The data table for the decomposition reaction of hydrogen peroxide H2 O2 shows how the reaction rate changes over time which statement describes the conclusion you can sharpen the table

The Data Table For The Decomposition Reaction Of Hydrogen Peroxide H2 O2 Shows How The Reaction Rate

Answers

Answer 1

The data table for the decomposition reaction of hydrogen peroxide H₂ O₂ shows down over time as the reactant rate get used up.

What is rate, reaction and rate of reaction?

Rate- The rate of a particular chemical reaction is calculated by dividing the rate of change in a reactant's or product's concentration by the coefficient from the given balanced equation.

Reactions- They are defined as the change of a chemical substance into an innovative substance through the formation and breaking of bonds among distinct atoms.

Rate of reaction- It is defined as the ratio of the increase in product concentration per unit time to the decrease in reactant concentration per unit time. The rate of reaction varies greatly.

It can be seen that with the concentration, the rate of decomposition is also decreased. Generally, it is found that as per hour concentration and rate of decomposition decreases as well.

Therefore, (A) option is the correct answer.

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Related Questions

One end of a meter stick is pinned to a table, so the stick can rotate freely in a plane parallel to the tabletop. Two forces, both parallel to the tabletop, are applied to the stick in such a way that the net torque is zero. The first force has a magnitude of 2.00 N and is applied perpendicular to the length of the stick at the free end. The second force has a magnitude of 6.00 N and acts at a 42.9o angle with respect to the length of the stick. Where along the stick is the 6.00-N force applied? Express this distance with respect to the end of the stick that is pinned.

Answers

Answer:

  x = 0.455 L

Explanation:

For this exercise we must use the rotational equilibrium condition

        Σ τ = 0

it has two forces, the first is perpendicular to the rod, so its stub is

         τ₁ = F₁ L

the second force is applied with an angle, so we can use trigonometry to find its components

          sin θ = F_parallel / F₂

          cos θ = F_perpendicular / F₂

         F_parallel = F₂ sin θ

         F _perpendicular = F₂ cos θ

torque is

         τ₂ = F_perpendicular x + F_parallel 0

the parallel force is on the rod therefore its distance is zero

           

we apply the equilibrium equation

          τ₁  - τ₂ = 0

          F₁ L = F₂ cos θ  x

          x = [tex]\frac{L}{cos \theta} \ \frac{F_1}{F_2}[/tex]

let's calculate

          x = [tex]\frac{L}{cos \ 42.9} \ \frac{2.00}{6.00}[/tex]

          x = 0.455 L


An object is projected from a height of 100m above the ground at an angle of 300to the
horizontal with a velocity of 100m/s.
Calculate
(4)
(4)
The maximum height reached above the ground
Time of flight
The velocity and the direction of the object 1 sec before it hit the ground
(4)​

Answers

Answer:

a) y = 127.6 m, b) 11.9s,  c)  v = 103.6  m / s, θ’= 326.7º

Explanation:

This is a missile throwing exercise

let's start by breaking down the initial velocity

         sin 30 = [tex]\frac{v_{oy} }{v_o}[/tex]

         cos 30 = v₀ₓ / v₀

         v_{oy} = v₀ go sin 30

         v₀ₓ = v₀ cos 30

         v_{oy} = 100 sin 30 = 50 m / s

         v₀ₓ = 100 cos 30 = 86.6 m / s

a) the maximum height is requested.

At this point the vertical velocity is zero (v_y = 0)

         v_y² = [tex]v_{oy}^2[/tex] - 2 g y

         0 = v_{oy}^2 - 2g y

         y = [tex]\frac{v_{oy}^2 }{2g}[/tex]

         y = 50² / (2  9.8)

         y = 127.6 m

b) Flight time

this is the time it takes to reach the ground, the reference system for this movement is taken on the ground this is a height of y = 0 m and the body is at an initial height of i = 100m

         y = y₀ + v₀ t - ½ g t²

         

       0 = 100 + 50 t - ½ 9.8 t²

we solve the quadratic equation

        4.9 t² - 50 t - 100 = 0

         t = [tex]\frac{50 \pm \sqrt{50^2 + 4 \ 4.9 \ 100} }{2 \ 4.9}[/tex]

         t = [tex]\frac{50 \ \pm \ 66.8}{9.8}[/tex]

         t₁ = 11.9 s

         t₂ = -8.4 s

flight time is 11.9s

c) The time 1 s before hitting the ground is

        t1 = 11.9 -1

        t1 = 10.9 s

let's find the vertical speed

       v_y =[tex]v_{oy}[/tex] - g t

       v_y = 50 - 9.8 10.9

       v_y = -56.8 m / s

the negative sign indicates that the direction of the velocity is downward.

