what would x be its speed at the bottom?
The correct answer of speed at 5 m/s at the bottom.
What is the connection between speed and kinetic energy?
A moving object's kinetic energy is inversely related to its mass and to the square of its velocity. Accordingly, an item with identical mass and speed will have twice the kinetic energy as one with double the mass and speed will have four times the kinetic energy.
When starting from rest, the cart’s PE is changed into KE:
Change in PE = Change in KE = 1/2m(4)²
When starting from 3 m/s, the
final KE is: KEf= KEi+ Change in KE= 1/2 m(3) ²+ 1/2m(4) ²= 1/2 m(25)
= 1/2 m(5) ²
Speed is not the same as kinetic energy
Hence the answer of speed is 5 m/s.
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A helium-filled weather balloon is held at ground level. The volume of the balloon is 4800 m3. The pressure of the helium is 98 kPa.
The balloon is released and rises to a height where the volume of the balloon is 7200 m3.
(i) Calculate the new pressure of the helium. Assume that the temperature stays constant.
65.3 kPa is the new pressure of the helium.
V1= 4800 m3
V2= 7200 m3.
P1= 98 kPa.
P2=?
P1V1=P2V2
P2=P1V1/V2
P2= 98×4800÷7200
P2=65.3 kPa.
The definition of pressure is force/area. For instance, the weight of the snow divided by the area of the roof would represent the pressure from snow on a roof. Gases are often where pressure in chemistry originates from. Vacuum is the term for the lack of pressure. Since "nature abhors a vacuum," humans have believed that vacuums are both impossible and unnatural for hundreds of years. This isn't really the case.
The amount of pressure units is insane! The torr or mmHg is a common unit. Simply put, this refers to the height of a mercury column. The atmospheric pressure is about 760 torr, or mmHg. You may also see mmH2O, which employs the same notion, but in this instance the atmospheric pressure is around 10.3 mH2O since water is less dense than mercury.
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a car is traveling 21 m/s when the driver sees a child standing in the road. he takes 0.8s to react then steps on the breaks and slows at 7.5m/s^2. how far does the car go before it stops?
The distance traveled by the car before it stops when moving with a velocity of 21 m/s is 19.2 m.
What is distance?Distance is the total length between two points.
To calculate the distance the car move before stopping, we use the formula below.
Formula:
S = ut+at²/2......... Equation 1Where:
S = Distanceu = Initial velocityt = Timea = accelerationFrom the question,
Given:
u = 21 m/st = 0.8 sa = 7.5 m/sSubstitute these values into equation 1
S = (21×0.8)+(7.5×0.8²/2)S = 16.8+2.4S = 19.2 mHence, the distance traveled by the car before it stops is 19.2 m.
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. ****an elastic cord is 80. cm long when it is supporting a mass of 10. kg hanging from it at rest at rest. when an additional 4.0 kg is added, the cord is 82.5 cm long. hint: 4 kg stretches the cord 2.5 cm!!
An elastic cord with natural length of 80 cm stretched to 82.5 cm when an additional 4 kg mass attached. The spring constant of the cord is 1600 N/m
According to the Hooke's Law, the force applied on a string is directly proportional to the length of extension ( or compression).
F = kx
Where:
F = applied force
k = spring constant
x = length of extension/compression
Data given from the problem:
Natural length = 80 cm
The length of stretch when an additional 4 kg mass added = 82.5
Hence,
x = length of extension = 82.5 - 80 = 2.5 cm = 2.5 x 10⁻² m
The force = 4 x 10 = 40 N
Hence, the spring constant:
k = F / x = 40 / (2.5 x 10⁻²) = 1600 N/m
Complete question:
an elastic cord is 80. cm long when it is supporting a mass of 10. kg hanging from it at rest at rest. when an additional 4.0 kg is added, the cord is 82.5 cm long. hint: 4 kg stretches the cord 2.5 cm!!
a. What is the spring constant of the cord?
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A baseball player dives head-first into
second base and slows down while sliding on the infield dirt.
Of the forces listed, identify which act upon the player.
1.Normal
2.Gravity
3.Applied
4.Friction
5.Tension
6. Air Resistance
Answer:
Explanation:
Discussion
The ones that are certain are
Normal GravityFrictionIf you have a normal, and the player slides into 2nd, and stops (which he must before he is tagged), then there must be friction involved. There must be gravity, or he would keep going up.
