Answer:
Area=1.5(1.5)=2.25m^2
Force of gravity=10N
\begin{gathered}\\ \sf\longmapsto Pressure=\dfrac{Force}{Area}\end{gathered}
⟼Pressure=
Area
Force
\begin{gathered}\\ \sf\longmapsto Pressure=\dfrac{10}{2.25}\end{gathered}
⟼Pressure=
2.25
10
\begin{gathered}\\ \sf\longmapsto Pressure=4.4Pa\end{gathered}
⟼Pressure=4.4Pa
The U.S. uses a household voltage of 110 V. However, electric stoves and dryers are wired with
220 V lines. Which would cause less damage --plugging a 110 V-rated curling iron into a 220 V
outlet, or a German-made 220 V-rated curling iron into a 110 V outlet? Explain. (Note: 110 and
220 V outlets are made in different shapes so that appliances cannot be accidentally
interchanged.)
Answer:
In the United States and neighboring countries, however, household outlets run at 110 or 120 volts. This can pose a serious problem for travelers. Connecting a 220-volt appliance to a 110-volt outlet can damage or destroy the appliance
một vật dao động trong 10 phút thực hiện 500 dao động tính chu kì và tần số dao động
Answer:
Explanation:
T = 10(60)/500 = 1.2 s
f = 1/T = 0.83 Hz
Your new motorcycle weighs 2580 N.
The acceleration of gravity is 9.8 m/s2.
What is its mass?
Answer in units of kg.
Answer:
answer to your question is 263.26kg
Explanation:
m=f÷a ,m=2580÷9.8=263.26kg
An empty 230 kg elevator accelerates upward
at 1.7 m/s^2
The acceleration of gravity is 9.8 m/s^2.
What is the tension in the cable that lifts
the elevator cab?
Answer in units of N.
Answer:
7.2 as used in the equation
. The artificial sweetener NutraSweet is a chemical called aspartame (C14H18N2O5). What is (a) its molecular mass (in atomic mass units)? (3) (b) the mass (in kg) of an aspartame molecule?
The molecular mass, in atomic mass unit, of aspartame would be 294 amu while the mass, in kg, of an aspartame molecule would be 0.294 kg
Aspartame has the chemical formula C14H18N2O5
C = 12, H = 1, N = 14, O = 16
(a) Molecular weight = (12x14) + (1x18) + (14x2) + (16x5)
= 168 + 18 + 28 + 80
= 294 amu
(b) Mass of 1 molecule of aspartame = mole x molar mass
= 1 x 294
= 294 g
Converting 294 g to kg = 294/1000
= 0.294 kg
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An object travelling at 12 m/s has 64.8j of stored kinetic energy. What is the mass of the object, in grams?
Answer:
So u divided 12 divided by 64.8 okay
Explanation:
and when I getc the answer that's urs answer
how much kinetic energy is stored in a 1.5 kg object that is moved at 15 m per second
Answer:
Explanation:
KE=0.5xM(Vpower2)
=0.5x1.5(15power2)
=168.75
If a 2 kg block of aluminium (SHC: 921 J/kg°C) is heated from 20°C to 40°C, how much energy was transferred to it?
H = mc∆T
where, H=heat energy
c = SHC
H = 2*921*(40-20)
H = 36840J
H = 36.84KJ
The energy transferred to it is 36.84KJ
The energy transferred to aluminum from 20°C to 40 °C is equal to 36840 J.
What is the specific heat capacity?The specific heat capacity can be described as the quantity of heat required to increase the temperature of 1 unit of substance by one degree Celsius. The specific heat capacity of the substance depends upon the nature of the substance.
The mathematical equation is used to calculate the specific heat is equal to:
[tex]Q = m\times C\times \triangle T[/tex]
Given, the mass of the aluminum block, m = 2 Kg
The initial temperature of aluminum, T₁ = 20 °C
The final temperature of the aluminum, T₂ = 40 °C
The specific heat capacity of aluminum, C = 921 J/kg°C
The energy transferred to the aluminum block:
Q = 2 × 921 × (40-20)
Q = 36840 J
Therefore, the energy transferred to aluminum from 20°C to 40°C is 36840 J.