On the x-axis there is no acceleration therefore the speed is constant.

Let's use the Pythagorean theorem

        v = [tex]\sqrt{v_x^2+v_y^2}[/tex]

        v = [tex]\sqrt { 86.6^2 + 56.8^2}[/tex]

        v = 103.6  m / s

let's use trigonometry

        tan θ = [tex]\frac{v_y}{v_x}[/tex]

        θ = tan⁻¹  \frac{v_y}{v_x}

        θ = tan⁻¹  (-56.8 / 86.60)

        θ = -33.3º

the negative sign indicates that it is measured clockwise from the x-axis

for a counterclockwise measurement

          θ’= 360 - θ

          θ' = 360 - 33.3

          θ’= 326.7º

HELP URGENT PLEASE!!!!!!!

Answers

Answer:

I think c I dont know sorry if I'm wrong

It is C because the North Magnets are stronger than the south magnets and C is the only diagram showing that relation in the middle :)

Which of the following happens to
density as air pressure decreases?
С C
A. Density increases.
B. Density stays the same.
C. Density decreases.
D. There is no correlation between air pressure and
density.

Answers

Explanation:

As pressure increases, with temperature constant, density increases. Conversely when temperature increases, with pressure constant, density decreases. Air density will decrease by about 1% for a decrease of 10 hPa in pressure or 3 °C increase in temperature.

Review please help.

Answers

Answer:

1 and 3

Explanation:

because they are going up from 0

I’ll mark you as brinlist please help.

Answers

Answer:

245 divided by 5.14=47.6653696 or 47.66

Explanation:

47.6653 is the correct answer

A student using a stopwatch finds that the time for 10 complete orbits of a ball on the end of a string is 25 seconds. The period of the orbiting ball is​

Answers

Answer:

T = 2.5 s

Explanation:

Given that,

Number of complete orbits = 10

Time, t = 25 seconds

We need to find the period of the orbiting ball. Let it is T. We know that number of oscillations per unit time is called frequency and the reciprocal of frequency is called period of the ball.

So,

[tex]T=\dfrac{t}{n}\\\\T=\dfrac{25}{10}\\\\T=2.5\ s[/tex]

So, the period of the orbiting ball is equal to 2.5 seconds.

A student takes the elevator up to the fourth floor to see her favorite physics instructor. She stands on the floor of the elevator, which is horizontal. Both the student and the elevator are solid objects, and they both accelerate upward at 5.80 m/s2. This acceleration only occurs briefly at the beginning of the ride up. Her mass is 87.0 kg. What is the normal force exerted by the floor of the elevator on the student during her brief acceleration? (Assume the j direction is upward.)

Answers

The normal force exerted by the floor of the elevator on the student during her brief acceleration is 1357.2 N.

To determine the normal force exerted by the floor of the elevator on the student during the brief acceleration, we need to analyze the forces acting on the student.

The force of gravity acting on the student can be calculated using the equation F_gravity = m * g, where m is the mass of the student and g is the acceleration due to gravity (approximately 9.8 m/s²). Therefore, F_gravity = 87.0 kg * 9.8 m/s² = 852.6 N.

Since the elevator and the student are accelerating upward, there is an additional upward force acting on the student. This force is equal to the mass of the student multiplied by the acceleration of the elevator, which is given as 5.80 m/s². So, the upward force is F_upward = m * a = 87.0 kg * 5.80 m/s² = 504.6 N.

Now, the normal force exerted by the floor of the elevator on the student is equal to the sum of the gravitational force and the upward force. In this case, the normal force is given by F_normal = F_gravity + F_upward = 852.6 N + 504.6 N = 1357.2 N.