I don't think there is tension. There might be some Air Resistance, but that force is very tiny. Don't be surprised if you answer includes Air Resistance, but I won't try it to begin with.
why or how do neutrons help to reduce the repulsion between protons and stabilize the atoms nucleus?
This question is typical on some driver’s license exams: A car moving at 43 km/h skids
14 m with locked brakes.
How far will the car skid with locked brakes
at 129 km/h? Assume that energy loss is due
only to sliding friction.
Answer in units of m
Answer:
Braking distance 126 meters
Explanation:
Given:
V₁ = 43 km/h = 43 000 m / 3 600 s ≈ 12 m/s
D₁ =14 m
V₂ = 129 km/h = 129 000 m / 3 600 s ≈ 36 m/s
____________________
D₂ - ?
D₁ = V₁² / (2·a)
2·a·D₁ = V₁²
a = V₁² / (2·D₁)
D₂ = V₂² / (2·a) = V₂²·2·D₁ / (2·V₁²) =
= V₂²·D₁ / V₁² = D₁·(V₂ / V₁)²
D₂ = 14·(36 / 12)² = 14·3² = 126 m
The braking distance has increased 9 times!
while underway in fog you hear a whistle signal consisting of one prolonged blast followed immediately by two short blasts. which vessels are required to sound this signal in fog?
In this case, blast at intervals of not more than two minutes is the signal which will be used by power-driven vessels when underway. One long blast plus two short blasts at intervals of not more than two minutes is the signal used by sailing vessels.
Why do vessels sound signals in fog?
Heavy fog leads to severe issues that lead to reduction in the signal-to-noise ratio to levels which may even affect the communication system. It leads to Restricted Visibility. Therefore various methods are used including Foghorns , fog signals that warn vehicles of hazards or rocky coastlines , and some other boats in foggy conditions.
Apart from this certain other methods including prolonged blast, fog signals, communication with the satellite can be used. The whole process is undertaken to reduce the amount of harmful impacts, issues that may be faced by the vessels
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Power-driven vessel underway making way are required to sound this signal in fog.
What is Power-driven vessel?The term "power driven vessel" means any vessel propelled by a machine. The term "sailing vessel" signal a vessel under sail, provided that no propulsion machinery is used.Power-driven vessel include sailing vessels operated by engine power. Here are the lights you need: Red and green sidelights are visible from at least two miles away on a dark, clear night.Mechanical vehicles in motion must give way to uncommand vehicles. For purposes of Rule 3(b), the term "engine craft" means any machine-powered craft. Power-driven vessel means a vessel propelled by an engine, fuel, rocket, or similar device.To learn more about Power-driven vessel from the given link:
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The weight of the atmosphere results in P_0 at the surface of the oil layer. Then the weight of the oil and the weight of the water combine to create the pressure at the bottom. Why does air pressure decrease with increasing altitude? (Select all that apply.) Less air above pushes down. Hot air rises. The weight of the air above is smaller. Colder air is less dense. There is more air below to push up more strongly. The weight of the air below is smaller. Use the worked example above to help you solve this problem. In a huge oil tanker, salt water has flooded an oil tank to a depth of h_2 = 4.75 m. On top of the water is a layer of oil h_1 = 8.40 m deep, as in the cross-sectional view of the tank as shown in the figure. The oil has a density of 0.700 g/cm^3. Find the pressure at the bottom of the tank. (Take 1,025 kg/m^3 as the density of salt water.) Calculate the pressure on the top lid of a chest buried under 3.80 meters of mud with density 1.75 x 10^3 kg/m^3 at the bottom of a 11.5-m-deep lake.