Learn more about specific heat capacity, here:
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I don’t get anything that this question is asking me and I need to turn this in quick
Answer:
Hey there
when they meat they will constructivly interfere, wich means they will become one big wave. After that they will pas right through each other and continue.
SI units are used for scientific works. Why?
Answer:
SI units are used for scientific works to bring uniformity in measurements all over the world.
21) A charged polyester ball is placed over a charged PVC pipe. The ball, which
has a mass of 1.2 grams, rests 42 cm above the pipe. If the ball and pipe have
the same negative charge, what is the charge on the ball?
The negative charge on the polyester ball is -1.53 x 10⁻⁶ C.
The given parameters;
mass of the ball, m = 1.2 gdistance between the ball and the pipe = 42 cm = 0.42 mThe gravitational force on the ball is calculated as follows;
F = mg
F = 0.012 x 9.8
F = 0.12 N
The electrostatic force on the ball is calculated as follows;
[tex]F= \frac{kq^2}{r^2} \\\\q^2 = \frac{Fr^2}{k} \\\\q = \sqrt{\frac{0.12 \times (0.42)^2}{9\times 10^9}} \\\\q =+/ -\ \ 1.53 \times 10^{-6} \ C\\\\q =-\ \ 1.53 \times 10^{-6} \ C[/tex]
Thus, the negative charge on the polyester ball is -1.53 x 10⁻⁶ C.
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is this kinetic energy ---> elastic potential energy OR elastic potential energy ---> kinetic energy ??
Answer:
it is potential energy ---- kinetic energy
One train (22,680 kg) moving east at 170 km/h collides with a car (1,200 kg) that was moving north at 5 km/h. They get attached to each other, moving in the direction of the train. What is the final velocity of the objects and the type of collision? If the collision happened in 1.2X10-3 seconds, what was the force? How much kinetic energy was lost?
According to the law of collision'
m1u1 + m2u2 = (m1+m2)v
Given the following:
m1 = 22,680kg
u1 =170km/h
m2 = 1200kg
u2 = 5km/hr
Get the final velocity "v"
22680(170) + 1200(5) = (22680 + 1200)v
3855600 + 6000 = 12880v
3,861,600 = 12880v
v = 3,861,600/12,880
v = 229.82km/hr
Hence the final velocity of the objects is 229.82km/hr
Since energy was lost after the collision, the type of collision that occurs is an elastic collision.
According to Newton's second law, the formula for calculating the force is expressed as;
F = ma
F = m(v-u)/t
F = 22680+1200(229.82-175)/t
Ft = 23880(54.82)
F = 1,309,101.6/0.0012
F = 1,090,918,000N
Hence the required force is 1,090,918,000N
KE lost = Kinetic energy after collision - Kinetic energy before collision
Kinetic energy after collision = 1/2 * 12880 * 229.82²
Kinetic energy after collision = 340,142,976.656 Jolues
Kinetic energy before collision = 1/2 * 22680(170)²+ 1/2*1200(5)²
Kinetic energy before collision = 327,726,000 + 15000
Kinetic energy before collision = 327,741,000
Kinetic energy lost = 340,142,976.656 - 327,741,000 = 12,401,976.656Joules
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Find the center of the galaxy with Shapley method
Answer:
Calculating Center
Shapley correctly determined the galactic center of the Milky Way to be located in the constellation of Sagittarius. He did this by mapping out a three-dimensional distribution of the globular clusters.
Explanation:
Mark me the Brainliest..PLS
While closing a door of mass 10 kg, a student pushes on it with a force of 25 N. As the door is accelerating to close, what
force does the door exert on the student?
A.5n
b.25n
c.250n
d.35n
Answer:
its 30 n
trust me
What happens if the incident beam is perpendicular to the surface (at an angle of 90 degrees)?