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if the density of a napthalene ball is 0.02kg.what is the mass of the napthalene ball if it has a volume of 100m³

Answers

Density=mass/volume
Mass=100x0.02=2

Which of the following best defines
weather?
A. the expanding or contracting of the atmosphere
B. the measurement of the amount of water vapor in the
atmosphere
C. the condition of the atmosphere at a certain time and
place
Help Resources
D. the average air temperature of a specific region

Answers

Answer:

I'd say D

Explanation:

because not all weather happens within the atmosphere, and most weather depends on region (lile if your near the equator or not)

which particle have a mass of 1 u​

Answers

Answer:

Explanation:

proton

7. A particle of mass 3 kg is held in equilibrium by two light unextensible strings. One string is horizontal, as shown in Figure 7.30. The tension in the horizontal string is PN and the tension in the other string is N. Find a) the value of 0 b) the value of P.​

Answers

The tension in the strings are 31.47 and 19.25 N respectively.

Mass of the block, m = 3 kg

From the figure, consider the vertical components,

T₁ sin45° + T₂ sin30° = mg

(T₁/√2) + (T₂/2) = 3 x 9.8 = 29.4

Also, consider the horizontal components,

T₁ cos45° = T₂ cos30°

T₁/√2 = T₂ x√3/2

T₁ = T₂ x √3/2 x √2

So,

T₁ = 0.612T₂

Applying in the first equation,

(T₁/√2) + (T₂/2) = 29.4

(0.612T₂/1.414) + 0.5T₂ = 29.4

0.434 T₂ + 0.5 T₂ = 29.4

0.934 T₂ = 29.4

Therefore, the tension,

T₂ = 29.4/0.934

T₂ = 31.47 N

So, the tension,

T₁ = 0.612 T₂

T₁ = 0.612 x 31.47

T₁ = 19.25 N

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_____is the nitrogen base found only in DNA.

Answers

Answer:

thymine

Explanation:

The nitrogen base found only in DNA is known as thymine which is also called 5-methyl uracil as thymine is a derivative of uracil.

A fisherman notices that his boat is moving up and down periodically without any horizontal motion, owing to waves on the surface of the water. It takes a time of 2.60 s for the boat to travel from its highest point to its lowest, a total distance of 0.630 m . The fisherman sees that the wave crests are spaced a horizontal distance of 5.70 m apart.

Required:
a. How fast are the waves traveling?
b. What is the amplitude of each wave?
c. If the total vertical distance traveled by the boat were 0.30 m but the other data remained the same, how would the answers to parts (a) and (b) be affected?

Answers

Answer:

a) v = 1.1 m/s

b) A = 0.315 m

c) v = 1.1 m/s  A= 0.15 m

Explanation:

a)

In any travelling wave, there exists a fixed relationship between the propagation speed, the wavelength and the frequency, as follows:

        [tex]v = \lambda * f (1)[/tex]

If the wave crests are spaced a horizontal distance of 5.7 m apart, this means that the wavelength of the wave is just the same, i.e., 5.70 m.Regarding the frequency, we know that the frequency is just the inverse of the period, i.e., the time needed to complete one oscillation.If it takes a time of 2.60 s to go from the highest point to the lowest, the time needed to complete an oscillation (the period T) will be just double of this time:⇒ T = 2.60 s * 2 = 5.20 s (2)Since we have now T, we can find the frequency f as follows:

       [tex]f = \frac{1}{T} = \frac{1}{5.20s} = 0.19 Hz (3)[/tex]

Replacing f and λ in (1) we get:

      [tex]v = \lambda * f = 5.70 m * 0.19 Hz = 1.10 m/s (4)[/tex]

b)

The amplitude of the wave is just the amount that the water aparts from its equilibrium level, which is just the half of the distance between its highest point and the lowest one, as follows:

      [tex]A = \frac{0.630m}{2} = 0.315 m (5)[/tex]

c)  

Part a) will not be affected by the new amplitude, because we have showed that the speed is independent of the amplitude, so v can be written as follows:

       v = 1.10 m/s (6)

Part b) will change , due to the amplitude changes. If the total vertical distance traveled by the boat is 0.30 m, by the same token as explained in b), the new amplitude will be just half of this, as follows:

       [tex]A = \frac{0.30m}{2} = 0.15 m (7)[/tex]

Which of these cubes absorb the most light?