The pressure at the bottom of the oil layer is given by,
P₁ = P₀ + ρgh₁ = (1.01 x 105 Pa) + (7 x 102 kg/m³) (9.8 m/s2) (8.4 m)
P₁ = (1.01 x 105 Pa) + (576.2 x 102 Pa)
P₁ = 1.58 x 105 Pa
Now, the pressure at the bottom of the tank which will be given using a formula, we have
P[tex]__{bottom}[/tex] = P1 + \rho g h2 = (1.58 x 105 Pa) + (1.025 x 103 kg/m3) (9.8 m/s2) (4.75 m)
P[tex]__{bottom}[/tex] = (1.58 x 105 Pa) + (47.7 x 103 Pa)
P[tex]__{bottom}[/tex] = 2.05 x 105 Pa
The pressure under mud will be given as
P₁ = P₀ + ρgh₁ = (1.01 x 105 Pa) + (1.75 x 103 kg/m3) (9.8 m/s2) (3.8 m)
P₁ = (1.01 x 105 Pa) + (65.1 x 103 Pa)
P₁ = 1.66 x 105 Pa
Now, the pressure on the top lid of a chest buried will be given as:
P[tex]__{top}[/tex] = P1 + \rho g h2 = (1.66 x 105 Pa) + (1.025 x 103 kg/m3) (9.8 m/s2) (11.5 m)
P[tex]__{top}[/tex] = (1.66 x 105 Pa) + (115.5 x 103 Pa)
P[tex]__{top}[/tex] = 2.81 x 105 Pa
The question is clearer in the picture
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if the tmt and e-elt get built as planned, what is one exciting potential discovery that astronomers hope to be able to make with them?
One exciting potential discovery that astronomers hope to be able to make with the E-ELT and TMT is life on other planets.
TMT and E-ELT are (currently) proposed telescopes. TMT (short for Thirty Meter Telescope) is a very large telescope composed of many small mirrors each about 1,4m in size. E-ELT (short for European Extremely Large Telescope) is going to be around 39m in diameter.
These proposed telescopes have very high resolution and sharper detection. They will be able to detect any exoplanet's atmosphere while it's transiting its star. In that detection, these telescopes may search for any biomarker molecules to detect the presence of life and habitability of the exoplanet.
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If another object (a can of beans) was dropped from 12 meters in free fall, how long will it take for that object to fall to the ground?
The time it takes the object to fall to the ground from a height of 12 m is 1.56 seconds.
What is time?Time can be defined as an ongoing and continuous sequence of events that occur in succession, from past through the present, and to the future.
To calculate the time it takes the object to fall to the ground, we use the formula below.
Formula:
H = ut+gt²/2.............. Equation 1Where:
H = Heightg = Acceleration due to gravityt = Timeu = Intial velecityFrom the question,
Given:
u = 0 m/s (drop from height)g = 9.8 m/s²H = 12 mSubstitute these values into equation 1 and solve for t.
12 = (0×t)+(9.8t²)/29.8t² = 12×2t² = 12×2/9.8t² = 2.45t = √2.45t = 1.56 seconds.Hence, the time it takes the object to fall to the ground is 1.56 seconds.
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A family in a car with the ma of 1400 kg. In an accident it hit a wall and goe from a peed of 27 m/ to a tandtill in 1. 5 econd. Calculate the force involved
The force involved is F₁.₅=-25.2KN when the car hit a wall and goes from a speed of 27m/s
What is meant by force?A force is an influence in physics that can modify the velocity of an object. A force can modify the velocity of a mass item. A force is a vector quantity since it has both magnitude and direction. It is measured in newtons, the SI unit of mass (N). The sign F represents force.
In its original form, Newton's second law states that the net force acting on an object equals the rate at which its momentum varies with time.
We know that,
Force=ma
F=ma
F=m((v-u)/t)
Given, t=1.5 second
Velocity v=0m/s at stand still
And mass m=1400kg
Speed u=27m/s
F₁.₅=1400((0-27m/s)/1.5)
F₁.₅=-25.2KN
Therefore, the force involved is F₁.₅=-25.2KN
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8. A bullet is fired horizontally from a gun. At the same time and from the same height,
a bullet is dropped. If we neglect the effects of air resistance, how will the time the
two bullets spend in the air compare to each other?
a. the bullet that is fired will spend less time in the air, hitting the ground first.
b. there is not enough information to determine this.
c. both bullets will spend the same amount of time in the air, landing at the same time.
d. the bullet that is fired will spend longer in the air, landing later.
Answer:
C hit the ground at the same time
Explanation:
Both bullets have to fall the same VERTICAL distance and are affected by gravity the same way in this regard.
How do you think you can calculate the total distance traveled if you were running at a constant speed?.
Distance = Speed x Time is a formula for calculating the total distance one covered while running at a constant speed.
To determine the total distance travelled if one is running at a constant speed we use formula:
d = s x t
d = distance covered
s = speed of the object
t = time taken.
The distance travelled is directly proportional to the amount of time required when the speed is constant.
d ∝ t
(at constant speed)
Distance = Speed x Time, is a formula for calculating the total distance one covered while running at a constant speed.
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