If the ray is perpendicular to the surface, then the incident ray, the reflected ray and the transmitted (refracted) ray all lie along the same line (i.e they are collinear). If the ray is not perpendicular to the surface, then the ray appears to be bent at the surface.
Which of the following is not an aspect of instincts?
the colour of the shadow of coloured objects is not same as the colour of the objects
When an opaque item absorbs all of the light falling from a light source, no light is reflected, and the thing appears black. The color of an object's shadow is independent of its hue; it can be red, yellow, green, or black.
PLEASE HELP
A student uses a ping pong ball launcher to shoot a projectile across a classroom. the launcher sits at the edge of a table and releases the ping pong ball 1.2 meters above the floor. as the ball leaves the launcher it has a speed of 13 m/s. if 5m/s is in the upwards direction and 12m/s is in the forward direction how far from the base of the table does the ping pong ball land
Answer:
Explanation:
It is hard to imaging that wind resistance is not a factor for such a low mass ball, but we must make that assumption on the first estimate.
s = s₀ + v₀t + ½at²
vertical analysis with floor level as origin
0 = 1.2 + 5t + ½(-9.8)t²
0 = 1.2 + 5t - 4.9t²
quadratic formula positive answer
t = (-5 - √(5² - 4(-4.9)(1.2))) / (2(-4.9))
t = 1.22 s is the flight time
horizontal analysis with launcher as origin
s = 0 + 12(1.22) + ½(0)1.22²
s = 14.6517... 15 m
I NEED HELP PLZZZZZZ
A 10-cm-long archerfish begins such a leap with its body vertical in the water, using its fins and undulating its body to propel itself sharply upward. Its acceleration steadily decreases as it leaves the water because less of its body and fewer of its fins are in contact with the water.
With what speed does the fish leave the water?
What height above the water does it reach?
Answer:
Explanation:
Velocity will be equal to the area under the curve of the acceleration-time plot.
v = ½(45)(0.075) = 1.6875
v = 1.7 m/s
h = (0² - 1.6875²) / (2(-9.8)) = 0.145288...
h = 15 cm
An object if mass 30 kg is falling in air and experiences a force due to air resistance of 50 newtons.
Hi there!
On the object, we know that there are two forces working on the object:
-Force due to gravity (Mg)
-Force due to air resistance
Let the positive direction of the force be downwards (direction of the acceleration)
We can write the summation of forces as:
∑F = Mg - Fa
Plug in values. Let g ≈ 10 m/s²
∑F = 30(10) - 50 = 250N
Find the acceleration using the formula:
∑F = m · a
∑F/m = a
Plug in values:
250/30 = 8.33 m/s²
momentum is conserved it can be transferred but not lost. true or false
Answer: False
explanation: because Total momentum is conserved only if the collision can be considered isolated from the influence of net external forces
✏️Topic: Comparing Arguments
My reflective journal.
Direction: Supply the sentence below to complete the information askes.
I learned that comparing arguments________________________One example of this is____________. We can use
Answer:
WOW ANG HIRAP NG TANONG MOExplanation:
Di ko yan masasagutan
stay safe
[tex]lol[/tex]
Calculate the kinetic energy of a 70 kg person moving at a speed of 5m/s
Answer:
875 JExplanation:
The kinetic energy of an object can be found by using the formula
[tex]k = \frac{1}{2} m {v}^{2} \\ [/tex]
m is the mass
v is the velocity
From the question we have
[tex]k = \frac{1}{2} \times 70 \times {5}^{2} \\ = 35 \times 25 \\ = 875[/tex]
We have the final answer as
875 JHope this helps you
Answer:
[tex]\boxed {\boxed {\sf 875 \ Joules}}[/tex]
Explanation:
Kinetic energy is the energy an object possesses due to motion. It is calculated using the following formula:
[tex]KE= \frac{1}{2}mv^2[/tex]
The mass of the person is 70 kilograms and they are moving at a speed of 5 meters per second.
m= 70 kg v= 5 m/sSubstitute these values into the formula.
[tex]KE= \frac{1}{2} (70 \ kg )(5 \ m/s)^2[/tex]
Solve the exponent.