Answers

Answera black cube or dark colors cause dark colors suck in heat

What is Newton's scientific view?

Answers

Answer:

Newton's first law of motion concerns any object that has no force applied to it.

Explanation:

three laws of motion and the law of universal gravitation.

What is the importance of using locally available resources in creating art?​

Answers

Answer:

please give me brainlist and follow

Explanation:

Using locally available resources for art help in the preservation of environment. A significant and practical aspects of art is material significance. The items used by artists while making an art piece affects both the form and the material. Every material delivers something special in the creative process.

A 1.65-m-long wire having a mass of 0.100 kg is fixed at both ends. The tension in the wire is maintained at 16.0 N. (a) What are the frequencies of the first three allowed modes of vibration

Answers

Answer:

Explanation:

mass per unit length ρ = .100 / 1.65 = .0606 . kg /m

length of wire L = 1.65 m

For fundamental frequency , the expression is as follows

n = [tex]\frac{1}{2L} \sqrt{\frac{T}{m} }[/tex]

L = 1.65 , T = 16 n and m = .0606

n = [tex]\frac{1}{2\times 1.65} \sqrt{\frac{16}{.0606} }[/tex]

= 4.9 /s .

This is fundamental frequency .

other mode of vibration ( first three ) will be as follows

4.9 x 2 = 9.8 /s ,

4.9 x 3 = 14.7 /s .

Pls help ASAP
Imagine that Maritans launch a rocket toward the Earth at a great speed. While the
rocket is traveling toward us, it will appear
than it actually is.
O more blue
darker
larger
more red

Answers

Answer:

The rocket will appear larger than it actually is

A 4.0 kg block is moving at 5.0 m/s along a horizontal frictionless surface toward and ideal spring that is attached to a wall , After the block collides with the spring, the spring is compressed a maximum distance of 0.68m . what is the speed of the block when the spring is compressed to only one-half of the maximum distance?

Answers

A 4.0 kg block is moving at 5.0 m/s along a horizontal frictionless surface toward an ideal spring that is attached to a wall, the maximum speed of the block when the spring is compressed to one-half of the maximum distance is 4.33 m/s

From the conservation of energy; the kinetic energy of the mass is equal to the work done on the spring.

i.e.

[tex]\mathbf{\dfrac{1}{2} mv^2 = \dfrac{1}{2}kx^2_{max}}[/tex]

Given that:

the mass of the block = 4.0 kg the speed at which it is moving = 5.0 m/scompression of the spring = 0.68 m

From the equation above, multiplying both sides with 2, we have:

[tex]\mathbf{mv^2 =kx^2_{max}}[/tex]

Making (k) the subject of the formula;

[tex]\mathbf{k = \dfrac{mv^2}{x^2_{max}}}[/tex]

[tex]\mathbf{k = \dfrac{4 \times 5^2}{0.68^2}}[/tex]

k = 216.26 N/m

However, when compressed to one-half of the maximum distance; the speed is computed as follows:

x = 0.68/2 = 0.34 m

[tex]\mathbf{\dfrac{1}{2}mv_o^2 - \dfrac{1}{2}mv^2 = \dfrac{1}{2}kx^2}[/tex]

[tex]\mathbf{m(v_o^2 -v^2) =kx^2}[/tex]

[tex]\mathbf{(v_o^2 -v^2) =\dfrac{kx^2}{m}}[/tex]

[tex]\mathbf{(5^2 -v^2) =\dfrac{216.26 \times 0.34^2}{4.0}}[/tex]

25 - v² = 6.25

25 -6.25 = v²

v² = 18.75

[tex]\mathbf{ v= \sqrt{18.75 }}[/tex]

v = 4.33 m/s

Therefore, we can conclude that the speed of the block when the spring is compressed to only one-half of the maximum distance is 4.33 m/s

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True or False
Microscopic organisms grow on the rocks near a volcano if the rocks are cooled to 120 degrees Celsius or less.