(5 m/s)² = 5 m/s * 5 m/s = 25 m²/s²[tex]KE= \frac{1}{2}(70 \ kg)(25 \ m^2/s^2)[/tex]
Multiply the numbers in parentheses.
[tex]KE= \frac{1}{2} (1750 \ kg*m^2/s^2)[/tex]
Multiply by 1/2 or divide by 2.
[tex]KE= 875 \ kg*m^2/s^2[/tex]
Convert the units. 1 kilogram meter squared per second squared is equal to 1 Joule. So, our answer of 875 kg*m²/s² is equal to 875 Joules.
[tex]KE= 875 \ J[/tex]
The person has 875 Joules of kinetic energy.
Reflect on your new experiences, what made you uncomfortable and what encouraged you. Did you learn anything new about yourself on the trip? Traveling can help you improve. Think about your journey and if it helped you grow in any way.
Answer:
keke
Explanation:
The pressure of liquid varies as per it's depth.
Answer: The pressure in a liquid is different at different depths. Pressure increases as the depth increases. The pressure in a liquid is due to the weight of the column of water above. The greater pressure at the bottom would give a greater 'force per unit area' on the wall.
Explanation:
2. What are the units of mass?
kg
N
m/s
m/s^2
(kg)(m/s)
m
S
Answer:
Kg
Explanation:
The units of mass are gram (g) , kilograms (Kg)
But SI of mass accepted is Kilograms (Kg)
Answer:
kg
Explanation:
the s.i unit is kilogramThe ruminant stomach has four compartments including the rumen, reticulum, omasum and large intestine,
O True
O False
Answer:
FalseIt has four compartments just not including all of those
Explanation:
Ruminant stomachs have four compartments: the rumen, the reticulum, the omasum and the abomasum.Anatomy of the ruminant digestive system includes the mouth, tongue, salivary glands (producing saliva for buffering rumen pH), esophagus, four-compartment stomach (rumen, reticulum, omasum, and abomasum), pancreas, gall bladder, small intestine (duodenum, jejunum, and ileum), and large intestine (cecum, colon, and rectum).One of your classmates, in a fit of unrestrained ego, jumps onto a lab table:
a) Draw a qualitative force diagram for the table. Use marks on the vectors to show the balance of forces.
b) Your classmate’s mass is 65 kg and the table weighs 0 N. Calculate the normal force on the table by the floor. Show your work!
c)Find the mass of the table
The equilibrium condition allows finding the results for the forces of the system are
a) The free body diagram is in the attachment
b) The normal force is N = 737 N
c) The mass of the table is 10.2 kg
Newton's second law indicates that the net force is proportional to the product of the mass and the acceleration of the bodies, in the special case that the acceleration is zero, it is called the equilibrium condition
∑ F = 0
Where the bold letters indicate vectors, F is the external forces
a) A free body diagram is a scheme of the forces without the details of the bodies, in the attachmentt we see a free body diagram of the system.
b) The reaction force of the ground is applied in each of the legs of the table, in general this force has the same magnitude in each leg, therefore in Newton's second law we can place it as a single force
N = N₁ + N₂ + N₃ + N₄₄
Let's apply the equilibrium condition
N - [tex]W_m -w_{table}[/tex] = 0
N = [tex]W_m +w_{table}[/tex]
N = [tex]M_m g + w_{table}[/tex]
They indicate the pose of the boy is 65 kg, for the weight of the table of a laboratory table is approximately 100 N
N = 65 9.8 + 100
N = 737 N
c) To calculate the mass of the table we use the relation
W = [tex]m_{table}[/tex] g
[tex]m_{table} = \frac{w_{table}}{g}[/tex]
[tex]m_{tabble}= \frac{100}{9.8}[/tex]
[tex]m_{table}[/tex]e = 10.2 kg
In conclusion using the equilibrium condition we can find the results for the forces are
a) The free body diagram is in the attachment
b) The normal force is N = 737 N
c) The mass of the table is 10.2 kg
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