Answers

Explanation:

it's true

Kiss me if I'm wrong. But dinosaurs still exist right?

Answer:

True

Definetely true

A scientist notices that an oil slick floating on water when viewed from above has many different colors reflecting off the surface, making it look rainbow-like (an effect known as iridescence). She aims a spectrometer at a particular spot and measures the wavelength to be 750 nm (in air). The index of refraction of water is 1.33.
Part A: The index of refraction of the oil is 1.20. What is the minimum thickness of the oil slick at that spot? t= 313nm
Part B: Suppose the oil had an index of refraction of 1.50. What would the minimum thickness be now? t=125nm

Answers

Answer:

a) The minimum thickness of the oil slick at the spot is 313 nm

b) the minimum thickness be now will be 125 nm

Explanation:  

Given the data in the question;

a) The index of refraction of the oil is 1.20. What is the minimum thickness of the oil slick at that spot?

t[tex]_{min[/tex] = λ/2n

given that; wavelength λ = 750 nm and  index of refraction of the oil n = 1.20

we substitute

t[tex]_{min[/tex] = 750 / 2(1.20)

t[tex]_{min[/tex] = 750 / 2.4

t[tex]_{min[/tex] = 312.5 ≈ 313 nm

Therefore, The minimum thickness of the oil slick at the spot is 313 nm

b)

Suppose the oil had an index of refraction of 1.50. What would the minimum thickness be now?

minimum thickness of the oil slick at the spot will be;

t[tex]_{min[/tex] = λ/4n

given that; wavelength λ = 750 nm and  index of refraction of the oil n = 1.50

we substitute

t[tex]_{min[/tex] = 750 / 4(1.50)

t[tex]_{min[/tex] = 750 / 6

t[tex]_{min[/tex] = 125 nm

Therefore, the minimum thickness be now will be 125 nm

If you live in Melbourne, Australia, the local magnetic field has a strength of about 4x10-5 T. The magnetic field vector is directed northward, making an angle of 30 deg above the horizontal. An electron in Melbourne is moving parallel to the ground, in the west direction, at a speed of 9x105 m/s. What are the magnitude and direction of the magnetic force on the electron

Answers

Answer:

[tex]5.76\times 10^{-18}\ \text{N}[/tex] perpendicular to the velocity and magnetic field

Explanation:

B = Magnetic field = [tex]4\times 10^{-5}\ \text{T}[/tex]

[tex]\theta[/tex] = Angle the magnetic field makes with the horizontal = [tex]30^{\circ}[/tex]

v = Velocity of electron = [tex]9\times 10^5\ \text{m/s}[/tex]

q = Charge of electron = [tex]1.6\times 10^{-19}\ \text{C}[/tex]

Magnetic force is given by

[tex]F=qvB\sin\theta\\\Rightarrow F=1.6\times 10^{-19}\times 9\times 10^5\times 4\times 10^{-5}\sin30^{\circ}\\\Rightarrow F=2.88\times 10^{-18}\ \text{N}[/tex]

The magnitude of the magnetic force is [tex]2.88\times 10^{-18}\ \text{N}[/tex] and the direction is perpendicular to the velocity and magnetic field.

light of wavelength 485 nm passes through a single slit of width 8.32 *10^-6m. what is the single between the first (m=1) and second (m=2) interference minima?

Answers

Answer:

3.35

Explanation:

Got it on Acellus

The light of wavelength 485 nm passes through a single slit. The single between the first (m=1) and second (m=2) interference minima is 3.36°.

What is diffraction?

Diffraction is the phenomenon of bending of waves through obstacles.  

Given is the wavelength λ= 485 nm, silt width d =  8.32 *10⁻⁶ m, then the angle θ will be

d sinθ =mλ

for m=1, sin θ₁ = λ/d

for m=2, sin θ₂ = 2λ/d

Substitute the values into both expressions to find the angles,

sin θ₁ = 485 x 10⁻⁹ /  8.32 *10⁻⁶

θ₁ = 3.34°

and sin θ₂ = (2 x  485 x 10⁻⁹ )/  8.32 *10⁻⁶

θ₂ = 6.7°

The angle between m =1 and m=2 will be

θ₂ -θ₁ = 6.7° - 3.34° =3.36°

Thus, angle between the first (m=1) and second (m=2) interference minima is 3.36°.

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Suppose a diode consists of a cylindrical cathode with a radius of 6.200×10−2 cm , mounted coaxially within a cylindrical anode with a radius of 0.5580 cm . The potential difference between the anode and cathode is 400 V . An electron leaves the surface of the cathode with zero initial speed (vinitial=0). Find its speed vfinal when it strikes the anode.

Answers

Answer:

The final speed will be "[tex]1.185\times 10^7 \ m/sec[/tex]".

Explanation:

The given values are:

Potential difference,

Δv = 400 v

Radius,

r = 0.5580 cm

As we know,

⇒  [tex]W=e \Delta v[/tex]

and,

⇒  [tex]\frac{1}{2}mv^2=e \Delta v[/tex]

then,

⇒  [tex]v=\sqrt{\frac{2e \Delta v}{m} }[/tex]

On substituting the values, we get

⇒     [tex]=\sqrt{\frac{2\times 1.6\times 10^{-19}\times 400}{9.11\times 10^{-31}} }[/tex]

⇒     [tex]=\sqrt{\frac{1.6\times 10^{-19}\times 800}{9.11\times 10^{-31}}}[/tex]

⇒     [tex]=1.185\times 10^7 \ m/sec[/tex]

What is a transfer of energy called?
A. Displacement
B. Acceleration
C. Work
D. Torque

Answers

Your answer is c, work

Please answer this for 15 points please don’t put in a link.

Answers

It’s b I took the test

Answer:

c. Double Replacement

Explanation:

As in Double Replacement reaction exchanges the cations (or the anions) of two ionic compounds.

Here, in BaCl2 , Ba has replaced with NO3 to form Ba(NO3)2

and in 2AgNo3 , Ag has replaced with Cl to form 2AgCl.


Please help me easy question just get mixed up.

Answers

Answer:

The mechanical energy of the ball is 112.667 J

Explanation:

Mechanical energy = kinetic energy + potential energy

Where:

kinetic energy = [tex]\frac{1}{2}[/tex]m[tex]v^{2}[/tex]

potential energy = mgh

So that for the given ball, its mechanical energy = [tex]\frac{1}{2}[/tex]m[tex]v^{2}[/tex] + mgh

                                = m([tex]\frac{1}{2}[/tex][tex]v^{2}[/tex] + gh)

But, m = 400 g = 0.4 kg, v = 23.0 m/s, g = 9.81 m/[tex]s^{2}[/tex] and h = 1.75 m.

Mechanical energy of the ball = 0.4([tex]\frac{1}{2}[/tex]([tex]23^{2}[/tex]) + 1.75*9.81)

                                                  = 0.4(264.5 + 17.1675)

                                                  = 0.4 x 281.6675

                                                  = 112.667

The mechanical energy of the ball is 112.667 J.

Blocks A (mass 5.00 kg) and B (mass 6.50 kg) move on a frictionless, horizontal surface. Initially, block B is at rest and block A is moving toward it at 3.00 m/s. The blocks are equipped with ideal spring bumpers. The collision is head-on, so all motion before and after the collision is along a straight line.
(a) Find the maximum energy stored in the spring bumpers and the velocity of each block at that time.
(b) Find the velocity of each block after they have moved apart.

Answers

Answer: i believe  its B Find the velocity of each block after they have moved apart sorry

Explanation: have a nice day buddy

The magnitude of the force can be determined as? ​

Answers

Answer:

the mass of the object multiplied by the acceleration of the object

Explanation:

N2L states that F = ma (force equals mass times acceleration).

Other Questions
A coin bank has 17 coins that contains only dimes and quarters. The coins are worth $3.35. How many of each coin are in the bank? oints Print Cash Short-term investments Receivables Inventory Prepaid expenses Total current assets Current liabilities Quick ratio Case X $ 910 Case X Case Z $ 1,768 720 1,240 3,100 5,980 2,300 1,340 . A random variable X has pdf fX(x) = 2e 2x , x 0.(a) Use Chebyshevs inequality to obtain an upper bound for P(X / (X 1, X + 1))(b) Use Chebyshevs inequality to obtain a lower bound for P(X (X 3, X + 3)) A purely domestic firm that sources and sells only domestically, Multiple Choice should never hedge since this could actually increase its currency exposure. faces no exchange rate risk and should never hedge since this could actually increase its currency exposure. faces no exchange rate risk. faces exchange rate risk to the extent that it has international competitors in the domestic market. What was the name of the Emperor who resisted military government of the Kamakura Shogunate? If the point M(2,2) is reflected over the y axis, what will be the coordinates of the resulting point, M? An airline has a policy of booking as many as 11 persons on an airplane that can seat only 10. (Past studies have revealed that only 86.0% of the booked passengers actually arrive for the flight.) Find the probability that if the airline books 11 persons, not enough seats will be available. Is it unlikely for such an overbooking to occur? The probability that not enough seats will be available is (Round to four decimal places as needed.) Is it unlikely for such an overbooking to occur? A. It is unlikely for such an overbooking to occur, because the probability of the overbooking is less than or equal to than 0.05. B. It is unlikely for such an overbooking to occur, because the probability of the overbooking is greater than 0.05. OC. It is not unlikely for such an overbooking to occur, because the probability of the overbooking is less than or equal to than 0.05. OD. It is not unlikely for such an overbooking to occur, because the probability of the overbooking is greater than 0.05. Cyber incivility is one of the personal mistreatments at workplace. The Western countries have identified it as a cause of turnover among employees. How prevalent is cyber incivility in non-Western countries? Discuss any two adverse consequences of cyber incivility as experienced by non-Western countriesemployees. What is the first thing you should do if you encounter an accident?A. Call 911B. Check the situationC. Give care right away Use the chart to help you answer the questions.Voter Registration Rates, 1965Which state had the lowest rate of AfricanAmerican voter registration?StateWhitesAfricanAmericansDONEAlabama692193AlabamaGeorgia62627.4GeorgiaLouisiana80.531.6Mississippi69.96.7MississippiNorth Carolina96.8468South Carolina75.7373Virginia61.1383Intro Most Americans eat and enjoy foods from other cultures. True False include step by step directions MAKE SURE ITS CORRECT Problem 12-04A The income statement of Kingbird, Inc. is presented here. Kingbird, Inc. Income Statement For the Year Ended November 30, 2020 Sales revenue $7,465,900 Cost of goods sold Beginning inventory $1,868,500 Purchases 4,450,600 Goods available for sale 6,319,100 Ending inventory 1,331,800 Total cost of goods sold 4,987,300 Gross profit 2,478,600 Operating expenses 1,120,500 Net income $1,358,100 Additional information: 1. Accounts receivable increased $205,900 during the year, and inventory decreased $536,700. 2. Prepaid expenses increased $179,800 during the year. 3. Accounts payable to suppliers of merchandise decreased $345,700 during the year. 4. Accrued expenses payable decreased $105,800 during the year. 5. Operating expenses include depreciation expense of $95,300. Prepare the operating activities section of the statement of cash flows using the direct method The intention of the homestead act was to provide undeveloped land as a solution to economic challenges that many faced in the united states which of he following was a flaw in the act?A The homestead did not allow women, africain americans, or immagrants to aquire land B people could acquire land but could not afford necessary tools C land available was not fertile D railroad companies and corporations acquired land under false pretenses to further profits What is the relationship between the values p and q plotted on the number line below? A. q>P B. p= q c. p> q What is a function of the kidneys of a healthy person? 3. Which of the following is not an example of a reference material? dictionaryinstruction manualthesaurus glossary Select the correct answer.What are the asymptote and the y-intercept of the function shown in the graph?f(x) = 3(0.2)^x + 2A. asymptote: y = -2y-intercept: (0,5)B. asymptote: y = 2y-intercept: (0,5)C. asymptote: y = 2y-intercept: (0,4)D. asymptote: y = -2y-intercept: (0,3) There is pollution that has spilled into a lake. Explain why the birds who live on the lake are more likely to survive than the fish. If an economy were experiencing substantial unemployment, the economy is producing inside the production possibilities frontier. (a) True (b) False